Answer:
yes with left over silver
An sample of water with a mass of 123.00 kg is heated from 25 C to 97 C. If the specific heat of water is 1 J-1 kg K-1 then how much energy is required?
Answer:
8856joules
Explanation:
Energy= MC. ©
energy = 123.00*1*(97-25)
energy =8856joules//
Answer: The amount of energy required will be 8856 Joules.
Explanation:
To calculate the amount of heat absorbed, we use the equation:
[tex]Q=mc\Delta T[/tex]
where,
Q = heat absorbed or released
m = Mass of the substance = 123 kg
c = specific heat capacity of water = [tex]1J/kg.K[/tex]
[tex]\Delta T[/tex] = change in temperature = [tex](97-25)^oC=72^oC=72K[/tex] (change remains the same)
Putting values in above equation, we get:
[tex]Q=123kg\times 1J/kg.K\times 72K\\\\Q=8856J[/tex]
Hence, the amount of energy required will be 8856 Joules.
How does the concentration of reactants affect the rate of a reaction
Answer:
B
Explanation:
If the concentration is increased, there are more particles to collide with each other, increasing the rate of the reaction.
The concentration of reactants affect the rate of a reaction by increasing the concentration increasing the collision of molecular frequency.
What rate of reaction?The reaction rate refers to how quickly the concentration of such a particular reactant as well as product changes during a chemical reaction.
What is concentration?The abundance of an ingredient divided by the volume of a combination is called concentration. Mass concentration, molar concentration, number concentration, as well as volume concentration are all examples of mathematical descriptions.
The concentration of reactants affect the rate of a reaction by increasing the concentration increasing the collision of molecular frequency.
Therefore, the correct answer will be option B
To know more about rate of reaction.
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which containe the most moles: water, aluminum, salt, baking soda
Moles are the number of particles in a given weight. So unless you state the amount of water, aluminum, salt, and baking soda no one can not consider which contain the most moles.
Study the image
Which type of clouds are shown?
cirrocumulus
cumulonimbus
cumulus
stratus
Answer:
The correct answer is Cirrocumulus.
Explanation:
Cirrocumulus : Clouds forming broken layer of small fleecy clouds at higher altitudes.
Cumulonimbus : Clouds forming a towering mass with flat base with flat base at lower altitude
Cumulus : Cloud forming rounded masses heaped or stacked on each other above a flat base , fairly at lower altitudes.
Stratus : Clouds forming continuous horizontal gray sheet, usually during rain or snow.
The given image corresponds to description given as Cirrocumulus.
Answer: A
Explanation:
6. How to calculate the mass of copper that can be plated out of a 1.0 M Cu(NO3)2 solution using a current of 0.75 A for 5.0 minutes?
Answer:
Approximately 0.074 grams.
Explanation:
Look up the relative atomic mass of copper on a modern periodic table: [tex]\rm 63.546[/tex]. Look up the Faraday's Constant: [tex]F \approx \rm 96485.33212\;C\cdot mol^{-1}[/tex]. This constant gives the amount of electrical charge on each mole of electrons.How does the electroplating works for copper? Copper exists as copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] in the copper(II) nitrate [tex]\rm Cu{(NO_3)}_2[/tex] solution. It takes two moles of electrons to reduce one mole of copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] to metallic copper [tex]\rm Cu[/tex].
[tex]\rm Cu^{2+}\;(aq) + 2\;e^{-} \to Cu\;(s)[/tex]. (Reduction half of the ionic equation.)
What are the steps for finding the mass of copper that has been deposited.Start by finding the charge on the electrons that have been supplied to this electrochemical cell. After that,
Find the number of moles of electrons that have been supplied based on the charge supplied; Find the number of moles of copper that have been reduced based on the number of moles of electrons supplied; andFind the mass of copper based on the number of moles of copper atoms reduced.What's the charge [tex]Q[/tex] on the electrons supplied to this electrochemical cell?For a constant direct current [tex]I[/tex], the charge [tex]Q[/tex] that has been delivered in time [tex]t[/tex] is equal to
[tex]Q = I \cdot t[/tex].
In case
[tex]I[/tex] is in Amperes [tex]\mathrm{A}[/tex] and[tex]t[/tex] is in seconds [tex]\mathrm{s}[/tex],[tex]Q[/tex] will be in Coulombs [tex]\mathrm{C}[/tex] (which is the same as [tex]\mathrm{A\cdot s}[/tex].)
For this electrochemical cell,
[tex]Q = I\cdot t = \rm 0.75\;A \times 300\;s = 225\;C[/tex].
How many moles of electrons were supplied to this electrochemical cell?The Faraday's Constant gives the size of charge (in Coulombs) on one mole of electrons.
[tex]F \approx \rm 96485.33212\;C\cdot mol^{-1}[/tex].
[tex]\displaystyle n(\mathrm{e^{-}}) = \frac{Q}{F} = \rm \frac{225\;C}{96485.33212\;C\cdot mol^{-1}}\approx 0.00233196\;mol[/tex].
How many moles of copper atoms have been deposited?Assume that copper(II) ions [tex]\mathrm{Cu}^{2+}[/tex] are in excess. Refer to the reduction half-equation, it takes two moles of electrons to deposit one mole of metallic copper.
[tex]\displaystyle \frac{n(\mathrm{Cu})}{n(\mathrm{e^{-}})} = \frac{1}{2}[/tex].
[tex]n(\mathrm{e^{-}})=\rm 0.00233196\;mol[/tex]. As a result,
[tex]\displaystyle n(\mathrm{Cu}) = n(\mathrm{e^{-}})\cdot \frac{n(\mathrm{Cu})}{n(\mathrm{e^{-}})} = \rm 0.00233196\;mol\times \frac{1}{2} = 0.00116598\; mol[/tex].
What's the mass of that many copper atoms?The Relative atomic mass of copper is [tex]63.546[/tex].
[tex]\begin{aligned}m(\mathrm{Cu})& = n(\mathrm{Cu}) \cdot M(\mathrm{Cu})\\& = \rm 0.00116598\; mol\times 63.546\; g\cdot mol^{-1}\\&\rm \approx 0.074\;g\end{aligned}[/tex].
Final answer:
The mass of copper that can be plated from a 1.0 M Cu(NO3)2 solution using 0.75 A for 5 minutes is calculated by converting the charge passed to moles of electrons, determining the moles of copper, and then converting it to mass, resulting in approximately 0.0740 grams.
Explanation:
To calculate the mass of copper that can be plated out of a 1.0 M Cu(NO3)2 solution using a current of 0.75 A for 5.0 minutes, we apply Faraday's laws of electrolysis and use the molar mass of copper.
Firstly, calculate the total charge passed through the solution using the formula Q = It, where Q is the charge in Coulombs, I is the current in Amperes, and t is the time in seconds. For 0.75 A over 5.0 minutes (or 300 seconds), we obtain Q = (0.75 A) × (300 s) = 225 Coulombs.
Next, convert the charge to moles of electrons using the charge of one mole of electrons, known as Faraday's constant (approximately 96485 C/mol). Thus, moles of electrons = 225 C / 96485 C/mol ≈ 0.00233 mol.
Since the copper plating involves Cu2+ ions gaining two electrons to become copper atoms (Cu2+ + 2e− → Cu), the moles of copper plated will be half the moles of electrons. So, 0.00233 mol / 2 = 0.001165 mol of copper.
Finally, calculate the mass of copper by multiplying the moles of copper by its molar mass (63.55 g/mol for Cu). Thus, mass of copper = 0.001165 mol × 63.55 g/mol ≈ 0.0740 g.
Therefore, the mass of copper that can be plated out using these conditions is approximately 0.0740 grams.
AgNO3(aq)+Na3PO4(aq) ionic equation
Answer:
3Ag⁺ + 3NO₃⁻ + 3Na⁺ + PO₄³⁻ → Ag₃PO₄(s) + 3Na⁺ + 3NO₃⁻
Explanation:
An ionic equation is a chemical equation where the electrolytes in aqueous solution are expressed as dissociated ions.
For the reaction:
3AgNO₃(aq) + Na₃PO₄(aq) → Ag₃PO₄(s) + 3 NaNO₃(aq)
AgNO₃(aq), Na₃PO₄(aq) and NaNO₃(aq) are dissociated in water thus:
AgNO₃(aq) → Ag⁺ + NO₃⁻
Na₃PO₄(aq) → 3Na⁺ + PO₄³⁻
NaNO₃(aq) → Na⁺ + NO₃⁻
The ionic equation is:
3Ag⁺ + 3NO₃⁻ + 3Na⁺ + PO₄³⁻ → Ag₃PO₄(s) + 3Na⁺ + 3NO₃⁻
I hope it helps!
3.4000*10^-6 + 5.7000*10^-3
Answer:
0.0057034 or 5.7034 * 10^-3
Using the conversion factor convert 1.56 ng NH3 to moles.
Answer:
9.02×10⁻¹¹ mol NH₃
Explanation:
Convert nanograms to grams:
1.56 ng NH₃ × (1 g / 10⁹ ng) = 1.56×10⁻⁹ g NH₃
Convert grams to moles:
1.56×10⁻⁹ g NH₃ × (1 mol NH₃ / 17.3 g NH₃) = 9.02×10⁻¹¹ mol NH₃
The answer is 9.02×10⁻¹¹ mol NH₃
How to convert grams to moles?Convert nanograms to grams:
1.56 ng NH₃ × (1 g / 10⁹ ng) = 1.56×10⁻⁹ g NH₃
Convert grams to moles:
1.56×10⁻⁹ g NH₃ × (1 mol NH₃ / 17.3 g NH₃) = 9.02×10⁻¹¹ mol NH₃
A mass of a substance in grams is numerically equal to its molecular weight. Example: A gram-mole of salt (NaCl) is 58.44 grams.
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why is specific heat capacity more useful then heat capacity when comparing two materials
Answer:
Explanation:
Specific heat capacity can be defined as the heat required to raise the temperature of a unit mass of a substance by 1kelvin.
The heat capacity on the other hand, expresses the heat required to raise the temperature of asubstance by 1kelvin.
When we use specific heat capacity, we are particular about the amount of heat that would be needed to actually cause a temperature change in a unit of a substance. This suggests that even if we don't have a complete substance, we can be sure that by knowing the mass of a unit of a body one can easily estimate how much heat is required to raise its temperature. The specific heat is fundamental in calculating the heat capacity of a body. Without the value of the specific heat, we cannot evalutate the heat capacity of a body.
A chemical factory is making soda ash (NA2CO3) from sodium bicarbonate. The production manager calculates they will make 80 tons of soda ash in the next 8 hour shift. At the end of the shift they weigh the produced soda ash at 74.3 tons. What was their percent yield?
Answer:
[tex]\boxed{\text{ 93 \%}}[/tex]
Explanation:
[tex]\text{\% yield} = \dfrac{\text{actual yield}}{\text {theoretical yield}} \times\text{100 \%}[/tex]
Data:
[tex]\begin{array}{rcr}\text{Actual yield} & = & \text{74.3 T}\\\text{Theoretical yield} & = & \text{80 T}\\\end{array}[/tex]
Calculation:
[tex]\text{\% yield} = \dfrac{\text{74.3 T}}{\text {80 T}} \times\text{100 \%} = \textbf{93 \%}}\\\\\text{The percent yield was } \boxed{\textbf{93 \%}}[/tex]
Radiocarbon dating can be used to determine the age of
A a sample less than a million years old
B a sample less than 100,000 years old
C a sample less than 50,000 years old
- D a sample less than five million years old
Answer:
Radiocarbon dating can be used to determine the age of a sample less than 50,000 years old - C
HELPPPPPPPPPPPPPPPPPPPP MEEEEEEEEEEEEEEEE PLZZZZZ WITHHHHH SCIENCE 13. Evaluate: What type of bonding does a material most likely have if it has a high melting point, is solid at room temperature, and easily dissolves in water?
14. Explain the following statement: All compounds are substances, but not all substances are compounds.
15. Suppose you have a found an unknown substance in a laboratory. It has the formula H2O2 written on the bottle. Is it water? How do you know?
13 An Ionic Bond
these are the characteristics of an ionic bond compounds like NaCl have these characteristics
14 substances could be compounds or elements hence not all substances are compounds
15 It is not water. The chemical composition of water is H2O not H202
(H202 is hydrogen peroxide and is toxic)
Baking soda is mixed with water, and no bubbles are produced. When baking soda is mixed with vinegar, it bubbles and foams rapidly.
What chemical property of baking soda is shown in this scenario?
flammability
color change
reactivity
boiling point
Answer:
Reactivity
Explanation:
The scenario shows that baking soda is reactive enough to produce bubbles with vinegar but not enough to do so in pure water.
Flammability, color change, and boiling point are all wrong. The scenario says nothing about these properties.
Answer:
Reactivity (Znk Elite Answerer is right)
Explanation:
I just took a test and I got it right. Even if the question says select all that apply there is only 1 answer and it is reactivity
Consider the following reversible reaction.
CO(g) + 2H2(g)
CH3OH(g)
What is the equilibrium constant expression for the given system?
A.Keg = [CO][H2]2
[CH3OH)
B.Keg = (СН3ОН)(CO)(H2)2
C.Keg=
[CO][H2]
[CH3OH]
D.Keg= [Ch3OH] [CO][H2]
Answer:
Explanation:
For any system in equilibrium, the molar concentration of all the species on the reactant side are related to those on the product side by a constant known as the equilibrium constant [tex]K_{eq}[/tex].
For a given reaction:
aA + bB ⇄ cC
[tex]K_{eq}[/tex] = [tex]\frac{[C]^{c} }{[A]^{a} [B]^{b} }[/tex]
The reaction equation is given as:
[tex]CO_{g}[/tex] + 2H₂[tex]_{g}[/tex] ⇆CH₃OH [tex]_{g}[/tex]
Note: All the species are in gaseous phase.
[tex]K_{eq}[/tex] = [tex]\frac{[CH_{3}OH ]}{[CO] [H_{2}] }[/tex]
Answer: [tex]K_c=\frac{[CH_3OH]{[CO][H_2]^2}[/tex]
Explanation:
Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients. It is expressed as [tex]K_{eq}[/tex]
[tex]CO(g)+2H_2(g)\rightarrow CH_3OH(g)[/tex]
The equilibrium constant in terms of concentration is written as :
[tex]K_eq=\frac{[CH_3OH]{[CO][H_2]^2}[/tex]
Thus the correct answer choice is B.
Which of the following equations is balanced correctly and has the correct products for the reactants RbNO3 and BeF2?
3RbNO3 + 3BeF2 → Be(NO3)3 + 3RbF, because Be increases in charge from 2+ to 3+ when it is replaced
2RbNO3 + BeF2 → Be(NO3)2 + 2RbF, because Be keeps a 2+ charge throughout the reaction
RbNO3 + BeF2 → BeNO3 + RbF2, because Be keeps a 1+ charge throughout the reaction
2RbNO3 + BeF2 → Be(NO3)2 + 2RbF, because Be increases in charge from 1+ to 2+ when it is replaced
Answer:
2RbNO₃ + BeF₂ → Be(NO₃)₂ + 2RbF, because Be keeps a 2+ charge throughout the reaction
Explanation:
2RbNO₃ + BeF₂ → Be(NO₃)₂ + 2RbF, because Be keeps a 2+ charge throughout the reaction
Rb is a +1 cation, NO3 is a -1 anion, Be is a +2 cation and F is a -1 anion.
In writing an ionic compound the charge of the cation becomes the subscript of the anion and the charge of the anion becomes the subscript of the cation.
So the ionic compound formed between Be2+ and F- is BeF2. The ionic compound formed between Be2+ and NO3- is Be(NO₃)₂.
As there are two NO₃ on the product side it is balanced by writing a 2 coefficient before RbNO₃ on the reactant side.
And as there are two F on the reactant side it is balanced by writing a 2 coefficient before RbF on the product side.
Answer:
2RbNO3 + BeF2 → Be(NO3)2 + 2RbF, because Be keeps a 2+ charge throughout the reaction
that equal volumes of gas under the same conditions have equal numbers of molecules. This concept is a very important one, as it will be used often in future studies.
Answer:
This one is easy. It's the Avogadros' Hypothesis or Avogadros' Law, where the equal volumes of gases in SAME conditions have an equal amount of molecules!
Answer:
Avagadro’s law states at constant temperature and pressure, volume is directly proportional to the number of molecules of the gas.
For example
At STP that is standard temperature and pressure at which T = 273K and P = 1 atm
Volume occupied by 1 mole ([tex]6.022\times 10^{23}[/tex] gas molecules) of any gas is equal to 22.4L
That is
1 mole = 22.4L
2 mole = 44.8 L
3 mole = 67.2 L
So 1 mole of [tex]CO_2[/tex] gas =22.4L ([tex]6.022\times 10^{23}[/tex] gas molecules)
1 mole of [tex]H_2[/tex] gas =22.4L ([tex]6.022\times 10^{23}[/tex] gas molecules)
1 mole of [tex]Cl_2[/tex] gas =22.4L ([tex]6.022\times 10^{23}[/tex] gas molecules)
What happens when a gas becomes ionized?
A. Deposition Occurs
B. Sublimation Occurs
C. It becomes a liquid
D. A plasma is formed
Answer:
A. Deposition Occurs
Explanation:
When a gas becomes ionized, deposition occurs.
Answer: Option (D) is the correct answer.
Explanation:
A plasma is defined as the state of matter in which gas exists in hot ionized formed that has similar number of positively charged ions and negatively charged electrons.
Whereas deposition is the change from gaseous to liquid or solid state in which particles come closer to each other.
Sublimation means direct conversion of solid into gaseous phase without undergoing liquid phase.
Thus, we can conclude that when a gas becomes ionized then a plasma is formed.
How did Bohr propose the particles within atom are arranged
A. Protons and electrons form the nucleus with neutrons orbiting it
B. Protons make up the atoms nucleus with electrons and neurons orbiting it
C. Protons and neutrons from the nucleus of the atom with electrons orbiting it
D. Neutrons make up the atoms nucleus with electrons and protons orbiting it
Answer:
Protons and neutrons form the nucleus of the atom with electrons orbiting it.- C.
The correct answer is C. Protons and neutrons form the nucleus of the atom with electrons orbiting it
Explanation:
Bohr model was proposed by Niels Bohr in 1913 to explain the structure of atoms, in this Bohr stated electrons (particles negatively charge) orbit the nucleus that contains both neutrons (neutral particles) and protons (positively charged particles). Additionally, according to this model electrons were placed in different levels of energy and orbit the nucleus constantly, resembling planets in the Solar System, although the Bohr model was the first one that integrated principles related to energy levels and changes in energy in electrons. Thus, Bohr proposed "Protons and neutrons form the nucleus of the atom with electrons orbiting it".
A nanotechnology equipment requires 7.40 x 10^18 atoms of potassium. What is the mass of this sample?
Answer:
4.81×10⁻⁴ g K
Explanation:
Convert atoms to moles:
7.40×10¹⁸ atoms K × (1 mol K / 6.02×10²³ atoms) = 1.23×10⁻⁵ mol K
Convert moles to mass:
1.23×10⁻⁵ mol K × (39.1 g K / mol K) = 4.81×10⁻⁴ g K
3. What do we call atoms of the same elements with different mass numbers?
Answer:
Isotopes
Explanation:
We call atoms of the same elements with different mass numbers isotopes.
Round off the measurement to three significant figures 12.17º C
The temperature 12.17º C rounded to three significant figures is 12.2º C, taking into account the fourth figure which is a 7. This causes an upward rounding due to the rule of significant figures.
To round off the temperature of 12.17º C to three significant figures, we look at the fourth figure which is a 7. Since 7 is greater than 5, we round the third significant figure up, which results in a rounded temperature of 12.2º C.
In the context of rounding based on significant figures, the temperature value is often dependent on the least precise measurement in a data set or calculation. As an example, if we had another measurement of 13.7 kg, which is to the 0.1 decimal place, any resultant calculation would need to be rounded to the tenths place for consistency, giving us a hypothetical final answer of 15.2 kg, to match the precision of 13.7 kg.
3. Sodium carbonate (Na2CO3) is formed from the reaction between
O A a weak acid and a strong base
B a strong acid and a strong base
C a strong acid and a weak base
OD a weak acid and a weak base
Na2C03 is formed through the reaction of
NaOH and H2CO3 namely sodium hydroxide and carbonic acid
NaOH -> strong base
H2CO3-> weak acid
Answer:
A. a weak acid and a strong base
Explanation:
An acid-base reaction is a chemical reaction between an acid and a base to form salt and water. The reaction is also known as a neutralization reaction.
An acid is a compound that when in aqueous solution it dissociate to form an hydrogen ion(H+).
A base is a compound that when in aqueous solution it produces an hydroxide ion(OH-) .
A strong acid is an acid that completely dissociate in an aqueous solution.
A strong base is a base that completely dissociate in an aqueous solution.
The reaction that produce a salt like sodium carbonate is a chemical reaction between a weak acid and a strong base. The chemical reaction can be represented as follows
H2CO3 + 2NaOH → Na2CO3 + 2H2O
H2CO3 is a weak acid as it partially dissociate in aqueous solution.
NaOH is a strong base as it completely dissociate in aqueous solution.
A 35.40 gram hydrate of sodium carbonate, Na2CO3•nH2O, is heated to a constant mass. Its final weight is 30.2 g. What is formula for the hydrate?
Answer:
Na₂CO₃•H₂O
Explanation:
After it is heated, the remaining mass is the mass of sodium carbonate.
30.2 g Na₂CO₃
Mass is conserved, so the difference is the mass of the water:
35.4 g − 30.2 g = 5.2 g H₂O
Convert masses to moles:
30.2 g Na₂CO₃ × (1 mol Na₂CO₃ / 106 g Na₂CO₃) = 0.285 mol Na₂CO₃
5.2 g H₂O × (1 mol H₂O / 18.0 g H₂O) = 0.289 mol H₂O
Normalize by dividing by the smallest:
0.285 / 0.285 = 1.00 mol Na₂CO₃
0.289 / 0.285 = 1.01 mol H₂O
The ratio is approximately 1:1. So the formula of the hydrate is Na₂CO₃•H₂O.
Na₂CO₃•H₂O
Further explanationGiven:
A 35.40 g hydrate of sodium carbonate, Na₂CO₃•nH₂O, is heated to a constant mass.Its final weight is 30.2 g.Question:
What is the formula for the hydrate?
Problem-solving:
We will solve problems related to The Law of Definite Proportion (Proust's Law).
"The ratio of the masses of elements in each compound is always constant. Put differently, a given compound invariably contains a similar proportion of elements by mass."
The heating reaction of the hydrate of sodium carbonate is as follows:
[tex]\boxed{ \ Na_2CO_3.nH_2O \xrightarrow{\text{heat}} Na_2CO_3 + nH_2O \ }[/tex]
Condition:
Before heating: 35.40 g of Na₂CO₃•nH₂O (hydrate)After heating: 30.20 g of Na₂CO₃ (anhydrate)The mass of H₂O that has left the compound is [tex]\boxed{ \ 35.40 - 30.20 = 5.2 \ g \ }[/tex][tex]\boxed{ \ Na_2CO_3.nH_2O \xrightarrow{\text{heat}} Na_2CO_3 + nH_2O \ }[/tex]
35.4 g 30.2 g 5.2 g
We want to determine the amount of water (with the symbol n) so that the formula for the hydrate can be known.
Recall that [tex]\boxed{ \ Moles = \frac{Mass \ (g)}{Mr} \ }[/tex]
Let us prepare the number of moles of Na₂CO₃ and H₂O respectively.
Mr Na₂CO₃ = 106 g/mol ⇒ [tex]\boxed{ \ moles = \frac{30.2}{106} \rightarrow \boxed{ \ 0.285 \ } \ }[/tex] Mr H₂O = 18 g/mol ⇒ [tex]\boxed{ \ moles = \frac{5.2}{18} \rightarrow \boxed{ \ 0.289 \ }\ }[/tex]Finally, we use the mole ratio to write the formula. Find the water-to-anhydrate mole ratio.
[tex]\boxed{ \ Na_2CO_3 \ : \ H_2O = 1 \ : \ n \ }[/tex]
[tex]\boxed{ \ H_2O \ : \ Na_2CO_3 = n \ : \ 1 \ }[/tex]
[tex]\boxed{ \ n \ : \ 1 = 0.289 \ : \ 0.285 \ }[/tex]
[tex]\boxed{ \ n = \frac{0.289}{0.285} \times 1 \ }[/tex]
Thus, the value of n after rounding is [tex]\boxed{ \ n = 1 \ }[/tex]
Substitute n = 1 into Na₂CO₃•nH₂O.
Therefore, the formula for the hydrate is [tex]\boxed{\boxed{ \ Na_2CO_3.H_2O \ }} [/tex]
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Why does magnesium oxide have a high melting point?
Please give as much information as possible?
Magnesium oxide is an ionic compound ( because it consists of a metal and a non-metal)
In ionic compounds, electrons from the outer shell exchange between the atoms so that they each get a full outer shell. Once these electrons are exchange, the atoms will become ions. One ion will have a positive charge, and the other ion will have a negative charge. The positive and negative ions then bond strongly together in a lattice structure, due to the electrostatic forces of attraction.
These electrostatic forces of attraction are very strong and require a lot of energy to break, as such the compound will have a high melting point.
__________________________________________
Now lets look at the ionic bonding between magnesium and oxygen:
In the outer shell of Magnesium, there are 2 electrons.
In the outer shell Oxygen, there are 6 electrons.
Magnesium gives it's two electrons to Oxygen, so that the Oxygen now has a full outer shell of 8 electrons. However, since Oxygen gained two electrons, it will form a negatively charged ion with a charge of -2.
Since Magnesium lost the two electrons, it's second shell (which has 8 eletrons) now becomes the outer shell. So Magnesium also now has a full outer shell. But since it has lost two electrons, it becomes a positively charged ion with a charge of + 2.
The positive Magnesium ion and negative Oxygen ion and now strongly attracted to each other, and form a strong ionic compound (magnesium oxide) with a lattice structure.
The electrostatic forces of attraction between the positive Magnesium and negative Oxygen are so strong that a lot of heat and energy are needed to break them.
Therefore magnesium oxide has a high melting point.
How are precipitation and temperature different between the polar and tropical climate zones? Explain.
Answer:
Earth has tremendous diversity of its ecosystems. Different regions are referred to as climate biomes to understand patterns of weather, biology, and natural events.
Explanation:
The greatest difference between tropical and polar climates is the difference in temperature. Tropical climates are located near the Equator and receive more sun year-round than anywhere else on Earth, while polar climates are the farthest from the Equator and receive the least sunlight and heat of any part of the globe. This makes the winters of polar climates fierce and the summers short, while practically every day in a tropical climate is hot. While both climates might bring to mind precipitation (such as rain in the tropics and snow at the poles), both can also be quite dry. Antarctica is considered the largest desert in the world, since almost no snow falls toward the center of the continent. Tropical deserts, such as the Namib of Africa, are extremely hot and dry, making it difficult for any life to survive.
Answer: In the polar climate zone, it is very cold and dry, receiving less precipitation every year. The tropical climate zone has very warm and hot temperatures all year round, receiving much rain.
Explanation: I read the lesson and it makes sense
Write the equation sulfur dioxide reacts with oxygen to form sulfur trioxide.
Answer:
2SO2 + 02 ====>2SO3
Explanation:
SO2 + O2 ===> SO3
The only thing you can do is balance the oxygens that are on the sulfurs. When you do that the oxygen (O2) can make the difference.
SO2 + O2 ===> 2SO3
Bring the oxygen on the right up to 6. When you do that, the sulfurs are out of balance. So balance the sulfurs.
2SO2 + 02 ====>2SO3
Your equation is now balanced. The trick is not to leave the number of oxygens on the right as an odd number. When you fix that problem, the equation will balance easily.
Species S O
Left 2 2+4=6
Right 2 2*3 =6
Balanced.
100 g of 20% salt solution is mixed with 200g of 10% salt solution. Find out the concentration of the resulting solution.
Explanation:
The total mass is:
100 g + 200 g
= 300 g
The mass of salt is:
0.20 (100 g) + 0.10 (200 g)
= 20 g + 20 g
= 40 g
So the concentration is:
40 g / 300 g
≈ 13.33%
Round as needed.
5. Assuming the temperature is held constant, how could you increase the pressure inside a
container by a factor of 37
Answer:
Decrease the volume or increase the number of moles by a factor of 37.
Explanation:
If the contents are a gas,
pV = nRT
If T is constant
[tex]p \propto \dfrac{n}{V}[/tex]
There are two ways to increase the pressure inside the container.
1. Decrease the volume
If you decrease the volume by a factor of 37, the pressure will increase by the same factor.
2 Increase the number of moles
If you add 36 times the number of moles, you will have 37n moles. Increasing the amount of gas by a factor of 37 increases the pressure by the same factor.
To increase the pressure inside a container by a factor of 37 while keeping the temperature constant, the volume of the gas must be reduced to 1/37th of its original volume, as per Boyle's Law, which states that pressure and volume are inversely proportional.
Assuming the temperature is held constant, to increase the pressure inside a container by a factor of 37, you must reduce the volume of the gas. This is based on Boyle's Law, which states that, for a given mass of gas at constant temperature, the pressure of the gas is inversely proportional to its volume. This means if you want to increase the pressure inside the container, you have to decrease the volume of the container correspondingly.
For instance, if the original pressure of the gas is P, and the volume is V, to increase the pressure by a factor of 37 (making it 37P), you would need to reduce the original volume (V) to V/37. This is because P1*V1 = P2*V2, where P1 and V1 are the initial conditions and P2 and V2 are the final conditions, assuming no change in the amount or temperature of the gas.
A meteorologist wants to create a visual aid different gases in earths atmosphere which type of chart or graph would best convey the data
Answer:
A pie chart
Explanation:
A pie chart would be the ideal type of chart to create this visual aid. A pie chart is simpler visually and easily understood. It can show data as portions or percentages of a whole. Since what they want is to present the different gases found in Earth's atmosphere, they can show what percentage of the different gases make up the atmosphere.
It is simpler because the size of each portion or "slice" of the pie chart itself can reveal a lot about the data without even reading the numbers.
Answer:
Pie chart
Explanation:
An insulated container that measures temperature change is a _______. It is used to calculate change in _________ (which is DH.)
the D is a triangle
Answer:
An insulated container that measures temperature change is a calorimeter. It is used to calculate change in enthalpy (which is ΔH.)
Explanation:
Enthalpy characterize a system from the energy point of view and it depends on the changes in the temperature of the system, the pressure (which is held constant) and the volume of the system (you know this because is an isolated system. Using a calorimeter is a key step in calculating the enthalpy, let's say for a chemical reaction.