A chemical property of copper is its what?
1 point

A. density
B. reactivity
C. color
D. melting point

22.  The free body diagram would not apply to the woman jumping off the floor as she would not be experiencing any normal force as she is airborne.

23.  For the box to be moving with constant speed, it would mean that there is no acceleration.  That also means that there would be no net force in the axis that the box is being pushed in.  So the applied force, F, would have to equal the frictional force f.

24.  First determine the weight of the sphere due to gravity:

F = ma

F = (175)(-9.8)

F = -1715N

Now, assuming the tension is from the top of the chain (because it's the only logical reason I can deduce as why the mass of the chain was given), you would have to find the weight of the chain due to gravity as well:

F = ma

F = (12)(-9.8)

F = -118N

The chain has to not only support the weight of the sphere, but also the weight of the chain itself, so the tension force is equal to the sum of the weights of both the sphere and the chain.

(1715)+(118) = 1833N  (Value is positive because tension acts in the direction opposite to the force it is withstanding)

Answer: D. 0.29 m

Explanation:

We will use the following equations to describe the leap of the cat:

[tex]y=V_{o}sin\theta t-\frac{gt^{2}}{2}[/tex]   (1)

[tex]V_{y}=V_{oy}-gt[/tex]   (2)

Where:

[tex]y[/tex]  is the height of the cat  

[tex]V_{oy}=V_{o}sin\theta[/tex] is the cat's initial velocity

[tex]\theta=60\°[/tex]

[tex]g=9.8m/s^{2}[/tex]  is the acceleration due gravity

[tex]t[/tex] is the time

[tex]V_{y}[/tex] is the y-component of the velocity

Now the cat will have its maximum height [tex]y_{max}[/tex] when [tex]V_{y}=0[/tex]. So equation (2) is rewritten as:

[tex]0=V_{oy}-gt[/tex]   (3)

Finding [tex]t[/tex]:

[tex]t=\frac{V_{oy}}{g}=\frac{V_{o}sin\theta}{g}[/tex]   (4)

[tex]t=\frac{2.74 m/s sin(60\°)}{9.8m/s^{2}}[/tex]   (5)

[tex]t=0.24 s[/tex]   (6)

Substituting (6) in (1):

[tex]y_{max}=(2.74 m/s)sin(60\°) (0.24 s)-\frac{(9.8m/s^{2})(0.24 s)^{2}}{2}[/tex]   (7)

Finally:

[tex]y_{max}=0.287 m \approx 0.29 m[/tex]   (8)

The highest point of the cat’s trajectory, considering the initial speed and angle, is found to be 0.29 m using kinematic equations. Therefore, the correct answer is option D.) 0.29 m.

To find the highest point of the cat's trajectory, we need to focus on the vertical component of the initial velocity and use the kinematic equation for vertical motion.

The initial speed of the cat is given as 2.74 m/s at an angle of 60.0° above the ground.

We first decompose this initial velocity into its vertical component:

Vertical component of velocity(Vy),

At the highest point of the trajectory, the vertical velocity(Vfy) becomes zero. We use the following kinematic equation to find the maximum height (h):

Since Vfy = 0 at the highest point of the trajectory:

Solving for h:

Thus, the highest point of the cat’s trajectory is 0.29 m. The correct answer is D. 0.29 m.

Answer:

Steps in the order they should occur:

Explanation:

This question is addressed to reflect on the scientific method, and so it deals with the logical steps that are followed regularly in such process.

It is the observation of a natural phenomenum what sparks the whole process. In this case, the student observes that there are acidic foods.

After such observation, some minds, the curious minds, start to ask questions: why?, how?, when?, what happens if? Numerous questions might arise, it is the curiosity attitude, that accompanies the scientific mind. So, the student asks a question about food’s acidity.

The trained scientist then elaborate a hypothesis : a logical tentative prediction which relates a thesis and a conclusion, in the form if _________ then ________, addresed to answer the question. This hypotheisis must be testable, so it must contains objective variables, which can be verified through an experiment by measurements that can be replicated by any one. So, at this point fhe student creates a hypothesis about the acidity.

The next steps are:

In ORDER:

5,2,1,6,4,3

The 150 scale if my calculations are correct

As we have formula for mass spring system

F= kx           ( where k is spring constant , x is displacement , F is the force acting due to load)

To find =x

So  x=F/k

x= (4N) / (5N/m)

x= 0.8 m

Answer:

The answer is 24.2 N.

Explanation:

Y- component = 10 N + 15 cos (30) = 23 N (North)

X - component = 15 N - 15 sin (30) = 7.5 N (west)

As, East, west and North are opposite direction so minus,

Magnitude = √ 23² + 7.5²

                  = 24.2 N.

The magnitude of the resultant force is 22.99 N.

The given forces are:

A force of 10 N north

A force of 15 N west

A force of 15 N 30 degrees east of north

The first two forces can be represented by vectors  

A and   as follows:

[tex]$\vec{A} = 10 \hat{\imath}$\\$\vec{B} = -15 \hat{\jmath}$[/tex]

The third force can be decomposed into its components as follows:

[tex]$\vec{C} = 15 \cos{30^\circ} \hat{\imath} + 15 \sin{30^\circ} \hat{\jmath}$\\= 12.5 \hat{\imath} + 7.5 \hat{\jmath}$[/tex]

The resultant force  

R is the sum of the three forces:

[tex]\vec{R} = \vec{A} + \vec{B} + \vec{C}\\= 10 \hat{\imath} - 15 \hat{\jmath} + 12.5 \hat{\imath} + 7.5 \hat{\jmath}\\= 22.5 \hat{\imath} - 7.5 \hat{\jmath}[/tex]

The magnitude of  

R is:

[tex]\| \vec{R} \| = \sqrt{(22.5)^2 + (-7.5)^2}[/tex]

= \sqrt{510.25}

= 22.99 N

Therefore, the magnitude of the resultant force is 22.99 N.

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Final answer:

To find the height of the cliff from which a rock falls in 3 seconds, we use the formula s = ut + ½ at², with an initial speed (u) of 0 m/s and acceleration (a) of 9.81 m/s² due to gravity. The calculation shows that the cliff is approximately 44.145 meters high.

Explanation:

The question requires the calculation of the height from which a rock falls off a cliff, given that it falls for 3 seconds. The scenario assumes Earth's gravity as the only acting force, thereby ignoring air resistance. To determine the height of the cliff, we will use the kinematic equation for freely falling objects:

s = ut + ½ at²

where:

Plugging the values into the equation:

s = 0 m/s * 3 s + ½ * 9.81 m/s² * (3 s)²

s = ½ * 9.81 m/s² * 9 s

s = 4.905 m/s² * 9 s
s = 44.145 m

Hence, the cliff is approximately 44.145 meters high.

The answer is "Three".

At the point when individuals take studies for factual purposes or when the Statistics Agency comes around and gets everyone's data, data from one individual is one information point for them. Toward the finish of its exploration or overview, the organization will have accumulated numerous bits of data from numerous individuals. One piece of information equals with one data point.

Different isotopes of an element have different numbers of electrons.

Isotopes are atoms of the same element that have different numbers of neutrons. Since the number of electrons in an atom is equal to the number of protons in the nucleus, isotopes with different numbers of neutrons will have different overall numbers of electrons. For example, carbon-12 and carbon-14 are isotopes of carbon, and carbon-12 has 6 electrons while carbon-14 has 8 electrons.

Isotopes are variants of chemical elements with the same number of protons but different numbers of neutrons. They have various practical applications. For example, radioactive isotopes are used in medicine for imaging and cancer treatment, while stable isotopes are used in tracing chemical reactions, dating archaeological artifacts, and studying geological and environmental processes.

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since Romeo throw the pebble from the ground at a position 9.8 m below the window and at horizontal distance of L = 9.7 m

It is given that he throw the pebble such that it hit the window only with horizontal speed.

So here vertical speed of the pebble will become zero as it hit the window

[tex]v_f^2 - v_i^2 = 2 a h[/tex]

so here we know that in y direction

[tex]v_f = 0[/tex]

[tex]a = - 9.8 m/s^2[/tex]

[tex]h = 9.8 m[/tex]

now we will plug in all values

[tex]0 - v_i^2 = 2*(-9.8)(9.8)[/tex]

[tex]v_i = 13.8 m/s[/tex]

also the time taken by the pebble to reach the window is given by another equation

[tex]v_f = v_i + at[/tex]

[tex]0 = 13.8 - 9.8*t[/tex]

[tex]t = 1.41 s[/tex]

now in the same time if stone reached the horizontal distance of L = 9.7 m so we can find its horizontal speed as

[tex]v_x = \frac{L}{t}[/tex]

[tex]v_x = \frac{9.7}{1.41}[/tex]

[tex]v_x = 6.9 m/s[/tex]

so the speed of the pebble will be 6.9 m/s when it will hit the window

Final answer:

To find the pebbles' impact velocity at Juliet's window, we used the time to fall the height of 9.8 meters to calculate the necessary horizontal velocity. The calculated horizontal impact velocity is 6.9 m/s.

Explanation:

Calculating Pebble's Velocity at Juliet's Window

To find the horizontal velocity with which Romeo's pebbles hit Juliet's window, we need to consider the pebbles' horizontal displacement (L) and vertical displacement (h). Since there is no acceleration horizontally, the horizontal component of velocity will remain constant throughout the motion. However, vertical motion is influenced by gravity, with a downward acceleration of 9.8 m/s2 (the value of gravitational acceleration).

We first calculate the time (t) it takes for the pebble to fall 9.8 meters using the equation for vertical motion:

1/2 × g × t2 = h

Substituting g = 9.8 m/s2 and h = 9.8 m, we find: 1/2 × 9.8 m/s2 × t2 = 9.8 m thus, t2 = 2 and t = √2 ≈ 1.41 s

Using the time it takes to reach Juliet's window, we can calculate the horizontal velocity (vx) needed: vx = L / t

Substituting L = 9.7 m and t ≈ 1.41 s, we get: vx = 9.7 m / 1.41 s ≈ 6.88 m/s

To two significant figures, the horizontal velocity with which the pebbles hit Juliet's window is 6.9 m/s.

Yes, how can I help you?

The IB Physics course, similar to AP Physics, provides high school students with an in-depth introduction to physics at a college level. Though these courses can prove challenging, as evidenced by a 30% withdrawal rate at ABC High School, they cover critical topics of physics and lay the groundwork for more advanced studies.

The question asks if anyone is taking IB Physics. The International Baccalaureate (IB) Physics course is similar to the Advanced Placement (AP) Physics course. Like AP Physics, the IB Physics course is a challenging program that provides high school students an in-depth study of physics similar to a college introductory course. However, these courses can be quite demanding, as denoted by the withdrawal rate from an elementary physics course in ABC High School being 30 percent for any given term.

In an IB Physics or AP Physics course, you will cover topics such as mechanics, thermodynamics, waves and sound, light and optics, and nuclear physics. The curriculum promotes depth of understanding over breadth of content, and organizes concepts around seven major themes known as the 'Big Ideas'. Despite a fear amongst many of difficult equations or memorizing formulas, these courses serve as a good foundation for future advanced physics courses at the college level.

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With questions involving Forces, it is best to draw a force diagram to model the problem, like the one shown below

We have two tension acting on the particle; T₁ and T₂. The tensions are vectors directed toward the ceiling.

There's also the force as weight acting vertically downwards from the particle. This force is 150N.

As the tension force acting in an angle, we will have to consider the sine and sine components of the tensions. 

We will also solve the force in the direction of x-axis and y-axis

Solving in x-axis direction:

T₂ cos 40° - T₁ cos 40° = 0

T₂ cos 40° = T₁ cos 40°

T₂ = T₁ ...(Eq 1)

Solving in y-axis direction:

T₁ sin 40° + T₂ sin 40° - 150N = 0

T₁ sin 40° + T₂ sin 40° = 150 ⇒ we know from (Eq 1) that T₁ = T₂

2T₁ sin 40° = 150

T₁ sin 40° = 75

T₁ = 75 ÷ sin 40°

T₁ = 116.7 N

Since T₁ = T₂, so T₂ = 116.7N

I hope this helps

As per Coulomb's law of force we can say

[tex]F = \frac{kq_1q_2}{r^2}[/tex]

here we can say

[tex]q_1,q_2[/tex]= magnitude of two charges

r = distance between two charges

so here we can say that force between two charges depends on

(i)product of charge of two point charges

(ii)distance between the two point charges

so here if we increase the distance force will decrease and vice versa.

So correct statement for the electrostatic force is given as

D. The electric force varies with the distance between the charges. The closer they are, the stronger the force. The farther apart they are, the weaker the force.

Answer:

D

Explanation:

weight of person on earth = 764 N

mass ?

w=mg           (g =9.8m/s²)

m = w/g

m= 764/9.8

m= 77.9 kg

Weight of person on other planet =5320 N

w=mg

g =w/m

g= 5320 / 77.9

g =68.3 m/s² ( acceleration due to gravity on other planet)

The 'weight' of an object depends directly on the acceleration of gravity in the place where he happens to be.

This guy weighs 764N on Earth, and 5320N where he is now.  So wherever he is now, the acceleration of gravity there is  (5320/764) = 6.96 times the acceleration of gravity on Earth.

The acceleration of gravity on Earth is 9.81 m/s², so it's (9.81 x 6.96) = 68.3 m/s² on the surface of the mystery planet where he is now.

==========================================

Note:  The biggest, heaviest, most massive object in the solar system ... except for the sun itself ... is the planet Jupiter, where the acceleration of gravity is 24.8 m/s².

On the planet where our man has landed, gravity is 2.75 times as strong as on Jupiter, and about 1/4 as strong as on the Sun itself.  He weighs almost 1200 pounds there.  He certainly can't walk around, and he probably won't be able to lift off in his rocket either.

A small increase in aperture will result in a small increase in brightness.

Answer:

large increase in brightness

Explanation:

just trust me.

density (P) Mass (M) volume (V)

P=M/V

The relation that exists between the density (D), mass (M), and volume (V) body are related as follows -

D = M/V

The density (D), mass (M), and volume (V) of any body are use to give information about the physical properties of body.

Given is the density (D), mass (M), and volume (V) of a body.

The following relation exist between the density (D), mass (M), and volume (V) body are related as follows -

density (D) = mass (M) / volume (V)

D = M/V

Density is the measurement of amount of mass per unit volume of the body. Volume is the measurement of total space occupied by the body and mass is the measurement of amount of matter inside body.

Therefore, the relation that exists between the density (D), mass (M), and volume (V) body are related as follows -

D = M/V

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The 1.0 lb bag of feathers, dropped under free fall conditions from the building, would have fallen approximately 11 meters after 1.5 seconds, according to the physics formula for distance traveled during free fall. The correct answer is (B) 11 m.

In this problem, Bob is examining the gravitational force acting on a falling object, specifically a 1.0 lb bag of feathers. To determine the distance the feathers have fallen after 1.5 seconds under free fall conditions, we utilize the physics formula for distance traveled during free fall, represented as d = 0.5 * g * t^2, where d is the distance, g is the gravitational acceleration (9.8 m/sec2), and t is the time.

Substitute the given values into the equation, you get d = 0.5 * 9.8 * (1.5)^2. After calculating, it results in approximately 11 meters. Therefore, the bag of feathers has fallen 11 meters after 1.5 seconds, assuming it has reached free fall. This implies that the correct answer is (B) 11 m.

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The bag has traveled approximately 7.4 meters after falling for 1.5 seconds.

To determine the distance the bag has traveled after falling for 1.5 seconds, we can use the equation of motion d = ½gt^2, where d is the distance, g is the gravitational acceleration, and t is the time.

Given that the gravitational acceleration is 9.8 m/sec^2 and the time is 1.5 seconds, we can substitute these values into the equation to calculate the distance:

d = ½ × 9.8 × (1.5)^2

Simplifying the equation, we have:

d = 0.5 × 9.8 × 2.25 = 7.425 m

Therefore, the bag has traveled a distance of approximately 7.4 meters after falling for 1.5 seconds.

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But rocks are not unchangeable! Just like the water cycle, rocks undergo changes of form in a rock cycle. A metamorphic rock can become an igneous rock, or a sedimentary rock can become a metamorphic one. Unlike the water cycle, you can’t see the process happening on a day-to-day basis. Rocks change very slowly under normal conditions, but sometimes catastrophic events like a volcanic eruption or a flood can speed up the process. So what are the three types of rocks, and how do they change into each other? Keep reading to find out!

Just like the water cycle, rocks undergo changes of form in a rock cycle. A metamorphic rock can become an igneous rock, or a sedimentary rock can become a metamorphic one. Unlike the water cycle, you can’t see the process happening on a day-to-day basis. Rocks change very slowly under normal conditions, but sometimes catastrophic events like a volcanic eruption or a flood can speed up the process. So what are the three types of rocks, and how do they change into each other? Keep reading to find out!

AS S =Vit +1/2 at²

Vi = 0   (as initially an object is at rest when it starts motion)

som

S = 1/2 at²

2S/t² =a  ( from this we can find acceleration)

Answer:

The stopping car has negative acceleration.

Explanation:

 We know acceleration is the rate of change of velocity. That is

            Acceleration(a) = ( Final velocity - Initial velocity )/ Time taken.

            Here Final velocity = 0 km/h( car stops) and initial velocity = 30 km/h

             So acceleration = (0-30)/time = -30/ time

             Time is always positive , so -30/time is negative, so the stopping car has negative acceleration.

Answer:

What is the wavelength in nm of a light whose first order bright band forms a diffraction angle of 19.0°, and the diffraction grating has 600.0 lines per mm?

543 nm

Explanation:

The wavelength in nm of a light whose first order bright band forms a diffraction angle of 19.0° is 543 nm.

The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave.

Using Huygen's principle of light, we have an expression

nλ =d sinθ

where, n is the order of maximum

           λ is the wavelength of light

           d is the distance between the lines on diffraction grating

           θ is the angle.

The distance between the lines on diffraction grating  is

d = 1 / (600 x 1000) or 0.00000167 m

For first order bright band, n = 1

Then, the wavelength will be

1 x λ = 0.00000167 x sin19.0°,

λ    = 0.000000543 m

 λ   = 543 nm

Thus, the wavelength of the first order bright band is 543 nm .

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Answer:

high temp star.

Explanation:

this is the correct answer on my odyssey ware

Answer:

Option B, 11 m is the correct answer.

Explanation:

We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this case u = 0 m/s , t = 1.5 seconds , a = acceleration due to gravity = [tex]9.8m/s^2[/tex], we need to find displacement

Substituting

     [tex]s= 0*1.5+\frac{1}{2}*9.8*1.5^2\\ \\ s=11.025m[/tex]

So option B, 11 m is the correct answer.

There are three laws which are postulated by Kepler for planetary motion.

Kepler's first law: As per the first law of Kepler,the orbits of planets around the sun is elliptical in nature in stead of circular. The sun is situated always at one of its foci.

Second law: Planets are moving in such a way that the areal velocity of the planets are constant i.e planets sweep out equal ares in equal interval of time.

Third law: The square of time period of planets around the sun is directly proportional to the cube of semi major axis.

       [tex]Mathematically\ T^{2} \alpha\ R^{3}[/tex]

where T is the time period and R is semi major axis.

Hence the correct answer to the question is C i.e third,first,second.

Explanation :

Kepler gives three laws of planetary motion :

First law :

First law is also known as the law of orbits. It states that all planets revolve in an elliptical orbit. The sun is present at one of its foci.

Second law :

Second law is also known as the law of areas. It states that draw a hypothetical line from the midpoint of the sun to the midpoint of the planet. This will sweep out the same areas in identical interval of time.

Third law :

This is also known as the law of periods. It states that the square of the orbital time period (T) is directly proportional to the cube of semi-major axis (a).

i.e. [tex]T^2\propto a^3[/tex]

So, Correct labeling is :

W: Third law

X: First law

Y: Second law

Hence, the correct option is (C).

Assume the motion when you are in the car or in the school bus to go to the school.

To describe the motion the first thing you need is a point of reference. Assume this is your house.

This should be a description:

Before coming into conclusion first we have to understand both scalar and vector .

A scalar quantity is a physical quantity which has only magnitude for it's complete specification.

A vector quantity is that physical quantity which not only requires magnitude but also possesses direction for it's complete specification.

So the most important factor that differentiate vector from scalar is the direction.

As per the question the student is doing an experiment where he is recording the data obtained during the process.

In order to arrange them in data table, he should ask about the direction of the quantity under consideration.

Hence the correct option is the third option(C)i.e does the measurement include direction?

The correct answer is:

Does the measurement include direction?

In fact, the basic difference between a scalar and a vector is that a scalar does not have a direction (it only has a magnitude), while a vector has both magnitude and direction. Therefore, if the answer to this question is "yes", it means the quantity is a vector, otherwise it is a scalar.