A circular loop of wire with a radius of 4.0 cm is in a uniform magnetic field of magnitude 0.069 t. the plane of the loop is perpendicular to the direction of the magnetic field. in a time interval of 0.46 s, the magnetic field changes to the opposite direction with a magnitude of 0.044 t. what is the magnitude of the average emf induced in the loop?

The energy change associated with the transition from n = 3 to n = 2 in the hydrogen atom is about -3.03 × 10⁻¹⁹ J

[tex]\texttt{ }[/tex]

The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is :

[tex]\large {\boxed {E = h \times f}}[/tex]

E = Energi of A Photon ( Joule )

h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )

f = Frequency of Eletromagnetic Wave ( Hz )

[tex]\texttt{ }[/tex]

The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.

[tex]\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}[/tex]

[tex]\large {\boxed {E = qV + \Phi}}[/tex]

E = Energi of A Photon ( Joule )

m = Mass of an Electron ( kg )

v = Electron Release Speed ( m/s )

Ф = Work Function of Metal ( Joule )

q = Charge of an Electron ( Coulomb )

V = Stopping Potential ( Volt )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

initial shell = n₁ = 3

final shell = n₂ = 2

Unknown:

ΔE = ?

Solution:

We will use this following formula to solve this problem:

[tex]\Delta E = R (\frac{1}{(n_2)^2} - \frac{1}{(n_1)^2})[/tex]

[tex]\Delta E = -2.18 \times 10^{-18} \times ( \frac{1}{2^2} - \frac{1}{3^2})[/tex]

[tex]\Delta E = -2.18 \times 10^{-18} \times ( \frac{1}{4} - \frac{1}{9} )[/tex]

[tex]\Delta E = -2.18 \times 10^{-18} \times \frac{5}{36}[/tex]

[tex]\Delta E \approx -3.03 \times 10^{-19} \texttt{ J}[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: College

Subject: Physics

Chapter: Quantum Physics

Answer:

The brightness of the beam of light increases.

Explanation:

As per Einstein's experimental verification he proves that light is of particle nature and his equation for energy balance is given as

[tex]h\nu = \phi + KE[/tex]

so incident photons on a photosensitive plate will eject the electrons from the plate with some sufficient KE.

So here light is considered as particles which means one photon will eject one electron. So here intensity of light is considered as

Intensity = (number of photons per second) (energy of one photon)

so it is given as

[tex]I = \frac{N}{t}(\frac{hc}{\lambda})[/tex]

now if the intensity of light is increased for same wavelength of light then it means the number of photon must have to be increase.

so correct answer will be

The brightness of the beam of light increases.

Explanation :

There can be many eye defects in the human eye. Some of them are Myopia, Hypermetropia, Astigmatism etc.

In Myopia the size of the eyeball is too long and the image is formed in front of the retina. A person suffering from this defect is not able to see far objects clearly but can see nearby objects normal.

Concave lenses are used to correct this defect so that the image is focused on the retina.

Third option is correct. The mass of an object remains same when an unbalanced force is applied to it.

the mass on an object doesn't depend on the applied force. it is constant.When an unbalanced force is applied to an object, it will get accelerated. The velocity of the object will increase or decrease depending on the direction of the force but the mass of the object remains same. That doesn't change with the applied force.

By exerting the given constant pressure, work done on the system to decrease from initial volume to final volume is 2.84kJ.

Given the data in the question

The magnitude of the work done when a gas expands is equal to the product of the pressure of the gas and the change in the volume of the gas.

For work done by gas against a constant external pressure, we use the

expression:

[tex]Work\ done = -P\ *\ \delta V[/tex]

We substitute our given values into the equation

[tex]Work\ done = -P\ *\ ( v_2 - v_1)\\\\Work\ done = -4.0atm\ *\ ( 13.0L - 20.0L)\\\\Work\ done = -4.0atm\ *\ -7L\\\\Work\ done = 28L.atm\\\\Work\ done = 28L.atm\ *\ [ \frac{101.3J}{L.atm}] \\\\Work\ done = 2836.4J\\\\Work\ done = 2.84 kJ[/tex]

Therefore, by exerting the given constant pressure, work done on the system to decrease from initial volume to final volume is 2.84kJ.

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To decrease the volume of a system from 20.0 l to 13.0 l by exerting a constant pressure of 4.0 atm, a work of 2836.4 Joules must be done on the system.

In Physics, the concept of work done in a constant-pressure or isobaric process is defined as the product of pressure and the change in volume (W = PΔV). Since the pressure is given as 4.0 atm and must be converted to Joules using the conversion factor (1 atm = 101.3 J/L), the pressure in usable units becomes 4.0 atm * 101.3 J/L = 405.2 J/L. The change in volume is the initial volume subtracted from the final volume, so ΔV = 20.0L - 13.0L = 7.0L.

Substituting the values into our equation, the work done to decrease the volume of the system becomes W = (405.2 J/L) * (7.0 L) = 2836.4 Joules. So, to decrease the volume of the system from 20.0 l to 13.0 l by exerting a constant pressure of 4.0 atm, a work of 2836.4 Joules must be done on the system.

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The relationship between the force between two magnetic poles and the distance of separation is The magnetic force is inversely proportional to the square of the distance between them.

Coloumb's law of magnetism states the relationship between the magnetic strength of two magnets. The force of attraction or repulsion between two magnets is directly proportional to the strength of magnetic poles and inversely proportional to the square of the distance between them.

Coloumb's law of magnetism describes the electric field between two charged objects. The force of attraction or repulsion is inversely proportional to the absolute permeability of the surrounding medium.

The attractive and repulsive force, F∝ m₁×m₂ / μ₀r², where m₁, and m₂ are the magnetic strength or magnetic poles and r is the distance between two magnets.

The attractive or repulsive force, F = k (m₁×m₂) / μ₀r², where μ₀ is the permeability of the medium and k is the constant of proportionality. The unit is Newton/Tesla. The magnetic force is inversely proportional to the square of the distance of separation.

Hence, the ideal solution is option D.

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White light is composed of a spectrum of many different colors (Option A).

The spectrum is the variety of colors created when light travels through a glass prism or a drop of water.

White light is a mixture of all the colors of the visible spectrum, which includes red, orange, yellow, green, blue, indigo, and violet. When light passes through a prism, it is separated into its individual colors, creating a rainbow-like effect.

This is because different colors of light have different wavelengths, and a prism bends the light of different wavelengths by different amounts, causing them to spread out and form a spectrum.

So, white light is actually composed of many different colors of light, each with its own unique wavelength.

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Answer:

Sample Response: As the air bubbles rise to the surface, the pressure on them decreases. This decrease in pressure allows the air to expand and each bubble increases in size. Boyle’s law explains why this occurs.

Explanation:

Final answer:

The wavelength of the monochromatic light in the double slit experiment is calculated to be 625 nm, using the provided measurements and the double slit interference formula.

Explanation:

The student is asking to determine the wavelength of monochromatic light based on observations from a double slit interference experiment. Given that the slit separation is 1.8 mm, the distance to the screen is 4.8 m, and there are 6.0 complete bright fringes per centimeter on the screen, we can calculate the wavelength using the formula for double slit interference, λ = Δy × d / D, where λ is the wavelength of light, Δy is the distance between adjacent bright fringes (the fringe spacing), d is the separation between the slits, and D is the distance from the slits to the screen.

First, we find the fringe spacing by noting that there are 6 bright fringes per centimeter, so Δy = 1 cm / 6 = 0.1667 cm = 1.667 mm. We can then use the given values to calculate the wavelength:

[tex]λ = (1.667 \times 10^{-3} m) \times (1.8 \times 10^{-3} m) / (4.8 m) = 6.25 \times 10^{-7} m = 625 nm.[/tex]

Therefore, the wavelength of the monochromatic light is 625 nm.

Answer:

if value of k is high then it results less stretchy spring

Explanation:

As we know by formula of spring force

F = kx

here we know

k = spring constant

x = stretch in the spring

Now we know that when same force is applied on two types of spring then the stretch of the spring is given as

[tex]x = \frac{F}{k}[/tex]

so if the value of k is higher then the stretch in the spring will be less as it is inversely depends on the spring constant.

So here we can say that if value of k is high then it results less stretchy spring

Answer:

Option-(D):  "A cat jumps from a tree limb to the ground."

Explanation:

Negative displacement(Assume positive position is measured vertically upward along a y-axis):

The displacement can be visualized going from the initial point been supposed as the ground level. While, the limb is considered more elevated as compared to the ground level. So, going from the lower level to the higher position is considered as positive displacement while the movement from the higher position to the lower point is considered as negative displacement.

The force require to stop the second object is greater because it has bigger momentum when compared to the first object.

The given parameters;

The force required to stop each object in the given time is determined by applying Newton's second law of motion as shown below;

[tex]F = ma = \frac{mv}{t} \\\\F_1 = \frac{8 \times 0.2}{10} \\\\F_1 = 0.16\ N[/tex]

For the second object;

[tex]F_2 = \frac{4 \times 1}{10} \\\\F_2 = 0.4 \ N[/tex]

Thus, the force require to stop the second object is greater because it has bigger momentum when compared to the first object.

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Answer:

Airbags:

" As the airbags comes in inbuilt form these days in most of the cars, as they fulfill the safety concerns of the passengers and make it sure that non of the individuals gets hurt in any accident faced during the travel."

Angle of Deployment:As the airbags will only deploy in the specific conditions provided, as the car must be speed over about the 25 km/hr and the accident must be more like a head-on-collision making the airbags to deploy. Or else if the car experiences an side wise crash with any other entity then it will never deploy in that case.

0.35 m is the maximum distance that the block will compress the spring after the collision.

Given :

Mass, [tex]\rm m_b = 15 \;Kg\;and\; m_s = 3\;Kg[/tex]

Spring constant, K = 500 N/m

Solution :

Before the collision the total momentum is,

[tex]\rm p_i = m_s \times v_s[/tex]

Whare [tex]m_s[/tex] is mass of stone and [tex]\rm v_s[/tex] is the velocity of stone beforethe collision.

After the collision stone and block both are moving therefore total momentum is,

[tex]\rm p_f = m_sv_s' + m_bv_b[/tex]

where, [tex]\rm v_s'[/tex] is the velocity of stone after collision, [tex]\rm m_b[/tex] is the mass of block and [tex]\rm v_b[/tex] is the speed of the block after collision.

Now, momentum should be conserve

[tex]\rm p_i = p_f[/tex]

[tex]\rm m_sv_s= m_sv_s'+ m_bv_b[/tex]

[tex]\rm v_b = \dfrac{m_s}{m_b}(v_s - v_s')[/tex]  ------- (1)

[tex]\rm v_s = 8\;m/sec[/tex]      (Given)

[tex]\rm v_s' = 2 \;m/sec[/tex]      (Given)

Now putting the values in equation (1) we get,

[tex]\rm v_b = \dfrac{3}{15}(8-2)[/tex]

[tex]\rm v_b = 2\;m/sec[/tex]

Therefore, block slides with the speed of 2 m/s to the right after the collision.

We know that the block starts to move with speed 2 m/s, so its kinetic energy is

[tex]\rm K = \dfrac{1}{2}m_bv_b^2[/tex]

As the spring is compress, block speed decreases and its kinetic energy is converted into elastic potential energy of the spring and the elastic potential energy of the spring is,

[tex]\rm U = \dfrac{1}{2} Kx^2_m_a_x[/tex]

Now through conservation of energy we have,

[tex]\rm K = U[/tex]

[tex]\rm m_bv_b^2 = Kx^2_m_a_x[/tex]

[tex]\rm x_m_a_x = \sqrt{\dfrac{m_bv_b^2}{K}}[/tex]----- (2)

Putting the values of  [tex]\rm m_b,\;v_b\;and\; K[/tex]  in equation (2),

[tex]\rm x_m_a_x= \sqrt{\dfrac{15\times2^2}{500}}[/tex]

[tex]\rm x_m_a_x=0.35\;m[/tex]

0.35 m is the maximum distance that the block will compress the spring after the collision.

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The center of mass and speed can be calculated using the formulas provided. Adding a fifth mass at either the origin or the current center of mass will affect the location of the center of mass, but it can only be determined with knowledge of the mass of the new particle.

The center of mass for a system of particles can be calculated using the following formulas: Xcm = ∑mi xi/mi and Ycm = ∑mi yi / ∑ mi, where 'mi' denotes the mass of the ith particle and 'xi' and 'yi' are the x and y coordinates respectively. This principle extends not just to two dimensions but also to three dimensions.

The speed of the center of mass of a group of particles can be calculated by the formula Vcm = ∑mi vi / ∑ mi, where 'vi' is the vector sum of the velocities of the particles, and 'mi' is the mass of the ith particle.

When a fifth mass is placed at the origin, the location of the center of mass can only be determined if the mass is known. Similarly, when a fifth mass is placed at the center of mass, the new location depends on the mass of the fifth particle and cannot be determined otherwise.

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This question involves the concept of Newton's Second Law of Motion.

The force exerted on the rocket is "5.85 x 10⁷ N".

According to Newton's Second Law of Motion, whenever an unbalanced force is applied to an object, it produces an acceleration in the direction of the force. Mathematically,

[tex]F=ma[/tex]

where,

Therefore,

[tex]F = \frac{m\Delta v}{t}[/tex]

where,

Therefore,

F = (1300 kg/s)(4.5 x 10⁴ m/s)

F = 5.85 x 10⁷ N

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Most people perceive the least intense sounds at a frequency around 2000 Hz with an intensity level at the threshold of hearing, which is about 0 dB or 10^-12 W/m².

The frequency at which most people perceive the least intense sounds is typically around the threshold of human hearing. This threshold is at about 0 dB, which corresponds to an intensity level of approximately 10-12 W/m². However, frequency and intensity are not the only factors that contribute to the perception of sound, as the sensitivity of the human ear varies across different frequencies. The human ear has the maximum sensitivity to frequencies ranging from 2000 to 5000 Hz. Sounds at these frequencies are perceived as louder compared to those at lower or higher frequencies, even if they have the same intensity level. Therefore, the least intense sounds that humans can perceive are at the lower end of this range, around 2000 Hz, at the absolute threshold of hearing of 0 dB.

Answer:

The smaller the amplitude of the wave, the smaller the displacement of the pendulum from the equilibrium position. The shorter the period, the shorter the pendulum’s rod.

To find the right answer, we could look the analysis of a simple pendulum movement. The relation that defines this movement is:

[tex]T=2 \pi \sqrt{\frac{l}{g} }[/tex]

[tex]T: \ period\\l: \ pendulum's \ rod \ length\\g: \ gravity[/tex]

From the equation, we can see the relation between the period and the length of the pendulum's rod. They are directly proportional, this means that if the period increases, the length increases, or vice versa. So, the shorter the period, the shorter the pendulum's rod, because they are directly proportional.

On the other hand, the amplitude of the harmonic motion refers to the displacement of the object from the equilibrium point which is in the center of the periodic movement. This allow us to deduct that if the amplitude is small, the displacement of the object is small, if the amplitude is big, the displacement from the equilibrium point is bid.

Answer:

The study was unethical

Explanation:

The study was deceptive to the participants, It failed to protect the participants involved and it denied them the right to withdraw from the experiment.

Answer:

Need to know THEIR TEMPERATURES

Explanation:

The amplitude of the block's oscillation is 0.103 A.

The speed of the block at the given position is 0.34 m/s.

How to calculate the amplitude of the oscillation?

The amplitude of the block's oscillation is calculated by applying the principle of conservation of energy as follows.

K.E = U

¹/₂mv² = ¹/₂kA²

mv² = kA²

A² = mv²/k

A = √ (mv² / k)

where;

A = √ (1.1 x 0.36² / 13.5)

A = 0.103 A

The speed of the block at the given position is calculated as follows;

¹/₂kA² = ¹/₂mv² + ¹/₂kx²

kA² = mv² + kx²

mv² = kA² - kx²

v² = (kA² - kx²) / m

v = √ (13.5 x 0.103²  -  13.5(0.3 x 0.103)² ) / 1.1

v = 0.34 m/s

The complete question is below:

A 1.10 kg block is attached to a spring with spring constant 13.5 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 36.0 cm/s .

What are the amplitude of the subsequent oscillations and the block's speed at the point where x = 0.3 A?

Answer:

Angular acceleration, α = -2βt

Explanation:

Angular velocity of fan is [tex]\omega_{z(t)}=\gamma -\beta t^2[/tex]

[tex]\gamma=4.90\ rad/s[/tex]

[tex]\beta=0.750\ rad/s^3[/tex]

Angular acceleration is given by :

[tex]\alpha=\dfrac{d\omega}{dt}[/tex]

[tex]\alpha=\dfrac{d(\gamma -\beta t^2)}{dt}[/tex]

[tex]\alpha=-2\beta t[/tex]

Hence, the above equation is the angular acceleration as a function of time.   

Answer:

A violin is a both ends fixed, and so successive harmonics are simply multiples of the fundamental:

Therefore, f1 = 440Hz (fundamental frequency)

f2 = 2f1 = 2 x 440 = 880 Hz

f3 = 3f1 = 3 x 440 = 1320 Hz

f4 = 4f1 = 4 x 440 = 1760 Hz

Answer:

SS and Ss

I did the test!!!!

Both athletes reach the same maximum height. This is because the kinetic energy they start with (due to their initial speed) is the same, which is fully transformed into potential energy when they reach their maximum heights.

The problem is solved by relating the kinetic energy and potential energy of the athletes.

Before the athletes grab the rope, they have kinetic energy due to their motion (1/2mv2). Once they reach the maximum height, this kinetic energy is fully transformed into gravitational potential energy (mgh).

In the first case, the kinetic energy is (1/2)m(v2) and this is equal to the potential energy h at the maximum height (mgh), thereby, h = (v2)/2g.

In the second case, the kinetic energy is (1/2)(2m)(v2), and this is equal to the potential energy at the maximum height (2m)(g)(2h). In this scenario, the maximum height reached is 2h = (v2)/2g.

So, comparing the two scenarios, we clearly see that the maximum height reached by both athletes is identical. Although the second athlete is twice as heavy, they both start with the same speed and so the initial kinetic energy is the same.

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