A class has 24 boys and 16 girls. on a test the class mean was 75. the mean of the girls' score was 72. what was the mean of the boys' scores?

To find the mass of 25,500 ounces of rice in kilograms, one needs to convert ounces to pounds, then pounds to kilograms. After the conversions, the crate contains approximately 724 kg of rice.

To calculate the mass of 25,500 ounces of rice in kilograms, we first convert ounces to pounds and then pounds to kilograms using the conversion rates provided.

When we round this number to the nearest whole number, we get 724 kg, which is the approximate mass of the rice in the crate.

Answer:

(2,0)

Step-by-step explanation:

Following the circle formula: [tex](x-h)^2 + (y-k)=r^2[/tex], we can deduce the values of Point(h,k).

The point is (2,0).

To simulate the probability in a spinner divide the spinner into colors depending on the probability each color represents.

This word refers to the likelihood for an event to occur. Moreover, it is often expressed either as a fraction, a percentage, or a number.

In this case, each of the colors represents a probability:

Green 20%

Blue 1/4 or 25%

Yellow 2/5 or 40%

Orange 15%

Now, Due to this, the best is to divide the spinner by colors and considering the percentages of each color.

Hence, For example 40% of the spinner should be red, while 15% should be orange.

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Explain how you would create and use a spinner to simulate the probability of an event with the following probabilities:

Percent chance: 20% green, ¼ blue, ⅖ yellow, and 15% orange

Answer : x >= -7

On simplifying,

2x - 8 - 9x  <=  -4x + 13

-7x - 8 <= -4x + 13

-3x - 8 < = 13

-3x <= 21

x >= -7

Answer: There is 58% of female respondents.

Step-by-step explanation:

                  Commercial A Commercial B                Total

Males      0.28                       0.14                             0.42

Females       0.33                        0.25                           0.58

Total             0.61                         0.39                           1.00

So, Percentage of the respondents were females is given by

[tex]\dfrac{0.58}{1}\times 100\\\\=58\%[/tex]

Hence, there is 58% of female respondents.

Savings Account B earned the most interest after one year.

To determine which savings account earned the most interest after one year, we can calculate the interest earned by each account using the formula:

Interest = Principal x Rate

For Account A: Interest = 1500 x 0.035 = $52.50

For Account B: Interest = 1400 x 0.04 = $56.00

Therefore, Account B earned more interest after one year, with a total of $56.00.

The zeros of the function f(x) = x(x – 8) are x = 0 and x = 8, which correspond to each factor of the equation being set equal to zero. Therefore, the correct answer is option A.

To identify the zeros of the function f(x) = x(x – 8), we should solve for x when f(x) is set to zero. Setting the function equal to zero gives us the equation 0 = x(x – 8).

We can find the zeros by looking for the values of x that make each factor in the equation equal to zero. The first factor is x, and it is equal to zero when x = 0. The second factor is (x – 8), which is equal to zero when x = 8.

Therefore, the zeros of the function f(x) are x = 0 and x = 8.

Selection A is the correct answer: The zeros of the function x(x – 8) are x = 0 and x = 8.

Answer:

146

Step-by-step explanation:

Answer:

height of the cone  = 4.01273885 units

Step-by-step explanation:

Volume of a cone(V) is given by:

[tex]V = \frac{1}{3} \pi r^2h[/tex]             ....[1]

where,

r is the radius and h is the height of the cone.

As per the statement:

A cone with radius 5 units and ts volume is 105 cubic units

⇒r = 5 units and V = 105 cubic units

Substitute these given values and use [tex]\pi = 3.14[/tex] in [1] we have;

[tex]105 = \frac{1}{3} \cdot 3.14 \cdot 5^2 \cdot h[/tex]

Multiply both sides by 3 we have;

⇒[tex]315 = 78.5 \cdot h[/tex]

Divide both sides by 78.5 we have;

[tex]4.01273885 = h[/tex]

or

h = 4.01273885 units

Therefore, the height of the cone is, 4.01273885 units

The height of the cone is 4 units.

The volume of the cone is equal to;

[tex]\rm Volume \ of \ cone=\dfrac{1}{3} \times b \times h[/tex]

Where; B is the area of the circular base of the cone, and h is the height of the cone.

The base of the cone is given by;

[tex]\rm Base=\pi r^2[/tex]

Substitute all the values in the equation

[tex]\rm Volume \ of \ cone=\dfrac{1}{3} \times b \times h\\\\Volume \ of \ cone=\dfrac{1}{3} \times \pi r^2\times h \\\\ 105=\dfrac{1}{3} \times 3.14 \times 5^2\times h\\\\h = \dfrac{105\times 3}{25 \times 3.14}\\\\h=64[/tex]

Hence, the height of the cone is 4 units.

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Juan's total pay p after working h hours is calculated using the equation p = 8h. This represents a direct relationship between hours worked and total earnings.

To represent Juan's total pay p after working h hours at a rate of 8 dollars per hour, we use the equation p = 8h. This equation shows that the total pay (p) is equal to the rate of pay per hour (8 dollars) multiplied by the number of hours worked (h).

For example, if Juan works for 8 hours a day, his total pay would be calculated as p = 8 * 8, which equals $64. If we consider a full day of work to be 8 hours producing a value of $160, we can see that Juan is being paid for only half the hours at that rate, since 8 hours' labor would have a value of $80 at his rate of pay.

The solutions to the problems in the mid-unit review quiz for Algebra Unit 3 Lesson 5 are A(2(m+6)), D(-8/(z^2-1)), and B(6/7). These are found by factoring out common factors and simplifying the expressions.

Let's solve the algebra mid-unit review quiz Unit 3 lesson 5 one by one.

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The quotient when [tex](x^3-3x^2+3x-2)\div(x^2-x+1)[/tex] is [tex](x-2)[/tex].

Given :

Equation -

[tex]\dfrac{x^3-3x^2+3x-2}{x^2-x+1}[/tex]

Solution :

[tex]\dfrac{x^3-3x^2+3x-2}{x^2-x+1} = \dfrac{x^3-2x^2-x^2+2x+x-2}{x^2-x+1}[/tex]

[tex]= \dfrac{(x^2(x-2)-x(x-2)+1(x-2))}{x^2-x+1}[/tex]      ------ (1)

Now taking (x - 2) common from numerator in equation (1) we get,

[tex]= \dfrac{(x-2)(x^2-x+1)}{x^2-x+1}[/tex]

[tex]=(x-2)[/tex]

Therefore the quotient when [tex](x^3-3x^2+3x-2)\div(x^2-x+1)[/tex] is [tex](x-2)[/tex].

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Answer:

The graph in the attached figure

Step-by-step explanation:

Let

x------> the number of hammers

y------> the number of of wrenches

we know that

[tex]10x+6y\leq 120[/tex] -----> inequality A

[tex]x+y\geq 14[/tex] -----> inequality B    

using a graphing tool

The solution of the system of inequalities is the shaded area  

see the attached figure