A compound consists of 47.5% S and 52.5% Cl by mass. Draw the Lewis structure based on the empirical formula and comment on its deficiencies. Draw a more plausible structure with the 7. same ratio of S and Cl

Answer:

The correct option is: b. the elements in the material are well apart (in different sides) in the periodic table            

Explanation:

Ionic bond is a type of chemical bonding that is formed by the transfer of electrons from one atom to another. It is formed between atoms having large electronegativity difference.

The more electronegative atom accepts electrons and becomes a negatively charged anion. Whereas, the less electronegative atom loses electrons and becomes a positively charged cation.

Simply, an ionic bond is formed when the electrons are transferred from a metal to a non-metal, which are present on different sides of the periodic table.

Answer:

Potential energy for n = 6 Bohr orbit electron is -1.21*10⁻¹⁹J

Explanation:

As per the Bohr model, the potential energy of electron in an nth orbit is given as:

[tex]PE_{n} = -\frac{kZe^{2}}{r_{n}}[/tex]

here:

k = Coulomb's constant = 9*10⁹ Nm2/C2

Z = nuclear charge

e = electron charge = 1.6*10⁻¹⁹ C

r(n) = radius of the nth orbit = n²(5.29*10⁻¹¹m)

Substituting for k, Z(= 1), e and r(n) in the above equation gives:

[tex]PE_{6} = -\frac{9*10^{9}Nm2/C2*1*(1.6*10^{-19}C)^{2}}{(6)^{2}*5.29*10^{-11}m}=-1.21*10^{-19}J[/tex]

Explanation:

According to Newtons second law,

                         F = m × a

where,       F = force acting on object

                  m = mass of object

                  a = acceleration

On Earth,       a = g

where,      g = gravitational acceleration constant = 9.8 [tex]m/sec^{2}[/tex]

Now, convert g into [tex]ft/sec^{2}[/tex] as follows.

                    1 m = 3.280 ft

           g = [tex]9.8 m/s^{2} \times 3.280 ft/m[/tex]

              = 32.144 [tex]ft/s^{2}[/tex]

It is given that m = 148 lbm. Hence, calculate force as follows.

                     F = [tex]148 lbm \times 32.144 ft/s^{2}[/tex]

                        = 4757.312 [tex]lbm.ft/s^{2}[/tex]

                        = 4757.312 poundal

Thus, we can conclude that the weight in poundals of an 148 lbm object on Earth is 4757.312 poundal.

Answer : a) [tex]\frac{[A^-]}{[HA]}=10^{4}[/tex]

b) [tex]\frac{[A^-]}{[HA]}=0.01[/tex]

Explanation : Given,

a) pH = 7.4

[tex]pK_a[/tex] for aspirin = 3.4

Using Henderson Hesselbach equation :

[tex]pH=pK_a+\log \frac{[Salt]}{[Acid]}[/tex]

Concentration of salt [tex](A^-)[/tex] = ?

Concentration of acid [tex](HA)[/tex] = ?

[tex]pH=pK_a+\log \frac{[A^-]}{[HA]}[/tex]

Now put all the given values in this expression, we get:

[tex]7.4=3.4+\log \frac{[A^-]}{[HA]}[/tex]

[tex]\frac{[A^-]}{[HA]}=10^{4}[/tex]

b) pH = 1.4

Using Henderson Hesselbach equation :

[tex]pH=pK_a+\log \frac{[A^-]}{[HA]}[/tex]

Now put all the given values in this expression, we get:

[tex]1.4=3.4+\log \frac{[A^-]}{[HA]}[/tex]

[tex]\frac{[A^-]}{[HA]}=0.01[/tex]

The pKa is the acid dissociation constant. The ratio of A to HA in the blood is, 10000, and in the stomach is 0.01.

The acid dissociation constant or pKa has been the dissociation of the compound into ions at specified pH.

The relation between pKa and pH can be given as:

[tex]\rm pH=pKa\;+\;log\;\dfrac{acid}{salt}[/tex]

The pKa of aspirin is 3.4.

[tex]\rm 7.4=3.4\;+\;log\;\dfrac{A}{HA} \\\dfrac{A}{HA}=10000[/tex]

[tex]\rm 7.4=1.4\;+\;log\;\dfrac{A}{HA} \\\dfrac{A}{HA}=0.01[/tex]

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Explanation:

Formula for compressibility factor is as follows.

                     z = [tex]\frac{P \times V_{m}}{R \times T}[/tex]

where,     z = compressibility factor for helium = 1.0005

               P = pressure

          [tex]V_{m}[/tex] = molar volume

                R = gas constant = 8.31 J/mol.K

                T = temperature

So, calculate the molar volume as follows.

                [tex]V_{m} = \frac{z \times R \times T}{P}[/tex]

                             = [tex]\frac{1.0005 \times 8.314 \times 10^{-3} m^{3}.kPa/mol K \times (60 + 273)K}{500 kPa}[/tex]

                             = 0.0056 [tex]m^{3}/mol[/tex]

As molar mass of helium is 4 g/mol. Hence, calculate specific volume of helium as follows.

                    [tex]V_{sp} = \frac{V_{m}}{M_{w}}[/tex]

                           = [tex]\frac{0.0056 m^{3}/mol}{4 g/mol}[/tex]

                           = 0.00139 [tex]m^{3}/g[/tex]

                           = 0.00139 [tex]m^{3}/g \times \frac{1 g}{10^{-3}kg}[/tex]

                                 = 1.39 [tex]m^{3}/kg[/tex]

Thus, we can conclude that the specific volume of Helium in given conditions is 1.39 [tex]m^{3}/kg[/tex].

Answer:

6.82% is the mass percent NaOH in the solution.

Explanation:

Mass of the solute that is NaOH = m = 20 g

Mass of the solution = M

Volume of the solution = V = 255 mL

Density of the solution = d = 1.15 g/mL

[tex]Density=\frac{Mass}{Volume}[/tex]

[tex]1.15 g/mL=\frac{M}{255 mL}[/tex]

M = 293.25 g

Mass percentage of solute :(w/w)%

[tex]\frac{m}{M}\times 100[/tex]

[tex](w/w)\%=\frac{20 g}{293.25 g}\times 100=6.82\%[/tex]

6.82% is the mass percent NaOH in the solution.

Answer:

Mutarotation refers to the change in the optical rotation or optical activity of a solution due to the change in the equilibrium of the two anomers. It depends upon the optical activity and ratio of the anomeric forms in the solution.

To measure the optical rotation of a given solution, a polarimeter can be used and thus the ratio of the anomeric forms can be calculated.

Answer:

0.0375 moles

Explanation:

Given that:

Molar mass of monopotassium phosphate = 136.09 g/mol

Given that volume = 250.0 mL

Also,

[tex]1\ mL=10^{-3}\ L[/tex]

So, Volume = 250 / 1000 L = 0.25 L

Molarity = 0.15 M

Considering:

[tex]Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}[/tex]

[tex]0.15=\frac{Moles\ of\ solute}{0.25}[/tex]

Thus, moles of monopotassium phosphate needed = 0.0375 moles

Answer:

a) Absorbance

b) The absorb light most strongly in 580nm

Explanation:

Beer-Lambert law relates concentration with light absorbance. The more concentrated solution are the more molecules and the most absorbance.

Wavelenght depends of composition of solution and doesn't change with different concentrations of the same solution.

Transmittance is inversely proportional to absorbance. Thus, the more concentrated solution the less transmittance.

Colored compounds are absorb energy of visible radiation. The colour that we see is a  result of the absortion of complimentary colour (Colour wheel). Thus, a blue-green solution absorb energy of ≈600 nm. Thus, the absorb light most strongly in 580nm.

I hope it helps!

Answer:

The rabbit population will reach 500 after 10 months.

Explanation:

According to the given data:

The initial number of rabbit's equals 2.

Number of rabbit's after 2 months =2x3= 6

Number of rabbit's after 4 months = 6x3=18

Number of rabbit's after 6 months = 18x3=54

Number of rabbit's after 8 months = 54x3=162

Thus we can see that the number of rabbit's form a Geometric series with common ratio =3 and initial term = 2

Now the general term of a geometric series with first term 'a' and common ratio 'r' is given by

[tex]T_{n+1}=ar^{n}[/tex]

Thus we need to find when the term becomes 500 thus using the given data we have  

[tex]500=2\cdot 3^{n}\\\\3^{n}=250\\\\(n)log_3(3)=log_3(250)\\\\(n)=5.025\\\\[/tex]

Thus the fifth term (excluding the start term) will have a rabbit count of 500 now since each term has a time difference of 2 months thus sixth term will occur after [tex]5\times 2=10months[/tex]

The psychical properties do no change the composition of the lithium metal.

The chemical properties will change the composition of the lithium producing other substances.

light enough to float on water - physical property

silvery gray in color - physical property

changes from silvery gray to black when placed in moist air - chemical property

(in air the lithium will react with the oxygen forming the oxide which have a black color)

can be cut with a sharp knife - physical property

in the liquid state, it boils at 1317 °C - physical property

reacts violently with chlorine to form a white solid - chemical property

in the liquid state, it reacts spontaneously with its glass container, producing a hole in the container - chemical property

burns in oxygen with a bright red flame - chemical property

Explanation:

A property that does not bring any change in chemical composition of a substance are known as physical properties.

For example, shape, size, mass, volume, density, hardness etc of a substance are all physical properties.

On the other hand, a property that changes chemical composition of a substance is known as chemical property.

For example, precipitation, reactivity, toxicity etc are chemical property.

Hence, the given properties of lithium are classified as follows.

Explanation:

The given data is as follows.

Diameter of pipe, D = 0.01 m

Velocity V = 0.03 m/s

Fluid density = 36.4 [tex]kg/m^{3}[/tex]

Viscosity = 0.651 Pa-s

Formula to calculate Reynold number is as follows.

Re = [tex]diameter \times velocity \times \frac{density}{viscosity}[/tex]

     = [tex]0.01 \times 0.03 \times \frac{36.4}{0.651}[/tex]

     = 0.01677

Since,  Re < 2100. This means that the flow is laminar.

So, for laminar flow in pipes,

Darcy friction factor f = [tex]\frac{64}{Re}[/tex]

                                   = [tex]\frac{64}{0.01677}[/tex]

                                    = 3816

Thus, we can conclude that the Darcy friction factor value is 3816.

Answer:

S AgBr = 2.82 E-3 mol/L

Explanation:

∴ Ksp = [ Ag+ ] * [ Br- ] = 5.0 E-13

∴ Kf = 1.6 E7 = α[Ag(NH3)2]+ / ( αAg+ )*( αNH3 )²

∴ C NH3(sln) = 1.00 M

from (1) + (2):

                             1 M                     0                       0

                            1 - 2x                   x                        x

∴ K = Ksp*Kf = ( 5.0 E-13 )*( 1.6 E7 ) = 8.0 E-6

⇒ K = ( [ Br- ] * [ Ag(NH3)2+] ) / [ NH3 ]² = 8.0 E-6

⇒ K = (( x )*( x )) / ( 1 - 2x ) = 8.0 E-6

⇒ x² = 8.0 E-6*( 1- 2x )

⇒ x² + 1.6 E-5x - 8.0 E-6 = 0

⇒ x = 2.82 E-3 M

⇒ [ Br- ] = [ AgBr ] = 2.82 E-3 M

To calculate the solubility of AgBr in a 1.00 M ammonia solution, we can use the equation for the formation constant of the silver(I) ammonia complex.

The solubility constant of AgBr is 5.0 x 10-13. The formation constant of the silver(I) ammonia complex, Ag(NH₃)₂, is 1.6 x 107. To calculate the solubility of AgBr in a 1.00 M ammonia solution, we can use the equation:

AgBr(s) → Ag+(aq) + Br-(aq)

Let x be the concentration of AgBr(s). Then, the equilibrium concentrations of Ag+ and Br- would be x and x, respectively.

Using the equation for the formation constant:

Kf = [Ag(NH₃)₂]+ / [Ag+][NH₃]₂

we can substitute the given values and solve for [Ag+] and [NH₃].

Answer:

To make 500 mL of a solution of PPP 1% w/v you need 5g

Explanation:

A percent w/v solution is calculated with the following formula using the gram as the base measure of weight (w):

% w/v = g of solute/ mL of solution × 100

A 1% w/v means that you have 1 g of PPP per 100 mL of solution

Thus, if you need to make 500 mL of solution you will need 5 g of PPP.

I hope it helps!

To prepare a 1% w/v solution of phenolphthalein di-phosphate (PPP) for 500ml, you need to weigh out 5 grams of PPP and dissolve it in enough water to make the total solution volume up to 500 ml.

To prepare a 1% w/v solution of phenolphthalein di-phosphate (PPP) for 500ml, you first need to understand that 1% w/v means you have 1 gram of solute for every 100 milliliters of solution. Then, for 500 milliliters, you would need 5 grams of PPP. The molar mass of PPP (478 g/mol) is only used to calculate moles from grams or vice versa and is not needed to prepare a percent weight/volume solution. Since you have enough PPP (25g), you can weigh out 5 grams of PPP and dissolve it in water to make a total volume of 500ml to achieve a 1% w/v concentration.

Steps to prepare the solution:

Answer:

Structure has been shown below

Explanation:

To draw the Lewis structure for H2O, count the valence electrons, place the atoms, represent the bonding pairs and lone pairs, and check for octet completeness.

The Lewis structure for H2O can be drawn using the following steps:

Count the total number of valence electrons for each atom. Hydrogen has 1 valence electron and oxygen has 6 valence electrons.

Place the atoms in a way that the central atom (in this case, oxygen) is surrounded by the other atoms (hydrogen).

Use single lines to represent the bonding pairs between the central atom and the surrounding atoms. In this case, draw two lines between the oxygen and hydrogen.

Distribute the remaining valence electrons around the atoms to complete their octets. Oxygen will have two lone pairs of electrons and hydrogen will have no lone pairs.

Check if every atom has a complete octet. In this case, oxygen has 8 electrons and hydrogen has 2.

Write the Lewis structure, making sure to correctly represent the bonding pairs and lone pairs. In this case, it would be H—O—H.

Answer:

b) Electrons with the same state must have opposite spins.

Explanation:

Pauli Exclusion Principle-

The principle states that in an atom or in a molecule, no two electrons present can have same set of the four quantum numbers.  

Even if the two electrons are present in same state which means that if it is present in the same orbital , n, l and m are same but still the forth quantum number which is spin quantum number is different for them. Both the two electrons have opposing spins having value either [tex]\frac {1}{2}[/tex] or [tex]\frac {-1}{2}[/tex].

Hence, option B is correct.

Answer:

Options A and B

Explanation:

The Pauli Exclusion Principle states that, in an atom or molecule, no two electrons can have the same four electronic quantum numbers. As an orbital can contain a maximum of only two electrons, the two electrons must have opposing spins.

Going through the options;

Option A - An electron shell can have more than two electrons. An orbital however can hold a maximum of two electrons.

Option B - This is correct because No two electrons in a atom can have the same four quantum numbers . This means that only two electrons are allowed in the same orbital, and then they have opposite spin, +1/2 and -1/2.

Option C  - Each electron orbital (state) can only contain a maximum of two lectrons.

Option D - This is wrong because no two electrons in a atom can have the same four quantum numbers . This means that only two electrons are allowed in the same orbital, and then they must have opposite spin, +1/2 and -1/2.

Answer:

The process described in the problem is steady-state.

Explanation:

The steady-state can be described by the conservation of mass. In a bathtub it will be the same as In=Out+ Accumulation. Since the water has already reached the adequate level and the drain is open, the accumulation is equal to zero, and therefore it is at steady state. This also means that In = Out which is also described in the problem: "the water is poured into the bathtub at an equivalent rate of the water being drained".

The freezing point of the solution made by dissolving the sodium chloride in the liquid is 2.48 °C, calculated using the freezing point depression equation and given constants.

This problem involves the Physical Chemistry concept of freezing point depression.

First, we need to calculate the molality of the solution. Molality (m) is defined as moles of solute (mol) divided by mass of solvent (kg). Given 7.57g of NaCl, and we know the molar mass of NaCl is approximately 58.44 g/mol, we therefore have 7.57g / 58.44 g/mol = 0.1297 mol. So, the molality (m) is 0.1297 mol / 0.350 kg = 0.370 mol/kg.

Next, we use the freezing point depression equation: ΔTF = i * K * m, where ΔTF is the change in freezing point, i is the number of ions produced per formula unit (for NaCl, i=2 because NaCl dissociates into 2 ions), K is the cryoscopic constant (given as 6.9 ºC-kg/mol) and m is the molality. Substituting the values we get ΔTF = 2 * 6.9 °C-kg/mol * 0.370 mol/kg = 5.118 °C.

Finally, we subtract this value from the original freezing point of the liquid X (7.60 °C) to get the new freezing point: FP_new =FP_old - ΔTF = 7.60°C - 5.118°C = 2.482°C. However, rounding to three significant figures, it should be 2.48 °C.

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The freezing point of the solution made of 7.57 g of NaCl dissolved in 350 g of liquid X is approximately [tex]\( 5.04 \, \text{degree\ C} \).[/tex]

The freezing point of the solution, we'll use the formula for freezing point depression.

[tex]\[ \Delta T_f = K_f \cdot m \][/tex]

where.

[tex]- \( \Delta T_f \)[/tex] is the freezing point depression,

[tex]- \( K_f \)[/tex] is the freezing point depression constant of the solvent liquid X.

[tex]- \( m \)[/tex] is the molality of the solution.

Let's find the molality [tex](\( m \))[/tex] of the solution.

1. Calculate moles of NaCl.

Molar mass of NaCl = [tex]\( 22.99 \, \text{g/mol} + 35.45 \, \text{g/mol} = 58.44 \, \text{g/mol} \)[/tex].

Moles of NaCl [tex]\( = \frac{7.57 \, \text{g}}{58.44 \, \text{g/mol}} = 0.1295 \, \text{mol} \)[/tex].

2. Calculate molality [tex](\( m \)).[/tex]

[tex]\( m = \frac{\text{moles of solute}}{\text{mass of solvent in kg}} \)[/tex]

  Mass of solvent [tex](liquid X) \( = 350 \, \text{g} = 0.350 \, \text{kg} \)[/tex].

3. Calculate the freezing point depression[tex](\( \Delta T_f \)).[/tex]

  Given [tex]\( K_f = 6.90 \, \text{degree\ C-kg/mol} \),[/tex]

 [tex]\( \Delta T_f = K_f \cdot m = 6.90 \, \text{°C-kg/mol} \cdot 0.370 \, \text{mol/kg} \)[/tex]

[tex]\( \Delta T_f = 2.557 \, \text{degree\ C} \)[/tex]

4. Calculate the freezing point of the solution.

  Freezing point of solution = Normal freezing point of solvent -[tex]\( \Delta T_f \)[/tex]

  Normal freezing point of X = 7.60 °C

  Freezing point of solution [tex]\( = 7.60 \, \text{degree\ C} - 2.557 \, \text{degree\ C} \)[/tex]

  Freezing point of solution [tex]\( = 5.043 \, \text{degree\ C} \)[/tex]

Round your answer to 3 significant digits [tex]\[ \\5.04 \, \text{degree\ C}} \][/tex]

Answer: The new pH of resulting solution is 6.03

Explanation:

We are adding hydrochloric acid to the solution, so it will react with salt (sodium hydrogen carbonate) only.

To calculate the number of moles for given molarity, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}[/tex]

Molarity of hydrochloric acid = 0.15 M

Volume of solution = 3 mL

Putting values in above equation, we get:

[tex]0.15M=\frac{\text{Moles of hydrochloric acid}\times 1000}{3mL}\\\\\text{Moles of hydrochloric acid}=0.00045mol[/tex]

Molarity of sodium hydrogen carbonate = 0.025 M

Volume of solution = 150 mL

Putting values in above equation, we get:

[tex]0.025M=\frac{\text{Moles of sodium hydrogen carbonate}\times 1000}{150mL}\\\\\text{Moles of sodium hydrogen carbonate}=0.00375mol[/tex]

Molarity of carbonic acid = 0.045 M

Volume of solution = 150 mL

Putting values in above equation, we get:

[tex]0.045M=\frac{\text{Moles of carbonic acid}\times 1000}{150mL}\\\\\text{Moles of carbonic acid}=0.00675mol[/tex]

The chemical reaction for sodium hydrogen carbonate and hydrochloric acid follows the equation:

                  [tex]NaHCO_3+HCl\rightarrow NaCl+H_2CO_3[/tex]

Initial:        0.00375    0.00045                0.00675

Final:         0.00330          -                       0.00720          

Volume of solution = 150 + 3 = 153 mL = 0.153 L    (Conversion factor:  1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

[tex]pH=pK_a+\log(\frac{[salt]}{[acid]})[/tex]

[tex]pH=pK_a+\log(\frac{[NaHCO_3]}{[H_2CO_3]})[/tex]

We are given:

[tex]pK_a[/tex] = negative logarithm of acid dissociation constant of carbonic acid = 6.37

[tex][NaHCO_3]=\frac{0.0033}{0.153}[/tex]

[tex][H_2CO_3]=\frac{0.0072}{0.153}[/tex]

pH = ?

Putting values in above equation, we get:

[tex]pH=6.37+\log(\frac{0.0033/0.153}{0.0072/0.153})\\\\pH=6.03[/tex]

Hence, the new pH of the solution is 6.03

Answer:

pH = 0.22

Explanation:

The pH of the a solution is related to the concentration of the hydronium ion as follows:

pH = -log([H₃O⁺])

HNO₃ is a strong acid that reacts to completion with water as follows:

HNO₃ + H₂O ⇒ H₃O⁺ + NO₃⁻

The molar ratio between nitric acid and the hydronium ion is 1:1, so a 0.60 M nitric acid solution has a hydronium ion concentration of 0.60 M.

The pH is calculated:

pH = -log([H₃O⁺]) = -log(0.60) = 0.22

The freezing point of the aqueous solution of urea at 300 K with an osmotic pressure of 120 kPa is -0.09°C

To calculate the freezing point of the solution, we can use the following equation:

ΔTf = Kf * m

where:

ΔTf is the freezing point depression in C

Kf is the molal freezing point constant of water in C·kg/mol (1.86 C·kg/mol)

m is the molality of the solution in mol/kg

The molality of the solution can be calculated from the osmotic pressure using the following equation:

Π = MRT

where:

Π is the osmotic pressure in Pa

M is the molarity of the solution in mol/m³

R is the ideal gas constant in J/mol·K (8.314 J/mol·K)

T is the temperature in K

Substituting the given values into the equation, we get:

M = Π / (RT) = 120 kPa / (8.314 J/mol·K * 300 K) = 0.4918 mol/m³

The molality of the solution is equal to the molarity divided by the density of the solvent. The density of water is 1 kg/L, so the molality of the solution is:

m = M / d = 0.4918 mol/m³ / 1 kg/L = 0.4918 mol/kg

Now that we know the molality of the solution, we can calculate the freezing point depression using the first equation:

ΔTf = Kf * m = 1.86 C·kg/mol * 0.4918 mol/kg = 0.09 °C

Finally, we can calculate the freezing point of the solution by subtracting the freezing point depression from the freezing point of pure water:

Freezing point of solution = freezing point of pure water - freezing point depression

Freezing point of solution =  0 °C-  0.09 °C = -0.09°C

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The freezing point of an aqueous solution of urea at 300 K with an osmotic pressure of 120 kPa is -0.08928 °C.

1. To find the freezing point depression (ΔTf) of the solution, we can use the formula: ΔTf = i x k x m, where:

2. We need to calculate the molality (m) using osmotic pressure (π), which we can find from the formula: π / (i x R x T), given:

3. Since the density of water is approximately 1kg/L, the molality (m) ≈ molarity (M) in this case: m ≈ 0.048 mol/kg

Now, we can find the freezing point depression (ΔTf):ΔTf = 1 x 1.86 °C kg/mol x 0.048 mol/kg = 0.08928 °C

Answer:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For example:

[tex]H_3BO_3(aq.)+HS^-(aq.)\rightarrow H_2BO_3^-(aq.)+H_2S(aq.)[/tex]

Here, [tex]H_3BO_3[/tex] is loosing a proton, thus it is considered as a bronsted acid and after losing a proton, it forms [tex]H_2BO_3^-[/tex] which is a conjugate base.

And, [tex]HS^-[/tex] is gaining a proton, thus it is considered as a bronsted base and after gaining a proton, it forms [tex]H_2S[/tex] which is a conjugate acid.

The sequence of the acids and bases in the above equation are:

[tex]Acid+Base\rightarrow Base+Acid[/tex]

Answer:

The density of old trunk is [tex]11.3 g/cm^3[/tex] and it is equal to the density of metal lead.

Explanation:

Mass of the trunk , m= 222 g

Length of the cubic trunk = 2.7 cm

Volume of the cube = [tex]a^3[/tex]

Density of the truck = [tex]\frac{Mass}{Volume}[/tex]

[tex]D=\frac{m}{a^3}=\frac{222 g}{(2.7 cm)^3}=11.2787 g/cm^3\approx 11.3 g/cm^3[/tex]

The density of old trunk is [tex]11.3 g/cm^3[/tex] and it is equal to the density of metal lead.

Final answer:

The density of the metal cube is calculated to be approximately 11.28 g/cm³, which closely matches the density of lead (11.3 g/cm³), suggesting that the cube is made of lead.

Explanation:

To determine the type of metal a cube is made of, you need to calculate its density and compare it with the given densities of possible materials. The density is calculated by dividing the mass of the cube by its volume.

The mass of the metal cube is given as 222 g, and the length of each side is 2.7 cm. The volume V of a cube is found by cubing the length of one of its sides: V = 2.7 cm × 2.7 cm × 2.7 cm = 19.683 cm³. The density ρ is then found by dividing the mass m by the volume V: ρ = m/V = 222 g / 19.683 cm³ ≈ 11.28 g/cm³.

Comparing this calculated density with the given densities, the closest match is lead (11.3 g/cm³). Therefore, the metal cube is most likely made of lead.

By converting the given natural logarithm equation to its equivalent exponential form, we find that e^0.863 equals x. Therefore, calculating this gives us x as approximately 2.37 when rounded to three significant figures.

The equation given is in the form of a natural logarithm (ln x), where 'ln' stands for the natural logarithm and 'x' is the variable we need to solve for. The natural logarithm of a number is the power to which the constant 'e' (approximately equal to 2.7182818) must be raised to equal the number. Therefore, to solve the equation, we need to convert the equation back to the exponential form using the property of logarithms that states a^b=c is equivalent to log_a c = b. As such, ln x = 0.863 becomes e^0.863 = x.

When you calculate e^0.863, you will get x to be approximately 2.37 when rounded to three significant figures (the zero after the decimal point is a significant figure because it's located to the right).

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Final answer:

To solve the equation 'ln x = 0.863', rewrite it as 'e0.863 = x' and calculate the value, which is approximately 2.37 to three significant figures.

Explanation:

To solve for x when given the equation ln x = 0.863, we need to use the property of logarithms that allows us to rewrite the equation in exponential form. The base of the natural logarithm (ln) is e, so we can rewrite the equation as e0.863 = x. Using a calculator, we find that e0.863 is approximately 2.37. Therefore, x ≈ 2.37 to three significant figures.

Answer:

Without doing any calculations it is possible to determine that silver chloride is more soluble than ACD, and silver chloride is less soluble than ___.

It is not possible to determine whether silver chloride is more or less soluble than B by simply comparing Ksp values.

Explanation:

The Lead (Pb) is a heavy metal and Zinc (Zn) is a transition metal, both combine with the anion phosphate produces heavy complexes very insoluble.

The silver cation (Ag+) is an acid cation which in basic conditions rapidly precipitates as AgOH which is highly insoluble and unstable.

The FeCO3 is a complex with a solubility relatively close between AgCl. The Kps of these two are [tex]3.2x10^{-11}[/tex] and [tex]1.8x10^{-10}[/tex] respectively at room temperature.

Answer:

Hands-free eyewash stations, sand bucket, fire blankets, fire extinguishers, fire alarm system and first aid kit.

Explanation:

Working in laboratories has many risks, therefore, preventive measures that should be incorporated to avoid the occurrence of any laboratory accidents.

Some of the important emergency equipment that should be available in laboratories are: hands-free eyewash stations, sand bucket, fire blankets, fire extinguishers, fire alarm system, chemical storage cabinet, first aid kits and fume hood.

Some of the personal protective equipment include lab coats, goggles, safety gloves and face shield.

Answer:

As the average kinetic energy increases, the particles move faster and collide more frequently per unit time and possess greater energy when they collide. Both of these factors increase the reaction rate. Hence the reaction rate of virtually all reactions increases with increasing temperature

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The activation energy for the reverse reaction of NO₂ (g) + CO (g) ⇒ NO (g) + CO₂ (g) is calculated using the given activation energy for the forward reaction and the enthalpy change. It is found to be 470 kJ/mol.

To determine the activation energy for the reverse reaction of NO₂ (g) + CO (g) ⇒ NO (g) + CO₂ (g), we must first understand the relationship between activation energy, enthalpy change, and the reverse reaction's activation energy.

The activation energy (Ea) for the forward reaction is given to be 218 kJ/mol. The enthalpy change for the forward reaction is -252 kJ/mol. This means that the products have 252 kJ/mol less energy than the reactants. Knowing this, we can use the equation:

Ea_reverse = Ea_forward +

Substituting the given values:

Ea_reverse = 218 kJ/mol - (-252 kJ/mol)

Ea_reverse = 218 kJ/mol + 252 kJ/mol

Ea_reverse = 470 kJ/mol

Therefore, the activation energy for the reverse reaction is 470 kJ/mol.

Answer:

Ethanol

Explanation:

Hello,

Since the hexanes and the ethyl acetate are mostly composed by C-C, C-H and for the ester C-O bonds which are apolar, just the ethanol which has one O-H bond could be classified as polar, allowing H-bridges to be present.

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Final answer:

Ethyl Acetate and Ethanol are the polar solvents among the given options. Hexanes are nonpolar and would not dissolve readily in water. Ethanol, being highly polar, and Ethyl Acetate, with moderate polarity, would indeed have an overall molecular dipole.

Explanation:

The question you've asked is related to the polarity of solvents and their solubility in water, which is a polar solvent. Among the choices given (Hexanes, Ethyl Acetate, and Ethanol), we need to determine which ones are polar and would have an overall molecular dipole.

Hexanes are hydrocarbons with a nonpolar nature due to the C-H bonds that possess minimal electronegativity difference. Therefore, hexanes are not polar and are insoluble in water.

Ethyl Acetate has a polar carbonyl group (C=O) and is overall a polar molecule, although it has a slight nonpolar character due to its ethyl groups. Because of this, it has moderate solubility in water.

Ethanol is highly polar due to the presence of an -OH group allowing hydrogen bonding. This makes ethanol soluble in water.

Therefore, the solvents that are polar and have an overall molecular dipole from the given options are Ethyl Acetate and Ethanol.

Answer:

In this case, the system doesn't be affected by the pressure change. This means that nothing will happen

Explanation:

We can answer this question applying the Le Chatelier's Principle. It says that changes on pressure, volume or temperature of an equilibrium reaction will change the reaction direction until it returns to the equilibrium condition again.

The results of these changes can define as:

Changes on pressure: the reaction will move depending the quantity of moles on each side of the reaction

Changes on temperature: The reaction will move depending on if it's endothermic or exothermic

Changes on volume: The reaction will move depending the limit reagent  and the quantity of moles on each side of the reaction

In the exercise, they mention a change on pressure of the system at constant temperature (that means the temperature doesn't change). As Le Chatelier Principle's says, we must analyze what happens if the pressure increase or decrease. If pressure increase the reaction will move on the side that have less quantity of moles, otherwise, if the pressure decreases the reaction will move to the side that have more quantity of moles. In this case, we can see that both sides of the equation have the same number of moles (2 for the reactants and 2 for the products). So, in this case, we can conclude that, despite the change on pressure (increase or decrease), nothing will happen.