A cyclist is going in the positive x-direction at 9m/s. A car initially at rest, accelerates for the first 10 seconds, then it goes with a constant velocity. If the car reaches the cyclist after 15 seconds from the moment the car started moving, find: (a) The acceleration of the car during the first 10 seconds, (b) The velocity of the cyclist with respect to the car when the car reaches the cyclist

Answers

Answer 1
1) The car is initially at rest, and it accelerates for the first 10 seconds with acceleration a, so the distance it covers in these first 10 seconds is (in meters)
[tex]d_1 = \frac{1}{2}at^2 = \frac{1}{2}a(10 s)^2 = 50 a [/tex]
The velocity the car has reached after these 10 seconds is
[tex]v=at = a (10 s)=10 a[/tex] (3)
Then the car moves for other 5 seconds with this constant velocity (v=10 a) before reaching the cyclist. During this time, the distance it covers is
[tex]d_2 = v t = 10 a \cdot (5 s) =50 a[/tex]
So the total distance covered by the car is
[tex]d=d_1 + d_2 = 50 a + 50 a =100 a[/tex] (1)

The cyclist is moving at constant speed of [tex]v=9m/s[/tex], so the distance it covered during the 15 seconds is
[tex]d=vt=(9m/s)(15 s)=135 m[/tex] (2)

And since the car covered the same distance during this time, we can use (1) and (2) to find the acceleration of the car during the first 10 seconds:
[tex]a= \frac{d}{100}= \frac{135}{100} = 1.35 m/s^2 [/tex]


2) The velocity of the car when it reaches the cyclist is given by (3):
[tex]v_1= 10 a= (10 s)(1.35 m/s^2) = 13.5 m/s[/tex]
The velocity of the cyclist is [tex]v_2 = 9m/s[/tex], therefore the velocity of the car relative to the cyclist is
[tex]v' = v_1 - v_2 = 13.5 m/s - 9m/s=4.5 m/s[/tex]

Related Questions

Assume that you have two objects, one with a mass of 10 kg and the other with a mass of 18 kg, each with a charge of −0.027 c and separated by a distance of 9 m. what is the electric force that these objects exert on one another? answer in units of n.

Answers

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Final answer:

Using Coulomb's law, the electric force between two objects with charges of – 0.027 C each and separated by 9 m is 81 N. The force is repulsive since the charges are alike.

Explanation:

To calculate the electric force between two objects using Coulomb's law, one needs to know the charges on the objects and the distance separating them. Coulomb's law is represented by the formula F = k * |q1 * q2| / r2, where F is the force between the charges, k is Coulomb's constant (9.0 × 109 N·m2/C2), q1 and q2 are the amounts of the charges, and r is the distance between them.

In this case, with both objects having a charge of – 0.027 C and separated by a distance of 9 m, the electric force F is calculated as follows:

F = (9.0 × 109 N·m2/C2) * |(– 0.027 C) * (– 0.027 C)| / (9 m)2

Since the charges are like charges, the force will be repulsive and we can ignore the negative sign for the purposes of calculating magnitude:

F = (9.0 × 109 N·m2/C2) * (0.027 C * 0.027 C) / (81 m2) = 9.0 × 109 * 0.000729 / 81 = 8.1 × 101 N

Thus, the electric force between the two objects is 81 N acting to push them apart.

An automotive research facility is testing a new design on bumpers to determine the force at which it will break. The formula for Force is F = 1 2 m v 2 Where m is the mass (weight) and v is the velocity (speed)What is the effect on the force if the velocity changes from 5 miles per hour to 10 miles per hour?

What is the effect on the force if the velocity changes from 5 miles per hour to 10 miles per hour?

Same
Twice as much
Four times as much
Five times as much

Answers

Let's call (F1) the force produced with a speed of 5 miles per hour.
 Call (F2) the force produced with a speed of 10 miles per hour.
 To know what the effect on force is, change the speed from 5 miles per hour to 10 miles per hour, divide F2 / F1 to find the relation.
 So:
 F2 / F1 = (12m * 10²) / (12m * 5²)
 F2 / F1 = 4.
 Therefore, the answer is option 3.
 Strength increases 4 times more

What is the pressure of the gas in this mercury manometer if h = 63 mm and atmospheric pressure is 773 mmhg?

Answers

We can find the gas pressure by using a simple proportion.

In fact, if the pressure of the gas was equal to the atmospheric pressure:
[tex]p_a = 1.01 \cdot 10^5 Pa[/tex]
we know that the height in the mercury manometer would have been
[tex]h_a = 773 mm[/tex]

Therefore, if the heigth in the mercury manometer is
[tex]h=63 mm[/tex]
Then the pressure of the gas is given by the following proportion
[tex]h_a : p_a = h: p[/tex]
From which we find
[tex]p= \frac{h p_a}{h_a}= \frac{(63 mm)(1.01 \cdot 10^5 Pa)}{773 mm}=8231 Pa [/tex]

The intensity of the sun's radiation incident upon the earth is about i=1.4kw/m2. suppose this is the value for the intensity of sunlight incident upon the satellite's solar panels. what is the total solar power p absorbed by the panels?

Answers

Intensity = power/ Area
⇒ Power absorbed = 1× A ⇒ 1.4 × 10∧3 ×(10)
= 14000 Watt = 14 kWatt
time - averaged intensity divided by speed of light in free space is the radiation pressure
P = (1.4 × 1000)/c
Force = pressure × area ⇒ ((1.4× 1000)/(10∧8)) × 10
= 0.00004666666N
0.000047N

A neutral copper ball is suspended by a string. a positively charged insulating rod is placed near the ball, which is observed to be attracted to the rod. why is this? 1. the ball becomes positively charged by induction. 2. the string is not a perfect conductor. 3. there is a rearrangement of the electrons in the ball. 4. the ball becomes negatively charged by induction. 5. the number of electrons i

Answers

The correct answer is:
3. there is a rearrangement of the electrons in the ball. 

In fact, the ball is made by copper, which is a good conductor, therefore its electrons are free to move on the surface of the ball. When the positively charged rod is placed near to the ball, the electrons in the ball re-arrange, in particular they are attracted from the positive charges of the rod so they move closer to it. And since opposite-sign charges attract each other, the ball is then attracted by the rod.

The copper ball is attracted to the rod because the electrons in the ball rearrange themselves, making one side of the ball negative and the other positive. This process is known as electrostatic induction. Thus, option 3 is correct.

A neutral copper ball is observed to be attracted to a positively charged insulating rod due to electrostatic induction. Here's a step-by-step explanation:

Rearrangement of Electrons: When the positively charged rod is brought close to the neutral copper ball, the electrons in the copper ball are attracted towards the rod because opposite charges attract each other.Induced Polarization: This movement causes the side of the ball closer to the rod to become slightly negative due to the accumulation of electrons, while the side farther from the rod becomes slightly positive due to the lack of electrons.Attraction: The negatively charged side of the copper ball is attracted to the positively charged rod, causing the ball to move towards the rod.

Therefore, the correct reason for the observed attraction is the rearrangement of the electrons in the ball, making option 3 the correct answer.

What is the approximate wavelength of a light whose first-order bright band forms a diffraction angle of 45.0° when it passes

Answers

** Missing info: Lines per mm = 500 **

Ans: The wavelength is =  λ = 1414.21 nm

Explanation:
The formula for diffraction grading is:

dsinθ = mλ --- (1)

Where
d = 1/lines-per-meter = (1/500)*10^-3 = 2 * 10^-6
m = order = 1
λ = wavelength
θ = 45°

Plug in the values in (1):
(1) => 2*10^-6*sin(45°) = (1)λ
=> λ = 1414.21 nm

A certain part of the electromagnetic spectrum ranges from 200 nm to 400 nm. what is the highest frequency associated with this portion of the spectrum? (c = 3.00 × 108 m/s)

Answers

The lowest and highest wavelengths of this part of the electromagnetic spectrum are:
[tex]\lambda_1 = 200 nm=200 \cdot 10^{-9} m[/tex]
[tex]\lambda_2 = 400 nm=400 \cdot 10^{-9} m[/tex]

The frequency and the wavelenght of an electromagnetic wave are related by
[tex]f= \frac{c}{\lambda} [/tex]
where c is the speed of light and f the frequency. By using this equation, we can find the frequencies that corresponds to the lowest and highest wavelengths of this part of the spectrum:
[tex]f_1 = \frac{c}{\lambda_1}= \frac{3 \cdot 10^8 m/s}{200 \cdot 10^{-9} m}=1.5 \cdot 10^{15}Hz [/tex]
[tex]f_2 = \frac{c}{\lambda_2}= \frac{3 \cdot 10^8 m/s}{400 \cdot 10^{-9} m}=7.5 \cdot 10^{14}Hz [/tex]

So, the highest frequency associated with this part of the spectrum is the one corresponding to the lowest wavelength:
[tex]f_1 = 1.5 \cdot 10^{15}Hz[/tex]
Final answer:

The highest frequency associated with the portion of the electromagnetic spectrum ranging from 200 nm to 400 nm is 7.50 × 10^14 Hz.

Explanation:

The highest frequency associated with the portion of the electromagnetic spectrum ranging from 200 nm to 400 nm can be determined using the formula c = fλ, where c is the speed of light. In this case, the wavelength is given as 200 nm to 400 nm. Converting the wavelength to meters, we find that it corresponds to 2.00 × 10-7 m to 4.00 × 10-7 m. Using the formula, we can rearrange it to solve for the frequency, f = c/λ. Plugging in the values, we get the highest frequency as 7.50 × 1014 Hz.

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Many __________ cause poor pupil function more quickly than alcohol does.


A. Pain relievers

B. Antihistamines

C. Tranquilizers

D. Benzodiazepines

Answers

The answer is A. Pain Relievers

Answer:

B. Antihistamines

Explanation:

Whenever you have an allergy, your body creates a chemical called histamines. For a short term treatment against there allergies, you can take antihistamines. However, among the side effects of this treatment is poor pupil function.

So the correct answer is:

B. Antihistamines

What is the resistance of a resistor if the potential differences across the resistor is 4v when a cirrent of 10 a flow through the resistor?

Answers

R=V/I = 4v / 10A = 0.4 ohms

which formula represents Snell's law


Answers

Its B. n1sin01=n2sin02

Snell's law is used for refraction of light

it is used to find the relation between refractive index of two medium and angle of incidence and angle of refraction.

As per this formula

[tex]n_1 sin\theta_i = n_2 sin\theta_r[/tex]

here [tex]n_1[/tex] = refractive index of first medium

[tex]n_2[/tex] = refractive index of second medium where light go after refraction

[tex]\theta_i[/tex] = angle of incidence

[tex]\theta_r[/tex] = angle of refraction


When ultraviolet light with a wavelength of 400 nm falls on a certain metal surface, the maximum kinetic energy of the emitted photoelectrons is measured to be 1.10 ev . part a what is the maximum kinetic energy of the photoelectrons when light of wavelength 295 nm falls on the same surface? emax =?

Answers

A general relationship between Kinetic Energy (KE) and wavelength (y) is that KE is inversely proportional to square of y. That is,

KE α 1/y^2 => KE = k/y^2 where k is a constant of proportionality.

For KE = 1.10 ev, and y = 400 nm;

k = KE*y^2 = 1.10*400 = 176,000 ev.nm^2

For y = 295 nm,

KE = k/y^2 = 176,000/295^2 = 2.02 ev.

Therefore, e max = 2.02 ev

Light of wavelength 600 nm illuminates a diffraction grating. the second-order maximum is at angle 39.5 ∘. part a how many lines per millimeter does this grating have?

Answers

Diffraction equation applies in this case:

d*Sin x = m*wavelength, where d = spacing of lines, x = angle = 39.5°, m = order of maximum = 2

Substituting;
d* Sin 39.5 = 2*600*10^-9
d = (2*600*10^-9)/Sin 39.5 = 1.88656*10^-6 m

In 1 mm (or 0.001 m), the number of lines is given as;
Number of lines = 0.001/d = 0.001/(1.88656*10^-6) = 530.065 ≈ 530 lines

The number of lines per millimeter that the grating has is : 530 lines

Given data :

light wavelength = 600 nm

second order maximum angle ( x ) = 39.5°

order of maximum = 2

Determine the number of lines the grating will have

We will apply diffraction equation

[tex]d*sinx = m*wavelength[/tex] --- ( 1 )

where : d = spacing of lines, x =  39.5°, m = 2

Insert values into equation ( 1 ) above

d * Sin ( 39.5 ) = 2 * 600 * 10⁻⁹

therefore ; d = 1.88656 * 10⁻⁶ m

Final step : determine the number of lines per mm

Number of lines per mm

= 0.001 / d

= 0.001 / (1.88656 * 10⁻⁶ )  ≈ 530 lines

Hence we can conclude that The number of lines per millimeter that the grating has is 530 lines

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How many new elements (fission fragments, or daughter nuclei) are typically presented as a result of fission?

1

3

2

5

Answers

The correct option is 2.
Nuclear fission refer to a nuclear reaction in which the nucleus of a single radioactive element is split into two different smaller nuclei, which are different from the parent element accompany with the release of energy. Nuclear fission is typically used to produce energy. The two smaller nuclei are called fission products.

What are three benefits of being assertive and what are three tips to help you develop an assertive style of communication? (Site 1)

                 

Answers

1. The benefits of been assertive include the following:
a. It improve one self image: When you choose to be assertive, you adopt  a self realistic image.
b. It enhance how we understand others: Been assertive helps you to see others in a more realistic context.
c. Promote self awareness and self confidence: Been assertive helps you to develop a greater respect for your own points of view when dealing with issues. 
d. Been assertive is a less stressful way of communicating.

2. The three steps needed to develop assertive communication, include:
a. Learn to 'no' more often: refuse to please everyone and do not behave according to people expectations of you. Be yourself.
b. Your tone must be properly turned when talking: Do not raise your voice or rush a communication. Be calm and cool when talking.
c. Be open to communication: Be willing to discuss issues until a suitable solution is found.
d. Pay attention to non-verbal communication of others: Keep eye contact when communicating and pay attention to other body gestures. 

which step makes proteins by binding amino acids together

Answers

Translation is when proteins are produced from amino acids carried by tRNA. If you need a thorough explanation, you can message me.

Calculate the quantity of energy produced per gram of reactant for the fusion of h-3 (atomic mass = 3.016049 amu) with h-1 (atomic mass = 1.007825 amu) to form he-4 (atomic mass = 4.002603 amu).

Answers

The total mass of one atom of H-3 and H-1 is 4.02387 amu. The stated amu is 4.002603.
There is a mass difference because it is being converted into energy.
Mass difference is 0.021271 amu
If it is converted to equivalent to grams per mole.
Equal to 0.000021271 kg
By using the Einsteins equation, E= mc∧2.
Per mole is
E=0.000021271 × 299792458∧2J
E = 1.91174 × 10∧12 J per mole
The reactant of one mole is 4.02387 grams
The energy which is being released per gram of reactant is 4.751 × 10∧11J/g
Final answer:

The energy produced per gram of reactant for the fusion of H-1 with H-3 to form He-4, can be calculated using the difference of total initial and final masses, which is then used in Einstein's mass-energy equivalence principle (E=mc²). The number of such reactions in 1 gram of reactant is used to convert the energy per reaction to energy per gram of reactant.

Explanation:

To calculate the energy produced per gram of reactant in fusion reaction, first let's understand what's happening in the fusion reaction of H-3 with H-1. A helium nucleus is formed with a mass that is 0.7% less than that of four hydrogen nuclei. This mass loss is converted into energy.

The masses of the reactants are 3.016049 u for H-3 and 1.007825 u for H-1, giving us a total initial mass of 4.023874 u. The mass of the helium atom produced, He-4, is 4.002603 u. The mass loss during the reaction equals initial mass minus final mass, which is 0.021271 u.]

Applying Einstein's mass-energy equivalence principle E=mc², where E is energy, m is the lost mass and c is the speed of light, the energy produced in the reaction, can be calculated. To convert amu to kilograms, multiply by 1.66054 x 10⁻²⁷. So, the mass lost is 3.53 x 10⁻²⁹ kg.

As speed of light c = 3 x 10^8 m/s, using the equation we get E = 3.53 x 10⁻²⁹ kg x (3 x 10⁸m/s)² = 3.18 x 10⁻¹²Joules.

Finally, to get the energy per gram, we calculate the number of such reactions in 1 gram of reactants. That would be (1 g)/(4.023874 g/mol) x Avogadro's number (6.02 x 10^23). Multiply this number with the energy produced per reaction to get the energy produced by 1 gram of reactant.

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1. Which of the following statements about mechanical waves is true?
a. mechanical waves require a medium to travel through
b. mechanical waves do not have amplitude and wavelength
c. mechanical waves do not have frequency
d. mechanical waves can travel through blank space

2. Which waves have the shortest wavelength and highest energy on electromagnetic spectrum?
a. microwaves
b. x-rays
c. infrared
c. gamma rays

3. What is true about infrared and X-Rays?
a. X-Rays have greater longer wavelength than infrared
b. Infrared have shorter wavelength than x-rays
c. x-rays have lower energy than infrared
d. Infrared have lower frequency than x-rays

4. In a longitudinal wave (compression wave_ the particles of a matter move ______
a. perpendicular (at right angles)
b. in a circular direction
c. backwards
d. parallel

5. In regard to spend of sound, sound travels slowest in ____
a. solids
b.liquids
c. gases

Answers

1) a. mechanical waves require a medium to travel through
In fact, mechanical waves cannot travel trough empty space, but they always require a medium for their propagation. (on the contrary, electromagnetic waves can also travel through empty space)

2) d. gamma rays
In fact, gamma rays are the radiations with shortest wavelength on the electromagnetic spectrum (range in the picometer). Correspondingly, this is the radiation with highest energy, because the energy of the radiation is inversely proportional to its wavelength, according to:
[tex]E=h \frac{c}{\lambda} [/tex]
where h is the planck constant, c the speed of light and [tex]\lambda[/tex] the wavelength.

3) d. Infrared have lower frequency than x-rays
In fact, infrared radiation has frequency in the range of the THz (terahertz, [tex]10^{12} Hz[/tex]), while x-rays have frequency in the range of hundreds of PHz (Petahertz, [tex]10^{15}Hz[/tex]).

4) d. parallel
In longitudinal waves, the oscillations of the wave (such as the motion of the particles in a compression wave) occur in the direction parallel to the direction of propagation of the wave itself.

5) c. gases
Sound travels slowest in gases. In fact, the speed of sound is proportional to the density of the medium: the more dense the medium is, the faster is the sound in that medium, and vice-versa. Since gases are less dense than liquids and solids, sound travels slowest in gases. The reason is that sounds propagates through the oscillations of the molecules of the medium; if the medium is less dense (such as in gases), it takes more time to transmit the sound through the medium itself.
Final answer:

Mechanical waves require a medium to travel, gamma rays have the highest energy and shortest wavelength on the electromagnetic spectrum, x-rays have higher frequency than infrared, particles in a longitudinal wave move in parallel, and sound travels slowest in gases.

Explanation:

1. The correct statement about mechanical waves is 'a. mechanical waves require a medium to travel through'. Unlike electromagnetic waves, mechanical waves, such as sound or seismic waves, need a medium like air, water, or solids to propagate or move.

2. The waves with the shortest wavelength and highest energy on the electromagnetic spectrum are 'c. gamma rays'.

3. The true statement about infrared and X-Rays is 'd. Infrared has lower frequency than x-rays'. X-rays have a higher frequency and shorter wavelength compared to infrared waves, which directly impacts their energy levels, with X-rays having higher energy.

4. In a longitudinal wave (compression wave), the particles of matter move 'd. parallel' to the direction of the wave's propagation. This is different from transverse waves where particles move perpendicular to the wave direction.

5. Sound travels slowest in 'c. gases'. Sound waves travel the fastest through solids, slower through liquids, and slowest through gases.

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Which statement is true of equinoxes? They occur in June and December. Days and nights are equal in length everywhere. The length of daylight in the Arctic and Antarctic circles is 24 hours. The sun’s vertical rays are striking either 23.5°S or 23.5°N.

Answers

Days and nights are equal in length everywhere.(gradpoint)

Answer: Days and nights are equal in length everywhere.

Explanation:

Equinox means equal night. There are two equinox - vernal equinox and autumnal equinox. When the sun crosses celestial equator, the sun rays fall directly over equator at noon. Thus, there is equal length of day and night in the two hemisphere. It occurs around March 22 and September 22.

Three 1.2 ohm lamps are connected in series and connected to a 3 volt battery. Calculate the total current in the circuit

Answers

Since the 3 lamps are connected in series, their equivalent resistance is equal to the sum of the three resistors:
[tex]R_{eq} =R_1+R_2+R_3=1.2 \Omega + 1.2 \Omega +1.2 \Omega = 3.6 \Omega[/tex]

And the total current flowing in the circuit can be calculated by using Ohm's law:
[tex]I= \frac{V}{R_{eq}} [/tex]
where V is the voltage of the battery. By using V=3 V, we find
[tex]I= \frac{3 V}{3.6 \Omega}= 0.83 A[/tex]

which form of energy is involved in weighting fruit on a spring scale ?

Answers

The correct answer is elastic potential energy.

I hoped this helped!
The answer would be ELASTIC POTENTIAL ENERGY...





Hope that helps!!!!

How many photons per second are emitted by the antenna of a microwave oven if its power output is 1.00 kw at a frequency of 2515 mhz?

Answers

Final answer:

To determine the number of photons emitted per second by the antenna of a microwave oven, we need to use the formulas for energy per photon and number of photons.

Explanation:

The number of photons emitted by the antenna of a microwave oven can be calculated using the formula:

Number of photons = (Power output / Energy per photon) x frequency

To find the energy per photon, we can use the formula:

Energy per photon = Planck's constant x frequency

Given that the power output is 1.00 kW and the frequency is 2560 MHz, we can convert these values to SI units and calculate the number of photons emitted per second.

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Approximately 6.01 x 10²⁶ photons per second are emitted by the antenna of the microwave oven.

To determine the number of photons emitted per second by a microwave oven, we can use the formula:

Number of Photons per Second (N) = Power Output (P) / Energy per Photon (E)

Given:

Power Output (P) = 1.00 kW (or 1000 W)Frequency (f) = 2515 MHz (or 2.515 x 10⁹ Hz)

First, find the energy per photon (E) using the equation:

E = h * f

where h is Planck's constant (6.626 x 10⁻³⁴ Js) and f is the frequency.

Substitute the values:

E = 6.626 x 10⁻³⁴ Js * 2.515 x 10⁹ Hz

E = 1.665 x 10⁻²⁴ J

Next, calculate the number of photons per second:

N = P / E

N = 1000 W / 1.665 x 10⁻²⁴ J

N ≈ 6.01 x 10²⁶ photons per second

Therefore, the antenna of the microwave oven emits approximately 6.01 x 10²⁶ photons per second.

What's the pressure and temp of 6694 meters high

Answers

Applying rule of thumb: For every 1000 m, temperature drops by 2 °C. If the ground temperature is room temperature at 20 °C, then:

At 6694 m, temperature = 20 - (6694/1000*2) = 6.6°C
Now,
H= (30t+8000)*ln (C/P), where H = Altitude, t = temperature, C = ground atmospheric pressure, say 101325 Pa, P is the pressure at the altitude.

Therefore,
6694 =(30*6.6+8000) ln (C/P) => 0.8165 = ln (1013255/P) => e^0.8165 = 101325/P => 2.2627 = 101325/P => P = 101325/2.2627 = 44781.39 Pa

Organ pipe a, with both ends open, has a fundamental frequency of 340 hz. the third harmonic of organ pipe b, with one end open, has the same frequency as the second harmonic of pipe
a. how long are (a) pipe a and (b) pipe b? (take the speed of sound to be 343 m/s.)

Answers

The fundamental frequency of the open pipe A
Length 'L₀' is, f₀ = U/2L₀ = 340 H₂
the speed of sound in air V=  343m/s
∴343/2L₀ = 340 → length L₀ = 343/2 ×340 = 0.5044 = 50.44
The third harmonic of closed pipe 'B' is 
F3₀ = 3V/4LC
The second harmonic of open pipe 'A'  is
f2₀ = 2V/2L₀
∴ 3V/4LC = 2V/2L →L₀ = 3L₀/4
⇒ The length of closed pipe B is 
Lc = 37.83cm

If the building absorbed so much heat that it turned into a liquid, then it would have undergone a phase change known as _____.

freezing

vaporizing

condensing

melting

Answers

when something gets to hot it reaches its melting point, meaning it melts. the the answer would be D melting

Answer:

Melting

Explanation:

If the building absorbed so much heat that it turned into a liquid, then it would have undergone a phase change known as:

freezing. NO. Freezing is the process in which a liquid turns into a solid.vaporizing. NO. Vaporizing is the process in which a liquid turns into a gas.condensing. NO. Condensing is the process in which a gas turns into a liquid.melting. YES. Melting is the process in which a solid turns into a liquid.

Which lists the amplitudes of sound waves from these sources in order from greatest to least?

busy roadway, kids whispering, average home

chainsaw, diesel truck, rustling leaves

kids whispering, vacuum cleaner, jet airplane

library, conversational speech, music from speaker

Answers

Answer:

The correct answer is option B which is a chainsaw, diesel truck, rustling leaves.

Explanation:The amplitude of the sound wave is the maximum displacement of the particles from their resting position.Higher the amplitude means high sound.So the sound of a chainsaw is high, so its amplitude will be great and after that the amplitude of diesel truck is high and rustling leaves have the lowest amplitude.

Answer:

B

Explanation:

Edge :)

Two long parallel wires carry currents of 20 a and 5.0 a in opposite directions. the wires are separated by 0.20 m. what is the magnitude of the magnetic field midway between the two wires?

Answers

Final answer:

The magnitude of the magnetic field midway between two long parallel wires carrying currents of 20 A and 5.0 A in opposite directions and separated by 0.20 m is 4.5 x 10⁻⁵ T.

Explanation:

To find the magnitude of the magnetic field midway between the two long parallel wires carrying currents of 20 A and 5.0 A in opposite directions and separated by 0.20 m, we can use the formula for the magnetic field due to a long straight wire. The magnitude of the magnetic field at a distance r from the wire is given by: B = (μ₀ * I) / (2π * r). Since we are looking for the magnetic field midway between the wires, the distance from each wire to the point is half of the total separation, which is 0.10 m. Plugging in the values, we get: B = (4π * 10⁻⁷ T·m/A * (20 A + 5.0 A)) / (2π * 0.10 m) = 4.5 x 10⁻⁵ T.

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Final answer:

The magnitude of the magnetic field midway between two parallel wires carrying currents of 20 A and 5 A in opposite directions and separated by 0.20 m is 3 * 10^-6 T.

Explanation:

To find the magnitude of the magnetic field midway between the two wires, we can use the formula for the magnetic field produced by a long straight wire:

B = (μ0 * I) / (2πr)

where B is the magnetic field, μ0 is the permeability of free space, I is the current, and r is the distance from the wire. In this case, we have two wires with currents of 20 A and 5 A, and they are separated by 0.20 m. Since we are interested in the magnetic field midway between the wires, the distance r will be half of the separation between the wires, which is 0.20 m / 2 = 0.10 m.

Plugging in the values, we get:

B = (4π * 10-7 T·m/A * (20 A - 5 A)) / (2π * 0.10 m) = (4 * 10-7 T·m/A * 15 A) / (0.20 m) = 3 * 10-6 T

So, the magnitude of the magnetic field midway between the two wires is 3 * 10-6 T.

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At what speed does the classical momentum, p=mv, give an error, when compared with the relativistic momentum, of 1.35 % ?

Answers

The classical momentum is given by:
[tex]p_c=mv[/tex]
where m is the particle mass and v its velocity, while the relativistic momentum is given by:
[tex]p_r=\gamma mv[/tex]
where 
[tex]\gamma = \frac{1}{ \sqrt{1- \frac{v^2}{c^2} } } [/tex]  (1)
is the relativistic factor, with c being the speed of light.

The condition given by the problem (error of 1.35%) can be rewritten as
[tex] \frac{p_r - p_c}{p_r} = 0.0135 [/tex]
which means
[tex]p_r = \frac{p_c}{0.9865} [/tex]
and since [tex]p_r = \gamma p_c[/tex], this also means that
[tex]\gamma = \frac{1}{0.9865}=1.0137 [/tex]

Now let's re-arrange eq.(1), and we get
[tex]v=c \sqrt{1- \frac{1}{\gamma^2} } [/tex]
and if we use [tex]\gamma=1.0137[/tex] as we found before, and [tex]c=3 \cdot 10^8 m/s[/tex], we find the corresponding velocity:
[tex]v=(3 \cdot 10^8 m/s) \sqrt{1- \frac{1}{(1.0137)^2} } = 4.9 \cdot 10^7 m/s[/tex]

Final answer:

To calculate the speed at which the classical momentum gives an error compared to the relativistic momentum, we need to find the ratio of the two different momenta. This can be done by solving for the velocity using the given equations and approximations.

Explanation:

The classical momentum, p=mv, gives an error when compared with the relativistic momentum. The error can be calculated by finding the ratio of the relativistic momentum to the classical momentum. In this case, the error is 1.35%. To find the velocity at which this error occurs, we need to solve for the velocity using the given equations and approximations.

(a) Find the momentum of a 1.00 × 10⁹ kg asteroid heading towards the Earth at 30.0 km/s.

(b) Find the ratio of this momentum to the classical momentum. (Hint: Use the approximation that y = 1+(1/2)v²/c² at low velocities.)

The most common natural fiber found at a crime scene, and thus forensically insignificant (unless it is of a unique color)

Answers

i believe the answer is cotton
The answer is cotton.

¿Cuál es la velocidad promedio de un hombre que camina 70m con una rapidez de 1m/s y luego corre 70m con una rapidez de 3m/s?

Answers

Hola!

Respuesta:

[tex]1,5 \frac{m}{s} [/tex]

Explicación:

Para calcular la velocidad promedio, necesitamos conocer dos cosas:

1: Distancia total recorrida
2: Tiempo total del recorrido

Del enunciado tenemos los siguientes datos:

Primer tramo:

Distancia recorrida : 70 m
Velocidad: [tex] \frac{1m}{s} [/tex]

Segundo tramo:

Distancia recorrida:70 m
Velocidad: [tex]\frac{3m}{s}[/tex]

Utilizando la siguiente formula:

[tex]X=Xo + V.t[/tex]

Donde:

X: Distancia final
Xo: Distancia inicial
V: Velocidad
T: Tiempo

Para este ejercicio, nos es dada la distancia recorrida, es decir  la diferencia entre la distancia final (X) y la distancia inicial (Xo), teniendo que:

[tex]X-Xo= V. t[/tex]

Sustituyendo los valores del primer tramo, tenemos:

[tex]70m= \frac{1m}{s} .t \\ t= \frac{70m}{ \frac{1m}{s \\ } } \\ t= 70s [/tex]

Sustutuyendo los valores del segundo tramo, tenemos:

[tex]70m= \frac{3m}{s} .t \\ t= \frac{70m}{ \frac{3m}{s \\ } } \\ t= 23,33 s[/tex]

Calculando ambos tiempos, tenemos un tiempo de recorrido total de:

[tex]Ttotal= [/tex] Tiempo en el tramo 1 + Tiempo en el tramo 2 [tex]= 93,33 s[/tex]

Para calcular la velocidad promedio, dividimos la distancia total del recorrido por el tiempo total recorrido. Esta viene dada por la siguiente formula:

[tex]Vprom= \frac{Distancia Total}{Tiempo Total} = \frac{140 m}{93,33s} = \frac{1,5m}{s} [/tex]

Que tengas un buen día!


Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined that the football would travel 15.1 m before landing. How would this value change if the football was kicked at an angle of 35.0°?Complete all equations without rounding and then round to the nearest tenth at the end.

Answers

Applicable equation:

R = [v^2* Sin 2Ф]/g, where R = horizontal range, Ф = angle, v = initial velocity, g=gravitational acceleration.

The missing value is the exact gravitational acceleration. Therefore,
g = [v^2*Sin 2Ф]/R = [13.9^2*Sin (2*25)]/15.1

At Ф = 35°;

R = [13.9^2*Sin (2*35)]/ {[13.9^2*Sin (2*25)]/15.1} = [15.1*Sin 70]/[Sin 50] ≈ 18.5 m

Therefore, if the ball was kicked at 35.0°, it would travel to 18.5 m before landing.

Answer:

If the football is kicked at a 35.0º angle, it will travel 18.5 m before landing. This is farther than if it were kicked at a 25° angle.

Explanation:

what it says on edge

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