Final answer:
By setting up a system of linear equations from the given conditions, we can determine that a large box weighs 60 pounds, and a small box weighs 35 pounds.
Explanation:
To solve the problem involving the weights of large and small boxes being transported by a delivery truck, we can set up a system of linear equations. Let L represent the weight of a large box and S represent the weight of a small box. We know from the problem statement the following:
A large box plus a small box weighs 95 pounds: L + S = 95
Total weight of all boxes: 50L + 65S = 5275
Now we can solve this system of equations by substitution or elimination. If we solve the first equation for L, we get L = 95 - S. Substituting this into the second equation gives us:
50(95 - S) + 65S = 5275
Expanding and simplifying the equation, we get:
4750 - 50S + 65S = 5275
15S = 5275 - 4750
15S = 525
S = 35
Now that we have the weight of the small box, we can substitute it back into the first equation to find the weight of the large box:
L + 35 = 95
L = 60
Therefore, a large box weighs 60 pounds, and a small box weighs 35 pounds.
Use the formula V = s³, where V is the volume and s is the edge length of the cube, to solve this problem.A cube-shaped bin has an edge length of 34 yard.What is the volume of the container? Enter your answer, as a fraction in simplest form, in the box.
which are the solutions of the quadratic equation x^2=9x+6
The solutions of the quadratic equation [tex]\(x^2 = 9x + 6\)[/tex]are:
[tex]\[x = \frac{9 + \sqrt{105}}{2}\][/tex] and [tex]\[x = \frac{9 - \sqrt{105}}{2}\][/tex]
To find the solutions of the quadratic equation [tex]\(x^2 = 9x + 6\)[/tex], we need to rewrite it in standard quadratic form [tex]\(ax^2 + bx + c = 0\).[/tex]
Given:
[tex]\[x^2 = 9x + 6\][/tex]
Subtract [tex]\(9x\) and \(6\)[/tex] from both sides to get it in standard form:
[tex]\[x^2 - 9x - 6 = 0\][/tex]
Now, to solve this quadratic equation, we can factor it or use the quadratic formula:
The quadratic formula is:
[tex]\[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\][/tex]
For our equation:
[tex]\[a = 1, b = -9, \text{ and } c = -6\][/tex]
Substituting these values into the quadratic formula:
[tex]\[x = \frac{-(-9) \pm \sqrt{(-9)^2-4(1)(-6)}}{2(1)}\]\[x = \frac{9 \pm \sqrt{81+24}}{2}\]\[x = \frac{9 \pm \sqrt{105}}{2}\][/tex]
So, the solutions of the quadratic equation [tex]\(x^2 = 9x + 6\)[/tex]are:
[tex]\[x = \frac{9 + \sqrt{105}}{2}\][/tex] and [tex]\[x = \frac{9 - \sqrt{105}}{2}\][/tex]
A large bag of marbles contains an equal amount of red, orange, yellow, blue, and green marbles. Brody randomly selects 1 marble from the bag. Which of the following represents the probability of selecting a red, blue, yellow, or green marble
A) 0.8
B) 0.7
C) 0.9
D) 0.6
Answer: The correct option is (A) 0.8.
Step-by-step explanation: Given that a large bag of marbles contains an equal amount of red, orange, yellow, blue, and green marbles. Brody randomly selects 1 marble from the bag.
We are to find the probability of selecting a red, blue, yellow or green marble.
Let n be the number of each color of marbles in the bag.
That is, the number of red, orange, yellow, blue, and green marbles, each equals n.
Let S denote the sample space of selecting a marble from the bag and A denote the event of selecting a red, blue, yellow or green marble.
Then, we have
n(S) = n + n + n + n + n = 5n,
n(A) = n + n + n + n = 4n.
Therefore, the probability of event A is given by
[tex]P(A)=\dfrac{n(A)}{n(S)}=\dfrac{4n}{5n}=\dfrac{4}{5}=0.8.[/tex]
Thus the required probability selecting a red, blue, yellow or green marble is 0.8.
Option (A) is CORRECT.
If the function graphed is f(x), find f(1).
A) -4
B) -1/4
C) 0
D) 4
El lote de la familia lópez tiene un lote de 16m*10m y se desea construir una casa de base rectangular en el centro de el.¿que dimensiones debe tener el rectángulo del piso de la casa si tiene un área de 91m2?
a building in san francisco is shaped like a square pyramid it has a slant height og 856.1 feet and each side of its base is 145 feel long find the lateral area of the building
Let g(x) = 2x and h(x) = x2 + 4. Evaluate (h ∘ g)(1). 2 8 10 4
Abby walked miles on Monday, miles on Tuesday, and miles on Wednesday. What is the total distance Abby walked in the three days?
a. miles
b. miles
c. miles
d. miles
Answer:WE Cant se the numbers
Step-by-step explanation:the ancwer would be 7 and 7/12
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
we are given
[tex]\frac{3x^6-19x^4-4x^3-24x^2+2x+178}{-2x^2-6}[/tex]
we can use long division method to divide it
so, we get
[tex]Quotient=-\frac{3x^4}{2}+14x^2+2x-30[/tex]
[tex]Remainder=14x-2[/tex]...........Answer
Compare and Contrast: Below are two equations. Solve each equation and compare the two solutions. Choose the statement that is true about each solution. Equation #1 Equation #2 |2x - 4| = 5 |3x - 4| = -12 Equation #1 and Equation #2 have the same number of solutions. Equation #1 has more solutions than equation #2. Equation #1 has fewer solutions than equation #2. None of the statements above describe the number of solutions to equations shown.
12 ticket sellers, 25 cleaning persons, and 15 ushers employees will be paid $10, $7.50, 8.50 per hour for 50 hours per month what is the monthly salary
A freight carrier charges $0.57 for a package weighing up to one ounce plus and additional $0.32 for each additional ounce or fraction of an ounce. A company is shipping a package weighing 224 grams. What is the weight of the package in ounces?
Answer:
its is 8 oz 224 grams is = to 7.901
Step-by-step explanation:
3. Divers looking for a sunken ship have defined the search area as a triangle with adjacent sides of length 2.75 miles and 1.32 miles. The angle between the sides of the triangle is 35. To the nearest hundredth, find the search area. 2.08 mi²
2.97 mi²
1.49 mi²
1.04 mi²
Answer:
2.08 mi²
Step-by-step explanation:
Since, the area of the triangle is,
[tex]A=s_1\times s_2\times sin \theta[/tex]
Where, [tex]s_1[/tex] and [tex]s_2[/tex] are adjacent sides and [tex]\theta[/tex] is the included angle of these sides,
Here, [tex]s_1[/tex] = 2.75 miles,
[tex]s_2[/tex] = 1.32 miles,
And, [tex]\theta[/tex] = 35°,
hence, the area of the given triangle is,
[tex]A=2.75\times 1.32\times sin 35^{\circ}[/tex]
[tex]= 3.63\times 0.57357643635[/tex]
[tex]= 2.08208246395\approx 2.08\text{ square miles}[/tex]
Find the product of (x + 5)(x − 5). (1 point)
x2 − 10x + 25
x2 + 10x + 25
x2 − 25
x2 + 25
Carbon-14 has a half-life of 5,730 years. If the age of an object older than 50,000 years cannot be determined by radiocarbon dating, then
* carbon-14 levels in a sample are undetectable after approximately ten half-lives.
* carbon-14 levels in a sample are undetectable after approximately nine half-lives.
* the half-life of carbon-14 is too long to accurately date the object.
* a radioisotope with a shorter half-life should be used to date the object.
PLZ HELP ME ON THIS
PLZ EXPLAIN IT TO ME
If the clock has a radius of 15 inches, how many inches of ribbon will terry need to use to surround the clock?
please help.
solve the inequality |6 - v| < 9
write the inequality as two inequalities with the absolute value and give a solution set.
helppppppppppppppppppppp
30 POINTS + BRAINLIEST! SHOW YOUR WORK FOR BRAINLIEST PLEASE!
2x+3+4x+3= 180o 6x+6=180 6x=174 174/6 29
2x+1 (2)29+1 59o
Step-by-step explanation:
Please help me answer
The area of a right triangle with one leg measuring 5ft and hypotenuse measuring 13ft is
A 30ft to the 2
B 37.5 ft to the 2
C 65ft to the 2
99pts WILL GIVE BRAINLIEST Use the diagram and given information to answer the questions and prove the statement. Given: X Z
Prove: [see image] Re-draw the diagram of the overlapping triangles so that the two triangles are separated.
What additional information would be necessary to prove that the two triangles, XBY and ZAY, are congruent?
What congruency theorem would be applied?
Prove using a list/flow chart proof.
Joes is 10 years older than james. in 8 years joe will be three times older than james. how old are they now
6.3% of 41 is?
a. 2.6
b. 6.5
c. 258.3
d. 650.8
What is the missing value in the following arithmetic sequence?
Answer:
Step-by-step explanation:
Alright, lets get started.
The first term is 2 and the second term is 3.8.
It means the common difference is [tex]3.8-2 = 1.8[/tex]
So, adding common difference :
First term = 2
Second term = 3.8
Third term = [tex]3.8+1.8=5.6[/tex]
Fourth term = [tex]5.6+1.8 = 7.4[/tex]
So the answer is 7.4 : answer
Hope it will help :)
Can someone please help me solve for x and y? Thank you
Please help.
What are the dimensions of the matrix?
⎡1 0 9⎤
⎢-2 3 5⎢
⎢5 4 -6⎢
⎣11 5 7⎦
Enter your answers in the boxes.
The matrix is a [_] × [_] matrix.
The size of a matrix is defined by the number of rows and columns that it contains.
The dimensions of a matrix are the number of rows by the number of columns.
The number of rows and columns of a matrix, written in the form rows×columns.
The given Matrix has four rows and three columns,
The rows go side to side; the columns go up and down. "Row" and "column" are technical terms, and are not interchangeable.
Matrix dimensions are always given with the number of rows first, followed by the number of columns.
The matrix is a [4_] × [3_] matrix.
The sales tax on a $250 computer is 17.50. find the sales tax rate.
2, 4, 6, 8, 10
I know this diverges but what is the limit?
Also, is there a limit with numbers that repeat? (ie: -1,1,-1,1...(-1)^n)