You see a marble sign. Its letters are too worn to read. What caused this?
The worn letters on a marble sign are the result of weathering and erosion from natural elements, human activities, and pollution, which cause the marble to deteriorate over time.
If you see a marble sign with letters too worn to read, it's likely that the sign has been subjected to various forms of weathering and erosion. Over time, natural elements like rain, wind, temperature changes, and possibly even the growth of lichens or moss can cause the marble to wear down. This process can gradually erase the inscriptions on the sign.
Additionally, human activities such as touching or rubbing the sign can accelerate the erosion of marble, further contributing to the letters becoming unreadable. Moreover, pollution can also have a corrosive effect on marble, causing the inscriptions to fade more quickly.
Overall, the combined effects of natural weathering, human interference, and environmental pollutants are responsible for the deterioration of marble signs and their inscriptions.
Paul and Ivan are riding a tandem bike together. They’re moving at a speed of 5 meters/second. Paul and Ivan each have a mass of 50 kilograms. What can Paul do to increase the bike’s kinetic energy?
A. He can let Ivan off at the next stop.
B. He can pedal harder to increase the rate to 10 meters/second.
C. He can reduce the speed to 3 meters/second.
D. He can pick up a third rider.
Answer: The correct answer is option C.
Explanation:
Kinetic energy is the energy possessed by the an object due to its motion.An its calculated by:
[tex]K.E.=\frac{1}{2}mass\times (velocity)^2[/tex]
Kinetic energy depends upon the mass and velocity of the an object.
So, Paul can increase the bike's kinetic energy by increasing the velocity of its bike. Hence, the correct answer is option C.
Increasing the mass will also increase the kinetic energy . But according to option (D) he has to stop the bike first by applying brakes which will reduce the kinetic energy of the bike.And then again have to perform the work to bring the bike in motion
A book rests on a table, exerting a downward force on the table. the reaction to this force is:
24 g of water is heated from 25 c to 35
c. how much heat energy was required
The heat energy required is approximately 1000 calories (or 4184 joules).
To calculate the heat energy required, we can use the formula:
Q = mcΔT
where:
Q = heat energy (in calories or joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in cal/g°C or J/g°C)
ΔT = change in temperature (in °C)
For water, the specific heat capacity is approximately 1 cal/g°C or 4.184 J/g°C.
Given that the mass of water (m) is 24 grams, and the change in temperature (ΔT) is 35°C - 25°C = 10°C, we can plug the values into the formula:
Q = (24 g) * (1 cal/g°C) * (10°C)
Q ≈ 240 calories
Since 1 calorie is approximately 4.184 joules, the heat energy required in joules is:
Q ≈ 240 calories * 4.184 J/cal
Q ≈ 1004.16 joules
So, approximately 1000 calories (or 1004.16 joules) of heat energy were required to heat 24 grams of water from 25°C to 35°C.
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Tai ran from his home to a position 300 m south of his home in 100 seconds. What was his velocity? A.0.33 m/s south B.0.33 m/s north C.3 m/s north D.3 m/s south
Why aren’t organisms on the sea floor crushed by water pressure
rapid energy transfer between ____ and ____ energy make roller coasters thrilling
When photons with a wavelength of 310 nm strike a magnesium plate the maximum velocity of the ejected electrons is 3.45*10^5 m/s. calculate the binding?
A uniform rod XY of weight 10.0N is freely hinged to a wall at X. It is held horizontal by a force F acting from Y at an angle 30° to the horizontal, as shown.
What is the value of F?
A- 5.0 N B- 8.7cm C- 10.0cm D-20.0cm
The value of the horizontal force acting on the rod is 10 N. Therefore option (C) is correct.:
Given data:
The weight of rod is, W = 10.0 N.
The angle made by force with respect to horizontal is, [tex]\theta = 30^\circ[/tex].
To maintain the steady position (equilibrium condition), the vertical component of force F must be balanced by the moment of force due to weight.
Therefore,
[tex](Fsin\theta) \times L = W \times \dfrac{L}{2} \\\\(F \times sin30^{\circ}) = \dfrac{10}{2} \\F = 10 \;\rm N[/tex]
Thus, the value of the horizontal force acting on the rod is 10 N. And option (C) is correct.
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which vector best represents the net force acting on the -3 C charge in the diagram
w
x
y
z
Answer:
W is the correct answer.
Explanation:
Since the charges are negative the forces acting is repulsive.
The left -4C charge repulse -3C, the force is shown in figure given as F2
The right -4C charge repulse -3C, the force is shown in figure given as F1
Since the charge magnitudes are same the magnitude of F1 and F2 are same, but their direction is different. From second figure we can see the angle between forces and W is 30⁰.
On resolving vectors the force along Z = F1 sin 30 and force along X = F2 sin 30
Since magnitudes are same they cancel each other.
Force along W = F1 cos 30 + F2 cos30 = 2Fcos 30 (Say F1 = F2 = F)
So net force is directed towards Z.
What is the energy of a photon with a frequency of 1.7 × 1017 Hz? Planck’s constant is 6.63 × 10–34 J•s.
1.1 × 10–17 J
1.1 × 10–16 J
8.3 × 10–16 J
8.3 × 10–15 J
Answer:
The correct answer is B.
Explanation:
Got a 100% on the Exam
When a clock reads 5.0 seconds a cart's velocity in the negative x direction is 3.0 m/s. when the clock reads 6.0 seconds, the cart's velocity in the positive x direction is 4.0 m/s. what is the magnitude (in m/s2) of the average acceleration of the cart?
The kinematic we find the average acceleration of the body is 7 m/s²
Given parameters
The velocity at two instant of time t₁ = 5.0 s, v₁ = -3.0 m / st₂= 6.0 s, v₂ = 4.0 m / s
To find
The average acceleration of the bodyKinematics studies the movement of the carpus, establishing relationships between their position, speed and acceleration.
Average acceleration is defined as the change in velocity in a given time interval
a_ {avg} = [tex]\frac{\Delta v}{\Delta t}[/tex]
Let's apply this expression to our case
let's set a reference frame where the positive direction of the x axis is positive, so v₁ is negative
a_ {avg} = [tex]\frac{v_2 -v_1}{t_2 -t_1}[/tex]
a_ {avg} = [tex]\frac{4- (-3)}{6-5}[/tex]
a_ {avg} = 7 m / s²
In conclusion using kinematics we find the average acceleration of the body is 7 m / s²
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A piston-cylinder system contains of 3 kg of saturated mixture of water at 160 kpa. initially, water is in liquid phase. heat is now transferred to the water and the piston, which is at the stop, start moving when the pressure reaches 500 kpa. heat transfer continues until the total volume increases by %20. determine,
a.the initial and final temperature,
b.the mass of liquid when the piston first starts moving, and
c.the work done during this proce
Why does a clear stream always appear to be shallower than it actually is?
Clear streams apparently look shallower than actual stream due to refraction of light.
What is refraction of light?Refraction is the redirection of a wave as it passes from one medium to another medium. The redirection can be because of the wave's change in speed or by a change in the medium.
The refracted light coming from water always bends away from the normal at the surface. The refracted light coming from rarer to denser medium always bends towards normal at the surface.
When some one see the base of the steam from the top of water, stream base appears elevated to the surface. This happens in water as light travels slower in water than in a vacuum.
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If an object that enters the Earth’s atmosphere does not completely disintegrate, its remains can impact the Earth true or flase
A raft is made of a plastic block with a density of 650 kg/m 3 , and its dimensions are 2.00 m à 3.00 m à 5.00 m. 1. what is the volume of the raft? _________________________________________________________________ 2. what is its mass? _________________________________________________________________ 3. what is its weight? _________________________________________________________________ 4. what is the raft's ap parent weight in water? (hint: density of water = 1.00 à 10 3 kg/m 3 ) _________________________________________________________________ 5. what is the buoyant force on the raft in water? _________________________________________________________________ 6. what is the mass of the displaced water? _________________________________________________________________ 7. what is the volume of the displaced water? _________________________________________________________________ 8. how much of the raft's volume is below water? how much is above? _________________________________________________________________ 9. answer items 5 â 8 using ethanol (density = 0.806 à 10 3 kg/m 3 ) instead of water.
Gold, which has a density of 19.32 g/cm3, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long fiber. (a)if a sample of gold with a mass of 7.583 g, is pressed into a leaf of 3.061 μm thickness, what is the area (in m2) of the leaf? (b)if, instead, the gold is drawn out into a cylindrical fiber of radius 2.500 μm, what is the length (in m) of the fiber?
A brick is dropped from 100m up. Find it's impact velocity and air time.
A man pushes a 35.2 kg box across a frictionless floor with a force of 128 N. What is the acceleration of the box
When a man pushes a 35.2 kg box across a frictionless floor with a force of 128 N, then the acceleration of the box would be 3.6363 meters/second².
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum. The mathematical expression for Newton's second law is as follows
F = ma
As given in the problem if a man pushes a 35.2 kg box across a frictionless floor with a force of 128 N, we have to calculate the acceleration of the box
Force = mass ×acceleration
128 = 35.2 × acceleration
acceleration = 128/35.2
= 3.6363 meters/second².
Thus, the acceleration of the box would be 3.6363 meters/second².
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A ball is thrown at a height of 1.2m above the ground with an initial speed of 20 m/s at an angle 60 degrees above the horizontal. find a vector valued function r(t) describing the position of the ball
Three uncharged capacitors with equal capacitances are combined in parallel. the combination is connected to a 5.55-v battery, which charges the capacitors. the charging process involves 3.45 Ã 10-4 c of charge moving through the battery. find the capacitance of each capacitor.
The equivalent capacitance of the number of capacitance connected in the parallel series is the sum of the individual capacitance.
The capacitance of each capacitor is [tex]2.1\times10^{-5}\rm F[/tex].
What is equivalent capacitance of parallel series?
The equivalent capacitance of the number of capacitance connected in the parallel series is the sum of the individual capacitance.
It can be given as,
[tex]C_{eq}=\dfrac{Q}{V}[/tex]
Here, [tex]Q[/tex] is the charge and [tex]V[/tex] is the voltage.
Given information-
The voltage of the battery is 5.55 V.
The value of charge is [tex]3.45\times10^{-4}[/tex] C.
Put the values in the above formula as,
[tex]C_{eq}=\dfrac{3.45\times10^{-4}}{5.55}\\C_{eq}=6.4\times10^{-4}\rm F[/tex]
Given that the three uncharged capacitors with equal capacitance are combined in parallel.
For the parallel connection of the capacitance the equivalent capacitance can be given as,
[tex]C_{eq}=C+C+C[/tex]
Here, [tex]C[/tex] is the capacitance of each capacitors. Put the values,
[tex]6.4\times10^{-4}\rm =3C\\C=2.1\times10^{-5}\rm F[/tex]
Hence the capacitance of each capacitor is [tex]2.1\times10^{-5}\rm F[/tex].
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At what separation will two charges, each of magnitude 6.0fYC,exert a force of 1.4N on each other?
a.0.48m
b.2.0m
c.5.1*10^6m
d.0.23m
e.40m
This question involves the concept of Colomb's Law and electrostatic force.
The separation between charges will be "a. 0.48 m".
COLOMB'S LAWAccording to Colomb's Law, every charge exerts an electrostatic force on the other charge, which is directly proportional to the product of the magnitudes of both the charges and inversely proportional to the square of the distance between them.
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
where,
F = electrostatic force = 1.4 Nk = Colomb's constant = 9 x 10⁹ N.m²/C²q₁ = magnitude of first charge = 6 μC = 6 x 10⁻⁶ Cq₂ = magnitude of second charge = 6 μC = 6 x 10⁻⁶ Cr = distance between charges = ?Therefore,
[tex]1.4 N = \frac{(9\ x\ 10^9\ N.m^2/C^2)(6\ x\ 10^{-6}\ C)(6\ x\ 10^{-6}\ C)}{r^2}\\\\r=\sqrt{\frac{(9\ x\ 10^9\ N.m^2/C^2)(6\ x\ 10^{-6}\ C)(6\ x\ 10^{-6}\ C)}{1.4\ N}}[/tex]
r = 0.48 m
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This back-and-forth movement of electrons is called . In contrast, the movement of electrons in one direction in a battery circuit is called .
Final answer:
The back-and-forth movement of electrons is called alternating current (AC), and the unidirectional flow in a battery circuit is known as direct current (DC). DC moves from the negative to the positive terminal of a battery, driven by the terminal voltage. The concept of conventional current assumes the flow of positive charges from positive to negative terminal.
Explanation:
The back-and-forth movement of electrons is called alternating current (AC). In contrast, the movement of electrons in one direction in a battery circuit is called direct current (DC).
When electrons move from a low-potential terminal (negative end) through a conductor, such as a wire, and enter a high-potential terminal (positive end) of a battery, this consistent unidirectional flow forms a DC. This is differ from AC, where the movement of electric charge periodically reverses direction. Electricity produced by batteries is a form of DC, and this is why it has definite positive and negative terminals.
The terminal voltage or electromotive force (emf) of a battery drives the flow of electrons, producing electric current. In metal wires, conventional current is carried by the flow of electrons which are negatively charged. However, conventional current is treated as if positive charges move from the positive to the negative terminal, reflecting historical conventions established before the discovery of the electron.
5. Amy and Josh are coasting on their bicycles down a 10° slope at 15 m/s through still air. The mass of Amy and her bicycle is 60 kg. The mass of Josh and his bicycle is 90 kg. The cross-sectional area of Amy and her bicycle is 0.45, while the cross-sectional area of Josh and his bicycle is 0.60. The drag coefficient for both cyclists is 0.70. Other than gravity and air resistance, the external forces acting on the two bicycle and rider systems are the same. Which cyclist is more affected by air resistance? The Answer is Amy but what is the math invovled, Please Show Work and Help!
Amy experiences less air resistance due to her smaller cross-sectional area compared to Josh, but as she has a lower mass, the air resistance has a more significant effect on her, making her more affected by air resistance.
Explanation:To determine which cyclist, Amy or Josh, is more affected by air resistance, we can examine the force due to air resistance, which can be calculated using the formula:
Fd = (1/2)ρCdAv2
where Fd is the force of drag (air resistance), ρ is the air density (which we'll assume to be constant for both cyclists), Cd is the drag coefficient, A is the cross-sectional area, and v is the velocity.
Given that both cyclists have the same drag coefficient (Cd = 0.70) and are traveling at the same velocity (v = 15 m/s), the only variables that differ between the two are their cross-sectional areas. Since Amy has a smaller mass and a smaller cross-sectional area (A = 0.45 m2), the force of air resistance will be smaller in magnitude compared to Josh's due to his larger cross-sectional area (A = 0.60 m2).
However, air resistance's impact on an object is also related to the object's mass. A smaller force applied to a smaller mass can have a more significant effect than the same force applied to a larger mass. Therefore, even if the force of air resistance is absolutely higher for Josh, Amy, with her lower mass, would be more affected by it, as it would constitute a more substantial proportion of her total mass.
14 gauge copper wire has a diameter of 1.6 mm. what length of this wire has a resistance of 4.8ω?
Describe the energy transformations that occur from the time a skydiver jumps out of a plane until landing on the ground.
Answer:
Before jumping from the plane, the skydiver has potential energy. When the skydiver jumps, the potential energy is transformed into kinetic energy, which increases until the skydiver reaches terminal velocity. Potential energy is then transformed into thermal energy.
Explanation:
Thats the answer
Tom and his little sister are enjoying an afternoon at the ice rink. they playfully place their hands together and push against each other. tom's mass is 61 kg and his little sister's mass is 15 kg. if the sister's acceleration is 2.1 m/s2 in magnitude, what is the magnitude of tom's acceleration?
Under the principle of conservation of momentum, Tom and his sister exert equal and opposite forces on each other when they push, leading to equal and opposite accelerations. Tom's acceleration is given by the force his sister exerts (her mass times her acceleration) divided by his mass. Thus, his acceleration is calculated to be 0.516 m/s².
Explanation:This problem involves the principle of conservation of momentum in physics. When Tom and his sister push against each other, they exert equal and opposite forces, leading to equal and opposite accelerations because acceleration = force/mass. The sister's acceleration (2.1 m/s²), as given in the problem, is directed away from Tom. To find Tom's acceleration, we need to use the equation: force = mass * acceleration (from Newton's 2nd law), solve this equation for Tom assuming that the force exerted by Tom and his sister on each other is the same.
Assuming that his sister's mass (15 kg) times her acceleration (2.1 m/s²) gives the force they exert on each other, we get 15 kg * 2.1 m/s² = 31.5 N. Then we divide this force by Tom's mass (61 kg) to get his acceleration: 31.5 N / 61 kg = 0.516 m/s². Therefore, Tom's acceleration is 0.516 m/s² away from his sister.
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The compound PCl5 decomposes into Cl2 and PCl3. The equilibrium of PCl5(g) Cl2(g) + PCl3(g) has a Keq of 2.24 x 10-2 at 327°C. What is the equilibrium concentration of Cl2 in a 1.00 liter vessel containing 0.235 mole of PCl5 and 0.174 mole of PCl3? Remember to use the correct number of significant digits. Cl2 = Are the products or reactants favored?
To find the equilibrium concentration of Cl2 in the decomposition of PCl5, we start with initial concentrations, assume x is the change at equilibrium, and apply the equilibrium expression using Keq = 2.24 x 10^-2. Solving this for x yields the equilibrium concentration of Cl2, showing whether reactants or products are favored.
To determine the equilibrium concentration of Cl2 when PCl5 decomposes into Cl2 and PCl3, we can start with the provided concentrations and use the equilibrium constant (Keq).
The equilibrium equation for this decomposition is:
PCl5(g) \<=> Cl2(g) + PCl3(g)
and the given Keq is 2.24 x 10-2 at 327°C.
Let's assume x is the amount of PCl5 that decomposes to form x moles of Cl2 and x moles of PCl3 at equilibrium:
Initial moles of PCl5 = 0.235 molInitial moles of PCl3 = 0.174 molChange for PCl5 = -xChange for Cl2 = +xChange for PCl3 = +xAt equilibrium, we will have:
[PCl5] = (0.235 - x) mol / 1.00 L[Cl2] = x mol / 1.00 L[PCl3] = (0.174 + x) mol / 1.00 LThe Keq expression is:
Keq = [PCl3][Cl2] / [PCl5]
Plugging in the equilibrium concentrations:
2.24 x 10-2 = ((0.174 + x) × x) / (0.235 - x)
This equation can be solved for x to find the equilibrium concentration of Cl2. With the calculated value of x, it is possible to determine the favorability of the reaction. A small Keq value (< 1) typically indicates that reactants are favored, which suggests in this case, PCl5 would be favored at equilibrium.
13) A branch falling from a tree is to gravity as a car driving on the road is to A) a driver's foot off of the accelerator, coasting. B) a driver's foot off the accelerator and on the break pedal. C) a driver's foot on the accelerator pressed down to maintain speed. D) a driver's foot on the accelerator and pressed down gradually more and more.
Its D: A driver's foot on the accelerator and pressed down gradually more and more.
A proton is fired from far away toward the nucleus of a mercury atom. mercury is element number 80, and the diameter of the nucleus is 14.0 fm. part a if the proton is fired at a speed of 3.4×107 m/s , what is its closest approach to the surface of the nucleus? assume the nucleus remains at rest. express your answer to two significant figures and include the appropriate units.
Answer:
[tex]27fm[/tex]
Explanation:
Kinetic Energy of proton
[tex]Kinetic Energy (K)=\frac{1}{2}mV^{2}[/tex]
[tex]m=Mass of proton[/tex]
[tex]V=Velocity of proton[/tex]
[tex]m=1.67\times 10^{-27} kg[/tex]
[tex]V=3.4\times 10^{7}ms^{-1}[/tex]
[tex]K=\frac{1}{2}\times 1.67\times 10^{-27}kg\times \left (3.4\times 10^{7}ms^{-1} \right )^2[/tex]
[tex]K=\frac{19.305}{2}\times 10^{-13}J[/tex]
[tex]K=9.65\times 10^{-13}J[/tex]
For conservation of energy;
[tex]Kinetic Energy=Potential energy[/tex]
[tex]K= U[/tex]
So,
[tex]U= 9.65\times 10^{-13}J[/tex]
Here,
[tex]U=Potential Energy[/tex]
[tex]U=k_{e}\frac{q_{1}q_{2}}{r}[/tex]
Here,
[tex]k_{e}=Coulomb's law constant[/tex]
[tex]k_{e}=8.99\times 10^{9}Nm^{2}C^{-2}[/tex]
[tex]q_{1}=80e[/tex]
[tex]q_{2}=e[/tex]
[tex]e=1.602\times 10^{-19}C[/tex]
[tex]r=The distance that proton will stop from the center of the nucleus[/tex]
[tex]U=k_{e}\frac{80e\times e}{r}[/tex]
[tex]9.65\times 10^{-13}J=8.99\times 10^{9}Nm^{2}C^{-2}\frac{80\times1.6\times 10^{-19}\times1.6\times 10^{-19} }{r}[/tex]
[tex]r=8.99\times 10^{9}Nm^{2}C^{-2}\frac{80\times1.6\times 10^{-19}\times1.6\times 10^{-19} }{9.65\times 10^{-13}J}[/tex]
[tex]34fm[/tex]
[tex]r_{0}=Radius of the atom[/tex]
[tex]Radius\left ( r_{0} \right )=\frac{diameter\left ( d \right )}{2}[/tex]
[tex]Diameter of the nucleus of mercury atom=14fm[/tex]
[tex]Radius of atom =\frac{14fm}{2}[/tex]
[tex]r=7fm[/tex]
[tex]d=r-r_{0}[/tex]
[tex]d=34fm-7fm[/tex]
[tex]d=27fm[/tex]
Further Explanation:
When a proton approaches a nucleus, it decelerates. Because the repulsive electric field and its kinetic energy converts into electric potential energy.
Then due to this, the proton will stop at a distance “r” from the center of the nucleus.
To find the distance from the surface where the proton hits, we have to subtract the radius of the nucleus.
Learn more:
1. Kinetic energy https://brainly.com/question/1621817 (answer by skyp)
2. Potential energy https://brainly.com/question/12489105 (answer by nitrotype2000)
3. Conservation of energy https://brainly.com/question/11911812 (answer by hrishisup)
Keywords:
Kinetic energy, potential energy, conservation of energy.