A falling skydiver opens his parachute. A short time later, the weight of the skydiver-parachute system and the drag force exerted on the system are equal in magnitude. The following statements predicts the motion of the skydiver at this time
The skydiver is moving downward with constant speed.
Explanation:
Immediately on leaving the aircraft, the skydiver accelerates downwards due to the force of gravity. There is no air resistance acting in the upwards direction, and there is a resultant force acting downwards. The skydiver accelerates towards the ground.
The forces acting on a falling leaf are : gravity and air resistance.
The net force and the acceleration on the falling skydiver is upward.
An upward net force on a downward falling object would cause that object to slow down. The skydiver thus slows down.
As the speed decreases, the amount of air resistance also decreases until once more the skydiver reaches a terminal velocity.
A skydiver falling at a constant speed opens his parachute. When the skydiver is falling, the forces are unbalanced.
The drag force opposes the relative motion of an object in a fluid
The option that gives the statement that predicts the motion of the skydiver when the magnitude of the weight of the skydiver-parachute system and the drag force are equal is option b.
b. The skydiver is moving downward with constant speed
The reason the above option is correct is as follows:
The skydiver is falling through the air which is a fluid and is therefore subject to drag force, [tex]F_D[/tex], which is given as follows;
[tex]F_D = \dfrac{1}{2} \times \rho \times v^2 \times C_D \times A[/tex]
Where;
[tex]F_D[/tex] = The drag force
ρ = The fluid density
v = The relative object speed compared to the fluid
A = Cross sectional area
[tex]C_D[/tex] = The drag coefficient
Therefore, given that the surface area of the falling skydiver is largely increased when the parachute is opened and the drag force is a function of the square of the velocity, we have that the drag force rapidly equals the weight of the skydiver, such that the net force becomes zero, and therefore, the speed of the skydiver becomes constant
Therefore, the correct option is that the skydiver is moving downward with constant speed
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What imaginary line marks the southern end of the tropical zone
Answer:
The tropic of Capricorn
Explanation:
This line runs 23.5 degrees south of the equator.
A mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 30. cm3. If the combustion of this mixture releases 984 J of energy, to what volume (in L) will the gases expand against a constant pressure of 648 torr if all the energy of combustion is converted into work to push back the piston?
Answer:
Explanation:
Given
Original volume V1=30cm^3 converting to L
=30/1000=0.03L
Constant pressure P= 648 tors
Converting to atm; 648 tors*1atm/760 torr=0.853 atm
Work=984J= 984**1L/101.33=9.7L.atm
Note before
W= -P(Vfinal-Vinitial)
-9.7/0.853+0.03L=11.68L
Answer:
Final expanded volume 11.43 L
Explanation:
The picture attached shows the solution
An object is situated to the left of a lens. A ray of light from the object is close to and parallel to the principal axis of the lens. The ray passes through the lens. Which one of the following statements is true?
The ray passes through a focal point of the lens only if the lens is a converging lens.
The ray passes through the lens without changing direction, no matter whether the lens is converging or diverging.
The ray crosses the principal axis at a distance from the lens equal to twice the focal length, no matter whether the lens is converging or diverging.
The ray passes through a focal point of the lens only if the lens is a diverging lens.
The ray passes through a focal point of the lens, no matter whether the lens is converging or diverging.
Answer:
The ray passes through a focal point of the lens only if the lens is a converging lens.
Explanation:
By the principles of geometric optics, we know that all rays parallel to the principal axis of converging lens, change its direction to a point situated in the axis of the lens. This last point is know as the focal point.
Hence, the only truth choice is:
The ray passes through a focal point of the lens only if the lens is a converging lens.
I attached an image to illustrate this situation
HOPE THIS HELPS!!
All particles made of quarks are called _____.
electrons
gluons
hadrons
nucleons
Answer:
All particles made of quarks are called hadrons.
All particles madeup of two or more quarks held together by a force are called ; ( C ) Hadrons
What are Hadrons ?Hadrons are subatomic particles which are made of two or more quarks which are held firmly by a force similar to electric force. An example of Hadron is Baryon which contains three quarks which are held closely together.
Hence we can conclude that All particles made of quarks are called Hadrons
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a company makes garden statues by pouring concrete into a mold. the amount of concrete used to make a statue of a deer weighs 3600 N. if the base of the deer statue is 0.60 meters long and 0.40 meters wide, how much pressure will the statue exert on the ground
Answer:
Pressure exerted by statue = [tex]15 kN/m^{2}[/tex]
Explanation:
Weight of the statue (F)= 3600 N
Area of the base of statue(A) = Length of the base x Width of the base
=0.6 m x 0.4 m =0.24 m
Pressure is defined as force per unit area.
[tex]Hence,\ pressure\ by\ statue= \frac{Force(F)}{Area(A)}=\frac{3600}{0.24} = 15000\ N/m^{2}[/tex]
Pressure exerted by statue = 15000 [tex]N/m^{2} = 15 kN/m^{2}[/tex]
The pressure exerted by the deer statue on the ground is approximately 15000 Pa.
Explanation:Pressure is a measure of the force exerted per unit area. In physics, it is defined as the force acting perpendicular to the surface of an object divided by the area over which the force is applied.
To calculate pressure (P), we use the formula [tex]\(P = \frac{force}{area}\).[/tex] The force exerted by the statue is its weight, which is the gravitational force acting on it, given by [tex]\(F = mg\)[/tex], where (m) is the mass and (g) is the acceleration due to gravity (approximately 9.8 m/s²).
Given the weight of the statue [tex]\(3600 \, N\),[/tex] we find the mass using [tex]\(F = mg\)[/tex], rearranging to [tex]\(m = \frac{F}{g}\)[/tex], which gives [tex]\(m \approx \frac{3600 \, N}{9.8 \, m/s^2} \approx 367.35 \, kg\)[/tex].
Now, we find the area (\(A\)) of the base of the statue:[tex]\(A = \text{length} \times \text{width} = 0.60 \, m \times 0.40 \, m = 0.24 \, m^2\).[/tex]
Finally, we use the pressure formula [tex](P = \frac{F}{A}\): \(P \approx \frac{3600 \, N}{0.24 \, m^2} \approx 15000 \, Pa\).[/tex]
Now, remove the positive charge by dragging it back to the basket, and drag one negative charge toward the middle of the screen. Determine how the voltage is different from that of the positive charge. How does the voltage differ from that of the positive charge? The voltage distribution does not change. The voltages become negative instead of positive and keep the same magnitudes. The voltages are positive, but the magnitude increases with increasing distance.
Answer:
The correct option is;
The voltages become negative instead of positive and keep the same magnitudes
Explanation:
Here we have that there is a change in direction from positive to negative with the direction pointing to opposite of the initial direction whereby the field strength does not change due to the reversal of the. Therefore the voltage becomes negative instead of negative while keeping the the magnitude.
That is there is a electric field reversal or a change electric field direction.
A thin uniform rod of mass M and length L is bent at its center so that the two segments are perpendicular to each other. Find its moment of inertia about an axis perpendicular to its plane and passing through the point where the two segments meet.
Answer:
[tex]\frac{1}{12}ML^2[/tex]
Explanation:
The moments of the whole object is the sum of the moments of the 2 segments of rod at their ends of which length is L/2 and mass M/2:
[tex]I = 2I_{end} = 2\frac{1}{3}\frac{M}{2}\left(\frac{L}{2}\right)^2[/tex]
[tex]I = \frac{1}{3}M\frac{L^2}{4}[/tex]
[tex]I = \frac{1}{12}ML^2[/tex]
Think about multiplying the mass of each student by a factor to calculate each student's kinetic energy. Is there a
common factor that works for every student? If so, what's this factor?
Answer:
Multiplying the mass of any student by a factor of 4.5 gives the kinetic energy of the student.
Explanation:
because
Answer: the question was asked to think about how to multiply a mass speech student by a factor to include the student. Kinetic energy, are there any common factors that appeal to them? The table shows mass energy and constant velocity. Let's calculate a constant factor, multiply it by mass, get the energy and see if we can do it. It's very easy. You can do it just in case. Only kinetic energy divided by mass can be produced. That is, the first is 100 and 21.5 divided by 27. Now you have the next 4.5. This is one. Then it is 162 divided by 36. This is 4.5. January 3, 202
Divide 5 by 45 to get 4.5. And hopefully you can see the patterns that are appearing here. In the fourth one, 243 divided by 54 gives 4.5. The fifth 288 divided by 64. Since it is 4.5, you can guess what it will be like. And finally, in the sixth case, it's 3 to 8.5 divided by 73. This is also equivalent to 4. Well, this common factor 4.5 was found.
What is kinetic energy?Kinetic energy is a form of energy that an object or particle has due to its movement. When work is done on an object by applying a net force that transfers energy, the object accelerates, thereby gaining kinetic energy. In physics, the kinetic energy of an object is the energy that the object has due to its motion.
This is defined as the work required to accelerate an object of a given mass from a stationary state to a specified velocity. After the body gains this energy during acceleration, the body retains this kinetic energy unless the velocity changes.
All moving objects use kinetic energy. Examples of kinetic energy are walkers, thrown baseball, bread crumbs falling from a table, and charged particles in an electric field.
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A simple pendulum is used to determine the acceleration due to gravity at the surface of a planet. The pendulum has a length of 2 m and its period is measured to be 2 s. The value of g obtained in this investigation is most nearly __________.A. 1 m/s²B. 2 m/s²C. 5 m/s²D. 10 m/s²E. 20 m/s²
Answer:
Acceleration due to gravity is 20 [tex]m/sec^2[/tex]
So option (E) will be correct answer
Explanation:
We have given length of the pendulum l = 2 m
Time period of the pendulum T = 2 sec
We have to find acceleration due to gravity g
We know that time period of pendulum is given by
[tex]T=2\pi \sqrt{\frac{l}{g}}[/tex]
[tex]2=2\times 3.14 \sqrt{\frac{2}{g}}[/tex]
[tex]0.3184= \sqrt{\frac{2}{g}}[/tex]
Squaring both side
[tex]0.1014= {\frac{2}{g}}[/tex]
[tex]g=19.71=20m/sec^2[/tex]
So acceleration due to gravity is 20 [tex]m/sec^2[/tex]
So option (E) will be correct answer.
Final answer:
Using the formula for the period of a simple pendulum and given values for length and period, the acceleration due to gravity on the planet is calculated to be approximately 9.87 m/s², which is closest to 10 m/s².
Explanation:
To determine the value of acceleration due to gravity (g) at the surface of a planet using a simple pendulum, we use the formula for the period (T) of a simple pendulum: T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
Rearranging the formula to solve for g gives us: g = (4π²L) / T². Given that the length (L) is 2 m and the period (T) is 2 s, we plug these values into the formula: g = (4π² × 2 m) / (2 s)².
Calculating this gives us: g = (4π² × 2 m) / 4, simplifying further gives g = π² × 2 m. Now substituting π = 3.14159, we find g = (3.14159)² × 2 m ≈ 9.87 m/s², which is closest to choice D: 10 m/s².
Physics - Wave Diagrams Assignment
Wave
Wave
B
CAN SOMEONE HELP ME LOL
Answer:At the top of the page is a transvers wave
C= crest
B= wavelingth
D= trough
A= amplatud
The next wave is a longitudinal wave
A grinding stone with a mass of 50 kg and a radius of .75 m is rotating with an angular velocity of 30 rev/s. A second, smaller stone with a mass of 20 kg and a radius of .5 m is dropped onto the first without slipping. What is the new angular velocity of the two stones?
Answer:
The new angular velocity of the two stones = 160.064 rad/s
Explanation:
This is a case of conservation of angular momentum.
For initial case:
Mass = 50 kg
Radius = 0.75 m
Angular velocity N = 30 rev/s
We must convert to rad/s w
w = 2¶N = 2 x 3.142 x 30 = 188.52 rad/s
Moment of inertia I = m x r^2
I = 50 x 0.75^2 = 28.125 kgm2
Angular momentum = I x w
= 28.125 x 188.52 = 5302.125 kgm2-rad/s
For second case smaller stone has
m = 20 kg
Radius = 0.5 m
I = m x r^2 = 20 x 0.5^2 = 5 kgm2
Therefore,
Total moment of inertia of new system is
I = 28.125 + 5 = 33.125 kgm2
Final angular momentum = I x Wf
Where Wf = final angular speed of the system.
= 33.125 x Wf = 33.125Wf
Equating the two angular moment, we have,
5302.125 = 33.125Wf
Wf = 5302.125/33.125 = 160.064 rad/s
Answer:
[tex]\dot n = 25.471\,\frac{rev}{s}[/tex]
Explanation:
The situation is described reasonably by the Principle of Angular Conservation:
[tex]\frac{1}{2}\cdot (50\,kg)\cdot (0.75\,m)^{2}\cdot \left(30\,\frac{rev}{s} \right) = \frac{1}{2}\cdot \left[(50\,kg)\cdot (0.75\,m)^{2}+ (20\,kg)\cdot (0.5\,m)^{2} \right] \cdot \dot n[/tex]
The final angular velocity is:
[tex]\dot n = 25.471\,\frac{rev}{s}[/tex]
A satellite views the earth at an angle of 20°. What is the arc measure
Answer:
The arc measure is 20°.
Answer:160
Explanation:edg
At the surface of the moon, the acceleration due to the gravity of the moon is x. At a distance from the center of the moon equal to four times the radius of the moon, the acceleration due to the gravity of the moon is _____.
Answer:
Gravity at a distance of 4R will be reduced to 1/16 th.
Explanation:
Given:
At the surface of the moon, the acceleration due to the gravity of the moon is x.
We have to find the gravity a t a distance of 4 times from the center of the moon.
Let the radius of the moon be "R".
And
The value of acceleration due to gravity is [tex]g_m[/tex] .
Formula:
⇒ [tex]g_m=\frac{GM}{R^2}[/tex] ...where M is the mass of the moon.
Now
Gravity of the moon at the its surface:
⇒ [tex]g_m=\frac{GM}{R^2}[/tex] ...equation (i)
Gravity of the moon at a distance of [tex]4R[/tex]:
⇒ [tex]g_m_1=\frac{GM}{(4R)^2}[/tex]
⇒ [tex]g_m_1=\frac{GM}{16R^2}[/tex] ...equation (ii)
Dividing equation (i) with (ii) to find the relationship between the two.
⇒ [tex]\frac{g_m_1}{g_m} =\frac{GM}{16R^2}\times \frac{R^2}{GM}[/tex]
⇒ [tex]\frac{g_m_1}{g_m} =\frac{1}{16}[/tex]
⇒ [tex]g_m_1 =g_m(\frac{1}{16})[/tex]
⇒ [tex]g_m_1 =x(\frac{1}{16})[/tex] ...as gm=x at the surface.
So,
We can say that the gravity at a distance of 4R will be reduced to 1/16 th.
Answer: The acceleration due to gravity on the surface of the moon is 1.620 m/s2. 2) The radius of the Earth is 6.38 x 106 m.
A particle has a charge of 5.2x10^-19 coulombs and experience a force of 9.5x10^-15 Newton's when it travels through a magnetic field with strength 2.2 x 10^-1 telsa what is the speed of the particle
Answer:
83000 m/s
Explanation:
Using
F = Bqv....................... Equation 1
Where F = Force experienced by the charge, B = magnetic field q = charge of the particle, v = speed of the particle.
make v the subject of the equation
v = F/Bq.................... Equation 2
Given: q = 5.2×10⁻¹⁹ Coulombs, F = 9.5×10⁻¹⁵ Newtons, B = 2.2×10⁻¹ Tesla
Substitute into equation 2
v = 9.5×10⁻¹⁵ /(5.2×10⁻¹⁹×2.2×10⁻¹)
v = 8.3×10⁴ m/s
v = 83000 m/s
A diagnostic sonogram produces a picture of internal organs by passing ultrasound through the tissue. In one application, it is used to fid the size, location, and shape of the prostate in preparation for surgery or other treatment. The speed of sound in the prostate is 1540 m/s, and a diagnostic sonogram uses ultrasound of frequency 1.40 MHz. The density of the prostate is 1060 kg/m3.1) What is the wavelength of the sonogram ultrasound? 2)What is Youngâs modulus for the prostate gland?
Answer:
a) 1.1mm
b) 2.513kg/ms^2
Explanation:
You can use the formula for the calculation of the wavelength of a wave
f=1.40MHz=1.40*10^{6}Hz
1 )
[tex]\lambda=\frac{v}{f}=\frac{1540m/s}{1.40*10^{6}Hz}=1.1*10^{-3}m=1.1mm[/tex]
2)
The Young modulus can be computed by using the expression:
[tex]v=\sqrt{\frac{Y}{\rho}}\\\\Y=v^2\rho[/tex]
where Y is the Young modulus and p is the density of the material. Here, you have considered that the prostate gland can be taken as a vibrating membrane or string.
By replacing you obtain:
[tex]Y=(1540m/s)^2(1060kg/m^3)=2.513*10^9kg/ms^2[/tex]
hence, the Young modulus of the prostate glande is 2.513kg/ms^2
Answer:
1) 1.1 x [tex]10^{-3}[/tex] m
2)2.51 x[tex]10^{9}[/tex]Pa
Explanation:
Given:
Speed of sound in prostate 'V'= 1540m/s
frequency 'f' = 1.40 MHz = 1.40 x [tex]10^{6}[/tex]Hz
density of prostate'ρ' = 1060 kg/m3
1) As we know that the relationship of the speed of sound, its frequency, and wavelength is the same as for all waves
V= fλ
λ= V/f => 1540/1.40 x [tex]10^{6}[/tex]
λ= 1.1 x [tex]10^{-3}[/tex] m
Thus, the wavelength of the sonogram ultrasound is 1.1 x [tex]10^{-3}[/tex] m
2)The speed of sound in a solid the depends on the Young's modulus of the medium and the density
V=√Y/ρ.
V² = Y/ρ
Y= V² x ρ=> 1540² x 1060
Y= 2.51 x[tex]10^{9}[/tex]Pa
Thus, Young's modulus for the prostate gland is 2.51 x[tex]10^{9}[/tex]Pa
A charged particle is surrounded by an electric field and a magnetic field
Answer:
yeah
Explanation:
electric fields help the charged particles interact
and isn't magnetic field the same as electric field.
Which of the following statements is FALSE?
a. After the Galveston Hurricane of 1900 the city built a 17-foot sea wall to protect Galveston from
future hurricanes.
b. One of the most devastating natural disasters to strike Texas was the Galveston Hurricane of
1900.
C. After the humcane of 1900, the city of Galveston removed 8 feet of soil to lower its elevation and
protect it from future hurricanes.
d. The rebuilding of Galveston after the hurricane of 1900 prompted the state to reorganize city
governments.
Answer:
C after the hurricane of 1900s
Explanation:
They didn’t remove 8 feet of soil they put 8 feet of soil
a force of 20N pushes an object of mass 5.0kg along a rough surface of 5.0N
Answer:
I'm sorry, I don't think there is any answer to give seeing as no question has been asked
Answer:
No question
Explanation: Sorry
How does the eye and brain work together to give you perception of color
Answer:
The human eye and brain together translate light into color. Light receptors within the eye transmit messages to the brain, which produces the familiar sensations of color. ... Rather, the surface of an object reflects some colors and absorbs all the others. We perceive only the reflected colors.
Explanation:
Final answer:
The eye and brain work together to perceive color. Light enters the eye and is detected by cones in the retina, which send signals to the brain. The brain processes these signals and combines information from different cones to create the perception of color.
Explanation:
The eye and brain work together to give you perception of color through a complex process. When light enters the eye, it is detected by special cells called cones in the retina. These cones are sensitive to different wavelengths of light and send signals to the brain. The brain then processes these signals and combines the information from different cones to create the perception of color.
For example, if you see a red object, the red cones in your eye will be activated and send signals to the brain. The brain then interprets these signals as the color red. Similarly, the green cones are activated by green light and the blue cones by blue light. By combining the information from all three types of cones, the brain is able to perceive a wide range of colors.
An early planetary model of the hydrogen atom consisted of a 1.67 X 10-27 kg proton in the nucleus and a 9.11 X 10-31 kg electron in orbit around it at a distance of 5.0 X 10-11 m. In this model, what is the gravitational force between a proton and an electron?
Answer:
The gravitational force between proton and an electron is [tex]4.06 \times 10^{-47}[/tex] N
Explanation:
Given:
Mass of proton [tex]m_{1} = 1.67 \times 10^{-27}[/tex] kg
Mass of electron [tex]m_{2} = 9.11 \times 10^{-31}[/tex] kg
Separation between electron and proton [tex]r = 5 \times 10^{-11}[/tex] m
According to the gravitational law,
[tex]F = \frac{Gm_{1} m_{2} }{r^{2} }[/tex]
Where [tex]G = 6.674 \times 10^{-11}[/tex] = gravitational constant.
[tex]F = \frac{6.674 \times 10^{-11} \times 1.67 \times 10^{-27} \times 9.11 \times 10^{-31} }{(5 \times 10^{-11} )^{2} }[/tex]
[tex]F = 4.06 \times 10^{-47}[/tex] N
Therefore, the gravitational force between proton and an electron is [tex]4.06 \times 10^{-47}[/tex] N
The gravitational force between a proton and an electron is 40 * 10⁻⁴⁸ N
Newton's law of gravitation is given by:
F = Gm₁m₂/r²
Where F is the force, m₁, m₂ are masses, r is the distance between the two masses and G is the gravitational constant = 6.67 * 10⁻¹¹ Nm²/kg²
Given that:
m₁ = 1.67 * 10⁻²⁷ kg, m₂ = 9.11 * 10⁻³¹ kg, r = 5 * 10⁻¹¹ m, hence:
F = 6.67 * 10⁻¹¹ Nm²/kg² * 1.67 * 10⁻²⁷ kg * 9.11 * 10⁻³¹ kg/ (5 * 10⁻¹¹ m)²
F = 40 * 10⁻⁴⁸ N
The gravitational force between a proton and an electron is 40 * 10⁻⁴⁸ N
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If the speed of a wave is 150 m/s and it’s frequency is 2 Hz , what is its wavelength ?
Answer:
75 m
Explanation:
wavelength = frequency/ speed = 75 m
To understand the forces between a bar magnet and 1. a stationary charge, 2. a moving charge, and 3. a ferromagnetic object. A bar magnet oriented along the y axis can rotate about an axis parallel to the z axis. Its north pole initially points along j^.
A stationary charge does not experience a force in a magnetic field. A moving charge experiences a force perpendicular to both its velocity and the magnetic field. A ferromagnetic object is attracted to a magnet regardless of its movement.
Explanation:The magnetic force between a bar magnet and different charged materials can be understood in respect to the properties of the magnetic field, and these forces can range from attractive to repulsive depending on the orientation of the objects in the field and the type of materials involved. For a stationary charge, magnetic forces do not act on it because the magnetic force on a charged particle is always perpendicular to the direction of its motion. Hence, a stationary charged particle does not experience a force.
In the case of a moving charge, a magnetic field exerts force on it. This force is perpendicular to both the velocity of the charge and to the magnetic field, and is dependent on the magnitude of the charge, its speed, and the magnetic field. For example, if you place a moving charge in a magnetic field, the charge will experience a force that's oriented at right angles to both its direction of movement and the field itself. Ferromagnetic objects like iron or nickel will experience attraction to the magnet irrespective of their movement. It is the property of the ferromagnetic material to align its domains in the direction of the external magnetic field (from the bar magnet), thus the entire object acts like a small magnet and feels an attraction.
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Several years from now you have graduated with an engineering/physics degree from OSU and have been hired by a nanoengineering firm as an intern. You have been assigned to work under a top engineer from the company. Their current project is to design a microscopic oscillator as a time keeping device. The engineering design involves placing a negative charge at the center of a very small positively charged metal ring. Your boss claims that the negative charge will undergo simple harmonic motion of displaced away from the center of the ring. Furthermore, they claim they can change the period (timing) of oscillation by adjusting the amount of charge on the ring. The first task they give you is to check the validity of their design.Consider a charge −???? located a small distance z above the center of a positively charged ring with total charge +Q and radius R. Write an expression for the net force exerted on the charge −???? due to the ring of charge. What is the magnitude of the force on the charge −???? if it is at the location z = 0?
Complete Question in order
See the first image attached
Answer and Explanation:
The three images attached discussed the solution to this question
second Image
Third Image
and Fourth Image
If the images are not clear enough right-click on it and open in a new tab
A setting Sun appears red due to the
a. scattering of lower frequencies by larger particles in the air.
b. light's longer path through the air at sunset.
c. absorption by smaller particles in the air.
d. lower frequencies of light emitted during sunset.
Answer:
a. scattering of lower frequencies by larger particles in the air.
b. light's longer path through the air at sunset.
Explanation:
Sun light has to travel several distances through the earth's atmosphere during Sun set and Sun rise. This light gets scattered by air molecules present and the shorter wave length blue gets upwards and red comes down. That is why the sun light appears red in our eyes.
Move the Earth so it is one box from the Sun. (Note: one box side equals about 46,000,000 miles.) Do not change the length of the velocity vector. Predict what will happen to the Earth and Sun when you hit Play?
Answer:
When we change the distance, the universal attraction force increases, so that the system is free to reach a new equilibrium, the linear speed of the earth must rise to the calculated value.
v = √ (G M / r)
Explanation:
For this exercise it is asked that if you maintain the linear speed of the Earth and bring it closer to the sun that would pass.
We pass the distance from Ro = 1.49 10¹¹ m to r = 0.736 10¹¹ m shortens, we write Newton's second law
F = m a
where the force is the universal force of attraction
F = G mM / r²
acceleration is central
a = v² / r
G m M / r² = m v² / r
v = √ (G M / r)
When we change the distance, the universal attraction force increases, so that the system is free to reach a new equilibrium, the linear speed of the earth must rise to the calculated value.
We can compare this value with that of the normal orbit
v₀ = √ (GM / R₀)
v / v₀ =√ (Ro / r)
v² r = v₀² R₀
either of these two expressions gives the relations gives the change in velocity with the radius of the orbit
A newly proposed device for generating electricity from the sun is a heat engine in which the hot reservoir is created by focusing sunlight on a small spot on one side of the engine. The cold reservoir is ambient air at 20°C. The designer claims that the efficiency will be 50%.
What minimum hot-reservoir temperature, in degrees C, would be required to produce this efficiency?
Answer:
The minimum temperature of hot reservoir is 586K or 313°C
Explanation:
The Carnot cycle is defined as ideal reversible process thermodynamic process which has four successive step. During the expansion and compression of the substance it can done upto desired point and then reversed up.
Here the energy is used from the hot reservoir to do work and deposited into the cold reservoir. As is it reversible the efficiency of the carnot cycle is the theoretical maximum of the heat engine.
The efficiency of carnot cycle is
η = 1 - [tex]\frac{Tc}{Th}[/tex] eq 1
Where Tc is the temperature of cold reservoir = 20° = 20°+273K = 293K
Th is the temperature of hot reservoir.
η is the efficency 50% = 0.5
The minimum temperature of the reservoir is related to the maximum efficiency,
Substituting values in eqn 1
0.05 = 1-[tex]\frac{293}{Th}[/tex]
Th = [tex]\frac{293}{1 - 0.5}[/tex] =586 K
The minimum temperature of hot reservoir is 586K.
ie 586K-273 = 313°C
Final answer:
The minimum hot-reservoir temperature required for a heat engine to have 50% efficiency with a cold reservoir at 20°C is 313.15°C.
Explanation:
To determine the minimum hot-reservoir temperature for a heat engine with 50% efficiency where the cold reservoir is at 20°C, we can use the efficiency formula for a Carnot engine: efficiency (e) = 1 - (Tc/Th), where Tc is the cold reservoir temperature and Th is the hot reservoir temperature, both in kelvins. Rearranging the formula to solve for Th gives: Th = Tc / (1 - e).
First, convert the cold reservoir temperature from Celsius to Kelvin: Tc = 20°C + 273.15 = 293.15 K. Now, plug in the efficiency value: Th = 293.15 K / (1 - 0.50) = 293.15 K / 0.50 = 586.3 K. Convert this back to Celsius to get the minimum hot-reservoir temperature required: Th - 273.15 = 586.3 K - 273.15 = 313.15°C.
Therefore, the minimum hot-reservoir temperature required for the proposed heat engine to reach 50% efficiency is 313.15°C.
An insoluble solid material that is produced in double replacement reactions is called
Answer:
Precipitate
Explanation:
When a double displacement reaction occurs, the cations and anions switch partners, resulting in the formation of two new ionic compounds AD and CB, one of products is in the solid state and forms an insoluble ionic compound called a precipitate.
Two wave pulses with equal positive amplitudes pass each other on a string, one is traveling toward the right and the other toward the left. At the point that they occupy the same region of space at the same time
constructive interference occurs
destructive interference occurs.
a standing wave is produced.
a traveling wave is produced.
a wave pulse is produced.
Answer:
Constructive interference occurs
Explanation
This is because at the point they both occupy the same region of space at the same time, there is a superposition of the waves causing them to add up. Since their amplitudes are equal and positive, they are in phase. and thus there is increase the resultant amplitude..This increase in amplitude is due to constructive interference.
Two wave pulses with equal positive amplitudes moving in opposite directions on a string will result in constructive interference where their displacements add up leading to an increased amplitude at the point of overlap. This is a momentary or transient event.
Explanation:When two wave pulses with equal positive amplitudes meet each other on a string, moving in opposite directions, what we experience is constructive interference. This happens because the displacement of the two waves at every point adds up. Essentially, they combine to produce a wave of increased amplitude. In this case, the resultant wave would have an amplitude that's twice that of the individual wave pulses. Please note: this phenomenon happens only at the instant when both waves overlap and not any time before or after that. In other words, it's a transient or temporary phenomenon, not a permanent one, causing a momentary increase in the height of the wave at the point of intersection.
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Coulomb measured the deflection of sphere A when spheres A and B had equal charges and were a distance d apart. He then made the charge on B one-third the charge on A. How far apart would the two spheres then have had to be for A to have had the same deflection that it had before
Answer:
The new separation is [tex]\bf{(d/\sqrt{3})}[/tex].
Explanation:
The expression of the force between two spheres is given by
[tex]F = k\dfrac{q_{A}q_{B}}{d^{2}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)[/tex]
where, [tex]q_{A}[/tex] is the charge on sphere A, [tex]q_{B}[/tex] is the charge on sphere B, [tex]k[/tex] is constant and [tex]d[/tex] i the separation between two spheres.
The new value of charge on sphere B is [tex]q_{B}^{n} = \dfrac{q_{A}}{3}[/tex]. Consider the new separation between the spheres be [tex]d'[/tex]. Under the new configuration the force between the spheres is given by
[tex]F = k \dfrac{q_{A}(q_{A}/3)}{d'^{2}}~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)[/tex]
Equating equation (1) and equation (2), we have
[tex]~~~~&& \dfrac{1}{d'^{2}} = \dfrac{1}{3d^{2}}\\&or,& d' = \dfrac{d}{\sqrt{3}}[/tex]
So, the new separation is [tex](d/\sqrt{3})[/tex].
What made it possible to construct skyscrapers in the 1800s
Answer:
It was made possible by the new methods of making steel
Explanation:
The Bessemer process was the first inexpensive industrial process for the mass production of steel from molten pig iron prior to the development of the open hearth furnace. The key principle used was the removal of impurities from the iron by process of oxidation with air being blown through the molten iron. The oxidation also enhances the temperature of the iron mass and keeps it molten. So with the presence of this, building of skyscraper was made possible.
Skyscrapers in the 1800s were made possible by the invention of steel girders and elevators, along with the high prices of real estate in city centers.
Explanation:The construction of skyscrapers in the 1800s was made possible by several key advancements. One important development was the invention of steel girders that could support the weight of tall buildings. These girders allowed for the construction of buildings beyond the previous limit of 10 to 12 stories.
Another crucial factor was the invention of elevators, both passenger and freight elevators. The introduction of elevators made it feasible for people and goods to reach higher floors easily, making taller buildings more practical.
Additionally, the price of real estate in city centers played a significant role. As the cost of land increased, developers turned to building upwards to maximize space and value. These advancements in construction technology and the need for efficient use of space contributed to the rise of skyscrapers in the 1800s.