A fisherman fishing from a pier observes that the float on his line bobs up and down, taking 2.4 s to move from its highest to its lowest point. He also estimates that the distance between adjacent wave crests is 48 m. What is the speed of the waves going past the pier?

(A) 20 m/s

(B) 1.0 m/s

(C) 10 m/s

(D) 5.0 m/s

(E) 115 m/s

Answer:

The attractive force between them is [tex]1.296 \times 10^{18}[/tex] N

Explanation:

Given:

Charge [tex]q = 96000[/tex] C

Distance between two charges [tex]r = 8[/tex] m

According to the coulomb's law,

    [tex]F = \frac{kq^{2} }{r^{2} }[/tex]

Where [tex]k = 9 \times 10^{9}[/tex] = force constant.

   [tex]F = \frac{9 \times 10^{9} \times (96000)^{2} }{8^{2} }[/tex]

   [tex]F = 1.296 \times 10^{18}[/tex] N

Therefore, the attractive force between them is [tex]1.296 \times 10^{18}[/tex] N

Answer:

Explanation:

Given that on the tree the gravitational energy stored is 8J

Then, mgh = 8J.

The apple begins to fall and hit the ground, what is the maximum kinetic energy?

Using conservation of energy, as the above is about to hit the ground, the apple is at is maximum speed, and the height then is 0m, so the potential energy at the ground is zero, so all the potential of the apple at the too of the tree is converted to kinetic energy as it is about to hits the ground. Along the way to the ground, both the Kinetic energy and potential energy is conserved, it is notice that at the top of the tree, the apple has only potential energy since velocity is zero at top, and at the bottom of the tree the apple has only kinetic energy since potential energy is zero(height=0)

So,

K.E(max) = 8J

Answer:

73.8 N

Explanation:

The total volume is,

V = [tex]\frac{m_Al}{P_Al} = \frac{m_copper}{P_copper}[/tex]

=  [tex]\frac{10m}{(100)(2.6)} = \frac{90m}{(100)(8.9)}[/tex]

= 0.1396 m

The average  density is,

[tex]p = \frac{m}{V}[/tex]

= [tex]\frac{m}{0.1396}[/tex]

= 7.169 g/cm³

The linear mass density is,

μ = pπr²

= (7.169 x 10⁹) (π (0.3 x 10⁻³)²)

= 2.026 x 10⁻³ Kg/m

The fundamental mode of length is,

L =  λ/2

λ=2L

= 2 x 0.65

= 1.3 m

The speed of the wave is,

v = λf

= 1.3 m x 147 Hz

= 1.91 m/s

The tension is,

v =  √T/ц

T = ц v²

= 2.026 x 10⁻³)(1.91 m/s)²

= 73.769N

73.8N

Answer:

a

When peter held the book for one minute the rate at which motor unites are fired increase steeply but as the duration increases the increese in the rate at which it is being fired becomes linear so the number of activated motors stay the same but are being activated at a more rapidly

b

The same motors are activated whilest he is hold the book for 2 minutes this is because for peter to hold the book in one fixed position one specific motor units  need to be activated

Note changing the motor unites would change the positon of the hand

Explanation:

Answer:

3.42 cubic mm

Explanation:

Let density of fresh water be [tex]\rho_w = 1000 kg/m^3[/tex]

And atmospheric pressure at the water surface be [tex]P_a = 101325 Pa[/tex]

Let g = 9.8 m/s2. The pressure at the dept of h = 25 m is

[tex]P = P_a + \rho_wgh = 101325 + 1000*9.8*25 = 346325 Pa[/tex]

Using ideal gas law and assume constant temperature, we have the following equation to calculate the volume at the water surface [tex]V_a[/tex], knowing that the volume at the lower depth V = 1 mm3:

[tex]P_aV_a = PV[/tex]

[tex]V_a = PV/P_a = 346325*1/101325 = 3.42 mm^3[/tex]

The volume of a nitrogen bubble in a diver's blood will expand when the pressure decreases as they rise to the surface. If the bubble was 1.00 mm3 at 25.0 m depth, it would expand to 2.5 mm3 at the surface. Rapid ascent can cause the bubbles to expand too quickly, leading to the condition known as Decompression Sickness, or The Bends.

The volume expansion of nitrogen bubbles in a diver's blood due to rapid ascent from a certain depth is governed by Boyle's Law that states the volume of gas is inversely proportional to its pressure, assuming the temperature remains constant. When a diver rises quickly from a depth of 25.0 m (approximately 2.5 atm, as each 10m of water is approximately 1 atm) to the surface (1 atm), the pressure decreases. According to Boyle's Law, the volume would therefore increase, thus, if a nitrogen bubble occupied 1.00 mm3 at the depth, at the surface it would expand to 2.5 x 1.00 mm3, or 2.5 mm3. This is why divers must ascend slowly, to allow gases to dissipate gradually and avoid the dangerous condition known as Decompression Sickness or The Bends.

https://brainly.com/question/36494413

#SPJ12

Answer: The gauge pressure in the tire when its temperature rises to 33◦C will be 28.7 lb/in2

Explanation: Please see the attachments below

Answer:

See explanation

Explanation:

Solution:-

Buoyancy is the force that causes objects to float. It is the force exerted on an object that is partly or wholly immersed in a fluid. Buoyancy is caused by the differences in pressure acting on opposite sides of an object immersed in a static fluid. It is also known as the buoyant force. Buoyancy is the phenomena due to Buoyant Force.

It is as an upward force exerted by a fluid that opposes the weight of an object immersed in a fluid. As we know, the pressure in a fluid column increases with depth. Thus, the pressure at the bottom of an object submerged in the fluid is greater than that at the top. The difference in this pressure results in a net upward force on the object which we define as buoyancy.

- The formula for buoyant force (Fb) is given:

                           Fb = ρ*g*V

- The force acts on all objects. However, it depends on the fluid density and amount of volume displaced.

- The Buoyant force exerted by air with density = 1.225 kg/m^3 on an object with volume (V) is:

                          Fb = ρ*g*V = 1.225*9.81*V = 12.02*V

- For the similar object with mass (m), the downward weight would be:

                           W = m*g

- For the object to float the buoyant force (Fb) must be greater than weight of the object:

                          Fb > W

                          12.02*V > m*9.81

                          V / m > 0.816

- The ratio of V / m must be at-least = 0.816.

- Assuming the object is fully immersed in air, then the volume displaced V = ρ_material*V

                         ρ_material < 1 / 0.816

                        ρ_material < 1.225 or ( ρ_air )

- So the for an object to float in air its material density must always be less than that of air. That why in balloons lighter gas is used which have density less than that of air like Helium.          

Final answer:

The air exerts a buoyant force on all objects due to Archimedes' principle, which states that the force on an object in a fluid is equal to the weight of the fluid it displaces. An object's ability to float is determined by its density relative to the surrounding air. All objects are subject to this force, whether they rise, sink, or remain suspended.

Explanation:

The air does indeed exert a buoyant force on all objects, not just on light objects like balloons. This buoyant force is a result of Archimedes' principle, which states that the force on an object in a fluid is equal to the weight of the fluid it displaces. Therefore, if an object's average density is less than that of the surrounding fluid, it will float. On the other hand, if an object's density is greater, it will sink. The key factor is the object's density relative to the air around it, determining if it will rise, fall, or remain suspended.

This principle extends to all objects in fluids, including gases such as air. It means that even objects that do not float, such as rocks or metal items, experience a buoyant force; however, this force is not enough to overcome their weight and make them float. Similarly, our bodies are buoyed by the atmosphere to some degree; it's just that the effect is not as noticeable as it is with helium balloons, which have a density much lower than that of air.

Answer:

Power, P = 96 kW

Explanation:

Mass of Shamu, m = 8000 kg

Initial velocity, u = 0

Final velocity, v = 12 m/s

We need to find the average power of the whale. It is equal to the work done per unit time. Work done is equal to the change in kinetic energy. So,

[tex]P=\dfrac{\Delta K}{t}\\\\P=\dfrac{mv^2}{2t}\\\\P=\dfrac{8000\times 12^2}{2\times 6}\\\\P=96000\ W[/tex]

or

P = 96 kW

So, the average power of the killer whale is 96 kW.

Final answer:

To calculate the average power Shamu the killer whale needs to generate to reach a speed of 12 m/s in 6 seconds, we first find the acceleration and then use it to calculate the work done. Dividing the work by the time gives us the average power, which is 96 kilowatts (kW).

Explanation:

The question asks us to calculate the average power required for a killer whale named Shamu to accelerate up to a speed of 12 m/s in 6 seconds, ignoring the drag of water. To find the power, we first need to calculate the work done in accelerating Shamu, and then divide that work by the time taken to find the average power.

Calculating Work Done

Work done is given by the equation:

Work = Force × Distance

First, we need the acceleration, which can be found using the equation:

Acceleration (a) = (Final speed - Initial speed) / Time

Since Shamu is starting from rest, the initial speed is 0. Thus, the acceleration is:

a = (12 m/s - 0 m/s) / 6 s = 2 m/s²

Next, we use Newton's second law to find the force:

Force = Mass × Acceleration

Force = 8.00 × 10³ kg × 2 m/s² = 16,000 N

Now we find the distance covered using the equation:

Distance = (Initial speed + Final speed) / 2 × Time

Distance = (0 + 12 m/s) / 2 × 6 s = 36 m

Thus, work done = 16,000 N × 36 m = 576,000 J

Calculating Average Power

Average power is work done divided by time:

Power = Work / Time

Power = 576,000 J / 6 s = 96,000 W or 96 kW

The average power generated by Shamu to reach the required speed is 96 kilowatts (kW).

Answer:

[tex]1.51\cdot 10^6 m/s[/tex] north

Explanation:

When a charged particle moves in a magnetic field, the particle experiences a force given by the formula:

[tex]F=qvB sin \theta[/tex]

where

q is the magnitude of the charge

v is its velocity

B is the magnetic field

[tex]\theta[/tex] is the angle between the directions of v and B

In this problem,

[tex]q=1.6\cdot 10^{-19}C[/tex] (charge of the electron)

[tex]B=8.3\cdot 10^{-2} T[/tex] (strength of magnetic field)

[tex]F=2.0\cdot 10^{-14} N[/tex] (force)

[tex]\theta=90^{\circ}[/tex]

Therefore, the velocity is

[tex]v=\frac{F}{qB sin \theta}=\frac{2.0\cdot 10^{-14}}{(1.6\cdot 10^{-19})(8.3\cdot 10^{-2})(sin 90^{\circ})}=1.51\cdot 10^6 m/s[/tex]

The direction of the force is perpendicular to both the direction of the velocity and the magnetic field, and it can be found using the right-hand rule:

. Thumb: direction of the force (downward) --> however the charge is negative, so this direction must be reversed: upward

- Middle finger: direction of the field (west)

- Index finger: direction of velocity --> north

So, the electron is travelling north.

Answer:

Number of revolutions = Δθ = 60.63 revs

Explanation:

The angular acceleration of the washer is given by

α = (ωf - ωi)/Δt

Where ωf is the initial angular speed, ωi is the final angular speed and Δt is the interval of time during this acceleration.

α = (4.7 - 0)/8.3

α = 0.56 rev/s²

As we know from the equation of kinematics,

2αΔθ = ωf² - ωi²

Where Δθ is the change in angular displacement of the washer.

Δθ = (ωf² - ωi²)/2α

Δθ = (4.7² - 0²)/2*0.56

Δθ = 19.72 revs

Now the tub decelerates and comes to a stop in 17.5 s

α = (ωf - ωi)/Δt

α = (-4.7 - 0)/17.5

α = -0.27 rev/s²

the corresponding change in angular displacement of the washer is

Δθ = (ωf² - ωi²)/2α

Δθ = (0² - 4.7²)/2*-0.27

Δθ = 40.91 revs

Therefore, the total number of revolutions undergone by the tub during this entire time interval is

Δθ = 19.72 + 40.91

Δθ = 60.63 revs

Answer:

c

Explanation:

big brain

Answer: C

guide and inspire good conduct

Explanation:

APA are rules of proper source documentation to avert difficulty. This makes you feel that you are not alone. Having to follow detailed citation and formatting guidelines as well may seem like just one more task to add to an already-too-long list of requirements.

Final answer:

Correct answer is C. The five general principles of the APA are meant to guide and inspire good conduct among psychologists, offering a values framework rather than serving as enforceable rules.

Explanation:

The five general principles from the American Psychological Association (APA) are meant to guide and inspire good conduct. These principles serve as ethical guidelines for behaviors and decision-making in psychological practice.

In contrast to enforceable rules, which are mandatory and spell out specific prohibitions and mandates, principles and guidelines such as those provided by the APA are not meant to be enforceable or stand up in court but rather to provide a framework for ethical practice.

They offer a set of values that psychologists are encouraged to aspire to in their professional conduct. These principles cover important areas such as respect for people's rights, integrity, and social responsibility in practice.

Answer:

Picking up a cup, throw or stop a ball, eating food.

Explanation:

A mechanical force can be defined as a force that features some direct contact between two objects (one applying the force and another which is in a state of rest or in a state of motion) and results in the production of a change in the state of the object (state of rest or state of motion).

So anything that moves an object to a different state of rest.

Answer:

Fc = [ - 4.45 * 10^-8 j ] N  

Explanation:

Given:-

- The masses and the position coordinates from ( 0 , 0 ) are:

       Sphere A : ma = 80 kg , ( 0 , 0 )

       Sphere B : ma = 60 kg , ( 0.25 , 0 )

       Sphere C : ma = 0.2 kg , ra = 0.2 m , rb = 0.15

- The gravitational constant G = 6.674×10−11 m3⋅kg−1⋅s−2

Find:-

what is the gravitational force on C due to A and B?

Solution:-

- The gravitational force between spheres is given by:

                       F = G*m1*m2 / r^2

Where, r : The distance between two bodies (sphere).

- The vector (rac and rbc) denote the position of sphere C from spheres A and B:-

 Determine the angle (α) between vectors rac and rab using cosine rule:

                   [tex]cos ( \alpha ) = \frac{rab^2 + rac^2 - rbc^2}{2*rab*rac} \\\\cos ( \alpha ) = \frac{0.25^2 + 0.2^2 - 0.15^2}{2*0.25*0.2}\\\\cos ( \alpha ) = 0.8\\\\\alpha = 36.87^{\circ \:}[/tex]

 Determine the angle (β) between vectors rbc and rab using cosine rule:

                   [tex]cos ( \beta ) = \frac{rab^2 + rbc^2 - rac^2}{2*rab*rbc} \\\\cos ( \beta ) = \frac{0.25^2 + 0.15^2 - 0.2^2}{2*0.25*0.15}\\\\cos ( \beta ) = 0.6\\\\\beta = 53.13^{\circ \:}[/tex]

- Now determine the scalar gravitational forces due to sphere A and B on C:

       Between sphere A and C:

                  Fac = G*ma*mc / rac^2

                  Fac = (6.674×10−11)*80*0.2 / 0.2^2  

                  Fac = 2.67*10^-8 N

                  vector Fac = Fac* [ - cos (α) i + - sin (α) j ]

                  vector Fac = 2.67*10^-8* [ - cos (36.87°) i + -sin (36.87°) j ]

                  vector Fac = [ - 2.136 i - 1.602 j ]*10^-8 N

       Between sphere B and C:

                  Fbc = G*mb*mc / rbc^2

                  Fbc = (6.674×10−11)*60*0.2 / 0.15^2  

                  Fbc = 3.56*10^-8 N

                  vector Fbc = Fbc* [ cos (β) i - sin (β) j ]

                  vector Fbc = 3.56*10^-8* [ cos (53.13°) i - sin (53.13°) j ]

                  vector Fbc = [ 2.136 i - 2.848 j ]*10^-8 N

- The Net gravitational force can now be determined from vector additon of Fac and Fbc:

                  Fc = vector Fac + vector Fbc

                  Fc = [ - 2.136 i - 1.602 j ]*10^-8  + [ 2.136 i - 2.848 j ]*10^-8

                  Fc = [ - 4.45 * 10^-8 j ] N  

Answer:

the object is placed at 2f

Explanation:

Converging lens are convex lens, as the name emanates , they are light rays that  converge at a  point via a certain distance at the opposite side. Often times , any incident rays that is moving and is parallel to the principal axis is usually termed as Converging lens.

So when the object is placed at 2f , the image will be formed at 2f to the right for converging lens.

Answer:

1. The moments of loudness represent constructive interference.

3.The moments of softness represent destructive interference.

5. The instrument is tuned when the frequencies of the standard and the instrument align.

Explanation:

Beats are the periodic and repeating fluctuations heard in the intensity of a sound when two sound waves of very similar frequencies interfere with one another.

Constructive interference is the process whereby two waves of identical wavelength that are in phase form a new wave with an amplitude equal to the sum of their individual amplitudes.

In the case of musical instruments, the loudness is due to a wave of larger amplitude formed as a result of the constructive interference of two waves that are in phase

Destructive Interference is the interference of two waves of equal frequency and opposite phase, resulting in the formation of a wave of lesser amplitude or even total cancellation.

The softness in sound is due to the destructive interference of two waves in opposite phase.

When there is an alignment in the frequency of the standard and the instrument, the instrument is tuned

Answer:

1. The moments of loudness represent constructive interference.

3.The moments of softness represent destructive interference.

5. The instrument is tuned when the frequencies of the standard and the instrument align.

Explanation:

The magnitude of the net magnetic field at the common center can be calculated using the formula MOI B = (at the center of the loop)/2R. The magnetic field strength at the center is approximately 6.28 × 10-5 T.

The magnitude of the net magnetic field at the common center can be calculated using the formula for the magnetic field strength at the center of a circular loop, which is given by MOI B = (at the center of the loop), 2R. In this case, the radius of each loop is 5.00 cm. Plugging in the values, the magnetic field strength at the center can be calculated.

Substituting the given values into the equation:

Magnetic field strength = MOI B = (2 × π × (5.00 cm)²)(2.10 A)/(2 × 5.00 cm) ≈ 6.28 × 10-5 T

Therefore, the magnitude of the net magnetic field at the common center is approximately 6.28 × 10-5 T.

https://brainly.com/question/32509429

#SPJ12

The net magnetic field at the common center of the loops will be 3.71 × 10⁻⁵ T.

The two circular loop of wire have their planes perpendicular to each other and share a common centre. This indicates that the direction of net magnetic field at the common centre due to any one of the loops will be perpendicular to the direction of the net magnetic field at the common centre due to the other loop.

As both the loops have the same radius (r), same number of turns (N), and carry the same current (I), hence, the magnetic field at the centre of the loops will have the same magnitude and can be given by the formula:

[tex]B = \frac{N\mu_oI}{2r}[/tex]

Given that:

N = 1

I = 2.10 A

r = 5.00 cm = 0.05 m

μ₀ = 4π × 10⁻⁷

Substituting the values, we get:

[tex]B = \frac{(4 \pi \times 10^{-7})(2.10 A)}{2(0.05 m)}[/tex]

B = 2.63 × 10⁻⁵ T

The net magnetic field at the common centre can be found using

[tex]B_{net} = \sqrt{B_1^{2} +B_2^{2} +2B_1B_2cos\theta}[/tex]

as both the magnetic fields are perpendicular to each other the angle (θ) between them will be 90°.

∴ [tex]B_{net} = \sqrt{B_1^{2} +B_2^{2} }[/tex]

[tex]B_{net} = \sqrt{2B^{2} }[/tex]

[tex]B_{net} = \sqrt{2(2.63 \times 10^{-5} T)^{2} }[/tex]

[tex]B_{net} = (2.63 \times 10^{-5} T)\sqrt{2} }[/tex]

or, [tex]B_{net} = 3.71 \times 10^{-5} \hspace{0.5mm} T[/tex]

Answer:

1026 N

Explanation:

Force on a moving charge in a magnetic field is given by

F= qvB Sinθ

F = 2 x 5 x 10^6 x 3 x 10-4 x Sin (20)

F = 1026 N

Answer:

1.0 x 10^-3 N

Explanation:

got it right on edge:3

Answer:

time taken to reach maximum height(t)=3seconds

Explanation:

1st equation of motion:v=u-gt ,but v=0 at maximum height.so 0=u-gt

t=u÷g where,u=30m/s,h=20m,g=10m/s square

so t=30÷10

t=3seconds

Answer: find the attached figure for a and b

Explanation:

A) The second figure depict electric field lines and equipotential lines for two equal but opposite charges. The equipotential lines can be drawn by making them perpendicular to the electric field lines. The potential is greatest (most positive) near the positive charge and least (most negative) near the negative charge.

B) The figure attached depicts an isolated point charge Q with its electric field lines in blue and equipotential lines in green. The potential is the same along each equipotential line, meaning that no work is required to move a charge anywhere along one of those lines. Work is needed to move a charge from one equipotential line to another. Equipotential lines are perpendicular to electric field lines in every case.

Please find the attached file for the figure

Answer:

Time, t = 0.104 seconds

Explanation:

Frequency of the click of the Dolphin, f = 55.3 kHz

A dolphin sends out a series of clicks that are reflected back from the bottom of the ocean 80 m below, d = 80 m

The speed of sound in seawater is, v = 1530 m/s

Once the sound is send and reflects, the total distance covered by it is 2d such that,

[tex]t=\dfrac{2d}{v}\\\\t=\dfrac{2\times 80}{1530}\\\\t=0.104\ s[/tex]

So, the time elapses before the dolphin hears the echoes of the clicks is 0.104 seconds.

We can see here that the correct answer is: A. KE increases and PE increases.

As the ball moves upward against gravity, its height increases, indicating a rise in its potential energy (PE). Since the ball moves, its speed increases, implying an increase in its kinetic energy (KE) as well.

KE (kinetic energy) is the energy possessed by an object due to its motion. When the batter hits the foul ball, the baseball is set in motion, and its kinetic energy increases as it moves upward.

PE (potential energy) is the energy possessed by an object due to its position or condition.

Answer:

The current in the loop will flow in anticlockwise direction , and the magnetic field created by the induced current point up.

Explanation:

Answer:

The correct option is;

c) Both technicians A and B

Explanation:

Normally the pressure required for a normally inflated tire is included on the side or sidewall of the tire along with the instruction as to the qualification and training required to inflate the vehicle tire. Other information on the sidewall includes the tire model, brand name and manufacturer.

The proper inflation pressure can also be located on the tire information manual or decal as well on the door on the driver's side.

Technician B is correct in recommending that tires should be inflated to the pressure specified on the vehicle's placard. It is more accurate than the maximum pressure imprinted on the tire sidewall.

When considering tire inflation for safe and economical operation of a vehicle, there seem to be conflicting recommendations from two technicians on the correct pressure. Technician A suggests that tire pressure should never exceed the maximum pressure imprinted on the sidewall of the tire. However, this is not necessarily the recommended operating pressure; it is simply the maximum pressure that the tire can safely handle. Technician B provides a more accurate recommendation by advising to inflate tires to the pressures recommended on the tire information decal or placard on the driver's door. This placard usually lists the optimal pressure for the vehicle's tires based on the manufacturer's specifications, and accounts for the best performance and safety.

Most vehicle manufacturers specify the optimal tire pressure for cold tires, which might differ from the maximum pressure on the tire sidewall. Maintaining the proper air pressure in the tires ensures smoother and safer rides, better gas mileage, and longer tire life. Therefore, the correct answer to the question is (b) Technician B only.

Nuclear power stations transfer energy by nuclear fission to heat water, producing steam. This steam drives turbines connected to generators, producing electricity. The electricity is transported through power lines across the national grid.

In a nuclear power station, the useful energy is primarily carried from the power plant through the national grid system. Here's how it works: nuclear power stations transfer energy via a process called nuclear fission where atoms are split, releasing a large amount of energy. This energy is used to heat up water, even to the point of converting it to steam. The steam drives the turbines which are connected to generators. These generators produce electricity, which is then distributed through power lines across the national grid, reaching homes, factories, offices and so on.

https://brainly.com/question/2409175

#SPJ3

The coefficient of linear expansion for the material of the rod can be calculated using the formula ΔL/L = α ΔT to be α = 2 x 10⁻⁵ °C⁻¹.

The subject of this question is the calculation of the coefficient of linear expansion for a certain material. The relevant formula here is: ΔL/L = α ΔT, where ΔL is change in length, L is original length, α is coefficient of linear expansion and ΔT is change in temperature.

Firstly, we calculate the change in length of the rod (ΔL) which is the final length minus initial length, 20.11 cm - 20.05 cm = 0.06 cm. Then, the change in temperature (ΔT) is the final temperature minus the initial one: 270°C - 20°C = 250°C.

After substitution into the formula, we get 0.06 cm / 20.05 cm = α × 250°C. Solving for α, we get the coefficient of linear expansion for the material of the rod to be α = 2 x 10-5 °C⁻¹.

https://brainly.com/question/35456061

#SPJ12

The coefficient of linear expansion for the material of the rod is approximately 0.011974 cm/°C.

To find the coefficient of linear expansion for the material of which the rod is made, we can use the equation for linear thermal expansion:

ΔL = αLΔT

where ΔL is the change in length, α is the coefficient of linear expansion, L is the initial length of the rod, and ΔT is the change in temperature.

Given that the initial length of the rod is 20.05 cm, the final length is 20.11 cm, and the change in temperature is 270 °C - 20 °C = 250 °C, we can substitute these values into the equation to solve for α:

Hence, the coefficient of linear expansion for the material of which the rod is made is approximately 0.011974 cm/°C.

https://brainly.com/question/35554239

#SPJ3

Final answer:

Both Technician A, who speaks about failure analysis for cost effectiveness, and Technician B, who discusses manufacturers' interest in analyzing engine failures under warranty, are correct. These considerations involve complex decision-making in modern automotive engineering, influenced by sophisticated technology and warranty strategies.

Explanation:

Both Technician A and Technician B are correct in their statements. Technician A remarks that a failure analysis is beneficial for determining the most cost-effective option between repairing or replacing an engine. Modern engine complexities mean assessment is critical for understanding the financial impacts of such decisions. Meanwhile, Technician B highlights the interest manufacturers may have in retrieving a failed engine under warranty for complete analysis to understand the failure reasons and improve future manufacturing processes.

Modern car engines have become sophisticated computer-controlled systems, and professionals often require expensive computerized equipment to carry out repairs. This necessity can change the business dynamics for auto repair shops. Warranties also play a significant role, helping to distinguish between higher and lower quality cars, with longer warranties often indicating confidence from the manufacturer in the vehicle's reliability.

Final answer:

Both Technician A and Technician B are correct; Technician A emphasizes the importance of a cost-benefit analysis, while Technician B points out the manufacturer's need for quality control and improvement.

Explanation:

The question revolves around the roles and statements made by two hypothetical technicians, Technician A and Technician B, in the context of engine failure analysis in the automotive industry. Technician A contends that failure analysis is beneficial for determining if it is more cost-effective to replace rather than repair an engine, which is a question of balancing the costs of new equipment against the costs and risks of continued equipment failure. Technician B states that when an engine fails while under warranty, the manufacturer might request the engine to determine the cause of failure, which is a matter of quality control and learning from product errors to prevent future occurrences.

In this scenario, both Technician A and Technician B are correct. Technician A highlights the importance of a cost-benefit analysis when deciding to repair or replace an engine. Technician B discusses the manufacturer's interest in warranty cases which is crucial for improving the product and maintaining customer satisfaction and safety.

Answer:

0.28 year

Explanation:

Heat lost through new window per year = heat loss through a window / R- value = (10 MMBTU/year × 2) / 7 = 2.86 MMBTUs/yr

Reduction in heat lost per year = heat loss through a window - Heat lost through new window per year = 10 MMBTUs/yr - 2.86 MMBTUs/yr  = 7.14 MMBTUs/yr

Savings in energy cost per year = Reduction in heat lost per year × heating price = 7.14 MMBTUs/yr × $10/MMBTU = $71.4 / yr

Payback period =  cost for filling Argon / Savings in energy cost per year = $20 / $71.4 /yr =  0.28 yrs

Answer:

cop = 4.859

power = 30.87 KW

Explanation:

the pictures attached herewith shows the calculation

By calculating the work input to the compressor (Wc) using the COP formula and known cooling load (Qc), and assuming a COP of 4, the power required is 37.5 kW.

To determine the Coefficient of Performance (COP) and power required for the ideal vapor-compression refrigeration cycle, we'll use the following steps and equations:

Find the Heat Transfer in the Evaporator (Qc):

Given Cooling Load (Qc) = 150 kW.

Calculate Work Input to the Compressor (Wc):

Using the first law of thermodynamics:

Qc = Wc + Qh

Rearrange to find Wc:

Wc = Qc - Qh

Determine Heat Rejected in the Condenser (Qh):

To find Qh, we need to calculate the change in enthalpy in the evaporator and condenser using refrigerant properties, such as specific enthalpy values. For refrigerant R-134a at -12 degrees Celsius, you can use property tables or software to find the enthalpy values.

Find COP:

COP is defined as:

COP = Qc / Wc

Calculate Power Required for Service:

Using the COP and Qc:

Wc = Qc / COP

Now, let's calculate:

Assuming a COP value (e.g., 4):

Wc = 150 kW / 4 = 37.5 kW

So, with a chosen COP of 4, the power required for the service is 37.5 kW.

For more such information on; compressor

https://brainly.com/question/30404542

#SPJ3

Answer:

Ellen tested the water in Massachusetts and it had way too much chlorine. She talked to the city and got them to stop dumping waste and garbage into the water.

Explanation:

oh btw im in 5th grade and i get these kind of questions your welcome