A flywheel in the form of a uniformly thick disk of radius 1.83 m, has a mass of 24.1 kg and spins counterclockwise at 217 rpm. calculate the constant torque required to stop it in 2.25 min.

Answers

Answer 1
We need to calculate the angular acceleration of the disk first.
The disk starts at 217 rpm and stops, so its final angular speed is zero, therefore the variation of angular speed is
[tex]\Delta \omega = 0 - 217 rpm =-217 rpm = -22.7 rad/s[/tex]
The time interval in which the disk stops is
[tex]\Delta t=2.25 min=135 s[/tex]
Therefore, the angular acceleration is
[tex]\alpha = \frac{\Delta \omega}{\Delta t}= \frac{-22.7 rad/s}{135 s}=-0.17 rad/s^2 [/tex]

Now, we can find the torque needed to stop the disk by using the equivalent of Netwon's second law for the rotational motions:
[tex]\tau = I \alpha[/tex]
where [tex]\tau [/tex] is the torque, [tex]I[/tex] is the moment of inertia of the object and [tex]\alpha[/tex] is the angular acceleration.
The moment of inertia for a disk is [tex]I= \frac{1}{2} mr^2 [/tex], therefore substituting this into the formula and by using the data of the exercise, we can find the torque:
[tex]\tau = ( \frac{1}{2} mr^2)\alpha = \frac{1}{2}(24.1 kg)(1.83m)^2 (-0.17rad/s^2)=-6.79kgm^2s^{-2} [/tex]
where the negative sign means the torque is directed against the direction of the rotation, so anti-clockwise.
Answer 2
Final answer:

The constant torque required to bring a flywheel of mass 24.1 kg and radius 1.83 m spinning at 217 rpm to rest in 135 seconds is approximately -6.78 N·m.

Explanation:

The question pertains to the principles of circular motion and angular momentum. It requires calculating the torque needed to stop a spinning flywheel. Torque can be equated to the change in angular momentum divided by the time it takes for that change to occur. Firstly, given the spinning speed of 217 rpm, we need to convert this to rad/s. After the conversion, we have an angular velocity ω of about 22.7 rad/s. The moment of inertia I of a uniformly thick disk is (1/2)*m*r^2, substituting m = 24.1 kg and r = 1.83 m, we get I to be approximately 40.3 kg·m². To find the final angular momentum, we multiply I by the final angular velocity, which is zero as the flywheel stops, and subtract from it the initial angular momentum. This results in a change in angular momentum of about -915.1 kg·m²/s. Dividing this by the time to stop in seconds (135s), we find the constant torque required to stop the flywheel to be approximately -6.78 N·m.

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Related Questions

An ideal gas in a sealed container has an initial volume of 2.30 l. at constant pressure, it is cooled to 24.00 °c where its final volume is 1.75 l. what was the initial temperature?

Answers

Considering the Charles' law, the initial temperature was 390.34 K or 117.34 °C.

Definition of Charles's Law

Charles's Law consists of the relationship that exists between the volume and temperature of a certain amount of ideal gas, which is maintained at a constant pressure, by means of a proportionality constant that is applied directly. For a given amount of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement of the gas molecules. .

In summary, Charles's law is a law that says that when the amount of gas and pressure remain constant, the ratio between volume and temperature will always have the same value:

V÷T=k

Analyzing an initial state 1 and a final state 2, the following is true:

V₁÷T₁=V₂÷T₂

Initial temperature

In this case, you know:

V₁= 2.30 LT₁= ?V₂= 1.75 LT₂= 24 °C= 297 K (being 0°C= 273 K)

Replacing in Charles' law:

2.30 L÷T₁= 1.75 L÷297 K

Solving:

2.30 L= (1.75 L÷297 K)× T₁

2.30 L÷ (1.75 L÷297 K)= T₁

390.34 K= 117.34 °C= T₁

Finally, the initial temperature was 390.34 K or 117.34 °C.

A hydrogen electron returns from energy level n = 3 to n = 1 during electron transition. What will the spectral lines emitted by this electron look like under a spectroscope? dark line spectrum white light continuous spectrum bright line spectrum

Answers

The answer is D for plato

Answer:

when electron jump from n=3 to n=1 then the photon coming out is of Lyman series. Here Lyman series photon is also known as Ultraviolet range of photon

Explanation:

As per Bohr's theory we know that when electron make transition from higher energy level to lower energy level then it emits photons of different energy range.

Here we know that when electron makes transition from any higher level to n=1 then it is ultraviolet range of photons.

While if electron makes transition from any higher energy range to n= 2 then it is visible range of photons

and for any higher energy level to n=3 then it is infrared range of photon

So here the spectrum received in this case is of ultraviolet range

A monatomic ideal gas expands slowly to twice its original volume, doing 280 j of work in the process. find the heat added to the gas if the process is isothermal.

Answers

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
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A 75-g bullet is fired from a rifle having a barrel 0.540 m long. choose the origin to be at the location where the bullet begins to move. then the force (in newtons) exerted by the expanding gas on the bullet is 16000 10000x - 26000x2, where x is in meters. (a) determine the work done by the gas on the bullet as the bullet travels the length of the barrel. (enter your answer to at least two decimal places.) 8.73 kj (b) if the barrel is 0.95 m long, how much work is done

Answers

part a) The work done by the gas on the bullet is the integral of the force in dx, where x is the distance covered by the bullet inside the barrel with respect to the origin:
[tex]W= \int\limits^{0.540m}_{0} {F} \, dx = \int\limits^{0.540m}_{0} {(16000+10000x-26000x^2)} \, dx = [/tex]
[tex]=16000x+10000 \frac{x^2}{2} - 26000 \frac{x^3}{3} [/tex]
By substituting the length of the barrel, L=0.540 m, we find the total work done by the gas on the bullet:
[tex]W=16000(0.540m)+10000 \frac{(0.540m)^2}{2} - 26000 \frac{(0.540m)^3}{3} = [/tex]
[tex]=8733 J=8.73 kJ [/tex]

part b) The resolution of the problem is the same, we just have to use the new length of the barrel (L=0.95 m) inside the final formula, and we find the new value of the work:
[tex]W=16000(0.95m)+10000 \frac{(0.95m)^2}{2} - 26000 \frac{(0.95m)^3}{3} =[/tex]
[tex]=12280 J=12.28 kJ[/tex]

Jack is working with layer masks on an image, but he is worried that he may damage the image. Which of these would be an accurate fact about layer masks?

Answers

It would be the last one. 

Layer masks are a non-destructive image editing technique that allows changes to be applied without altering the original image data, providing safety and flexibility in editing.

One accurate fact about layer masks in image editing is that they are non-destructive. This means that when Jack works with layer masks, he is not directly altering or damaging the original image data. Instead, layer masks allow him to apply changes, such as hiding or revealing parts of the layer, without permanently affecting the image. These masks can be edited at any time to adjust the visibility of different portions of the layer. If a mistake is made, Jack can simply edit the mask to correct the issue, rather than having to restore the original image from a separate file. Therefore, layer masks provide flexibility and safety for image editing, ensuring the original data remains intact.

An object has a kinetic energy of 225 j and a momentum of magnitude 28.3 kg · m/s. (a) find the speed of the object. m/s (b) find the mass of the object

Answers

A. hope this helps ;0

Which statement best describes how a wave would move differently through a pot of boiling water than the steam created from it? The wave would move faster through the water than through the steam. The wave would move slower through the water than through the steam. The wave would move the same speed through the water and the steam. The wave would move through the water and steam at the same speed, but decrease in speed at the transition point.

Answers

Your answer would be option A

Answer:

The wave would move faster through the water than through the steam

Explanation:

A mechanical wave is a wave that is transmitted through the oscillations of the particles in a medium. The closer the particles in the medium are, the more efficient the transmission of the wave is (because the collisions between the particles are more frequent), and so the faster the wave.

For this reason, mechanical waves travel faster in liquids (such as water) than in gases (such as the steam): because particles in liquids are closer together than in gases, where they are more spread apart. Therefore, the correct choice is

The wave would move faster through the water than through the steam

Consider a wire that has resistance r, length l and the cross-sectional area
a. the correct expression for the resistivity of that wire is:

Answers

rho = R * A/l
rho is the resistivity in ohm meters.
R is the resistance in ohms
A is the cross sectional area in meter^2
l is in meters.

Answer:

[tex]\rho = \frac{RA}{L}[/tex]

Explanation:

.As we know that the resistance of the wire is given as

[tex]R = \rho \frac{L}{A}[/tex]

here we know that

A = cross-sectional area

L = length

R = resistance of wire

now multiply both sides of above equation with Area

[tex]R A = \rho L[/tex]

now divide both sides with length of the wire

[tex]\rho = \frac{RA}{L}[/tex]

so above is the expression of resistivity of wire in terms of resistance, Area and length of the wire

Which layer of the sun is responsible for producing the light shown in the picture above?

Radiative zone
Convective zone
Photosphere
Chromosphere

Answers

Answer:

C. Photosphere

Explanation:

The lights shown in the figure comes from the outermost layer of the Sun. This layer is called photosphere.

This is the layer from where the light of the Sun is radiated, before travelling through space and reaching us.

The photosphere is the coldest layer of the Sun: its surface temperature is between 4500 and 6000 K. Its width is approximately 100 km.

A characteristic of the photosphere is the presence of the sunspots, which appear as darker spots, and are regions of lower temperature caused by a concentration of magnetic flux.

The correct option is Option C( Photosphere).The photosphere is the layer of the sun responsible for producing the visible light we see. It has a temperature range of 4500 K to 6800 K. The photosphere is the sun's visible surface.

The layer of the sun responsible for producing the light that we see is the photosphere. The photosphere is the visible surface of the sun and has a temperature that ranges from 4500 K to about 6800 K. It is where the light that we see directly is emitted. Above the photosphere are other layers such as the chromosphere and the corona, but it is the photosphere that generates the light.

Assuming the wind blew the same direction all night, what direction, in degrees north of west, did the wind blow jack during the night?

Answers

Final answer:

The question involves physics and vector subtraction to determine the wind's speed and direction affecting an airplane's travel based on its heading and ground velocity.

Explanation:

The student is asking about determining the wind's speed and direction based on an airplane's velocity relative to the ground and its intended heading. To solve for this, we need to use vector subtraction since the airplane's ground velocity can be thought of as a combination of its own speed and the wind's influence. Given that the airplane is heading north at 45.0 m/s and its ground speed is 38.0 m/s at an angle west of north, the wind's speed and direction are the vectors that need to be added to the airplane's heading to equal the ground speed vector. A vector diagram would need to be drawn, and trigonometry would be used to calculate the magnitude of the wind's vector and its angle relative to the west.

Which scientists contributed to discovering the universal law of gravitation? Check all that apply. Tycho Brahe Albert Einstein Johannes Kepler Nicolaus Copernicus Sir Isaac Newton Robert Hooke

Answers

Tycho Brahe

Johannes Kepler

Nicolaus Copernicus

Sir Isaac Newton

Robert Hooke

The scientists contributed to discovering the universal law of gravitation are Tycho Brahe,  Johannes Kepler , Nicolaus Copernicus , Sir Isaac  Newton , and Robert Hooke .

What is science?

Science is the methodical, empirically-based pursuit and application of knowledge and understanding of the natural and social worlds.

A method of learning about the world is science. Science allows people to participate in the creation of new knowledge as well as use that knowledge to further their goals.

Tycho Brahe, Johannes Kepler, Nicolaus Copernicus, Sir Isaac Newton, and Robert Hooke are the scientists who made significant contributions to the discovery of the gravitational constant.

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what is rolling friction

Answers

When something rubs on a object with friction and negative charges react so for instance if you had a furry dog with a lot of hair and he rolled on a hairy carpet he would get negative charges.

Rolling friction is a force resisting motion when an object rolls on a surface. An example could be a ball rolling or a tire.

What does it mean to say that science is a “systematic” process?

Answers

Well, "Systematic" means doing something, according to plan, meaning if we play tic-tac-toe, and you go first and i go second, and it keeps repeating the same way, its systematic. Because we played according to the rules. The plan.

A wooden block has a mass of 986 g and a density of 16 g/ cm3. What is the volume?

Answers

Density = Mass / Volume.
Volume = Mass / Density = 986 / 16 = 61.625 cm^3.

Express 4,560 m in km. Remember to keep the same number of significant figures in your answer as was in the original measurement.

Answers

Since

1 km = 1000 m,

we multiply 4560 by 1000.

4560 × 1000 = 4,560,000

Hope this helps!

Answer:

4.56 km.

Explanation:

Blessings.

"(a) how much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 6.00 cm2? (assume air has a dielectric strength of 3.00 ✕ 106 v/m and dielectric constant of 1.00.)"

Answers

The voltage value for the electric breakdown is given by
[tex]V_{BD}=E_{DS} d[/tex] (1)
where [tex]E_{DS}=3.0 \cdot 10^6 V/m[/tex] is the dielectric strenght of the air while d is the distance between the two plates of the capacitor.

For a parallel plate capacitor, the capacitance is given by
[tex]C= \frac{Q}{V}= \frac{\epsilon A}{d} [/tex] (2)
where Q is the charge on the capacitor, V the voltage applied, [tex]\epsilon=1[/tex] is the dielectric constant in air and [tex]A=6.0 cm^2 = 6.0 \cdot 10^{-4} m^2[/tex] is the area of the plates in our problem. 

If we use the breakdown voltage given by equation (1) and replace V in equation (2) with this value, we find:
[tex] \frac{Q}{E_{DS} d}= \frac{\epsilon A}{d} [/tex]
and from this, we can find the maximum charge allowed on the capacitor before the break down:
[tex]Q=\epsilon A E_{DS}= (1)(6\cdot 10^{-4}m^2)(3 \cdot 10^6 V/m)=1800 C[/tex]

A ____ is a region so dense that nothing, including light, can escape its gravity field.

a. supernova c. black hole b. white dwarf d. supergiant Please select the best answer from the choices provided

Answers

The answer is c. black hole

Answer:

black hole

Explanation:

A black hole is a region which is highly dense and very high gravitational field.

As the density of black hole is very high, so the mass of black g=hole is very large thus the force of gravitation is very large. So, even light cannot escape from the gravitational filed from the black hole.

A microwave oven operates at 2.70 ghz . what is the wavelength of the radiation produced by this appliance? express the wavelength numerically in nanometers.

Answers

The wavelength of the microwave radiation produced by microwave oven is [tex]\boxed{1.1\times {10^8}\,{\text{nm}}}[/tex].

Further Explanation:

A microwave is an appliance which is used to heat and cook food by direct exposing it to electromagnetic radiation. Microwave oven uses radio waves to heat and cook food. A magnetron is used as a source of microwave radiation.

The radiation travels with the speed of light inside the microwave oven.

Given:

The operational frequency of the microwave oven is [tex]2.70\text{ GHz}[/tex].

The speed of the radiation is [tex]3\times10^{8}\text{ m/s}[/tex].

Concept:

The frequency and wavelength of an electromagnetic radiation are related according to the following expression.  

[tex]c=f \cdot \,\lambda[/tex]

Rearrange the above expression for [tex]\lambda[/tex] .

[tex]\boxed{\lambda=\dfrac{c}{f}}[/tex]                                 …… (1)

Here, [tex]c[/tex] is the speed of light, [tex]f[/tex] is the frequency of the radiation and [tex]\lambda[/tex] is the wavelength of the radiation.

Converting [tex]\text{GHz}[/tex] into [tex]\text{Hz}[/tex].

[tex]2.70\,{\text{GHz=2}}{\text{.70}} \times {\text{1}}{{\text{0}}^9}\,{\text{Hz}}[/tex]

Substitute [tex]3.00 \times {10^8}\,{\text{m/s}}[/tex] for [tex]c[/tex] and [tex]2.70 \times {10^9}\,{\text{Hz}}[/tex] for [tex]f[/tex] in equation (1).  

[tex]\begin{aligned}\lambda&=\frac{{3.00 \times {{10}^8}\,{\text{m/s}}}}{{2.70 \times {{10}^9}\,{\text{Hz}}}} \\&=0.11\,{\text{m}} \\&=1.1\times10^{8}\text{ nm} \\ \end{aligned}[/tex]

Thus, the wavelength of the microwave radiation produced by microwave oven is [tex]\boxed{1.1\times {10^8}\,{\text{nm}}}[/tex].

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Answer Details:  

Grade: High school  

Subject: Physics  

Chapter: Electromagnetic radiation  

Keywords:  

Microwave oven, 2.70 GHz, 2.70 ghz, 2.70 times 10^9 Hz, wavelength, numerically, nanometers, 0.11 m, 0.11 times 10^9 nm, 1.1 times 10^8 nm , magnetron, 0.11 times 10power9 nm, 1.1 times 10 power 8 nm.

The wavelength of the radiation produced by the microwave oven is approximately 111,111,111 nanometers.

To find the wavelength of the radiation produced by a microwave oven operating at 2.70 GHz, you can use the formula:

Wavelength (λ) = Speed of Light (c) / Frequency (f)

Where:

Speed of Light (c) = 3 x [tex]10^8[/tex] meters per second (approximately)

Frequency (f) = 2.70 GHz = 2.70 x [tex]10^9[/tex] Hertz

Now, plug these values into the formula:

λ = (3  x [tex]10^8[/tex]  m/s) / (2.70 x [tex]10^9[/tex] Hz)

λ = 0.1111 meters.

To express this wavelength in nanometers, you can convert meters to nanometers. There are 1 billion nanometers in a meter, so:

λ ≈ 0.1111 meters * 1,000,000,000 nanometers/meter ≈ 111,111,111.11 nanometers

Hence , The wavelength of the radiation produced by the microwave oven is approximately 111,111,111 nanometers.

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Describe a situation in which different units of measure could cause confusion.

Answers

Answer:

When different countries use different forms of measurement there is many different mistakes and confusion that can happen.

Explanation:

Final answer:

Different units of measure can cause confusion and serious mishaps in critical fields like medicine and aviation. Unit conversion is essential for clear communication, with dimensional analysis being a key tool for accurate conversions. Appropriate units must be used in context to avoid misunderstandings.

Explanation:

Different units of measure can lead to confusion, miscommunication, and even dangerous situations if not properly managed. This is particularly true in fields where precise measurements are critical, such as medicine, engineering, and aviation.

One famous example is the loss of the Mars Climate Orbiter spacecraft in 1999 due to the use of English units in the software while engineers used metric units for its development. Similarly, in 1983, an Air Canada plane ran out of fuel and had to make an emergency landing because the fuel tanks were filled using pounds instead of kilograms. Even in daily life, incorrect unit conversion can be problematic, such as when dispensing medication and precise dosages are required for safety.

To avoid such missteps, unit conversion is necessary. By converting units, we effectively communicate the same quantity in different terms. For example, 12 inches can also be expressed as 1 foot, but both units describe the identical length. Understanding dimensional analysis is key to accurate conversion and communication of measurements.

When selecting appropriate units, context is important to convey measurements accurately. The distance between two towns is best measured in kilometers or miles, the weight of a peanut in grams, the length of a hand in centimeters, and the volume of a raindrop in milliliters. Using the correct units ensures clarity and avoids confusion.

A 2.00-kg metal object requires 1.00 × 104 J of heat to raise its temperature from 20.0 °C to 60.0 °C. What is the specific heat of the metal?

Answers

Answer:

  0.125 J/(g·k)

Explanation:

Specific heat has units of J/(g·K), so we find the value by dividing the energy by the product of mass and temperature change.

  (10^4 J)/(2·10^3 g·(60 -20)K) = 10/(2·40) J/(g·K) = 0.125 J/(g·k)

Which of the following statements best describes the labor market in the field of healthcare?

Answers

The statements are as follows:
A. It is losing jobs.
B. It is adding jobs.
C. The number of workers is expected to remain the same.
D. The number of workers needed has been in steady decline.
The correct option is B. 
The labour market in the field of health care is the fastest growing job sector in the USA and it creates more jobs than any other sector. For instance, in 2016, the sector helped to drive the total annual job growth to 2.2 million according to the report of Bureau of Labor statistics. 

Answer:

b  

Explanation:

What is the fate of solar radiation that reaches the earth?

Answers

when solar radiation reaches the Earth it quickly dissipates as most of the radiation and UV rays are blocked by ozone layer, but more radiation and UV rays are able to get through because of global warming.

When solar radiation reaches the Earth, some parts of it is defused by the atmosphere and some parts transmitted to Earth's surface.

What is the solar radiation?

A broad name for the electromagnetic radiation emitted by the sun is solar radiation, also known as the solar resource or just sunshine. With the use of various technologies, solar radiation may be absorbed and converted into usable forms of energy like heat and electricity. However, a certain location's solar resource determines whether these systems are technically feasible and operate economically.

Some of the sunlight is absorbed, scattered, and reflected by air molecules, water vapour, clouds, dust, pollutants, forest fires, and volcanoes as it travels through the atmosphere. The term for this is diffuse sun radiation.

Direct beam solar radiation is the type of solar radiation that directly reaches the surface of the Earth. Global solar radiation is the total of both diffuse and direct sun radiation. Direct beam radiation can be reduced by atmospheric conditions by 10% on clear, dry days and by 100% on days with heavy clouds.

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At the top of a giant swing on the gymnastics high bar, candy's velocity is 1 m/s, and she is 3.5 m high. if candy's mass is 50 kg, what is her total mechanical energy at this instant?

Answers

The total mechanical energy is the sum of the kinetic energy and the gravitational potential energy:
[tex]E=K+U= \frac{1}{2}mv^2 +mgh[/tex]
where m=3.5 kg is Candy's mass, v=1 m/s is her velocity and h=3.5 m is her height. If we replace these numbers, we find the mechanical energy of the system:
[tex]E= \frac{1}{2} (50 kg)(1m/s)^2 + (50 kg)(9.81 m/s^2)(3.5 m)=1742 J =1.74 kJ [/tex]

At the top of the giant swing on the gymnastics high bar, candy's total mechanical energy is 1740J.

Given the data in the question;

Candy's velocity; [tex]v = 1 m/s[/tex]Candy's height from the ground; [tex]h = 3.5m[/tex]Candy's mass; [tex]m = 50kg[/tex]

Candy's total mechanical energy; [tex]M.E_c = \ ?[/tex]

Total Mechanical Energy (M.E) is the sum of both the potential energy and the kinetic energy of an object.

[tex]Mechanical \ Energy = Potential \ Energy + Kinetic \ Energy[/tex]

[tex]M.E = mgh + \frac{1}{2}mv^2[/tex]

Where m is the mass, g is gravitational acceleration( [tex]9.8m/s^2[/tex] ), h is the height and v is the velocity.

We substitute our values into the equation

[tex]M.E_c = ( 50kg * 9.8m/s^2*3.5m) + ( \frac{1}{2}* 50\ *(1m/s)^2)\\\\M.E_c = 1715kg.m^2/s^2 + 25kg.m^2/s^2\\\\M.E_c = 1740 kg.m^2/m^2\\\\M.E_c = 1740J\\[/tex]

Therefore, at the top of the giant swing on the gymnastics high bar, candy's total mechanical energy is 1740J

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A horse does 910 J of work in 380 seconds while pulling a wagon. What is the power output of the horse? Round your answer to two significant figures. The power output of the horse is W.

Answers

Final answer:

The power output of the horse is calculated by dividing the work done by the time taken. With 910 joules of work done in 380 seconds, the power output is approximately 2.4 watts after rounding to two significant figures.

Explanation:

To calculate the power output of the horse, you can use the formula for power, which is work divided by time.

Power (P) = Work (W) / Time (T)

Given the information, the horse does 910 joules (J) of work in 380 seconds. Using the formula:

P = 910 J / 380 s ≈ 2.395 W

Rounded to two significant figures, the power output of the horse is approximately 2.4 watts (W).

Final answer:

It comes out to be approximately 2.394736842 W, which is rounded to 2.4 W to two significant figures. The power output of the horse is calculated by dividing the work done by the time taken.

Explanation:

To calculate the power output of the horse, we use the formula for power (P), which is P = Work done (W) / Time taken (t).

The horse does 910 J of work in 380 seconds.

Therefore, the power output P is:

P = 910 J / 380 s = 2.394736842 J/s

Since 1 watt (W) is equivalent to 1 joule per second (J/s), the power output of the horse is approximately:

P = 2.394736842 W

Rounded to two significant figures, the power output of the horse is 2.4 W.

a system that uses reflected radio waves to detect objects and to measure their distance and speed is called

Answers

Such system is called RADAR (RAdio Detection And Ranging).

The Radar emits radio waves, that are reflected back by the object. Since the speed of the radio waves is known (their speed is equal to the speed of light), by measuring the time the waves take to come back to the source it is possible to infer the distance they covered, and so the distance of the object.

A gas made up of atoms escapes through a pinhole 3.16 times as fast as ar gas. write the chemical formula of the gas.

Answers

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
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An example of a radioactive isotope is carbon-12. carbon-14. neon-20. neon-22.

Answers

The only one on the list that I know is radioactive is Carbon-14. 

Carbon-14 is an example of a radioactive isotope because this element can emit radioactivity.

What is Radioactivity?

Radioactivity is a property where an element can emit energy and atomic particles in a spontaneous manner.

What is isotope?

Isotopes are two or more types of atoms that have the same atomic number and position in the periodic table, and that differ in nucleon numbers due to different numbers of neutrons in their nuclei.

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A block with mass 0.5kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.2m. when the spring is released, the block moves on a horizontal tabletop for 1.00 m before coming to rest. the force constant k is 100n/m. what is the coefficient of kinetic friction μk between the block and the tabletop?

Answers

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
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Photons of light with an energy of 656 nm are being directed through a chamber of hydrogen gas atoms. the gas atoms began in their ground state (ni=1). what happens?

Answers

Since there is not quite enough energy for transition from n=1 to n=2. So, the photons will pass through the gas chamber without affecting the gas.

Further explanation:

If the energy of photons is enough to excite all the electrons to go in higher state, the electron absorbs the energy of photon and go from a lower energy state to higher energy state. Transition of electron from lower energy state t higher energy state depends on the energy of photons.

Given:

The wavelength of the photons directed through a chamber of hydrogen gas atoms is [tex]656\text{ nm}[/tex].

The electron is excited from the energy state [tex]n=1[/tex] to higher energy state.

Concept:

The energy associated with a photon is given by the following relation.

[tex]E = \dfrac{{hc}}{\lambda}[/tex]

Here, [tex]E[/tex] is the energy associated with photon, [tex]h[/tex] is the plank constant, [tex]c[/tex] is the speed of the light and [tex]\lambda[/tex] is the wavelength associated with photon.

Substitute [tex]6.625\times{10^{-34}}\text{ J}\cdot\text{s}[/tex] for [tex]h[/tex], [tex]3.00\times{10^8}\text{ m/s}}[/tex] for [tex]c[/tex] and [tex]656\text{ nm}[/tex] for [tex]\lambda[/tex] in the above expression.

[tex]\begin{aligned}E&=\frac{{\left( {6.625 \times {{10}^{ - 34}}\,{\text{Js}}} \right)\left( {3.0 \times {{10}^8}\,{\text{m/s}}} \right)}}{{\left( {656 \times {{10}^{ - 9}}\,{\text{m}}} \right)}}\\&=3.0281 \times {10^{-19}}\,{\text{J}}\\\end{aligned}[/tex]

Rydberg equations is used to find out the energy level of an electron while transition from one energy state to another energy state.

[tex]\dfrac{1}{\lambda}=R{z^2}\left({\dfrac{1}{{n_1^2}}-\dfrac{1}{{n_2^2}}}\right)[/tex]

Here, [tex]\lambda[/tex]  is the wavelength of the photons directed through a chamber, [tex]R[/tex] is the Rydberg constant, [tex]z[/tex] is the atomic number of hydrogen atom, [tex]{n_1}[/tex] is the lower energy state and [tex]{n_2}[/tex] is the higher energy state.

Substitute [tex]656\times{10^{-9}}\,{\text{m}}[/tex] for [tex]\lambda[/tex], [tex]1.0973 \times {10^7}\,{{\text{m}}^{{\text{-1}}}}[/tex] for [tex]R[/tex], [tex]1[/tex] for [tex]z[/tex] and [tex]1[/tex] for [tex]{n_1}[/tex] in the above expression.

[tex]\dfrac{1}{{\left( {656 \times {{10}^{ - 9}}\,{\text{m}}} \right)}} = \left( {1.0973 \times {{10}^7}{\mkern 1mu} {{\text{m}}^{{\text{-1}}}}} \right){\left( 1 \right)^2}\left( {\dfrac{1}{{{{\left( 1 \right)}^2}}}-\dfrac{1}{{n_2^2}}}\right)[/tex]

Simplify the above expression for [tex]{n_2}[/tex]

[tex]\begin{aligned}{n_2}&=\sqrt{\dfrac{1}{{0.861}}}\\&=1.08\\\end{aligned}[/tex]

From the above result it can be concluded that photons with wavelength [tex]656\text{ nm}[/tex] does not have enough energy to cause an electron to jump even one level higher.

Thus, there is not quite enough energy for transition from n=1 to n=2. So, the photons will pass through the gas chamber without affecting the gas.

Learn more:

1.  A Na+ ion moves from inside a cell https://brainly.com/question/9251988

2.  The kinetic energy of the emitted electrons when cesium is exposed to UV rays https://brainly.com/question/9059731

3. The frequency of the light for wavelength 7.1x10^2 nm https://brainly.com/question/9559140

Answer Details:

Grade: College

Subject: Physics

Chapter: Modern physics

Keywords:

Photons, light, energy, 656 nm, 656 times 10^-9 m, 6.56 times 10^-7 m, directed, chamber, hydrogen, gas atom, ground state, ni=1, 1.071, few, absorbed, quite enough, electrons, nf=2.

Final answer:

When photons with an energy of 656 nm pass through a chamber of hydrogen gas, the gas atoms can absorb these photons, causing the electrons to transition to higher energy levels.

Explanation:

When photons of light with an energy of 656 nm pass through a chamber of hydrogen gas atoms, the gas atoms can absorb photons that have the exact energy required to raise an electron from one energy level to another. In this case, the 656 nm photons have just the right energy to raise an electron in a hydrogen atom from the second to the third orbit.

When the hydrogen atoms absorb the 656 nm photons, the electrons that were initially in the second energy level will move to the third energy level, resulting in a number of missing photons of this wavelength and energy from the general stream of light passing through the gas. This phenomenon is known as absorption.

In summary, when photons with an energy of 656 nm pass through a chamber of hydrogen gas, the hydrogen gas atoms can absorb these photons, causing the electrons to transition to higher energy levels.

A 9.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. the coefficient of kinetic friction between block and surface is 0.20. the bullet remains embedded in the block, which is observed to slide 0.340 m along the surface before stopping. part a what was the initial speed of the bullet? express your answer with the appropriate units.

Answers

Final answer:

To find the initial speed of the bullet, we can use the conservation of linear momentum. By applying the conservation of momentum equation, we can solve for the initial velocity of the bullet. In this case, the initial velocity of the bullet is found to be 0 m/s.

Explanation:

To find the initial speed of the bullet, we need to consider the conservation of linear momentum. The initial momentum of the bullet is equal to the final momentum of the bullet and the block together.

The momentum of an object is given by the product of its mass and velocity. The bullet has a mass of 9.00 g and its velocity is the initial speed we want to find. The block has a mass of 1.20 kg and its velocity is 0 m/s initially.

Applying the conservation of momentum, we have: (mass of bullet) × (initial velocity of bullet) = (mass of bullet + mass of block) × (final velocity of bullet + block).

Since the bullet remains embedded in the block, the final velocity of the bullet and block together is 0 m/s. Plugging in the values, we can solve for the initial velocity of the bullet.

9.00 g × (initial velocity of bullet) = (9.00 g + 1.20 kg) × 0

(initial velocity of bullet) = 0 / (10.2 g)

(initial velocity of bullet) = 0 m/s

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