A gaseous hydrocarbon (a compound that contains only hydrogen and carbon) is found to be 11 % hydrogen by mass. a. Find the empirical formula for the compound.A gaseous hydrocarbon (a compound that contains only hydrogen and carbon) is found to be 11 % hydrogen by mass. a. Find the empirical formula for the compound.

Final answer:

The IUPAC name for the compound is 4-sec-Butyl-2,4-dimethylheptane, which is determined by identifying the longest continuous carbon chain and naming the substituents.

Explanation:

The IUPAC name for the compound is 4-sec-Butyl-2,4-dimethylheptane.

The name is determined by identifying the longest continuous carbon chain, which in this case is heptane. The substituents are then named using prefixes such as sec-, iso-, or tert-, which indicate the position of the substituent on the main chain. The substituents are listed alphabetically, followed by the position number and the main chain name.

In this case, the compound has a butyl group attached at the 4th position on the main chain, and two methyl groups attached at the 2nd and 4th positions. Therefore, the IUPAC name is 4-sec-Butyl-2,4-dimethylheptane.

Answer:

Yes

Explanation:

A reaction normally takes place between metals and non metals. The metals acts as the electron donors and the non metals acts as the electron acceptors. This exchange of electrons form bonds such as ionic or covalent.

A good example of a reaction between a metal and non metal is Sodium metal and Chlorine(non metal). They form an ionic bond and the product is Sodium chloride.

Answer:

Nitrification is a biological process by which ammonia is oxidized to nitrites ([tex]NO_{2} ^{-}[/tex]) and then to nitrates ([tex]NO_{3} ^{-}[/tex]) by action of specialized bacteria in nature (such as nitrosomonas and nitrobacter).

Explanation:

This two-step process utilizes molecular atmospheric oxygen and ammonia and ammonium components of soil and nature.

(a.) Ammonia and ammonium compounds to nitrite

[tex]NH_{4} ^{+} + O_{2}[/tex] → [tex]NO_{2} ^{-} + 4H^{+}[/tex]

[tex]2NH_{3} ^{+} + 3O_{2}[/tex] → [tex]2NO_{2} ^{-} + 2H^{+} + 2H_{2} O[/tex]

(b.) Nitrite to nitrate

[tex]2NO_{2} ^{-} + O_{2}[/tex] → [tex]2NO_{3} ^{-} + energy[/tex]

(c.) The reverse process involves reduction of nitrates to molecular nitrogen, called denitrification (with succinic acid in the equation below).

[tex]4NO_{3} ^{-} + 10H^{+} + (CH_{2})_{2}(COOH)_{2}[/tex] → [tex]2N_{2} +4CO_{2} + 8 H_{2} O[/tex]

([tex]NO[/tex] and [tex]N_{2}O[/tex] is an intermediate product in this process.)

At equilibrium, the composition of the system is determined by the stoichiometry of the reaction. Doubling the pressure will not have a significant effect on the composition of the system at equilibrium.

At equilibrium, the composition of the system can be determined using the stoichiometry of the reaction. In this reaction, one N2 molecule reacts with one C2H2 molecule to produce two HCN molecules. Therefore, at equilibrium, the concentration of N2 and C2H2 will both decrease by the same amount, while the concentration of HCN will increase by twice that amount.

If the pressure is doubled, the system will try to relieve the stress by shifting the equilibrium to the side with fewer moles of gas. In this case, the total number of moles of gas will remain the same, so doubling the pressure will not have a significant effect on the composition of the system at equilibrium.

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Answer:

0.0626 M

Explanation:

Equation of the reaction

CH3COOH(aq) + NaOH(aq) ---------> CH3COONa(aq) + H2O

Concentration of acid CA= ???

Concentration of base CB= 0.1943 M

Volume of acid VA= 10.0ml

Volume of base VB= 32.22 ml

Number of moles of acid NA= 1

Number of moles of base NB= 1

From

CA= CB VB NA/VA NB

Hence ;

CA= 0.1943 M × 32.22 ml × 1/10.0ml ×1

CA= 0.0626 M

Answer:

26 g

Explanation:

Write the balanced reaction first

CH4 + 2 O2 --> CO2 + 2 H2O

9.3g + 52.3g --> ? CO2

You must determine how much carbon dioxide can be made from each of the reactants. The maximum mass that can be made is the lower of the two.

From CH4:

9.3g CH4 (1molCH4/16.05gCH4) (1molCO2 / 1molCH4) (44.01g CH4 / 1molCO2) = 26 g

From O2:

52.3g O2 (1molO2/32gO2) (1molCO2/2molO2)(44.01g/1molCO2) = 36 g

Final answer:

Evidence of a chemical reaction can be determined by changes such as temperature fluctuations, formation of a precipitate, gas production, and color changes. Temperatures changing, solid products forming, gas releasing, and explosions are all indications of chemical reactions.

Explanation:

Evidence indicating that a chemical reaction has occurred includes:

Based on these observations, the correct answers from the choices provided are: (a) The temperature decreased, (b) A solid brown product formed, (c) The temperature increased, (d) A gas formed, and potentially (e) An explosion occurred, as an explosion indicates a rapid energy transfer and creation of new substances.

Answer:

For 1: The molecular equation is [tex]CuI_2(aq)+2NaOH(aq)\rightarrow Cu(OH)_2(s)+2NaI(aq)[/tex]

For 2: The net ionic equation is [tex]Cu(OH)_2(s)\rightarrow Cu^{2+}(aq)+2I^{-}(aq)[/tex]

For 3: The equilibrium constant expression is [tex]K_{eq}=[Cu^{2+}][I^-]^2[/tex]

Explanation:

A molecular equation is defined as the chemical equation in which the ionic compounds are written as molecules rather than component ions.

The molecular equation for the reaction of copper (II) iodide and sodium hydroxide is given as:

[tex]CuI_2(aq)+2NaOH(aq)\rightarrow Cu(OH)_2(s)+2NaI(aq)[/tex]

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of copper hydroxide and sodium iodide is given as:

[tex]2NaI(aq)+Cu(OH)_2(s)\rightarrow 2NaOH(aq)+CuI_2(aq)[/tex]

Ionic form of the above equation follows:

[tex]2Na^{+}(aq)+2I^{-}(aq)+Cu(OH)_2(s)\rightarrow 2Na^+(aq)+2OH^-(aq)+Cu^{2+}(aq.)+2I^{-}(aq.)[/tex]

As, sodium and iodide ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

[tex]Cu(OH)_2(s)\rightarrow Cu^{2+}(aq)+2I^{-}(aq)[/tex]

The expression of equilibrium constant for the net ionic equation above follows:

[tex]K_{eq}=[Cu^{2+}][I^-]^2[/tex]

Concentrations of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Answer:

Explanation:

1. Number of moles of gasoline

a)  Convert 60.0 liters to grams

b) Convert 46,200 grams to moles

2. Number of moles of carbon dioxide, CO₂ produced

a) Balanced chemical equation (given):

b) mole ratio:

Solve for x:

3. Convert the number of moles of carbon dioxide to volume

Use the ideal gas equation:

Substitute and compute:

Round to two significant figures (because the density has two significant figures): 79,000 liters ← answer

The liters L of carbon dioxide at 1.00 atm and 298.15 K released from the car's engine upon consumption of a 60.0 L LIQUID tank gasoline is 79230.76 L

From the given information;

The equation for the reaction can be expressed as:

[tex]\mathbf{C_8H_8 _{(l)} + \frac{25}{2}O_2_{(g)} \to 8 CO_2_{(g)} + 9H_2O_{(g)}}[/tex]

Given that:

The first thing to do is to determine the mass amount of gasoline used by using the relation:

[tex]\mathbf{Density = \dfrac{mass}{volume}}[/tex]

[tex]\mathbf{0.77 \ kg/L = \dfrac{mass}{60 \ L}}}[/tex]

mass amount of gasoline used = 0.77 kg/L × 60 L

mass amount of gasoline used = 46.2 kg

mass amount of gasoline used = 46.2 × 1000g

mass amount of gasoline used = 46200 g

Now, since we know the mass amount of the gasoline used, we can determine the number of moles of the gasoline by using the formula:

[tex]\mathbf{number of moles = \dfrac{mass}{molar \ mass}}[/tex]

[tex]\mathbf{number of moles = \dfrac{46200 \ g}{114.2 \ g/mol}}[/tex]

[tex]\mathbf{number \ of \ moles = 404.6 \ moles }[/tex]

From the given reaction, 1 mole of gasoline react to produce 8 moles of CO₂

As such, 404.6 moles of gasoline will produce = (404.6 moles × 8)/ 1

= 3236.8 moles of CO₂ is produced.

Now, using the ideal gas equation to determine the volume of CO₂ that  are released;

PV = nRT

[tex]\mathbf{1.00 atm \times V = 3236.8 moles \times 0.0821 atm L /K/mol \times 298.15 \ K}[/tex]

[tex]\mathbf{V = \dfrac{3236.8 moles \times 0.0821 atm L /K/mol \times 298.15 \ K}{1.00 atm}}[/tex]

V = 79230.76 L

Therefore, we can conclude that the liters L of carbon dioxide at 1.00 atm and 298.15 K released from the car's engine upon consumption of a 60.0 L LIQUID tank gasoline is 79230.76 L

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Answer:

A. In the formation of water, H2 is the limiting reactant and O2 is the excess reactant.

B. In the Combustion of methane (CH4), O2 is the limiting reactant and CH4 is the excess reactant.

C. In the formation of ammonia (NH3), H2 is the limiting reactant and N2 is the excess reactant.

Explanation:

The question suggests that each reactant has 5 moles.

A. Formation of water. Water is produced when H2 and O2 combine together according to the balanced equation below:

2H2 + O2 —> 2H2O

From the balanced equation above,

2 moles of H2 reacted with 1 mole of O2.

Therefore, 5 moles of H2 will react with = 5/2 = 2.5 moles of O2.

From the above calculations, we can see that there are left over for O2 as only 2.5 moles reacted out of the 5 moles that was given.

Therefore, H2 is the limiting reactant and O2 is the excess reactant.

B. Combustion of methane. Combustion is simply a reaction in the presence of oxygen. The balance equation for the Combustion of methane (CH4) is given below:

CH4 + 2O2 —> CO2 + 2H2O

From the balanced equation above,

1 mole of CH4 reacted with 2 moles of O2.

Therefore, 5 moles of CH4 will react with = 5 x 2 = 10 moles of O2.

From the calculations made above, we can see that it requires higher amount of O2 to react with 5 moles CH4. Therefore, O2 is the limiting reactant and CH4 is the excess reactant.

C. Formation of ammonia.

Ammonia is obtained when N2 and H2 combine according to the balanced equation below:

N2 + 3H2 —> 2NH3

From the balanced equation above,

1 mole of N2 reacted with 3 moles of H2.

Therefore, 5 moles of N2 will react with = 5 x 3 = 15 moles of H2.

From the calculations made above, a higher amount of H2 is required to react with 5 moles of N2. Therefore, H2 is the limiting reactant and N2 is the excess reactant.

Final answer:

To determine limiting or excess reactants, compare the stoichiometry of the balanced equations to the amounts provided. For reactions involving the formation of water or ammonia, and the combustion of methane, the limiting reactant is based on the stoichiometric ratio required for each reactant. Hence, O2 typically ends up as the limiting reactant for the formation of water and combustion of methane, while N2 is the limiting reactant in the formation of ammonia.

Explanation:

When determining whether a reactant is a limiting reactant or an excess reactant, you must look at the balanced chemical equations for the reactions. Consider the stoichiometric coefficients, which tell you the proportions in which reactants combine to form products. If starting with five moles of each reactant:

To identify the limiting reactant, compare the molar ratios of the reactants to those in the balanced equation. The reactant that is in a smaller proportion relative to its stoichiometric coefficient in the equation is the limiting reactant. The one in the larger proportion is the excess reactant.

The properties of matter including structure, composition, and behavior can all be explained on a submicroscopic level. The atoms or molecules' arrangement, what they are composed of, and their response to different conditions, helps in understanding the properties of the matter.

The properties of matter such as structure, composition, and behavior can all be explained on a submicroscopic level. In fact, observing matter at this level allows us to understand why material behaves in the way that it does.

Structure refers to the arrangement of atoms in a material. For example, diamonds and graphite are both made of carbon atoms, but their different structures make them drastically different in hardness.

Composition refers to what a material is made of at the elemental level. For example, water is composed of two hydrogen atoms and one oxygen atom, leading to its unique properties.

Behavior can be understood as the way that material reacts under different conditions, this can be due to the interaction of its molecules. For example, water boils at 100 degrees Celsius because that's the temperature at which its molecules have enough energy to change from a liquid to a gas.

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Final answer:

To calculate the percent dissociation of trimethylacetic acid in an aqueous solution, use the equilibrium constant expression and the initial concentration of the acid.

Explanation:

To calculate the percent dissociation of trimethylacetic acid in an aqueous solution, we need to use the equilibrium constant expression and the initial concentration of the acid. The equilibrium expression for the dissociation of trimethylacetic acid is written as:

Ka = [CH₃COOH]/[CH₃C₃H₇OH]

where [CH₃COOH] represents the concentration of trimethylacetic acid and [CH₃C₃H₇OH] represents the concentration of the dissociated form of the acid.

By rearranging the equation, we can solve for the percent dissociation:

Percent Dissociation = ([CH₃C₃H₇OH]/[CH₃COOH]) x 100

Using the given information or data from the ALEKS Data resource, we can substitute the values into the equation and calculate the percent dissociation.

Answer: Time required for 100 molecules of valinomycin to transport enough [tex]K^{+}[/tex] to change the concentration inside an erythrocyte is 10 minutes.

Explanation:

The given data is as follows.

 Ions to be transported = [tex](10 mM) \times (100 \mu^{3})(N)[/tex]

            = [tex]0.010 mol \times 10^{-13} L \times 6.02 \times 10^{23} ions/mol[/tex]

             = [tex]6.02 \times 10^{6}[/tex] ions

Here, there are 100 ionophores are present and each one of ionophores are required to transport a value of  ions.

Therefore, the time required for 100 molecules of valinomycin to transport enough [tex]K^{+}[/tex] to change the concentration inside an erythrocyte is as follows.

   [tex]6.02 \times 10^{6} ions \times \frac{1 sec}{10^{4} ions}[/tex]

              = 602 sec

or,          = 10 minutes        (as 1 min = 60 sec)

Thus, we can conclude that time required for 100 molecules of valinomycin to transport enough [tex]K^{+}[/tex] to change the concentration inside an erythrocyte is 10 minutes.

Final answer:

The heat of combustion of one mole of naphthalene is 591 kJ/mol.

Explanation:

To calculate the heat of combustion of one mole of naphthalene, we first need to calculate the heat released by the combustion of the given mass of naphthalene. We can use the formula q = mcΔT, where q is the heat released, m is the mass of the naphthalene, c is the heat capacity of the calorimeter and its surroundings, and ΔT is the change in temperature. Substituting the given values into the equation, we have:

q = 1.44 g * 10.17 kJ/°C * (30.70°C - 25.00°C)

q = 1.44 g * 10.17 kJ/°C * 5.7°C

q = 82.9728 kJ

Now, to calculate the heat of combustion per mole of naphthalene, we will use the molar mass of naphthalene, which is 128.18 g/mol:

Heat of combustion per mole = 82.9728 kJ / 1.44 g * 128.18 g/mol

Heat of combustion per mole = 591 kJ/mol

Final answer:

To determine the heat of combustion per mole of naphthalene, the heat released was first calculated using the calorimeter's heat capacity and the observed temperature change. This amount was then divided by the mass of naphthalene burned to find the heat of combustion per gram, which was finally multiplied by the molar mass of naphthalene to get the value per mole.

Explanation:

To find the heat of combustion of one mole of naphthalene using a bomb calorimeter, we first need to use the given heat capacity of the calorimeter, which is 10.17 kJ/°C, and the temperature change that the combustion caused in the water, which was from 25.00°C to 30.70°C. The mass of naphthalene combusted was 1.44 g.

First, calculate the total heat q released during the combustion:

q = C₁₄₂₃ bomb × ΔT = (10.17 kJ/°C) × (30.70°C - 25.00°C) = 10.17 kJ/°C × 5.70°C = 57.969 kJ

Next, calculate the heat of combustion per gram of naphthalene:

q per gram = 57.969 kJ / 1.44 g = 40.2604 kJ/g

Now, to find the heat of combustion per mole of naphthalene, we multiply this value by the molar mass of naphthalene. The molar mass of naphthalene (C₁₀H₈) is approximately 128.17 g/mol.

Heat of combustion per mole = q per gram × Molar Mass = 40.2604 kJ/g × 128.17 g/mol ≈ 5160.76 kJ/mol

Therefore, the heat of combustion of one mole of naphthalene is around 5160.76 kJ/mol.

Answer : The specific heat capacity of lead is, [tex]0.128J/g^oC[/tex]

Explanation :

Formula used:

[tex]q=m\times c\times (T_2-T_1)[/tex]

where,

q = heat produced = 3840 J

m = mass of lead = 3 kg = 3000 g

c = specific heat capacity of lead = ?

[tex]T_1[/tex] = initial temperature = [tex]40^oC[/tex]

[tex]T_2[/tex] = final temperature = [tex]50^oC[/tex]

Now put all the given values in the above formula, we get:

[tex]3840J=3000g\times c\times (50-40)^oC[/tex]

[tex]c=0.128J/g^oC[/tex]

Therefore, the specific heat capacity of lead is, [tex]0.128J/g^oC[/tex]

Answer:

Yes is possible

Explanation:

MnSO4*7H2O(s) → MnSO4(s) + 7H2O(g)

This should be an endothermic reaction. The water molecules are interacting with the Mn2+ and SO42- ions within the crystal lattice of the compound. You must overcome those interactions, and so that would require the input of energy.

Explanation:

Water Content of Epidermal Cells

Temperature: Increase in the temperature causes stomata to open

Answer:

Temperature: Increase in the temperature causes stomata to open

Explanation:

Answer:

0.73M

Explanation:

Answer:

The wavelength the student should use is 700 nm.

Explanation:

Attached below you can find the diagram I found for this question elsewhere.

Because the idea is to minimize the interference of the Co⁺²(aq) species, we should choose a wavelength in which its absorbance is minimum.

At 400 nm Co⁺²(aq) shows no absorbance, however neither does Cu⁺²(aq). While at 700 nm Co⁺²(aq) shows no absorbance and Cu⁺²(aq) does.

Answer:

Spectrophotometric analysis is a quantitative measure of the interaction of spectrum rays and certain molecules.  The wavelength used by student is 700 nanometers.

Explanation:

Spectrophotometric analysis is a method used to measure the amount of absorbance or transmittance done by a substance.

From the knowledge of spectrometric analysis:

In the given question, to minimize the interference by cobalt ion, the student should use the wavelength of 700 nanometers or more. The copper is absorbed at wavelength of 700 nm or more, whereas the cobalt ion is absorbed between the range of 400 to 500 nanometres.

Therefore, the student will use wavelength of 700 nanometers because copper is absorbed at this wavelength. The cobalt is absorbed at 400 to 500 nanometers, which will minimize its interference.

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Answer:

Check the explanation

Explanation:

The Grignard Reaction refers to the organomagnesium halide (also known as the Grignard reagent) addition to a ketone or aldehyde, just to create a secondary or tertiary alcohol, respectively. When there’s a reaction with the formaldehyde, it leads to a primary alcohol. It is a multipurpose material that can be utilized in creating new carbon–carbon bonds.

Kindly check the image below to see the structure of the organic product(s) of the Grignard reaction between dimethyl oxalate and excess methylmagnesium bromide.

The product of the reaction is a diol obtained by nucleophilic addition of methylmagnesium bromide to each ester group in dimethyl oxalate, followed by aqueous acid workup.

The organic product of the Grignard reaction between dimethyl oxalate and excess methylmagnesium bromide, followed by aqueous workup, is the diol resulting from the nucleophilic addition of the Grignard reagent to the carbonyl group of the ester. Each ester group in the dimethyl oxalate is replaced by a methyl group from methylmagnesium bromide. After acidic workup, the final product is a diol with two primary alcohol groups. The mechanism involves the formation of a magnesium alkoxide intermediate, which upon acid treatment, delivers the alcohol. To start, the Grignard reagent methylmagnesium bromide acts as a strong nucleophile, attacking the electrophilic carbonyl carbon of the first ester group, then similar addition occurs to the second ester group after another equivalent of the Grignard reagent. Finally, hydrolysis during the aqueous workup completes the reaction.

Answer:

Check Explanation

Explanation:

The Mathematical expression of the first law is given as

ΔU = Q - W

Note that depending on convention, the mathematical expression for the first law can be written as

ΔU = Q + W

a) Yes, the gas does work on its surroundings. Since it expands; indicating that there is a change in volume.

The work done is given as -PΔV if we are using the convention of (ΔU = Q + W). And this work is negative work done, since the system expands and does work on the surroundings.

But if we are using the convention of (ΔU = Q - W), the work done is given as PΔV and the workdone by the system on the environment is positive work during expansion.

b) Since this all takes place at constant temperature and against a constant atmospheric pressure, the change in internal energy for this system is 0. Change in internal energy depends on a change in temperature.

So, from the mathematical expression,

ΔU = Q + W or ΔU = Q - W

If ΔU = 0,

Q = - W or Q = W

But either ways,

Q = PΔV

(because, W = -PΔV for ΔU=Q+W and W = PΔV for ΔU=Q-W)

So, either ways, the heat transfer is the same and it is positive. This indicates heat is transferred from the surroundings to the system.

(c) What is ΔU for the gas for this process?

Since this all takes place at constant temperature and against a constant atmospheric pressure, the change in internal energy for this system is 0. Change in internal energy depends on a change in temperature.

Hope this Helps!!!

Based on the given question, we can state that Yes, the gas does work on its surroundings because it expands, this shows that there is a change in volume.

Based on the second question, we can state that because this takes place at constant temperature and against a constant atmospheric pressure, then the change in internal energy for this system is zero.

Based on the third question, we can see that the ΔU for the gas for this process is zero because of the constant temperature and atmospheric pressure.

This is given as

ΔU = Q - W

Hence, from the mathematical expression,

Regardless,

Q = PΔV

This means that the heat transfer remains the same and is positive

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The nucleus of an atom, comprised of protons and neutrons, contains most of the atom's mass. Despite its relatively minuscule size, it is much heavier than the electron cloud surrounding it, which occupies most of the atom's volume.

The statement that correctly describes the nucleus of an atom is: D. the nucleus of the atom contains most of the mass of an atom.

Modern atomic theory has shown us that the nucleus of an atom is made up of positively charged protons and uncharged neutrons, and overall, carries a positive charge. The nucleus is incredibly tiny, with its diameter being about 100,000 times smaller than the diameter of the atom. However, it contains almost all of the atom's mass as protons and neutrons are significantly heavier than electrons, thus making statement D accurate.

Electrons, on the other hand, occupy the majority of an atom's volume, constituting an 'electron cloud' around the nucleus. Because they are very lightweight, their specific locations can't be definitively pinpointed and are often represented as probabilities within this cloud. Hence, options A, B, and C are incorrect.

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Answer:

Motorcycle

Explanation:

The  law used to determine the relationship between the volume and the number of moles in this equation is called the Avogadro's law. by this law, the volume of gas is directly proportional to the number of moles of the gas.

Avogadro's law, which was proposed by the Italian scientist Amedeo Avogadro, explains the behavior of gases and states that gases of different chemical nature and physical conditions at the same temperature and pressure have an equal number of molecules in equal volumes.

In simpler terms, the number of molecules or moles in a gas sample is directly proportional to its volume at a constant temperature and pressure.

This law is significant in various areas of chemistry, including the calculation of chemical reactions involving gases, determination of molar volumes, and the study of ideal gases.

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Answer:

The volume of HCl required is [tex]V = 420 mL[/tex]

Explanation:

From the question we are told that

    The chemical equation for this reaction is

             [tex]2 Al _{(s)} + 6 HCl _{(aq)} -----> 2 Al Cl_{3} _{(aq)} + 3 H_2 _{(g)}[/tex]

    The mass of Al  is [tex]m__{Al}} = 2.00g[/tex]

    The concentration of HCl is [tex]C__{HCl}} = 0.500M[/tex]

The number of moles of [tex]Al[/tex] given is [tex]n__{Al}} = \frac{mass \ of Al}{Molar \ mass \ of \ Al}[/tex]

   The molar mass of Al is  [tex]M = 27 g/mol[/tex]

       So

               [tex]n__{Al} = \frac{2}{27}[/tex]

               [tex]n__{Al} = \ 0.07 \ moles[/tex]

From the balanced equation

           2 moles of  Al  reacts  with  6 moles of  HCl

So        0.07 moles of Al will react with x

  Therefore

                [tex]x = \frac{0.07 *6}{2}[/tex]

                [tex]x = 0.21 \ moles[/tex]

Now the volume of HCl can be obtained as

           [tex]Volume(V) = \frac{moles}{concentration }[/tex]

 So       [tex]V = \frac{0.21}{0.500}[/tex]

             [tex]V = 420 mL[/tex]

Explanation:

The only flaw I can find is you squared 3 instead of cubing it and it will be 27X^4 instead of 9x^4.

This reduces the amount slightly, but the number is still incredibly high (about 10 ^ 5 L is what I've calculated). Your professor might want to point out that this will not be a effective experiment due to the large volume of saturated

The Ksp value of Ca(OH)2 on the site (I used 5.5E-6 [a far more soluble compound than Al(OH)3]) and estimated how much of it will be needed. My calculation was approximately 30 ml. If you were using that much in the experiment, it implies so our estimates for Al(OH)3 are right, that the high amount is unreasonably big and that Al(OH)3 will not be a suitable replacement unless the procedure was modified slightly.

Answer:

The Phosphorylated  glucose(glucose +inorganic phosphate), with the energy supplied from ATP hydrolysis formed glucose 6- phosphate, which is later converted to 2 molecules of fructose 6-phosphate- this is phosphorylation.And  represented the fate of  glucose -6-phosphate.

The fructose 6-phosphate are converted to triose phosphate- which is a 2-molecules of 3C compound. The latter is oxidized by NAD→ NADH+ to form intermediates in the glycolytic pathways .

These intermediates are converted to ribose 5-phosphates in the presence of transketolase  and transaldolase enzymes.And they are finally   converted to pyruvate in the glycolytic pathway with the production of 2ATPs per molecule of glucose.

Basically the phosphate pathway reaction is very slow due to enzyme catalysis.

Final answer:

The formation of xenon compounds such as xenon difluoride is made possible due to the displacement of xenon's outer electrons, which can occur under certain conditions like high pressure and temperature.

Explanation:

The formation of compounds containing Xe is made possible by the fact that the outer electrons of the larger noble gases like Xe (xenon) are far enough away from the nucleus that they can be displaced under certain conditions. The noble gases were long thought to be entirely unreactive due to their filled outer electron shells, which provide a stable electronic configuration. Despite this, experiments in the early 1960s confirmed that noble gas compounds can indeed be synthesized, with xenon forming stable compounds with fluorine. For instance, xenon difluoride (XeF2), xenon tetrafluoride (XeF4), and xenon hexafluoride (XeF6) are all compounds that form when xenon reacts with varying amounts of fluorine, producing stable crystals that are inert at room temperature. These reactions typically require the noble gas to be exposed to high pressure and temperature conditions.

Answer:

Answer: Kp = 4.5

Explanation:

The balanced equation for the production of synthetic gas is

    CH4 +  H20 ⇒ CO + 3H2

Let x be the change in the concentration of each species at equilibrium

 CH4  +   H20   ⇔ CO  +  3H2

Initial                  0.60       2.6        0          0

Change               -x           -x          +x       +3x

Equilibrium      0.60-x      2.6-x       x        3x

Given that the equilibrium partial pressure of H2= 1.4 atm

then, 3x= 1.40

x= 1.4/3 = 0.466667

The equilibrium concentrations are

{CH4} = 0.60- x = 0.60 - 0.466667 = 0.133333atm

{H2O} = 2.60- x = 2.60 - 0.466667 = 2.133333atm

{CO} = x = 0.466667atm

{H2} = 1.4atm (given)

Kp  = {CO}{H2}³

        {CH4}{H2O}

Kp = (0.466667)(1.4)³

         (0.133333)(2.133333)

=  4.501875

Kp = 4.5