Given:
m= 50 g =0.05 Kg
Velocity= 70m/s
t=0.05 sec
acceleration= velocity/time
acceleration=70/0.05
acceleration= 1400 m/s∧2
Force= mass x acceleration
Force= 0.05 x 1400 =70 N
John and Caroline go out for a walk one day. This graph represents their distance from home.
Which statement accurately describes their walk?
A) They walked quickly, then they were still, then they walked slowly.
B) They walked forward fast, then they were still, then they walked backward slow.
C) They walked in one direction, then they were still, then they walked in the opposite direction.
D) They walked faster and faster until they walked at a constant rate, then they walked slower and slower.
Answer:
Option C is the correct answer.
Explanation:
We have velocity of a body = Change in position/ Time.
Considering first portion of graph,
Change in position = 30 - 0 = 30 m
Time = 0.75 hours = 45 minutes = 2700 seconds
Velocity = 30/2700 = 0.011 m/s
Considering second portion of graph,
Change in position = 30 - 30 = 0 m
Time = 0.5 hours = 30 minutes = 1800 seconds
Velocity = 0/1800 = 0 m/s
Considering third portion of graph,
Change in position = 0 - 30 = -30 m
Time = 0.75 hours = 45 minutes = 2700 seconds
Velocity = -30/2700 = -0.011 m/s
So firstly they walked in one direction(positive direction), then they were still(velocity is zero), then they walked in the opposite direction( velocity is negative).
Option C is the correct answer.
Answer:
I had this same question the answer is C 100% sure
Explanation:
You are sitting in a car in a parking lot. The person gets in the car beside you and begins to back out of the parking space. Why do you feel like you are moving forward, if only for a moment?
Dave rows a boat across a river at 4.0 m/s. the river flows at 6.0 m/s and is 360 m across.
a. in what direction, relative to the shore, does dave’s boat go?
b. how long does it take dave to cross the river?
c. how far downstream is dave’s landing point?
d. how long would it take dave to cross the river if there were no current?
a) Let's call x the direction parallel to the river and y the direction perpendicular to the river.
Dave's velocity of 4.0 m/s corresponds to the velocity along y (across the river), while 6.0 m/s corresponds to the velocity of the boat along x. Therefore, the drection of Dave's boat is given by:
[tex]\theta= arctan(\frac{v_y}{v_x})=arctan(\frac{4.0 m/s}{6.0 m/s})=arctan(0.67)=33.7^{\circ}[/tex]
relative to the direction of the river.
b) The distance Dave has to travel it S=360 m, along the y direction. Since the velocity along y is constant (4.0 m/s), this is a uniform motion, so the time taken to cross the river is given by
[tex]t=\frac{S_y}{v_y}=\frac{360 m}{4.0 m/s}=90 s[/tex]
c) The boat takes 90 s in total to cross the river. The displacement along the y-direction, during this time, is 360 m. The displacement along the x-direction is
[tex]S_x = v_x t =(6.0 m/s)(90 s)=540 m[/tex]
so, Dave's landing point is 540 m downstream.
d) If there were no current, Dave would still take 90 seconds to cross the river, because its velocity on the y-axis (4.0 m/s) does not change, so the problem would be solved exactly as done at point b).
Which is a future NASA research project? Check all that apply.
use a probe to collect data
improve aviation technology
conduct research from a space station
collect samples on an asteroid
conduct an unmanned space mission
Future NASA research projects include using probes to collect data, collecting samples on an asteroid, and conducting unmanned space missions.
Explanation:The future NASA research projects that apply to the given options in the question are:
Use a probe to collect data: NASA often sends probes to explore different celestial bodies in our solar system, such as planets, moons, and asteroids. Probes are equipped with various instruments to collect data and study the target in detail.Collect samples on an asteroid: NASA has plans to send a spacecraft to collect samples from an asteroid called Bennu as part of the OSIRIS-REx mission.Conduct an unmanned space mission: NASA conducts numerous unmanned space missions to study distant objects in the solar system, such as planets, comets, and asteroids.
What average braking force is required to stop a 1134-kg car traveling at a speed of 83 km/hr before it reaches a stop sign that is 98 m away?
Given:
m(mass of the car)=1134 Kg
u(Initial velocity)=83Km/HR=23m/s
s(distance traveled by the car)=98m
v(final velocity)=0(as it is given the car stops).
Now we know,
v=u+at
Where v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
0=23+at
at=-23
Also
s=ut+1/2(at^2)
s is the distance covered by the car
u is the initial velocity
t is the time necessary for the car to cover a particular distance.
a is the acceleration
Now substituting these values we get
98=23t-1/2(23t)
98=23t-11.5t
11.5t=98
t=8.52secs
Now we have already derived
at=-23
ax8.52=-23
a=-23/8.52
a=-2.75 m/s^2
F=mxa
Where F is the force acting on the car.
m is the mass of the car.
a is the acceleration.
F=1134 x-2.75
F=-3119N
List four conditions that may result in the emission of electrons from a conductor
There are 4 ways in which electrons are emitted from the conductor.
i. Thermionic emission
ii. Electric field electron emission
iii. Photoelectric emission
iv. Secondary emission
In thermionic emission large amount of external energy in the form of heat is supplied to release free electrons from the metal.
In electric field electron emission, electrons are emitted from the metal surface when the metals are placed in a very strong electric field.
During photoelectric emission, light is absorbed by the metals and this provides energy to the valence electrons which break their bond with the parent atom and which are then released from the atom.
Valence electrons do have some kinetic energy, but they don't have enough energy to escape from the atom. During secondary emission, a high-speed electron is bombarded with an atom, which provides the energy for the valence electrons to break their bonds with their parent atom which are then released from the atom.
Answer:
Conditions that result in the emission of electrons from a conductor:
Heating the conductor to a suitable temperature
Exposing the conductor to a strong light
Subjecting the conductor to a very high applied voltage
Subjecting the conductor to high-speed electrons from another source
Explanation:
The same physical quantity, such as density, can be reported using different units. Above, you found that water has a density of 1000kg/m3=1g/cm3 . Because the density of water must be the same regardless of what units you use to measure it, you can conclude that an object whose density is 1 kg/m3 must be less dense than water. In other words, 1 kg/m3 is less than 1 g/cm3 . If you had three different objects with densities of 1 kg/m3 , 1 g/m3 , and 1 kg/mm3 , which object would be the most dense? Rank the given densities from most to least dense. To rank items as equivalent, overlap them.
In the question there are three values of densities.
We are asked to arrange these values in descending order.
In order to solve this problem first we have to convert each values into same unit.Let the unit chosen to be gram per cubic centimeter.
The first value is 1000 kg per cubic metre.
we know that 1 kg=1000 kg and and 1 m=100 cm
Hence the value in CGS system will be-
[tex]1 kg/m^3 =\frac{10^3 gram}{[10^2cm]^3}[/tex]
[tex]=10^-3\ g/cm^3[/tex]
The second value is 1 gram per cubic centimetre.
Third value is 1 kg per cubic millimeter.
we know that
[tex]1 mm =10^-1 cm[/tex]
Hence 1 kg per cubic millimeter i.e
[tex]1 kg/mm^3[/tex]
[tex]=\frac{10^3 gram}{[10^-1cm]^3}[/tex]
[tex]=10^6 g/cm^3[/tex]
Hence the perfect order will be-
[tex]10^6 g/cm^3[/tex] >[tex]1 g/cm^3[/tex] > [tex]10^-3\ g/cm^3[/tex]
[tex]i.e\ 1 kg/mm^3>1\ g/cm^3>1 kg/m^3[/tex]
Answer:
1 kg/mm³, 1 kg/m³, 1 g/m³
Explanation:
We have 3 objects of different densities, 1 kg/m³, 1 g/m³, and 1 kg/mm³.
In order to compare their densities, we will express all of them in the same units, for instance, kg/m³.
First object
It has a density of 1 kg/m³.
Second object
We know that 1 kg = 10³ g. Then,
1 g/m³ × (1 kg/10³ g) = 10⁻³ kg/m³
Third object
We know that 1 m = 10³ mm. Then,
1 kg/mm³ × (10³ mm/1 m)³ = 10⁹ kg/mm³
The densities, from most to least dense are:
1 kg/mm³, 1 kg/m³, 1 g/m³
Use conservation of energy arguments to find the speed of the ball when it reaches the top of the circular path about the peg. your answer should be expressed in terms of l, g and
d.
Final answer:
Conservation of energy dictates that the speed of the ball at the top of the circular path decreases as its kinetic energy is converted to potential energy. The final speed can be calculated using the formula v = √(2gh).
Explanation:
Conservation of energy states that the total energy of a system remains constant. In the case of the ball on a string winding around a post, as the ball reaches the top, its kinetic energy will be converted to potential energy, resulting in a decreased speed.
To find the speed of the ball at the top of the circular path, we can set the initial kinetic energy equal to the final potential energy. This can be expressed as:
[tex]1/2 mv^2 = mgh[/tex], where 'v' is the final speed, 'm' is the mass of the ball, 'h' is the height above the peg, and 'g' is the acceleration due to gravity.
Therefore, the speed of the ball at the top of the circular path is v = √(2gh), where 'g' is the acceleration due to gravity and 'h' is the height of the circular path above the peg.
This term means pertaining to or exist at or from the very beginning.
A. Primordial
B. Accretion
C. By-product
D. Homogeneous
the time of a collision experienced by a driver is 0.1 seconds without an air bag, with an air bag this is increased to 0.5 seconds. Explain the benefits of this detail
With the air bag deployed, the driver has 5 times longer to decelerate and lessen her/his impact and risk of injury.
An object is represented by the dot on the motion map. Which object is most likely represented by the dot?
A. a car driving over the top of a hill
B. a ball on a string that stopped at the top of a vertical loop
C. a roller coaster car at the top of a vertical loop of track
D. a bug on the top of a rolling hula hoop
Answer:
B on edge
Explanation:
if energy is conserved, why do people get tired , and why are we running short on “energy supplies?”
an astronaut has a mass of 100 kg and has a weight of 370N on Mars. what is the gravitational strength on Mars?
Weight of the object on surface of any planet is given as the gravitational pull on the object due to planet
This gravitational pull is defined as formula below
[tex]F = mg[/tex]
m = mass of object
g = acceleration due to gravity of the planet
now here it is given that weight on the planet is 370 N which is defined as the force due to planet
Also the mass is given as 100 kg
now using the formula above
[tex]370 = 100 * g[/tex]
[tex]g = \frac{370}{100}[/tex]
[tex]g = 3.7 m/s^2[/tex]
so the gravitational strength of the mars will be 3.7 m/s^2
Answer:
The gravitational strength of the mars will be 3.7 m/s^2
Explanation:
how can you tell, as you walk close to a parked car, if it had been running recently? describe your reasoning in terms of energy flows.
Final answer:
The presence of heat, steam, and condensation, as well as feeling or hearing the engine cooling down, can indicate if a parked car had been running recently.
Explanation:
When walking close to a parked car, you can tell if it has been recently running by paying attention to energy flows. If the engine was running recently, you may be able to feel the heat radiating from the hood or hear the engine cooling down. Another clue is the presence of steam or condensation from the exhaust pipe, indicating that the engine has been producing heat and burning fuel. These signs indicate that the car was using stored chemical energy in the form of gasoline, converting it into mechanical energy to power the engine and produce heat.
why is it important to select a coordinate system when studying motion?
Motion is detected when an object changes its position with respect to a reference point. Coordinate system is basically used to represent motion. A coordinate system uses numbers or coordinates which represent position of the reference points on a two-dimensional or three-dimensional space. The trajectory of a point or line can be studied on a coordinate system which describes various aspects of motion like velocity, acceleration, distance, displacement etc. Coordinate system is important because it helps to choose a starting point and the direction (which will be positive).
An 80-kg fireman slides 5.0m down a fire pole. He holds the pole, which exerts a 500-N steady resistive force on thr fireman. At the bottom he slows to a stop in 0.40m by bending his knees. What can you determine using thos information?
Quite a few things can be determined using this information.
(i) First, we can calculate the Weight of the fireman using W = mg.
We get its magnitude as W = (80)(9.8) = 784 N
(ii) While his Weight is responsible for pulling him down, the pole exerts a constant Resistive Force that is given to be 500 N.
We can calculate the Net Force acting on the fireman as
[tex]F_{net} = W - Resistive Force[/tex]
We get its numerical value to be [tex]F_{net} = 284N[/tex]
(iii) Using this, we can calculate the acceleration with which he slides down the pole from Newton's 2nd law equation as
[tex]F_{net} =ma[/tex]
Therefore, [tex]a = \frac{284}{80} =3.55 m/s^{2}[/tex]
(iv) With this acceleration, he slides down a distance of 5.0 m - 0.4 m = 4.6 m before he starts applying an additional force with his knees.
We can calculate the velocity he attains just before bending his knees using the following data:
Initial Velocity at the top of the pole [tex]V_{i} =0[/tex]
Vertical displacement down the pole D = 4.6 m
Acceleration [tex]a = 3.55 m/s^{2}[/tex]
Final Velocity [tex]V_{f} = ?[/tex]
Using the equation [tex]V^{2} _{f} =V^{2} _{i} +2aD[/tex]
Plugging in the numbers, we have [tex]V^{2} _{f} =0+2(3.55)(4.6)[/tex]
Thus, we get the value of [tex]V_{f}[/tex] as 5.72 m/s
(v) This velocity serves as the initial velocity for the part of the journey with his knees bent.
We can calculate the acceleration he has using the following data:
Initial Velocity [tex]V_{i}=5.72[/tex] m/s
Final Velocity [tex]V_{f} =0[/tex]
Displacement during the last part of the journey D = 0.4 m
Acceleration a = ?
Again using the equation [tex]V^{2} _{f} =V^{2} _{i} +2aD[/tex], and plugging in the known numbers, we get
[tex](0)^{2} =(5.72)^{2} +2(a)(0.4)[/tex]
Hence, [tex]a=-40.898 m/s^{2}[/tex]
(vi) We can calculate the Net Force acting on him during this part of the journey as
[tex]F_{net} =(80)(-40.898)=-3271.84N[/tex]
(vii) Since the Net Force is the vector sum of Weight, Resistive Force, and the additional Knee Force, we can write them as
[tex]W-Resistive Force-Knee Force=-3271.84N[/tex]
Solving for Knee Force gives its magnitude to be 3555.84 N.
Thus, the fireman begins applying an additional 3,556 N force to stop himself in 0.4 m.
(viii) We can even calculate the time taken for the entire journey. We will deal with it in two parts.
For part one, the following information can be used:
Initial Velocity [tex]V_{i} =0[/tex]
Final Velocity [tex]V_{f} =5.72m/s[/tex]
Acceleration [tex]a = 3.55m/s^{2}[/tex]
Time taken t = ?
Using the equation [tex]V_{f} =V_{i} +at[/tex], we get the time taken as 1.6 seconds.
For the second part of the journey, the following information can be used:
Initial Velocity [tex]V_{i} =5.72m/s[/tex]
Final Velocity [tex]V_{f} =0[/tex]
Acceleration [tex]a=-40.898m/s^{2}[/tex]
Time taken t = ?
Using the equation [tex]V_{f} =V_{i} +at[/tex] again, and plugging in the appropriate values, we get the time taken as 0.14 seconds.
Hence, the total time the fireman took to slide down the 5.0 m pole is 1.74 seconds.
Hope this helps!
The calculation using the physics concept of work and energy determines the work done by a fireman when he slides down and stops, and quantifies the force he exerts when slowing to a stop.
Explanation:This is a classic problem in physics, specifically in the area of kinetic energy and work-energy theorem. First, as the fireman slides down, he is doing work and transforming potential energy into kinetic energy. We can calculate this work using the equation work = force x distance. In this case, the force is the resistive force of 500N, and the distance is 5.0m. So the work done is 500N x 5.0m = 2500J.
Next, when he bends his knees to slow to a stop, he is doing another amount of work to remove this kinetic energy. We can use the same formula as before, but this time the distance is 0.40m. We won't know the force directly, but we know the work done needs to be equal to the kinetic energy obtained earlier. So, we can solve for the 'force': 2500J = force x 0.40m, thus the force exerted would be around 6250N.
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Both prokaryotes and eukaryote cells have this structure. It helps maintain homeostasis ant is a boundary between the inside of the cell and the outside environment. It is the
IT's cell membrane because it maintains homeostasis by controlling what enters the cell and what exits it.
Which of these chemical compounds is generated during the process of cellular respiration
Cellular respiration is of two types namely aerobic and anaerobic respiration.
During aerobic respiration,the food(glucose) is broken down in the mitochondria to produce ATP,water and CO2.This is carried out in 3 steps glycolysis followed by Tricarboxylic acid cycle and electron transport chain.
During anaerobic respiration, glucose is broken down in the absence of oxygen to produce ethanol,CO2 and water. Anaerobic respiration occurs in the cytoplasm.
A ball is thrown straight up in the air. When will its kinetic energy be the smallest before it is caught? at the start of its flight halfway to the top of its flight at the top of its flight at the end of its flight
Answer: At the top of its flight.
At the top of the flight,the height from the ground is maximum. Owing to this position the potential energy attained here is the maximum.
Also potential energy = mgh
Where m is the mass of the object.
g is the acceleration due to gravity
h is the height of object.
From this equation we can conclude that at the top,the maximum height would be attained and hence it would possess maximum potential energy.
Also at the top the object will possess zero velocity.
Kinetic energy = 1/2 (mv^2).
Where m is the mass of the object
v is the velocity of the object.
Hence at the top, since the velocity of the object is zero,the kinetic energy would be zero as explained in the below equation.
Kinetic energy= 1/2(m x 0)
Kinetic energy = 0.
Thus at the top of the flight,the ball possess only potential energy and minimum (0) kinetic energy.
Sam is riding his bike in the park when he sees a soccer ball rolling toward him. He applies his brakes to slow down. Once he stops, he notices that the tires on his bike became warmer after he applied the brakes. Why did the tires on Sam's bike become warmer as he applies the brakes on his bike?
When Sam applies the brakes on his bike, the friction between the brake pads and the tires converts the kinetic energy of the moving bike into heat energy, causing the tires to become warmer.
Explanation:When Sam applies the brakes on his bike, it creates friction between the brake pads and the tires. This friction converts the kinetic energy of the moving bike into heat energy, causing the tires to become warmer. This is similar to how car brakes work - they use friction to reduce speed and convert motion energy into heat energy, which is why the brakes can become hot after stopping.
The cause and effect of breaking a egg
Hold up raw egg and say “CAUSE” as you crack the egg on the side of the bowl.
2. Say “EFFECT” as you break open the egg into the bowl.
3. Hold up the hardboiled egg and say “CAUSE” as you go through exaggerated motions of tossing the egg to a student.
4. As they either catch it or drop it, say “EFFECT”.
Corbin, an avid skier leaves the horizontal end of a ramp with a velocity of 33.0 m/s and lands 63.0 m from the base the ramp. How high is the end of the ramp from the ground?
Answer:
Height of ramp = 17.49 m
Explanation:
We have equation of motion , [tex]s= ut+\frac{1}{2} at^2[/tex], s is the displacement, u is the initial velocity, a is the acceleration and t is the time.
Considering horizontal motion of skier
Initial velocity = 33 m/s, Displacement = 63 m, acceleration = 0 and we need to find time taken to reach ground by the skier.
[tex]63= 33t+\frac{1}{2} *0*t^2\\ \\ t=1.909seconds[/tex]
The vertical distance traveled in 1.909 seconds is the height of ramp
Initial velocity = 0 m/s, acceleration = acceleration due to gravity = 9.8 [tex]m/s^2[/tex], time = 1.909 s and we need to find displacement.
[tex]s= 0*1.909+\frac{1}{2} *9.8*1.909^2\\ \\ s=17.49 m[/tex]
So height of ramp = 17.49 m
How much would a 150 g apple weigh if it were on the moon
The weight will be 1/6 time less on the moon than earth.
ExplantionThe varies the size of the object the effects the of gravitational pull will vary. As the moon is smaller than the size of the earth, then it has less gravitational pull. The value of gravity is [tex]9.8 ms^{-2}[/tex]on the earth but in the moon, it will reduce 1/6 times and will be [tex]1.62ms^{-2}[/tex]. The weight change by change the planet but mass remain same. In the given question the weight is 150g. So,
[tex]W = m * g[/tex]
at earth[tex]g = 9.8ms^{-2}[/tex]
by rearranging
[tex]m= W/g[/tex]
[tex]m = 150/9.8[/tex]
[tex]m = 15.3 g[/tex]
On moon [tex]g = 1.62 ms{^-2}[/tex]
[tex]m = 150/1.62[/tex]
[tex]m = 92.6 g[/tex]
The change in mass was because of gravitational pull
a water wave squeezing through a small hole is an example of
Answer;
Diffraction
Explanation;
Diffraction involves a change in direction of waves as they pass through an opening or around a barrier in their path. Water waves have the ability to travel around corners, around obstacles and through openings. This ability is most obvious for water waves with longer wavelengths.
Diffraction of water waves is observed in a harbor as waves bend around small boats and are found to disturb the water behind them. The same waves however are unable to diffract around larger boats since their wavelength is smaller than the boat.
Your forehead can withstand a force of about 6.0 kn before fracturing, while your cheekbone can withstand only about 1.3 kn. suppose a 140 g baseball traveling at 30 m/s strikes your head and stops in 1.5 ms.
a. what is the magnitude of the force that stops the baseball?
b. what force does the baseball exert on your head? explain.
c. are you in danger of a fracture if the ball hits you in the fore- head? on the cheek?
a) The change in momentum of the ball is given by:
[tex]\Delta p = m \Delta v[/tex]
where m=140 g=0.14 kg is the mass of the ball, and [tex]\Delta v =30 m/s[/tex] is the change in velocity. Substituting, we find
[tex]\Delta p=(0.14 kg)(30 m/s)=4.2 kg m/s[/tex]
The ball stops in t=1.5 ms=0.0015 s; the magnitude of the force that stops the baseball is given by the ratio between the change in momentum and the time taken:
[tex]F=\frac{\Delta p}{t}=\frac{4.2 kg m/s}{0.0015 s}=2800 N=2.8 kN[/tex]
b) The force we found at point a) is the force that the head exerts on the ball to stop it. However, Newton's third law states that when an object A exerts a force on an object B, object B also exerts a force equal and opposite on object A. If we apply this law to this case, we understand that the force exerted by the baseball on the head is equal to the force exerted by the head on the ball: therefore, the answer is still 2.8 kN.
c) The forehead is not in danger of a fracture, since it can withstand a maximum force of 6.0 kN, while the ball exerts a force of 2.8 kN. Instead, the cheek is in danger of fracture, because it can withstand only a maximum force of 1.3 kN.
What will the stopping distance be for a 2,000-kg car if -2,000 N of force are applied when the car is traveling 20 m/s?
A. 400,000 m
B. 200 m
C. 100 m
D. 20 m
Answer is B- 200 m
Given:
m (mass of the car) = 2000 Kg
F = -2000 N
u(initial velocity)= 20 m/s.
v(final velocity)= 0.
Now we know that
F= ma
Where F is the force exerted on the object
m is the mass of the object
a is the acceleration of the object
Substituting the given values
-2000 = 2000 × a
a = -1 m/s∧2
Consider the equation
v=u +at
where v is the initial velocity
u is the initial velocity
a is the acceleration
t is the time
0= 20 -t
t=20 secs
s = ut +1/2(at∧2)
where s is the displacement of the object
u is the initial velocity
t is the time
v is the final velocity
a is the acceleration
s= 20 ×20 +(-1×20×20)/2
s= 200 m
Answer:
Stopping distance, s = 200 meters
Explanation:
Mass of the car, m = 2000 kg
Force acting in the car, F = -2000 N
Initial speed of car, u = 20 m/s
Finally, it stops, v = 0
Using second equation of motion as :
[tex]F=ma[/tex]
[tex]a=\dfrac{F}{m}[/tex]
[tex]a=\dfrac{-2000}{2000}[/tex]
[tex]a=-1\ m/s^2[/tex]
Let s is the stopping distance. Now using third equation of motion as :
[tex]s=\dfrac{v^2-u^2}{2a}[/tex]
[tex]s=\dfrac{0-(20)^2}{2\times -1}[/tex]
s = 200 meters
So, the stopping distance of the car is 200 meters. Hence, this is the required solution.
Grinding wheat in to flour is a a. physical change b. chemical change Please select the best answer from the choices provided
It is a physical change. One is physically change the wheat from one form to the other.
Which statement is true for both types of transistors?
Current flows from the collector to the emitter.
Current flows from the base to the emitter.
The base is between the collector and the emitter.
The base is a p-type semiconductor.
For both NPN and PNP this is true:
The base is between the collector and the emitter.
In the transistors, the base is between the collector and emitter.
Option C is the correct answer.
The Transistor has two types, they are NPN transistor and PNP transistor.
What are the characteristics of transistors?Both NPN and PNP transistor are bipolar transistor. In the NPN transistor, base will be the P-type semiconductor, emitter and collector will be the N- type semiconductor where as in the PNP transistor, base will be the N- type semiconductor, emitter and collector will be the P -type semiconductor. The circuit diagram of both the transistor will be attached as a image. The current flow in both the transistor will be collector to emitter and emitter to collector.
So that, the base is between the collector and emitter is the true statement in the given options.
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As a pendulum swings, the amounts of potential and kinetic energy change. Does the amount of mechanical energy change?
No, the mechanical energy does not change if it is ideal.
We define mechanical energy as the sum of kinetic energy and potential energy
ME = PE + KE
When the pendulum swings, potential energy is converted to kinetic energy and vise versa. But the sum of both remains constant, which is the mechanical energy.
The given vector represents a hot air balloon that experiences a 0.25m/s^2 up and 0.25 m/s^2 to the right at 45 degrees. Find the magnitude of the resultant
when two vectors are inclined at some angle to each other then the magnitude of resultant of two vectors is given as
[tex]R = \sqrt{A^2 + B^2 + 2AB cos\theta}[/tex]
here A and B are the magnitude of two vectors and theta is the angle between them
now here we know that two vectors are of magnitude 0.25 m/s^2 each and they are inclined at angle of 45 degree
now we will plug in all data above
A = B = 0.25
[tex]\theta = 45[/tex]
[tex]a_{net} = \sqrt{0.25^2 + 0.25^2 + 2*(0.25)(0.25)cos45}[/tex]
[tex]a_{net} = 0.46 m/s^2[/tex]
So the magnitude of resultant acceleration will be 0.46 m/s^2
The magnitude of the resultant is 0.354 m/s^2.
Explanation:The magnitude of the resultant can be found using the Pythagorean theorem. Since the balloon experiences an upward acceleration of 0.25 m/s^2 and a rightward acceleration of 0.25 m/s^2 at 45 degrees, we can find the magnitude of the resultant using:
R = sqrt((0.25)^2 + (0.25)^2) = 0.354 m/s^2.
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