A golf instructor ordered 21 cartons of golf balls. Each carton contained 15 golf balls. And equal number of golf balls were given to each of his six classes and the rest were put in his golf bag. How many golf balls to the instructor put in his golf bag?

Answers

Answer 1

10 1/2 golf balls to get it




Related Questions

The minimum of a parabola is located at (-1,-3). the point (0,1) is also on the graph. which equation can be solved to determine the a value in the function representing the parabola?

Answers

Answer:

The equation that can be used to solve for a is 1 = a(0=1)²-3.

Explanation:

In this case, I would model the parabola in vertex form.  Vertex form is y = a(x-h)²+k, where (h,k) is the vertex of the parabola.  Using the information from the question, we can plug in values to get 1 = a(0+1)²-3.  (This could be simplified as 1 = a(1)²-3 ⇒ 1 = a-3 ⇒ a = 4, but we are only interested in finding the equation that can solve for a.)

Answer:

The correct answer is A, 1 = a(0 + 1)^2 – 3

Step-by-step explanation:

The verified guy made a typo, putting = instead of + :P

please help with7 thru 12

Answers



below #7 is #9 ans below it is #11

A bucket holds c liters of water, but a jar holds d liters more. How much water do they hold together?

Answers

2c+d

c+d=jar
c=bucked

combine
2c+d
Final answer:

The total volume of water that the bucket and jar hold together is found by adding the liters the bucket holds (c) and the liters the jar holds more than the bucket (d). Therefore, the expression for total volume is c + d.

Explanation:

The subject of the question is simple addition in Mathematics. To solve this, we need to add the liters of water the bucket holds (represented by c) and the liters of water the jar holds (represented by d liters more than the bucket). On this basis, the equation is as follows: total liters = c + (c + d).

However, as the question states that the jar holds d liters more than the bucket, not that it holds d liters more than the total amount in the bucket, the correct equation to find out the total volume of water in both the bucket and the jar together is: total liters = c + d.

So, if the bucket holds 5 liters of water (c=5) and the jar holds 2 liters more (d=2), then together, they hold 5 + 2 = 7 liters of water.

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Terence owes $5.00 to his mother and his father. Write the integer problem and determine the total amount he owes his parents. (50 PTS SUPER EASY)

Answers

he owes a total sum of 10 dollars.

$5 + $5 = $10

Terence owes both his parents a total of $10

Hope this helps you

-AaronWiseIsBae

please help.......... with number 1

Answers

I don't like algebra masquerading as geometry.  Algebra and geometry are connected in interesting ways, but this is boring.

It just says the two little angles add to the big angle,

(2x + 6) + (10x - 5) = 73

Solving,

12x + 1 = 73

12x = 72

x = 6

SQR = 2x+6 = 18 degrees

PQR = 10x -5 = 55 degrees


a team played 42 games and won 5/14 of them. how many games were lost?

Answers

27 games were lost

fraction of games lost = 1 - [tex]\frac{5}{14}[/tex] = [tex]\frac{14}{14}[/tex] - [tex]\frac{5}{14}[/tex] = [tex]\frac{9}{14}[/tex]

number of games lost = [tex]\frac{9}{14}[/tex] of 42

                                     = [tex]\frac{9}{14}[/tex]× 42 = 27


Final answer:

The team played 42 games and won 5/14 of them, which equals 15 games. Subtracting the number of games won from the total number of games played gives the total number of games lost, which is 27.

Explanation:

The team played 42 games and won 5/14 of them. To find out how many games were lost, we first have to find out how many they won. 5/14 of 42 games is 15 games. So, they won 15 games. Now, to find out how many games were lost, we need to subtract the number of games won (15 games) from the total number of games played (42 games). Therefore, 42 games - 15 games = 27 games. So, the team lost 27 games.

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Solve the formula for the specified variable
N=(1/6)rm what is r

Answers

N=(1/6)rm

Solve for r

[tex]N = \frac{1}{6} rm[/tex]

[tex]N = \frac{1}{6}*r*m[/tex]

To remove the fraction 1/6, we multiply both side by reciprocal 6/1

[tex]N\frac{6}{1}= \frac{1}{6}*r*m\frac{6}{1}[/tex]

6N = rm

Now divide by m on both sides

[tex]\frac{6N}{m}= \frac{r}{m}[/tex]

[tex]\frac{6N}{m}= r[/tex]

We solved for r

[tex]r = \frac{6N}{m}[/tex]


Answer:

r = [tex]\frac{6N}{m}[/tex]

Step-by-step explanation:

Given an equation in terms of N on the left side and r, m variables on the right side.

Instead of N on left side we have to bring r on left side alone and other terms on right side to get formula for r.

For this multiply the given equation first by 6.

6N = rm

Now divide by m

r = [tex]\frac{6N}{m}[/tex]

This is the formula for r in terms of N, m.


Locating Zeros of Polynomial Function:
Describe how you find an upper bound and a lower bound for the zeros of a polynomial function

Answers

The value p is an upper bound on the real roots of the polynomial if division of the polynomial by (x-p) results in quotient terms that all have positive coefficients.

The value q is a lower bound on the real roots of the polynomial if division of the polynomial by (x-q) results in quotient terms that alternate signs.

_____

The division can be either synthetic division or long division.

_____ ______

An upper bound on the magnitude of the roots can be found this way:

Divide all coefficients by that of the highest-degree termFind the absolute value of the resultChoose the maximum of those results and increase it by 1

There are various refinements, including finding the sum of the ratios of successive coefficients, or taking increasing roots of the ratios found above, then doubling the maximum of those.

Use synthetic division to find the values of the polynomial function for consecutive integers. An integer that produces no sign change in the quotient and the remainder is an upper bound. To find a lower bound of a function, find an upper bound for the function of -x. The lower bound is the negative of the upper bound for the function of -x.

That is the right answer as I just finished the 10 practice problems on E2020

In a usually right-angled (x, y, z)-coordinate system, three planes are given by the following system of linear equations:

[tex]\alpha_1: x-y+(a-1)z=a\\\alpha_2: x+(a-1)y=0 \\\alpha_3: ax+ay+(a-1)z=0[/tex]
a ∈ R

a) Solve the equation system for [tex]a=2[/tex]

b) Find the value of [tex]a[/tex] for which the three planes intersection is a straight line and specify a parametric equation for the line.

c) Find the value of [tex]a[/tex] for which the three plans have no common point.

d) Is there a value of [tex]a[/tex] for which the three plans have the common intersection [tex](1, -\frac{1}{69}, \frac{4624}{4761})[/tex]?

Please, explain how you found the solutions :-)

Extra:
e) Illustrate questions a) and b) with Maple software.
Hint: The [tex]implicitplot3d[/tex] command can sure to be helpful. Also note that the argument [tex]orientation[/tex] can lock your plot in a favorable position for inspection.

Answers

Answer:

a) (x, y, z) = (1, -1, 0)

b) a = 0; L = {t, t, 0}

c) a = 1 . . or . . a = 3

d) No

Step-by-step explanation:

a) The solution using row-reduction techniques is shown in the first attachment, part (a). The generic solution is shown evaluated for a=2, the result being (1, -1, 0).

You will note that the solution gives indeterminate values for a=1 and a=3, which make the denominators zero.

b) For this, we use the point solution of part (a) together with the cross product of the normal vectors of planes 1 and 2. Said cross product will be in the direction of their line of intersection. We substitute the parametric equation for that line into the equation for plane 3 and solve for a. The result is a = 0.

The simplification of the resulting equation also gives a=1 and a=3, but we treat those as extraneous solutions because the corresponding common point of intersection of the planes does not exist.

c) The values a = 1 and a = 3 were found in part (a). These are values of a that make the common point indeterminate.

d) Substituting the given values for (x, y, z) gives three equations for a that have 3 different solutions. Hence there cannot be a value of a that makes this be a common point of intersection.

e) The second attachment illustrates part (a), with a=2. The third attachment illustrates part (b) with a=0.

The fourth attachment illustrates part (c). The first picture has the triangular tunnel between the planes in a vertical orientation (a=1). The second picture has the triangular tunnel extending from lower front to upper back (a=3).

11.57-n=7.51 write the unknown number for n

Answers

it is true and stands for 4.06

n = 4.06

isolate the term in n by subtracting 11.57 from both sides of the equation

- n = 7.51 - 11.57 = - 4.06

multiply both sides by - 1

n = 4.06


Help asap will mark as brainlyst

Answers

d because 0.7 is larger than 0.007

C is the correct answer because just because 0.007 has bigger and more numbers doesn’t mean it’s bigger than the other numbers,it’s just adding zeros .

4- is there any price for which there are. I data

5-

Answers

4. There are no data for prices other than integer values in the range $11 to $16. For example, there is no data for a price of $11.50, or for a price of $17.

5. insufficient information

Jennifer is making costumes for the school play she has 70 M of Ribbon if she beeds 54 percent of the ribbon for the costumes. how much ribbon does she need Will mark brainiest show your work

Answers

70 m * .54=37.8 METERS

She needs 37.8, how I got my answer.

I simply found that 54% of 70 equals 37.8.

I hope this helps!

1 .Which statement correctly describes the relationship between the graph of f(x)=2x
and the graph of g(x)=f(x)−4 ?

A. The graph of g(x) is the graph of ​ f(x)​ translated 4 units right.

B. The graph of g(x) is the graph of f(x) translated 4 units left.

C. The graph of g(x) is the graph of ​​ f(x)​ translated 4 units up.

D. The graph of g(x) is the graph of​​ ​ f(x) ​ translated 4 units down.




2. Which statement correctly describes the relationship between the graph of f(x) and g(x)=f(x−7) ?


A. The graph of g(x) is the graph of ​f(x)​ translated 7 units down.

B. The graph of g(x) is the graph of ​f(x)​ translated 7 units left.

C. The graph of g(x) is the graph of ​f(x)​ translated 7 units right.

D. The graph of g(x) is the graph of ​f(x)​ translated 7 units up.




3. The graph of g(x) is the graph of f(x)=x+6 reflected across the x-axis.

Which equation describes the function g?

A. g(x)=−x−6

B. g(x)=x−6

C. g(x)=−x+6

D. g(x)=−6x−6

4. The graph of g(x) ​​is the graph of f(x)=12x+6 compressed vertically by a factor of ​
1/3 ​ .

Which equation describes the function g?

A. g(x)=4x+2

​ B. g(x)=4x+6 ​

C. ​ g(x)=12x+2 ​

D. ​ g(x)=36x+6 ​



5. Which series of transformations take the graph of f(x)=2x+3 to the graph of g(x)=−2x+4 ?

A. reflect the graph about the y-axis and translate 1 unit up

B. reflect the graph about the y-axis and translate 1 unit down

C. reflect the graph about the x-axis and translate 1 unit up

D. reflect the graph about the x-axis and translate 1 unit down

Answers

D

the graph of g(x) is the graph of f(x) translated 4 units down


I looked at them and i'm not sure its d but you should try d.

A ball rolling down a hill was displaced 19.6 m while uniformly accelerating from the rest. If the final velocity was 5.00m/s, what was rate of acceleration?

Answers

we are given

A ball rolling down a hill was displaced 19.6 m

so,

[tex]h=19.6m[/tex]

the final velocity was 5.00m/s

so, [tex]v=5m/s[/tex]

Since, a ball rolling down a hill was displaced

so, we get

[tex]u=0m/s[/tex]

we can use kinematic equation formula

[tex]v^2-u^2=2ah[/tex]

Here ,

v is final velocity

u is initial velocity

a is acceleration

h is height from which ball is dropped

now, we can plug our values

[tex]5^2-0^2=2a(19.6)[/tex]

[tex]2a\left(19.6\right)=5^2[/tex]

[tex]2a\left(19.6\right)=25[/tex]

[tex]a=0.63776m/s^2[/tex]................Answer

Using the equation of Motion, the rate of acceleration of the ball is 0.638 m/s²

Using the 2nd equation of Motion :

Height, h = 19.6 meters Final velocity, v = 5 m/sInitial Velocity, u = 0

v² = u² - 2gh (downward motion)

5² = 0 - 2(19.6)a

25 = 0 - 39.2a

39.2a = 25

a = 25/39.2

a = 0.638 m/s²

Therefore, the rate of acceleration is 0.638 m/

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What is the solution of sqrt x+12=x ? x = –3 x = 4 x = –3 or x = 4 no solution

Answers

x = 4 is the solution

given [tex]\sqrt{x+12}[/tex] = x ( square both sides )

x + 12 = x² ( rearrange into standard form )

x² - x - 12 = 0 ← in standard form

(x - 4 )(x + 3 ) = 0 ← in factored form

equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x + 3 = 0 ⇒ x = - 3

substitute these values into the original equation and if both sides are equal then they are the solutions

x = 4 : [tex]\sqrt{4+12}[/tex] = [tex]\sqrt{16}[/tex] = 4 = x ← correct

x = - 3 : [tex]\sqrt{-3+12}[/tex] = [tex]\sqrt{9}[/tex] = 3 ≠ - 3 ← false

the solution is x = 4


Answer: x= 4

Step-by-step explanation:

Which is a translation of the shaded figure?

A.) D


B.) A


C.) B


D.) C

Answers

The answer is D. because they are the same shape and have the same dimensions.

The solution is Option A.) D

What is Translation?

A translation moves a shape up, down, or from side to side, but it has no effect on its appearance. A transformation is an example of translation. A transformation is a method of changing a shape's size or position. Every point in the shape is translated in the same direction by the same amount.

Given data ,

From the given figure , we can see that only figure represents the same exact figure as per the pre-image

Now , a translation moves a figure only up , down or from side to side

The figure in the image is only translated by a scale factor and no other changes are happening or no other transformations occur.

So , it is clear from the options that the image D is the only possible outcome where a translation of the shaded figure takes place.

Hence , the solution is figure D

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Write a word problem for this inequality
72-12a<24

Answers

Think of absolute value and inverse operation, +72 to 72 and 24

Part 1: Create an equation of a line in point-slope form. Be sure to identify all parts of the equation before writing the equation.
Part 2: Using the equation of the line you wrote in part 1, write an equation of a line that is perpendicular to this line.

Answers

Answer with explanation:

Part--1:

We know that a equation in point-slope form is represented by:

               [tex]y-y_1=m(x-x_1)[/tex]

where m is the slope of the line and [tex](x_,y_1)[/tex] is a point through which the line passes.  

  Consider a equation in a point-slope form as:

           [tex]y-5=2(x-1)[/tex]

This means that the slope of the line is: 5

and the line  passes through the point (1,5).

Part--2:

Now as we know that if a line has a slope as m then the perpendicular line has a slope: -1/m

Since,

[tex]m\times \text{Slope\ of\ second\ line}=-1\\\\i.e.\\\\\text{Slope\ of\ second\ line}=\dfrac{-1}{m}[/tex]

Let this perpendicular line passes through (2,6)

Hence, the equation of a line in point slope form is given by:

             [tex]y-6=\dfrac{-1}{2}(x-2)[/tex]

Answer:

Equation:

y-y1=m(x-x1)

y-2=4(x-1)

Part 2:

y=-1/4x +b

Step-by-step explanation:

please answer i dont understand

Answers

Remark

On the right, the deposits will build up and the river will have trouble depositing more material and still follow the path it is on. Eventually the river will want to take a short cut across the narrowest part or the neck.

Usually during flooding the water will cut across the narrowest part and an oxbow lake is formed. I think you are intended to answer B, but 50 years may not be enough time in which case D is the answer.

If you have notes on this event, find out what they say. I will choose B, but if you agree don't be surprised if it is D.

jerome tries to find the value of the expression 3-6+5 by first applying the communtative property. he rewrites the expression as 3-5+6. explain what is wrong with jeromes approach

Answers

The commutative property is a property of addition, not of subtraction. It can work in a subtraction problem if you keep the sign with the number, so you're adding positive and negative numbers.

3 - 6 + 5

= (3) + (-6) + (5)

= (3) + (5) + (-6)

= 3 + 5 - 6

if a cd can store 700,000,000 bytes of data express, in scientific notation the number of bytes of data which can be store on 2 such cd

Answers

700,000,000 = 7.00E8 bytes of data.  Then, 2 such cd's will hold 2(7.00E8 bytes of data) = 1.4E9 byes of data (answer)

Find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length.

Answers

find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length

To find the perimeter of a triangle we add all the sides of the triangle

The length of the sides of the triangle are given as 15 inches, 15 inches, and 21 inches

Perimeter of a triangle =

15 inches + 15 inches +   21 inches = 51 inches

So 51 inches is the perimeter

evaluate this expression

[tex]2^{-2}[/tex]

Answers

Answer:

0.25

Step-by-step explanation:

we have to use the following formula here-

[tex]a^{-m}= \frac{1}{a^{m}}[/tex]

Now, here we get,

[tex]2^{-2}[/tex]

So, applying the formula we get

[tex]2^{-2}= \frac{1}{2^{2}}= \frac{1}{4} =0.25[/tex]


So, the answer is     0.25

[tex]2^{-2}[/tex] = [tex]\frac{1}{4}[/tex]

using the law of exponents

[tex]a^{-m}[/tex] ⇔ [tex]\frac{1}{}a^{m}[/tex]

[tex]2^{-2}[/tex] = [tex]\frac{1}{}2^{2}[/tex] = [tex]\frac{1}{4}[/tex]


is a fraction a numerical or algebraic
[tex] \frac{n}{4} [/tex]

Answers

Algebraic is your answer

In a numerical fraction, there can only be numbers and the operation that is connected with the numbers

In an Algebraic fraction, not only can you have numbers and operation, you can also have variables.

~Rise Above the Ordinary, Senpai

Two lines intersect to form a linear pair with equal measures. One angle has the measure 3x° and the other angle has the measure (9y − 18)°. Find the values of x and y.

Answers

3x + 9y - 18 = 180

3x = 9y - 18

Which means

3x = 90

9y - 18 = 90

Solving for each:

x = 90/ 3

x = 30

And

9y = 108

y = 108/9

y = 12


Answer: x = 30 , y = 12

The values of x and y are 33 and 13, respectively. To find these, we used the properties of a linear pair of angles being equal and supplementary, which led us to a system of equations that we solved for both variables.

When two angles form a linear pair with equal measures, they are supplementary and equal to each other. Therefore, the sum of their measures is 180 degrees. Since both angles in the linear pair are equal, we can set them equal to each other to find the values of x and y.

The first angle is given as 3x degrees and the second angle is given as (9y - 18) degrees. Since they are equal, we can set up the equation:

3x = 9y - 18

To find the value of x and y, we also need to use the fact that angles in a linear pair add up to 180 degrees. Thus:

3x + (9y - 18) = 180

Substituting the value of 3x from the first equation into the second:

3x + 3x = 180 + 18

6x = 198

x = 33

Now substituting the value of x back into the first equation to find the value of y:

3(33) = 9y - 18

99 = 9y - 18

9y = 117

y = 13

The values of x and y are therefore 33 and 13, respectively.

Solve for x.
3x / 6 + 1 = 7

Answers

3x/6 +1 = 7

Subtract 1 from each side:

3x/6 = 6

Multiply both sides by 6:


3x = 36

Divide both sides by 3:

X = 36 / 3

X = 12

x = 12

given [tex]\frac{3x}{6}[/tex] + 1 = 7 ( subtract 1 from both sides )

[tex]\frac{3x}{6}[/tex] = 6 ( multiply both sides by 6 )

3x = 36 ( divide both sides by 3 )

x = 12


HELP PLEASE!!!! 8TH GRADE MATH

Answers

1. 12 pages per minute

if you miss a payment for a bill, how do you compute the interest due on the next bill?

Answers

Final answer:

To calculate the interest due after missing a payment, add any late fees to the unpaid bill and apply the monthly interest rate to the outstanding balance. Interest compounds monthly, so it's crucial to pay off the debt quickly to prevent the balance from growing.

Explanation:

To compute the interest due on the next bill after missing a payment for a bill, you need to consider any late fees in addition to the compounded interest. For a credit card company that charges a flat rate of $10 for a late payment and a daily rate of $5 for each day the payment remains unpaid, you would add these fees to the subtotal of the unpaid bill. Additionally, most creditors use a formula to calculate minimum payments and interest on the outstanding balance, typically on a monthly basis.

The interest on the next bill is calculated by multiplying the balance you owe by the interest rate that is applied each month. If you continue to carry a balance from month to month, this interest will be added to your outstanding balance, which will increase the amount you owe. It is important to pay off credit card debt as promptly as possible to avoid accruing additional interest.

Find the value of the expression 2x^4–5x^3+x^2+3x+2 for x=−5

Answers

Answer:

1887

Step-by-step explanation:

You can do this by putting the value -5 where x is in the expression, using synthetic division, or letting a calculator evaluate the function. (Likely a calculator is involved, regardless.)

Shown in the attachments are a couple of these methods.

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