let's convert 400 newtons to Kg, which is 40.7886.
now we put it in a formula that includes gravity and acceleration
(40.7886 kg) ( 9.8 m/s2) + (40.7886 kg) (0)
now we come up with the answer of 399.72828 kg or 3920 Newtons
Not sure which unit you are looking for but they are both there.
How is the energy of an electromagnetic wave carried from one place to another
changing electric field gives a changing magnetc field ... can calculate energy using Poynting vector
A copper penny has a mass of 3.1 g and a volume of 0.35 cm3. What is the density of copper? Be sure to show your work and include units.
The density of copper that has a mass of 3.1 g and a volume of 0.35 cm³ is 8.86g/cm³
HOW TO CALCULATE DENSITY:
The density of a substance can be calculated by dividing the mass of the substance by its volume as follows:Density (g/cm³) = mass (g) ÷ volume (cm³)According to this question, copper has a mass of 3.1 g and a volume of 0.35 cm³, hence, the density can be calculated as follows:Density (g/cm³) = 3.1g ÷ 0.35cm³Density of copper = 8.86g/cm³Therefore, the density of copper that has a mass of 3.1 g and a volume of 0.35 cm³ is 8.86g/cm³.Learn more at: https://brainly.com/question/2040396?referrer=searchResults
Which of these experiments would make use of quantitative data?
A
A study of the different amounts of time it takes water to evaporate completely
B
A study of the effects of sunlight on the color of construction paper
C
A study of the differences in cloud shapes on three successive days
a ) study of the different amounts of time it takes water to evaporate completely.
i always end up helping u <3 lol
Answer: A . A study of the different amounts of time it takes water to evaporate completely
Explanation:
The quantitative data can be define as the property or parameter which can be measured in units and counted in numbers. It can be represented in symbols, units and number code.
A is the correct option this is because of the fact that time can be measured in seconds, minutes and hours. Thus different amounts of time it takes water to evaporate completely can be a approach to conduct the experiment using quantitative data.
What best describes why kepler’s observation of planetary motion is a law instead of a theory
A hypothesis is a guess based off of previous dater or simply reasoning for the most logical outcome.
A theory is a statement that has evidence and facts supporting it but still has room for change or error.
A law is a proven statement that works in every possible case without exception and will never be disproved (unless it was wrongly named a law in the first place).
A cheetah can run at a maximum speed 97.8 km/h and a gazelle can run at a maximum speed of 78.2 km/h. If both animals are running at full speed, with the gazelle 96.8 m ahead, how long before the cheetah catches its prey? Answer in units of s.
The cheetah can maintain its maximum speed for only 7.5 s. What is the minimum distance the gazelle must be ahead of the cheetah to have a chance of escape? (After 7.5 s the speed of cheetah is less than that of the gazelle.) Answer in units of m.
(1)
Cheetah speed: [tex]v_c = 97.8 km/h=27.2 m/s[/tex]
Its position at time t is given by
[tex]S_c (t)= v_c t[/tex] (1)
Gazelle speed: [tex]v_g = 78.2 km/h=21.7 m/s[/tex]
the gazelle starts S0=96.8 m ahead, therefore its position at time t is given by
[tex]S_g(t)=S_0 +v_g t[/tex] (2)
The cheetah reaches the gazelle when [tex]S_c=S_g[/tex]. Therefore, equalizing (1) and (2) and solving for t, we find the time the cheetah needs to catch the gazelle:
[tex]v_c t=S_0 + v_g t[/tex]
[tex](v_c -v_g t)=S_0[/tex]
[tex]t=\frac{S_0}{v_c-v_t}=\frac{96.8 m}{27.2 m/s-21.7 m/s}=17.6 s[/tex]
(2) To solve the problem, we have to calculate the distance that the two animals can cover in t=7.5 s.
Cheetah: [tex]S_c = v_c t =(27.2 m/s)(7.5 s)=204 m[/tex]
Gazelle: [tex]S_g = v_g t =(21.7 m/s)(7.5 s)=162.8 m[/tex]
So, the gazelle should be ahead of the cheetah of at least
[tex]d=S_c -S_g =204 m-162.8 m=41.2 m[/tex]
The cheetah catches the prey [tex]\fbox{17.78 s}[/tex] before the gazelle.
The minimum distance the gazelle must be ahead of the cheetah to have a chance of escape is [tex]\fbox{40.83 m}[/tex].
Further Explanation:
The speed is the rate of change of the distance and the relative speed is the speed of the one object in respect of another object. If two body moves in same direction then the relative speed in respect of the one body is given by subtract of both speed and it they are moving in opposite direction the relative speed in respect of the one body is given by sum of both speeds.
Given:
The maximum speed of the cheetah is [tex]97.8 km/h[/tex].
The maximum speed of the gazelle is [tex]78.2 km/h[/tex].
The distance between the starting points of cheetah and the gazelle is [tex]96.8 m[/tex].
Concept:
The expression for the position of the cheetah at some time t is:
[tex]{S_1}={v_c}t[/tex] …… (1)
Here, [tex]{S_1}[/tex]the position of the cheetah at some time [tex]t[/tex], [tex]{v_c}[/tex] is the speed of the cheetah and [tex]{S_1}[/tex] is the distance covered at time [tex]t[/tex].
The expression for the position of the gazelle at some time [tex]t[/tex] is:
[tex]{S_2}={S_o}+{v_g}t[/tex] …… (2)
Here, [tex]{S_2}[/tex] the position of the gazelle at some time [tex]t[/tex], [tex]{v_g}[/tex] is the speed of the gazelle, [tex]{S_o}[/tex] is the distance between the starting points of cheetah and the gazelle.
At the time when the cheetah reached the gazelle then [tex]{S_1}={S_2}[/tex].
Equate equation (1) and (2).
[tex]\begin{aligned}{v_c}t&={S_o}+{v_g}t\hfill\\{v_c}t-{v_g}t&={S_o}\hfill\\t\left( {{v_c} - {v_g}}\right)&={S_o}\hfill\\t&=\frac{{{S_o}}}{{\left( {{v_c} - {v_g}} \right)}}\hfill\\\end{aligned}[/tex]
Substitute [tex]97.8 km/h[/tex] for [tex]{v_c}[/tex], [tex]78.2 km/h[/tex] for [tex]{v_g}[/tex] and [tex]96.8 m[/tex] for [tex]{S_o}[/tex] in the above equation.
[tex]\begin{aligned}t&=\frac{{96.8{\text{ m}}}}{{\left( {97.8 - 78.2} \right){\text{km/h}}\left({\frac{{1000{\text{ m}}}}{{1{\text{ km}}}}} \right)\left( {\frac{{1{\text{ h}}}}{{{\text{3600 s}}}}} \right)}}\\&=\frac{{96.8{\text{ m}}}}{{{\text{19}}{\text{.6 m/s}}\left( {\frac{5}{{18}}}\right)}}\\&=17.78{\text{s}}\\\end{aligned}[/tex]
Therefore, the cheetah catches the prey [tex]17.78 s[/tex] before the gazelle.
To calculate the minimum distance the gazelle must be ahead of the cheetah to have a chance of escape we should subtract the distance covered by the cheetah and gazelle in [tex]7.5 s[/tex].
The expression for the distance covered is:
[tex]S = vt[/tex]
Here, [tex]S[/tex] is the distance covered, [tex]v[/tex] is the speed and [tex]t[/tex] is the travel time.
Substitute [tex]97.8 km/h[/tex] for [tex]v[/tex] and [tex]7.5 s[/tex] for [tex]t[/tex] in the above equation.
[tex]\begin{aligned}S&=\left( {97.8{\text{ km/h}}} \right)\left( {\frac{{1000{\text{ m}}}}{{1{\text{ km}}}}} \right)\left( {\frac{{1{\text{ h}}}}{{{\text{3600 s}}}}} \right)\left( {7.5{\text{ s}}} \right)\\&=\left( {97.8{\text{ m/s}}} \right)\left( {\frac{5}{{18}}} \right)\left( {7.5{\text{ s}}} \right)\\&=203.75{\text{m}}\\\end{aligned}[/tex]
Therefore, the distance covered by the cheetah in [tex]7.5 s[/tex] is [tex]203.75 m[/tex].
Substitute [tex]78.2 km/h[/tex] for [tex]v[/tex] and [tex]7.5 s[/tex] for [tex]t[/tex] in the above equation.
[tex]\begin{aligned}S&=\left( {78.2{\text{ km/h}}} \right)\left( {\frac{{1000{\text{ m}}}}{{1{\text{ km}}}}} \right)\left( {\frac{{1{\text{ h}}}}{{{\text{3600 s}}}}} \right)\left( {7.5{\text{ s}}} \right)\\&=\left( {78.2{\text{ m/s}}} \right)\left( {\frac{5}{{18}}} \right)\left( {7.5{\text{ s}}} \right)\\&=162.92{\text{ m}}\\\end{aligned}[/tex]
Therefore, the distance covered by gazelle in [tex]7.5 s[/tex] is [tex]162.92 m[/tex].
The minimum distance the gazelle must be ahead of the cheetah to have a chance of escape is:
[tex]\begin{aligned}d&=\left( {203.75 - 162.92} \right){\text{ m}}\\&=40.83{\text{ m}}\\\end{aligned}[/tex]
Therefore, the minimum distance the gazelle must be ahead of the cheetah to have a chance of escape is [tex]\fbox{40.83 m}[/tex].
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Answer Details:
Grade: High school
Subject: Physics
Chapter: Kinematics
Keywords:
Cheetah, 97.8 km/h, gazelle, 78.2 km/h, full speed, 96.8 m. ahead, catches, prey, 7.5 s, minimum, ahead, escape, answer, unit, s, m, 40.83 m.
A jet airliner moving initially at 548 mph
(with respect to the ground) to the east moves
into a region where the wind is blowing at
343 mph in a direction 67◦
north of east.
What is the new speed of the aircraft with
respect to the ground?
Answer in units of mph.
Let's choose the "east" direction as positive x-direction. The new velocity of the jet is the vector sum of two velocities: the initial velocity of the jet, which is
[tex]v_1 =548 mph[/tex] along the x-direction
[tex]v_2 = 343 mph[/tex] in a direction [tex]67^{\circ}[/tex] north of east.
To find the resultant, we must resolve both vectors on the x- and y- axis:
[tex]v_{1x}= 548 mph[/tex]
[tex]v_{1y}=0[/tex]
[tex]v_{2x} = (343 mph)( cos 67^{\circ})=134.0 mph[/tex]
[tex]v_{2y} = (343 mph)( sin 67^{\circ})=315.7 mph[/tex]
So, the components of the resultant velocity in the two directions are
[tex]v_{x}=548 mph+134 mph=682 mph[/tex]
[tex]v_{y}=0 mph+315.7 mph=315.7 mph[/tex]
So the new speed of the aircraft is:
[tex]v=\sqrt{v_x^2+v_y^2}=\sqrt{(682 mph)^2+(315.7 mph)^2}=751.5 mph[/tex]
The new speed of the aircraft with respect to the ground, taking into account the wind speed and direction, is approximately 744.91 mph.
Explanation:To solve this problem, you should first break the wind's velocity into its eastward (x-component) and northward (y-component) using trigonometry. The eastward component is 343 mph x cos(67) = 134.87 mph, and the northward component is 343 mph x sin(67) = 313.37 mph.
Now, you can add the eastward component of the wind speed to the initial speed of the jet airliner (548 mph + 134.87 mph = 682.87 mph). The northward component of the wind's speed remains the same (313.37 mph) since the plane was initially moving only eastwards with no northwards component.
The new speed of the aircraft with respect to the ground (or resultant velocity) can be found using Pythagoras' theorem: √[(682.87)^2 + (313.37)^2] = 744.91 mph.
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What parts of clam are likely to be preserved?
A:Hard parts
B:soft parts
C:all parts
D:No parts
the answer is a. hard parts.
The hard parts of clams are most likely to be preserved as fossils. Soft parts rarely survive the fossilization process due to their rapid decay, and complete fossil preservation including soft parts is extremely rare.
Explanation:When it comes to preservation, it is the hard parts of bivalves, which include clams, scallops, oysters, and mussels, that are more likely to be fossilized. These organisms have a shell composed of two parts that can open and close, which offers a durable structure capable of surviving long-term geological processes. The soft parts, such as the mouth, heart, intestine, gills, and stomach, typically decay and are rarely preserved; however, there are exceptional occurrences where conditions permit the preservation of soft tissues, as seen with some belemnite fossils, though this is extremely rare.
The alteration of hard parts is a common occurrence in fossil records, resulting in fossil preservation such as permineralization, recrystallization, replacement, carbonization, or dissolution. These processes affect the skeletal material of the hard parts, making them the principal components discovered in fossil records.
In electric dryer consumes 6.0×10 6 jewel of energy when operating at 220 V for 30 minutes. During operation the dryer draws a current of approximately?
Final answer:
The electric dryer, which consumes 6.0×10⁶joules of energy at 220 V for 30 minutes, draws an approximate current of 15.15 amperes during operation.
Explanation:
To determine the current drawn by an electric dryer that consumes 6.0×10⁶ joules of energy while operating at a voltage of 220 V for 30 minutes, we use the relationship between power, voltage, and current given by the equation P = IV, where P is power in watts, I is current in amperes, and V is voltage in volts. First, we need to calculate the power used by the dryer. Power is the rate of energy consumption over time, so:
Power (P) = Energy (E) / Time (t)P = 6.0×10⁶ J / (30 * 60 s) = 6.0×10⁶ J / 1800 s = 3333.33 WNext, we can calculate the current using the power:
Current (I) = Power (P) / Voltage (V)I = 3333.33 W / 220 V ≈ 15.15 ATherefore, the electric dryer draws an approximate current of 15.15 amperes during operation.
The current drawn by the electric dryer is approximately [tex]\( {0.00421 \text{ A}} \)[/tex] (or 4.21 mA).
Given:
- Energy consumed [tex]\( E = 6.0 \times 10^6 \)[/tex] joules
- Operating voltage ( V = 220 ) V
- Operating time t = 30 minutes
First, convert the operating time from minutes to seconds:
[tex]\[ t = 30 \text{ minutes} = 30 \times 60 \text{ seconds} = 1800 \text{ seconds} \][/tex]
Next, convert the energy consumed from joules to kilowatt-hours (kWh):
[tex]\[ E_{\text{in kWh}} = \frac{6.0 \times 10^6 \text{ J}}{3600 \text{ s}} \times \frac{1 \text{ kWh}}{3.6 \times 10^6 \text{ J}} \]\[ E_{\text{in kWh}} = \frac{6.0 \times 10^6}{3600 \times 3.6 \times 10^6} \text{ kWh} \]\[ E_{\text{in kWh}} = \frac{6.0}{12960} \text{ kWh} \]\[ E_{\text{in kWh}} \approx 0.000463 \text{ kWh} \][/tex]
Now, calculate the power P in kilowatts (kW):
[tex]\[ P = \frac{E_{\text{in kWh}}}{t_{\text{in hours}}} = \frac{0.000463 \text{ kWh}}{0.5 \text{ hours}} = 0.000926 \text{ kW} \][/tex]
Convert the power from kilowatts to watts (W):
[tex]\[ P = 0.000926 \text{ kW} \times 1000 = 0.926 \text{ W} \][/tex]
Now, use the formula ( P = VI ) to find the current ( I ):
[tex]\[ I = \frac{P}{V} \][/tex]
Substitute [tex]\( P = 0.926 \text{ W} \)[/tex][tex]\( P = 0.926 \text{ W} \)[/tex] P = 0.926 W and [tex]\( V = 220 \text{ V} \)[/tex]:
[tex]\[ I = \frac{0.926}{220} \]\[ I \approx 0.00421 \text{ A} \][/tex]
PLEASE HELP FAST FOR 20p
If a 100 N force pulls to the West on an object and a second 100 N force pulls South on the object, which direction is the object likely to move?
equivalent force was applied
N
W E
S
because its is being pulled by south and west it will travel south west.
-What can you say about the snowboarder’s kinetic energy as he moves?
-Similarly, what can you say about the potential energy of the snowboarder?
-Based on your observations, what can you say about your prediction in Parts A and B above concerning the potential and kinetic energy?
Answer:
His kinetic energy increases, potential energy decreases
The sum of kinetic and potential energy is a constant at any instant before he comes to rest.
Explanation:
Snowboarder is starting from a height and moving to the down direction. As he moves down his velocity increases, we know that kinetic energy is given by the expression [tex]\frac{1}{2} mv^2[/tex], so as he moves his kinetic energy increases.
When the snowboarder is starting his potential energy is maximum(Potential energy = mgh), as he comes down his potential energy decreases.
Based on this we can conclude that the sum of potential energy and kinetic energy is a constant at any instant for a snowboarder before he comes to rest.
mgh+[tex]\frac{1}{2} mv^2[/tex]= Constant
Answer:
Answer:
His kinetic energy increases, potential energy decreases
The sum of kinetic and potential energy is a constant at any instant before he comes to rest.
Explanation:
Snowboarder is starting from a height and moving to the down direction. As he moves down his velocity increases, we know that kinetic energy is given by the expression , so as he moves his kinetic energy increases.
When the snowboarder is starting his potential energy is maximum(Potential energy = mgh), as he comes down his potential energy decreases.
Based on this we can conclude that the sum of potential energy and kinetic energy is a constant at any instant for a snowboarder before he comes to rest.
Briefly describe the history of the metric system as it applies to the meter and how the definition of a meter has changed over time.
Answer and explanation;
In 1670 Gabriel Mouton, Vicar of St. Paul’s Church and an astronomer proposed the swing length of a pendulum with a frequency of one beat per second as the unit of length.
In 1791 the Commission of the French Academy of Sciences proposed the name meter to the unit of length. It would equal one tens-millionth of the distance from the North Pole to the equator along the meridian through Paris.It is realistically represented by the distance between two marks on an iron bar kept in Paris.
In 1889 the 1st General Conference on Weights and Measures define the meter as the distance between two lines on a standard bar that made of an alloy of 90%platinum with 10%iridium.
In 1960 the meter was redefined as 1650763.73 wavelengths of orange-red light, in a vacuum, produced by burning the element krypton (Kr-86).
In 1984 the Geneva Conference on Weights and Measures has defined the meter as the distance light travels, in a vacuum, in 1299792458⁄ seconds with time measured by a cesium-133 atomic clock which emits pulses of radiation at very rapid, regular intervals.
The metric system was first put into practice in 1799, during the French Revolution, when the existing system of measures became impractical for trade and was supplanted by a decimal system based on the kilogram and the meter.
What is metric system?During the French Revolution, the existing system of measures became impractical for trade and was replaced by a decimal system based on the kilogram and the meter, and the metric system was born.
In 1793, the meter was defined as one ten-millionth of the distance from the equator to the North Pole along a great circle, implying that the Earth's circumference is approximately 40000 km.
The meter was redefined in 1799 in terms of a prototype meter bar.
The meter was introduced as a new unit of length, defined as one ten-millionth of the shortest distance between the North Pole and the Equator passing through Paris, assuming an Earth flattening of 1/334.
Thus, this is the history of the metric system as it applies to the meter.
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When the final velocity is less than the initial velocity, this is , options: speed time acceleration deceleration
When an object is having variable velocity then we can use the definition of acceleration to find it that rate of change in velocity is known as acceleration.
We can define it as
[tex]a = \frac{v_f - v_i}{\Delta t}[/tex]
here
[tex]v_f[/tex] = final velocity
[tex]v_i[/tex] = initial velocity
[tex]\Delta t[/tex] = time interval
now it is given here that final velocity is less than initial velocity after some time which means
[tex]v_f < v_i[/tex]
so here we can say acceleration will have negative value which shows it is opposite to the direction of velocity.
So this is the case of decreasing velocity which is known as deceleration.
So correct answer is
deceleration
If you were standing on the moon and you had a radio signal transmitter, you could send the radio signal to Earth in 1.28 seconds. If radio waves travel at 3.00 X 1018 m/s, what is the distance from the moon to the earth in kilometers?
Answer:
Distance between moon and earth = [tex]3.84*10^{5}km[/tex]
Explanation:
Distance traveled by radio waves = Velocity of radio waves * Time taken by radio waves
Velocity of radio waves = [tex]3*10^{8}m/s[/tex]
Time taken by radio waves = 1.28 seconds
So distance traveled by radio wave = [tex]3*10^{8}*1.28=3.84*10^{8}m[/tex]
Distance between moon and earth = [tex]3.84*10^{8}m[/tex]=[tex]3.84*10^{5}km[/tex]
If you had a positive 8 score on the sit-an-reach test you
Answer:you are very flexible
Explanation:
That’s a very high score.
If v =5.00 meters/second and makes an angle of 60 with the negative direction of the y-axis coalculate the possible values of vx
An angle of 60 degrees with the negative y-axis could mean 60 degrees clockwise or counterclockwise, which translates to two possible angles (starting from the positive x-axis and moving counterclockwise) of 210 degrees or 330 degrees.
Then the horizontal component [tex]v_x[/tex] of a velocity vector [tex]\mathbf v[/tex] with magnitude [tex]5.00\,\dfrac{\mathrm m}{\mathrm s}[/tex] could be one of two expressions:
[tex]v_x=\left(5.00\,\dfrac{\mathrm m}{\mathrm s}\right)\cos210^\circ=-4.33\,\dfrac{\mathrm m}{\mathrm s}[/tex]
[tex]v_x=\left(5.00\,\dfrac{\mathrm m}{\mathrm s}\right)\cos330^\circ=4.33\,\dfrac{\mathrm m}{\mathrm s}[/tex]
Physics Question, Please Help:
Which of the following can you determine from the graph of the force of the sun on a comet?
A) The force increases as the distance decreases.
B) The force is sometimes zero.
C) The force decreases as the distance decreases.
D) The force does not depend on the distance.
From that graph of the force of the sun on a comet, you can see that the force increases as the distance decreases. (A)
Here, we are required to determine the relationship between the force exerted by the sun on a Comet and the distance between the sun and the comet.
From the graph, the force exerted by the sun on the comet increases as the distance between them decreases.
From the graph, it is evident that the slope of the graph is negative.
Although, the slope of the graph is not constant as in the case of linear graphs (equation of a straight line).
However, the positioning of the line joining all points on the graph suggests that the slope of the graph is negative.
Consequently, the parameters ( i.e the force and distance) are inversely proportional to one another.
Therefore, as the force increases, the distance decreases.
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What is the most common mineral in an igneous rock?
What are the three types of sedimentary rocks where you will most likely find fossils?
Usually fossils are formed when a layer of sediment covers dead plants, animals and microorganisms. This makes sedimentary rocks like limestone and shale the best in the formation of fossils.
To improve the acoustics in an auditorium, a sound reflector with a mass of 170 kg is suspended by a chain from the ceiling. What is the tension in the chain? Assume that the mass of the chain itself is 8.0 kg.
Remark
Tension is a type of force. In this case the total force is that of the chain and the reflector are both vertical and therefore acted on by gravity.
Step One
Find the total mass
Mass = m = M1 + M2
M1 = 170 kg
M2 = 8.0 kg
m= 178.0
Step Two
Find the tension
m = 178.0 kg
a = 9.81
T = ???
Formula
T = m * a
T = 178 * 9.81
T = 1746 N
Comment
If this seems a little strange to you, remember that you are actually finding the downward force felt by the hook holding up the chain and reflector. That hook is going to experience the weight of both. I think the question used 9.8 rather than 9.81. That's what it did.
Answer
C
What part of a tidal power plant is the tidal water pushed through to generate electricity a.Turbine b.Barrage c.Boat d.Dam
a. Turbine
The turbine converts the kinetic energy of falling water into mechanical energy.
Answer : Turbine is used to generate electricity in tidal power plant.
Explanation :
In tidal power plant, the kinetic energy of moving water is used to generate electricity. It is one of the renewable source of energy.
The turbine is a part of the tidal power plant which is used to generate electricity. It is kept on the floor of the sea where there is a very strong tidal flow.
The turbines used in tidal power plant is very expensive as compared with the wind turbines.
Hence, the correct option is (a) " turbine ".
A space station has a radius of 200m.
A. What period of rotation is needed to provide an artificial gravity of g at the rim?
For artificial gravity the the position of rim we have to rotate the space station
Due to rotation it will experience centripetal acceleration at the position of rim
Now in order to experience this acceleration to be same as gravity we can say centripetal acceleration must be equal to gravity here
[tex]a_c = g[/tex]
as we know that centripetal acceleration is given as
[tex]a_c = w^2R[/tex]
[tex]a_c = w^2*200 = g[/tex]
[tex]w^2* 200 = 9.8[/tex]
[tex]w = \sqrt{\frac{9.8}{200}}[/tex]
[tex]w = 0.22 rad/s[/tex]
now we know that angular frequency will be related to time period as
[tex]T = \frac{2\pi}{w}[/tex]
[tex]T = \frac{2\pi}{0.22}[/tex]
[tex]T = 28.4 s[/tex]
so it will rotated by time period T = 28.4 s
The decomposition of water into hydrogen gas h2 and oxygen gas o2 can be moldled by the balanced chemical equation
Which vector should be negative?
any vector whose magnitude is less than 1
a displacement in the direction North
the velocity of a falling object
any vector whose magnitude is greater than 1
Answer:
The velocity of a falling object
Explanation:
The positive X axis is towards right and positive Y axis is towards up, so North direction is positive
A vector with less than 1 magnitude is not negative, because its magnitude may be in between 0 and 1 which is positive vector.
Any vector whose magnitude is greater than 1 is never be a negative vector.
The velocity of a falling object is towards bottom, that is towards negative Y axis. So that vector is negative.
The angle between magnetic north and the north to which a compass needle points is known as magnetic declination.
Please select the best answer from the choices provided
T
F
From among the choices provided, the better choice is the upper-case letter 'T '. That symbol can conveniently be used to represent the words "true" or "truth", which is exactly the reason that it is the better choice for a response, since the complicated statement at the beginning of the question is completely true in its every detail, nuance, jot and tittle.
Answer:
it is true my child
Explanation:
a train engineer started the train from a standstill and sped up to 5 meters per second, she then rounded a corner at a constant speed. She then sped the train up to 10 meters per second on the next straightaway. Next, the train chugged around another bend at 10 m/sec, and then its speed slowed to 5 meters per second after coming out of the bend. Finally, the train reached the station, and the engineer applied the brakes and brought the engine to a stop. How many times did the train accelerate? Once a carousel is in motion, the constant movement of the carousel horse around the center of the circle can best be described as
The train accelerates four times during its journey, and the examples provided illustrate concepts of acceleration and uniform circular motion as they apply to trains, buses, and rides like the carousel.
The train described in the question undergoes acceleration several times throughout its journey:
When it speeds up from a standstill to 5 m/s.When it increases its speed from 5 m/s to 10 m/s on a straightaway.When it slows down from 10 m/s to 5 m/s after a bend.When it comes to a stop at the station.Overall, the train accelerates a total of four times. On the other hand, uniform circular motion, such as that of a carousel horse moving around the center, involves an object traveling in a circular path at a constant speed. Despite the speed being constant, because the direction is changing, the object is still experiencing a centripetal acceleration towards the center of the circle.
For example 10.2.3 regarding the slow acceleration of trains, we can calculate the train's movement and wheel's angular velocity after 200 revolutions given the wheel radius and angular acceleration. To find out how far the train has moved down the track, we can use the formula for the circumference of a circle (C = 2πr) multiplied by the number of revolutions. To find the final angular velocity, we can use the kinematic equation for rotational motion (ω2 = ω02 + 2αθ), where ω0 is the initial angular velocity (zero in this case), α is the angular acceleration, and θ is the angular displacement (total revolutions times 2π).
The train accelerated twice at two different points in its journey. In the first instance, it accelerated from a standstill to 5 meters per second, and in the second instance, it accelerated from 5 meters per second to 10 meters per second.
Why do atoms bond?
Some atoms are sticky so they stick to other atoms.
They have too many electrons on their inner shell and need to give some away.
They want to fill up their nucleus in order to become stable.
They want to fill up their outer electron shell in order to become stable.
They want to fill up their outer electron shell in order to become stable. All things in life are made from atoms and all atoms want to reside in their lowest energy state because it is most stable. To do so, atom either share, give, or gain electrons to achieve this stability.
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Below is a picture of a swimmer in a river. Looking at the vectors being added is the swimmer going downstream or upstream?
Downstream, the current is helping the swimmer go faster relative to the land.
Upstream, the current is slowing the swimmer down.
Answer:
Downstream, the current is helping the swimmer go faster relative to the land.
Explanation:
As shown in the figure the resultant vector is the addition of velocity of water and velocity of swimmer.
This shows that the swimmer is in the direction along the flow of the current. Thus, answer is downwards, the current is helping the swimmer go faster relative to the land.
Which of the foolwing best define net force?
Net force can be defined as the sum of force acting on an object in all the directions
.i.e Net force= F acting on a body at upward direction+ F at downward direction+ F at leftward direction+ F at rightward direction.
e.g if a body is at rest the sum of forces acting on body in all direction is zero
but if a body is moving its mean body is facing an unbalanced net force.
If a 0.200-kilogram ball sits on a shelf 2.00 meters from the floor, how much mechanical energy (me) does it possess? More than 3.92 j exactly 3.92 j less than 3.92 j cannot be determined because kinetic energy cannot be calculated
Answer:
Mechanical energy = 3.92 J
exactly 3.92 j
Explanation:
As we know that mechanical energy is sum of kinetic energy and potential energy of the system
so here we can say that mechanical energy is sum of kinetic energy of ball and its potential energy
Since ball is at rest so kinetic energy of the ball must be ZERO
Now for potential energy we know that
[tex]U = mgh[/tex]
now we know
m = 0.2 kg
h = 2 m
now for potential ene'rgy
[tex]U = (0.20)(9.8)(2)[/tex]
[tex]U = 3.92 J[/tex]
so mechanical energy is given as
Mechanical Energy = 3.92 + 0 = 3.92 J
Answer:
b
Explanation:
A car accelerates from rest at 3.6 m/s 2 . How much time does it need to attain a speed of 5 m/s?
car starts from rest
[tex]v_i = 0[/tex]
final speed attained by the car is
[tex]v_f = 5 m/s[/tex]
acceleration of the car will be
[tex]a = 3.6 m/s^2[/tex]
now the time to reach this final speed will be
[tex]t = \frac{v_f - v_i}{a}[/tex]
[tex]t = \frac{5 - 0}{3.6}[/tex]
[tex]t = 1.39 s[/tex]
so it required 1.39 s to reach this final speed
To calculate the time to reach 5 m/s from rest with an acceleration of 3.6 [tex]m/s^2[/tex], the kinematic equation v = u + at is used, where u is zero. Solving for t gives 1.39 seconds.
The question asks about the time it takes for a car to reach a certain speed given a constant acceleration, which falls under the subject of Physics.
To find the time required for the car to attain a speed of 5 m/s from rest with an acceleration of 3.6 [tex]m/s^2[/tex], you use the kinematic equation:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Since the car starts from rest, the initial velocity u is 0, and we can rearrange the formula to solve for time:
t = (v - u) / a
Plugging in the given values:
t = (5 m/s - 0 m/s) / 3.6 [tex]m/s^2[/tex] t = 5 / 3.6 t = 1.39 seconds
Thus, the car needs approximately 1.39 seconds to accelerate to 5 m/s.
What is the relationship between the internal energy of a substance and its state of matter? A) As a gas loses internal energy it becomes a plasma. Eliminate B) Closer packed atoms generally have more internal energy. C) As the internal energy decreases a substance will spread further apart. D) As the internal energy increases a substance would go from solid to a liquid.
D. As the internal energy increases a substance would go from solid to a liquid.
hope this helps :)
Answer: Option (D) is the correct answer.
Explanation:
Internal energy is defined as the minimum amount of energy present within the molecules of a substance.
More is the internal energy within the molecules of a substance more will be the number of collisions between them.
As a results, the particles will move away from each other and this leads to change in state of matter from solid to liquid and liquid to gaseous state.
Thus, we can conclude that the relationship between the internal energy of a substance and its state of matter is that as the internal energy increases a substance would go from solid to a liquid.