A group of 500 transistors is known to contain one defective unit. What is the probability that a transistor selected at random from the lot is the bad one?

Solution:- Answer is 19.33%

Annual percentage rate (APR) is the yearly rate for a price which have to pay for borrowing money through credit card.

Here Caleb has an offer from a credit card issue for i=0% APR for the first 30 days.

now, effective interest rate for n= 30 days  

=[tex]r=(1+\frac{i}{n} )^n-1\\\Rightarrow\ r=(1+\frac{0}{30} )^{30}-1\\\Rightarrow\ r=(1+0)^{30}-1=1-1=0[/tex]

After 30 days APR =17.68%=0.1768

n=365-30=335 days

now the effective interest rate for n=335 days

=[tex]r=(1+\frac{i}{n} )^n-1\\\Rightarrow\ r=(1+\frac{0.1789}{335} )^{335}-1\\\Rightarrow\ r=(1+0.000527)^{335}-1=(1.000527)^{335}-1=1.1933-1=0.1933[/tex]

=19.33%

So the effective interest rate for 365 days =0+19.33% =19.33%

So fourth option is correct.

Answer:

17.61%

Step-by-step explanation:

just did it

Answer:

D. The rider is closest to the ground when he is 25 ft from the left side of the ride.

Step-by-step explanation:

The vertex of x-coordinate represents the distance from the from the origin of the pendulum, which is the closest to the ground when he is 25 ft away from 0.

Hope this will helpful.

Thank you.

For this case we must simplify the following expression:

[tex]\frac {4x ^ 2-32x + 48} {3x ^ 2-17x-6}[/tex]

Simplifying the numerator, dividing all the terms by 4, we have:

[tex]x ^ 2-8x + 12[/tex]

We factor by looking for two numbers that when added together give -8 and when multiplied by 12. These are: -6 and -2

[tex]-6-2 = -8\\-6 * -2 = 12[/tex]

So, we have to:

[tex]x ^ 2-8x + 12 = (x-6) (x-2)[/tex]

Simplifying the denominator:

We rewrite -17x as -18x + x:

[tex]3x ^ 2-18x + x-6[/tex]

We factor the highest common denominator of each group:

[tex]3x (x-6) +1 (x-6)[/tex]

We factor the polynomial by factoring the highest common denominator (x-6):

[tex](x-6) (3x + 1)[/tex]

So, we have to:

[tex]3x ^ 2-17x-6 = (x-6) (3x + 1)[/tex]

Substituting in the original expression we have:

[tex]\frac {(x-6) (x-2)} {(x-6) (3x + 1)} = \frac {x-2} {3x + 1}[/tex]

ANswer:

[tex]\frac {4x ^ 2-32x + 48} {3x ^ 2-17x-6} = \frac {x-2} {3x + 1}[/tex]

Answer:

The number of dimes she has = 42

Step-by-step explanation:

Rhianna has $5.25 in dimes and nickels for a total of 63 coins.

Let the number of nickels be x and the dimes be y.

Since nickels = 0.05 cent and Dimes = 0.10 cent

Now we will form the equations.

10 y + .05 x = 5.25

5x + 10y = 525

x + 2y = 105 ------(1)

x + y = 63 ----(2)

By subtracting equation 2 from 1.

(x + 2y)-(x + y) = 105 - 63

x + 2y - x - y = 42

y = 42

By putting y = 42 in equation 1

x + 42 = 63

x = 63 - 42 = 21

Therefore

Number of dimes will be 42.

The correct answer is that the other components equal 12% of the milk.

To solve this problem, one must understand that the total percentage of all components in milk must add up to 100%. Given that 88% of milk is water, the remaining percentage will be the sum of all other components in the milk.

To find the percentage of the other components, subtract the percentage of water from the total percentage:

Total percentage of milk = 100%

Percentage of water in milk = 88%

Percentage of other components = Total percentage of milk - Percentage of water in milk

Percentage of other components = 100% - 88%

Percentage of other components = 12%

Therefore, the other components in the milk make up 12% of the milk.

Complete question:- If 88% of milk is water, what percent do the other components equal?

Answer:

[tex]a_{n} =\frac{-a_{n-1}}{4}[/tex].

Step-by-step explanation:

We are given a geometric sequence { -16, 4, -1, .... }

i.e. [tex]a_{1} =-16[/tex], [tex]a_{2} =4[/tex], [tex]a_{3} =-1[/tex], ...

We will first find the common ratio 'r'.

Now, [tex]r=\frac{a_{n}}{a_{n-1}}[/tex]

i.e. [tex]r=\frac{a_{2}}{a_{1}}[/tex]

i.e. [tex]r=\frac{4}{-16}[/tex]

i.e. [tex]r=\frac{1}{-4}[/tex]

Similarly, i.e. [tex]r=\frac{a_{3}}{a_{2}}[/tex]

i.e. [tex]r=\frac{-1}{4}[/tex]

So, we get that the common ratio is [tex]r=\frac{-1}{4}[/tex].

Now, the recursive formula for the geometric sequence is given by,

[tex]a_{n} =r \times a_{n-1}[/tex]

i.e. [tex]a_{n} =\frac{-1}{4} \times a_{n-1}[/tex]

i.e. [tex]a_{n} =\frac{-a_{n-1}}{4}[/tex].

Hence, the recursive formula for this sequence is [tex]a_{n} =\frac{-a_{n-1}}{4}[/tex].

Answer:

7 on k-12

Step-by-step explanation:

7(w+1)7w+77w+77w+7−7w7217=======5(2w−3)+110w−15+110w−1410w−14−7w3w−143wwDistribute on each side.Simplify the right side.Subtract 7w from each side.Combine like terms.Add 14 to each side.Divide each side by 3.

Answer:

71

Step-by-step explanation:

Answer:  [tex]\angle{B}[/tex]

Step-by-step explanation:

We know that if two triangles are congruent , then their corresponding sides and angles are congruent (by CPCTC).

[CPCTC is the acronym use for the property of congruent triangles that says that corresponding parts of two  congruent triangles are congruent]

Given : ΔABC  ≅  ΔMNO

Then , [tex]\angle{A}[/tex] corresponds [tex]\angle{M}[/tex] [First letter]

[tex]\angle{B}[/tex] corresponds [tex]\angle{N}[/tex] [Middle letter]

[tex]\angle{C[/tex] corresponds [tex]\angle{O}[/tex] [last letter]

Then , by CPCTC, we have

[tex]\angle{B}\cong\angle{N}[/tex]

Hence, angle B is the corresponding angle which is congruent to angle N.

Answer:

z = -0.5

Step-by-step explanation:

Using exponent rule:

[tex]x^a = x^b[/tex] then a = b

Given the equation:

[tex]25^{z+2} = 125[/tex]

We can write 25 and 125 as:

[tex]25 = 5 \cdot 5 = 5^2[/tex]

[tex]125 = 5 \cdot 5 \cdot 5 = 5^3[/tex]

then;

[tex]5^{2(z+2)}= 5^3[/tex]

Apply the rule:

[tex]2(z+2) = 3[/tex]

using distributive property [tex]a \cdot (b+c) = a\cdot b+ a\cdot c[/tex]

[tex]2z+4 = 3[/tex]

Subtract 4 from both sides we have;

[tex]2z = -1[/tex]

Divide both sides by 2 we have;

z = -0.5

Therefore, the solution for the given equation is, z = -0.5

integers, polynomials and whole numbers

The average speed of an object is computed as follows,

[tex]v=\frac{d}{t}[/tex] , where [tex]d[/tex] is the distance covered in the time interval of interest and  [tex]t[/tex]  is the time taken  to cover the distance.

In this problem, the distance covered is

[tex]d= 3\frac{1}{6} km =\frac{19}{6} km.[/tex] as an equivalent fraction.

The time taken for the journey is

[tex]t=\frac{1}{4} hour.[/tex].

The avarage is speed is then,

[tex]v=\frac{d}{t}[/tex]

[tex]v=\frac{(19/6)km}{(1/4)h} =\frac{19\times 4 km}{6\times 1h} =\frac{38km}{3h} = 12.67km/h.[/tex]

To find the difference between the larger of x1 and x2 and the smaller of y1 and y2, you first identify these respective values using max and min functions. Then, simply subtract the smaller value from the larger one.

To solve this problem, we first identify the larger value between x1 and x2, and the smaller value between y1 and y2. We can do this by using the 'max' function for the variables x1 and x2 and the 'min' function for y1 and y2. Once we have identified these values, we then compute the difference between the larger of x1 and x2 and the smaller of y1 and y2. This concept is based on comparison operations in mathematics.

Here is how it would look like in a programming context:

int larger = Math.max(x1, x2);

int smaller = Math.min(y1, y2);

int difference = larger - smaller;

where 'difference' is the answer you are looking for.

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