A hiker walks 3.3km at an angle of 40 degrees north of west. Then, the hiker walks 3.4km at an angle of 60 degrees north of west. What is the hiker's total displacement

Answers

Answer 1

Answer

6.6 km

The description of the problem is shown in the attached figure, where the line "d" represents the final displacement vector.

First, the trekker walked 3.3km in a 40 ° direction, as shown in the figure. We can write this vector in its Cartesian coordinates:

[tex]-3.3sin (40)x + 3.3cos (40)y[/tex]

Then the hiker walked 3.4 km in a 60 degree northwest direction.

We can write this as a vector in its Cartesian coordinates:

[tex]-3.4sin (60)x + 3.4cos (60)y[/tex].

When adding this two vectors we will obtain the final displacement "d"

[tex]d = [- 3.3sin(40) -3.4sin (60)]x + [3.3cos(40) + 3.3cos (60)]y\\[/tex]

[tex]d = -5.07x +4.23y\\[/tex]

To obtain the magnitude of this vector we calculate its module:

[tex]\sqrt{5.07 ^2 +4.23 ^ 2}[/tex]

Then the magnitude of the final displacement was:

6.6 km

A Hiker Walks 3.3km At An Angle Of 40 Degrees North Of West. Then, The Hiker Walks 3.4km At An Angle

Related Questions

if an object of mass 6 kg has an acceleratoon of 9 m/s2, what is the unbalanced force acting on it?

Answers

So long as an object is accelerating, it means there is an unbalanced force acting on it.

Force = mass * acceleration
F = ma
F = (6)(9)
F = 54N

Which position-time graph matches the velocity-time graph?

Answers

Answer:

b

Explanation:

cuz i no

Final answer:

The slope of the position-time graph represents the corresponding velocity - this relationship forms the basis for the creation of a velocity-time graph. Positive slopes on the position-time graph mean forward motion and negative slopes mean backward motion which is graphically represented as positive and negative slopes on the velocity-time graph respectively.

Explanation:

The position-time graph and the velocity-time graph are closely related. The slope of the position-time graph at any given point represents the velocity at that point in time. For example, if you have a straight line on a position-time graph which has a positive slope, it means the object is moving in a positive direction or forward. Therefore, the velocity-time graph for the same object would also have a straight line with positive slope.

A similar concept applies if the slope on the position-time graph is zero, it means the velocity at that time is zero and this would be represented as horizontal line on the velocity-time graph. Another interesting aspect is, if the slope of a position-time graph is negative, it means the object is moving in a negative or backward direction and the corresponding a velocity-time graph would have a negative slope.

It’s notable that straight lines on velocity-time graphs indicate constant velocity, whereas lines with positive or negative slope indicate acceleration or deceleration respectively.

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An unbalanced force of 500 N is applied to a 75 kg object. What is the acceleration of the object?

Answers

1. Define Newtons second law of motion (this will help put things into perspective)

2.Get the mass of the object (in this case 75 kg)

3.The net force acting on the object...find it (in this case 500 N)

4.Change the equation to F=ma (500=75a)

5.Divide both sides by 75 and that is the acceleration.

Answer:

Acceleration, [tex]a=6.66\ m/s^2[/tex]

Explanation:

Given that,

Force acting on the object, F = 500 N

Mass of the object, m = 75 kg

We need to find the acceleration of the object. The force acting on the object is given by :

[tex]a=\dfrac{F}{m}[/tex]

[tex]a=\dfrac{500\ N}{75\ kg}[/tex]

[tex]a=6.66\ m/s^2[/tex]

So, the acceleration of the object is [tex]6.66\ m/s^2[/tex]. Hence, this is the required solution.

knowimg all about the moon has less mass than earth, what do you think happenes to objects on the moon.(they fall at the same rate as they do on earth)(they fall slower)(they dont fall)(they fall faster

Answers

They fall slower. Hope this helped :)

What I think happens, is that the object tends to FALL SLOWER.  

(Eg.  A heavy Rock thrown in the water.).






Hope that helps!!!!!                                      : )

Please explain your answer when you found the answer (Only question number 9)

Answers

With a uniform acceleration of 2 m/s ²

A 55 kg block needs to be lifted 30m. Once lifted, what is the block’s potential energy?

Answers

Mass of block = 55kg

Height   = 30m

Block's potential energy at height of 30 m=/

As

Potential energy = mgh

g=9.8m/sec²

So P.E= (55kg)(9.8m/sec²)(30m)

P.E= 16170 kgm²/sec²

P.E= 16170 joules

Final answer:

The potential energy of the 55 kg block that is lifted 30 m can be calculated using the formula: Potential Energy = mass x gravity x height. Plugging in the values, the potential energy of the block is 16,170 Joules.

Explanation:

The potential energy of a block lifted to a certain height can be calculated using the formula:

Potential Energy = mass × gravity × height

Given that the mass of the block is 55 kg, the acceleration due to gravity is 9.8 m/s2, and the height is 30 m, we can plug in these values to calculate the potential energy of the block:

Potential Energy = 55 kg × 9.8 m/s2 × 30 m = 16,170 J

Therefore, the potential energy of the block is 16,170 Joules.

An 80.0-kg object is falling and experiences a drag force due to air resistance. The magnitude of this drag force depends on its speed, v, and obeys the equation Fdrag=(12.0N⋅s/m)v+(4.00N⋅s2/m2)v2. What is the terminal speed of this object?

Answers

Answer:

 Terminal velocity of object = 12.58 m/s

Explanation:

 We know that the terminal velocity is attained when drag force and gravitational force are of the same magnitude.

Gravitational force = mg = 80 * 9.8 = 784 N

Drag force = [tex]12.0v+4.00v^2[/tex]

Equating both, we have

    [tex]784=12.0v+4.00v^2\\ \\ v^2+3v-196=0\\ \\ (v-12.58)(v+15.58)=0[/tex]

  So v = 12.58 m/s or v = -15.58 m/s ( not possible)

 So terminal velocity of object = 12.58 m/s    

Several hormones are released during puberty. What are these hormones? How do they impact a teenager during puberty? Justify your answer.

Answers

For Girls it's called estrogen
For boys it's testosterone
They each do different things to the sex and they each come at different time periods of their lives.

An object is moving with a constant velocity of 278m/s. how long will it take to travel 7500m

Answers

Velocity = 278m/s

Distance = 7500m

Time = How long it takes?

Time = Distance/Velocity = 7500m ÷ 278m/s = 26.98 seconds (Rounded up to nearest two decimal places)


how is the chemical symbol of an element determined?

Answers

The number of protons defines what element it is and also determines the chemical behaviour of the element. ... Atomic symbol: The atomic symbol (or element symbol) is an abbreviation chosen to represent an element ("C" for carbon, "H" for hydrogen and "O" for oxygen)
Final answer:

The chemical symbol of an element is determined by its name in English or Latin, with the first letter used to create a one or two-letter symbol. The symbols are standardized by IUPAC.

Explanation:

The chemical symbol of an element is determined based on its name in English or Latin. The first letter of the element's English or Latin name is used to create a one or two-letter symbol. If the symbol has two letters, the first letter is capitalized and the second letter is lowercase.

For example, the symbol for Hydrogen is H, Oxygen is O, Carbon is C, and Gold is Au. In some cases, symbols are derived from the element's Latin name, such as Sodium (Na) from Natrium and Potassium (K) from Kalium.

This system of chemical symbols was established by the International Union of Pure and Applied Chemistry (IUPAC) to provide a standardized representation for elements across different languages and countries.

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Jenny wants to determine if a new brand name washing detergent is better than her old detergent she washed ten dirty t-shirts with the new washing detergent and ten dirty t-shirts with the old detergent identify the dependent and independent variables for this experiment

Answers

Answer:


Independent variable: washer detergent

Dependent varaible: cleaing power of effectivenes of the detergent.


Explanation:


When an experiiment is performed there exists one independent variable, one dependent variable, and some other variables that must be controlled.


The goal of the experiment is to test a hypothesis, which is a statement that relates an effect with a cause and that must be proved true or false.


The effect in the dependent variable, and the cause is the independent variable.


Jenny (the scientist) wants to show how an effect or phenomenun, the dependent variable, is explained by the explanatory, independent, variable.


In the stated experiment, Jenny wants to know how the effectiveness of a new brand detergent and an old one compare with each other. Therefore, she designs a test in which she will determine how the brand of detergent may  explain (explanatory or independent variable) the cleaning power or effectiveness, the dependent variable.


Jenny only can manipulate the independent variable and observe the effect on the dependent variable.


To be conclusive, other variables must be controlled, like the fabric and the amount of dirt of the t-shirts.

Dina is walking 0.5 m/s forward on a train that is traveling at 8.0 m/s north. What is Dina's velocity relative to the ground?

Answers

her velocity is 0.82012

Answer:

Dina's velocity relative to the ground is 7.5 m/s.

Explanation:

Given that,

Velocity of Dina v = 0.5 m/s

Velocity of train v' = 8.0 m/s

We need to calculate the Dina's relative velocity

Using formula of relative velocity

Relative velocity=velocity of train - velocity of Dina

[tex]v_{r}=v'-v[/tex]

Where, v' = Velocity of train

v = Velocity of Dina

Put the value into the formula

[tex]v_{r}=8.0-0.5[/tex]

[tex]v_{r}=7.5\ m/s[/tex]

Hence, Dina's velocity relative to the ground is 7.5 m/s.

What is the kinetic energy of a 478 kg object that is moving with the speed of 15 m/s

Answers

Kinetic energy = (1/2)*mass*velocity^2
KE = (1/2)mv^2
KE = (1/2)(478)(15)^2
KE = 53775J

The kinetic energy of the object is 53775 Joules.

Given the following data:

Mass = 478 kgVelocity = 15 m/s.

To find the kinetic energy of the object:

Kinetic energy is an energy that is possessed by a physical object or body due to its motion.

Mathematically, kinetic energy is calculated by using the formula;

[tex]K.E = \frac{1}{2} MV^2[/tex]

Where:

K.E is the kinetic energy.M is the mass of an object.V is the velocity of an object.

Substituting the values, we have;

[tex]K.E = \frac{1}{2}[/tex] × [tex]478[/tex] × [tex]15^2[/tex]

[tex]K.E = 239[/tex] × [tex]225[/tex]

Kinetic energy = 53775 Joules

Therefore, the kinetic energy of the object is 53775 Joules.

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Match the term with the definition. Match Term Definition Compressibility A) Measure of how much heat is given off when a substance is burned Flammability B) The ability of a substance to damage or harm an organism Heat of combustion C) Measure of how much the volume of matter can decrease under pressure Toxicity D) How easily a substance can be set on fire

Answers

oohhhhhhh i just figured this out

toxicity- B

heat of combustion- A

flammability- D

compressibility- C

Here are the matched terms with their corresponding definitions:

A) Compressibility: Measure of how much the volume of matter can decrease under pressure.

B) Flammability: How easily a substance can be set on fire.

C) Heat of combustion: Measure of how much heat is given off when a substance is burned.

D) Toxicity: The ability of a substance to damage or harm an organism.

What is Flammability ?

Flammability is a property of a substance that refers to how easily it can catch fire or ignite when exposed to an open flame, heat, or other sources of ignition. It is a measure of the substance's susceptibility to burning. Substances with high flammability are more likely to ignite and sustain combustion, while those with low flammability are less likely to do so.

Flammability is an important characteristic to consider in various contexts, including safety regulations, the handling and storage of chemicals, and the development of fire-resistant materials.

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It takes a car one minute to go from rest to 30 m/s east what is the acceleration of this car?

Answers

its .5m/s cause you divide it
follow me would appreciate it thanka

The acceleration of the car that when from rest to 30m/s in 1 minute is 0.5 m/s².

What is the acceleration of the car?

The first equation of motion is expressed as:

v = u + at

Given the data in the question:

Elapsed time t = 1 minutes = 1 × 60 = 60 seconds

Initial velocity u = 0

Final velocity = 30 m/s

Acceleration a =?

Plug the given values into the above formula and solve for the acceleration of the car.

v = u + at

30 = 0 + ( a × 60 )

30 = 0 + 60a

30 = 60a

a = 30/60

a = 3/6

a = 0.5 m/s²

Therefore, the acceleration is 0.5 m/s².

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Metals are used in many products because of the characteristic properties that most metals share. Which properties of the metal tungsten make it useful in the thin, glowing filaments of light bulbs? Tungsten is electrically conductive, ductile, and opaque. Tungsten is ductile, is malleable, and has a high luster. Tungsten is ductile, has a high melting point, and is electrically conductive. Tungsten has a high luster, has a high melting point, and is silver in color.Metals are used in many products because of the characteristic properties that most metals share. Which properties of the metal tungsten make it useful in the thin, glowing filaments of light bulbs? Tungsten is electrically conductive, ductile, and opaque. Tungsten is ductile, is malleable, and has a high luster. Tungsten is ductile, has a high melting point, and is electrically conductive. Tungsten has a high luster, has a high melting point, and is silver in color.

Answers

The most important characteristics that are exhibited by metals are-

1- Metals are ductile

2-Most metals are conductive in nature.

3-Most metals are malleable.

4- Metals have strong inter molecular force of attraction between the.

5-Metals have luster.

6-Metals are sonorous.

Here we are given Tungsten filament.

Tungsten is  a metal.So it must be conductive and as well as ductile in nature.

The electric filament that we are using in our electric bulb glows due to the heating effect of current.Hence the chosen substances for glowing electric bulb must have high melting point.

The melting point of tungsten is 1650 degree celsius which is very high.That's why it is used in electric bulb.

Hence the correct answer to the question is the third one i.e Tungsten is ductile,has a high melting point, and is electrically conductive.



Answer:

c) Tungsten is ductile, has a high melting point, and is electrically conductive.

Explanation:

i took the test

a net force of 500N acts on a 100 kg cart what is the acceleration

Answers

The formula is sum of the forces = Mass* Acceleration


If there is no friction (which i'm assuming not)

500N = 100 * A

A = 5 M/S/S (Or M/S^2)

An 1.0 kg mass book, initially at rest, is supported against a vertical wall, being pressed by a horizontal force of F 50 N module, as indicated in the figure. The acceleration of gravity has a modulus of 10.0m / s, the coefficient of static friction between the wall surface and the book is 0.25 and the coefficient of kinetic friction 0.20. Mark the correct statement.
a) The book slides along the wall and the modulus of the friction force is 10.0 N
b) The book remains at rest and the module of the normal force of contact between the book is the wall is 10N
c) The book remains at rest and the modulus of frictional force between the book and the wall is 12.5N.
d) The book remains at rest and the modulus of frictional force between the book and the wall is 10 N
e) The book slides along the wall and the module friction force is 12.5 N.

Answers

Você é brasileiro? Tú eres español?
Final answer:

By calculating the frictional force (0.25 * 50 N = 12.5 N), which is larger than the force of gravity on the book (10 N) we find that the book remains at rest against the wall. Hence, option c is correct.

Explanation:

This problem is about force and friction acting on a static object. To solve it, you first need to get the normal force acting on the book which is equal to the horizontal force pressing it against the wall (50 N). For a book to remain at rest the frictional force should be equal or greater than the weight of the book which is the mass times gravity, that is, 1 kg * 10 m/s^2 = 10 N.

The static frictional force between the book and the wall is calculated by multiplying the coefficient of static friction (0.25) and the normal force (50 N). This gives us a frictional force of 12.5 N which is greater than the weight of the book (10 N). Therefore the book remains at rest and doesn't slide along the wall. The correct statement hence is option c: The book remains at rest and the modulus of the frictional force between the book and the wall is 12.5N.

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3. Question
Classical mechanics is fundamentally based on?

1.Einsteins theory of relativity

2.Newton's Laws of Motion

3.The Universal Motion System

Answers

2. Newton's laws of motion

Hello!

Answer: Newton's Laws of Motion.

Explanation:

↓↓↓↓↓↓↓↓↓↓↓↓

Isaac Newton he performed many experiments involving light (optics). Then he published works on mathematics, history, calculus, and theology. And he published his most significant book, Philosophiae Naturalis Principia Mathematica, in 1687. Newton's first law of motion states that an object at rest stays at rest, and an object in motion stays in motion, unless acted on by an unbalanced force. This is also known as the law of inertia. Inertia is the natural tendency of objects to resist change in motion. Newton's second law of motion states that the total net force acting an object is equal to mass times acceleration. Newton's third law of motion states that for every action, there is an equal and opposite reaction. It considered action and reaction forces.

Hope this helps!

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-Charlie

Picking up a hot coal is an example of what type of heat transfer?

Conduction
Convection
Radiation
Transmission

Answers

That would be a conduction.

conduction

hope this helped


All the bats living in a cave form a _____ of bats in the cave ecosystem.

Answers

All the bats living in a cave form a __colony__of bats in the cave ecosystem.

Final answer:

The bats living in a cave form a population of bats within that cave ecosystem. The term 'population' in biology refers to all individuals of a particular species inhabiting a specific area. Factors such as diseases and resource exploitation can though impact a population.

Explanation:

All the bats living in a cave form a population of bats in that cave ecosystem. A population refers to all individuals of a species living within a specific area. For instance, the bats in a cave represent the population of bats in that particular cave. It's important to note that populations aren't static - they can be affected by various factors such as disease. For instance, the tragedy of the commons principle suggests that resources held in common, such as a cave, could potentially be overexploited, leading to population decline. A specific example is white-nose syndrome, a disease impacting bat populations that inhabit caves in the eastern United States and Canada.

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A few students in your class were probably able to exceed 1 hp of power output. how is this possible considering the fact that a horse is much stronger than a human?

Answers

They probably used a bike that is 1 hp

A ball is on a horizontal, flat plane at the orgin of your axis system at t0. the ball has an initial velocity of 1.30m/s along the + y axis and, starting at t0 recieves an acceleration of 2.10 m/s^2 in the + x direction. at t= 2.50s a) what is the position of the ball in terms of its x and y coordinates? b) what is the displacement of the ball? c) what is the velocity of the ball?

Answers

It sounds like the ball's velocity along the [tex]y[/tex]-axis should be taken to be constant, in which case the ball has velocity vector

[tex]\mathbf v(t)=\left(2.10\,\dfrac{\mathrm m}{\mathrm s^2}\right)t\,\hat{\imath}+\left(1.30\,\dfrac{\mathrm m}{\mathrm s}\right)\,\hat{\jmath}[/tex]

We note that at [tex]t=t_0[/tex], we're told the ball is at the origin, so its position at this point is [tex]\mathbf r(t_0)=\mathbf 0[/tex]. We then integrate the velocity vector to find the position vector:

[tex]\mathbf r(t)=\mathbf r(t_0)+\displaystyle\int_{\tau=t_0}^{\tau=t}\mathbf v(\tau)\,\mathrm d\tau[/tex]

[tex]\mathbf r(t)=\displaystyle\int_{\tau=t_0}^{\tau=t}\left(2.10\,\dfrac{\mathrm m}{\mathrm s^2}\right)\tau\,\hat{\imath}+\left(1.30\,\dfrac{\mathrm m}{\mathrm s}\right)\,\hat{\jmath}\,\mathrm d\tau[/tex]

[tex]\mathbf r(t)=\left(1.05\,\dfrac{\mathrm m}{\mathrm s^2}\right)\tau^2\,\hat{\imath}+\left(1.30\,\dfrac{\mathrm m}{\mathrm s}\right)\tau\,\hat{\jmath}\bigg|_{\tau=t_0}^{\tau=t}[/tex]

[tex]\mathbf r(t)=\left(1.05\,\dfrac{\mathrm m}{\mathrm s^2}\right)(t^2-{t_0}^2)\,\hat{\imath}+\left(1.30\,\dfrac{\mathrm m}{\mathrm s}\right)(t-t_0)\,\hat{\jmath}[/tex]

For the sake of simplicity, I'll assume [tex]t_0=0[/tex], so that

[tex]\mathbf r(t)=\left(1.05\,\dfrac{\mathrm m}{\mathrm s^2}\right)t^2\,\hat{\imath}+\left(1.30\,\dfrac{\mathrm m}{\mathrm s}\right)t\,\hat{\jmath}[/tex]

(a) Then at [tex]t=2.50\,\mathrm s[/tex], the ball's position in the plane is given by the vector

[tex]\mathbf r(2.50\,\mathrm m)=(6.56\,\mathrm m)\,\hat{\imath}+(3.25\,\mathrm m)\,\hat{\jmath}[/tex]

which is to say its position in the plane is at the point (6.56, 3.25).

(b) The ball's displacement is the same as its position, but in vector form (as above).

(c) The ball has velocity

[tex]\mathbf v(2.50\,\mathrm s)=\left(5.25\,\dfrac{\mathrm m}{\mathrm s}\right)\,\hat{\imath}+\left(1.3\,\dfrac{\mathrm m}{\mathrm s}\right)\,\hat{\jmath}[/tex]

That is, the ball has a speed of [tex]\|\mathbf v(2.50\,\mathrm s)\|=5.41\,\dfrac{\mathrm m}{\mathrm s}[/tex] and is traveling in a direction of about [tex]13.9^\circ[/tex] relative to the positive [tex]x[/tex]-axis.

Final answer:

At t=2.5s, the ball's position will be at coordinates (6.5625, 3.25), have a displacement of approximately 7.23 metres, and have a velocity of 5.25 m/s in the x direction and 1.3 m/s in the y direction.

Explanation:

The subject of this question is physics, specifically kinematics, and the topic is motion in two dimensions. We will calculate the x and y coordinates, the displacement, and the velocity for the given conditions. First we will calculate the x-coordinate using the equation of motion x = ut + 0.5at^2, where 'u' is initial velocity, 'a' is acceleration and 't' is time. Here, the initial velocity along x-axis is zero, acceleration is 2.10 m/s^2, and time is 2.5 s. Substituting these values, we get x = 0 + 0.5 * 2.1 * (2.5)^2 = 6.5625 m.

Next, for the y-coordinate, since there is no acceleration along y-axis, its position at any time is given by y = ut, where 'u' is initial velocity along y-axis, and 't' is time. So, y = 1.30 * 2.50 = 3.25 m.

Next, the displacement, which is the shortest distance from the initial to the final position, can be found using the Pythagorean theorem, d = sqrt(x^2 + y^2). Thus, d = sqrt((6.5625)^2 + (3.25)^2) = 7.23 m approximately.

Lastly, the velocity of the ball at any point is given by v = u + at, where 'a' is the acceleration along the x-axis, 't' is time and 'u' is the initial velocity (which is zero in this case along the x-axis). So, v = 0 + 2.1 * 2.5 = 5.25 m/s along the + x-direction. And, the velocity along the y-axis remains constant as 1.30 m/s because there's no acceleration in the y direction.

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How many times louder is a sound wave with an intensity of 50 dB than a sound wave with an intensity of 20 dB?

Answers

I believe it's 30dB louder but then again I'm not familiar with sound waves

What do you predict would happen if a person did aerobic exercise but did not work to build muscle?

Answers

Final answer:

If a person does aerobic exercise but does not work to build muscle, they may improve cardiovascular fitness and endurance, but may not see significant changes in muscle size or strength.

Explanation:

Doing aerobic exercise without working to build muscle can have several effects. Aerobic exercise primarily targets and improves cardiovascular fitness, which includes strengthening the heart and improving lung capacity. However, without resistance training, muscle mass and strength may not significantly increase. This means that while a person may improve their endurance and cardiovascular health, they may not see significant changes in muscle size or strength.

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A block of iron has the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. It has a mass of 213 g. When placed in water, the block sinks. What volume of water did it displace?
A. 27.0 cm3
B. 213 cm3
C. 7.89 cm3
D. 0.127 cm3

Answers

Answer:

The answer is A.

Explanation:

D = m/V  

Volume:  

3.00 x 3.00 x 3.00 = 27 cm³  

Answer A

The volume of the block is (3cm) · (3cm) · (3cm) = 27 cm³ .

That's how much water gets pushed out of the way when the block sinks in water. It makes no difference what the block is made of, or what its mass or density is.  Pick choice-A .

Galileo and Newton both studied the night sky. Galileo studied Jupiter and its moons. Newton studied the gravitational force that held the planets in orbit. Which of these statements best explains why the two scientists proposed different theories about the solar system?


Both had limited data.

Both had different interests.

They wanted to contradict each other's theory.

They wanted to be the first to discover new planets.

Answers

Both had different interests

Explanation :

Galileo studied Jupiter and its moons. Newton studied the gravitational force that held the planets in orbit.

Galileo constructed a telescope called Galileo's Telescopes. He also supported the Copernican theory.

Newton proposed the Universal law of gravitation. According to him, there exists a force between objects in the universe which is directly proportional to the product of masses and inversely proportional to the square of the distance between them.

i.e.

[tex]F=G\dfrac{m_1m_2}{r^2}[/tex]

So, we can say that the two scientists proposed different theories about the solar system. This shows that they both had different interests.

Is density a physical change, chemical change, physical property, or a chemical property?

Answers

density is a chemichal change

Final answer:

Density is a physical property of a substance, which can be observed and measured without changing the substance's chemical identity.

Explanation:

Density is a characteristic of a substance that refers to how much mass is contained in a given volume. It is considered a physical property because it can be observed and measured without changing the substance's chemical identity. Density can be particularly helpful in identifying substances and is measured in units such as grams per cubic centimeter (g/cm³) for solids and liquids or grams per liter (g/L) for gases.

Contrasting with physical properties are chemical properties, which describe how a substance can change or react to form new substances. These require a chemical change to be observed, such as rusting iron or burning wood, which both result in new chemical substances being formed.

Therefore, to answer the student's question, density is not a physical change, a chemical change, nor a chemical property; it is a physical property.

Which graph set-up would enable students to calculate instantaneous acceleration from the slope on the graph? a) Place distance on the x-axis and time on the y-axis b) Place time on the x-axis and distance on the y-axis c) Place speed on the x-axis and distance on the y-axis d) Place time on the x-axis and velocity on the y-axis

Answers

Instantaneous acceleration is defined as rate of change in velocity

it is given by the equation

[tex]a = \frac{dv}{dt}[/tex]

so here it shows that acceleration is always depends on change in velocity with time and now if we required this change in velocity with time for a small instant of time then it will be given by the slope of velocity and time graph.

So here the graph must be like this to find the slope of any graph we always use the concept that for any graph between y and x we use

[tex]slope = \frac{dy}{dx}[/tex]

if we compare it with the formula of acceleration above

then on Y axis we must have to draw the speed and on x axis we must have to draw the time

so correct answer must be

d) Place time on the x-axis and velocity on the y-axis

A team of eight dogs pulls a sled with waxed wood runners on wet snow (mush!). The dogs have average masses of 19.0 kg, and the loaded sled with its rider has a mass of 210 kg. (a) Calculate the acceleration of the dogs starting from rest if each dog exerts an average force of 185 N backward on the snow. (b) Calculate the force in the coupling between the dogs and the sled.

Answers

The acceleration of the dogs as they pull the sled on the snow is [tex]\boxed{4.09\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}}[/tex] . The force experienced by the sled due to the dogs is [tex]\boxed{859\,{\text{N}}}[/tex] .

Further Explanation:

As the dogs collectively full the sled on the wet snow surface, the sled will experience a net force due to all the dogs acting on it.

Part (a):

The net force applied by the 8 dogs on the sled is:

[tex]\begin{aligned}{F_{{\text{net}}}}&=8\timesF\\&=8\times185\\&=1480\,{\text{N}}\\\end{aligned}[/tex]

The net mass of the dog and the sled combined is:

[tex]\begin{aligned}M&=\left({8\times{m_d}}\right)+{m_s}\\&=\left({8\times19}\right)+210\\&=362\,{\text{kg}}\\\end{aligned}[/tex]

The net acceleration of the dogs and the sled combined is:

[tex]a=\frac{{{F_{net}}}}{M}[/tex]

Substitute the values of net force and mass in above expression.

[tex]\begin{aligned}a&=\frac{{1480}}{{362}}\\&=4.088\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}\\&\approx4.09\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}\\\end{aligned}[/tex]

Thus, the acceleration of the dogs as they pull the sled on the snow is [tex]\boxed{4.09\,{{\text{m}}\mathord{\left/{\vphantom {{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}}[/tex] .

Part (b):

Since the sled is moving with an acceleration of [tex]4.09\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}[/tex] , the net force experienced by the sled due to the pull of the dogs is:

[tex]{F_{sled}}={m_s}\times a[/tex]

Substitute the values in above expression:

[tex]\begin{aligned}{F_{sled}}&=210\times4.09\\&=858.9\,{\text{N}}\\&\approx{\text{859}}\,{\text{N}}\\\end{aligned}[/tex]

Thus, the force experienced by the sled due to the dogs is [tex]\boxed{859\,{\text{N}}}[/tex] .

Learn More:

1. A 30.0-kg box is being pulled across a carpeted floor by a horizontal force of 230 N https://brainly.com/question/7031524

2. A horizontal rope is tied to a 50 kg box https://brainly.com/question/2416204

3. Why is it important to define a frame of reference https://brainly.com/question/526888

Answer Details:

Grade: High School

Subject: Physics

Chapter: Newton’s law of Motion

Keywords:

Team of eight dogs, waxed wood runners, loaded sled, with its rider, acceleration, average force 185 N, coupling between dog and sled, average masses of 19 kg each.

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