A horizontal wooden beam sags a bit when supported at its ends. In between the top and bottom surfaces is a region of

Answer:

The answer of the question is None.

Answer:

Period is 1/20 of a second.

Explanation:

Frequency is 20 vibrations per second. Period and frequency are reciprocals (period = 1/f). Period is 1/20 of a second.

Answer:

Lightning strikes the empire state building at an average of about 23 times a year.

Explanation:

The Empire State Building is one of the tallest buildings in New York. Because of how high it stretches up into the sky, lightning strikes are quite common to it. This is because part of the building touches the clouds which are usually charged during thunder storms.

According to weather reports, and the Empire State Building website, lightning strikes the empire state building about 23 times a year on the average.

Answer:

The outer shell electrons in metals are free to move from atom to atln

Explanation:

Answer:

Will not.

Explanation:

just got the question correct.

Answer:

will not .

Explanation:

Tt will take approximately 0.14 seconds for the force of 2.5 N to bring the 0.25 kg object to rest from an initial velocity of 1.4 m/s

The question involves the application of Newton's second law of motion and the concepts of force, mass, acceleration, and time to bring an object to rest. Given a 0.25-kg object moving at 1.4 m/s, and a force of 2.5 N acting on it, we can first determine the acceleration using Newton's second law, F=ma, which gives us an acceleration of 10 m/s2. Next, we use the kinematic equation v = u + at (where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time) to find the time. Since the object comes to rest, v = 0 m/s, solving the equation for t gives us a time of 0.14 seconds to bring the object to rest.

Answer:

kinetic energy does not change

Explanation:

you can use the formula for the kinetic energy of the electron and for the radius of the trajectory of an electron in a uniform magnetic field:

[tex]E_k=\frac{1}{2}m_ev^2\\\\r=\frac{m_e v}{qB}[/tex]

me: mass of the electron

B: magnetic field

q: charge of the electron

r: radius

By doing v the subject of the formula and replace it in the expression for the kinetic energy you obtain:

[tex]v=\frac{rqB}{m_e}\\\\E_k=\frac{1}{2}m_e(\frac{rqB}{m_e})^2=\frac{r^2q^2B^2}{2m_e}[/tex]

as youcan see, all parameters r, q, B and me are constant.

hence, the kinetic energy does not change

Answer:

C) 4.4

Explanation:

The potential of a cylindrical capacitor is given by the formula:

[tex]V=\frac{2kq}{L\epsilon}ln(\frac{a}{b})\\\\\epsilon=\frac{2kq}{LV}ln(\frac{a}{b})[/tex]

where:

k : Coulomb Constant

L : length of the capacitor

a : outer radius

b : inner radius

V : potential

By replacing we obtain:

[tex]\epsilon=\frac{2(8.89*10^{9}N/m^2C^2)(8.8*10^{-6}C)}{(1m)(6000V)}ln(\frac{1.3mm}{1.1mm})=4.35[/tex]

Hence, the answer is C) 4.4 (4.35 is approximately 4.4)

hope this helps!!

The spacecraft had an angular acceleration of 0.00873 rad/s². At 6 minutes into the flight, a point on the skin of the spacecraft had a radial (centripetal) acceleration of 0.01167 m/s² and a tangential acceleration of 0.0371 m/s².

First, let's find the angular acceleration which is the rate of change of angular velocity. The spacecraft went from 0 to 1 revolution per minute in 12 minutes. This is an angular acceleration (α) of 1 rev/min/12 min = 1/12 rev/min². However, we generally measure angular acceleration in rad/s², not rev/min². We know that 1 revolution = 2π rad and 1 min = 60 s, so we can convert our units to get α = ((1/12 rev/min²) x (2π rad/rev) x (1 min/60 s)²) = 0.00873 rad/s².

Next, we find the radial (centripetal) and tangential components of linear acceleration at 6 minutes. At 6 minutes, the angular velocity (ω) is (α x t) = ((1/12 rev/min) x 6 min) = 0.5 rev/min. Convert this to rad/s: ω = ((0.5 rev/min) x (2π rad/rev) x (1 min/60 s)) = 0.05236 rad/s. Now, the radial or centripetal acceleration (a_r) is given by (ω² x r) and the tangential acceleration (a_t) is given by (α x r), where r is the radius of the spacecraft, which is half of the diameter or 8.5 m / 2 = 4.25 m. We can plug the numbers in to get: a_r = (ω² x r) = (0.05236 rad/s)² x 4.25 m = 0.01167 m/s² and a_t = α x r = 0.00873 rad/s² x 4.25 m = 0.0371 m/s². So, the radial acceleration is 0.01167 m/s² and the tangential acceleration is 0.0371 m/s².

https://brainly.com/question/32293403

#SPJ11

Answer:

The magnitude of the acceleration of the stone is 19.87 m/s²

Explanation:

Given;

mass of stone, m = 375 g = 0.375 kg

moment of inertia, I = 0.0125 kg.m²

radius of the pulley, r = 26 cm = 0.26 m

Torque generated by the pulley on the stone is given as;

τ = F x r = Iα

where;

F is applied force on the stone due to its weight

r is the radius of the pulley

I is moment of inertia

α is angular acceleration (rad/s²)

Force, F = mg = 0.375 x 9.8 = 3.675 N

Torque, τ = F x r

τ = 3.675 x 0.26

τ = 0.9555 N.m

τ = Iα

Angular acceleration, α = τ / I

α = 0.9555 / 0.0125

α = 76.44 rad/s²

Finally, determine linear acceleration, a,  in m/s²

a = αr

a = 76.44 x 0.26

a = 19.87 m/s²

Therefore, the magnitude of the acceleration of the stone is 19.87 m/s²

The stone's acceleration, calculated using Newton's second law for rotational and linear systems, and the relationship between linear and angular acceleration for a non-slip condition, is 3.53 m/s².

To determine the magnitude of the acceleration of the stone, we need to apply Newton's second law for rotational and linear systems. Specifically, we should set up equations for torque and force.

1. Sum of forces in the vertical direction (y-axis): T - mg = ma, where T is the tension in the string, m is the mass of the stone (0.375 kg), g is the acceleration due to gravity (9.81 m/s²), and a is the linear acceleration of the stone.

2. Sum of torques about the pulley's axis: τ = Iα, where I is the moment of inertia of the pulley (0.0125 kg · m²), α is the angular acceleration, and τ is the torque due to the tension (T·r, with r being the radius of the pulley).

Because the string unwinds without slipping, we have a relationship between linear and angular acceleration: a = αr.

Combining the equations, we can solve for the acceleration 'a' of the stone:

T = Iα/r = Ia/r²

So, T - mg = ma becomes:

Ia/r² - mg = ma

And by solving for 'a', we get:

a = ​(mg)/(m + I/r²)

Substituting the given values:

a = (0.375 kg × 9.81 m/s²)/(0.375 kg + 0.0125 kg m²/ (0.26 m)²) = 3.53 m/s²

Thus, the stone's acceleration is 3.53 m/s².

https://brainly.com/question/34744515

#SPJ12

Option (E) is correct

Neither (they arrive together)

Explanation:

Neither of the cylinders gets to the bottom first, they both will arrive together. Every object can gain speed with time if it is pushed, it is called the acceleration of that object. It the acceleration that decides which object reaches the bottom first.

Acceleration = I / mr^2.

In the case of both the cylinders, the acceleration will be the same, with the same acceleration they will reach the bottom at the same time.

Answer:

a white dwarf

Explanation:

A white dwarf, is otherwise known as a degenerate dwarf, it is a stellar core remnant which is mostly composed of electron-degenerate matter. A white dwarf is very dense, and has a mass which is comparable to that of the Sun, while its volume is comparable to that of Earth. It faint luminosity comes from the emission of stored heat energy; and no fusion takes place in a white dwarf

In 10 billion years, the solar system would be unrecognisable. The Sun would have become a white dwarf after expanding as a red giant.

If you returned to the solar system in 10 billion years, you'd likely find a vastly different environment from today. Given the current understanding of stellar evolution, the Sun, which is currently a main-sequence star, would have exited this phase. After going through a red giant phase, where it would have engulfed the inner planets, the Sun would have lost most of its outer material, leaving behind a white dwarf. This white dwarf would eventually cool and fade over time, becoming a black dwarf. Surrounding planetary bodies might be destroyed, transformed, or ejected from the solar system altogether due to the Sun's changes and the gravitational influences of other celestial bodies over such a vast period.

In this older universe, new star systems may have formed within the Milky Way from the abundant materials available in the galaxy. However, it's challenging to predict the exact state of the solar system due to numerous factors including potential asteroid impacts, close encounters with passing stars, or even interactions with interstellar objects. One thing is certain: the solar system as we know it will have undergone significant changes.

Answer:

Shares electrons

Answer:

becuase it is big

Explanation:

Answer:

Frequency, f = 59.6 kHz

Explanation:

Given that,

Speed of sound, v = 340 m/s

The bat can detect an insect that is 0.0057 m long, [tex]\lambda=0.0057\ m[/tex]

We need to find the minimum frequency of sound waves required for a bat to detect an insect. The speed of a wave is given by :

[tex]v=f\lambda\\\\f=\dfrac{v}{\lambda}\\\\f=\dfrac{340\ m/s}{0.0057\ m}\\\\f=59649.12\ Hz[/tex]

or

f = 59.6 kHz

So, the frequency detected by the bat is 59.6 kHz.

The minimum required frequency of the sound wave is 59.65 kHz

Given information:

speed of sound, v = 340 m/s

the wavelength of insect that the bat can detect, λ = 0.0057 m

The wavelength, frequency, and speed are related as follows:

v = fλ

The minimum frequency of sound wave required is:

f = v/λ

where f is the frequency of the sound

f = 340/0.0057 s⁻¹

f = 59649 Hz

or,

f = 59.65 kHz

So the frequency comes out to be 59.65 kHz

Learn more about frequency:

https://brainly.com/question/17196899?referrer=searchResults

Answer:

A C and D

Explanation:

Answer:

A C D

Explanation:

Final answer:

To determine the speed of an object attached to a horizontally lying spring on a frictionless surface at a specific stretch, we apply the law of conservation of energy and calculate the distribution of potential and kinetic energy at that point.

Explanation:

The subject of this question is Physics, and it involves a concept known as simple harmonic motion(SHM). To find the speed of the object at the instant when the spring is stretched by 0.041 m relative to its unstrained length, we can use the law of conservation of energy. In SHM, the total mechanical energy (sum of potential and kinetic energy) is conserved if there is no energy loss due to friction or other non-conservative forces.

At the compressed position (0.080 m from equilibrium), all the energy is potential, given by Ep = 1/2 k x2, where k is the spring constant and x is the displacement from equilibrium. At the position where the spring is stretched by 0.041 m, the energy will be partly potential and partly kinetic. The potential energy at this point is Ep = 1/2 k (0.041 m)2 and the kinetic energy is Ek = 1/2 m v2, where m is the mass and v is the velocity of the object.

Conservation of energy gives us:

1/2 k (0.080 m)2 = 1/2 k (0.041 m)2 + 1/2 m v2.

We can solve this equation for v, the speed at 0.041 m stretch, knowing the values of k, m, and x.

Answer:

Answer in explanation

Explanation:

In this question, we will be providing an explanation as to why OPMD provides more than 10^10 higher rate acceleration than CA

we proceed as follows;

Kcat is a measure of the catalytic activity of an enzyme indicating how many reactions a molecule of enzyme can catalyze per second. But Michaelis constant, Km also plays role during rate acceleration. The kcat/Km ratio is useful for comparing the activities of different enzymes. It is also possible to assess the efficiency of an enzyme by measuring its catalytic proficiency.

This value is equal to the rate constants for a reaction in the presence of the enzyme (kcat/Km) divided by the rate constant for the same reaction in the absence of the enzyme (kn). an enzyme with rapid binding might evolve a mechanism that favored a faster reaction.

An electric field around the OMPD active site enhances the rate of formation of the ES complex. Electrostatic effects allow OMPD to bind and remove OMPD much faster than expected from random collisions of enzyme and substrate.

Answer:

They will come back at the same time.

Explanation:

The angular velocity equation of ω[tex]= \frac{V}{r}[/tex] where ω is the frequency of the movement, dependent on the angle. But since swings are simple pendulums and their angles of 8 and 4 degrees are small, they will come back to their starting points at the same time.

I hope this answer helps.

Answer:

The bodies will not come back to their starting point at he same time.

Explanation:

Since they are both pulled back at an angle to the vertical, there is a tangential component of acceleration a = gsinθ

When θ = 4 , a = 9.8sin4 = 0.684 m/s²

When θ = 8 , a = 9.8sin8 = 1.364 m/s²

Using s = ut + 1/2at². Where s is the distance covered and t = time taken, u = initial speed = 0 (assumed since they are both released at the same time)

So s = 0 × t + 1/2at² = 1/2at²

s = 1/2at²

t = √2s/a. Now, since s is the same for both swings, it follows that

t ∝ 1/a. Since their accelerations are different, the bodies will not come back to their starting point at he same time.

Answer:

[tex]\Delta V=\frac{Q d}{A \epsilon_0}[/tex]

Explanation:

for the calculation of the electric potential inside a parallel plate capacitor you can use the formula for the electric field inside the capacitor.

[tex]\Delta V=V(d)-V(0)=\int_0^dEdx[/tex]

where d is the distance between plates and E is the electric field, which is given by:

[tex]E=\frac{\sigma}{\epsilon_0}[/tex]

By replacing you obtain:

[tex]\Delta V=E\int_0^ddx=Ed=\frac{\sigma d}{\epsilon_0}=\frac{Qd}{A\epsilon_0}[/tex]

where Q is the charge stored by the capacitor and A is the area of the plates.

hence, the answer is Qd/Ae0

The electric potential inside a parallel-plate capacitor is directly proportional to the amount of charge on the capacitor.

The electric potential inside a parallel-plate capacitor is directly proportional to the amount of charge on the capacitor. The magnitude of the electrical field between the plates is directly proportional to the charge, which means that the electric potential is also directly proportional to the charge.

https://brainly.com/question/31758890

#SPJ11

Answer:

Store chemical energy and transfer it to electrical energy when a circuit is connected.

Explanation:

A battery (single cell) is a container made of one cell that can produce a particular amount of electrical energy when needed.

It works by converting chemical energy to electric energy which is then used as a power source.

It stores up chemical energy and when connected to an external circuit, it provides electrical energy (through the flow of electrical current) to the circuit.

A battery is usually made up of a positive electrode and a negative electrode.

Answer:

3.528×10⁻⁸ V.

Explanation:

Electric Potential: This can be defined as the work done in an electric field in moving a unit charge from infinity to any point. The S.I unit of electric potential is Volt (V) or J/C.

From the question,

V = Fd................ Equation 1

Where V = Electric Potential, F = force experienced by the charge, d = distance.

Given: F = 3.6×10⁻⁴ N, d = 9.8×10⁻⁵ m.

Substitute into equation 1

V = 3.6×10⁻⁴( 9.8×10⁻⁵)

V = 3.528×10⁻⁸ V.

Wavelength = speed / frequency

(345 m/s) / (20,000 Hz) = 0.017 m

Formula to solve for the wavelength: w = s/f

w = wavelength

s = speed

f = frequency

Solve using the given values.

w = 345/20000

w = 0.01725

Round if necessary.

0.0173

Therefore, the wavelength is approximately 0.0173 meters.

Best of Luck!

Answer:

(A) Frictional force will be equal to 27.92 N

(B) Mass is equal to 33120 kg

Explanation:

(A) Diameter of nozzle d = 2.20 cm

So radius [tex]r=\frac{d}{2}=\frac{2.20}{2}=1.10cm[/tex]

eight h = 7.5 m

Density of water [tex]\rho =1000kg/m^3[/tex]

Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]

Pressure on the rubber stopper

[tex]P=\rho hg[/tex]

[tex]p=1000\times 7.5\times 9.8=73500Pa[/tex]

Area of cross section [tex]A=\pi r^2[/tex]

[tex]A=3.14\times 0.01^2=3.799\times 10^{-4}m^2[/tex]

So force [tex]F=PA[/tex]

[tex]F=73500\times 3.799\times 10^{-4}=27.92N[/tex]

(B) Speed of the water through nozzle

[tex]v=\sqrt{2gh}[/tex]

[tex]=\sqrt{2\times 9.8\times 7.5}=12.12m/sec[/tex]

Volume of water flow

[tex]V=vA=12.12\times 3.799\times 10^{-4}=0.0046m^3/sec[/tex]

Mass of water flow per sec

[tex]m=\rho V=1000\times 0.0046=4.6kg[/tex]

Total time t = 2 hour = 2×3600 = 7200 sec

So total mass flow

[tex]m=4.6\times 7200=33120kg[/tex]

To calculate the friction force exerted on the stopper by the nozzle, use Bernoulli's equation for fluid flow. To calculate the mass of water that flows from the nozzle, use the equation Q = A * V.

To calculate the friction force exerted on the stopper by the nozzle, we can use Bernoulli's equation for fluid flow. The pressure at the top of the tank is atmospheric pressure, and the pressure at the nozzle is also atmospheric pressure. The friction force can be calculated by the equation F = P * A, where P is the pressure difference and A is the cross-sectional area of the stopper.

To calculate the mass of water that flows from the nozzle in 2.00 hours, we can use the equation Q = A * V, where Q is the volumetric flow rate, A is the cross-sectional area of the nozzle, and V is the velocity of the water.

https://brainly.com/question/34457794

#SPJ11

According to the law of conversion of mass, the mass of a closed system is neither made or taken away in a physical change. It is the same for a chemical change as well.

Therefore, the mass of the substance remains 8g.

Best of Luck!

Answer:

[tex]E_n = \frac{kQ}{2} = 2E[/tex]

If the charge is doubled, the electric field is also doubled.

Explanation:

Electric field due to the negative charge is given as:

[tex]E = \frac{kQ}{r^2}[/tex]

where k = Coulomb's constant

Q = electric charge

r = distance between charge and point of consideration

At 2 m from the negative charge, the magnitude of the Electric field due to a negative charge -Q is given as E:

[tex]E = |\frac{-kQ}{2^2}| \\\\\\E = \frac{kQ}{4}[/tex]

If the charge is doubled, the new charge becomes -2Q and the new electric field becomes:

[tex]E_n = |\frac{-2kQ}{4}| \\\\\\E_n = |\frac{-kQ}{2}|[/tex]

[tex]E_n = \frac{kQ}{2} = 2E[/tex]

If the charge is doubled, the electric field is also doubled.

Answer:

E'=(1/4)E

Explanation:

The magnitude of the electric force is given by:

[tex]E=k\frac{q}{r^2}[/tex]

where k is the Coulomb constant (8.89*10^{9}Nm^2/C^2).

When the distance is r=2m we have:

[tex]E=k\frac{q}{(2m)^2}=k\frac{q}{4m^2}[/tex]

when the distance is doubled we obtain:

[tex]E'=k\frac{q}{(4m)^2}=k\frac{q}{16m^2}=\frac{1}{4}k\frac{q}{4m^2}=\frac{1}{4}E[/tex]

Hence, the new electric field is a quarter of the first electric field.

hope this helps!

Answer: GLOMERULUS

Explanation:

The specialized capillary bed responsible for the pressure that drives filtration is the

GLOMERULUS.

The kidney is an organ responsible for the excretion of nitrogenous wastes from the human body and osmoregulation of the blood and body fluids. The structure which is responsible for formation of urine is the nephron( kidney tubule). The GLOMERULUS are found within the Bowman's capsule of the nephrons. It is made up of specialised bundle of capillary beds which are the only capillary beds that are not surrounded by interstitial fluid in the body. In the glomerulus, blood pressure is high because an arteriole enters and exists the capillary beds which is responsible for the pressure that drives filtration.

The glomerulus, a specialized capillary bed in the kidney nephrons, creates pressure driving filtration, a process important for maintaining body homeostasis.

The specialized capillary bed responsible for the pressure that drives filtration is the glomerulus. This structure, located within the nephrons of the kidney, creates a pressure high enough to force substances such as water, glucose, and electrolytes out of the blood and into the nephron tubule, beginning the process of urine formation. The glomerular filtration process is an essential part of maintaining bodily homeostasis, i.e., keeping a stable internal environment in the body.

https://brainly.com/question/32157648

#SPJ6

Answer:

The water level rises more when the cube is located above the raft before submerging.

Explanation:

These kinds of problems are based on the principle of Archimedes, who says that by immersing a body in a volume of water, the initial water level will be increased, raising the water level. That is, the height in the container with water will rise in level. The difference between the new volume and the initial volume of the water will be the volume of the submerged body.

Now we have two moments when the steel cube is held by the raft and when it is at the bottom of the pool.

When the cube is at the bottom of the water we know that the volume will increase, and we can calculate this volume using the volume of the cube.

Vc = 0.45*0.45*0.45 = 0.0911 [m^3]

Now when a body floats it is because a balance is established in the densities, the density of the body and the density of the water.

[tex]Ro_{H2O}=R_{c+r}\\where:\\Ro_{H2O}= water density = 1000 [kg/m^3]\\Ro_{c+r}= combined density cube + raft [kg/m^3][/tex]

Density is given by:

Ro = m/V

where:

m= mass [kg]

V = volume [m^3]

The buoyancy force can be calculated using the following equation:

[tex]F_{B}=W=Ro_{H20}*g*Vs\\W = (200+730)*9.81\\W=9123.3[N]\\\\9123=1000*9.81*Vs\\Vs = 0.93 [m^3][/tex]

Vs > Vc, What it means is that the combined volume of the raft and the cube is greater than that of the cube at the bottom of the pool. Therefore the water level rises more when the cube is located above the raft before submerging.

Answer:

B

Explanation:

Answer:

12.27 ft/s

Explanation:

At 72 ft above the ground,  the balloons height increases at a rate of 4ft/s. For 66s, vertical distance moved, y = 4ft/s × 66 s = 264 ft. When the balloon is at 72 ft above the ground, just below it, the bicycle which moves at a rate of 12 ft/s in 66 s, covers a horizontal distance, x = 12ft/s 66 = 792 ft.

The distance between the bicycle and the balloon 66 s later is given by

s = √(x² + (y + 72)²) = √(792² + (264 + 72)²) = √(792² + 336²) = √740160 ft = 860.33 ft

From calculus

The rate of change of the distance between the balloon and bicycle s is obtained by differentiating s with respect to t. So,

ds/dt = (1/s)(xdx/dt + ydy/dt)

dx/dt = 12 ft/s, x = 792 ft, dy/dt = 4 ft/s, y = 264 ft, s = 860.33. These are the values of the variables at t = 66 s.

So, substituting these values into ds/dt, we have

ds/dt = (1/860.33)(792 ft × 12 ft/s + 264 ft × 4ft/s) = (1/860.33)(9504 + 1056) = 10560/860.33 = 12.27 ft/s

Coulomb's law and the universal law of gravity both have inverse-square relationships, involve a proportionality constant, and describe forces between two objects.

The factors that Coulomb's law and the universal law of gravity have in common are: