A Large school wants to put a clock in each of its 224 classrooms
The clocks are sold in packs of 14.
How many packs of clocks should the school buy?

Answers

Answer 1

Answer:

16 packs

Step-by-step explanation:

u just have to divide 224 by 14 to get 16

Answer 2

the school wants to get 224 clocks, they clocks come in packs of 14, so each pack has 14 clocks, how many packs are needed?

well, how many times does 14 go into 224? 224 ÷ 14, and you know what that is.


Related Questions

what can go in to 12 and 57?? ​

Answers

3 can go into both 12 and 57

24. SP6 - M
Jared has a spinner that is divided into four congruent sections (pictured below).
If he spins the spinner 500 times, which statement below is most likely to be true?
a. It will land on an even number exactly 250 times.
b. It will land on 1 approximately 100 times
C. It will land on a 2 or 3 approximately 400 times
d. It will land on 1 about 100 times

Answers

Answer:

No correct answer.

Step-by-step explanation:

C: 2 or 3 is  1/2 the probability. The expectation is that you should get about 250 readings that are either 2 or 3.

A is not correct. It will land on an even number about 250 times. What should happen in theory is far different than what will happen when you try it. Exactly is too confining a word.

B: It will land on 1 about 1 out of every 4 times. 1/4 * 500 = 125. So B is not right.

D: Same as B. There is no answer.  

what is 1/3 to the power of -4

Answers

First, to get applied by the fraction rule: [tex]\displaystyle\frac{3^4}{1}[/tex], then, the applied rule [tex]\displaystyle\frac{a}{1}=a[/tex]. Finally, simplify to find the answer. [tex]\displaystyle3^4=3*3*3*3=81[/tex], the correct answer is 81. I hope this will help you. Have a wonderful day!

[tex]\left(\dfrac{1}{3}\right)^{-4}=3^4=81[/tex]

(x+2) is one of the factors of the polynomial x³+13x²+32x+20. Find its remaining factors.

A little help....​

Answers

Answer:

x^2+11x+10

or

(x+1)(x+10) since you can factor x^2+11x+10

Step-by-step explanation:

Let's do synthetic division.

We are dividing by x+2, so -2 will be on the outside. Like this:

-2 |         1          13          32         20

   |                     -2        -22         -20

   |___________________________

             1          11           10            0

The remainder is 0, so (x+2) is indeed a factor of x^3+13x^2+32x+20.

The other factor we found by doing this is (x^2+11x+10).

You can find more factors by factoring x^2+11x+10.

Two numbers that multiply to be 10 and add to be 11 is 10 and 1 so the factored form of x^2+11x+10 is (x+10)(x+1).

Suppose 46% of American singers are Grammy award winners.

If a random sample of size 622 is selected, what is the probability that the proportion of Grammy award winners will be less than 47%? Round your answer to four decimal places.

Answers

Answer:

The probability that the proportion of Grammy award winners will be less than 47% is 0.6915

Step-by-step explanation:

* Lets explain how to solve the problem

- Suppose 46% of American singers are Grammy award winners.

- In a random sample of size 622 is selected

- We want to find the probability that the proportion of Grammy award

 winners will be less than 47%

* At first we must to calculate z

∵ [tex]z=\frac{P^{'}-P}{\sqrt{\frac{P(1-P)}{n}}}[/tex], where

# P' is the sample proportion

# n is the sample size

# P is probability of success

∵ The sample proportion is 47% = 47/100 = 0.47

∴ P' = 0.47

∵ The sample size is 622

∴ n = 622

∵ The probability of success is 46% = 46/100 = 0.46

∴ P = 0.46

∴ [tex]z=\frac{0.47-0.46}{\sqrt{\frac{0.46(1-0.46)}{622}}}=0.5004[/tex]

- P(P' < 0.47) = P(z < 0.5004)

∵ P(z < 0.5004) = 0.6915

∴ P(P' < 0.47) = 0.6915

* The probability that the proportion of Grammy award winners will

 be less than 47% is 0.6915

a portion of road A climbs steadily for 154 feet over a horizontal distance of 2200 feet. a portion of road B climbs steadily for 153 feet over a horizontal distance of 3400 feet. which road is steeper?

Answers

Answer:

Road A

Step-by-step explanation:

The slope of road A is:

154 / 2200 = 0.07

The slope of road B is:

153 / 3400 = 0.045

Road A has the larger slope, and is therefore steeper.

Final answer:

The steepness of a road is determined by the ratio of the vertical climb to the horizontal distance. By calculating this ratio for both Road A and Road B, we find that Road A, with a ratio of 0.07, is steeper than Road B, which has a ratio of 0.045.

Explanation:

The steepness of a road is determined by the ratio of the vertical climb to the horizontal distance. This is equivalent to finding the slope in mathematics. We can calculate this for both Road A and Road B:

For Road A, the slope can be calculated as rise over run, or 154 feet over 2200 feet, yielding approximately 0.07. For Road B, applying the same formula gives 153 feet over 3400 feet, resulting in a slope of about 0.045.

Comparing these two results, it is clear that Road A, with a slope of 0.07, is steeper than Road B, which has a slope of 0.045.

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Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).

Answers

Answer:

[tex]\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1[/tex]

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

[tex]\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1[/tex]

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is [tex]2a=|4--10|[/tex].

[tex]\implies 2a=|14|[/tex]

[tex]\implies 2a=14[/tex]

[tex]\implies a=7[/tex]

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is [tex](\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)[/tex]

We need to use the relation [tex]a^2+b^2=c^2[/tex] to find [tex]b^2[/tex].

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

[tex]c=|6--3|=9[/tex]

[tex]\implies 7^2+b^2=9^2[/tex]

[tex]\implies b^2=9^2-7^2[/tex]

[tex]\implies b^2=81-49[/tex]

[tex]\implies b^2=32[/tex]

We substitute these values into the standard equation of the hyperbola to obtain:

[tex]\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1[/tex]

[tex]\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1[/tex]

How is the pattern for a perfect square trinomial used to factor the trinomial?

Answers

Final answer:

A perfect square trinomial can be factored using the pattern x²+2ab+b²=(x+a)² or x²-2ab+b²=(x-a)². The term 'a' is the square root of the last term, and 'b' is half of the second term's coefficient.

Explanation:

In mathematics, a perfect square trinomial is a type of second-order polynomial or quadratic function with a specific form. It is used in the factorization process, particularly when solving quadratic equations of the form ax² + bx + c.

A perfect square trinomial is a trinomial in the form x²+2ab+b² or x²-2ab+b². To factor such a trinomial, the pattern (x+a)² or (x-a)² is used where 'x' is the variable, 'a' is the square root of the third term, and 'b' is half of the coefficient of the second term. Hence, x²+2ab+b² factors to (x+a)², whereas x²-2ab+b² factors to (x-a)².

Take for example, the trinomial x²+6x+9. Here, 'a' is 3 (as √9=3) and 'b' is 3 (as half of 6 is 3). Both 'a' and 'b' are equal so we know the trinomial is perfect square and it factors to (x+3)².

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The factor a perfect square trinomial, use the pattern [tex](a+b)^2[/tex] = [tex]a^2[/tex]  +2ab+  [tex]b ^{2}[/tex] and simplify .

The pattern for a perfect square trinomial is a helpful algebraic expression that represents the square of a binomial.

It takes the form [tex](a+b)^2[/tex] = [tex]a^2[/tex] +2ab+[tex]b ^{2}[/tex]  

where a and b are variables. When faced with a trinomial that fits this pattern, you can use it to factor the trinomial efficiently.

To factor a perfect square trinomial, compare it with the pattern. If the trinomial can be expressed in the form [tex](a+b)^2[/tex] =[tex]a^2[/tex]+2ab+ [tex]b ^{2}[/tex] , then it is a perfect square trinomial.

Identify [tex]a^2[/tex]  ,2ab and [tex]b ^{2}[/tex] terms in the trinomial.

Once identified, you can write the factored form as [tex](a+b)^2[/tex].  This means the trinomial can be factored as  [tex](a+b)^2[/tex] where a is the square root of the first term, and b is the square root of the last term.

This process is essentially reverse-engineering the expansion of the perfect square trinomial pattern.

Factoring using the perfect square trinomial pattern can save time compared to other methods, making it a valuable tool in algebraic manipulations and simplifying expressions.

   

Find the value of a in the picture

Answers

Answer:

= 52°

Step-by-step explanation:

The obtuse angle at O is twice the angle made at the circumference /by the same segment b.

=52×2=104°

The base angles that are made by isosceles triangle that has the apex with angle 104° equal to (180-104)/2=38°

The radii of a circle are equal and meet tangents at right angles.

Angle a= 90-38= 52°

Find the distance between the points (0,10) and (-9,1)

Answers

[tex]\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{10})\qquad (\stackrel{x_2}{-9}~,~\stackrel{y_2}{1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(-9-0)^2+(1-10)^2}\implies d=\sqrt{(-9)^2+(-9)^2} \\\\\\ d=\sqrt{81+81}\implies d=\sqrt{162}\implies d\approx 12.73[/tex]

Multiply 3/sqrt17- sqrt2 by which fraction will produce an equivalent fraction with rational denominator

Answers

Answer:

B.

Step-by-step explanation:

To simplify something that looks like [tex]\frac{\text{whatever}}{\sqrt{a}-\sqrt{b}}[/tex] you would multiply the top and bottom by the conjugate of the bottom. So you multiply the top and bottom for this problem I just made by:

[tex]\sqrt{a}+\sqrt{b}[/tex].

If you had  [tex]\frac{\text{whatever}}{\sqrt{a}+\sqrt{b}}[/tex], then you would multiply top and bottom the conjugate of [tex]\sqrt{a}+\sqrt{b}[/tex] which is [tex]\sqrt{a}-\sqrt{b}[/tex].

The conjugate of a+b is a-b.

These have a term for it because when you multiply them something special happens.  The middle terms cancel so you only have to really multiply the first terms and the last terms.

Let's see:

(a+b)(a-b)

I'm going to use foil:

First:  a(a)=a^2

Outer: a(-b)=-ab

Inner:  b(a)=ab

Last:    b(-b)=-b^2

--------------------------Adding.

a^2-b^2

See -ab+ab canceled so all you had to do was the "first" and "last" of foil.

This would get rid of square roots if a and b had them because they are being squared.

Anyways the conjugate of [tex]\sqrt{17}-\sqrt{2}[/tex] is

[tex]\sqrt{17}+\sqrt{2}[/tex].

This is the thing we are multiplying and top and bottom.

For this case we have the following expression:

[tex]\frac {3} {\sqrt {17} - \sqrt {2}}[/tex]

We must rationalize the expression, so we multiply by:

[tex]\frac {\sqrt {17} + \sqrt {2}} {\sqrt {17} + \sqrt {2}}[/tex]

So, we have:

[tex]\frac {3} {\sqrt {17} - \sqrt {2}} * \frac {\sqrt {17} + \sqrt {2}} {\sqrt {17} + \sqrt {2}} =\\\frac {3 (\sqrt {17} + \sqrt {2}} {17- \sqrt {17} * \sqrt {2} + \sqrt {17} * \sqrt {2} -2} =\\\frac {3 (\sqrt {17} + \sqrt {2}} {15}[/tex]

Thus, the correct option is option B.

Answer:

OPTION B

If g(x) = 3(x + 10), what is the value of the
function when x = -8?
O
-8
-2
24

Answers

Answer:

6 which is none of your answers.

Are you sure your function is right?

Is value to plug in x=-8?

Step-by-step explanation:

To find the value of the function at x=-8, you replace x with -8 in the function.

g(x)=3(x+10)

g(-8)=3(-8+10)

g(-8)=3(2)

g(-8)=6

g(-8) = 6.

The value of g(x) = 3(x + 10) when x = -8 is:

Substituting x = -8 in the function g(x)

g(-8) = 3 (-8+ 10)

Solving the operation in the  parenthesis

g(-8) = 3 (-8 + 10)

g(-8) = 3 (2)

Solving the multiplication

g(-8) = 6

is 5 a soluation to the equation? 3x(+1)=7(×-2)-3​

Answers

Answer:

x=5

Step-by-step explanation:

If the equation is:

3(x+1)=7(x-2) -3

Solution:

Multiply (x+1) by 3 and (x-2) by 7

3x+3 = 7x-14 -3

3x+3 = 7x -17

Now combine the like terms:

3+17 = 7x-3x

20 = 4x

Now divide both the terms by 4

20/4 = 4x/4

5 = x

You can write it as x=5

Thus the value of x is 5 ....

What is 8/2(2+2)
It’s one right?
If it’s not I’ll Be disappointed in humanity

Answers

Answer:

16

Step-by-step explanation:

8 / 2  * (2 + 2)

4 * (2 + 2)

4 * 4

16

Step-by-step explanation:

PEMDAS is ( Thank you google )

" PEMDAS is an acronym for the words parenthesis, exponents, multiplication, division, addition, subtraction. Given two or more operations in a single expression, the order of the letters in PEMDAS tells you what to calculate first, second, third and so on, until the calculation is complete."

First, 2 + 2 = 4

Second, 8 divided by 2 is 4.

Third, 4x4= 16

Therefore, the answer is 16.

Which expression can be used to determine the slope of the line that passes through the points (-7, 3) and (1,-97

Answers

Answer:

see explanation

Step-by-step explanation:

Calculate the slope m of the line using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 7, 3) and (x₂, y₂ ) = (1, - 97)

m = [tex]\frac{-97-3}{1+7}[/tex] = [tex]\frac{-100}{8}[/tex] = - [tex]\frac{25}{2}[/tex]

Convert each angle measure to Radion measure 45°

Answers

Answer:

[tex]\frac{\pi }{4}[/tex]

Step-by-step explanation:

To convert from degrees to radians

radian measure = degree measure × [tex]\frac{\pi }{180}[/tex]

given degree measure = 45°, then

radian = 45 × [tex]\frac{\pi }{180}[/tex] ( divide 45 and 180 by 45 )

           = [tex]\frac{\pi }{4}[/tex]

Answer:

π/4 radians.

Step-by-step explanation:

To convert to radians we multiply degrees by π/180.

So 45 degrees = 45 * π / 180

= π/4 radians.

choose the equation that represents a line that passes through points -3,2 and 2,1
5x+y=-13
5x-y=17
x-5y=-13
x+5y=7​

Answers

bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

[tex]\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-2}{2-(-3)}\implies \cfrac{1-2}{2+3}\implies -\cfrac{1}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-\cfrac{1}{5}[x-(-3)]\implies y-2=-\cfrac{1}{5}(x+3)[/tex]

[tex]\bf y-2=-\cfrac{1}{5}x-\cfrac{3}{5}\implies y=-\cfrac{1}{5}x-\cfrac{3}{5}+2\implies y=-\cfrac{1}{5}x+\cfrac{7}{5} \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{5}}{5(y)=5\left( -\cfrac{1}{5}x+\cfrac{7}{5} \right)}\implies 5y=-x+7\implies \blacktriangleright x+5y=7 \blacktriangleleft[/tex]

Final answer:

The equation of the line passing through points (-3,2) and (2,15) is calculated using the point-slope formula after calculating the slope. The derived equation is y = 2.6x + 7.8.

Explanation:

The question is asking to find the equation of the line that passes through two given points: (-3,2) and (2,15). To tackle this, firstly we need to calculate the slope (m) of the line, which is given by the formula: (y2 - y1) / (x2 - x1). Secondly, we apply the point-slope formula, y - y1 = m(x - x1), where (x1, y1) can be either point.

Now, calculating the slope using the given points, we find (15-2) / (2- (-3)) equals to 13/5 or 2.6. Next, we use the point-slope formula to write the equation. If using point (-3,2) we find y - 2 = 2.6 (x - (-3)). Thus, the equation for the line that passes through (-3,2) and (2,15) is y = 2.6x + 7.8 after simplifying the equation.

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What is the rate of change for this set of ordered pairs ?
X | 0 | 1 | 2 | 3 | 4
y | 7 | 12 | 17 | 22 | 27
A)2
B)2.5
C) 5
D)4

Answers

Answer:

Option C is correct.

Step-by-step explanation:

The rate of change can be found by finding the slope of given ordered pairs.

y₂=12, y₁=7,x₂=1,x₁=0

rate of change = y₂-y₁/x₂-x₁

rate of change = 12-7/1-0

rate of change = 5/1 = 5

Now considering next two points,

y₂=17, y₁=7,x₂=2,x₁=1

rate of change = y₂-y₁/x₂-x₁

rate of change = 17-12/2-1

rate of change = 5/1 = 5

So, the rate of change for this set of ordered pairs is 5.

Option C is correct.

What is the solution to the following equation?
3(x-4)-5= x-3

Answers

Answer:

x = 7

Step-by-step explanation:

[tex]3(x-4)-5=x-3\qquad\text{use the distributive property}\\3x-12-5=x-3\\3x-17=x-3\qquad\text{add 17 to both sides}\\3x-17+17=x-3+17\\3x=x+14\qquad\text{subtract}\ x\ \text{from both sides}\\3x-x=x-x+14\\2x=14\qquad\text{divide both sides by 2}\\\dfrac{2x}{2}=\dfrac{14}{2}\\\\x=7[/tex]

brianna is graphing the function f(x)=x^2+6x+5. what x intercepts should brianna use to graph f(x)

Answers

Answer:

x = - 5, x = - 1

Step-by-step explanation:

To find the x- intercepts let f(x) = 0, that is

x² + 6x + 5 = 0 ← in standard form

Consider the factors of the constant term (+ 5) which sum to give the coefficient of the x- term ( + 6)

The factors are + 5 and + 1, since

5 × 1 = 5 and 5 + 1 = + 6, hence

(x + 5)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 5 = 0 ⇒ x = - 5 ⇒ (- 5, 0 )

x + 1 = 0 ⇒ x = - 1 ⇒ (- 1, 0)

Answer:

-5 -1

Step-by-step explanation:

on edge

Question 3
1 pts
8 men and 6 women apply for a job at a new startup. How many
ways can 4 of the applicants be selected for a second interview?

Answers

Answer:

1001 ways

Step-by-step explanation:

Total number of people who applied for the job = 8 + 6 = 14

Number of people to be chosen = 4

This is a combination problem because the order of selection does not matter. A group selection involves the combinations. So here we have to find the combinations of 14 people taken 4 at a time. The formula for the combination is:

[tex]^{n}C_{r} = \frac{n!}{r!(n-r)!}[/tex]

Here, n is the total number of objects which is 14 in this case.

r is the number of objects to be chosen which is 4 in this case.

Using these values, we get:

[tex]^{14}C_{4}=\frac{14!}{4!(14-4)!}\\\\ = \frac{14!}{4! \times 10!}\\\\ =1001[/tex]

Thus, there are 1001 ways to select 4 applicants from 8 men and 6 women for the second interview.

Tangent wz and secant WV intersect at point W. Find the length of YV If necessary, round to the hundredths place.

A 2.67
B5
с.9
D. 10

Answers

Answer:

Option B. [tex]YV=5\ units[/tex]

Step-by-step explanation:

we know that

The Intersecting Secant-Tangent Theorem, states that If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment

so

In this problem

[tex]WZ^{2}=WV*WY[/tex]

substitute and solve for WV

[tex]6^{2}=WV*4[/tex]

[tex]WV=36/4=9\ units[/tex]

we have that

[tex]WV=WY+YV[/tex]

substitute

[tex]9=4+YV[/tex]

[tex]YV=9-4=5\ units[/tex]

What is the average rate of change for this quadratic function for the interval
from x= 2 to x = 4?​

Answers

Answer:

-6

Step-by-step explanation:

The average rate of a function f(x) on the interval from x=a to x=b is [tex]\frac{f(b)-f(a)}{b-a}[/tex].

So in the problem you have from [tex]x=2[/tex] to [tex]x=4[/tex].

The average rate of the function from x=2 to x=4 is

[tex]\frac{f(4)-f(2)}{4-2}=\frac{f(4)-f(2)}{2}[/tex].

Now we need to find f(4) and f(2).

f(4) means what is the y-coordinate that corresponds to x=4 on the curve.

f(4)=-15 since the ordered pair at x=4 is (4,-15).

f(2) means what is the y-coordinate that corresponds to x=2 on the curve.

f(2)=-3 since the ordered pair at x=2 is (2,-3).

So let's plug in those values:

[tex]\frac{f(4)-f(2)}{4-2}=\frac{-15-(-3))}{2}[/tex].

Now we just simplify:

[tex]\frac{-15+3}{2}[/tex]

[tex]\frac{-12}{2}[/tex]

[tex]-6[/tex]

For which rational expression is -5 an excluded value of x?

Answers

Ration expressions cause excluded values wherever the denominator equals zero.

So, for any expression like

[tex]h(x)=\dfrac{f(x)}{g(x)}[/tex]

-5 is an excluded value if [tex]g(-5)=0[/tex]

For example, the simplest one would be

[tex]h(x) = \dfrac{1}{x+5}[/tex]

In fact, if you try to evaluate this function at -5, you'd have

[tex]h(-5)=\dfrac{1}{5+5}=\dfrac{1}{0}[/tex]

which is undefined, and thus you can't evaluate the function, and thus -5 is an excluded value.

Answer:

6/x+5

Step-by-step explanation:

Step 1: Choose a point on the line, such as (2, 5).
Step 2: Choose another point on the line, such as (1, 3).
Step 3: Count units to determine the slope ratio. The line runs 1 unit to the right and rises 2 units up, so the slope is .
Step 4: Substitute those values into the point-slope form.

y – y1 = m(x – x1)

y – 3 = (x – 1)

Answers

Answer:

y-3=2(x-1)

Step-by-step explanation:

So it looks like your line goes through (2,5) and (1,3) based on what you have said.

Looking at 5 to 3, that is down 2.

Locking at 2 to 1, that is left 1.

So the slope is -2/-1 =2/1=2.

Plug in the (x1,y1)=(1,3) and slope=m=2.

So using point slope form we have y-3=2(x-1).

Answer:

Step 3

Step-by-step explanation:

Just did the test


Find my number, if it is the smallest four-digit number with all different digits.

Answers

I think the answer would 1023

Graph the system of equations on graph paper to answer the question.

{y=25x+4
{y=2x+12



What is the solution for this system of equations?

HELP PLS!!

Answers

Answer:

[tex]x = \frac{8}{23} \: \: \: \\ y = \frac{292}{23} [/tex]

Answer:

-5, 2

Step-by-step explanation:

I really need help with this I don’t understand

Answers

Answer:

Step-by-step explanation:

There is not possible solution in the real number system or the complex field.

Oddly, before I answer your question, I would point out that the equation given is a perfectly legitimate equation in some computer languages. It has the meaning of

Take the current value in memory location x Subtract 5 from it. Put the new result in memory location x.

But that is not what you are being asked about.

The blank you could put in 4

so 4 = 4 - 5

4 = - 1

The second blank will give you the result of 4 = - 1 which can't be true in a million years.

Find X. Round to the nearest tenth if necessary.

Answers

Answer:

3.2

Step-by-step explanation:

If there are 2 secont lines intersecting inside a circle like the picture shown, then the theorem tells us that "the product of 2 segments of one secant line is equal to the product of 2 segments of other secant line"

Thus, we can say that:

x * 10 = 8 * 4

10x = 32

x = 32/10

x = 3.2


Prove that the diagonals of a rectangle bisect each other.

The midpoint of BD is _____

Answers

Answer:

a,b

Step-by-step explanation:

in the rectangle when bisected

if mid point is taken as O

BO=OD

AO=OC

X=2a

mid point of X=2a/2=a

Y=2b

y mid point = b

The midpoint of BD will be ( a,b ) so option (C) will be correct.

What is a line segment?

A line section that can connect two places is referred to as a segment.

In other terms, a line segment is merely a section of a larger, straight line that extends indefinitely in both directions.

The line is here! It extends endlessly in both directions and has no beginning or conclusion.

The midpoint of a line associated with two coordinates is given by

(x₁ + x₂)/2 and (y₁ + y₂)/2

Given that B (0,2b) D (2a,0)

So midpoint

(0 + 2a)/2 and (2b + 0)/2

⇒ (a,b) so the midpoint will be this.

For more about line segment

https://brainly.com/question/25727583

#SPJ5

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