A light bulb does 100 joules of work in 2.5 seconds. How much power does it have.

Amy experiences less air resistance due to her smaller cross-sectional area compared to Josh, but as she has a lower mass, the air resistance has a more significant effect on her, making her more affected by air resistance.

To determine which cyclist, Amy or Josh, is more affected by air resistance, we can examine the force due to air resistance, which can be calculated using the formula:

Fd = (1/2)ρCdAv2

where Fd is the force of drag (air resistance), ρ is the air density (which we'll assume to be constant for both cyclists), Cd is the drag coefficient, A is the cross-sectional area, and v is the velocity.

Given that both cyclists have the same drag coefficient (Cd = 0.70) and are traveling at the same velocity (v = 15 m/s), the only variables that differ between the two are their cross-sectional areas. Since Amy has a smaller mass and a smaller cross-sectional area (A = 0.45 m2), the force of air resistance will be smaller in magnitude compared to Josh's due to his larger cross-sectional area (A = 0.60 m2).

However, air resistance's impact on an object is also related to the object's mass. A smaller force applied to a smaller mass can have a more significant effect than the same force applied to a larger mass. Therefore, even if the force of air resistance is absolutely higher for Josh, Amy, with her lower mass, would be more affected by it, as it would constitute a more substantial proportion of her total mass.

Answer:

[tex]27fm[/tex]

Explanation:

Kinetic Energy of proton

[tex]Kinetic Energy (K)=\frac{1}{2}mV^{2}[/tex]

[tex]m=Mass of proton[/tex]

[tex]V=Velocity of proton[/tex]

[tex]m=1.67\times 10^{-27} kg[/tex]

[tex]V=3.4\times 10^{7}ms^{-1}[/tex]

[tex]K=\frac{1}{2}\times 1.67\times 10^{-27}kg\times \left (3.4\times 10^{7}ms^{-1}  \right )^2[/tex]

[tex]K=\frac{19.305}{2}\times 10^{-13}J[/tex]

[tex]K=9.65\times 10^{-13}J[/tex]

For conservation of energy;

[tex]Kinetic Energy=Potential energy[/tex]

[tex]K= U[/tex]

So,

[tex]U= 9.65\times 10^{-13}J[/tex]

Here,

[tex]U=Potential Energy[/tex]

[tex]U=k_{e}\frac{q_{1}q_{2}}{r}[/tex]

Here,

[tex]k_{e}=Coulomb's law constant[/tex]

[tex]k_{e}=8.99\times 10^{9}Nm^{2}C^{-2}[/tex]

[tex]q_{1}=80e[/tex]

[tex]q_{2}=e[/tex]

[tex]e=1.602\times 10^{-19}C[/tex]

[tex]r=The distance that proton will stop from the center of the nucleus[/tex]

[tex]U=k_{e}\frac{80e\times e}{r}[/tex]

[tex]9.65\times 10^{-13}J=8.99\times 10^{9}Nm^{2}C^{-2}\frac{80\times1.6\times 10^{-19}\times1.6\times 10^{-19} }{r}[/tex]

[tex]r=8.99\times 10^{9}Nm^{2}C^{-2}\frac{80\times1.6\times 10^{-19}\times1.6\times 10^{-19} }{9.65\times 10^{-13}J}[/tex]

[tex]34fm[/tex]

[tex]r_{0}=Radius of the atom[/tex]

[tex]Radius\left ( r_{0} \right )=\frac{diameter\left ( d \right )}{2}[/tex]

[tex]Diameter of the nucleus of mercury atom=14fm[/tex]

[tex]Radius of atom =\frac{14fm}{2}[/tex]

[tex]r=7fm[/tex]

[tex]d=r-r_{0}[/tex]

[tex]d=34fm-7fm[/tex]

[tex]d=27fm[/tex]

Further Explanation:

When a proton approaches a nucleus, it decelerates. Because the repulsive electric field and its kinetic energy converts into electric potential energy.  

Then due to this, the proton will stop at a distance “r” from the center of the nucleus.  

To find the distance from the surface where the proton hits, we have to subtract the radius of the nucleus.  

Learn more:

1. Kinetic energy https://brainly.com/question/1621817 (answer by skyp)

2. Potential energy https://brainly.com/question/12489105 (answer by nitrotype2000)

3. Conservation of energy https://brainly.com/question/11911812 (answer by hrishisup)

Keywords:

Kinetic energy, potential energy, conservation of energy.  

Its D: A driver's foot on the accelerator and pressed down gradually more and more.

Answer:

Cyanobacteria.

Explanation:

The oldest forms of life would be considered the cyanobacteria from the options, this bacteria are called extremists because they can survive in environments with littlo to zero oxygen andis thought that they have been present from the early begining of the universe because they are the only living organisms known to mankind that are able to survive under those conditions.

To find the equilibrium concentration of Cl2 in the decomposition of PCl5, we start with initial concentrations, assume x is the change at equilibrium, and apply the equilibrium expression using Keq = 2.24 x 10^-2. Solving this for x yields the equilibrium concentration of Cl2, showing whether reactants or products are favored.

To determine the equilibrium concentration of Cl2 when PCl5 decomposes into Cl2 and PCl3, we can start with the provided concentrations and use the equilibrium constant (Keq).

The equilibrium equation for this decomposition is:
PCl5(g) \<=> Cl2(g) + PCl3(g)
and the given Keq is 2.24 x 10-2 at 327°C.

Let's assume x is the amount of PCl5 that decomposes to form x moles of Cl2 and x moles of PCl3 at equilibrium:

At equilibrium, we will have:

The Keq expression is:

Keq = [PCl3][Cl2] / [PCl5]

Plugging in the equilibrium concentrations:

2.24 x 10-2 = ((0.174 + x) × x) / (0.235 - x)

This equation can be solved for x to find the equilibrium concentration of Cl2. With the calculated value of x, it is possible to determine the favorability of the reaction. A small Keq value (< 1) typically indicates that reactants are favored, which suggests in this case, PCl5 would be favored at equilibrium.

The equivalent capacitance of the number of capacitance connected in the parallel series is the sum of  the individual capacitance.

The capacitance of each capacitor is [tex]2.1\times10^{-5}\rm F[/tex].

The equivalent capacitance of the number of capacitance connected in the parallel series is the sum of  the individual capacitance.

It can be given as,

[tex]C_{eq}=\dfrac{Q}{V}[/tex]

Here, [tex]Q[/tex] is the charge and [tex]V[/tex] is the voltage.

Given information-

The voltage of the battery is 5.55 V.

The value of charge is [tex]3.45\times10^{-4}[/tex] C.

Put the values in the above formula as,

[tex]C_{eq}=\dfrac{3.45\times10^{-4}}{5.55}\\C_{eq}=6.4\times10^{-4}\rm F[/tex]

Given that the three uncharged capacitors with equal capacitance are combined in parallel.

For the parallel connection of the capacitance the equivalent capacitance can be given as,

[tex]C_{eq}=C+C+C[/tex]

Here, [tex]C[/tex] is the capacitance of each capacitors. Put the values,

[tex]6.4\times10^{-4}\rm =3C\\C=2.1\times10^{-5}\rm F[/tex]

Hence the capacitance of each capacitor is [tex]2.1\times10^{-5}\rm F[/tex].

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Answer:

The two metals absorb different amounts of thermal energy.

Explanation:

Temperature controlling device in an electric equipment like a heater, is called a thermostat.

A bimetallic strip contains two different metals. Each metal has its own characteristic property of expansion or cooling. Coefficient of thermal expansion has a different value for different metals.

The metal that has a higher expansion coefficients will expand more when  heated, compared to the metal that has a lower coefficient of expansion.

In a thermostat used in a heating circuit, the electric contact is cut off due to the bending of the bimetallic strip, when the desired temperature is reached.

The amount of kinetic energy gained after it has moved 0.5 m is calculated as [tex]4\times10^{-15}\ J[/tex].

Given:

Electric field, [tex]E = 50000\ V/m[/tex]

Displacement, [tex]d= 0.5\ m[/tex]

Kinetic energy is a term used in physics to refer to the energy that an item has as a result of motion. It's a fundamental idea that explains how an object's motion and energy state are connected.

The particle physics community frequently refers to energy in terms of electron volts , especially when addressing the energies of atomic and subatomic particles. An electron is said to have one electron volt of kinetic energy when it accelerates through an electric potential difference of one volt.

The kinetic energy is given as:

[tex]KE = eV\\KE = e\timesE\timesd\\KE = 1.6\times10^{-19}\times50000\times0.5\\KE = 4\times10^{-15}\ J[/tex]

Hence, the amount of kinetic energy gained after it has moved 0.5 m is calculated as [tex]4\times10^{-15}\ J[/tex].

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The kinematic we find the average acceleration of the body is 7 m/s²

Given parameters

           t₂= 6.0 s,  v₂ = 4.0 m / s

To find

Kinematics studies the movement of the carpus, establishing relationships between their position, speed and acceleration.

Average acceleration is defined as the change in velocity in a given time interval

             a_ {avg} = [tex]\frac{\Delta v}{\Delta t}[/tex]

Let's apply this expression to our case

let's set a reference frame where the positive direction of the x axis is positive, so v₁ is negative

             a_ {avg} = [tex]\frac{v_2 -v_1}{t_2 -t_1}[/tex]

             a_ {avg} = [tex]\frac{4- (-3)}{6-5}[/tex]

             a_ {avg} = 7 m / s²

In conclusion using kinematics we find the average acceleration of the body is 7 m / s²

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Answer: D.

Explanation: Glucose levels are only option that relates to realistic diagnosis

Rest of the answers-

a DNA analysis to identify genetic abnormalities

a physical exam to look for tumors

a study to observe David’s social behaviors

a test to check David’s glucose levels

Answer:

B) because it slows down, which causes it to bend

Explanation:Light hits the glass in a lens because it slows down, which causes it to bend. The material of a lens is more optically dense than the air it is traveling from.

Answer: The correct answer is option C.

Explanation:

Kinetic energy is the energy possessed by the an object due to its motion.An its calculated by:

[tex]K.E.=\frac{1}{2}mass\times (velocity)^2[/tex]

Kinetic energy depends upon the mass and velocity of the an object.

So, Paul can increase the bike's kinetic energy by increasing the velocity of its bike. Hence, the correct answer is option C.

Increasing the mass will also increase the kinetic energy . But according to option (D) he has to stop the bike first by applying brakes which will reduce the kinetic energy of the bike.And then again have to perform the work to bring the bike in motion

Answer:

Before jumping from the plane, the skydiver has potential energy. When the skydiver jumps, the potential energy is transformed into kinetic energy, which increases until the skydiver reaches terminal velocity. Potential energy is then transformed into thermal energy.

Explanation:

Thats the answer

The value of the horizontal force acting on the rod is 10 N. Therefore option (C) is correct.:

Given data:

The weight of rod is, W = 10.0 N.

The angle made by force with respect to horizontal is, [tex]\theta = 30^\circ[/tex].

To maintain the steady position (equilibrium condition), the vertical component of force F must be balanced by the moment of force due to weight.

Therefore,

[tex](Fsin\theta) \times L = W \times \dfrac{L}{2} \\\\(F \times sin30^{\circ}) = \dfrac{10}{2} \\F = 10 \;\rm N[/tex]

Thus, the value of the horizontal force acting on the rod is 10 N. And option (C) is correct.

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Answer:

19

Explanation:

Fluorine-19.

The isotope of fluorine with 9 protons and 10 neutrons is named Fluorine-19. This is because the mass number of an isotope equals the sum of its protons and neutrons, and in this case, 9 (protons) + 10 (neutrons) = 19. The atomic number of fluorine is 9, which means any atom of fluorine will always have 9 protons. A normal (most commonly occurring) atom of fluorine also has a mass number of 19, deriving from 9 protons and 10 neutrons. This makes Fluorine-19 the only stable and naturally-occurring isotope of fluorine.

Answer: Horizontal component of arrow :40.955 m/s

Vertical component of arrow :28.675 m/s

Explanation:

The initial speed of the arrow = u = 50 m/s

The horizontal component of the arrow =[tex]u_x=u\cos\theta [/tex]

The horizontal component of the arrow =[tex]u_y=u\sin\theta [/tex]

Angle between the velocity vector and x component = 35°

Horizontal component of arrow :

[tex]\cos\theta=\frac{u_x}{u}[/tex]

[tex]\cos35^o=0.8191=\frac{u_x}{50}[/tex]

[tex]u_x=0.8191\times 50=40.955 m/s[/tex]

Vertical component of arrow :

[tex]\sin\theta=\frac{u_y}{u}[/tex]

[tex]\sin35^o=0.5735=\frac{u_y}{50}[/tex]

[tex]u_y=0.5735\times 50=28.675 m/s[/tex]

Horizontal component of arrow :40.955 m/s

Vertical component of arrow :28.675 m/s

Answer:

Net horizontal force, [tex]F_{net}=231.5\ N[/tex]

Explanation:

It is given that,

Mass of the box, m = 50 kg

The coefficient of kinetic friction between the box and the ground is 0.35, [tex]\mu=0.35[/tex]

Acceleration of the box, [tex]a=1.2\ m/s^2[/tex]

We know that the frictional force acts in opposite direction to the direction of motion. The net force acting on it is given by :

[tex]F_{net}=f+ma[/tex]

[tex]F_{net}=\mu mg+ma[/tex]

[tex]F_{net}=m(\mu g+a)[/tex]

[tex]F_{net}=50\times (0.35\times 9.8+1.2)[/tex]

[tex]F_{net}=231.5\ N[/tex]

So, the net force acting on the box is 231.5 N. hence, this is the required solution.

Explanation:

Radius of earth, r = 4000 miles

Angular velocity is the ratio of linear velocity and radius.

         [tex]\omega =\frac{v}{r}[/tex]

Linear distance from Kampala to Singapore = 5000 miles

Time taken = 8.3 hours

         Distance = Time x Velocity

         5000 = 8.3 x Velocity

         Velocity, v = 602.41 mph

Substituting in angular velocity equation

        [tex]\omega =\frac{v}{r}=\frac{602.41}{4000}=0.15rad/hr[/tex]

Plane's angular velocity relative to the earth's surface = 0.15 rad/hr

The plane's angular velocity in hours can be calculated using the angle in radians covered in one hour's flight and the Earth's radius, applying the formula for angular velocity.

To find the plane's angular velocity relative to the Earth's surface, we need to calculate how many radians the plane covers in an hour and then convert this to angular velocity in degrees per hour. The formula for angular velocity (ω) is ω = θ / t, where θ is the angle in radians and t is the time in seconds. Given that the Earth's circumference is approximately 24,900 miles, we can determine the angle by using the proportion θ / (2π) = distance / Earth's circumference. With the plane's distance being 5000 miles and the Earth's radius being 4000 miles, we use the arc length formula s = rθ, where s is the arc length (5000 miles), r is the radius of the Earth (4000 miles), and θ is the angle in radians. Solving this for θ gives us θ = s / r.

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The magnitude of the charge on each plate of a 4.50 μF capacitor connected to a 12.0 V battery is 54 μC.

To find the magnitude of charge stored on each plate of a capacitor when a voltage is applied, you can use the formula Q = CV, where Q is the charge, C is the capacitance, and V is the voltage applied. Given a capacitor with a capacitance (C) of 4.50 μF and a voltage (V) of 12.0 V, we can calculate the charge (Q) as follows:

Q = CV = (4.50 μF) (12.0 V) = (4.50 × 10-6 F) (12.0 V) = 54 × 10-6 C = 54 μC

Therefore, the magnitude of the charge on each of the plates of the capacitor is 54 μC.

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To find the charge stored on a capacitor with given capacitance and voltage, use the formula Q = C × V. Substituting 4.50 μF and 12.0 V into the equation yields a charge of 5.40 × 10⁻⁵ C on each plate.

To determine the charge stored on a capacitor's plates, we use the formula:

Q = C × V

Where:

In this case, we have a capacitance C = 4.50 μF (which is 4.50 × 10⁻⁶ F) and a voltage V = 12.0 V.

By substituting these values into the formula, we get:

[tex]Q = 4.50 \times 10^{-6} \, \text{F} \times 12.0 \, \text{V}[/tex]

Q = 5.40 × 10⁻⁵C

Therefore, the magnitude of the charge on each of the plates is 5.40 × 10⁻⁵ C.