A line has a slope of - 3/5. Which ordered pairs could be points on a line that is perpendicular to this line? Check all that apply.
(–8, 8) and (2, 2)
(–5, –1) and (0, 2)
(–3, 6) and (6, –9)
(–2, 1) and (3, –2)
(0, 2) and (5, 5)

Answer:

a, the first graph

Step-by-step explanation:

The probability distribution represents the likelihood of each possible value of a random variable. In this case, the random variable X represents the number of times red is spun. The graph that represents this probability distribution would have the values 0, 9/33, and 24/33 plotted for X=0, X=1, and X=2.

The probability distribution represents the likelihood of each possible value of a random variable. In this case, the random variable X represents the number of times red is spun. The sample space S consists of nine outcomes with one red spin and twenty-four outcomes with two red spins.

To find the probability distribution, we calculate the probability of each possible value of X. The probability of X=0 (no red spins) is 0, the probability of X=1 (one red spin) is 9/33, and the probability of X=2 (two red spins) is 24/33.

The graph that represents this probability distribution would have the values 0, 9/33, and 24/33 plotted on the y-axis for the corresponding values of X=0, X=1, and X=2 on the x-axis.

Answer:

-1

Step-by-step explanation:

7.3

------ = -1

-7.3

The answer is - It likely won't be drawn. The likelihood of Jaden's ticket being drawn is 1%, so it is unlikely that his ticket will be selected.

The likelihood that Jaden's ticket will be drawn depends on the probability of his ticket being selected. In this case, each ticket has a 1% chance of being drawn, which means there is a 1 in 100 chance that Jaden's ticket will be selected. Therefore, it is likely that Jaden's ticket won't be drawn.

Jaden's raffle ticket has a 1% chance of being drawn, making it much more likely that it won't be drawn than it will. The concept of 'being due to win' is a common fallacy as each draw is an independent event with a constant probability.

Following are the calculation to the given equation:

Given:

[tex]\to \frac{1}{4}(8x+56)=20[/tex]

To find:

x=?

Solution:

[tex]\to \frac{1}{4}(8x+56)=20\\\\\to \frac{8x}{4} + \frac{56}{4}=20\\\\\to 2x + 14=20\\\\\to 2x = 20-14\\\\\to 2x= 6\\\\\to x=\frac{6}{2}\\\\\to x= 3[/tex]

Therefore, the final answer is "3".

Learn more:

brainly.com/question/23248705

Answer:

Step-by-step explanation:

To find angle 3, we need to first find angle 2.

-It is given that it's a square. The full angle is 90°. Angle 2 would be 90-72, which is 18°.

Now that we have angle 2, we can find angle 3 because angle 2 and 3 are linear pairs.

180°-18°

162°

m<3=162°

Final answer:

Avenue A is perpendicular to North Street, and it would also be perpendicular to South Street since they run parallel. The concept of vector components Ax and Ay, being perpendicular and analogous to these streets, helps illustrate the perpendicular relationship between Avenue A and South Street.

Explanation:

Given that Avenue A is perpendicular to North Street, we can infer that Avenue A is also perpendicular to South Street because in a typical city grid, north and south streets run parallel to each other. When two lines are perpendicular to a third line, they are parallel to each other and form a 90° angle with the perpendicular line.

The relationships among vectors can help further illustrate this idea. If we look at the components of a vector, Ax and Ay, where Ax is the movement in the east-west direction (like Avenue A) and Ay is the movement in the north-south direction (like North Street), they form a right angle with each other. If you walk along Avenue A (the Ax component), then along North Street (the Ay component), you construct a path that is the resultant vector A with its own magnitude and direction.

The sum of these vectors is represented as Ax + Ay = A. This combination holds only for vector quantities, which include both magnitude and direction. This principle does not apply when we're summing up the magnitudes alone, as in the example where if Ax is 3 m east and Ay is 4 m north, the direct path A would not simply be their sum in magnitudes but would instead be a diagonal 5 m northeast according to the Pythagorean theorem.

Answer:

c

Step-by-step explanation:

To find the IQR, the data was first sorted and then split into two halves to find Q1 (42) and Q3 (60). The IQR of the theme park ticket prices is the difference between Q3 and Q1, which is 18 dollars.

To find the interquartile range (IQR) of the admission price for one-day tickets to 10 theme parks in the United States, first, we need to arrange the data in ascending order: 25, 40, 42, 42, 43, 43, 52, 60, 60, 65. With the data sorted, we find the median (the middle value) to divide the data set into two halves. However, since there are an even number of observations, the median will fall between the two middle numbers. The two middle numbers are the 5th and 6th values, which are 43 and 43, so their average is also 43.

Next, we find the first quartile (Q1) and the third quartile (Q3). Q1 is the median of the first half of the data (25, 40, 42, 42, 43), which is 42. Q3 is the median of the second half of the data (43, 52, 60, 60, 65), which is 60. The IQR is then found by subtracting Q1 from Q3, which is 60 - 42 = 18.

Answer: In an observational study, researchers do not control treatment, and in an experiment they do .

Step-by-step explanation:

Observational study is the study where the researcher observes the subjects and measures variables, but does not influence the population where as in an experiment the experimenter has control on the independent variable to see the effect on the dependent variable.

So the correct difference between an observational study and an experiment is that "in an observational study, researchers do not control treatment, and in an experiment they do."

Answer:

B on EDG

Step-by-step explanation:

Here, we know that 1 pint = 2 cups

Thus, 1 cup = [tex] \frac{1 pints}{2} [/tex]

3 ponds apples are needed for 4 cups i.e. 3 ponds of apples = 4 cups of applesauce

1 cup of applesauce = [tex] \frac{3 ponds}{4} [/tex]

Now, 6 pints will have 12 cups of applesauce

Multiplying this equation by 12 ⇒ 1 cup of applesauce = [tex] \frac{3 ponds}{4} [/tex]

12 ×1 cup of applesauce = 12 × [tex] \frac{3 ponds}{4} [/tex]

So, 12 cups of applesauce = 9 ponds of apple.

Thus, 9 ponds of apple will be needed to make 6 pints of applesauce.

Answer: Pink 12 %, Orange 40%, Green 28%, Blue 20%

Step-by-step explanation:

Given, Total number of,

Pink button = 300

Green button = 700

Orange button = 1000

Blue button = 500

Thus, total button = 300 + 700 + 1000 + 500 = 2500

Now,  the probability of getting pink button =  [tex]\frac{300_C_1}{2500_C_1} = \frac{300}{2500} = 0.12=12\%[/tex]

The probability of getting green button =  [tex]\frac{700_C_1}{2500_C_1} = \frac{700}{2500} = 0.28=28\%[/tex]

The probability of getting orange button =  [tex]\frac{300_C_1}{2500_C_1} = \frac{1000}{2500} = 0.40=40\%[/tex]

The probability of getting blue button =  [tex]\frac{300_C_1}{2500_C_1} = \frac{500}{2500} = 0.20=20\%[/tex]

⇒ Third Option is correct.

Answer:

the third one

Step-by-step explanation:

i got 100

The probability stated as P(blue) = 1/4 illustrates theoretical probability, which is determined by the number of favorable outcomes divided by the total number of outcomes without the need for any experiment or past data.

The type of probability illustrated by the statement "A jar contains blue, red, yellow, and green marbles with P(blue) = 1/4" is theoretical probability. This is because the probability value is based on the known possible outcomes and the assumption that each outcome has an equal chance of occurring. For example, if a bag contains four green marbles, three red marbles, and two yellow marbles, the theoretical probability of drawing a yellow marble followed by a green marble without replacement would be calculated using the number of ways these events can happen divided by the total number of outcomes.

Theoretical probability does not require experimental results or past data and is often used in problems involving equally likely events, such as drawing marbles from a jar or flipping a fair coin. In contrast, experimental probability is based on the frequency of an event happening from trials or experiments. In the given example with the jar of marbles, we assume that each marble color is equally likely to be drawn.

Answer:

Step-by-step explanation:

8 x(10+3)