A line passes through the point , 8−1 and has a slope of −3/4 . Write an equation in slope-intercept form for this line.

Answers

Answer 1

Answer: y = -3/4 + 5

Slope-intercept form: y = mx + b
^ ^
m is the slope b is the y-intercept

Since -3/4 is the slope of the line, the equation is y = -3/4x + b.

Solve for b, the y-intercept, by substituting in 8 for x and -1 for y.
y = -3/4x + b Substitution
-1 = -3/4(8) + b Multiply -3/4 and 8
-1 = -6 + b Add 6 to both sides
b = 5 y-intercept!

Substitute in the y-intercept, 5, back into y = -3/4 + b.
y = -3/4 + 5

Related Questions

A rectangle is 2 times as long as it is wide. if the area is 18 square feet, find its perimeter.

Answers

the perimeter would also be 18 square feet

Which linear inequality is represented by the graph? y > 2/3x – 1/5 y ≥ 3/2x + 1/5 y ≤ 2/3x + 1/5 y < 3/2x – 1/5

Answers

What you must do for this case first is to find the equation of the line.
We have then that by substituting the values of x = 0 and x = 3 we obtain:
y = 0.2
y = 2.2
Respectively.
So, the line is:
y = 2 / 3x + 1/5
Then, the points that satisfy the inequality are all those of the shaded region.
Answer:
The inequality is:
y ≤ 2 / 3x + 1/5

Answer: The correct option is third, i.e., [tex]y\geq \frac{3}{2} x+\frac{1}{5}[/tex].

Explanation:

From the figure it is noticed that the line passing through the points (0,0.2) and (3,2.2).

The equation of line passing through two points is,

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)[/tex]

[tex]y-0.2=\frac{2.2-0.2}{3-0}(x-0)[/tex]

[tex]y-\frac{1}{5} =\frac{2}{3} x[/tex]

[tex]y =\frac{2}{3} x+\frac{1}{5}[/tex]

The equation of the line is [tex]y =\frac{2}{3} x+\frac{1}{5}[/tex].

From the figure it is noticed that as the value of x increases the value of y is less.

he point (1,0) lies on the shaded reason it means this point must satisfy the equation.

[tex](0)=\frac{2}{3} (1)+\frac{1}{5}[/tex]

[tex](0)=\frac{2}{3} +\frac{1}{5}[/tex]

[tex](0)=\frac{10+3}{15}[/tex]

[tex](0)=\frac{13}{15}[/tex]

It is true of the sign is less than or equal to instead of equal.

[tex]y \leq \frac{2}{3} x+\frac{1}{5}[/tex]

Therefore, option third is correct.

Danielle poured 3/4 gallon of water from a 7/8 gallon bucket. How much water is left in the bucket?

Answers

3/4 = 6/8 after you multiply top and bottom by 2

Subtract 3/4 from 7/8 and we get
7/8 - 3/4 = 7/8 - 6/8 = (7-6)/8 = 1/8

There is 1/8 of a gallon left

in quadrilateral abcd , angle A=57 degrees , angle B=65 degrees and angle c=118 degrees What is the measure of an exterior angle at D

Answers

The total measure of the interior angles of a quadrilateral is 360 degrees
you are given 57, 65, 118
That is 240
to solve for the last angle
360-240
120
The exterior angle of a D would be the number that you add that will make it 180 degrees.
meaning 180-120 is
The exterior angle of angle D is 60 degrees.

Hope this helps

Ben and Marge are purchasing a house with a 20-year, 5/1 ARM for $265,000 at 5.25% with a 3/12 cap structure. What will the difference in payments be from year 5 to year 6?
A. $925.81
B. $880.29
C. $369.32
D. $234.39

Answers

The difference in payments from year 5 to year 6 is approximately $369.32 for the 5/1 ARM mortgage.

To calculate the payment difference from year 5 to year 6 for a 5/1 ARM (Adjustable Rate Mortgage) with a 3/12 cap structure, we need to understand how the ARM works and how the caps affect the adjustment.

1. Initial Mortgage Parameters :

- Loan Amount: $265,000

- Interest Rate: 5.25%

- Term: 20 years

2. Adjustment Frequency : The 5/1 ARM adjusts after the initial 5-year fixed period, then annually.

3. Cap Structure :

- Initial Adjustment Cap: 3%

- Subsequent Adjustment Cap: Each year after the initial adjustment, the rate can adjust up to 3% from the previous rate.

4. Calculation Steps :

a. Calculate the initial monthly payment using the loan amount, interest rate, and term.

b. Determine the new interest rate for year 6 based on the cap structure.

c. Calculate the monthly payment for year 6 with the new interest rate.

d. Find the difference between the payments from year 5 to year 6.

Let's start the calculations:

a. Calculate the initial monthly payment using the loan amount, interest rate, and term. We'll use the formula for a fixed-rate mortgage:

[tex]\[ P = \frac{P_r \cdot A}{1 - (1 + r)^{-n}} \][/tex]

Where:

- [tex]$ P $[/tex] = Monthly Payment

- [tex]$ P_r $[/tex] = Periodic Interest Rate (annual rate divided by 12)

- [tex]$ A $[/tex] = Loan Amount

- [tex]$ r $[/tex] = Periodic Interest Rate

- [tex]$ n $[/tex] = Total number of payments (loan term in years multiplied by 12)

For the initial fixed period of 5 years:

[tex]\[ P_r = \frac{5.25\%}{12} = 0.004375 \][/tex]

[tex]\[ n = 20 \times 12 = 240 \][/tex]

Plugging these values into the formula:

[tex]\[ P = \frac{0.004375 \cdot 265000}{1 - (1 + 0.004375)^{-240}} \][/tex]

[tex]\[ P \approx 1645.80 \][/tex]

So, the initial monthly payment is approximately $1,645.80.

b. Determine the new interest rate for year 6 :

- The initial rate can adjust up to 3% in year 6.

- So, the new interest rate could be up to $ 5.25\% + 3\% = 8.25\% $.

c. Calculate the monthly payment for year 6 :

- Use the formula for the monthly payment again with the new interest rate:

[tex]\[ P_r = \frac{8.25\%}{12} = 0.006875 \][/tex]

Plugging into the formula:

[tex]\[ P = \frac{0.006875 \cdot 265000}{1 - (1 + 0.006875)^{-240}} \][/tex]

[tex]\[ P \approx 1985.09 \][/tex]

So, the monthly payment for year 6 is approximately $1,985.09.

d. Find the difference in payments from year 5 to year 6:

[tex]\[ Difference = Payment_{Year6} - Payment_{Year5} \][/tex]

[tex]\[ Difference = 1985.09 - 1645.80 \][/tex]

[tex]\[ Difference \approx 339.29 \][/tex]

So, the difference in payments from year 5 to year 6 is approximately $339.29.

Therefore, the closest answer is C. $369.32 .

Tickets for the school play cost $17 each. Gary wrote the expression n X 17 to find the cost of n tickets to the play. He used the Distributive Property to find the product. Use the Distributive Property to write Gary's expression another way.

Answers

Well, the distributive property is that by which the multiplication of a number by a sum will give us the same as the sum of each of the addends multiplied by that number.
We have then that the expression used by Gary:
n = X * 17
Using the distributive property we have another way to rewrite the expression is:
n = 17 * X
Where,
x: is the sum of all tickets sold.
Answer:
n = 17 * X

In a Quadratic Regression problem, a graph is a perfect fit for the data when r = ? a. 1 c. 2 b. 0 d. 100 Please select the best answer from the choices provided A B C D

Answers

Answer:

the answer is A on edge :)

Step-by-step explanation:

The graph that is a perfect fit for the given data in a quadratic regression problem is when r is; A: 1

What is a quadratic regression?

Quadratic regression is defined as a statistical technique that is used to find the equation of the parabola that best fits a set of data.

Now, this type of regression is an extension of simple linear regression that is used to find the equation of the straight line that best fits a set of data.

Thus, in this type of regression, we say a graph is a perfect fit when r = 1.

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The city of Beijing has a population of more than 10 to the 7th power people. Write 10 to the 7th power without using an exponent

Answers

10^7 = 10 * 10 * 10 * 10 * 10 * 10 * 10 = 10 000 000

Answer:

[tex]10\times 10\times 10\times 10\times 10\times 10 \times 10[/tex]

Step-by-step explanation:

Exponentiation is the operation used to write the product of two or more equal factors. This expression can written as follows:

[tex]a^n\\\\Where:\\\\a=Base\\n=Exponent[/tex]

That is, [tex]a^n[/tex] is the product of multiplying n bases:

[tex]a^n=a\times...\times...\times a[/tex]

In this sense:

[tex]10^7=10\times 10\times 10\times 10\times 10\times 10 \times 10[/tex]

Which expression represents the number of sides in the polygon for the nth member of the pattern? A) n + 3 B) n3 C) n + 2 D) 3n

Answers

1st member has 3 sides, (3x1)
2nd member has 6 sides (3x2)
3rd member has 9 sides' (3x3)
Therefore, i think for nth member
the appropriate expression for n th member will be 3n

If a 10. m3 volume of air (acting as an ideal gas) is at a pressure of 760 mm and a temperature of 27 degrees Celsius is taken to a high altitude where the pressure is 400. mm Hg and a temperature of -23 degrees Celsius, what volume will it occupy? (Hint: remember the temperature must be in Kelvin)

Answers

From the combined gas law
P1V1/T1 = P2V2/T2, Where P1, V1 and T1 are the initial pressure, volume and temperature respectively, while P2,V2 and T1 are the new pressure, volume and temperatures respectively.
Thus; P1= 760 mmHg, V1=10 m^3, T1 = 27 +273 = 300 K
P2= 400 mmHg, V2= ? and T2= -23 +273 = 250K
V2 = (P1V1T2)/T1P2
= (760×10×250)/(300×400)
= 1900000/120000
= 15.83
Therefore, the new volume is 15.83 m³

Answer:

16. m3

Step-by-step explanation:

27 degrees Celsius= 27+273= 300 kelvin

23 degrees Celsius= -23+273=250 kelvin

Combined Gas Law: P1V1/T1 = P2V2/T2

(760mm*10 m3)/300 K=(400mm*x m3)/250 K x= 16. m3

The volume that it will occupy is 16. m3.

(Don't forget the sig fig, 15.83--->16. because the question said 10.)

The formula used to find the length of a line segment in space.

Answers

It's the same formula as the one used on Earth. It is based on the Pythagorean theorem.

length = √((∆x)^2 +(∆y)^2 +(∆z)^2)
.. where ∆x, ∆y, ∆z are the differences between the end-point coordinates in the x-, y-, and z-directions, respectively.

if youre doing the vocab thing -- Distance

in a given circuit, the supplied voltage is 1.5 volts, and the resistor value is 3 ohms. use ohm's law to determine the current in the circuit

Answers

0.5 is the answer. I = V/ R

Final answer:

The current in a circuit with a supplied voltage of 1.5 volts and a resistance of 3 ohms is calculated using Ohm's Law (I = V/R), resulting in a current of 0.5 amperes.

Explanation:

Using Ohm's Law to Calculate Current

To determine the current in a circuit with a supplied voltage of 1.5 volts and a resistor value of 3 ohms, we can use Ohm's Law, which is stated as I = V/R, where I is the current, V is the voltage, and R is the resistance. Plugging in the values, we have I = 1.5 volts / 3 ohms. Therefore, I = 0.5 amperes or 500 milliamperes. This is the current flowing through the circuit.

Ohm's Law is a fundamental principle in physics used for analyzing simple circuits where the relationship between voltage, current, and resistance is linear. Remember that this law holds true for ohmic materials where the resistance remains constant over a range of voltages and temperatures.

A small plane leaves an airport at a speed of 252 miles per hour. A jet leaves the airport 2 hours later traveling at 672 miles per hour. How long will the small plane be flying before the jet catches up to it? What unit will you use for your answer?

Answers

recall your d = rt, distance = rate * time.

the small plane runs at a rate of 252 mph, the jet runs at 672 mph, but the jet takes off 2 hours later.

if the jet plane say has been traveling for "t" hours by the time they meet, the small plane was already rolling before the jet, actually 2 hours earlier, so if the jet has gone for "t" hours, the small plane has been going for "t+2" hours.

now, by the time they both meet, the distance covered by say the small plane is "d" miles, but the distance covered by the jet is also the same "d" miles, since they're meeting.

[tex]\bf \begin{array}{lccclll} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ &------&------&------\\ \textit{small plane}&d&252&t+2\\ \textit{jet plane}&d&672&t \end{array} \\\\\\ \begin{cases} d=252(t+2)\\ d=672t\\ --------\\ 252(t+2)=672t \end{cases} \\\\\\ 252t+504=672t\implies 504=420t\implies \cfrac{504}{420}=t\implies \cfrac{6}{5}=t \\\\\\ \textit{an hour and 12 minutes}=t[/tex]

No, thanks to you, I got the question wrong it was hours.

Which graph represents the function over the interval [−3, 3]?

Answers

In mathematics, the functions of the whole part are functions that take a real number and return a whole number, either by excess or by default.
Function floor (or ground), that to each real number assigns the nearest whole number by defect, that is to say, the greater whole number equal or smaller than that real number.
Let's evaluate the extremes of the interval
x = -3
g (-3) = floor (-3) -2 = -5
x = 3
g (3) = floor (3) -2 = 1
Therefore, the graph that best corresponds to the function in the given interval is the attached graph.

Third graphrepresents the function [tex]f\left( x \right) = \left\lfloor x \right\rfloor-2[/tex] over the interval [tex]\left[ { - 3,3} \right].[/tex]

Further explanation:

Given:

The function is [tex]f\left( x \right) = \left\lfloor x \right\rfloor- 2.[/tex]

The function is defined in the interval [tex]\left[ {-3,3}\right].[/tex]

Explanation:

The greatest integer function is represented [tex]y = \left\lfloor x \right\rfloor.[/tex]

The greatest integer can also be known as floor function. The function is integral part of real numbers.

The values of greatest function [tex]f\left( x \right)= \left\lfloorx \right\rfloor- 2[/tex] in interval [tex]\left[{ - 3,3}\right][/tex] can be obtained as follows,

Substitute [tex]-3[/tex] for [tex]x[/tex] in the function [tex]f\left( x \right)= \left\lfloor x \right\rfloor- 2.[/tex]

[tex]\begin{aligned}f\left({- 3} \right)&=\left\lfloor{ - 3} \right\rfloor- 2\\&=- 3- 2\\&=- 5\\\end{aligned}[/tex]

Substitute [tex]3[/tex] for [tex]x[/tex] in the function [tex]f\left( x \right)=\left\lfloor x \right\rfloor- 2.[/tex]

[tex]\begin{aligned}f\left( 3 \right)&= \left\lfloor3\right\rfloor- 2\\&=3- 2\\&=1\\\end{aligned}[/tex]

The minimum value of the function in [tex]\left[ { - 3,3} \right] {\text{is}\: \boxed{ - 5}.[/tex]

The maximum value of the function in [tex]\left[ { - 3,3} \right] {\text{is}\: \boxed{1}.[/tex]

Third graphrepresents the function [tex]f\left( x \right)=\left\lfloor x\right\rfloor- 2[/tex] over the interval [tex]\left[{ - 3,3}\right].[/tex]

Kindly refer to the image attached.

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Answer details:

Grade: High school

Subject: Mathematics

Chapter: Number system

Keywords: factor, factorization, polynomial, quadratic, cubic, greatest common factor, groups, multiplication, product, identities, common factor, expression, terms, grouping.

A group of college students are volunteering for Help the Homeless during their spring break. They are putting the finishing touches on a house they built. Working alone, Irina can paint a certain room in 9 hours. Paulo can paint the same room in 8 hours. Write an equation that can be used to find how long it will take them working together to paint the room. How many hours will it take them to paint the room? If necessary, round your answer to the nearest hundredth

Answers

Since Irina can paint 1 room in 9 hours, that means she paints 1/9 of the room in 1 hour. Her portion of the equation would be 1/9x, with x being the number of hours she works and 1/9 of a room per hour being her speed.
Since Paulo can paint 1 room in 8 hours, that means he paints 1/8 of the room in 1 hour. His portion of the equation would be 1/8x, with x being the number of hours he works and 1/8 of a room per hour being his speed.
The equation would then be 1/9x + 1/8x = 1 (Irina's portion of the room, plus Paulo's portion of the room, equal to one whole room).
Find a common denominator. 72 is the first number that both 9 and 8 divide evenly into. Since 9*8 = 72, we multiply the top of 1/9 by 8 to convert the fraction and get 8/72x. Since 8*9 = 72, we multiply the top of 1/8 by 9 to convert the fractio and get 9/72x. We now have 8/72x+9/72x=1
17/72x=1
Divide both sides by 17/72:
17/72x ÷ 17/72 = 1÷17/72
x=1/1 ÷ 17/72
x=1/1 * 72/17
x=72/17=4.24
Together it should take them 4.24 hours.

The combined work rate can be found by using the equation for combined rate.

The correct responses;The time it will take them working together is; [tex]\displaystyle \underline{\frac{1}{t_b} = \frac{1}{t_1} + \frac{1}{t_2} }[/tex]

The number of hours it will take them working together to paint the room is approximately 4.24 hours.

The method by which the above responses are obtained:

The time it takes Irina to paint the room alone, t₁ = 9 hours

Time it takes Paulo to paint the room, t₂ = 8 hours

Required:

To write the equation for the combined rate of Irina and Paulo

Solution:

The equation that gives the time, [tex]\mathbf{t_b}[/tex], it will take both Irina and Paulo to paint the room together is given by the combined rate formula, as follows;

[tex]\displaystyle \underline{ \frac{1}{t_b} = \frac{1}{t_1} + \frac{1}{t_2}}[/tex]

Required:

The duration it will take them to paint the room when working together.

Solution:

The time it will take them to paint the room together is found as follows;

[tex]\displaystyle \frac{1}{t_b} = \mathbf{\frac{1}{9} + \frac{1}{8}}[/tex]

Which gives;

[tex]\displaystyle \frac{1}{t_b} = \frac{8 + 9}{9 \times 8} = \mathbf{\frac{17}{72}}[/tex]

Therefore;

[tex]\displaystyle t_b = \frac{72}{17} \approx \mathbf{4.24}[/tex]

The time it takes Irina and Paulo to paint together, [tex]t_b[/tex] ≈ 4.24 hrs.

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Joan has 45 marbles . MARY HAS m marbles if Joan has 15 times as many marbles , write an equation that shows how many marbles mary has

Answers

Final answer:

Mary has 3 marbles.

Explanation:

To find out how many marbles Mary has, we can use the information that Joan has 45 marbles and Joan has 15 times as many marbles as Mary. So, we can set up an equation:

45 = 15m

To solve for m, we divide both sides of the equation by 15:

m = 45/15

Simplifying the expression, we get:

m = 3

Therefore, Mary has 3 marbles.

PLEASE HELP
Is this A, B, or C?

Answers

This is the sum of the first six terms of a geometric sequence.
The sum can be written like this:
[tex]-4\frac{1-\left(\frac{1}{2}\right)^6}{1-\frac{1}{2}}=-8\left(1-\dfrac{1}{2^6}\right)\\ =-8\dfrac{63}{64}\\=-\dfrac{63}{8}[/tex]
The correct answer is the second one.

Use the Remainder Theorem to find the remainder: (–6x3 + 3x2 – 4) ÷ (2x – 3).

23

-17.5

-4.4444444...

-0.8888888...

Answers

we have that
(–6x³ + 3x² – 4) ÷ (2x – 3)
----------------------║--------------------------
+6x³+9x² -3x²+6x+9
---------------------
12x²-4
-------------------
-12x²+18x
-------------------
18x-4
-----------------
-18x+27
----------------
23-----------------> the remainder

the answer is 23

The remainder obtained when we carry out the operation (-6x³ + 3x² - 4) ÷ (2x - 3) is -17.5 (2nd option)

How do i determine the remainder?

The following data were obtained from the question:

Expression = (-6x³ + 3x² - 4) ÷ (2x - 3)Remainder =?

Using the remainder theorem, we can obtain the remainder as illustrated below:

Let

f(x) = -6x³ + 3x² - 4

2x - 3 = 0

From 2x - 3 = 0, make x the subject as shown below:

2x - 3 = 0

x = 3/2

Substitute the value of x into f(x). We have:

f(x) = -6x³ + 3x² - 4

f(3/2) = -6(3/2)³ + 3(3/2)² - 4

= -6(27/8) + 3(9/4) - 4

= -20.25 + 6.75 - 4

= -17.5

Thus, we can conclude that the remainder obtained when (-6x³ + 3x² - 4) is divided by (2x - 3) is -17.5 (2nd option)

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An ellipse has vertices along the major axis at (0, 1) and (0, −9). The foci of the ellipse are located at (0, −1) and (0, −7). The equation of the ellipse is in the form below.

Answers

so, with those points provided, notice the vertices are lying along the y-axis, check the picture below, thus is a vertical ellipse.

now, the center is half-way between the vertices, therefore it'd be at 0, -4, like in the picture in red.

the distance from the center to either foci, is "c", and that's c = 3.

the "a" component of the major axis is 5 units, now let's find the "b" component,

[tex]\bf \textit{ellipse, vertical major axis} \\\\ \cfrac{(x- h)^2}{ b^2}+\cfrac{(y- k)^2}{ a^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h, k\pm a)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2- b ^2} \end{cases}\\\\ -------------------------------[/tex]

[tex]\bf \begin{cases} a=5\\ c=3 \end{cases}\implies c=\sqrt{a^2-b^2}\implies c^2=a^2-b^2\implies b^2=a^2-c^2 \\\\\\ b=\sqrt{a^2-c^2}\implies b=\sqrt{5^2-3^2}\implies b=4\\\\ -------------------------------\\\\ \begin{cases} h=0\\ k=-4\\ a=5\\ b=4 \end{cases}\implies \cfrac{(x- 0)^2}{ 4^2}+\cfrac{[y-(-4)]^2}{ 5^2}=1 \\\\\\ \cfrac{(x- 0)^2}{ 16}+\cfrac{(y+4)^2}{25}=1[/tex]

The equation of the ellipse is required.

The required equation is [tex]\dfrac{x^2}{16}+\dfrac{(y+4)^2}{25}=1[/tex]

It can be see that the major axis is parallel to the y axis.

The major axis points are

[tex](h,k+a)=(0,1)[/tex]

[tex](h,k-a)=(0,-9)[/tex]

[tex]k+a=1[/tex]

[tex]k-a=-9[/tex]

Subtracting the equations

[tex]2a=10\\\Rightarrow a=5[/tex]

The foci are

[tex](h,k+c)=(0,-1)[/tex]

[tex](h,k-c)=(0,-7)[/tex]

[tex]k+c=-1[/tex]

[tex]k-c=-7[/tex]

Subtracting the equations

[tex]2c=6\\\Rightarrow c=3[/tex]

[tex]k+c=-1\\\Rightarrow k=-1-c\\\Rightarrow k=-1-3\\\Rightarrow k=-4[/tex]

Foci is given by

[tex]c^2=a^2-b^2\\\Rightarrow b=\sqrt{a^2-c^2}\\\Rightarrow b=\sqrt{5^2-3^2}=4[/tex]

The equation is

[tex]\dfrac{(x-h)^2}{b^2}+\dfrac{(x-k)^2}{a^2}=1\\\Rightarrow \dfrac{(x-0)^2}{4^2}+\dfrac{(y+4)^2}{5^2}=1\\\Rightarrow \dfrac{x^2}{16}+\dfrac{(y+4)^2}{25}=1[/tex]

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if the remainder on division of x^3+2x^2+kx+3 by x-3 is 21,find the quotient and the value of k. Hence,find the zeroes of the cubic polynomial x^3+2x^2+kx-18.

Answers

Let p(x)=x^3+2x^2+kx+3
On dividing p(x) by x-3, the remainder is 21. Therefore,
P(3)=21
Substituting x=3 in p(x)
P(3)=3^3 +2*(3)^2+k*3+3
=27+18+3k+3
=48+3k
We know that, p(3)=21.
So, 48+3k=21
3k=21-48
3k=-27
k=-27/3 =-9
now, p(x) =x^3+2x^2-9x-18
-2 is a factor of p(x) on inspection. Therefore, divide p(x) by x+2 to find the
zeroes of the polynomial.
On dividing, we get the factors to be, (x^2-9)(x+2)
(x^2-3^2)(x+2)
Factorizing using the identity a^2-b^2=(a+b)(a-b) we get,
(x+3)(x-3)(x+2)
Therefore, the zeroes of the polynomials are -3,+3 and -2.

Can someone help me please!!!

Answers

3x + 2y = 11
3x + 2(5x - 1) = 11
3x + 10x - 2 = 11
13x = 13
x = 1
y = 11 - 3x
y = 11 - 3
y = 8

3x + 2y = 11
y = 5x -1
Using substitution
3x + 2(5x-1) = 11
3x + 10 x -2 = 11
13x = 13
x = 1
but, y= 5x -1
y = 5 (1)- 1
= 4
Therefore, y =4 and x = 1

Question 2
Using linear combination method
2x -3y = 13
x+2y = -4 multiplying the second equation by 2 to eliminate x
we get
2x - 3y = 13
2x + 4y = -8 ( subtracting the two equations)
-7y = 21
y = -3
To get x we substitute y with -3 in one of the equation
x = -4 -2y
x = -4 - 2(-3)
x = 2
Therefore, the value of x = 2 and y =-3

Question 3
The first thing is to get a table of values for each of the equation using at least three values of x, this gives you at least three coordinates that can be used to plot the lines on the Cartesian plane.
That is;
For; y = (1/2)x + 3
x y
(2 , 4)
(4, 5)
(6, 6)
And for -3x +y = -2 which is the same as y =-2 +3x

x y
(0, -2)
(1, 1)
(2, 4)

Then, plot the two lines on the plane using the above coordinates,
The solution will be the point of intersection of the two lines (where the two lines plotted meet)

What is the circumference of a circle with a radius of 6.1 centimeters? Enter your answer as a decimal in the box. Use 3.14 for pi. Round your answer to the nearest tenth. cm

Answers

We must use a certain formula to find the circumference. The formula for circumference of a circle is:

C = 2 * pi × r

Substitute:

C = 3.14 × 6.1 × 2

C = 38.303

Round to the nearest tenth:

38.3.

ANSWER:

The circumference of the circle is about 38.3 centimetres.

It is 38.308 or 38.3
:D

An inscribed angle has a measure of 48°. Determine the measure of the intercepted arc.
24° 48° 72° 96°

Answers

An inscribed angle has a measure of 1/2 of the intercepting arc. Since our angle is 48°, we can set up the equation [tex]48=\frac{1}{2}x[/tex] to represent this. Divide both sides by 1/2:
[tex]\frac{48}{\frac{1}{2}}=\frac{\frac{1}{2}x}{\frac{1}{2}} \\ 48 \div \frac{1}{2} = x \\ \frac{48}{1} \div \frac{1}{2} = x \\ \frac{48}{1}*\frac{2}{1} = x \\ \frac{96}{1}=x \\ 96=x[/tex]
The measure of the intercepted arc is 96°.

At a furniture manufacturer, worker A can assemble a shelving unit in 5 hours. Worker B can assemble the same shelving unit in 3 hours. Which equation can be used to find t, the time it takes for worker A and worker B to assemble a shelving unit together?

Answers

Let's define the following variable:
t = total time it takes to assemble a shelving unit together.
We then have the following equation:
1/5 + 1/3 = 1 / t
Solving the equation we have:
3t + 5t = 15
8t = 15
t = 1,875 hours
Answer:
the time it takes for worker A and worker B to assemble a shelving unit together is:
t = 1,875 hours

The equation 1/t = 1/5 + 1/3 can be used to find the time it takes for worker A and worker B to assemble a shelving unit together.

To find the time t it takes for worker A and worker B to assemble a shelving unit together, we need to add their work rates.

Worker A's work rate is 1 unit per 5 hours (or 1/5 units per hour), and worker B's work rate is 1 unit per 3 hours (or 1/3 units per hour).

The combined work rate is the sum of their individual work rates:

1/5 + 1/3 = (3 + 5) / 15 = 8 / 15 units per hour

If t is the time they take together to complete one shelving unit, then their combined work rate is 1 unit per t hours. Setting this equal to their combined rate, we get:

1/t = 8/15

Solving for t gives:

t = 15/8 hours

Therefore, the equation 1/t = 1/5 + 1/3 can be used to find the time it takes for worker A and worker B to assemble a shelving unit together.

Would be glad if you answer my question!

Answers

Well, the question is asking you to transform the equation into ' p = ...'
and it's not that you just have to divide the 'a' from both sides giving the answer as p = (px+c) ÷ a, but you have to write in terms of ' a,x and c'.

so ap = px+c
1)collect all the likes to one side (ap - px = c)
2) Take the common out [ p(a-x) = c ]
3) Divide by '(a-x)' to put equation in terms of "p="
4) therfore, p = c ÷ (a-x)

Hope this answered your question

helppppppppppppppppppppp

Answers

First we write both functions:
f (a) = 5 + a ^ 2
g (a) = root (a-5) -2
By making the composition we have:
g (f (a)) = root ((5 + a ^ 2) -5) -2
Rewriting the function:
g (f (a)) = root (5 + a ^ 2-5) -2
g (f (a)) = root (a ^ 2) -2
g (f (a)) = lal-2
Answer:
The functions are:
f (a) = 5 + a ^ 2
g (a) = root (a-5) -2
option 3

Which is the ratio for sin a written as a fraction in simplest form

Answers

answer is square root 3/2

your Answer issss:

√3/2

Instructions:Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
is parallel to . and are perpendicular to and .
The ratio of the lengths of and is
:
.

Answers

I think is 1:1 but im not 100% sure

Answer:

The ratio of the lengths of PR and QS is 1 : 1

Step-by-step explanation:

If your question is based on this exercise:

PQ Is parallel to RS. PR and QS are perpendicular to PQ and RS

Here is why

Which list shows all the factors of 18?
1, 2, 3, 4, 6, 9, 18
1, 2, 3, 6, 9, 18
2, 3, 4, 6, 9
2, 3, 6, 9

Answers

line number 2 is the correct answer

the second choice is the answer

Is .8/100 equal to .8%

Answers

Yes 8/100 is equal to 8%

Yes .8/100 is equal to .8%,
but is also equal to 2/25, the simplest form of .8/100

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