A. List three things that your body strives to keep constant. (example metabolism)
B. Describe one way in which each of the items you listed in Part A could be at least temporarily disrupted from equilibrium. Can you think of a way your body could respond to restore homeostasis after one of these disruptions?

Answer:- Molar mass of [tex]CO_2[/tex] .

Solution:- It is a stoichiometry problem. Mass of the grill is 30.0 kg and the mass after burning the grill is also 30.0 kg. It means all the charcol is burned and the gas is given off.

2.0 kg of charcol are converted to grams which is 2000 g. Since charcol is pure solid carbon, the grams are divided by the atomic mass of carbon which is 12.

The combustion equation of charcol is written as:

[tex]C(s)+O_2(g)\rightarrow CO_2(g)[/tex]

From this balanced equation, there is 1:1 mol ratio between charcol and carbon dioxide. So, the moles of carbon dioxide gas formed are equivalent to the moles of charcol. To convert the moles of carbon dioxide to grams we multiply the moles by it's molar mass.

Carbon dioxide has one carbon and two oxygen atoms so it's molar mass = 12 + 2(16) = 12 + 32 = 44

So, 44 is the molar mass of carbon dioxide and above calculations clearly shows how and where we get this.

Answer: Resulting solution will not be neutral because the moles of [tex]OH^-[/tex]ions is greater. The remaining concentration of [tex][OH^-][/tex]ions =0.0058 M.

Explanation:

Given,

[HCl]=0.100 M

[tex][HNO_3][/tex] = 0.200 M

[tex][Ca(OH)_2][/tex] =0.0100 M

[RbOH] =0.100 M

Few steps are involved:

Step 1: Calculating the total moles of [tex]H^+[/tex] ion from both the acids

moles of [tex]H^+[/tex] in HCl

[tex]HCl\rightarrow {H^+}+Cl^-[/tex]

if 1 L of [tex]HCl[/tex]solution =0.100 moles of HCl

then 0.05L of HCl solution= 0.05 [tex]\times [/tex]0.1 moles= 0.005 moles    (1L=1000mL)

moles of [tex]H^+[/tex] in HCl = 0.005 moles

Similarliy

moles of [tex]H^+[/tex] in [tex] HNO_3[/tex]

[tex]HNO_3\rightarrow H^++NO_3^-}[/tex]

If 1L of [tex]HNO_3[/tex] solution= 0.200 moles

Then 0.1L of [tex]HNO_3[/tex] solution= 0.1 [tex]\times [/tex] 0.200 moles= 0.02 moles

moles of [tex]H^+[/tex] in [tex]HNO_3[/tex] =0.02 moles

so, Total moles of [tex]H^+[/tex] ions  = 0.005+0.02= 0.025 moles     .....(1)

Step 2: Calculating the total moles of [tex][OH^-][/tex] ion from both the bases

Moles of [tex]OH^-\text{ in }Ca(OH)_2[/tex]

[tex]Ca(OH)_2\rightarrow Ca^2{+}+2OH^-[/tex]

1 L of [tex]Ca(OH)_2[/tex]= 0.0100 moles

Then in 0.5 L [tex]Ca(OH)_2[/tex] solution = 0.5 [tex]\times [/tex]0.0100 moles = 0.005 moles

[tex]Ca(OH)_2[/tex] produces two moles of [tex]OH^-[/tex] ions

moles of [tex]OH^-[/tex] = 0.005 [tex]\times [/tex] 2= 0.01 moles

Moles of [tex]OH^-[/tex] in [tex]RbOH[/tex]

[tex]RbOH\rightarrow Rb^++OH^-[/tex]

1 L of RbOH= 0.100 moles

then 0.2 [RbOH] solution= 0.2 [tex]\times [/tex] 0.100 moles = 0.02 moles

Moles of [tex]OH^-[/tex] = 0.02 moles

so,Total moles of [tex]OH^-[/tex] ions = 0.01 + 0.02=0.030 moles      ....(2)

Step 3: Comparing the moles of both [tex]H^+\text{ and }OH^-[/tex] ions

One mole of [tex]H^+[/tex] ions will combine with one mole of [tex]OH^-[/tex] ions, so

Total moles of [tex]H^+[/tex] ions  = 0.005+0.02= 0.025 moles....(1)

Total moles of [tex]OH^-[/tex] ions = 0.01 + 0.02=0.030 moles.....(2)

For a solution to be neutral, we have

Total moles of [tex]H^+[/tex] ions = total moles of [tex]OH^-[/tex] ions

0.025 moles [tex]H^+[/tex] will neutralize the 0.025 moles of [tex]OH^-[/tex]

Moles of [tex]OH^-[/tex] ions is in excess        (from 1 and 2)

The remaining moles of [tex]OH^-[/tex] will be = 0.030 - 0.025 = 0.005 moles

So,The resulting solution will not be neutral.

Remaining Concentration of [tex]OH^-[/tex] ions = [tex]\frac{\text{Moles remaining}}{\text{Total volume}}[/tex]

[tex][OH^-]=\frac{0.005}{0.85}=0.0058M[/tex]

By the mass percentage, [tex]100[/tex] grams of the sample would contain

Which corresponds to

Hence the approximate ratio [tex]n(\text{N}) : n(\text{C}) \approx 1 : 1[/tex] and the empirical formula [tex]\text{CN}[/tex].

Apply the idea gas formula to determine the number of moles of the gas molecules present in the [tex]462 \; \text{cm}^{3} = 0.462 \; \text{L} [/tex] sample:

[tex]\begin{array}{lll}n &= & (\text{P}\cdot \text{V}) / (\text{R} \cdot \text{T})\\ & = & 1.01 \times 10^2 \times 0.462 /(8.314 \times 273) \\ &= &0.0206\; \text{mol}\end{array}[/tex]

Thus

[tex]M = m / n = 1.048 / 0.0206 = 51.0 \; \text{g} \cdot \text{mol}^{-1}[/tex]

which is approximately twice of [tex]26.02\; \text{g} \cdot \text{mol}^{-1}[/tex], formula mass for the empirical formula [tex]\text{CN}[/tex]. Hence the molecular formula [tex]\text{C}_2\text{N}_2[/tex]

The molecular formula of the compound is C2N2.

From the ideal gas equation;

PV = nRT

P = 1.01 x 10^5 Pa or 1.01 atm

V = 462 cm^3 or 0.462 L

R = 0.082 atm Lmol-1K-1

T = 273 K

n = ?

n = PV/RT

n = 1.01 atm × 0.462 L/ 0.082 atm Lmol-1K-1 × 273 K

n =0.467 /22.386

n = 0.02086 moles

Now;

Molar mass of the compound  is obtained from;

number of moles  = mass/molar mass

molar mass = mass/number of moles

molar mass =  1.048g/0.02086 moles

molar mass = 50.24 g/mol

The empirical formula of the compound is;

C - 53.8%/12,         N - 46.2%/14

C - 4.48,                 N - 3.3

Dividing through by the lowest ratio

C -4.48/3.3            N - 3.3/3.3

C - 1                       N - 1

The empirical formula is CN

The molecular formula is obtained thus;

[12 + 14]n = 50.24

n = 50.24/26

n = 2

The molecular formula of the compound is C2N2

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Explanation:

An atom consists of electrons, protons, and neutron. The protons and neutrons are present inside the nucleus whereas the electrons are present outside the nucleus.

These electrons revolve around the nucleus in circular motion. Therefore, an electron pair surrounds the central atom of a molecule. It is known that an electron contains a negative charge and like charges repel each other.

Hence, in an atom the force of repulsion between electron pairs pulls the atoms away from each other.

As a result, a molecules atoms are as far away from each other as they can get.

Answer:

forces between electron pairs push the atom apart

Explanation:

apex

Here we have to get the correct molecular formula of the compound.

The molecular formula of the compound is C₆H₆O₆ i.e. option C.

Let assume, the empirical formula of the compound is [tex](CHO)_{n}[/tex].

The given molar mass of the compound is 176.124 g/mole.

The percent of carbon in the compound is [tex]\frac{283.4}{692.5}[/tex]×100 = 40.924.

The percent of hydrogen in the compound is [tex]\frac{31.7}{692.5}[/tex]×100 = 4.577.

The percent of oxygen in the compound is [tex]\frac{377.4}{692.5}[/tex]×100 = 54.498.

Now the ratio of the atomic number in the compound for carbon is [tex]\frac{40.924}{12}[/tex] = 3.410

Now the ratio of the atomic number in the compound for hydrogen is [tex]\frac{4.577}{1}[/tex] = 4.577

Now the ratio of the atomic number in the compound for oxygen is [tex]\frac{54.498}{16}[/tex] = 3.406

So, the C, H and O lowest ratio is [tex]\frac{3.410}{3.406}[/tex] = 1, [tex]\frac{4.577}{3.406}[/tex] = 1 and [tex]\frac{3.406}{3.406}[/tex] = 1

Thus the empirical formula of the compound is [tex][CH_{1}O] _{n}[/tex] (where n = integer.

12n + 1n + 16n = 176.24

29n = 176.24

n = 6 (approx)

Thus the molecular formula of the compound is C₆H₆O₆.

Final answer:

By calculating the number of moles of carbon, hydrogen, and oxygen and deriving the ratio among them, it is determined that the molecular formula of the compound with a molar mass of 176.124 grams/mole is C6H8O6 (D).

Explanation:

To find the molecular formula of the compound used as a food additive with a molar mass of 176.124 grams/mole from the given decomposition data, we first need to calculate the number of moles of each element present in the given sample.

For carbon: (283.4 g) / (12.0 g/mol) = 23.62 moles
For hydrogen: (31.7 g) / (1.0 g/mol) = 31.7 moles
For oxygen: (377.4 g) / (16.0 g/mol) = 23.59 moles

Next, we divide by the smallest number of moles to get the atom ratio.
C: 23.62 / 23.59 ≈ 1
H: 31.7 / 23.59 ≈ 1.34
O: 23.59 / 23.59 = 1

The ratio of hydrogen is not a whole number, so we multiply all ratios by the smallest whole number that gives us whole number ratios for each element, which in this case would be 3 (since 1.34 is approximately 4/3).

After multiplying, the moles of each element become:
C: 1 x 3 = 3
H: 1.34 x 3 ≈ 4
O: 1 x 3 = 3

Thus, the empirical formula of the compound is C3H4O3, and the molecular formula is the same as the empirical formula because the molar mass of C3H4O3 (3(12.0) + 4(1.0) + 3(16.0) = 88.0 g/mol) is half that of the given molar mass. Therefore, the molecular formula must be C6H8O6, which is twice the empirical formula.

The correct molecular formula of the compound is D. C6H8O6.

The answer is d. Igneous rocks is indeed formed through the cooling of molten lava on the surface, making extrusive igneous rock. However, if those underground pockets of magma were to cool underneath the surface, because of its force to, it will still form intrusive igneous rock, slowly cooling.

The study of rocks is called petrology. There are different types of rocks and are igneous rock, magma, igneous rock and etc.

The correct answer is D which is cooled slowly and intrusive.

Igneous rocks are indeed formed through the cooling of molten lava on the surface, making extrusive igneous rock.

However, if those underground pockets of magma were to cool underneath the surface, because of its force, it will still form intrusive igneous rock, slowly cooling.

Hence, the correct answer is option D.

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The main function of concept mapping is: C. Organization

A map can be defined as a representation of all or some parts of the Earth drawn to scale on a flat surface.

In Science, there are different types of map and these include;

A concept map can be defined as a visual representation of information and ideas, so as to depict (illustrate) the relationships between two or more concepts while organizing them.

Hence, main function of concept mapping is for the proper organization or structuring of information and ideas in a graphic format.

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1] Find out how many moles  

2] Use Avagadro's number to find number of molecules  

1] [2.3 g (NH4)2SO4] x [1 mol (NH4)2SO4] / [132.14g(NH4)2SO4 )] = 0.017406 moles (NH4)2SO4  

2] 0.017406 moles x 6.022 x 10^23 molecules/mole = 1.05 x 10^21 molecules (NH4)2SO4

Answer: Yes it is possible for two different compounds to be made from the exact two same elements.

Reason: Oxygen(O)+Oxygen(O)=Oxygen Gas(O2)

The correct option is A. which is the concentration of calcium in the myofibril must decrease.

Answer:

5.3 × 10⁻¹⁷ mol·L⁻¹

Explanation:

Let s = the molar solubility.

                Cu₂S(s) ⇌ 2Cu⁺(aq) + S²⁻(aq); K_{sp} = 6.1 × 10⁻⁴⁹

E/mol·L⁻¹:                        2s             s

K_{sp}  =[Cu⁺]²[S²⁻] = (2s)²×s = 4s^3 = 6.1 × 10⁻⁴⁹

[tex]s^{3}= \frac{6.1 \times 10^{-49}}{4} = 1.52 \times 10^{-49}[/tex]

[tex]s = \sqrt[3]{1.52 \times 10^{-49}} \text{ mol/L} = 5.3 \times 10^{-17} \text{ mol/L}[/tex]

The solubility of copper(I) sulfide, Cu2S, in water, given its Ksp value of 6.1 × 10^-49, is calculated to be approximately 1.15 × 10^-17 mol/L. by understanding the dissolution process and solving the Ksp expression.

The question asks about the solubility of copper(I) sulfide, Cu2S, given its Ksp value is 6.1 × 10^-49. To solve for the solubility in mol/L, we must first understand the dissolution process of Cu2S in water. The equation for this process is Cu2S(s) → 2 Cu+(aq) + S2-(aq). For every mole of Cu2S that dissolves, it produces 2 moles of Cu+ and 1 mole of S2-. Therefore, if the solubility of Cu2S is 's' mol/L, the concentration of Cu+ ions is 2s mol/L, and the concentration of S2- ions is s mol/L.

Substituting these values into the Ksp expression gives: Ksp = [2s]^2[s] = 4s^3. Plugging in the Ksp value of 6.1 × 10^-49 and solving for 's' provides: 4s^3 = 6.1 × 10^-49, leading to s^3 = 1.525 × 10^-49 and s ≈ 1.15 × 10^-17 mol/L. Therefore, the solubility of copper(I) sulfide, Cu2S, in water is approximately 1.15 × 10^-17 mol/L.

Answer:

Mg+2     Its D

Explanation:

DDDDDDDDDDDDDDDDDD on edge 2020

Answer:

Its D.

Explanation:

Got it correct in the question.

Answer : The initial quantity of sodium metal used is 17.25 grams.

Solution : Given,

Volume of [tex]H_2[/tex] gas = 8.40 L

Molar mass of Na metal = 23 g/mole

The Net balanced chemical reaction is,

[tex]2Na+2H_2O\rightarrow 2NaOH+H_2[/tex]

At STP,  22.4 L of volume is occupied by 1 mole of [tex]H_2[/tex] gas

so,  8.40 L of volume is occupied by = [tex]\frac{8.40L\times 1mole}{22.4L}[/tex] = 0.375 moles of [tex]H_2[/tex] gas

Now from the above reaction, we conclude that

1 mole of [tex]H_2[/tex] gas produced by the 2 moles of Na metal

0.375 moles of [tex]H_2[/tex] gas produced = [tex]\frac{2moles\times 0.375mole}{1mole}=0.75moles[/tex] of Na metal

The quantity of Na metal used = Moles of Na metal × Molar mass of Na metal = 0.75 moles × 23 g/mole = 17.25 grams

Therefore, the initial quantity of sodium metal used is 17.25 grams.

Answer:

17.2

Explanation:

took the test

Answer: 5.5

The alien planet has unfamiliar names for substances and units of measures.  

8 quibs of the substance called skwarnick has been obtained.

According to the units of  measurement used in the alien planet,

13 quibs equal to 9 sleps

Therefore, 1 quib =[tex]\frac{9}{13}sleps[/tex]

Thus, 8 quibs of skvarnick = [tex]\frac{9}{13}[/tex] x 8 = 5.5 sleps.

For this reason, 8 quibs of skvarnick in units of sleps is 5.5 sleps.

Jon should report his answer to one significant digit only.

When several numbers are multiplied, the number of significant digits in the final answer is determined by the number that has the least number of significant digits.

In this case, 1 has only one significant digit, whereas 2.0 has two, 3.00 has three, and 4.000 has four significant digits. Hence, 1 strongly affects the number of significant figures in the answer.

Answer: A. for those who dont like to read

Explanation:

Neither plate subducts because the crust have approximately the same density. Instead, the rocks are smashed together causing them to recrystallize due to the intense heat and pressure from the colliding plates.

Start by determining the oxidation numbers of each element on both sides of the equation CuO(s) + H2 (g) → Cu(s) + H2O (l)

Let's start with the reactants.

In the compound CuO(s), the oxidation number of O is -2 and the oxidation number of Cu is +2. (Remember, oxygen's oxidation number is -2 unless it's in a peroxide)

In H2(g) the oxidation number of H is 0 because it is in its elemental form.

Now onto the products

The oxidation number of Cu(s) is 0 because it is in its elemental form

In H2O(l) the oxidation number of oxygen is -2, and the oxidation number of H is +1.

Now let's summarize the change in the oxidation numbers of each element.

Cu: started as +2 and became 0

O: started as -2 and became -2 (didn't change)

H: started as 0 and became +1

To determine which element was oxidized, we look at which element lost electrons, and thus became more positive. So, we can determine that H was oxidized in this reaction, because it started with the oxidation number 0 and became +1.

Answer: you are a god

Explanation:

Neutrons are very important in provide stability for an atom. When atoms are created by fusion, neutrons are included in this process. Because protons don't like each other and repel each other that's where neutrons come in.

answer: the role of a neutron in an atom holds the center of the atom so it provides the stability of the center of the atom.

hope this helps! ❤ from peachimin

Answer:

0.089.

Explanation:

Cl₂O + H₂O ⇄ 2HClO,

Kc = [HClO]²/[Cl₂O][H₂O].

[H₂O] = 0.077 M , [Cl₂O] = 0.077 M , [HClO] = 0.023 M.

∴ Kc = [HClO]²/[Cl₂O][H₂O] = (0.023 M)²/(0.077 M)(0.077 M) = 0.08922 ≅ 0.089.

Answer:

A

Explanation:

It told me

Answer: Option (C) is the correct answer.

Explanation:

According to collision theory, more is the number of collision between the reactant molecules more will be the rate of reaction.

For example, [tex]Mg + 2HCl \rightarrow MgCl_{2} + H_{2}[/tex]

When we increase the concentration of reactants then it means there is increase in number of molecules. Hence, more is the number of molecules more will be the number of collisions.

Thus, we can conclude that by increasing the concentration of Mg in the reaction mixture we increase the rate of collisions between the reactants in this reaction.

Answer:

C. Increase the concentration of Mg in the reaction mixture.

Explanation:

Hello!

To find the mass in grams of 100 atoms of carbon, we need to use Avogadro's number, which is 6.02 x 10^23 grams, and divide that by the total number of atoms.

Next, we would need to find how much one mole of carbon weighs. In this case, it is exactly 12 grams.

1. Divide by Avogadro's number

100 / (6.02 x 10^23) ≈ 1.66 x 10^-22  

2. Multiply by one mole of carbon

(1.66 x 10^-22) x 12 ≈ 2.0 x 10^-21

Therefore, the mass of 100 atoms of carbon is equal to about 2.0 x 10^-21 grams.

Moles of a gas = 0.500

Volume = 2.50 L

Pressure = 13. atm

Temperature = ?

Solution:

Formula:

                       PV = n RT

Putting the values in formula:

 T = PV/nR = 13 * 2.5 / 0.5 *  0.082057

   =  32.5/0.041 = 792.68 K

                    T = 792.68 K

Answer:

B.0.456 g

Explanation:

It is that becuase if u convert miligrams to grams it is 1000mg =1g

Srry if I'm late the answer to the first question about chemical changes is B. when a new substance is formed, it's going to be chemical. For example, when you burn paper, it turns into ash, which is a new substance. The burning is a chemical change. C is wrong because you can undo the mixture.

For number 2, the trick is to check if there is a carbon is double bonded to another carbon. Then it would be unsaturated. You can also check if there's a kink the chain. So therefore,

saturated is 3-methl..  and propane

unsaturated is propyne heptyne and cyclpentene

good luck!

The statement that describes a Chemical changes in hematite is B. The hematite particles rearrange to form a new substance.

The statement that describes a chemical change in hematite is B. The hematite particles rearrange to form a new substance.

A chemical change involves the formation of new substances with different chemical properties.

In this case, the rearrangement of hematite particles leads to the formation of a new substance.

Example: When hematite (Fe2O3) is heated strongly, it undergoes a chemical change and turns into magnetite (Fe3O4).

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