A lucky integer is a positive integer which is divisible by the sum of its digits. what is the least positive multiple of 9 that is not a lucky integer?

Answers

Answer 1

99.

It is not divisible by 18. Before that they are all added up to 9.

Related Questions

Which of these is an example of continuous random variable

A. Number of flights leaving an airport
B. Distance of a javelin throw
C. Pieces of mail in your mailbox
D. Attendance at a sporting event

Answers

The correct answer would be Choice B. Distance of a javelin throw.

A continuous random variable is a variable that can be any number between the integers not just the integers themselves.

For example, the distance for a javelin throw could be 6.70819203 feet.
However, you would not say that you have 6.70819203 flights, pieces of mail or people at a sporting event.

Final answer:

The B. distance of a javelin throw is an example of a continuous random variable.

Explanation:

A continuous random variable is a variable that can take any value within a specified range, often associated with measurements and quantities. Unlike discrete variables, it can assume an infinite number of values, typically represented by intervals on the real number line.

Out of the given options, the distance of a javelin throw is an example of a continuous random variable. A continuous random variable is one that can take on any value within a given range. In the case of a javelin throw, the distance can be any real number value within a certain range, such as 0 to infinity. This is in contrast to the other options, which are discrete random variables that can only take on specific whole number values.

Rewrite with only sin x and cos x. Sin2x-cos2x

Answers

From trig identities, we know that sin2x = 2sinxcosx and cos2x = [tex]cos^{2} x - sin^{2} x[/tex]

So sin2x-cos2x = 2sinxcosx - ([tex]cos^{2} x - sin^{2} x[/tex]) in terms of sinx and cosx

help me 15p for an answer and brainliest
help mme please
the true it is 20p

Answers

Option 4.
______________

Answer:

Option 4.

Step-by-step explanation:

can you please help me on this worksheet and try to show the work

Answers

For 13 and 14, the conversion factor is
180° = π radians

13. (105°)*(π radians)/180° = 7π/12 radians

14. 5π/6 radians * 180°/(π radians) = 150°

15. (The geometry shown cannot actually exist. The total of subtended arcs on any linked sprockets must be 360°.)
a.
The arc length on the smaller sprocket is (12 in)*(160/360) = 5 1/3 in.
The arc length on the larger sprocket is (20 in)*(185/360) = 10 5/18 in.
The total chain length is 5 6/18 +10 + 10 5/18 + 10 = 35 11/18 in. Rounded to the nearest tenth inch, the chain length is 10.3 inches.

b.
10.3/0.5 ≈ 20.6 ≈ 21
The chain has about 21 links. (There are no "teeth" on a chain.)

1. The radius can be found by looking at the distance between the origin and the line 8x+6y-48=0. That distance is |-48|/√(8²+6²) = 4.8.

Since the radius of the circle is 4.8, so its circumference is ...
9.6π cm, about 30.159 cm.

2. s = rθ
s = (12 cm)(π/3 radians) = 4π cm
The length of arc AB is 4π cm, about 12.566 cm.

A man has 25 25 coins in his pocket, all of which are dimes and quarters. if the total value of his change is $ 4.45 $4.45, how many dimes and how many quarters does he have?

Answers

If all were dimes, the value would be $2.50. The man has $1.95 more than that amount. Trading a dime for a quarter increases the value by $0.15, so there must be
$1.95/$0.15 = 13
quarters.

The man has 12 dimes and 13 quarters.

_____
Check:
12*$0.10 +13*$0.25 = $1.20 +3.25 = $4.45 . . . (answer checks OK)

10 POINTS!!! FULL ANSWER IN STEP BY STEP FORMAT!!

Answers

I find short work can be made of many limit problems simply by graphing them. Your limits appear to be:
1. 1
2. -1
3. 0
4. 1
5. 1 (x has been replaced by 1/x and the limiting value of x changed to 0)

Use the given graph to determine the limit, if it exists.
Find limit as x approaches two from the left of f of x. and limit as x approaches two from the right of f of x.

Answers

We can see from the graph, as the value of x approaches 2 from the left hand side i.e. the negative side, the value of the function approaches 4.

As the value of x approaches 2 from the positive side i.e. the right hand side, the value of function approaches -4

Since the Right hand limit and the Left hand limit as x approaches 2 are not the same, the limit does not exist at x = 2

Write an algebraic expression for the verbal description. the distance a car travels in t hours at a rate of 50 miles per hour

Answers

The correct answer is
d=50t
Where; d is the distance covered in miles
t is the time taken in hours

The algebraic expression is D = 50t where D is the distance covered in miles and t is the time taken in hours.

What is the distance?

Distance is defined as the product of speed and time.

What are Arithmetic operations?

Arithmetic operations can also be specified by adding, subtracting, dividing, and multiplying built-in functions.

The operator that performs the arithmetic operations is called arithmetic operator.

* Multiplication operation: Multiplies values on either side of the operator

For example 4*2 = 8

/ Division operation: Divides left-hand operand by right-hand operand

For example 4/2 = 2

Given that the distance a car travels in t hours at a rate of 50 miles per hour

Let the distance covered in miles = D

And t is the time taken in hours

Since distance is defined as the multiplication of speed and time.

So an algebraic expression for the verbal description as

⇒ D = 50t

Hence, the algebraic expression is D = 50t where D is the distance covered in miles and t is the time taken in hours.

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Find the area of the shaded region.

Answers

1)
Area of bigger rectangle
A = (x+1)(x+1) = x^2 + 2x + 1

2)
Area of smaller rectangle
A = 5(x - 7) = 5x - 35

3)
The difference:
(x^2 + 2x + 1) - (5x - 35)
= x^2 + 2x + 1 - 5x +35
= x^2 - 3x + 36

area of the shaded region = x^2 - 3x + 36

Hello!

You first have to find the area of the bigger rectangle

You find this by multiplying the sides

(x + 1)(x + 1) = x^2 + 2x + 1

Next you have to find the area of the smaller rectangle

(x - 7) * 5 = 5x - 35

Subtract the two polynomials

(x^2 + 2x + 1) - (5x - 35) = x^2 - 3x + 36

The answer is [tex] x^{2} -3x + 36[/tex]

Hope this helps!

look at the image then answer the question that goes with it

Answers

[tex]\sin(\theta) = \dfrac{\text{opp}}{\text{hyp}}[/tex]

[tex]\sin(60) = \dfrac{x}{8} [/tex]

[tex]x = 8\sin(60) [/tex]

[tex]x = \dfrac{8 \sqrt{3} }{2} [/tex]

[tex]x = 4 \sqrt{3} [/tex]

x = 8 x sin(60)
x = 4sqrt3

Solve system by elimination
y=x^2
y=x+2
SHOW YOUR WORK

Answers

we have that
y=x²----> equation 1
y=x+2-----> equation 2

multiply equation 1 by -1
-y=-x²

add equation 1 and equation 2
-y=-x²
y=x+2
------------
0=-x²+x+2-------------> -x²+x+2=0-----> x²-x-2=0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x²-x)=2
Complete the square. Remember to balance the equation by adding the same constants to each side
(x²-x+0.5²)=2+0.5²

Rewrite as perfect squares

(x-0.5)²=2+0.5²
(x-0.5)²=2.25-----> (x-0.5)=(+/-)√2.25-----> (x-0.5)=(+/-)1.5
x1=1.5+0.5-----> x1=2
x2=-1.5+0.5---- > x2=-1

for x=2
y=x²----> y=2²----> y=4
the point is (2,4)

for x=-1
y=x²----> y=(-1)²---> y=1
the point is (-1,1)

the answer is
the solution of the system are the points
(2,4) and (-1,1)

describe the steps you would use to solve the following inequality

Answers

[tex] \frac{x + 1}{2x - 3} > 2 \\ x + 1 > 2(2x - 3) \\ x + 1 > 4x - 6 \\ - 3x + 1 > - 6 \\ - 3x > - 7x \\ x < \frac{7}{3} [/tex]

Answer:

Rewrite the inequality so there is a single rational expression on one side, and 0 on the other.

Combine under a common denominator.

Test points in the critical regions.

Construct the solution.

Step-by-step explanation:

Answer Above

What is the best estimate for the sum of 3/8 and 1/12?

Answers

the best estimate is 5/12

The best answer would be 0.458

Choose the example that correctly shows the mean population density of a region.

A. 678 people per cubic meter

B. 678 cubic meter per number of people

C. 678 people per square mile

D. 678 square mile per people

Answers

678 people per cubic meter - lol!! That would be a SQUash!!!

The answer is C

- 678 per square mile

does anyone know the surface area for this problem. if so i will mark brainliest.

Answers

From the given volume, we know that the ratio is:
[tex]\text {Ratio of yellow eraser to white eraser = } \sqrt[3]{ \dfrac{16}{2} } [/tex]

From the given area, we know that the ratio is:
[tex]\text {Ratio of yellow eraser to white eraser = } \sqrt{ \dfrac{52}{x} } [/tex]

Equate the two ratio and solve for x:
[tex]\sqrt[3]{ \dfrac{16}{2} } = \sqrt{ \dfrac{52}{x} } [/tex]

Cube both sides:
[tex]\dfrac{16}{2} = \bigg(\sqrt{ \dfrac{52}{x} }\bigg)^3[/tex]

Square both sides:
[tex]\bigg(\dfrac{16}{2} \bigg)^2 = \bigg( \dfrac{52}{x} }\bigg)^3[/tex]

Simplify each term:
[tex]\dfrac{16^2}{2^2} = \dfrac{52^3}{x^3} [/tex]

Cross multiply:
[tex]256x^3 = 562432[/tex]

Divide both sides by 256:
[tex] x^3 = 2197[/tex]

Cube root both sides:
[tex] x = 13[/tex]

a boy flies a kite with a 100 foot long string. the angle of elevation of the string is 48 degrees. how high is the kite from the ground?

Answers

we know that
in a right triangle
sin ∅=opposite side angle ∅/hypotenuse
opposite side angle ∅=hypotenuse*sin ∅

in this problem
angle ∅=48°
hypotenuse=100 ft
opposite side angle ∅=?----> height of the kite from the ground

opposite side angle ∅=100*sin 48°------> 74.31 ft

the answer is
74.31 ft

Create a function to model the height of a firework when shot in the air. Explain whether the function will have a maximum or a minimum value.

Answers

The function would be h(t)=-16t²+v₀t+0, where v₀ is the initial velocity of the firework.

0 is the initial height, since you cannot hold one in your hand and safely set it off.

This will have a maximum; the firework will reach a highest point and fall back down. This is also evident from the equation; the negative in front of t² flips the parabola upside down, which gives it a maximum.

Simplify. x + 4.7 = −9.2 A. −13.9 B. 13.9 C. −12.9 D. 12.9

Answers

Note the equal sign. What you do to one side you do to the other.

Isolate the x, subtract 4.7 from both sides

x + 4.7 = - 9.2

x + 4.7 (-4.7) = - 9.2 (-4.7)

x = -9.2 - 4.7

x = -13.9

-13.9, or A, is your answer

hope this helps

SOLVE FOR X one question 20 points

Answers

We simply need to use the Pythagorean theorem:
a^2 + b^2 = c^2 (c^2 is the hypertenuse)
The equation will look like this:
14^2 + 14^2 = x^2
196 + 196 = x^2
x^2 = 392
So the answer is the square root of 392:
14[tex] \sqrt{2} [/tex]
If you want a decimal form:
14 * 1.414 = 19.796

Answer:

ANSWER IS

Step-by-step explanation:

The shorter leg of a right triangle is 7 inches shorter than the longer leg. The hypotenuse is 17 inches longer than the longer leg. Find the side lengths of the triangle.

Answers

Or round them all up.

a² + b² = c²

c² - a² = b²

17² - 7² = x² ↓

289 - 49 = √240

√240 = 15.49193338482967 (rounded 15.49 or 15.5)

Hope this helps,

♥A.W.E.S.W.A.N.♥

If the areas of two rhombi are equal, are the perimeters sometimes, always or never equal. explain your answer – you can use examples with actual numbers to do so.equalif the areas of two rhombi are equal

Answers

If the areas are equal then the perimeters are also equal.
The area of a rhombus = length of base * altitude. To keep the area the same we would have to keep the same base and move the opposite side so its parallel to the base. But doing this will lengthen the other 2 sides of the figure so its no longer a rhombus.

The perimeters of two rhombi with equal areas are sometimes equal, but not always.

Let's consider the formula for the area of a rhombus, which is given by [tex]$ A = \frac{1}{2} \times d_1 \times d_2 $, where $ d_1 $ and $ d_2 $[/tex] are the lengths of the diagonals. For the perimeter P, we have [tex]$ P = 4 \times s $[/tex], where s is the length of one side of the rhombus.

For two rhombi to have equal areas, the product of their diagonals must be the same. That is, if we have two rhombi with diagonals [tex]$ (d_1, d_2) $ and $ (d_1', d_2') $, then $ d_1 \times d_2 = d_1' \times d_2' $[/tex].

However, the perimeter depends only on the length of one side, s, and not on the diagonals. Therefore, two rhombi with the same area can have different side lengths and thus different perimeters.

Let's consider an example:

Rhombus 1:

[tex]- Diagonals $ d_1 = 8 $ units and $ d_2 = 4 $ units[/tex]

[tex]- Area $ A = \frac{1}{2} \times 8 \times 4 = 16 $ square units[/tex]

[tex]- Side length $ s $, using the Pythagorean theorem (since the diagonals bisect each other at right angles), is $ s = \sqrt{4^2 + 2^2} = \sqrt{16 + 4} = \sqrt{20} $ units[/tex]

[tex]- Perimeter $ P = 4 \times s = 4 \times \sqrt{20} $ units[/tex]

Rhombus 2:

[tex]- Diagonals $ d_1' = 10 $ units and $ d_2' = 3.2 $ units[/tex]

[tex]- Area $ A' = \frac{1}{2} \times 10 \times 3.2 = 16 $ square units (equal to the area of Rhombus 1)[/tex]

[tex]- Side length $ s' $, using the Pythagorean theorem, is $ s' = \sqrt{1.6^2 + 2.56^2} = \sqrt{2.56 + 6.5536} = \sqrt{9.1136} $ units[/tex]

[tex]- Perimeter $ P' = 4 \times s' = 4 \times \sqrt{9.1136} $ units[/tex]

Comparing the perimeters:

[tex]- $ P = 4 \times \sqrt{20} \approx 4 \times 4.472 = 17.888 $ units[/tex]

[tex]- $ P' = 4 \times \sqrt{9.1136} \approx 4 \times 3.0188 = 12.0752 $ units[/tex]

Clearly, the perimeters are not equal, even though the areas are the same.

However, it is possible for two rhombi with equal areas to have equal perimeters if their side lengths are the same. For instance, if Rhombus 1 and Rhombus 2 both had side lengths of s = s' = 4 units, then their perimeters would both be P = P' = [tex]4 \times 4 = 16 \)[/tex] units, regardless of the lengths of their diagonals, as long as the diagonals satisfy the area condition [tex]$ d_1 \times d_2 = d_1' \times d_2' $[/tex].

In conclusion, the perimeters of two rhombi with equal areas can sometimes be equal, specifically when the side lengths are the same, but they are not always equal, as demonstrated by the example above.

find the greatest common factor 9x^2a + 9xa^2

Answers

To get the GCF we proceed as follow:
9x^2a+9xa^2
factor out 9 we get:
9(x^2a+xa^2)
=factoring out x we get
9x(xa+a^2)
factoring out a we get
9ax(x+a)
therefore the GCF is 9ax

if (x+1) is a factor of x^3+2x^2-x-2, find the remaining factors.

Answers

Using synthetic division to divide x³ + 2x² - x - 2. Since (x + 1) is the factor, we can divide by -1. See the attached file for the synthetic division. After that, we are left with x² + x - 2. This can easily be factored into (x + 2)(x - 1). The remaining factors are (x + 2) and (x - 1).

Answer:

The other factors are (x-1) and (x+2).

Find the determinant of G

Answers

the determinant is found by the formula ad-cb

where the letters are: a and b is the top row and c and d is the bottom row
so ad = 12*2 and cb = -6*0

12x2 = 24
-6x0 =0

24-0 = 24
the determinant = 24

Rachel enjoys exercising outdoors. Today she walked5 2/3 miles in2 2/3 hours. What is Rachel’s unit walking rate in miles per hour and in hours per mile

Answers

the answer to your question is

Unit walking rate in miles per hour = 5 2/3 / 2 2/3 = 17/3 / 8/3 = 17/3 x 3/8 = 17/8 = 2 1/8 miles per hour.

Unit walking rate in hours per mile = 1/ 17/8 = 8/17 hours per mile

Answer:

Rachel enjoys exercising outdoors. Today she walked 5 2/3 miles or 5.67 miles in 2 2/3 hours or 2.67 hours.

Rachel’s unit walking rate in miles per hour is = [tex]\frac{5.67}{2.67}[/tex] = 2.125 miles per hour or 2 1/8 miles per hour.

Rachel’s unit walking rate in hours per mile = [tex]\frac{2.67}{5.67}[/tex] = 0.47 hours per mile.

Find the values of b such that the function has the given maximum value. f(x) = −x2 + bx − 14; Maximum value: 86

Answers

[tex]f(x)=-x^2+bx-14\\\\y_{max}=86[/tex]
[tex]y_{max}\ \text{is in the vertex of the parabola}.[/tex]
[tex]\text{The coordinates of the vertex of the parabola}\ f(x)=ax^2+bx+c:\\\\V\left(\dfrac{-b}{2a};\ \dfrac{-(b^2-4ac)}{4a}\right)[/tex]
[tex]\text{We have:}\\\\f(x)=-x^2+bx-14\to a=-1;\ b=b;\ c=-14[/tex]
[tex]\text{Substitute:}\\\\\dfrac{-\left(b^2-4\cdot(-1)\cdot(-14)\right)}{4\cdot(-1)}=86\\\\\dfrac{b^2-56}{4}=86\ \ \ \ |\cdot4\\\\b^2-56=344\ \ \ \ |+56\\\\b^2=400\to b=\pm\sqrt{400}\\\\b=-20\ \vee\ b=20[/tex]
Answer: b = -20 or b = 20.

Final answer:

To find the value of 'b' that gives the maximum value of 86 for the function f(x) = -x² + bx - 14, substitute the x-coordinate of the vertex (-b/2a) into the function, equate it with 86 and solve for 'b'.

Explanation:

To find the values of b for which the quadratic function f(x) = -x² + bx - 14; Maximum value: 86 holds true, we need to utilize the properties of quadratic functions. In a quadratic function in the form f(x) = ax² + bx + c, the maximum value occurs at the vertex of the parabola. The x-coordinate of the vertex is given by -b/2a.

Given that our quadratic is a maximum (opens downwards since a=-1), the y-coordinate of the vertex, which is our maximum value, is 86. Substituting these into our function, we get f(-b/2a) = 86, replacing a=-1, this reduces to -b²/4 -14 = 86. Simplifying this equation will give you the value of b.

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The length of a rectangle is 4 feet shorter than its width. the area of the rectangle is 42 square feet. find the length and width. round your answer to the nearest tenth of a foot

Answers

Length is [tex]\boldsymbol{4.4}[/tex] feets and width is equal to [tex]\boldsymbol{8.8}[/tex] feets.

Area of a rectangle

The area of a two-dimensional region, form, or planar lamina in the plane is the quantity that expresses its extent.

A quadrilateral having four right angles is known as a rectangle.

Let [tex]\boldsymbol{w}[/tex] feets denotes width of a rectangle.

Length of a rectangle [tex]=\boldsymbol{w-4}[/tex] feets

Area of a rectangle [tex]=\boldsymbol{42}[/tex] square feet

Length [tex]\times[/tex] Width [tex]=42[/tex]

[tex]w(w-4)=42[/tex]

[tex]w^2-4w-42=0[/tex]

[tex]w=\frac{4\pm \sqrt{16+168}}{2}[/tex]

[tex]=2\pm \sqrt{46}[/tex]

As dimension can not be negative, [tex]2-\sqrt{46}[/tex] is rejected.

So,

[tex]w=2+ \sqrt{46}[/tex]

[tex]=\boldsymbol{8.8}[/tex] feets

Length [tex]=8.8-4[/tex]

[tex]=\boldsymbol{4.4}[/tex] feets

So, length is [tex]4.4[/tex] feets and width is equal to [tex]8.8[/tex] feets.

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PLEASE HELP! - Caitlyn recorded the height of each plant after she exposed each plant to a set amount of darkness daily. The scatterplot shows her results after 2 weeks of exposing each plant to the amount of darkness.

(Graph Below)

Which statement about the scatterplot is true?
A. The point (17, 12) could cause the description of the data set to be overstated.
B. The point (17, 12) could cause the description of the data set to be understated.
C. The point (17, 12) shows that there is no relationship between the number of hours of darkness and the height of the plant.
D. Although (17, 12) is an extreme value, it should be part of the description of the relationship between number of hours of darkness and the height of the plant.

Answers

Answer:

I think it's b, please correct me if I'm wrong.

Step-by-step explanation:

I'm taking the test rn so I hope its right.

Answer:

its b i just did it

Step-by-step explanation:

PLEASE HELP ME

If the maximum density of killer whales per cubic foot is 0.000011142, what is the maximum number of killer whales allowed in the main show tank at any given time? You must explain your answer using words, and you must show all work and calculations

Answers

a]
Given that the the tank has a radius of 70 ft;
The volume of the sphere will be:
V=1/4[4/3*pi*r^3]
v=1/4[4/3*3.14*70^3]
V=359,006.6675

b] The maximum number of whales will be given by:
density=mass/volume
thus
0.000011142=x/(359006.6675)
thus
x=0.000011142*359006.6675
x=4
thus the maximum number of whale would be 4

How many degrees is w?

Answers

See the attached picture:

w = 180 - (180 -142) - 49
w = 180 -38 - 49
w = 93

Answer
w = 93°

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