A marketing firm is studying consumer preferences for winter fashions in four different months. From a population of women, 18-21 years of age, a random sample of 100 women was selected in January. Another random sample of 100 women was selected in March. Another random sample of 100 women was selected in June. Another random sample of 100 women was selected in September.
A) The sample size was 4.
B) The sample size was 100.
C) The sample size was 400.
D) The sample size was 1.

Answers

Answer 1

Answer:

B) The sample size was 100

Step-by-step explanation:

Number of sample size in January = 100

Number of sample size in March   = 100

Number of sample size in June     = 100

Number of sample size in  September = 100

The average sample size for the study = (100 +100+100+100)/4  

                                                                =  400/4

                                                                = 100

So the average sample size for the study is 100 women between 18 to 21 years.


Related Questions

the circular ripple caused by dropping a stone in a pond is increasing in area at a constant rate of 20 square meters per second. Determine how fast the radius of this circular ripple is increasing when the area of the circular region is 25 pi

Answers

Answer:

  2/π ≈ 0.637 m/s

Step-by-step explanation:

The rate of change of area with respect to time is ...

  A = πr²

  dA/dt = 2πr·dr/dt

Filling in given values in the above equations, we can find r and dr/dt.

  25π = πr²   ⇒   r = 5

  20 = 2π·5·dr/dt

  dr/dt = 20/(10π) = 2/π . . . . meters per second

The radius is increasing at the rate of 2/π ≈ 0.637 meters per second.

In a recent survey of drinking laws, a random sample of 1000 women showed that 65% were in favor of increasing the legal drinking age. In a random sample of 1000 men, 60% favored increasing the legal drinking age. Test the hypothesis that the percentage of men and women favoring a higher legal drinking age is the same. Use α = 0.05.

Answers

Answer:

The percentage of men and women favoring a higher legal drinking age is the same

Step-by-step explanation:

A random sample of 1000 women showed that 65% were in favor of increasing the legal drinking age

n = 1000

No. of females were in favor of increasing the legal drinking age = [tex]\frac{65}{100} \times 1000=650[/tex]

y=650

In a random sample of 1000 men, 60% favored increasing the legal drinking age

n = 1000

No. of males were in favor of increasing the legal drinking age = [tex]\frac{60}{100} \times 1000=600[/tex]

y=600

[tex]n_1=1000 , y_1=650\\n_2=1000 , y_2=600[/tex]

We will use Comparing Two Proportions

[tex]\widehat{p_1}=\frac{y_1}{n_1}[/tex]

[tex]\widehat{p_1}=\frac{650}{1000}[/tex]

[tex]\widehat{p_1}=0.65[/tex]

[tex]\widehat{p_2}=\frac{y_2}{n_2}[/tex]

[tex]\widehat{p_2}=\frac{600}{1000}[/tex]

[tex]\widehat{p_2}=0.6[/tex]

Let p_1 and p_2 be the probabilities of men and women favoring a higher legal drinking age is the same.

So, [tex]H_0:p_1=p_2\\H_a:p_1 \neq p_2[/tex]

[tex]\widehat{p}=\frac{y_1+y_2}{n_1+n_2} =\frac{600+650}{1000+1000}=0.625[/tex]

Formula of test statistic :[tex]\frac{\widehat{p_1}-\widehat{p_2}}{\sqrt{\widehat{p}(1-\widehat{p})(\frac{1}{n_1}+\frac{1}{n_2})}}[/tex]

test statistic : [tex]\frac{0.65-0.6}{\sqrt{0.625(1-0.625)(\frac{1}{1000}+\frac{1}{1000})}}[/tex]

test statistic : 2.3094

Refer the z table for p value :

p value : 0.9893

α = 0.05.

p value > α

So, we failed to reject null hypothesis .

So,  the percentage of men and women favoring a higher legal drinking age is the same

Sally has just finished her thirty-fifth year with her company and is getting ready to retire. During her thirty-five years, Sallys average annual salary was 45,603 How much can Sally expect to receive from Social Security annually if she were to retire today?
a. $191.53
b. $1,915.33
c. $19,153.26
d. $191,532.60

Answers

Answer:

$19153.26

Step-by-step explanation:

Here is the complete question: Sally has just finished her thirty-fifth year with her company and is getting ready to retire. During her thirty-five years, Sallys average annual salary was 45,603 How much can Sally expect to receive from Social Security annually if she were to retire today? (Assume she will receive 42% of her average annual salary.)

Given: Sally´s average salary while working is $45603.

           Sally will receive 42% of her average annual salary as social security.

Now, finding annual income of sally after retirement.

Sally´s income from social security after retirement= [tex]\frac{42}{100} \times 45603= \$ 19153.26[/tex]

Sally receive $ 19153.26 annually from social security.

Which of the following best describes artificial intelligence? a. To build systems that can mimic human intelligence b. Viewing the physical world with computer-generated layers of information c. A computer simulated environment d. A knowledge-based information system that accomplishes specific tasks on behalf of its users

Answers

Answer:

a. To build systems that can mimic human intelligence.

Step-by-step explanation:

Artificial intelligence or machine intelligence is a part of computer development where computer systems are made to be able to perform tasks that usually require human intelligence like - speech recognition, language translation etc.

Artificial intelligence seeks to build a system that can mimic human intelligence.

Hence, the correct answer is option A.

Artificial intelligence seeks to build systems that can mimic human intelligence. Then the correct option is A.

What is artificial intelligence?

The ability of an electronic machine that can perform tasks commonly associated with intelligent beings.

Artificial intelligence is a part of computer development where computer systems are made to be able to perform tasks that usually require human intelligence like speech recognition, language translation, etc.

Since all the condition that is fulfilled by option A.

Thus, the correct option is A.

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Given a central angle of 100 in a circle with a radius of 7 in., what is the intercepted arc length of the central angle?

**Use 3.14 for π and round to ONE decimal place.

Answers

Answer:

12.2 inches

Step-by-step explanation:

Write and solve a proportion.

Arc length / circumference = central angle / 360°

x / (2π × 7) = 100° / 360°

x = 12.2

The arc length is 12.2 inches

Naturally occurring gallium is a mixture of isotopes that contains 60.11% of Ga-69 (atomic mass = 68.93 u) and 39.89% of Ga-71 (atomic mass = 70.92 u). Which numerical setup can be used to determine the atomic mass of naturally occurring gallium?

Answers

Final answer:

To determine the atomic mass of naturally occurring gallium, convert the percentages of each isotope to decimals, multiply each decimal by its atomic mass, and add the products. The average atomic mass of gallium is 69.72 u.

Explanation:

The atomic mass of naturally occurring gallium can be determined using the following numerical setup:

Convert the percentages of the isotopes (60.11% and 39.89%) to decimals (0.6011 and 0.3989).

Multiply the decimal for each isotope by its atomic mass.

Add the products from step 2 to get the average atomic mass.

Round the final result to the appropriate number of significant figures.

In this case, the numerical setup would be:

(0.6011 x 68.93 u) + (0.3989 x 70.92 u) = 69.72 u

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Final answer:

To find the atomic mass of naturally occurring gallium, you perform a weighted average, multiplying the abundance of each isotope by its atomic mass, then summing the results. Using the given abundances and atomic masses, the atomic mass of gallium is approximately 69.75 u.

Explanation:

To calculate the atomic mass of naturally occurring gallium, which is a mixture of isotopes, you would set up a weighted average based on the isotopic composition and the atomic masses of the individual isotopes. You have Ga-69 with an atomic mass of 68.93 u, comprising 60.11% of gallium, and Ga-71 with an atomic mass of 70.92 u, making up 39.89% of gallium.

The numerical setup is as follows:

Atomic mass of gallium = (% abundance of Ga-69 × atomic mass of Ga-69) + (% abundance of Ga-71 × atomic mass of Ga-71)

Converting the percentage to a decimal fraction (60.11% = 0.6011 and 39.89% = 0.3989), the equation becomes:

Atomic mass of gallium = (0.6011 × 68.93 u) + (0.3989 × 70.92 u)

We then perform the multiplication and add the results:

Atomic mass of gallium = (0.6011 × 68.93 u) + (0.3989 × 70.92 u) = 41.433863 u + 28.320708 u = 69.754571 u

Thus, the atomic mass of naturally occurring gallium can be approximated to 69.75 u.

I’d appreciate the help!

Answers

Answer:

[tex]\displaystyle 1\frac{119}{250}\:liter[/tex]

[tex]\displaystyle 7,5\:sleps[/tex]

[tex]\displaystyle 37,3\:sleps [/tex]

Step-by-step explanation:

[tex]\displaystyle 1\frac{119}{250} = \frac{1476}{1000}[/tex]

[tex]\displaystyle 1\frac{1}{13} \times 7 = 7\frac{7}{13} ≈ 7,538461538 ≈ 7,5[/tex]

[tex]\displaystyle \frac{41}{1\frac{1}{10}} = 37\frac{3}{11} ≈ 37,3[/tex]

I am joyous to assist you anytime.

You bike 9.8 miles in 1.4 hours at a steady rate.What equation represents the proportional relationship between the x hours you bike and the distance in miles that you travel

Answers

Answer:

The equation is [tex]\frac{x}{y}= 8[/tex]

Step-by-step explanation:

Let the time for which i bike is = x hours

Let the distance traveled in x hours = y miles

Ratio of distance and time will be = x : y

I travel 11.2 miles in 1.4 hours then the ratio of time and the distance traveled will be 1.4 : 11.2 Or 14 : 112

then the ratio of distance and time will be same in both the cases

So equation will be

[tex]\frac{x}{y} =\frac{14}{112}\\\\\frac{x}{y} =8[/tex]

Hence, equation representing the proportional relationship will be  [tex]\frac{x}{y}= 8[/tex]

A sample size of n=12 is a simple random sample selected from a normally distributed population. Find the critical value t* corresponding to a 95% confidence level (two-sided).

Answers

Final answer:

For a sample size of n=12, the degrees of freedom (df) would be 11, and the critical t value for a two-tailed 95% confidence interval is typically around 2.201, as determined by a t-distribution table or statistical software.

Explanation:

To find the critical t* value corresponding to a 95% confidence level for a sample size of n=12, you must take into account that the degrees of freedom (df) are equal to n - 1, which is 11 in this case. You use a t-distribution, not the z-distribution, because the population standard deviation is unknown. The critical t* value can be found using a t-distribution table or statistical software.

With the degrees of freedom at 11 for a 95% confidence interval (two-sided), the critical t value is typically around 2.201. However, one must look up the exact value using statistical software or a t-distribution table, as the value may vary slightly based on different sources or rounding.

Thus, to answer the student's question: For a two-tailed 95 percent confidence interval and 11 degrees of freedom, the corresponding critical value t* will typically be around 2.201.

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In a certain carnival game the player selects two balls at random from an urn containing 3 red balls and 9 white balls. The player receives $4 if he draws two red balls and $1 if he draws one red ball. He loses $2 if no red balls are in the sample. Determine the probability distribution for the experiment of playing the game and observing the player's earnings.
The probability to draw two red balls is __, to draw one red ball is __, and to draw zero red balls is __.

Answers

Answer:

The probability to draw two red balls = 1/22

The probability to draw one red ball = 9/22

The probability to draw no red ball = 12/22

Step-by-step explanation:

Number of Red balls = 3

Number of White balls = 9

If the player draws two red balls, he receives $4

If the player draws one red ball, he receives $1

If the player draws no red ball, he looses $2

The total number of balls = 3+9

= 12

Let R represent Red balls

Let W represent White balls

The probability that the player earns $4 by picking two red balls is represented as Pr(R1 n R2)

Pr(R1 n R2) = Pr(R1) * Pr(R2)

Pr(R1) = 3/12

= 1/4

Pr(R2) = 2/11(we assume he draws without replacement)

Pr(R1 n R2) = 1/4*2/11

= 2/44

= 1/22

The probability of earning $4 is 1/22

The probability of drawing one red ball is Pr(R1 n W2) or Pr(W1 n R2)

Pr(R1) = 3/12

= 1/4

Pr(W2) = 9/11

Pr(W1) = 9/12

= 3/4

Pr(R2) = 3/11

Pr(R1 n W2) or Pr(W1 n R2) =

(1/4 * 9/11) + (3/4 * 3/11)

= (9/44) + (9/44)

= 18/44

= 9/22

Therefore, the probability of earning $1 is 9/22

The probability that no red ball is chosen is Pr(W1nW2)

Pr(W1) = 9/12

= 3/4

Pr(W2) = 8/12

Pr(W1nW2) = 3/4 * 8/11

= 24/44

= 12/22

therefore. the probability of loosing $2 is 12/22

The probability to draw two red balls is [tex]\(\frac{1}{22}\)[/tex], to draw one red ball is [tex]\(\frac{9}{22}\)[/tex], and to draw zero red balls is [tex]\(\frac{15}{22}\)[/tex].

To find the probability distribution, we need to calculate the probabilities of drawing two red balls, one red ball, and no red balls from the urn containing 3 red balls and 9 white balls. We use combinations to determine these probabilities.

1. Total Possible Combinations:

  The total number of ways to choose 2 balls out of 12 is given by the combination formula:

 [tex]\[ \binom{12}{2} = \frac{12!}{2!(12-2)!} = \frac{12 \times 11}{2 \times 1} = 66 \][/tex]

2. Probability of Drawing Two Red Balls:

  To draw 2 red balls, we select 2 out of the 3 red balls:

  [tex]\[ \binom{3}{2} = \frac{3!}{2!(3-2)!} = \frac{3 \times 2}{2 \times 1} = 3 \][/tex]

  The probability is:

 [tex]\[ P(\text{2 red balls}) = \frac{\binom{3}{2}}{\binom{12}{2}} = \frac{3}{66} = \frac{1}{22} \][/tex]

3. Probability of Drawing One Red Ball:

  To draw 1 red ball and 1 white ball, we select 1 out of the 3 red balls and 1 out of the 9 white balls:

 [tex]\[ \binom{3}{1} = 3 \quad \text{and} \quad \binom{9}{1} = 9 \][/tex]

  The number of ways to draw 1 red and 1 white ball is:

 [tex]\[ \binom{3}{1} \times \binom{9}{1} = 3 \times 9 = 27 \][/tex]

  The probability is:

  [tex]\[ P(\text{1 red ball}) = \frac{\binom{3}{1} \times \binom{9}{1}}{\binom{12}{2}} = \frac{27}{66} = \frac{9}{22} \][/tex]

4. Probability of Drawing Zero Red Balls:

  To draw 0 red balls (i.e., both balls are white), we select 2 out of the 9 white balls:

 [tex]\[ \binom{9}{2} = \frac{9!}{2!(9-2)!} = \frac{9 \times 8}{2 \times 1} = 36 \][/tex]

  The probability is:

 [tex]\[ P(\text{0 red balls}) = \frac{\binom{9}{2}}{\binom{12}{2}} = \frac{36}{66} = \frac{18}{33} = \frac{6}{11} = \frac{15}{22} \][/tex]

5. Probability Distribution for Earnings:

  Now, we summarize the probabilities and corresponding earnings

  - Drawing two red balls: [tex]\(\frac{1}{22}\)[/tex], earning $4

  - Drawing one red ball: [tex]\(\frac{9}{22}\)[/tex], earning $1

  - Drawing zero red balls: [tex]\(\frac{15}{22}\)[/tex], losing $2

Thus, the correct probability distribution for the experiment of playing the game and observing the player's earnings is:

- Probability to draw two red balls: [tex]\(\frac{1}{22}\)[/tex]

- Probability to draw one red ball: [tex]\(\frac{9}{22}\)[/tex]

- Probability to draw zero red balls: [tex]\(\frac{15}{22}\)[/tex]

The angle measurements in the diagram are represented by the following expressions.
Solve for X then find the measurement of ∠B:

Answers

Answer:

x = 6

∠B = 126

Step-by-step explanation:

∠A = ∠B through alternate interior angles

∠A = ∠B

8x + 78 = 2x + 114

8x - 2x = 114 - 78

6x = 36

x = 36 ÷ 6

x = 6

∠B = 2x + 114

2(6) + 114

12 + 114

= 126

d1 || d2 => ∡A = ∡B

8x + 78° = 2x + 114°

8x - 2x = 114° - 78°

6x = 36°

x = 36° : 6

x = 6°

∡B = 2x + 114°

∡B = 2×6° + 114°

∡B = 12° + 114°

∡B = 126°

2. A stone is an English measure of weight. There are 14 pounds in 1 stone and 2.2 pounds in 1 kilogram. A certain person weighs 9 stone.

(a) If you wanted to convert the person’s weight to kilograms, what conversion factor should you use? Round the conversion to the nearest hundredth. Show your work.

(b) What is the person’s weight in kilograms rounded to the nearest tenth?

Answers

Answer:

The answer to your question is 57.3 kg

Step-by-step explanation:

a)

   [tex]X stones \frac{14 pounds}{1 stone} \frac{1 kilogram}{2.2 pounds}[/tex]

   = [tex]\frac{14}{2.2}[/tex]

  = 6.36 X stones

b)    Weight = 6.36 (x)

x = 9 stones

      Weight = 6.36 (9)                

                    = 57.3 kg

A cylinder has a volume of 33 cubic inches. What is the volume of a cone with the same radius and height?

A: 44 cubic inches
B: 33 cubic inches
C: 11 cubic inches
D: 99 cubic inches

Answers

C

Step-by-step explanation:

The volume of a cylinder = πr²h

= 33 cubic inches

The volume of a cone = ¹/3 πr²h

If the cylinder and come share the same radius and height then ‘πr²h’ part of the formulas is the same for both;

It means the difference in proportionality is ¹/3 (because even π is the same across board). The volume of the cone is therefore;

¹/3 (33)

= 11

= 11 cubic inches

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A rope, attached to a weight, goes up through a pulley at the ceiling and back down to a worker. The worker holds the rope at the same height as the connection point between the rope and weight. The distance from the connection point to the ceiling is 40 ft. Suppose the worker stands directly next to the weight (i.e., a total rope length of 80 ft) and begins to walk away at a constant rate of 2 ft/s. How fast is the weight rising when the worker has walked: 10 feet? Answer = 30 feet? Answer =

Answers

Final answer:

The weight rises at the same constant rate of 2ft/s that the worker walks away, regardless of how far the worker has travelled. When the worker walks away, the length of the rope attached to the weight decreases and thus raises the weight. Therefore, at both distances, 10ft and 30ft, the weight will be rising at 2ft/s.

Explanation:

This is a physics problem involving related rates under the concept of kinematics. When the worker walks, the total length of the rope (80 ft) remains the same, so as the worker's part of the rope increases, the part attached to the weight decreases causing an upward motion. The rates at which the worker walks away and the weight retracts up are directly related.

When the worker has walked 10 feet, the worker's part of the rope has become 50 ft (original 40ft + 10ft walked), thus the weight's part of the rope is 30ft (80ft total - 50ft). Because the worker is walking at a constant rate of 2ft/s, this means that the weight is also rising at that same constant rate of 2ft/s.

Then, when the worker has walked 30 feet, the worker's part of the rope has become 70ft, thus the weight's part of the rope is 10ft. As previously explained, because the worker has a constant rate of walking away, the weight also has a constant rate of 2ft/s in the upward direction. Regardless of the worker's position, it does not impact the rate of the weight's ascent.

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The weight rises at a constant rate of 1 ft/s regardless of whether the worker has walked 10 feet or 30 feet.

Finding the Rate of the Weight Rising

First, let’s set up the problem with the given data:

Distance from the connection point to the ceiling: 40 ft

Worker’s walking speed: 2 ft/s

When the worker is directly next to the weight, the total rope length is 80 ft (rope goes up 40 ft to the pulley, and 40 ft down to the worker).

As the worker walks away, the rope is extended, and the weight rises. We need to determine how fast the weight is rising after the worker has walked different distances. Here’s how to do it step-by-step:

Step-by-Step Solution:

Let x be the distance the worker has walked away from the initial point. Therefore, the total length of the rope now serves both the height the weight has risen (h) and the horizontal distance the worker has walked (x).

Using the Pythagorean Theorem: the new distance of the rope from the worker to the pulley and down to the weight can be written as:

80 ft = 2h + x

Differentiate this equation with respect to time (t):

0 = 2(dh/dt) + dx/dt

Given that dx/dt = 2 ft/s (rate the worker walks away), we can solve for dh/dt.

2(dh/dt) + 2 = 0

2(dh/dt) = -2

dh/dt = -1 ft/s

Now, we'll analyze the specific cases: when the worker has walked 10 feet and 30 feet respectively.

a) For 10 feet: Plugging into the length equation:

2h + 10 = 80

2h = 70

⇒ h = 35 ft

b) For 30 feet: Plugging into the length equation:

2h + 30 = 80

2h = 50

∴ h = 25 ft

The weight rises at a rate of 1 ft/s when the worker has walked either 10 feet or 30 feet because the rate change of height (dh/dt) is constant.

Madison bought an empty lot for $2,000 and later sold it for a 25% profit. How much did Madison sell the lot for? A) $500 B) $1,500 C) $2,500 D) $3,000

Answers

Answer:

  C)  $2,500

Step-by-step explanation:

Madison's profit is 25% of the $2000 paid, so is ...

  0.25 × $2000 = $500

That means the lot was sold for ...

  $2000 + 500 = $2500

_____

Profit can also be expressed as a percentage of the selling price. If that were the case here, Madison's initial cost would be 0.75 of the $2666.67 selling price, and the 25% profit would be $666.67. Since that is not among the answer choices, we presume our assumption is correct that Madison's profit is measured as a percentage of cost.

Answer:

c

Step-by-step explanation:

your welcome

A ladder 10 ft long leans against a vertical wall. If the bottom of the ladder slides away from the base of the wall at a speed of 2 ft/s, how fast is the angle between the ladder and the wall changing when the bottom of the ladder is 6 ft from the base of the wall?

Answers

Answer:

[tex]\frac{dx}{dt}=\frac{-8}{3}\frac{ft}{s}[/tex]

Step-by-step explanation:

Be [tex]\frac{dy}{dt}=2\frac{ft}{s}[/tex] to find [tex]\frac{dx}{dt}=?, x=6ft[/tex]

[tex]x^{2} +y^{2}=10^{2};6^{2}+y^{2}=100;y^{2}=100-36=64;y=\sqrt{64}=+-8[/tex]→ y=8 for being the positive distance, deriving from t, [tex]x^{2} +y^{2}=100[/tex]→[tex]2x\frac{dx}{dt}+2y\frac{dy}{dt}=0[/tex]→[tex]2x\frac{dx}{dt}=-2y\frac{dy}{dt};\frac{dx}{dt}=-\frac{2y}{2x}\frac{dy}{dt}; \frac{dx}{dt}=-\frac{y}{x}\frac{dy}{dt}[/tex], if x=6 and y=8

[tex]\frac{dx}{dt}=\frac{-8}{6}2[/tex]→[tex]\frac{dx}{dt}=\frac{-8}{3}\frac{ft}{s}[/tex]

we must find the rate of change in radians over seconds, being the speed 8/3 ft / s = 2.66 ft / s the variation in degrees is determined when traveling 6 ft

PLEASE HELP ME!!!!!!! I AM NOT GOOD AT MATH!
Given the function f(x)= \frac{x^2+7x+10}{x^2+9x+20} Describe where the function has a hole and how you found your answer.

Answers

Only hole of function [tex]f(x) = \frac{x^{2}+7x+10 }{x^{2}+9x+20 }[/tex] is at x=(-4)

Step-by-step explanation:

Given the function is [tex]f(x) = \frac{x^{2}+7x+10 }{x^{2}+9x+20 }[/tex]

In order to find holes of any function, you should find when function is becoming undefined or say " infinity"

Given function is polynomial function.

It will become undefined become denominator become zero

[tex]x^{2}+9x+20=0[/tex]

Solving for x value when denominator become zero

[tex]x^{2}+9x+20=0\\x^{2}+5x+4x+20=0\\x(x+5)+4(x+5)=0\\(x+4)(x+5)=0[/tex]

we get possible holes at x=(-4) and x=(-5)

Check whether you can eliminate any holes

Now, Solving for x value when numerator become zero

[tex]x^{2}+7x+10=0\\x^{2}+5x+2x+10=0\\(x+5)(x+2)=0[/tex]

x=(-5) and x=(-2)

x=(-5) is common is both numerator and denominator.

So that, we can eliminate it.

[tex]f(x) = \frac{(x+5)(x+2)}{(x+5)(x+4)}[/tex]

[tex]f(x) = \frac{(x+2)}{(x+4)}[/tex]

Therefore, Only hole of function [tex]f(x) = \frac{x^{2}+7x+10 }{x^{2}+9x+20 }[/tex] is at x=(-4)

Min collects 334 pounds of aluminum cans on Monday and 124 pounds on Tuesday. Jessica collects 414 pounds on Monday and 314 pounds on Tuesday. How many more pounds does Jessica collect than Min? Enter your answer in the box as a mixed number in simplest form.

Answers

Answer:

270 more pounds of aluminium cans collected by Jessica than Min

Step-by-step explanation:

334 + 124 = 458 (Total pounds of aluminium cans collected by min)

414 + 314 = 728 (Total pounds of aluminium cans collected by Jessica)

728 - 458 = 270 (More pounds Jessica collected than Min)

Final answer:

Jessica collected 270 pounds more of aluminum cans than Min did over the two days. Min collected 458 pounds in total, and Jessica collected 728 pounds in total.

Explanation:

The student's question is asking us to compare the total amount of aluminum cans collected by two individuals, Min and Jessica, over a two-day period and determine how much more Jessica collected compared to Min. To solve this, we need to add the amounts collected by each individual for both days and then subtract Min's total from Jessica's total.

First, we find Min's total collection by adding her collections from Monday and Tuesday: 334 pounds + 124 pounds = 458 pounds.

Next, we find Jessica's total collection by adding her collections from Monday and Tuesday: 414 pounds + 314 pounds = 728 pounds.

Finally, we calculate how much more Jessica collected than Min by subtracting Min's total from Jessica's total: 728 pounds - 458 pounds = 270 pounds. Since the question asks for the answer as a mixed number in simplest form and 270 is already a whole number, our answer is simply 270 pounds. There is no need to convert to a mixed number.

An art student is trying to determine how many tubes of paint they will need for their mural. If they are using 3 tubes every 4 days, how many tubes would they use in 8 days?

Answers

Answer: 6 tubes

Step-by-step explanation:

Create a simple relationship.

4 days = 3 tubes

8 days = ? tubes

Well, if there is twice as many days, twice as many tubes will be used.

4 days x 2 = 8 days

3 tubes x 2 = 6 tubes

Asked what the central limit theorem says, a student replies, As you take larger and larger samples from a population, the histogram of the sample values looks more and more Normal.

Is the student right?

A. No. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means.
B. Yes. This is exactly what the theorem says

Answers

Answer:

A. No, the student is not right. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means.

Step-by-step explanation:

No, the student is not right. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means. The central limit theorem says that if we take a large sample (i.e., a sample of size n > 30) of any distribution with finite mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], then, the sample average is approximately normally distributed  with mean [tex]\mu[/tex] and variance [tex]\sigma^2/n[/tex].

Yes. The student is exactly what the theorem says.

True. According to the central limit theorem, as the sample size increases, the sampling distribution of the sample means becomes more Normal.

An example illustrates how from a population with a uniform distribution, as samples are drawn and the means are calculated, the distribution of these means approximates a normal distribution as the sample size increases.

The central limit theorem ensures that regardless of the population's distribution, with sufficiently large samples, the distribution of sample means tends towards a normal distribution.

Going against the current, a boat takes 6 hours to make a 120-mile trip. When the boat travels with the current on the return trip, it takes 5 hours. If x = the rate of the boat in still water and y = the rate of the current, which of the following systems could be used to solve the problem? A) 6(x - y) = 120 B) 5(x + y) = 120 C) 6(x + y) = 120 D) 5(x - y) = 120 E) 6x - 5y = 120 F) x + y = 120

Answers

Answer:

You can use A and B systems

Step-by-step explanation:

Lets call z the total speed of the boat. If the boat goes against the current, then, the current will drop the boat natural speed, and therefore z is obtained from substracting y from the rate of the boat on still water, x. Thus, z = x-y. If The boat goes in favor of the current, then the current will raise the speed, and we obtain z by adding y to x. If we want to calculate x and y, we know that:

On the first trip, z = x-y, and it took 6 hours to finish the 120 mile trip, therefore 6z = 120, or equivalently, 6(x-y)=120

On the return trip, z = x+y, and it took 5 hours to finish the trip, so we have 5z = 5(x+y) = 120.

Thus, in order so solve the problem, we can use system A and B.

Note that system A is equivalent to the equation x-y = 20, obtained by dididing everything by 6. If we divide by 5 the second equation we obtain that x+y = 24. We have

x-y = 20x+y = 24

By summing this equations it follows that 2x = 44, therefore x = 22. Since x-y = 20, we obtain that y = 2.

Answer:

The correct answer is 6(x - y) = 120 and 5(x + y) = 120

Pilar used six reusable shopping bags on a recent purchase she made at a grocery store. Each bag decreased the amount she spent by 5 cents. What was the change to the amount Pilar spent at the grocery store by using the reusable bags?

Answers

Pilar will pay 30 cents less from the original amount by using reusable bags.

Step-by-step explanation:

Bags used by Pilar = b = 6

Price decrease per bag = 5 cents

Let x be the total amount paid by Pilar.

Decrease will lessen the amount paid by Pilar, therefore, according to statement;

P(x) = x - 5b

As she used 6 bags, therefore, putting b=6

[tex]P(x)=x-5(6)\\P(x)=x-30[/tex]

Pilar will pay 30 cents less from the original amount by using reusable bags.

Keywords: subtraction, function

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Rachel runs 2km to her bus stop, and then rides 4.5 km to school. On average, the bus is 45 km/h faster than Rachel's average running speed. If the entire trip takes 25 minutes, how fast does Rachel run?

Answers

Answer:6.042km/h 6km/h approximately

Step-by-step explanation:

First off we have to know the formula relating speed, distance and time which is

Speed = distance/time

Now we are looking for Rachel's running speed

We are to find Rachel's running speed, so let's label is x

We are given that the distance Rachel runs to her bus stop is 2km

We were not given the time she uses to run to the bus stop

So let's label the time Rachel uses to run to her bus stop as y

So from the formula speed = distance/time

We have x = 2/y

Now we are told that the speed the bus uses to get to school is 45km/h faster than her speed used to run

So speed of bus = 45 + x

And the overall time for the whole journey is 25mins, changing this to hours, because the speed details given is in km/h we divide 25 by 60 which will give 0.417

Now if the total time is 0.417 hours, and we labeled the time for Rachel to run to the bus as y, so the time for the time for the bus to get to school will be 0.417 - y

We are also told the bus rides for 4.5km to school

So adding this together to relate the speed, distance and time of the bus with the formula speed = distance/time

We get 45 + x = 4.5/(0.417 - y)

So we have two equations

x = 2/y (1)

45+x = 4.5/(0.417-y) (2)

So putting (1) in (2) we have

45 + (2/y) = 4.5/(0.417-y)

Expanding further

(45y + 2)/y = 4.5(0.417-y)

Cross multiplying

(45y + 2)(0.417 - y) = 4.5y

Opening the brackets

18.765y - 45y2 + 0.834 - 2y = 4.5y

Collecting like terms

-45y2 + 18.765y -2y - 4.5y + 0.834 = 0

-45y2 + 12.265 + 0.834 = 0

Dividing all sides by -45 to make the coefficient of y2 1

y2 - 0.273y - 0.019 = 0

Now we have gotten a quadratic equation, and since it's with decimal numbers we can use either completing the square method of almighty formula

I'm using almighty formula her

For solving

ax2 + bx + c = 0

x = (-b +-root(b2-4ac)/2a

For our own equation, we are finding y

From our our quadratic equation

a = 1, b=-0.273, c = -0.834

you = (-(-0.273)+-root(-0.273-4(1)(-0.019))/2(1)

y = (273+-root(0.151))/2

y = (0.273+0.389)/2 or (0.273-0.389)/2

y = 0.331 or -0.085

So we use the positive answer which is 0.331, because time can't be negative

Then we put y = 0.331 in (1)

x = 2/y

x = 2/0.331

x = 6.042km/h

x = 6km/h approximately

Final answer:

Rachel's running speed was calculated by forming equations based on the given scenario of her running and riding the bus, solving these equations simultaneously provides the answer.

Explanation:

This problem is a classic case of the combined speed-time-distance problem. It involves two segments: Rachel running and then riding the bus. The time taken for these two segments combined is given as 25 minutes. We can denote Rachel's running speed as 'r' and her running time as 't1', and the bus speed as 'r+45' and bus time as 't2'.

From the question, we can formulate the following two equations:

Distance = Speed X Time, thus: 2 = r x t1 And, 4.5 = (r+45) x t2

The total time 't1 + t2' is equal to 25/60 hours (converting to the same unit).

Now, we solve these equations together to find the value of 'r', Rachel's running speed.

This shows the importance and application of average speed, time and distance in real-world situations.

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find the length and width of a rectangle whose perimeter is 26 feet and whose area is 42 square feet

Answers

Answer: length = 7 feet's

Width = 6 feets

Step-by-step explanation:

Perimeter of a rectangle is the distance round the rectangle.

Perimeter of rectangle is expressed as

2(length + width)

The perimeter of the given rectangle is 26 feet. Therefore

2(L + W) = 26

Dividing by 2,

L+W = 13

The area of a rectangle is expressed as length × width

The given area is 42 square feet. Therefore,

L×W = 42

Substituting L = 13 - W into LW = 42, it becomes

W(13-W) = 42

13W - W^2 = 42

W^2 -13W + 42 = 0

W^2 -7W - 6W + 42 = 0

W(W - 7) - 6(W - 7) = 0

(W-6)(w-7)=0

W-6 = 0 or W-7=0

W=6 or W = 7

L= 13-6 or L= 13-7

L= 7 or L = 6

Final answer:

Using the formulas for the perimeter and the area of a rectangle, we set up two equations, solved them simultaneously, factored a quadratic equation, and found that the dimensions of the rectangle are 7 feet in length and 6 feet in width.

Explanation:

To find the dimensions of a rectangle given the perimeter and the area, we can set up two equations based on these two pieces of information. The perimeter (P) of a rectangle is given by the formula P = 2l + 2w, where l is the length and w is the width. The area (A) of a rectangle is given by the formula A = lw. For the problem given, we have:

P = 26 feetA = 42 square feet

Let's denote the length as l and the width as w. We can now write:

2l + 2w = 26lw = 42

Solving these two equations simultaneously will give us the length and width of the rectangle. Firstly, we can rearrange the perimeter equation to express one variable in terms of the other:

l = (26 - 2w) / 2

Substitute this expression for l into the area equation:

((26 - 2w) / 2)w = 42

Multiplying both sides of the equation by 2 to clear the fraction:

(26 - 2w)w = 84

Distribute w across:

26w - 2w² = 84

Rearrange the quadratic equation:

2w² - 26w + 84 = 0

Divide by 2 to simplify:

w² - 13w + 42 = 0

Factor the quadratic equation:

(w - 6)(w - 7) = 0

Therefore, w could be either 6 or 7. Since the width must be less than the length for a rectangle (based on the problem context where length is typically the longer dimension), we can deduce that:

Width (w) = 6 feet

Then substitute the width into the perimeter equation to find the length:

2l + 2(6) = 26

2l + 12 = 26

2l = 14

l = 14 / 2

Length (l) = 7 feet

Hence, the dimensions of the rectangle are 7 feet by 6 feet.

raul is 5 years older than twice carlos age. the sum of their ages is 101. how old is carlos?

Answers

Answer:32years old

Step-by-step explanation:

R= 2c+5

R+C= 101

2c+5+c=101

3c+5=101

3c=96

c=32

Answer:

32 years

Step-by-step explanation:

Let the age of Carlos be represented by x

Then the age of Raul can be represented as the sum of twice the age of Carlos and 5.

In other words, Raul's age = 2x + 5

Sum of Carlos and Raul's age is 101

That is, \[x + 2x + 5 = 101\]

Or, \[3x + 5 = 101\]

Or, \[3x = 96\]

Or, \[x = 32\]

Hence, the age of Carlos is 32 years.

Age of Raul on the other hand is 2*32 + 5 = 69 years

Sum of their ages is 32 + 69 = 101 years.

Which of the following illustrates the truth value of the given conjunction?

The number [tex]-\frac{343}{9}[/tex] is an integer, and a rational number.

Answers

The conjunction is false because the number -343/9 is not an integer but is a rational number.

The number [tex]-\frac{343}{9} is an integer, and a rational number.
To determine the truth value of this conjunction, we need to understand that an integer is a whole number like -1, 0, or 1, and a rational number is a ratio of integers like 2/1 or 3/4.
Since the number [tex]-\frac{343}{9} is not an integer and also a rational number (since it can be expressed as -343/9), the conjunction is false.

You have a gift card for a coffee shop worth $90. Each day you use the card to get a coffee for $4.10. Write an explicit formula to represent the amount of money available as an arithmetic sequence. What is the value of the card after you buy your 8th coffee?

Answers

Answer: The value of the card after you buy your 8th coffee will be $61.3

Step-by-step explanation:

The worth of the gift card for the coffee shop is $90. Each day you use the card to get a coffee for $4.10. This means that the worth of the gift card is reducing by $4.10 each day. This rate is in arithmetic progression.

The formula for the nth term of an arithmetic sequence, Tn is expressed as

Tn = a + (n-1)d

Where a is the first term

d is the common difference

n is the number of days

From the information given,

a = $90

d = - $4.1

The explicit formula representing the amount of money available will be

Tn = 90 - 4.1(n - 1)

The value of the card after you buy your 8th coffee will be

T8 = 90 - 4.1(8 - 1) = T8 = 90 - 4.1×7

T8 = 90 - 28.7

T8 = $61.3

The radius of a cylindrical construction pipe is 3.5 ft. If the pipe is 35 ft long, what is its volume?
Use the value 3.14 for a, and round your answer to the nearest whole number.
Be sure to include the correct unit in your answer.

Answers

Answer:

Volume = 1346.275 [tex]ft^{3}[/tex]

Step-by-step explanation:

The radius of the pipe is 3.5 ft and height is 35 ft.

The volume of cylinder is found by the formula,

V = (π)([tex]R^{2})(h)[/tex]

(think about the formula as area of individual circles multiplied by the height of cylinder)

taking value of π as 3.14,

Where, the r = radius and h is height of cylinder.

inserting the above values,

[tex]V = (3.14)(3.5^{2})(35)[/tex]

V = 1346.275 [tex]ft^{3}[/tex]

Brian found 12-19 by breaking apart 19 into 12+7 write equations to show how Brian could have found the difference. ?

Answers

Answer:

Answer is  12-19 = -7

Step-by-step explanation:

12- 19 you can break 19  into 12 +7

then

it is easy to find  12-12 = 0

Now subtracts  0 - 7 =- 7

then

break 7 into 3 + 4

then

0 - 3 = -3

-3 - 4 = -7

So ,

12 - 19 = -7

The equation [tex]2m^{2}-1m-8=0[/tex] has solutions of the form

M= N +or- sqaure root of D/over M


Solve this equation and find the appropriate values of N,M,and D. Do not worry about simplifying the √D portion of the solution.


N= M= D=

Answers

Answer:

N = 1M = 4D = 65

Step-by-step explanation:

The given equation is of the form ...

  ax² +bx +c = 0

where a=2, b=-1, c=-8.

The quadratic formula gives the solution to the above equation as ...

  [tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

So, for your equation, the solution is ...

  [tex]m=\dfrac{-(-1)\pm\sqrt{(-1)^2-4(2)(-8)}}{2(2)}=\dfrac{1\pm\sqrt{65}}{4}[/tex]

Comparing this to the form ...

  [tex]m=\dfrac{N\pm\sqrt{D}}{M}[/tex]

we see ...

N = 1M = 4D = 65
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