Answer:
95% confidence interval for the mean consumption of meat among people over age 30 is [2.9 pounds , 3.1 pounds].
Step-by-step explanation:
We are given that a sample of 2092 people over age 30 was drawn and the mean meat consumption was 3 pounds. Assume that the population standard deviation is known to be 1.4 pounds.
Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;
P.Q. = [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] ~ N(0,1)
where, [tex]\bar X[/tex] = sample mean meat consumption = 3 pounds
s = population standard deviation = 1.4 pounds
n = sample of people = 2092
[tex]\mu[/tex] = population mean consumption of meat
Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.
So, 95% confidence interval for the population mean, [tex]\mu[/tex] is ;
P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level
of significance are -1.96 & 1.96}
P(-1.96 < [tex]\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }[/tex] < 1.96) = 0.95
P( [tex]-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}[/tex] < [tex]-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ) = 0.95
P( [tex]\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ) = 0.95
95% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] , [tex]\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }[/tex] ]
= [ [tex]3-1.96 \times {\frac{1.4}{\sqrt{2092} } }[/tex] , [tex]3+1.96 \times {\frac{1.4}{\sqrt{2092} } }[/tex] ]
= [2.9 pounds , 3.1 pounds]
Therefore, 95% confidence interval for the mean consumption of meat among people over age 30 is [2.9 pounds , 3.1 pounds].
What are the solutions of the quadratic equation 49x2 = 9? x = StartFraction 1 Over 9 EndFraction and x = StartFraction negative 1 Over 9 EndFraction x = StartFraction 3 Over 7 EndFraction and x = Start Fraction negative 3 Over 7 EndFraction x = StartFraction 3 Over 4 EndFraction and x = StartFraction negative 3 Over 4 EndFraction x = StartFraction Over 49 EndFraction and x = StartFraction negative 9 Over 49 EndFraction
The solution of the quadratic equation is x = ±3/7
How to solve quadratic equationsQuadratic equations are equations that have a leading degree of 2
Given the quadratic function
49x^2 = 9
Divide both sides by 49
49x^2/49 = 9/49
x^2 = 9/49
x = √9/49
x = ±3/7
Hence the solution of the quadratic equation is x = ±3/7
Learn more on quadratic equation here: https://brainly.com/question/1214333
A survey was conducted to find out how much time people have to spend commuting to work. The sample means for two samples are 71 and 72 minutes, with p-values of 0.03 and 0.06, respectively. The population mean is μμ. Choose the possible pair of the null and alternative hypotheses.A : H0:μ=80H0:μ=80, Ha:μ<80Ha:μ<80B : H0:μ=60H0:μ=60, Ha:μ>60Ha:μ>60C : H0:μ=71H0:μ=71, Ha:μ>71Ha:μ>71D : H0:μ=72H0:μ=72, Ha:μ<72Ha:μ<72E : None of the above
Answer:
E: None of the above
Step-by-step explanation:
Hello!
The objective is to find out how much time it takes people to commute to work.
Two samples where taken and two hypothesis tests where made:
One:
Sample mean 71 min; p-value: 0.03
Two:
Sample mean 72 min; p-value: 0.06
You have to choose from the options, a possible pair of hypotheses used for these two tests.
The parameter of the study is the population mean μ.
In the statistic hypotheses, the parameters are given either a known population value or a suspected value. So all options including sample values are wrong.
As said before the objective of the survey is to "determine how much time people spend commuting to work" in other words, whether or not the population mean is equal to a certain value.
H₀: μ = μ₀
H₁: μ = μ₀
Where μ₀ represents the theoretical value of the population mean. As you can say the hypotheses pair is two-tailed, not one-tailed.
Then the correct answer is E: None of the above
I hope this helps!
National data indicates that 35% of households own a desktop computer. In a random sample of 570 households, 40% owned a desktop computer. Does this provide enough evidence to show a difference in the proportion of households that own a desktop? Identify the appropriate null and alternative hypotheses.
Answer:
Yes, this provide enough evidence to show a difference in the proportion of households that own a desktop.
Step-by-step explanation:
We are given that National data indicates that 35% of households own a desktop computer.
In a random sample of 570 households, 40% owned a desktop computer.
Let p = population proportion of households who own a desktop computer
SO, Null Hypothesis, [tex]H_0[/tex] : p = 25% {means that 35% of households own a desktop computer}
Alternate Hypothesis, [tex]H_A[/tex] : p [tex]\neq[/tex] 25% {means that % of households who own a desktop computer is different from 35%}
The test statistics that will be used here is One-sample z proportion statistics;
T.S. = [tex]\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }[/tex] ~ N(0,1)
where, [tex]\hat p[/tex] = sample proportion of 570 households who owned a desktop computer = 40%
n = sample of households = 570
So, test statistics = [tex]\frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }[/tex]
= 2.437
Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.
Therefore, we conclude that % of households who own a desktop computer is different from 35%.
Need help with this question
Answer:
[tex] \overline{AB} \cong \overline{DB} \:\: and \:\: \overline{AC} \cong \overline{DC}[/tex]
Step-by-step explanation:
[tex] \red{ \boxed{ \bold{\overline{AB} \cong \overline{DB} \:\: and \:\: \overline{AC} \cong \overline{DC}}} }\\ \overline{BC} \cong \overline{BC}... (common\: side) \\ [/tex]
A list of five positive integers has a median of 3 and a mean of 11. What is the maximum possible value of the list's largest element? please
Answer:
47
Step-by-step explanation:
Since the 5 numbers have a mean of 11, the sum of the numbers is 5 X 11 = 55. To make the largest number as large as possible, we make the other numbers must be as small as possible. However, in order for the median to be 3, the middle number must be 3. Since this is the middle number, there must be two other numbers that are at least 3. So, we let three of the other four numbers be 1, 1, and 3 to make them as small as possible. Finally, this means the remaining number is 55 - 1 - 1 - 3 - 3= 47. Hope that helps!
Answer:
47
Step-by-step explanation:
What’s the answer to a^2b^2-100
Answer:
(ab - 10)(ab + 10)
Step-by-step explanation:
[tex] {a}^{2} {b}^{2} - 100 \\ = (ab) ^{2} - (10)^{2} \\ = (ab - 10)(ab + 10) \\ [/tex]
What is the missing angel in the triangle 69,34,
Answer:
77
Step-by-step explanation:
69+34=103
180-103=77
all triangles add up to 180
I hope this helps!
Answer:
The answer is 77
Step-by-step explanation: We know the angles add up to 180 in a triangle. so we simply do 69+34=103 then we do 180-103= 77
Suppose you have 18 objects (10 of type A, 5 of type B, and 3 of type C). Objects of type A are indistinguishable from each other; objects of type B are indistinguishable from each other; and objects of type C are indistinguishable from each other. In how many ways can you Pick 5 of the 18 objects (order does not matter)
Answer:
[tex] \binom{18}{5}= 8568[/tex]
Step-by-step explanation:
Note that we have in total 18 items. Even though we are given information regarding the amounts of items per type, the general question asks the total number of ways in which you can pick 5 out of the 18 objects, without any restriction on the type of chosen items. Therefore, the information regarding the type is unnecessary to solve the problem.
Recall that given n elements, the different ways of choosing k elements out of n is given by the binomial coefficient [tex]\binom{n}{k})[/tex].
Therefore, in this case the total number of ways is just [tex]\binom{18}{5}=8568[/tex]
Answer:
Given:
Number of objects: n = 18
Type A objects: 10
Type B objects: 5
Type C objects: 3
To find:
In how many ways can you Pick 5 of the 18 objects (order does not matter)
Step-by-step explanation:
When the order does not matter we use Combination.
Formula to calculate combination:
C(n,r) = n! / r! ( n - r )!
n = 18
r = 5
Putting the values:
C(n,r)
= C(18,5)
= 18! / 5! ( 18 - 5 )!
= 18! / 5! ( 13 )!
= ( 18 * 17 * 16 * 15 * 14 * 13 * 12 * 11 * 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 ) / ( 5 * 4 * 3 * 2 * 1 ) * (13 * 12 * 11 * 10 *9* 8 * 7 *6 * 5 * 4 * 3 * 2 *1 )
Cancel 13!
= (18 * 17 * 16 * 15 * 14 ) / ( 5 * 4 * 3 * 2 * 1 )
= 1028160 / 120
= 8568
So you can pick 5 of the 18 objects in 8568 ways.
Carrie has 3 gallon of paint. Bryan has 10 quarts of paint. How many more pints of paint does carrie have than Bryan
Answer:
4 pints
Step-by-step explanation:
There are 8 pints in one gallon, and 2 pints in one quart.
Carrie has 3 gallons of paint. 8*3 = 24 pints of paint.
Bryan has 10 quarts of paint. 10*2 = 20 pints of paint.
24 - 20 = 4. Carrie has 4 more pints of paint.
Answer:
Step-by-step explanation:
Findthe
y -intercept
oftheparabola
y = x2 − 2x .
Answer:
Step-by-step explanation:
kupa
645665465
Answer:
y=x(x-2)
Step-by-step explanation:
QUICK!!! Use the information in the diagram to answer the questions.
100 percent is the 30 dollars wholesale price, 30 percent is the markup, and the retail price is unknown.
The original cost is .
The percent of the markup is .
The markup amount is .
The new price is .
Answer:
the original cost is $30 , the percent of the markup is 30% , the markup amount is $9 , the new price is $39.
Step-by-step explanation:
Answer:
$30,30%,9,39
Step-by-step explanation:
ik u hate edgunity good thing this is ur last day
on how many points do the graphic cross each other
[tex]y = x \: \: y = x {}^{2} [/tex]
A)3
B)2
C)1
D)0
Which BEST describes the shape of the distribution?
B. Skewed Right
Answer: Skewed left. (If there is an answer choice for it)
Step-by-step explanation: The data on the Y-Axis is higher on the left side of the graph than the right side of the graph. If it was higher on the right side of the graph, then it would be skewed right. Hope this helps!
In a class of 7 students, there are 5 students who forget their lunch. If the teacher chooses 2 students, what will the probability that neither of them forget their lunch?
Answer:
4711
Step-by-step explanation:
Answer by rothauserc(4711) (Show Source):
You can put this solution on YOUR website!
the probability that the first student picked has a lunch is 6/9 or 2/3
the probability that the second student picked has a lunch is 5/8
The area of a cross section at station 4+50 is 10.31 sq. in., and at station 5+00 is 14.18 sq. in. The horizontal scale of the cross section is 1" = 40’ and the vertical scale is 1" = 10’. What is the volume of earthwork between these two stations, in cubic yards, using the average end area method? Group of answer choices
A) 45
B) 18141
C) 9070
D) 907
Answer:
12233445555?????????
There is a red, a green, and a yellow bulletin board hanging in the hallway. All of the bulletin boards are rectangular with a height of 4 feet. Their lengths are 6 feet, 5 feet, and 3 feet. The red bulletin board has the largest area and the yellow one has the smallest area. What is the area of the green bulletin board
Answer:
it would be 5 feet
Step-by-step explanation:
A group of five friends ate lunch at a restaurant the bill came to $42 And the friends agreed to spilt it equally. which expression represents the number of dollars each person paid?
Answer:
8.40
Step-by-step explanation:
42 divided by 5 equals 8.40 so each person would have to pay $8.40
Final answer:
The expression to represent the split cost of a $42 bill by five friends is 42 / 5, or $8.40 per person.
Explanation:
The expression representing the number of dollars each person paid when five friends split a $42 lunch bill equally would be $42 divided by 5. This can also be written as 42 / 5, which equals $8.40 per person.
For additional practice, let's look at a similar scenario: Mr. and Mrs. Green and their four children went out to dinner, and the meal cost was $72 with a restaurant-added tip of 18%. To find the total cost of the dinner, first calculate the tip amount by multiplying 18% (or 0.18) by the cost of the meal ($72). The tip would be $12.96. Adding this to the original cost, the total comes to $84.96.
3 A prism is completely filled with 96 cubes that have edge length of 1 2 cm. What is the volume of the prism? Enter your answer in the box. cm³
The volume of a cube is found using the formula v = s^3, where s is the length of a side.
The volume of a cube with a side of 1/2cm is
V = 1/2^3 = 1/8 cubic cm.
Now multiply the volume of one cube by total cubes:
1/8 x 96 = 12 cubic cm
The prism has a volume of 12 cubic cm.
Answer:
it is 12 if u still need it
Step-by-step explanation:
The time between consecutive eruptions of Mont Etna in Sicily is exponentially distributed denoted by random variable X, with the mean of ????[X] = 1/???? years. The exponential pdf fX(x) = ????e−????x for x ≥ 0, and zero elsewhere. Find the probability of the next eruption occurs before next 2 years, P(x < 2) =?
Answer:
0.9975
Step-by-step explanation:
check the attached files below
Verify that the given two-parameter family of functions is the general solution of the nonhomogeneous differential equation on the indicated interval.
2x2y'' + 5xy' + y = x2 − x;
y = c1x−1/2 + c2x−1 + 1/15(x^2)-1/6(x), (0,infinity)
The functions (x^-1/2) and (x^-1) satisfy the differential equation and are linearly independent since W(x^-1/2, x^-1)= ____?____ for 0
The question is :
2x²y'' + 5xy' + y = x² - x;
y = c1x^(1/2) + c2x^(-1) + 1/15(x^2) - 1/6(x), (0,infinity)
The functions (x^-1/2) and (x^-1) satisfy the differential equation and are linearly independent since W(x^-1/2, x^-1)= ____?____ for 0
Answer:
The functions x^(-1/2) and x^(-1) are linearly independent since their wronskian is (-1/2)x^(-5/2) ≠ 0.
Step-by-step explanation:
Suppose the functions x^(-1/2) and x^(-1) satisfy the differential equation 2x²y'' + 5xy' + y = x² - x;
and are linearly independent, then their wronskian is not zero.
Wronskian of y1 and y2 is given as
W(y1, y2) = y1y2' - y1'y2
Let y1 = x^(-1/2)
y1' = (-1/2)x^(-3/2)
Let y2 = x^(-1)
y2' = -x^(-2)
W(y1, y2) =
x^(-1/2)(-x^(-2)) - (-1/2)x^(-3/2)x^(-1)
= -x^(-5/2) + (1/2)(x^(-5/2)
= (-1/2)x^(-5/2)
So, W(y1, y2) = (-1/2)x^(-5/2) ≠ 0
Which means the functions are linearly independent.
The functions [tex]\rm (x^\frac{-1}{2})[/tex] and [tex]\rm (x^{-1})[/tex] satisfy the differential equation and are linearly independent since [tex]W(x^{-1/2}, x^{-1})[/tex] = [tex](-x^{5/2} )+ \dfrac{1}{2}.(x^{5/2})[/tex] .
Given that,
The given two-parameter family of functions is the general solution of the non-homogeneous differential equation on the indicated interval.
[tex]\rm 2x^2y^n+5xy'+y = x^2-x[/tex]
[tex]\rm y = c_1x^{\frac{-1}{2} }+c_2{-x} \dfrac{1}{15}x^2=\dfrac{1}{5}x ,[/tex]
We have to determine,
The functions [tex]\rm (x^\frac{-1}{2})[/tex] and [tex]\rm (x^{-1})[/tex] satisfy the differential equation and are linearly independent since [tex]W(x^{-1/2}, x^{-1})[/tex] for 0?
According to the question,
The functions [tex]\rm (x^\frac{-1}{2})[/tex] and [tex]\rm (x^{-1})[/tex] satisfy the differential equation,
[tex]\rm 2x^2y^n+5xy'+y = x^2-x[/tex]
And are linearly independent, then their differentiation is not zero.
The differential equation is given by,
[tex]\rm Y(y_1, y_2) = y_1.y_2'- y_2.y_1'[/tex]
The value [tex]\rm y_1'[/tex] is,
[tex]\rm y_1 = x^{(-1/2})\\\\ y_1' = \dfrac{-1}{2} x^{(-3/2)}[/tex]
And value of [tex]\rm y_2'[/tex]
[tex]\rm y_2 = x^{(-1)}\\\\y_2' = -x^{(-2)}[/tex]
Therefore,
[tex]\rm Y(y_1, y_2) = (x^{-1/2}.(-x)^{-2}-(-\dfrac{1}{2}.x^{-3/2}).(x^{-1})\\\\\rm Y(y_1, y_2) = (-x^{5/2} )+ \dfrac{1}{2}.(x^{5/2})\neq 0\\\\[/tex]
Hence, The value of the function is not equal to zero then the function is linearly independent.
For more details refer to the link given below.
https://brainly.com/question/18510715
Dalgliesh the detective fancies himself a shrewd judge of human nature. In careful tests, it has been discovered that he is right 80 percent of the time about whether a suspect is lying or telling the truth. Dalgliesh says that Jones is lying. The polygraph expert, who is right 100 percent of the time, says that 40 percent of the subjects interviewed by Dagliesh are telling the truth. What is the probability that Jones is lying?
Answer:
The probability that Jones is lying is 6/7
Step-by-step explanation:
First we will list out 2 different cases when the outcome is a lie
1.probability that Jones tells lies is = 0.6 and probability that dalgiliesh analyses it correctly is 0.8
So the probability that dagliesh correctly analyses that he is telling lies is 0.8*0.6=0.48
2.Probability that Jones tells truth is 0.4 and if dagliesh analyses it incorrectly (which has a probability of 0.2) the outcome(as analysed by dagiliesh) is a lie
So probability that dagliesh analyses Jones truth as a lie is 0.2*.0.4=0.08
Total probability of outcome being a lie is 0.48+0.08=0.56
But we need the probability of Jones actually saying a lie which is nothing but 0.48/0.56= 6/7
The probability of that Jones is lying is [tex]\frac{6}{7}[/tex] .
Probability is defined as, divide favourable outcomes by total outcomes.
First case:
Probability that Jones tells lies is = 0.6
Probability that Dalgliesh analyses it correctly is, = 0.8
Therefore, the probability that Dalgliesh correctly analyses that Jones is telling lies is,
[tex]P=0.8*0.6=0.48[/tex]
Second case :
Probability that Jones tells truth is, = 0.4
Probability of Dalgliesh analyses it incorrectly that Jones tells truth is,
= 0.2
So, Probability that Dalgliesh analyses Jones truth as a lie is,
[tex]0.2*.0.4=0.08[/tex]
Total probability of outcome being a lie is,
[tex]0.48+0.08=0.56[/tex]
Thus, Probability of Jones telling lie is, [tex]=\frac{0.48}{0.56} =\frac{6}{7}[/tex]
Learn more:
https://brainly.com/question/12594357
Keely is planning a bridal shower for her best friend. At the party, she wants to serve 4 beverages, 3 appetizers, and 4 desserts, but she does not have time to cook. She can choose from 11 bottled drinks, 10 frozen appetizers, and 8 prepared desserts at the supermarket. How many different ways can Keely pick the food and drinks to serve at the bridal shower?
Answer:
The different ways in which Keely can pick the food and drinks to serve at the bridal shower is 2,772,000.
Step-by-step explanation:
Combinations is a mathematical procedure to determine the number of ways to select k items from n different items, without replacement and irrespective of the order of selection.
The formula to compute the combination of k items from n items is:
[tex]{n\choose k}=\frac{n!}{k!(n-k)!}[/tex]
The menu for the bridal shower consists of:
Beverages: 4
Appetizers: 3
Dessert: 4
It is provided that Keely does not have time to cook. SO she goes to the supermarket and there she has the following options:
Beverages: 11
Appetizers: 10
Dessert: 8
Compute the number of ways Keely can select 4 beverages from 11 bottled drinks as follows:
[tex]{n\choose k}=\frac{n!}{k!(n-k)!}[/tex]
[tex]{11\choose 4}=\frac{11!}{4!(11-4)!}[/tex]
[tex]=\frac{11!}{4!\times 7!}[/tex]
[tex]=\frac{11\times 10\times 9\times 8\times 7!}{4!\times 7!}[/tex]
[tex]=330[/tex]
Keely can select 4 beverages in 330 ways.
Compute the number of ways Keely can select 3 appetizers from 10 frozen appetizers as follows:
[tex]{n\choose k}=\frac{n!}{k!(n-k)!}[/tex]
[tex]{10\choose 3}=\frac{10!}{3!(10-3)!}[/tex]
[tex]=\frac{10!}{3!\times 7!}[/tex]
[tex]=\frac{10\times 9\times 8\times 7!}{3!\times 7!}[/tex]
[tex]=120[/tex]
Keely can select 3 appetizers in 120 ways.
Compute the number of ways Keely can select 4 desserts from 8 prepared desserts as follows:
[tex]{n\choose k}=\frac{n!}{k!(n-k)!}[/tex]
[tex]{8\choose 4}=\frac{8!}{4!(8-4)!}[/tex]
[tex]=\frac{8!}{4!\times 4!}[/tex]
[tex]=\frac{8\times 7\times 6\times 5\times 4!}{4!\times 4!}[/tex]
[tex]=70[/tex]
Keely can select 4 desserts in 70 ways.
Compute the total number of ways in which Keely can select 4 beverages, 3 appetizers, and 4 desserts for the party as follows:
Total number of ways = n (4 beverages) × n (appetizers) × n (dessert)
[tex]={11\choose 4}\times {10\choose 3}\times {8\choose 4}[/tex]
[tex]=330\times 120\times 70\\=2772000[/tex]
Thus, the different ways in which Keely can pick the food and drinks to serve at the bridal shower is 2,772,000.
Use a special right triangle to express the cosine of 45 degree as a fraction and as a decimal to the nearest hundredth
The special triangle you need is a right isosceles triangle, with legs 1 and hypotenuse [tex]\sqrt{2}[/tex].
As for every right triangle, you can find of the cosine of an angle using the "adjacent/hypotenuse" ratio.
In this case, the two base angles are equal, and so are the two legs. So, it doesn't matter which angle or leg you'll choose, the ratio will be
[tex]\cos(45)=\dfrac{1}{\sqrt{2}}[/tex]
which indeed is both the sine and cosine of 45°
Its approximated value is 0.707...
The cosine of 45 degree as a fraction and as a decimal to the nearest hundredth are [tex]\( \frac{\sqrt{2}}{2} \)[/tex] and 0.71 respectively.
In a 45-45-90 triangle, which is a special right triangle, the sides are in the ratio [tex]\( 1:1:\sqrt{2} \).[/tex] This means if the legs (both shorter sides) are [tex]\( a \)[/tex], then the hypotenuse is [tex]\( \sqrt{2} \cdot a \).[/tex]
To find the cosine of [tex]\( 45^\circ \):[/tex]
The cosine of an angle in a right triangle is given by the ratio of the adjacent side to the hypotenuse. In a 45-45-90 triangle, each leg is adjacent to the 45° angle, and the hypotenuse is opposite the 90° angle.
Therefore, [tex]\( \cos(45^\circ) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{a}{\sqrt{2} \cdot a} \).[/tex]
Simplifying this gives:
[tex]\[ \cos(45^\circ) = \frac{a}{a\sqrt{2}} = \frac{1}{\sqrt{2}} \][/tex]
Rationalizing the denominator:
[tex]\[ \cos(45^\circ) = \frac{1}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}}{2} \][/tex]
Therefore, the cosine of [tex]\( 45^\circ \)[/tex] as a fraction is [tex]\( \frac{\sqrt{2}}{2} \).[/tex]
To find the decimal value of [tex]\( \frac{\sqrt{2}}{2} \):[/tex]
First, approximate [tex]\( \sqrt{2} \):[/tex]
[tex]\[ \sqrt{2} \approx 1.414 \][/tex]
Now, calculate [tex]\( \frac{1.414}{2} \):[/tex]
[tex]\[ \frac{1.414}{2} \approx 0.707 \][/tex]
Rounded to the nearest hundredth, the decimal form of [tex]\( \cos(45^\circ) \)[/tex] is 0.71.
The diagram of question is:
what can 8 and 6 both go into equally
write 64 as a power with exponent 3
Answer:
4
Step-by-step explanation:
because 4x4 is 16 and 16 x four is 64
Answer:
4³
I think this is right. the problem isnt explained very well.
In circle K with mLJKL = 112 and
JK = 7 units find area of sector JKL.
Round to the nearest hundredth.
Area of the sector JKL is 47.89 unit²
How the area of the sector is calculated
From the figure
Given that
JKL is a sector that subtends ∠JKL at the center of the circle JL.
The radius of the circle is KL or JK
Area of a sector = θ/360 * πr²
where
r is the radius
θ is angle subtended at the center
m∠JKL = 112⁰ = θ
JK = 7 units = radius
Therefore,
Area = 112/360*π(7)²
A = 112/360 * 3.142 * 49
= 17243.296/360
= 47.89 unit²
Therefore, area of the sector JKL is 47.89 unit²
Dave rented a jet ski for $6 per hours plus $20 for insurance. How many hours did he use the jet ski if he spent a total of $68? solving equation applications equations and solution
Answer:
8 hours
Step-by-step explanation:
6x+20=68
subtract 20 from both sides
6x=48
divide 6 both sides
x=8
Answer:
Step-by-step explanation:
If d ran 12 meters in 6 second and c ran 15 meters in 5 seconds who ran faster or was it the same
Answer:
12/6 = 2 miles per second for d
15/5 = 3 miles per second for c
c runs faster because runs 3 miles every second while d only runs 2 miles per second
Step-by-step explanation:
uppose a small cannonball weighing 16 pounds is shot vertically upward, with an initial velocity v0 = 290 ft/s. The answer to the question "How high does the cannonball go?" depends on whether we take air resistance into account. If air resistance is ignored and the positive direction is upward, then a model for the state of the cannonball is given by d2s/dt2 = −g (equation (12) of Section 1.3). Since ds/dt = v(t) the last differential equation is the same as dv/dt = −g, where we take g = 32 ft/s2. If air resistance is incorporated into the model, it stands to reason that the maximum height attained by the cannonball must be less than if air resistance is ignored. (a) Assume air resistance is proportional to instantaneous velocity. If the positive direction is upward, a model for the state of the cannonball is given by m dv dt = −mg − kv, where m is the mass of the cannonball and k > 0 is a constant of proportionality. Suppose k = 0.0025 and find the velocity v(t) of the cannonball at time t.
Solving for the velocity v(t) of a cannonball considering air resistance involves integrating the differential equation m dv/dt = -mg - kv, where k is a constant of proportionality. Given initial conditions, this allows one to calculate the cannonball's velocity at any time.
Explanation:A student has asked how to find the velocity v(t) of a cannonball, considering air resistance, modeled by m dv/dt = -mg - kv, where m is the mass of the cannonball, g is the acceleration due to gravity (32 ft/s2), and k is a constant of proportionality (0.0025). Given the initial velocity v0 = 290 ft/s, the solution involves solving this differential equation with the given initial condition.
However, solving this specific differential equation requires integration techniques that account for the linear dependence of the air resistance on the velocity, which will yield an expression for v(t) as a function of time t. This formula can then be used to calculate the velocity of the cannonball at any given time, illustrating how air resistance affects its ascent and eventual descent.
Four cups are placed upturned on the counter. each cup has the same number of sweets and a declaration about the number of sweets in it. The declaration are: Five or six, seven or eight, six or seven, seven or five. Only one of the declaration is correct. How many sweets are there under each cup?
Answer:
6? i hope this helps some! :)
Step-by-step explanation:
each has 6 in between the number
5 or 6 p there is a possibility of there being 6
7 or 8 there is at least 6 in this cup
6 or 7 there is at least 6 in this cup
7 or 5 there is a possibility of there being 6
Final answer:
There are either 7 or 5 sweets under each cup. The declaration 'Seven or five' is correct.
Explanation:
Each cup has a declaration about the number of sweets in it: 'Five or six', 'Seven or eight', 'Six or seven', and 'Seven or five'. Only one of the declarations is correct. To find the number of sweets under each cup, we need to analyze the given information.
If the declaration 'Five or six' is correct, then there can be 5 or 6 sweets under the cup. But since there are no other cups with 5 or 6 as a declaration, this declaration cannot be correct.
If the declaration 'Seven or eight' is correct, then there can be 7 or 8 sweets under the cup. But since there are no other cups with 7 or 8 as a declaration, this declaration cannot be correct.
If the declaration 'Six or seven' is correct, then there can be 6 or 7 sweets under the cup. But since there is another cup with the declaration 'Seven or five', and both declarations share the number 7, this declaration cannot be correct.
Therefore, the only remaining declaration 'Seven or five' must be correct. So, there are either 7 or 5 sweets under the cup with this declaration.
In conclusion, there are either 7 or 5 sweets under each cup, and the declaration 'Seven or five' is correct.