A package falls off a truck that is moving at 30 m/s

well yes because it will rquerid to have heat

Answer:

Explanation: its false

Answer:

1st box: Sedimentary rocks

2nd box:metamorphic rock

3rd box: igneous rock

Explanation:

Sedimentary rocks are rocks formed from weathered pieces of rocks (sediments)  which have accumulated over a period of time. An example of a sedimentary rock is limestone

Metamorphic rocks are rocks that have been reformed as a result of long term effects of high temperature and pressure. they can be said to ave changed or metamorphosed from their original state which could be igneous , sedimentary or even metamorphic. example is marble

igneous rocks are solidified hot molten magma which have become cooled after a period of time. An example is granite

We can use the kinematics equation

v1^2-v0^2=2as

where v1=final velocity = 0 m/s

v0=initial velocity = 24 m/s

a=acceleration = to be determined

S=distance travelled during acceleration = 225 m

=>

a=(v1^2-v0^2)/(2S)

=(0^2-24^2)/(2*225)

=-576/450

=-1.28 m/s^2

So van is decelerating at 1.28 m/s^2

The frictional force is therefore

F = ma = 1400 kg * 1.28 m/s^2 = 1792 N

The force of friction acting on the 1400 kg van, which comes to a stop after 225 meters, is calculated using the work-energy principle and is found to be 1792 Newtons.

Finding the Force of Friction Acting on the Van

To determine the force of friction acting on a van that rolls to a stop after the driver takes her foot off the gas pedal, we need to apply the principles of kinetic energy and work done. The work done by friction is equal to the change in kinetic energy of the van as it comes to a stop. Since the van starts at a speed (v) of 24 m/s and ends at 0 m/s, the initial kinetic energy ([tex]KE_i[/tex]) is

[tex]KE_i = 1/2 mv^2[/tex]

where m is the mass of the van (1400 kg). The work done by friction (W) equals the force of friction (f) multiplied by the distance (d) over which it acts, hence W = fd. Work done by friction is also equal to the change in kinetic energy:

[tex]W = KE_i - KE_f[/tex]

Because the van stops, [tex]KE_f[/tex] (final kinetic energy) is 0, and the work done by friction will equal the initial kinetic energy. We can calculate the force of friction now that we know the work done and the distance:

f = [tex]KE_i[/tex] / d

Using the given values:

[tex]KE_i[/tex] = 1/2 (1400 kg)(24 m/s)² = 403200 J

So the force of friction (f) can be calculated as:

f = 403200 J / 225 m = 1792 N

The force of friction acting on the van is therefore 1792 N.

as per the reaction we have

[tex]H_2 + O_2 ---> H_2O_2[/tex]

so here 1 mole of H2 react with 1 mole of O2 and give 1 mole of H2O2 as the product

now we will find the moles of given reactant

moles of H2

[tex]n_1 = \frac{2}{2} = 1 mole[/tex]

moles of O2

[tex]n_2 = \frac{32}{32} = 1 mole[/tex]

so here both present in 1 mole each hence the product will also formed 1 mole

so here we have

[tex]n = 1 mole[/tex] H2O2 will form

so mass of the product

mass = moles* molecular mass

[tex]m = 1 * (2 + 32)[/tex]

[tex]m = 34 g[/tex]

so the product mass will be 34 g

Final answer:

Electrical energy is transformed into thermal energy by an electric blanket to warm a bed. The electric current passes through a heating element in the blanket, where the resistance generates heat to provide warmth.

Explanation:

When an electric blanket warms a bed on a chilly night, electrical energy is being transformed into thermal energy. This process involves the conversion of electricity into heat through the use of a heating element within the blanket. As electricity flows through the heating element, the resistance of the material converts electric energy into heat, which then warms up the bed. This is an example of energy transformation where the desired output is the warming effect, even though some energy may be lost to the environment as part of this process.

Electric blankets are designed to be energy efficient, ensuring that the majority of electric power is converted into heat to keep users warm. This functionality is similar to other devices that transform energy into heat, such as space heaters or waterbed heaters. However, it's worth noting that no process is 100% efficient, and some energy will be lost in the form of waste heat.

A) X: Decreasing to half will quadruple force

Y: Doubling will double force

The regions marked X and Y will be given as

X: Decreasing to half will quadruple the force

Y: Doubling will double force

The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force. Although the law was known earlier, it was first published in 1785 by French physicist Charles-Augustin de Coulomb, hence the name.

Coulomb's law was essential to the development of the theory of electromagnetism, maybe even its starting point,[1] as it made it possible to discuss the quantity of electric charge in a meaningful way.

The law states that the magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them.

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

Hence the regions marked X and Y will be given as

X: Decreasing to half will quadruple the force

Y: Doubling will double force

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The coin tossed straight upward on a train that is accelerating will land back in your hand, retaining its initial horizontal velocity and moving forward with the train due to Newton's first law of motion and the principle of relative motion.

If you toss a coin straight upward on a train that gains speed while the coin is in the air, the coin will still land back in your hand, provided there is no significant air resistance inside the train and you do not move from your spot. This is because when the coin is tossed, it already has the horizontal velocity of the train. As per Newton's first law of motion, objects in motion stay in motion with the same velocity unless acted upon by an unbalanced force.
Therefore, even though the train is accelerating, the coin retains its initial horizontal velocity and moves forward with the train.

An important concept to take note of here is the principle of relative motion. To an observer inside the train, the coin appears to move straight up and down because both the observer and the coin are sharing the same initial horizontal velocity due to the motion of the train. To an observer outside the train, the coin would appear to be following a projectile motion pathway, because they can see both the vertical and the accelerated horizontal motion of the coin. However, since the internal movement of the coin and the observer are both relative to the moving train, the coin will land back in the hand from which it was tossed, assuming the hand remains in the same position relative to the train.

Answer:

Option A is the correct answer.

Explanation:

The instantaneous acceleration = Change in velocity in velocity/Time taken

The slope of the graph should give instantaneous acceleration.

  Slope of a graph = Change in value of Y -axis / Change in values of X -axis

 Comparing both the equations

   Change in value of Y -axis = Change in velocity in velocity

   Change in values of X -axis = Time taken

So velocity values should be on the Y axis and Time values should be on the X axis.

Option A is the correct answer.

A) Velocity on the y-axis, time on the x-axis

Answer:

Northeast

Explanation:

Let magnitude of the force acting along north and east be F.

One worker pushes it toward north and another pushes it along east with same magnitude.

According to law of parallelogram the Resultant force has direction along northeast as shown in the figure.

Answer:

The correct answer is A.

Objects in free fall accelerate due to gravity.

Explanation:

Momentum can help an object to keep its state of motion at a constant velocity when no external force is applied. It can never accelerate the object.

According to the laws of motion, we know that acceleration is produced in a body only when a Force is applied in the direction of motion of body.

During a free fall, only the force of gravity is acting on an object and that too in the direction of its motion. Hence, the acceleration produced in a free falling object is due to gravity.

Answer:

gravity

Explanation:

Answer:

The moon’s axis does not always align with Earth’s shadow.

Explanation:

The lunar eclipse happens when the Earth comes between the moon and the Sun, blocking the light falling on the moon. It occurs on a full moon. On the other hand, a solar eclipse occurs when the moon comes between the Earth and the Sun, blocking the sunlight falling on Earth. It occurs on new moon day. For each to occur, the three bodies must be aligned in straight line. As the orbital plane of the moon is not exactly aligned to that of the Earth, the eclipses do not occur every month.

The reason why lunar and solar eclipses do not happen every month is because: D. The moon’s axis does not always align with Earth’s shadow.

An eclipse is simply an astronomical phenomenon (event) that usually takes place when a celestial body such as a Moon in space moves in between the Sun and another celestial body such as planet Earth, usually causing the total or partial blockage or obscuration of light to the celestial body.

Based on space exploration and science, there are two (2) main types of eclipse;

I. Lunar eclipse: it is an astronomical phenomenon (event) that occurs when planet Earth gets between the Moon and the Sun, thereby causing it to cover or obscure the Moon with its shadow.

II. Solar eclipse: this is an astronomical phenomenon (event) that typically occurs when the Sun is obscured or blocked by the Moon, thereby engulfing a portion of planet Earth.

However, these astronomical phenomenon (lunar and solar eclipses) do not happen every month because the axis of the Moon is tilted five (5) degrees and as such doesn't always align with Earth’s shadow.

In conclusion, without this tilt of the Moon from Earth's orbit around the Sun, lunar and solar eclipses would happen every month.

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Artificial gravity is created by rotating the cylinder

So here we can say that the acceleration is due to centripetal acceleration

So here we know that the formula of centripetal acceleration is given by

[tex]a_c = \frac{v^2}{R}[/tex]

so here we know that

[tex]a_c = 9.8 m/s^2[/tex]

[tex]v = 30.9 m/s[/tex]

now we will plug in all values

[tex]9.8 = \frac{30.9^2}{R}[/tex]

[tex]R = \frac{30.9^2}{9.8}[/tex]

[tex]R = 97.43 m[/tex]

So above is the radius of the cylinder

Now to find the diameter

[tex]d = 2R[/tex]

[tex]d = 2*97.43[/tex]

[tex]d = 194.8 m[/tex]

so its diameter is 194.8 m

In order to generate the same gravitational acceleration felt on Earth's surface, the diameter of a spinning, cylindrical space station, around which an astronaut standing inside its outer rim moves tangentially at 30.9 m/s, should be approximately 194.36 meters.

The problem in question concerns the concept of artificial gravity and circular motion in physics. To answer this question, we would use the formula for the centripetal acceleration in circular motion, which is a = v² / r, where v = velocity (30.9 m/s) and r = radius of the circle (the part we are trying to find). We equate this to g, the acceleration due to gravity on earth, which is 9.81 m/s². This gives us the equation 9.81 m/s² = (30.9 m/s)² / r. Solving for r gives us r = (30.9 m/s)² / 9.81 m/s² = 97.18 m. This is the radius. But we need the diameter of the space station, so we multiply the radius by 2, giving us a diameter of approximately 194.36 meters.

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gravity is the correct answer.

In two-dimensional motion that is not projectile motion, the object may experience acceleration due to various forces acting on it. Projectile motion is a specific case where the only significant force acting on the object is the force of gravity, resulting in a distinct motion trajectory.

Projectile motion refers to a specific type of two-dimensional motion in which an object is launched into the air and moves under the influence of gravity alone, experiencing no forces other than gravity. In this case, the object's motion is characterized by a constant horizontal velocity and a vertical acceleration due to gravity.

However, in other two-dimensional motions where the object is not a projectile, there may be other forces acting on it, causing it to accelerate in various directions. Some examples of forces that can cause acceleration in two-dimensional motion include:

Applied Forces: If an external force is applied to the object, it will accelerate in the direction of that force. For example, pushing a box across the floor or throwing a ball horizontally.

Frictional Forces: Friction opposes the relative motion between two surfaces in contact. It can cause acceleration in the opposite direction to the motion, reducing the object's speed.

Tension: In systems with ropes or strings, tension can cause an object to accelerate in the direction of the net force.

Electrostatic Forces: If the object carries an electric charge and is in the vicinity of other charged objects, electrostatic forces may cause it to accelerate.

Magnetic Forces: If the object is influenced by magnetic fields, magnetic forces can cause it to accelerate in specific directions.

Spring Forces: In systems involving springs, the compression or stretching of the spring can cause acceleration in the object attached to it.

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Initial speed of the package will be same as the speed of helicopter as it has been dropped from the helicopter.

So if we find the velocity of package relative to helicopter then it will be zero

so here we can say

[tex]v_i = v_{helicopter} = 3.1 m/s[/tex]

Now here relative velocity of the of the package will increase due to free fall in gravity and then just before if hit the ground the speed of the package will be 9.5 m/s relative to the helicopter.

so here we can say

[tex]v_{p/H} = v_p - v_H[/tex]

[tex]v_{p/H} = 9.5 m/s[/tex]

[tex]v_H = 3.1 m/s[/tex]

so here the net velocity with respect to ground will be

[tex]v_p = V_{p/H} + v_H[/tex]

[tex]v_p = 3.1 + 9.5 = 12.6 m/s[/tex]

so package will hit with speed 12.6 m/s downwards

Meter is standard unit for measurement of length. Larger unit used for measurement of length is Kilometer.

Since,

1 Kilometer= 1000 meter

or

1 meter = 1/1000 Kilometer

therefore,

35 meter = 35/1000 Kilometer

35 meter = 0.035 Kilometer

35 m is equivalent to 0.035 km.

35 meters is equivalent to 0.035 kilometers, which is found by dividing the number of meters by 1000.

To convert meters to kilometers, you need to know the basic conversion rate: 1 kilometer (km) is equivalent to 1000 meters (m). Therefore, to convert meters to kilometers, you divide the number of meters by 1000.

35 meters is equivalent to 0.035 kilometers because:

35 m / 1000 = 0.035 km

None of the other options (35000 km, 35000 km, 0.0035 km) are correct. The correct conversion is to simply divide the number of meters by 1000 to get the kilometers.

An electric force exists between the following:

-Two negative objects

-Two positive objects

-A negative object and a positive object

Electric forces exist between charged objects. Therefore, two negative objects, two positive objects, and a positive and a negative object all experience electric force. However, under certain conditions, a neutral object and a charged object may also experience electric force.

An electric force exists between objects with charge. So, the correct pairs from your options that will experience electric force are: two negative objects (since like charges repel), two positive objects (as these also repel each other) and a negative object and a positive object (because opposite charges attract each other).

A neutral object and a positive object, as well as a neutral object and a negative object, may also experience electric force due to induced charges under certain conditions. However, two neutral objects will not experience electric force as they do not have charge.

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Answer:

It is a characteristic of matter that describes its ability to change into a different substance.

Explanation:

As per Pascal's law

Pressure must be equally transmitted to all points of fluids

So here we can say

[tex]P_{in} = P_{out}[/tex]

As we know that pressure is the ratio of force and area so we can say

[tex]\frac{F_{in}}{A_{in}} = \frac{F_{out}}{A_{out}}[/tex]

Given that

[tex]F_{in} = 200 N[/tex]

[tex]A_{in} = 0.1 m^2[/tex]

[tex]A_{out} = 5 m^2[/tex]

[tex]\frac{200}{0.1} = \frac{F_{out}}{5}[/tex]

[tex]F_{out} = 5 * 2000 = 10000[/tex]

so output force will be 10 kN

so A option is correct

Answer:

The answer is A 10 kN

Explanation:

I got it right on the test.

Paint is immiscible because the layer that forms on top of settled paint is a substance which cannot dissolve with the rest of the paint.  Stirring the paint is only temporarily in effort to form an even and thoroughly mixed solution by physically mixing the separate molecules of the solution.  However, for it to be miscible, it the solution has to be evenly distributed (chemically) on a molecular level as to not separate when left for a lengthy period of time.

Time of impact: [tex]\(0.0217\)[/tex] seconds, calculated using impulse-momentum theorem with force [tex]\(460 \, \text{N}\) and mass \(0.25 \, \text{kg}\)[/tex].

To find the time of impact, we can use the impulse-momentum theorem, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:

[tex]\[ J = \Delta p \][/tex]

Where:

- [tex]\( J \)[/tex] is the impulse

- [tex]\( \Delta p \)[/tex] is the change in momentum

The impulse [tex](\( J \))[/tex] can be calculated using the force [tex](\( F \))[/tex] and time [tex](\( \Delta t \))[/tex] of impact:

[tex]\[ J = F \cdot \Delta t \][/tex]

Given that the force [tex](\( F \))[/tex] is 460 N, we can rearrange the equation to solve for the time ([tex]\( \Delta t \)[/tex]):

[tex]\[ \Delta t = \frac{J}{F} \][/tex]

The change in momentum ([tex]\( \Delta p \)[/tex]) can be calculated using the mass [tex](\( m \))[/tex] and the final velocity (\( v_f \)) of the ball:

[tex]\[ \Delta p = m \cdot v_f \][/tex]

Given that the mass [tex](\( m \))[/tex] is 0.25 kg and the final velocity [tex](\( v_f \))[/tex] is 40 m/s, we can substitute these values into the equation to find the change in momentum.

Once we have both the impulse [tex](\( J \))[/tex] and the change in momentum [tex](\( \Delta p \))[/tex], we can solve for the time of impact [tex](\( \Delta t \))[/tex].

Let's calculate:

[tex]\[ \Delta p = m \cdot v_f = 0.25 \, \text{kg} \times 40 \, \text{m/s} = 10 \, \text{kg} \cdot \text{m/s} \][/tex]

[tex]\[ \Delta t = \frac{J}{F} = \frac{10 \, \text{kg} \cdot \text{m/s}}{460 \, \text{N}} \][/tex]

[tex]\[ \Delta t = \frac{10}{460} \, \text{s} \][/tex]

[tex]\[ \Delta t[/tex] ≈ [tex]0.0217 \, \text{s}[/tex]

So, the time of impact for this event is approximately [tex]\( 0.0217 \)[/tex] seconds.

Answer: the velocity of a falling object.

As the object is falling down it is experiencing a velocity that is continuously reducing each second and becomes 0 once it reaches the ground. The graph between velocity and time in this case would be a negative slope.

Thus for a object falling down the velocity considered would be negative owing to the reducing speed.

b) proton

the proton is the only one of these that are in the nucleus. if you think the electron is, its not; the electrons are all outside the nucleus in the electron cloud. :)

For an ideal condition The Mass does not  affect the time taken by an object to hit the ground.

As the ground attracts all object with the same acceleration due to gravity 9.8 m/s². so all objects that  drop from a certain height hit the ground at same time .

But in real condition there is air resistance present ,due to which objects of different masses take different time to hit the ground.

Answer:

it is gravitational force

Explanation:

i did the test is the pretest of force and motion trust me its right

Here's something I'll bet you never thought about before:

A function is called "linear" if it makes a straight line when you graph it.

There are three different functions on the graph you provided.  The only one of them that's a "linear" function is line B .