A pastry chef wants to bake and sells fries. Before they start production, they need to make sure they can make a profit with the materials and labor force they have. Their accountant has given them a cost equation of y=0.65x+1410 and a revenue equation of y=0.8x. How many pies will they need to sell in order to reach the break order point?

Answers

Answer 1

Answer:

They need to sell 9400 pies to reach the break-order point

Step-by-step explanation:

* Lets explain the break-order point

- The break-order point is the point at which total cost and total

  revenue are equal

∴ The total cost = The total revenue

* Lets solve the problem

∵ The equation of the total cost is y = 0.65x + 1410

∵ The revenue equation is y = 0.8x

- To find the break-order point equate the two equations

∴ 0.65x + 1410 = 0.8x

- Subtract 0.65x from both sides

∴ 1410 = 0.8x - 0.65x

∴ 0.15x = 1410

- Divide both sides by 0.15

∴ x = 1410/0.15 = 9400

∵ x is the number of pies

* They need to sell 9400 pies to reach the break-order point


Related Questions

What's the solution to 3x – 6 < 3x + 13? A. x > 5 B. There are no solutions. C. There are infinitely many solutions. D. x < –5

Answers

Answer:

C. There are infinitely many solutions.  

Step-by-step explanation:

3x – 6 < 3x + 13

Subtract 3x from each side

-6 < -13

This inequality is always true.

There are infinitely many solutions.

Final answer:

After simplifying the inequality, it becomes apparent that it holds true for all values of x. Therefore, there are infinitely many solutions to this inequality.

Explanation:

To solve the inequality 3x – 6 < 3x + 13, we need to isolate the variable x on one side. However, when we attempt to subtract 3x from both sides to move the terms involving x to one side, we are left with – 6 < 13 which is a true statement, but no longer contains the variable x. This means that the inequality holds true for all values of x. Therefore, the solution to the inequality is that there are infinitely many solutions. No matter what value of x you choose, the inequality will always be true.

An airplane is at an altitude of 1200 m, the angle of depression to a building at the airport on the ground measures 28∘. Find the distance from the plane to the building. Round your answer to the nearest tenth. Hint: Find the hypotenuse. The distance from the plane to the building is meters.

Answers

Answer:

Option C (2556.1 meters).

Step-by-step explanation:

This question can be solved using one of the three trigonometric ratios. The height of the airplane from the ground is 1200 meters and the angle of depression is 28°. It can be seen that the required distance is given by x meters. This forms a right angled triangle, as it can be seen in the diagram. The perpendicular is given by 1200 meters, the hypotenuse is unknown, and the angle of 28° is given, as shown in the attached diagram. Therefore, the formula to be used is:

sin θ = Perpendicular/Hypotenuse.

Plugging in the values give:

sin 28 = 1200/x.

x = 1200/sin 28.

x = 2556.06536183 meters.

Therefore, the airplane is 2556.1 meters (to the nearest tenths) far away from the building!!!

The distance from the airplane to the building is approximately 2256.6 meters, rounded to the nearest tenth.

To find the distance d from the airplane to the building on the ground, we can use trigonometry, specifically the tangent function.

Given:

- Altitude of the airplane h = 1200 m

- Angle of depression [tex]\( \theta = 28^\circ \)[/tex]

The tangent of the angle of depression [tex]\( \theta \)[/tex] is defined as the ratio of the opposite side altitude h to the adjacent side (distance d from the airplane to the building):

[tex]\[ \tan(\theta) = \frac{h}{d} \][/tex]

Substitute the given values:

[tex]\[ \tan(28^\circ) = \frac{1200}{d} \][/tex]

Now, solve for d:

[tex]\[ d = \frac{1200}{\tan(28^\circ)} \][/tex]

Calculate [tex]\( \tan(28^\circ) \)[/tex]:

[tex]\[ \tan(28^\circ) \approx 0.5317 \][/tex]

Now, plug in this value:

[tex]\[ d = \frac{1200}{0.5317} \][/tex]

[tex]\[ d \approx 2256.6 \][/tex]

If f(x) = x2 - 2x and g(x) = 6x + 4, for which value of x does (f+g)(x) = 0?

Answers

Answer:

-2

Step-by-step explanation:

Let's plug your functions f(x)=x^2-2x and g(x)=6x+4 into (f+g)(x)=0 and then solve your equation for x.

So (f+g)(x) means f(x)+g(x).

So (f+g)(x)=x^2+4x+4

Now we are solving (f+g)(x)=0 which means we are solve x^2+4x+4=0.

x^2+4x+4 is actually a perfect square and is equal to (x+2)^2.

So our equation is equivalent to solving (x+2)^2=0.

(x+2)^2=0 when x+2=0.

Subtracting 2 on both sides gives us x=-2.

Answer:

x=-2

Step-by-step explanation:

f(x) = x^2 - 2x

g(x) = 6x + 4

Add them together

f(x) = x^2 - 2x

g(x) =       6x + 4

-----------------------

f(x) + g(x) =x^2 +4x+4

We want to find when this equals 0

0 =x^2 +4x+4

Factor

What two numbers multiply together to give us 4 and add together to give us 4

2*2 =4

2+2=4

0=(x+2) (x+2)

Using the zero product property

x+2 =0    x+2=0

x+2-2=0-2

x=-2

If A=(-2,5) and B=(3,1), find AB

Answers

An estimate would be 6.4. When using the Pythagorean theorem

Final answer:

To calculate vector AB from points A=(-2,5) and B=(3,1), subtract the coordinates of A from B to get AB = (5, -4). Then, use the Pythagorean theorem to find the magnitude |AB|, which is the square root of 41 units.

Explanation:

The question asks for the calculation of the magnitude of the vector AB, given two points A and B with coordinates A=(-2,5) and B=(3,1), respectively. To find vector AB, we subtract the coordinates of point A from point B. This results in AB = (Bx - Ax, By - Ay) = (3 - (-2), 1 - 5) which simplifies to AB = (5, -4). The magnitude of vector AB, often denoted as |AB|, can then be found using the Pythagorean theorem: |AB| = √((5)2 + (-4)2) = √(25 + 16) = √41 units.

Find the geometric means in the following sequence.
47,
?
,
?
,
?
,
?, - 789, 929
R
Select one:
a. -6,580, -9,870, -13,160, -16,450
b. 329, 2,303, 16,121, 112,847
C. 2,303, -16,121, 112,847, -789,944
d. -329, 2,303, -16,121, 112,847

Answers

Answer:

d (last choice)

Step-by-step explanation:

The explicit form of a geometric sequence is [tex]a_n=a_1 \cdot r^{n-1}[/tex] where [tex]a_1[/tex] is the first term while [tex]r[/tex] is the common ratio.

We are given the first term [tex]a_1=47[/tex].

We are given the sixth term [tex]a_6=-789929[/tex].

If we divide 6th term by 1st term this is the result:

[tex]\frac{a_1 \cdot r^5}{a_1 }=\frac{-789929}{47}[/tex]

Simplify both sides:

[tex]r^5=-16807[/tex]

Take the fifth root of both sides:

[tex]r=-7[/tex]

The common ratio is -7.

So all we have to do is start with the first term and keep multiplying by -7 to get the other terms.

[tex]a_1=47[/tex]

[tex]a_2=47(-7)=-329[/tex]

[tex]a_3=47(-7)^2=2303[/tex]

[tex]a_4=47(-7)^3=-16121[/tex]

[tex]a_5=47(-7)^4=112847[/tex]

[tex]a_6=47(-7)^5=-789929[/tex]

The terms -329,2303,-16121,112847 are what we are looking for in our choices.

That's the last choice.

The variable z is directly proportional to r. When x is 18, z has the value 216.
What is the value of z when 2 = 26?

Answers

Answer:

z=312 if you meant x=26

Step-by-step explanation:

Direct proportional means there is a constant k such that z=kr. k is called the constant of proportionality. The constant k will never change no matter your (x,z).

So using our equation z=kr with point (18,216) we will find k.

216=k(18)

Divide both sides by 18

216/18=k

k=216/18

Simplify

k=12

So we now know the equation fully that satisfies the given conditions of directly proportion and goes through (x,z)=(18,216).

It is z=12x.

Now we want to know the value of z if x=26.

Plug it in. z=12(26)=312

z=312

A metalworker has a metal alloy that is 25% copper and another alloy that is 75% copper. How many kilograms of each alloy should the metal worker combine to create 60kg of 65% copper alloy?
The metal worker should use _____ kilograms of the metal alloy that is 25% copper and _____ kilograms of the metal alloy that is 75% copper.

Answers

Answer:

x=48

Step-by-step explanation:


The data represents the semester exam scores of 8 students in a math course.
{51, 91, 46, 30, 36, 50, 73, 80}
What is the five-number summary?​

Answers

Answer:

C

Step-by-step explanation:

if u try and find the median you get 50.5 because it is the middle of 50 (fourth term) and 51 (fifth term) and only c has the correct median

The Allied Taxi Company charges $2.50 to pick up a passenger and then adds $1.95 per mile. Isaac was charged $27.46 to go from one city to another. If x represents the number of miles driven by the taxi, which linear equation can be used to solve this problem, and how many miles did Isaac travel, rounded to the nearest tenth?

Answers

Answer:

Isaac traveled 12.8 miles by taxi for $27.46.

Step-by-step explanation:

The formula required here is

$2.50 + ($1.95/mile)x = $27.46.

We need to solve this for x, the number of miles traveled:

Subtract $2.50 from both sides, obtaining:

($1.95/mile)x = $24.96

Now divide both sides by ($1.95/mile):

   $24.96

------------------ = 12.8 miles

($1.95/mile)

Isaac traveled 12.8 miles by taxi for $27.46.

Answer:

1.95x + 2.50 = 27.46; Isaac traveled 12.8 miles.

Please hurry i need to turn in this homework , help me please !!

An object is thrown upward at a speed of 58 feet per second by a machine from a height of 7 feet off the ground. The height h of the object after t seconds can be found using the equation h=−16t^2+58t+7

1.When will the height be 17 feet?


2.When will the object reach the ground?

Answers

Answer:

First part:

Set h(t) = 17and solve for t.

-16t²+ 58t + 7= 17

-16t² + 58t - 10 = 0

Solve this quadratic equation for t. You should get 2 positive solutions. The lower value is the time to reach 17 on the way up, and the higher value is the time to reach 17 again, on the way down.

Second part:

Set h(t) = 0 and solve the resulting quadratic equation for t. You should get a negative solution (which you can discard), and a positive solution. The latter is your answer.

What is the interquartile range of the data 120 140 150 195 203 226 245 i280

Answers

Answer:

Interquartile Range = 90.5

Step-by-step explanation:

We are given the following data set for which we have to find its interquartile range:

[tex]120,140,150,195,203,226,245,280[/tex]

Since we have an even number data set here so dividing the data set into two halves and taking the average of two middle values for each date set to find [tex]Q_1[/tex] and [tex]Q_3[/tex].

[tex]Q_1=\frac{140+150}{2} =145[/tex]

[tex]Q_3= \frac{226+245}{2}=235.5[/tex]

Interquartile Range [tex](Q_3-Q_1) = 235.5-145[/tex] = 90.5

Find the equation of a line passing through the points (2,6) and (-2,-10)

Answers

[tex]\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-10}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-10-6}{-2-2}\implies \cfrac{-16}{-4}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-6=4(x-2) \\\\\\ y-6=4x-8\implies y=4x-2[/tex]

Answer:

y = 4x - 2.

Step-by-step explanation:

The slope is  difference in y values  / difference in x values

= (6 - -10) /  (2 - -2)

= 16 / 4

= 4.

Using the point-slope form of a line

y - y1 = m(x - x1)  where m = slope and (x1, y1) is a point on the line, we have:

y - 6 = 4(x - 2)

y = 4x - 8 + 6

y = 4x - 2.

Multiply. Express your answer in simplest form. 9 1/6 × 1 1/11

Answers

Answer:

10

Step-by-step explanation:

9 1/6 × 1 1/11

Change each number to an improper fraction

9 1/6 = (6*9 +1)/6 = 55/6

1 1/11 = (11*1 +1) /11 = 12/11

55/6 * 12/11

Rearranging

12/6 *55/11

2/1 *5/1

10

Answer:

10

Step-by-step explanation:

[tex]\tt 9\cfrac{1}{6}\cdot 1\cfrac{1}{11}= \cfrac{55}{6}\cdot\cfrac{12}{11}=\cfrac{5}{1}\cdot\cfrac{2}{1}=10[/tex]

Which point is a solution to y s 4x + 5?
O A. (0,10)
O B. (0, -2)
O C. (-4,0)
O D. (-6,4)

Answers

Answer:

Step-by-step explanation:

Each one of those options is a coordinate point; the first number represents x and the second represents y.  In order for a coordinate point to be a solution to an equation, one side of the equation has to equal the other side when you plug in the number that represents x where x is, and the number that represents y wher y is and then solve.

The first coordinate point filled in looks like this:

If y = 4x + 5, then where x = 0 and y = 10

10 = 4(0) + 5. Solv that to get

10 = 5

Does 10 equal 5?  No.  10 equals 10, not anything else.  So that point doesn't work.

The next point (0, -2) filled in looks like this:

-2 = 4(0) + 5

Does -2 = 5?  No.  Not a solution.

The next point (-4, 0) filled in looks like this:

0 = 4(-4) + 5 and

0 = -16 + 5 and

0 = -11

True?  No.

The next point (-6, 4)

4 = 4(-6) + 5

4 = -24 + 5 and

4 = -19

None of them work. At least according to what you have as your equation and as your points.


Point Q of quadrilateral QRST is (-9,2). What is the image of Q after QRST has been reflected across
the y-axis and then rotated 90 degrees about the origin?
• (2,-2).
• (-29)
(9,2)
None of the other answers are correct
• (-9,-2)

Answers

The image of Q after QRST has been reflected across the y-axis and then rotated 90 degrees about the origin is (-2,9 ), (2,-9) is correct .

The point Q(-9,2) undergoes a reflection across the y-axis, resulting in Q'(9,2).

Subsequently, two possible 90-degree rotations about the origin are considered.

For a counterclockwise rotation, the coordinates become Q'(-2,9), while for a clockwise rotation, the coordinates become Q'(2,-9).

The process of reflection across the y-axis involves negating the x-coordinate, and the rule for this transformation is (x, y) → (-x, y).

Applied to Q(-9,2), it yields Q'(9,2).

For a counterclockwise rotation of 90 degrees, the rule is (x, y) → (-y, x). Applying this to the reflected point Q'(9,2) results in Q'(-2,9).

Alternatively, for a clockwise rotation of 90 degrees, the rule is (x, y) → (y, -x). Applying this rule to the reflected point Q'(9,2) yields Q'(2,-9).

Therefore, after a reflection across the y-axis followed by a 90-degree rotation (either counterclockwise or clockwise) about the origin, the coordinates of the final image point Q' can be either (-2,9) or (2,-9), depending on the direction of rotation.

Two bakeries sell muffins that can be customized with different kinds of berries. Berry Bakery sells muffins for $14.50 a dozen, plus $0.50 for each kind of berry added. Raisin Bakery sells muffins for $12.00 a dozen, plus an additional $0.75 for each kind of berry added. Let b be the number of the kinds of berries added. The equation that represents when the cost of one dozen muffins is the same at both bakeries is 14.5 + .5b = 12 + .75b.

Answers

Yes. The original price of the dozen added to the price of berries (.5) multiplied by the amount(b) is the same equational representation to the right of the equal sign.

Answer:

its B It gives the number of the kinds of berries needed for the cost to be the same at both bakeries.

Step-by-step explanation:

suppose that a biologist is watching a trail known for wildebeest migration. During the first minute, 24 wildebeests migrated past the biologist on the trail. Was hoping minute, the number increased by 3. How many wildebeests migrated past the biologist during the first 20 mins

Answers

Answer:

=1050 wildebeests

Step-by-step explanation:

We can form an arithmetic series for the wildebeest migration.

Sₙ=n/2(2a+(n-1)d) where  n is the number of terms, d is the common difference and a is the first term.

a=24

n=20

d=3

Sₙ=(20/2)(2(24)+(20-1)3)

Sₙ=10(48+57)

=1050 wildebeests

the parent function of the function g(x)=(x-h)^2+k is f(x)=x^2. the vertex of the function g(x) is located at (9,8). what are the values of h and k?

Answers

Answer:

h = 9, k = 8

Step-by-step explanation:

[tex]\text{The vertex form of an an equation of a quadratic function:}\\\\y=a(x-h)^2+k\\\\(h,\ k)-vertex\\\\\text{We have}\ g(x)=(x-h)^2+k,\ \text{and the vertex in}\ (9,\ 8).\\\\\text{Therefore}\ h=9\ \text{and}\ k=8.\ \text{substitute:}\\\\g(x)=(x-9)^2+8[/tex]

Answer:

The answer is g(x) = (x - 9)^2 + -8

So 9 and -8 are the correct answers

Step-by-step explanation:

The guy above got the first one right but not the second one, it's supposed to be negative.

A species of extremely rare, deep water fish rarely have children. if there are 821 of this type of fish and their growth rate is 2% each month, how many will there be in half of a years, in 2 years, and in 10 years?

Answers

Answer:

There are 925 in half of a year

There are 1321 in 2 years

There are 8838 in 10 years

Step-by-step explanation:

* Lets revise the exponential function

- The original exponential formula was y = ab^x, where a is the initial

 amount and b is the growth factor

- The new growth and decay functions is y = a(1 ± r)^x. , the b value

 (growth factor) has been replaced either by (1 + r) or by (1 - r).

- The growth rate r is determined as b = 1 + r

* Lets solve the problem

∵ The number of fish is growth every month

∴ We will use the growth equation y = a(1 + r)^x, where a is the initial

  amount of the fish, r is the rate of growth every month and x is the

  number of months

- There are 821 of a type of fish

∴ The initial amount is 821 fish

a = 821

- Their growth rate is 2% each month

∴ The rate of growth is 2% per month

r = 2/100 = 0.02

- We want to find how many of them be in half year

∵ There are 6 months in half year

∴ y = 821(1 + 0.02)^6

∴ y = 821(1.02)^6 = 924.58 ≅ 925

* There are 925 in half of a year

∵ There are 24 months in 2 years

∴ y = 821(1 + 0.02)^24

∴ y = 821(1.02)^24 = 1320.53 ≅ 1321

* There are 1321 in 2 years

∵ There are 120 months in 10 years

∴ y = 821(1 + 0.02)^120

∴ y = 821(1.02)^120 = 8838.20 ≅ 8838

* There are 8838 in 10 years

Write an expression for the area of a square with side s = 2x + 5

Answers

Answer:

[tex]4x^2+20x+25[/tex] square units

Step-by-step explanation:

We are given that side of a square has the dimension [tex]s = 2x + 5[/tex] and using this, we are to write an expression for the area of this square.

We know that the formula of area of a square is given by:

Area of square = [tex]s^2[/tex]

So substituting the given value in the above formula to get:

Area of square = [tex](2x+5)^2 = (2x+5)(2x+5) = 2x(2x)+2x\times5+5(2x)+5\times5 = 4x^2+20x+25[/tex] square units

Answer:

[tex]A = 4x ^ 2 + 20x +25[/tex]

Step-by-step explanation:

Remember that all sides of a square have the same length. Therefore, the Area of a square is defined as:

[tex]A = s ^ 2[/tex]

Where s is the length of the sides of the squares.

In this case we know that the length of the sides is:

[tex]s = 2x + 5[/tex]

So the area is:

[tex]A = (2x +5) ^ 2[/tex]

We develop the expression and we have left that the area is:

[tex]A = 4x ^ 2 + 20x +25[/tex]

a ladder is 40 ft and an 80 degree decline its an isosceles right triangle what so my sides equal

Answers

Answer:

The sides are equal to

x=6.9 ft and y=39.4 ft

Step-by-step explanation:

step 1

Find the adjacent side to the angle of 80 degrees

Let

x ----> the adjacent side to the angle of 80 degrees

we know that

The function cosine of angle of 80 degrees is equal to divide the adjacent side to the angle of 80 degrees by the hypotenuse (40 ft)

cos(80°)=x/40

x=(40)cos(80°)

x=6.9 ft

step 2

Find the opposite side to the angle of 80 degrees

Let

y ----> the opposite side to the angle of 80 degrees

we know that

The function sine of angle of 80 degrees is equal to divide the opposite side to the angle of 80 degrees by the hypotenuse (40 ft)

sin(80°)=y/40

y=(40)sin(80°)

y=39.4 ft

Adante begins to evaluate the expression 3 1/3 x 5 1/4

Answers

A is your next step. Distribution.
Answer:

The next step for the evaluation of the given expression is:

         [tex](3)(5)+(\dfrac{1}{3})(5)+(3)(\dfrac{1}{4})+(\dfrac{1}{3})(\dfrac{1}{4})[/tex]

Step-by-step explanation:

We are given an arithmetic expression as follows:

      [tex](3+\dfrac{1}{3})(5)+(3+\dfracx{1}{3})(\dfrac{1}{4})[/tex]

Now, in order to solve the given arithmetic expression we need to use the distributive property.

i.e.

[tex](a+b)c=a\cdot c+b\cdot c[/tex]

Now, the expression in the next step is written as follows:

[tex](3+\dfrac{1}{3})(5)+(3+\dfracx{1}{3})(\dfrac{1}{4})=(3)(5)+(\dfrac{1}{3})(5)+(3)(\dfrac{1}{4})+(\dfrac{1}{3})(\dfrac{1}{4})[/tex]

What percent of $x$ is equal to $40\%$ of $50\%$ of $x$?

Answers

Answer:

20%

Step-by-step explanation:

step 1

Find 50% of x

we know that

50%=50/100=0.50

so

Multiply the number x by 0.50 to determine 50% of x

(x)(0.50)=0.50x

step 2

Find 40% of 50% of x

we know that

50% of x is equal to 0.50x (see the step 1)

40%=40/100=0.40

so

Multiply the number 0.50x by 0.40 to determine 40% of 0.50x

(0.50x)(0.40)=0.20x

therefore

The percent of x is equal to 0.20*100=20%

Answer:

20%

Step-by-step explanation:

there's really no point of explaining since the other person just explained and I don't wanna copy pasta their explanation

Rewrite the expression in a radical form k^2/9

Answers

The numerator stays in the house and the denominator shows the power

If two lines are parallel, which statement must be true

Answers

Answer:

Step-by-step explanation:

If two lines are parallel, their slopes are equal.

Next time, if you are given possible answer choices, please share them.

Answer:

The slopes of the two lines that are parallel, are equal.

Step-by-step explanation:

In order for two or more lines to be parallel their slopes have to be the same.

Samantha’s rectangular gift is 10 inches. by 12 inches and is framed with a ribbon. She wants to use the same length of ribbon to frame a circular clock. What is the maximum radius of the circular clock? Round to the nearest whole number.
(JUSTIFY)

Answers

Answer:

7 inches

Step-by-step explanation:

The dimension of the rectangular gift is 10 by 12 inches so let us find the perimeter of this rectangle.

Perimeter of rectangular gift = 2 (L+ W) = 2 (10 +12) = 44 inches

Since we are to use the same length of ribbon to wrap a circular clock so the perimeter or circumference should be 44 inches.

[tex]2\pi r=44[/tex]

[tex]r=\frac{44}{2\pi }[/tex]

[tex]r=7.003[/tex]

Therefore, the maximum radius of the circular clock would be 7 inches.

Answer:

The maximum radius of the circular clock is 7 in

Step-by-step explanation:

We must calculate the perimeter of the rectangle

We know that the rectangle is 10 in x 12 in

If we call L the rectangle length and we call W the width of the rectangle then the perimeter P is:

[tex]P = 2L + 2W[/tex]

Where

[tex]L = 10[/tex]

[tex]W = 12[/tex]

[tex]P = 2 * 10 + 2 * 12\\\\P = 20 + 24[/tex]

[tex]P = 44\ in[/tex]

Now we know that the perimeter of a circle is:

[tex]P = 2\pi r[/tex]

In order for the perimeter of the circumference to be equal to that of the rectangle, it must be fulfilled that:

[tex]2\pi r = 44\\\\r=\frac{44}{2\pi}\\\\r=7\ in[/tex]

We solve the equation for r

PLS HELP, I'm not very good at math so I need the answer to this

Answers

Answer:

A BT = CT

Step-by-step explanation:

BAT ≅ CAT

That means

The angles are the same and the sides are the same by CPCTC

AB = AC

CT = BT

AT=AT

and

< BAT = <CAT

< ATB = <ATC

< TBA = <TCA

Given the choices on the left

A BT = CT is one of them

The height of a cone is twice the radius of its base. What expression represents the volume of the cone, in cubic units?

Answers

[tex]V=\dfrac{1}{3}\pi r^2h\\\\h=2r\\V=\dfrac{1}{3}\pi r^2\cdot(2r)=\dfrac{2}{3}\pi r^3[/tex]

Answer:

[tex]V=\frac{2}{3}\pi R^{3}[/tex]

Step-by-step explanation:

The Volume of a cone is by definition 1/3 of the volume of a Cylinder. In this question, the height equals to diameter (2R).

So, We have:

[tex]h_{cone}=2R\\V=\frac{1}{3}\pi R^{2}h \Rightarrow V=\frac{1}{3}\pi R^{2}2R \Rightarrow V=\frac{2}{3}\pi R^{3}[/tex]

We conclude that under this circumstance, a cone with a height equal to its diameter will turn its volume to be equal to 2/3 of pi times the radius raised to the third power.

In other words, when the height is equal to the diameter. The relation between radius, height and Volume changes completely.

Find the value of z.
A. 6
B. 3
C. 4
D. 2

Answers

The two chords on top of each other are the same length as the single vertical chord.

The vertical chord is  2 + 4 +2  = 8 units long.

Z = 8-2 = 6

The answer is A.

Length of chord z is 6.

What is chord length?

It is defined as the line segment joining any two points on the circumference of the circle, not passing through its center. Therefore, the diameter is the longest chord of a given circle, as it passes through the center of the circle.

From the figure we can write,

[tex]z+2=2+4+2[/tex]

[tex]z+2=8[/tex]

[tex]z=8-2=6[/tex]

Length of chord z is 6.

Find out more information about chord length here

https://brainly.com/question/9857445

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help!
Drag the labels to the correct locations. Each label can be used more than
once.
Label each quadratic function with the number of solutions it has
one solution
two solutions
no real solutions

Answers

Answer:

Graph 1 has two solutions

Graph 2 has one solution

Graph 3 has no solution

Graph 4 has two solutions

Step-by-step explanation:

* Lets explain the solution of the quadratic equation

- The quadratic equation represented graphically by a parabola

- The solution of the quadratic equation is the intersection point

  between the parabola and the x-axis

- At the x-axis y coordinate of any point is zero, then the solution is

 the value of x-coordinate of this point

- If the parabola cuts the x-axis at 2 points then there are 2 solutions

- If the parabola cuts the x-axis at 1 point then there is 1 solutions

- If the parabola doesn't cut the x-axis then there is no solution

* Lets solve the problem

# Graph 1:

∵ The parabola cuts the x-axis at two points

∴ There are two solutions

# Graph 2:

∵ The parabola cuts the x-axis at one point

∴ There is one solution

# Graph 3:

∵ The parabola doesn't cut the x-axis

∴ There is no solution

# Graph 4:

∵ The parabola cuts the x-axis at two points

∴ There are two solutions

A quadratic function is given in the general form ax^2 + bx + c = 0, where a, b, and c are constants, and a ≠ 0.
The solutions of a quadratic function are found using the quadratic formula:
x = (-b ± √(b² - 4ac)) / (2a)
The number of solutions is determined by the discriminant, which is the expression inside the square root: b² - 4ac.
Here's how the discriminant determines the number of solutions:
1. If the discriminant is positive (b² - 4ac > 0), there are two distinct real solutions.
2. If the discriminant is zero (b² - 4ac = 0), there is exactly one real solution.
3. If the discriminant is negative (b² - 4ac < 0), there are no real solutions (but there are two complex solutions).
Now, let's apply this to the quadratic functions that you've been given. Unfortunately, you haven't provided the specific functions, so I'll give you a generic example for each case. You will be able to use this method to determine the number of solutions for any given quadratic function.
Example 1: One Solution
Consider the equation x^2 - 4x + 4 = 0.
Here, a = 1, b = -4, c = 4.
Discriminant = (-4)² - 4(1)(4) = 16 - 16 = 0.
Since the discriminant is zero, there is exactly one solution.
Example 2: Two Solutions
Consider the equation x^2 - 4x + 3 = 0.
Here, a = 1, b = -4, c = 3.
Discriminant = (-4)² - 4(1)(3) = 16 - 12 = 4.
Since the discriminant is positive, there are two distinct real solutions.
Example 3: No Real Solutions
Consider the equation x^2 + 2x + 5 = 0.
Here, a = 1, b = 2, c = 5.
Discriminant = (2)² - 4(1)(5) = 4 - 20 = -16.
Since the discriminant is negative, there are no real solutions.
Drag and label each quadratic function with the number of solutions based on your calculation of the discriminant:
- If the discriminant is zero, label it "one solution."
- If the discriminant is positive, label it "two solutions."
- If the discriminant is negative, label it "no real solutions."
Remember to apply this method to each of the quadratic functions that you have by calculating their discriminants.

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