Answer:
v = 2 m/s
Explanation:
Here we can use energy conservation to find the speed at the lowest point on its trajectory
As we know that by energy conservation
initial total gravitational potential energy = final total kinetic energy
now the height that is moved by the pendulum while it swing down is given as
[tex]h = L(1 - cos30)[/tex]
[tex]h = 1.5(1 - cos30) = 0.200 m[/tex]
now we can use energy conservation as
[tex]mgh = \frac{1}{2}mv^2[/tex]
[tex]v = \sqrt{2gh}[/tex]
[tex]v = \sqrt{2(9.8)(0.200)}[/tex]
[tex]v = 2 m/s[/tex]
Answer:
v = 1.978 m/s
Explanation:
Given that,
Mass of the object, m = 2 kg
Length of the string, l = 1.5 m
The maximum angle the string makes with the vertical as the pendulum swings is 30°, [tex]\theta=30^{\circ}[/tex]
The pendulum have gravitational potential energy when the angle is maximum. The pendulum has only kinetic energy at its lowest point. Let v is the speed of the object at the lowest point in its trajectory. It can be calculated as :
[tex]mgh=\dfrac{1}{2}mv^2[/tex]
h is the height moved by the pendulum.
[tex]h=l(1-cos(30))[/tex]
[tex]h=1.5(1-cos(30))[/tex]
h = 0.2 m
[tex]v=\sqrt{2gh}[/tex]
[tex]v=\sqrt{2\times 9.8\times 0.2}[/tex]
v = 1.978 m/s
So, the speed of the object at the lowest point in its trajectory is 1.978 m/s.
Marina is staring at an optical illusion where he sees a version of the American flag that is colored green, yellow, and black. When the flag is removed and she stares at a blank screen, she sees an afterimage of the flag that is red, white, and blue. Which theory best explains this illusion?
Explanation:
The reason why Marina sees the colour red, white and blue or the original colour of the American flag is that because of a phenomenon known as Afterimage. The retina in our eyes have mainly three receptors that are colour sensitive known as cones. These receptors can perceive the colour green, red and blue. Now when we look or stare at a particular colour for a long time, what happen is that our retina becomes tired and they ignore the colours that stared at. And now they work to form other colours at the retina just like the way when we produce other colour from the primary colour.
If the red receptor gets exhausted we will see the colour red. Likewise when we see the colour orange when we stare at the colour blue.
This explains the optical illusion of the American flag.
Final answer:
Marina's observation of a red, white, and blue afterimage after staring at a green, yellow, and black flag is explained by the opponent-process theory of color perception. This theory indicates that colors are perceived in opposing pairs, and overstimulation of certain color-sensitive cells can lead to the perception of their opposite colors when looking away.
Explanation:
The Opponent-Process Theory of Color Perception
The optical illusion experienced by Marina where she sees an afterimage of the American flag in red, white, and blue after staring at a flag colored green, yellow, and black can be explained by the opponent-process theory of color perception.
This theory suggests that color perception is controlled by the activity of two opposing sets of colors: red versus green, and blue versus yellow, plus a black versus white system. When Marina stares at the green, yellow, and black flag, the respective ganglion cells in her retina which are associated with these colors become fatigued.
After looking away and viewing a blank screen, these cells reduce their activity, resulting in Marina's brain interpreting the lack of those colors as their opposites, which are red, white, and blue. This means that the afterimage is not just a random occurrence but rather a direct consequence of the way our visual system works to perceive colors.
The opponent-process theory is supported by how the retinal ganglion cells and the neurons in the visual cortex process color signals, as well as experimental demonstrations like staring at a flag and observing the afterimage that appears.
This illusion occurs because while staring at the flag, the green, black, and yellow sensitive ganglion cells become overstimulated and when the gaze is moved to a white background, the decreased stimulation is interpreted as their opponent colors. This effect persists until the ganglion cells return to their normal activity state, at which point the afterimage will fade away.
A certain sound level increases by an additional 20 db. By how much does the intensity increase?
Answer:
The intensity increases by a factor 100.
Explanation:
Given that,
Sound intensity = 20 db
We need to calculate the intensity factor
[tex]F=10^{\dfrac{LI}{10}}[/tex]
Where, LI = sound intensity
Put the value into the formula
[tex]F=10^{\dfrac{20}{10}}[/tex]
[tex]F=10^2[/tex]
[tex]F=100[/tex]
Hence, The intensity increases by a factor 100.
Final answer:
A 20 dB increase in sound level corresponds to a 100 times increase in sound intensity, as each 10 dB increase represents a tenfold increase in intensity.
Explanation:
A sound level increase of 20 dB signifies a substantial increase in sound intensity. Given that each 10 dB increase corresponds to a tenfold increase in intensity, a 20 dB increase would mean the intensity is 10 times 10, or 100 times greater than the original level. This is derived from the logarithmic scale used to measure sound intensity in decibels (dB), where an increase of 10 dB represents a tenfold increase in sound intensity. Therefore, we can say that a 20 dB increase in sound level would result in the new sound being 100 times more intense than the original. To provide an example, if one sound measures 60 dB and another sound measures 80 dB, the latter is 100 times more intense than the former.
The work done by an engine equals one-fourth the energy it absorbs from a reservoir. True or False
True IF the engine is 25% efficient. False otherwise.
The Kinetic energy, K, of an object with mass m moving with velocity v can be found using the formula - E_{\text{k}}={\tfrac {1}{2}}mv^{2}
. A scientist measured the velocity of a 5-kilogram object and a 20-kilogram object in an experiment. If the velocity of the 5-kilogram object was twice the velocity of the 20-kilogram object, what was the ratio of the kinetic energy of the 5 kilogram object to the kinetic energy of the 20-kilogram object?
Answer:
The ratio of kinetic energies of 5 kg object to 20 kg object is 1:1.
Explanation:
Kinetic energy is defined as energy possessed by an object due to its motion.It is calculated by:
[tex]K.E=\frac{1}{2}mv^2[/tex]
Kinetic energy of the 5 kg object.
Mass of object,m = 5 kg
Velocity of an object = v
[tex]K.E=\frac{1}{2}mv^2=\frac{1}{2}\times 5kg\times v^2[/tex]
Kinetic energy of the 20 kg object.
Mass of object,m' = 20 kg
Velocity of an object = v'
[tex]K.E=\frac{1}{2}mv^2=\frac{1}{2}\times 20kg\times v'^2[/tex]
The ratio of the kinetic energy of the 5 kilogram object to the kinetic energy of the 20-kilogram object:
[tex]\frac{K.E}{K.E'}=\frac{\frac{1}{2}\times 5kg\times v^2}{\frac{1}{2}\times 20kg\times v'^2}[/tex]
Given that, v = 2v'
[tex]\frac{K.E}{K.E'}=\frac{1}{1}[/tex]
The ratio of kinetic energies of 5 kg object to 20 kg object is 1:1.
Two charged ping-pong balls separated by a distance of 1.63 m exert an electric force of 0.0224 N on each other. What will be the force if the objects are brought closer, to a separation of only 24.0 cm? (in N)
Answer: 1.024 N
Explanation:
Step 1:
Using Coulomb's law: F=kQ1Q2/d^2
We can rearrange the terms to get :
kQ1Q2=Fxr^2
Substituting: kQ1Q2=0.0224N x (1.63m)^2
Thus kQ1Q2=0.0595
We know that this value will not change when the balls are brought closer together.
Step 2:
Change from cm to m : 1cm=0.01m
24cm=0.24 m
Substitute into the new distance and the calculated value for kQ1Q2 into the coulomb law formula to calculate the new force
F=kQ1Q2/d^2=0.059/(0.24)^2
F=1.024N
Final answer:
The force between the ping-pong balls will be approximately 1.665 N when they are brought closer to a separation of 24.0 cm.
Explanation:
The force between two charged objects can be calculated using Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
In this case, the initial force between the ping-pong balls is 0.0224 N when they are separated by 1.63 m. To find the force when they are brought closer to a separation of 24.0 cm, we can use the fact that the force is inversely proportional to the square of the distance.
We can set up a proportion:
(0.0224 N) / (1.63 m)²= (x) / (0.24 m)²
Solving for x, we find that the force will be approximately 1.665 N.
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed of 1.7 m/s, how fast is the length of his shadow on the building decreasing when he is 4 m from the building?
Answer:
0.6375 m/s
Explanation:
Let x be the distance of the man from the building
from the figure attached
initially the value of x=12
Given:
[tex]\frac{dx}{dt}=-1.7m/s[/tex]
where the negative sign depicts that the distance of the man from the building is decreasing.
Now, Let The length of the shadow be = y
we have to calculate [tex]\frac{dy}{dt}[/tex] when x=4
from the similar triangles
we have,
[tex]\frac{2}{12-x}=\frac{y}{12}[/tex]
or
[tex]y=\frac{24}{12-x}[/tex]
Differentiating with respect to time 't' we get
[tex]\frac{dy}{dt}=-\frac{24}{12-x}^2\frac{-dx}{dt}[/tex]
or
[tex]\frac{dy}{dt}=\frac{24}{12-x}^2\frac{dx}{dt}[/tex]
Now for x = 4, and [tex]\frac{dx}{dt}=-1.7m/s[/tex] we have,
[tex]\frac{dy}{dt}=\frac{24}{12-4}^2\times (-1.7)[/tex]
or
[tex]\frac{dy}{dt}=-0.6375m/s[/tex]
here, the negative sign depicts the decrease in length and in the question it is asked the decreasing rate thus, the answer is 0.6375m/s
A student measures the volume of a gas sample at several different temperatures. The results are tabulated as follows:Temperature of gas (K) Volume of gas (L)298 4.55315 4.81325 4.96335 Formulate a tentative law from the measurements.Check all that apply.
a. The temperature of a gas is directly proportional to its volume.
b. The temperature of a gas is inversely proportional to its volume.
c. The temperature-to-volume ratio of a gas is constant.
d. The temperature-to-volume ratio of a gas isn't constant.
Answer:
Check the first and the third choices:
a. The temperature of a gas is directly proportional to its volumeb. The temperature-to-volume ratio of a gas is constant.
Explanation:
Rewrite the table for better understanding:
Temperature of gas (K) Volume of gas (L)
298 4.55
315 4.81
325 4.96
335 ?
Calculate the ratios temperature to volume with 3 significant figures:
298 / 4.55 = 65.5315 / 4.81 = 65.5325 / 4.96 = 65.5Then, those numbers show a constant temperature-to-volume ratio, which may be expressed in a formula as:
Temperature / Volume = constant, which is a directly proportional variation (the volume increases in a constant proportion to the increase of the temperature).Hence, the correct choices are:
The temperature of a gas is directly proportional to its volume (first statement), andThe emperature-to-volume ratio of a gas is constant (third statement).The data provided by the student supports the formulation of a tentative law that aligns with Charles's law, indicating that the temperature of a gas is directly proportional to its volume, and the temperature-to-volume ratio of a gas is constant when pressure is held constant.
Explanation:The student's measurements of the volume of a gas sample at different temperatures demonstrate a principle in chemistry known as Charles's law. According to this law, the volume of a gas is directly proportional to its temperature when pressure is held constant. Given the data provided, we can infer that as the temperature of the gas increases, so does its volume. This observation can be used to tentatively declare a law based on the student's measurements.
From the answer choices provided:
a. The temperature of a gas is directly proportional to its volume.c. The temperature-to-volume ratio of a gas is constant when measured in kelvins and pressure is constant.These explanations are consistent with the observed data that show the volume of the gas increases with increasing temperature. Thus, choices (a) and (c) are the correct interpretations of the experimental data.
wo tiny spheres have the same mass and carry charges of the same magnitude. The mass of each sphere is 2.0 × 10−6 kg. The gravitational force that each sphere exerts on the other is balanced by the electric force. determine the charge magnitude.
Answer:
Charge, [tex]q=1.72\times 10^{-16}\ C[/tex]
Explanation:
It is given that, two tiny spheres have the same mass and carry charges of the same magnitude. Let charge on both sphere is q.
Also, the gravitational force that each sphere exerts on the other is balanced by the electric force i.e.
[tex]F_g=F_e[/tex]
[tex]G\dfrac{m^2}{r^2}=k\dfrac{q^2}{r^2}[/tex]
[tex]q=\sqrt{\dfrac{Gm^2}{k}}[/tex]
Where
G is the universal gravitational constant
k is the electrostatic constant
[tex]q=\sqrt{\dfrac{6.67\times 10^{-11}\ Nm^2/kg^2\times (2\times 10^{-6}\ kg)^2}{9\times 10^9\ Nm^2/C^2}}[/tex]
[tex]q=1.72\times 10^{-16}\ C[/tex]
So, the charge on both the spheres is [tex]1.72\times 10^{-16}\ C[/tex]. Hence, this is the required solution.
Answer:
[tex] q =5.439\times 10^{-17}C[/tex]
Explanation:
Given:
Mass of the tiny sphere, M = 2.0 × 10⁻⁶ kg
also masses are equal i.e M₁ = M₂
Now,
the gravitational force between the two masses M₁ and M₂ is given as:
[tex]F_G = \frac{GM_1M_2}{r^2}[/tex]
where,
G is the gravitational force constant = 6.67 x 10⁻¹¹ m³/kg.s²
r = center to center distance between the masses
also,
Electric force between the charges is given as
[tex]F_e=\frac{kq_1q_2}{r^2}[/tex]
where,
q₁ and q₂ are the charges and also it is given that q₁=q₂=q
k is the coulomb's law constant = 9.0 x 10⁹ N.m²/C²
since it is mentioned that [tex]F_G = F_e[/tex]
we have
[tex]\frac{kq_1q_2}{r^2} = \frac{GM_1M_2}{r^2}[/tex]
or
[tex]{9\times 10^9\times q^2} ={6.67\times 10^{-11}(2.0\times 10^{-6})^2}[/tex]
or
[tex] q =5.439\times 10^{-17}C[/tex]
Different units can be used to measure the same physical quantity, differing only by some multiplicative factor. The cgs unit for magnetic field, the gauss, is equal to ________ tesla.
Answer: the creect answer is 10^-4
Explanation:
CGS stands for Cetimetre-Gram-Metre system and Gaussian units constitute a metric system of physical units.
One gauss (G) is equivalent to 1x10^-4 tesla (T) and is used as a unit for measuring magnetic field strength.
Explanation:The cgs unit for magnetic field strength is the gauss (G), which is a smaller unit compared to the SI unit of tesla (T). When converting from gauss to tesla, the relation is that 1 gauss is equal to ×10-4 tesla. For reference, the Earth's magnetic field at its surface is about 0.5 G, or 5 × 10-5 T.
A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15°C. What is the volume of the bubble when it reaches the surface where the pressure is 1.0 atm and the temperature is 27°C?
Answer: 624.98 mL
Explanation:
According to the Ideal Gas Law:
[tex]\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}[/tex] (1)
Where:
[tex]P_{1}=2.4 atm[/tex] is the pressure of the bubble under the surface
[tex]V_{1}=250 mL[/tex] is the volume of the bubble under the surface
[tex]T_{1}=15\°C + 273.15=288.15 K[/tex] is the temperature of the bubble under the surface
[tex]P_{2}=1 atm[/tex] is the pressure of the bubble at the surface
[tex]V_{2}[/tex] is the volume of the bubble at the surface
[tex]T_{2}=27\°C + 273.15=300.15 K[/tex] is the temperature of the bubble at the surface
So, we have to find [tex]V_{2}[/tex]:
[tex]V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}[/tex] (2)
[tex]V_{2}=\frac{(2.4 atm)(250 mL)(300.15 K)}{(288.15 K)(1 atm)}[/tex] (3)
Finally:
[tex]V_{2}=624.98 mL[/tex] This is the volume of the bubble when it reaches the surface
The volume of the bubble when it reaches the surface is about 625 mL
Further explanationThe basic formula of pressure that needs to be recalled is:
Pressure = Force / Cross-sectional Area
or symbolized:
[tex]\large {\boxed {P = F \div A} }[/tex]
P = Pressure (Pa)
F = Force (N)
A = Cross-sectional Area (m²)
Let us now tackle the problem !
In this problem , we will use Ideal Gas Law as follows:
Given:
Initial Volume = V₁ = 250 mL
Initial Pressure = P₁ = 2.4 atm
Initial Temperature = T₁ = 15 + 273 = 288 K
Final Pressure = P₂ = 1.0 atm
Final Temperature = T₂ = 27 + 273 = 300 K
Unknown:
Final Volume = V₂ = ?
Solution:
[tex]\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}[/tex]
[tex]\frac{2.4(250)}{288} = \frac{1.0V_2}{300}[/tex]
[tex]\frac{600}{288} = \frac{1.0V_2}{300}[/tex]
[tex]\frac{25}{12} = \frac{V_2}{300}[/tex]
[tex]V_2 = \frac{25}{12} \times 300[/tex]
[tex]V_2 = 625 \texttt{ mL}[/tex]
[tex]\texttt{ }[/tex]
Learn moreMinimum Coefficient of Static Friction : https://brainly.com/question/5884009The Pressure In A Sealed Plastic Container : https://brainly.com/question/10209135Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454Answer detailsGrade: High School
Subject: Physics
Chapter: Pressure
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant , Liquid , Pressure
Roberto and Laura are studying across from each other at a wide table. Laura slides a 2.2 kg book
toward Roberto. If the net force acting on the book is 1.6 N to the right, what is the book's acceleration?
Explanation:
Force = Mass × Acceleration
1.6 = 2.2 × a
a = 1.6/2.2
= 0.73 m/s^2
Note that the acceleration will be negative.
Answer: The acceleration of the book is [tex]0.73m/s^2[/tex]
Explanation:
Force is defined as the push or pull on an object with some mass that causes change in its velocity.
It is also defined as the mass multiplied by the acceleration of the object.
Mathematically,
[tex]F=ma[/tex]
where,
F = force exerted on the book = 1.6 N
m = mass of the book = 2.2 kg
a = acceleration of the book = ?
Putting values in above equation, we get:
[tex]1.6kg.m/s^2=2.2\times a\\\\a=\frac{1.6}{2.2}=0.73m/s^2[/tex]
Hence, the acceleration of the book is [tex]0.73m/s^2[/tex]
If the magnitude of the electric field in air exceeds roughly 3 ✕ 106 N/C, the air breaks down and a spark forms. For a two-disk capacitor of radius 54 cm with a gap of 3 mm, what is the maximum charge (plus and minus) that can be placed on the disks without a spark forming (which would permit charge to flow from one disk to the other)? The constant ε0 = 8.85 ✕ 10-12 C2/(N·m2).
The electric field inside a parallel plate capacitor is given by:
E = Q/(ε₀A)
E is the electric field, Q is the charge stored on one of the plates, and A is the area of one of the plates.
The plates are circular, so the area A of one of the plates is given by:
A = πr²
where r is the radius.
Therefore the electric field is given by:
E = Q/(ε₀πr²)
Given values:
E = 3×10⁶N/C (max E field allowed before breakdown occurs)
r = 54×10⁻²m
Plug in these values and solve for Q:
3×10⁶ = Q/(ε₀π(54×10⁻²)²)
Q = 2.4×10⁻⁵C
A rope has one end tied to a vertical support. You hold the other end so that the rope is horizontal. If you move the end of the rope back and forth with a frequency of 4 Hz, the transverse wave you produce has a wavelength of 0.5 m. What is the speed of the wave in the rope?
a. 0.13 m/s
b. 8 m/s
c. 2 m/s
d. 4 m/s
Like any other wave, the speed of the wave on the rope is
Speed = (frequency) x (wavelength)
Speed = (4 Hz) x (0.5 m)
Speed = 2 m/s
Which of the fundamental forces explains the structure of atoms and molecules? gravitational force
electromagnetic force
weak nuclear force
strong nuclear force
pls help me
Answer:
Strong nuclear force
Explanation:
Strong nuclear force (which is the strongest of the forces of the universe) is responsible for the attractive force between quarks to form nucleons (protons and neutrons). It is the reason why the protons (that are positive in charge) do not fly apart due to electromagnetic repulsion in the nucleus of an atom.
Which of the following is also a form of electromagnetic waves like light? A. Microwaves B. Sound waves C. Thermal energy D. Alpha radiation
Microwaves is a form of electromagnetic waves like light.
Answer: Option A
Explanation:
Electromagnetic spectrum constitutes a broad classification of waves of different wavelength starting from radio waves to gamma rays. Microwaves are in the order of Giga hertz (i.e) 10^9 where it finds major applications like antennas used in the television, frequency of FM radio channels, cellular phones, e.t.c.
Their wavelength ranges from 1 meter to one millimeter. The sun is also capable of emitting microwaves where most of them are observed by the earth's atmosphere.
In Ptolemy's Earth-centered model for the solar system, Venus's phase is never full as viewed from Earth because it always lies between Earth and the Sun. In reality, as Galileo first recognized, Venus is __________.
Explanation:
Galileo observed that Venus presented phases (such as those of the moon) together with a variation in size; observations that are only compatible with the fact that Venus rotates around the Sun and not around Earth.
This is because Venus presented its smaller size when it was in full phase and the largest size when it was in the new one, when it is between the Sun and the Earth.
In other words: When Venus is in its full phase it is not possible to observe it from the Earth because always in this phase, Venus, the Sun and the Earth are in conjunction (or aligned). This means the Sun is between Venus and Earth, in the orbit that both planets describe around this star.
Therefore, from the Earth, the Sun covers Venus.
This fact along with other discoveries were presented by Galileo to the Catholic Church (which supported the geocentric theory at that time) as a proof that completely refuted Ptolemy's geocentric system and affirmed Copernicus' heliocentric theory.
The drag force pushes opposite your motion as you ride a bicycle. If you double your speed, what happens to your force?
Explanation:
The Drag Force equation is:
[tex]F_{D}=\frac{1}{2}C_{D}\rho A_{D}V^{2}[/tex] (1)
Where:
[tex]F_{D}[/tex] is the Drag Force
[tex]C_{D}[/tex] is the Drag coefficient, which depends on the material
[tex]\rho[/tex] is the density of the fluid where the bicycle is moving (air in this case)
[tex]A_{D}[/tex] is the transversal area of the body or object
[tex]V[/tex] the bicycle's velocity
Now, if we assume [tex]C_{D}[/tex], [tex]\rho[/tex] and [tex]A_{D}[/tex] are constant (do not change) we can rewrite (1) as:
[tex]F_{D}=C.V^{2}[/tex] (2)
Where [tex]C[/tex] groups all these coefficients.
So, if we have a new velocity [tex]V_{n}[/tex] , which is the double of the former velocity:
[tex]V_{n}=2V[/tex] (3)
Equation (2) is written as:
[tex]F_{D}=C.(V_{n})^{2}=C.(2V)^{2}[/tex]
[tex]F_{D}=4CV^{2}[/tex] (4)
Comparing (2) and (4) we can conclude the Drag force is four times greater when the speed is doubled.
1. What is the average acceleration of a subway train that speeds up from 9.6m/s to 12m/s in .8s on a straight track?
2. An acorn at rest falls from an oak tree. The acorn hits the ground with a velocity of 14.7m/s. How long did it take the acorn to land?
3. What force is necessary to accelerate a 1,250 kg car at a rate of 40m/s^2
4. The mass of a person that weighs 500 N is about...?
PLEASE HELP ME THANK YOU
Explanation:
1. Average acceleration is change in velocity over change in time.
a = Δv / Δt
a = (12 m/s - 9.6 m/s) / 0.8 s
a = 3 m/s²
2. a = Δv / Δt
9.8 m/s² = (14.7 m/s - 0 m/s) / Δt
Δt = 1.5 s
3. Force is mass times acceleration.
F = ma
F = (1250 kg) (40 m/s²)
F = 50,000 N
4. F = ma
500 N = m (9.8 m/s²)
m ≈ 51 kg
The problems are solved by applying physics concepts and formulas: acceleration (`(final velocity - initial velocity)/time`), time (`velocity/acceleration`), force (`mass x acceleration`), and weight (`mass x gravity`), thereby finding the acceleration as 3 m/s², the time as 1.5s, the force as 50,000N, and the person's mass as 51kg.
Explanation:The questions are related to fundamental concepts in Physics; namely acceleration, time, force, and mass.
To find the average acceleration, you use the formula `(final velocity - initial velocity)/time`. Substituting the values, you get `(12m/s - 9.6m/s)/0.8s` which equals 3 m/s².To find the time an acorn takes to land, you use the formula `distance/velocity`. Assuming the acorn falls from rest and no air resistance, the distance is equivalent to velocity multiplied by time. However, because the velocity isn't constant, we must use the formula for velocity in uniformly accelerated motion: velocity = acceleration x time`. In this case, acceleration due to gravity is 9.8m/s², so 14.7m/s = 9.8m/s² x time. Solving that gives time ≈ 1.5s.To find the force to accelerate a car, use the formula force = mass x acceleration. Substituting the values, we get 1250kg x 40m/s², which equals 50000 N.To find a person's mass from weight, use the formula weight = mass x gravity. Given the weight is 500N and assuming gravity is 9.8m/s², rearranging the formula gives mass = weight/gravity which equals approximately 51kg.Learn more about Physics formulas here:https://brainly.com/question/34207444
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The formula of acetic acid is C2H4O2. How many atoms is acetic acid composed of? A. 6 B. 8 C. 4 D. 3
Acetic acid, with the chemical formula C2H4O2, is composed of B. 8 atoms.
What is acetic acid?Acetic acid is represented by the chemical formula C2H4O2. In this formula, there are 2 carbon atoms, 4 hydrogen atoms, and 2 oxygen atoms.
Each letter in the chemical formula corresponds to one atom, and the subscripts denote the number of atoms of each element present. By adding these numbers together (2 + 4 + 2), we obtain the total number of atoms in acetic acid, which is 8. Therefore, the correct option is B (8).
Acetic acid, with its molecular formula C2H4O2, consists of 8 atoms in total, comprising carbon, hydrogen, and oxygen.
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2. An engine's _______ contains the cylinder head, the valves, the valve train components, the manifolds, and the engine covers. A. lower end B. upper end C. bottom end D. back end
Answer:
B. upper end
Explanation:
An engine's upper end contains the cylinder head, the valves, the valve train components, the manifolds, and the engine covers.
Final answer:
The upper end of an engine contains important components such as the cylinder head, valves, and valve train components.
Explanation:
The answer to the question is B. upper end. The upper end of an engine refers to the components located above the engine block. This includes the cylinder head, valves, valve train components, manifolds, and engine covers. These components are responsible for controlling the flow of air and fuel into the cylinders and the expulsion of exhaust gases.
A 65-kg bungee jumper, who is attached to one end of an 85-m long bungee cord that has its other end tied to a bridge, jumps off the bridge and toward the river below. When stretched, the bungee cord acts like a spring and provides a force on the jumper that increases linearly as the cord is stretched. When the bungee cord is stretched to its maximum length, it exerts a 2.2 kN force on the jumper. If the bungee cord is stretched beyond its equilibrium length for a duration of 1.2 seconds, what is the impulse delivered to the bungee jumper
Answer:
The impulse delivered to the bungee jumper is 1.32 kN.s
Explanation:
The situation can be shown graphically as shown in the figure.
Impulse delivered to the bungee jumper = Area under the curve.
The curve represents a triangle and the area of traiangle = (1/2)base×height
The base of the triangle from the graph = 1.2 seconds.
The height of the triangle from the graph = 2.2 kN
Thus,
Impulse = (1/2)×(1.2 seconds)×(2.2 kN) = 1.32 kN.s
Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.70 m. It takes the ball 0.60 seconds to complete one full circle. Calculate the tension in the string and its direction that provides the centripetal force acting on the ball to keep it in the circular path.
A) 0.0077 N, toward the center of the circle
B) 1.2 N, toward the center of the circle
C) 0.0077 N, along the line tangent to the circle
D) 1.2 N, along the line tangent to the circle
Answer:
B) 1.2 N, toward the center of the circle
Explanation:
The circumference of the circle is:
C = 2πr
C = 2π (0.70 m)
C = 4.40 m
So the velocity of the ball is:
v = C/t
v = 4.40 m / 0.60 s
v = 7.33 m/s
Sum of the forces in the radial direction:
∑F = ma
T = m v² / r
T = (0.015 kg) (7.33 m/s)² / (0.70 m)
T = 1.2 N
The tension force is 1.2 N towards the center of the circle.
Answer:
1.2 N, toward the center of the circle
Explanation:
It is given that,
Mass of the ball, m = 0.015 kg
The radius of the circle, r = 0.7 m
Time taken by the ball to complete complete circle, t = 0.6 s
We need to find the tension in the string and its direction that provides the centripetal force acting on the ball to keep it in the circular path. Here, tension in the string balances the centripetal force so that the ball moves in circular path. So,
[tex]T=\dfrac{mv^2}{r}[/tex]
Since, [tex]v=\dfrac{2\pi r}{t}=\dfrac{2\pi \times 0.7}{0.6}=7.33\ m/s[/tex]
So, [tex]T=\dfrac{0.015\times (7.33)^2}{0.7}[/tex]
T = 1.15 N
or
T = 1.2 N
The direction of centripetal force is toward the center of circle. So, the correct option is (b).
An archer shoots an arrow at a 75.0 m distant target; the bull's-eye of the target is at same height as the release height of the arrow. (a) At what angle must the arrow be released to hit the bull's-eye if its initial speed is 35.0 m/s? In this part of the problem, explicitly show how you follow the steps involved in solving projectile motion problems. (b) There is a large tree halfway between the archer and the target with an overhanging horizontal branch 3.50 m above the release height of the arrow. Will the arrow go over or under the branch?
(a) [tex]18.4^{\circ}[/tex]
We know that the horizontal distance travelled by the arrow is
d = 75.0 m
We also know that the horizontal range of a projectile is given by
[tex]d=\frac{v^2}{g} sin 2\theta[/tex]
where
v is the speed of the projectile
g = 9.8 m/s^2 is the acceleration of gravity
[tex]\theta[/tex] is the angle of the projectile
Here we have
v = 35.0 m/s
Substituting into the equation and solving for [tex]\theta[/tex], we find
[tex]\theta=\frac{1}{2}sin^{-1} (\frac{dg}{v^2})=\frac{1}{2}sin^{-1} (\frac{(75.0 m)(9.8 m/s^2)}{(35.0 m/s)^2})=18.4^{\circ}[/tex]
(b) 6.2 m
In order to answer this part of the problem, we have to calculate what is the maximum height reached by the projectile in its trajectory.
First of all, we can calculate the vertical component of the velocity, which is given by:
[tex]u_y = u sin \theta = (35.0 m/s) sin 18.4^{\circ} = 11.0 m/s[/tex]
The motion along the vertical direction is a uniformly accelerated motion with constant acceleration
g = -9.8 m/s^2
(negative since it points downward). So we can write
[tex]v_y^2 - u_y^2 = 2gh[/tex]
where
[tex]v_y = 0[/tex] is the vertical velocity at the point of maximum height
h is the maximum height
Solving for h, we find
[tex]h=\frac{v_y^2 - u_y^2}{2g}=\frac{0-(11.0 m/s)^2}{2(-9.8 m/s^2)}=6.2 m[/tex]
Therefore, the arrow will go over the branch (which is located 3.50 m above the ground).
Projectile motion principles can be used to solve this problem. θ can be calculated by substituting the given values into the kinematic equation. To know if the arrow goes over or under the branch, calculate the arrow's height at halfway point and compare with the height of the branch.
Explanation:The subject of this question pertains to projectile motion in physics. In order to solve this, we must apply kinematic equations, specifically the equation for horizontal projectile motion which is θ = arctan[(v² ± √(v⁴ - g*(g*x² + 2*y*v²)) / (g*x)], where v is the initial speed, g is the acceleration due to gravity, x is the horizontal distance, and y is the vertical distance.
First, determine the initial speed in m/s, which is given as 35.0 m/s.Next, set the acceleration due to gravity as g = 9.8 m/s².Then, define the horizontal distance x to the target, which is 75.0 m.Set y = 0, because the release height and target height are the same.Plug these numbers into the equation to find θ, which will need to be calculated twice because of the ± in the equation. You'll get two angles, but only the smaller one is practically possible, because the larger would require the arrow to first rise above the target before falling to it.For part (b), to determine if the arrow will go over or under the branch, calculate the arrow's height at the halfway point using the formula y = x*tan(θ) - [(g*x²) / (2*v²*cos²(θ))]. If this height is greater than 3.5 m, the arrow will go over the branch. Otherwise, it will go under.Learn more about Projectile Motion here:https://brainly.com/question/20627626
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A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end.The wire is 0.330 m long and has a mass of 9.60 g. It is fixed at both ends and oscillates in its fundamental mode.By resonance,it sets the air column in the tube into oscillation at that column’s fundamental frequency. Find (a) that frequency and (b) the tension in the wire.
Answer:
Explanation:
tube:
f=v/4L = 343/(4*1.2)= 71.4583Hz tube's fundamental frequency
wire:
f=v/2L -> v=2Lf
v= 2*0.323*71.4583= 46.162m/s
ρ= 0.0095/0.323= 0.02941kg/m
v=√(T/ρ) -> T=v^2*ρ
T= 46.162^2*0.02941= 62.67[N] Tension of wire.
Nuclear energy comes from splitting atoms of __________ to generate heat.
Answer:
Nuclear energy originates from the splitting of uranium atoms – a process called fission. This generates heat to produce steam, which is used by a turbine generator to generate electricity. Because nuclear power plants do not burn fuel, they do not produce greenhouse gas emissions.
Explanation:
Nuclear energy primarily comes from the process of nuclear fission, specifically the splitting of Uranium-235 atoms. This process releases immense energy which is utilized to generate power in nuclear power plants.
Explanation:Nuclear energy, used feasible in power plants, comes primarily from the process of splitting atoms of Uranium-235, a process known as nuclear fission. In this process, a neutron collides with a Uranium atom, causing the atom to split and release more neutrons along with a large amount of energy. This energy, in the form of heat, is then used to produce steam which drives turbines, thereby generating electricity.
Thus, it's clear that the process of splitting large, complex atomic nuclei, particularly those of Uranium-235, not only induces a chain reaction (due to the release of more neutrons) but also provides us with a sophisticated method of generating power in the form of nuclear energy.
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A small cylinder made of a diamagnetic material is brought near a bar magnet. One end of the cylinder is brought near the North pole of the magnet and is repelled. What happens when the other end of the cylinder is brought near the North pole of the magnet? (A) The other end of the cylinder will be repelled by the magnet.(B) The other end of the cylinder will not be affected by the magnet.(C) The other end of the cylinder will be attracted more strongly by the magnet.(D) The other end of the cylinder will be attracted less strongly by the magnet.(E) The other end of the cylinder will be attracted by the magnet.
Answer: Option (A) is the correct answer.
Explanation:
A diamagnetic material does not contain any unpaired electrons and therefore, in a magnetic field direction they will always flow in the direction opposite to the magnetic field.
Hence, a diamagnetic material will always repel the magnetic field whenever it comes in contact with that.
Thus, we can conclude that when the other end of the cylinder is brought near the North pole of the magnet then the other end of the cylinder will be repelled by the magnet.
A diffraction grating with 750 slits per mm is illuminated by light which gives a first-order diffraction angle of 34.0°. What is the wavelength of the light?
Explanation:
The diffraction angles [tex]\theta_{n}[/tex] when we have a slit divided into [tex]n[/tex] parts are obtained by the following equation:
[tex]dsin\theta_{n}=n\lambda[/tex] (1)
Where:
[tex]d[/tex] is the width of the slit
[tex]\lambda[/tex] is the wavelength of the light
[tex]n[/tex] is an integer different from zero
Now, the first-order diffraction angle is given when [tex]n=1[/tex], hence equation (1) becomes:
[tex]dsin\theta_{1}=\lambda[/tex] (2)
We know:
[tex]\theta_{1}=34\°[/tex]
In addition we are told the diffraction grating has 750 slits per mm, this means:
[tex]d=\frac{1mm}{750}[/tex]
Solving (2) with the known values we will find [tex]\lambda[/tex]:
[tex]\lambda=(\frac{1mm}{750})sin(34\°)[/tex] (3)
[tex]\lambda=0.00074559mm[/tex] (4)
Knowing [tex]1mm=10^{6}nm[/tex]:
[tex]\lambda=745.59nm[/tex] >>>This is the wavelength of the light, wich corresponds to red.
Divers often inflate heavy duty balloons attached to salvage items on the sea floor. If a balloon is filled to a volume of 3.00 L at a pressure of 2.50 atm, what is the volume of the balloon when it reaches the surface?
Answer: The volume of balloon when it reaches the surface is 7.5 L.
Explanation:
The normal pressure at the surface of sea is 1 atm.
To calculate the volume of balloon, we use the equation given by Boyle's law.
This law states that pressure of the gas is inversely proportional to the volume of the gas at constant temperature. The equation for this law follows:
[tex]P_1V_1=P_2V_2[/tex]
[tex]P_1\text{ and }V_1[/tex] are initial pressure and volume.
[tex]P_2\text{ and }V_2[/tex] are final pressure and volume.
We are given:
[tex]P_1=2.5atm\\V_1=3.00L\\P_2=1atm\\V_2=?L[/tex]
Putting values in above equation, we get:
[tex]2.5atm\times 3L=1atm\times V_2\\\\V_2=7.5L[/tex]
Hence, the volume of balloon when it reaches the surface is 7.5 L.
A rock thrown with speed 7.50 m/s and launch angle 30.0 ∘ (above the horizontal) travels a horizontal distance of d = 18.0 m before hitting the ground. From what height was the rock thrown? Use the value g = 9.800 m/s2 for the free-fall acceleration.
Answer:
height from where rock was thrown is 27.916 m
Explanation:
speed = 7.50 m/s
θ = 30°
g= 9.8 m/s²
horizontal distance = 18 m
time require for vertical displacement
[tex]time = \frac{distance}{velocity} \\t = \frac{18}{7.5\ cos30^0}[/tex]
t = 2.8 sec
now for calculation of height
s = ut + 0.5 a t²
-h = v sinθ× t + 0.5 ×(-9.8)× (2.8²)
-h = 7.5 sin30°× 2.8 - 0.5 ×(9.8)× (2.8²)
-h = -27.916 m
h= 27.916 m
height from where rock was thrown is 27.916 m
Final answer:
To find the height from which the rock was thrown, we can use the equations of projectile motion to calculate the time it takes for the rock to hit the ground and then find the height using another equation. The rock was thrown from a height of 5.7 meters.
Explanation:
To find the height from which the rock was thrown, first, we need to determine the time it takes for the rock to hit the ground.
Using the equation d = v_iy * t + (1/2) * g * t^2, where d is the vertical distance, v_iy is the initial vertical velocity, t is the time, and g is the acceleration due to gravity, plug in the values:
d = 0 (since the rock starts and ends at the same height)
v_iy = 7.5 m/s * sin(30°)
g = 9.8 m/s^2
Solving for t, we get t = 1.22 s.
Next, we can find the height by using the equation d = v_iy * t - (1/2) * g * t^2 and plugging in the values:
d = ?, the height we want to find
v_iy = 7.5 m/s * sin(30°)
t = 1.22 s
g = 9.8 m/s^2
Solving for d, we get d = 5.7 m.
Therefore, the rock was thrown from a height of 5.7 meters.
If you were to cut a small permanent bar magnet in half,A) None of these statements is true. B) one piece would be a magnetic north pole and the other piece would be a south pole.C) each piece would in itself be a smaller bar magnet with both north and south poles.D) neither piece would be magnetic.
Explanation:
According to classical physics, a magnetic field always has two associated magnetic poles (north and south), the same happens with magnets. This means that if we break a magnet in half, we will have two magnets, where each new magnet will have a new south pole, and a new north pole. However, the magnetic force of each magnet will be less than that of the original magnet.
This is because for classical physics, naturally, magnetic monopoles can not exist.
Nevertheless, according to quantum physics, magnetic monopoles do exist, which was predicted by Paul Dirac in 1981. This has led to several experiments and investigations, among which the most recent one so far (year 2014), is the experiment led by a group of scientists from the Amherst College (United States) and the University of Aalto (Finland), that reported having synthesized for the first time in a laboratory a magnet of a single magnetic pole.