The man lands 12.1 m far from the base of the cliff, so he will survive
Explanation:
The motion of the person is a projectile motion, which consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
We start by considering the vertical motion, to find the time of flight of the person, with the following suvat equation:
[tex]s=ut+\frac{1}{2}gt^2[/tex]
where :
s = 50 m is the vertical displacement of the man (the height of the cliff)
t is the time of flight
u = 0 is the initial vertical velocity
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
Solving for t, we find
[tex]t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(50)}{9.8}}=3.19 s[/tex]
Now we know that the man moves horizontally, with a constant velocity of
[tex]v_x = 3.8 m/s[/tex]
Therefore, the horizontal distance covered by the man during this time is
[tex]d=v_x t = (3.8)(3.19)=12.1 m[/tex]
So the man lands 12.1 m far from the base of the cliff: therefore, on the lake, so he will survive.
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A 4 kg textbook sits on a desk. It is pushed horizontally with a 50 N applied force against a 15 N frictional force.
a. Draw a free body diagram for the textbook.
b. What is the motion in the vertical?
c. What is the net horizontal force acting on the book?
d. What is the net force acting on the book?
e. What is the acceleration of the book?
Answer:
a. See attached diagram
b. There is no vertical motion
c. Net horizontal force: 35 N
d. Total net force: 35 N
e. Acceleration of the book: 8.75 m/s^2
Explanation:
Please see attached diagram for all the forces acting on the book:
Forces acting vertically:
1) The book's weight (force exerted by gravity) is pictured in purple pointing down and labeled "w".
2) The normal force the table exerts on the book as reaction, is pictured in blue pointing up, and labeled "n". It cancels with the force of gravity, so there is no vertical movement since gravitational force and the normal are the only forces acting in the vertical direction.
Forces acting horizontally:
1) the pushing 50 N force is pictured in green and pointing to the right, parallel to the surface of the table.
2) the 15 N force of friction is pictured in red, and acting in opposite direction to the pushing force. It is represented by a shorter vector than the pushing force due to the fact that its magnitude is smaller.
In this horizontal direction there is a net force that is propelling the object in horizontal motion. This net force is the difference between the 50 N force and the 15 N force, resulting in a 35 N force pointing in the same direction as the pushing force.
The net horizontal force is 35 N in magnitude.
The addition of all forces acting is dominated by the horizontal components, since the vertical acting forces cancel each other. Therefore, the total net force acting on the book is the 35 N resulting horizontal force.
The acceleration of the book can be calculated via Newton's second law of motion:
[tex]F_{net}=m\,*\,a\\35 N = 4\,kg\,*a\\a=\frac{35}{4} \,\frac{m}{s^2} \\a=8.75\, \frac{m}{s^2}[/tex]
We all know that in the earth gravity is there,but why clouds doesn't fall down???
Answer: Clouds are evaporated sea water. You should be asking "Why does the gravity on Earth pull us down and not evaporated water.
Explanation:
Answer:
Because of their mass
Explanation:
Clouds are made of water right ? so you are asking why they don't fall down if air is lighter than water .
The two biggest reasons the clouds stay in the sky are
1. Small Drops
2. Wind
Small drops of water fall more slowly than big drops, as the drops of the clouds fall thought the air, the air pushes back to them, because Small drops has less mass than large drops, clouds can only contain small drops of water.
You are standing on the SCALE
The scale is on the floor.
What are the forces on the SCALE?
Answer:
The Normal and Gravitational Force
Explanation:
The normal force pushes up and is between the ground and the scale. The gravitational force is the force exerted on the ground.
4. A safe is hurled down from the top of a 1.3 x 102 m
building at a speed of 11.0 m/s. What is its velocity as
it hits the ground?
The final speed of the safe is 51.7 m/s
Explanation:
The motion of the safe is a free fall motion, which is a motion at constant acceleration ([tex]g=9.8 m/s^2[/tex], towards the ground). Therefore, we can apply the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
In this problem we have (taking downward as positive direction):
u = 11.0 m/s
[tex]a=g=9.8 m/s^2[/tex]
[tex]s=1.3\cdot 10^2 m= 130 m[/tex] is the vertical displacement (the height of the building)
Solving for v, we find the final velocity (and so, the final speed):
[tex]v=\sqrt{u^2+2as}=\sqrt{11.0^2+2(9.8)(130)}=51.7 m/s[/tex]
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A cat walks 15 m north and then 12 m south. What distance did the cat walk?
O
A. 27 m north
O
B. 3 m
O
c. 27 m
O
D. 3 m north
Answer:
it's 27 meters - answer B
Most of the sun's energy reaches Earth by
conduction
radiation
convection
thermal expansion
Radiation is the process by which energy is transferred in the form of electromagnetic waves, including visible light, infrared radiation, and ultraviolet radiation. Most of the Sun's energy reaches Earth by b) radiation.
The Sun emits a vast amount of energy through nuclear fusion processes occurring in its core. This energy travels through space in the form of electromagnetic waves and reaches Earth as sunlight. Unlike conduction and convection, which require a medium or material substance to transfer heat, radiation can occur in a vacuum and does not require a physical medium.
The energy from the Sun's radiation is essential for sustaining life on Earth and driving various Earthly processes such as weather, climate, and photosynthesis.
Most of the Sun's energy reaches Earth by b) radiation.
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So, like my previous question, how do you solve for 4/5 - 1/2?
Answer:
3/10
Explanation:
4/5(2)
-1/2(5)
8/10-5/10
3/10
Answer:
I believe its x = 22
Consider this situation: A child is holding onto a tree rope and swinging through the air.
Of the forces listed, identify which act upon the child.
a. Normal Force
b. Gravity Force
c. Applied Force
d. Friction Force
e. Tension Force
f. Air Resistance Force
Final answer:
In the scenario of a child swinging on a rope, the acting forces are the gravity force, tension force, and air resistance force. Normal force and applied force are not directly acting on the child in the swing, and friction force is not a significant factor in this context.
Explanation:
When a child is swinging through the air while holding onto a tree rope, the child is subject to several forces. Among the forces listed, the following forces act upon the child:
Gravity Force: This is also known as weight, represented by W in the free-body diagram. It pulls the child directly downwards towards the center of the Earth.
Tension Force: Represented by T in the free-body diagram, this force is exerted by the rope on the child, pulling upwards and often inclined depending on the motion of the swing.
Air Resistance Force: As the child swings, they encounter air resistance that opposes their motion through the air.
The normal force does not act upon the child while they are swinging because there is no perpendicular contact with a solid surface like the ground or a table. Applied force would be present if someone or something else is pushing the child to start the swinging motion or to keep it going. However, for the child simply swinging, we do not consider an ongoing applied force. Friction force is usually associated with contact between two surfaces, such as the wheels of a wagon rolling on the ground. Therefore, friction is not a significant factor when considering a child swinging on a rope.
Using this understanding, we can create a free-body diagram that includes only external forces such as gravity force, tension force, and air resistance force to analyze the child's motion.
When a loaded cannon is fired, which physical variables are affected?
Answer:
it can explode lol
Explanation:
Historically, massive stone or metal balls were fired from cannons, which are big, powerful guns that are typically mounted on two or four wheels.
What are the physical variables?Because they result from the existence of quantitative characteristics of physical systems, physical variables provide the basis of the mathematical formulation of physics. It is convenient to begin with a thorough investigation of the physical variables in a physical theory before analyzing its mathematical structure.
When a loaded cannon is fired, some of the physical variables get affected
the cannon's temperaturethe potential energy of chemicalsthe ball's temperaturethe canon's momentumBall's velocity and so on.These are few physical variables which get affected when loaded cannon is fired.
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- 4x4 – 13x3 + 8x2 – 21x + 18 is divided by 2 – 3?
Answer:
x = 3/4 or x = ((-1)^(1/3) (127 - 18 sqrt(43))^(2/3) - 13 (-1)^(2/3))/(3 (127 - 18 sqrt(43))^(1/3)) - 4/3 or x = 1/3 (13 (-1/(127 - 18 sqrt(43)))^(1/3) - (-1)^(1/3) (18 sqrt(43) - 127)^(1/3)) - 4/3 or x = (-(127 - 18 sqrt(43))^(2/3) - 13)/(3 (127 - 18 sqrt(43))^(1/3)) - 4/3
Explanation:
Solve for x over the real numbers:
4 x^4 + 13 x^3 - 8 x^2 + 21 x - 18 = 0
The left hand side factors into a product with two terms:
(4 x - 3) (x^3 + 4 x^2 + x + 6) = 0
Split into two equations:
4 x - 3 = 0 or x^3 + 4 x^2 + x + 6 = 0
Add 3 to both sides:
4 x = 3 or x^3 + 4 x^2 + x + 6 = 0
Divide both sides by 4:
x = 3/4 or x^3 + 4 x^2 + x + 6 = 0
Eliminate the quadratic term by substituting y = x + 4/3:
x = 3/4 or 14/3 + 4 (y - 4/3)^2 + (y - 4/3)^3 + y = 0
Expand out terms of the left hand side:
x = 3/4 or y^3 - (13 y)/3 + 254/27 = 0
Change coordinates by substituting y = z + λ/z, where λ is a constant value that will be determined later:
x = 3/4 or 254/27 - 13/3 (z + λ/z) + (z + λ/z)^3 = 0
Multiply both sides by z^3 and collect in terms of z:
x = 3/4 or z^6 + z^4 (3 λ - 13/3) + (254 z^3)/27 + z^2 (3 λ^2 - (13 λ)/3) + λ^3 = 0
Substitute λ = 13/9 and then u = z^3, yielding a quadratic equation in the variable u:
x = 3/4 or u^2 + (254 u)/27 + 2197/729 = 0
Find the positive solution to the quadratic equation:
x = 3/4 or u = 1/27 (18 sqrt(43) - 127)
Substitute back for u = z^3:
x = 3/4 or z^3 = 1/27 (18 sqrt(43) - 127)
Taking cube roots gives 1/3 (18 sqrt(43) - 127)^(1/3) times the third roots of unity:
x = 3/4 or z = 1/3 (18 sqrt(43) - 127)^(1/3) or z = -1/3 (-1)^(1/3) (18 sqrt(43) - 127)^(1/3) or z = 1/3 (-1)^(2/3) (18 sqrt(43) - 127)^(1/3)
Substitute each value of z into y = z + 13/(9 z):
x = 3/4 or y = 1/3 (18 sqrt(43) - 127)^(1/3) - (13 (-1)^(2/3))/(3 (127 - 18 sqrt(43))^(1/3)) or y = 13/3 ((-1)/(127 - 18 sqrt(43)))^(1/3) - 1/3 (-1)^(1/3) (18 sqrt(43) - 127)^(1/3) or y = 1/3 (-1)^(2/3) (18 sqrt(43) - 127)^(1/3) - 13/(3 (127 - 18 sqrt(43))^(1/3))
Bring each solution to a common denominator and simplify:
x = 3/4 or y = ((-1)^(1/3) (127 - 18 sqrt(43))^(2/3) - 13 (-1)^(2/3))/(3 (127 - 18 sqrt(43))^(1/3)) or y = 1/3 (13 ((-1)/(127 - 18 sqrt(43)))^(1/3) - (-1)^(1/3) (18 sqrt(43) - 127)^(1/3)) or y = (-(127 - 18 sqrt(43))^(2/3) - 13)/(3 (127 - 18 sqrt(43))^(1/3))
Substitute back for x = y - 4/3:
Answer: x = 3/4 or x = ((-1)^(1/3) (127 - 18 sqrt(43))^(2/3) - 13 (-1)^(2/3))/(3 (127 - 18 sqrt(43))^(1/3)) - 4/3 or x = 1/3 (13 (-1/(127 - 18 sqrt(43)))^(1/3) - (-1)^(1/3) (18 sqrt(43) - 127)^(1/3)) - 4/3 or x = (-(127 - 18 sqrt(43))^(2/3) - 13)/(3 (127 - 18 sqrt(43))^(1/3)) - 4/3
Answer:
-58 i think
Explanation:
-16 - 39 + 16 - 21x = 18 divid 2 -3
-16 - 55 - 39x divided by 2 - 3
-110 divided by 2 - 3
-55 - 3 = -58
An airplane weighing 11,000 N climbs to a
height of 1.6 km in 9.8 min. Calculate the
accomplished power in horsepower.
The power in horsepower is 40.1 hp
Explanation:
We start by calculating the work done by the airplane during the climb, which is equal to its change in gravitational potential energy:
[tex]W=(mg)\Delta h[/tex]
where
mg = 11,000 N is the weight of the airplane
[tex]\Delta h = 1.6 km = 1600 m[/tex] is the change in height
Substituting,
[tex]W=(11,000)(1600)=17.6\cdot 10^6 J[/tex]
Now we can calculate the power delivered, which is given by
[tex]P=\frac{W}{t}[/tex]
where
[tex]W=17.6\cdot 10^6 J[/tex] is the work done
[tex]t=9.8 min \cdot 60 = 588 s[/tex] is the time taken
Substituting,
[tex]P=\frac{17.6\cdot 10^6 J}{588}=2.99\cdot 10^4 W[/tex]
Finally, we can convert the power into horsepower (hp), keeping in mind that
[tex]1 hp = 746 W[/tex]
Therefore,
[tex]P=\frac{2.99\cdot 10^4}{746}=40.1 hp[/tex]
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Final answer:
The power accomplished by an airplane weighing 11,000 N climbing to a height of 1.6 km in 9.8 min is calculated by determining the change in gravitational potential energy and then converting that work into power over the time taken. The result is approximately 40.13 horsepower.
Explanation:
To calculate the power accomplished, we can use the work-energy principle where the work done by the airplane engines to climb to the height is equal to the change in gravitational potential energy. The gravitational potential energy (GPE) change is calculated as the weight of the airplane times the height it reaches. The formula for GPE is:
GPE = weight × height
For the airplane problem, we have:
GPE = 11,000 N × 1.6 km = 11,000 N × 1600 m = 17,600,000 J (joules)
Next, we convert 9.8 minutes to seconds to find the power in watts. Power is work (or GPE here) divided by time:
Time = 9.8 minutes × 60 seconds/minute = 588 seconds
Power in watts = GPE / Time
Power in watts = 17,600,000 J / 588 s ≈ 29,932 W (watts)
To convert power to horsepower, we use the conversion factor 1 horsepower ≈ 746 watts:
Power in horsepower = Power in watts / 746
Power in horsepower ≈ 29,932 W / 746 ≈ 40.13 hp
Therefore, the accomplished power in horsepower while the airplane climbs to a height of 1.6 km in 9.8 min is approximately 40.13 hp.
If a crane worker lifts a crate with a mass of 200 kg from the ground to a
shipping container that is 45 meters off the ground, by how much has the
worker increased the gravitational potential energy of the crate? (Recall that g
= 9.8 m/s2)
A. 88,200 J
B. 31,900 J
C. 63,500 u
D. 48,100 J
Answer:
A. 88,200 J
Explanation:
Given data,
The mass of the crate, m = 200 kg
The height of the shipping container, h = 45 m
The gravitational of a body is possessed by the body due to the virtue of its position.
The formula for gravitational potential energy is,
P.E = mgh joules
Substituting the values
P.E = 200 x 9.8 x 45
= 88,200 J
Hence, the gravitational potential energy of the crate is, P.E = 88,200 J
12345678910
As a sound wave travels from liquid water into ice, its wavelength would
Stretch.
Hope this helps.
Why should people pay attention to scientists when making decisions?
) A. Scientists are always correct.
B. Scientists are the smartest people.
C. Scientists make the best decisions.
D. Scientists use observation and peer review.
SUBMIT
Final answer:
People should pay attention to scientists when making decisions because they utilize an evidence-based process, with observation and peer review, to discern truths about the natural world. The scientific method underpins the reliability of their findings, which can help inform well-grounded decisions.
Explanation:
People should pay attention to scientists when making decisions because scientists use observation and peer review as a part of the scientific method. This process involves making detailed observations, formulating hypotheses, conducting experiments, and drawing conclusions based on evidence. Scientists' claims are supported by evidence that can be examined and experiments that can be replicated, ensuring reliability and validity in their findings.
Additionally, scientists often work in a community where peer-review plays an essential role in validating studies and research before they are widely accepted. Although the process of science may not be perfect due to factors such as human error or bias, the method remains the best we have for systematically understanding the natural world. The iterative nature of science, with its self-correcting mechanisms like peer-review and replication, often leads to a gradual refinement of knowledge.
Therefore, scientists, through their evidence-based approach, are considered reliable sources for informing decisions related to their field of study. Considering science in decision-making processes also ensures that conclusions are rooted in systematically acquired data, as opposed to unfounded claims or assumptions.
Final answer:
Scientists use observation and peer review to ensure the reliability of their findings, making their conclusions more trustworthy than mere opinion or guesswork. Furthermore, science is a democratic and cumulative process, where open debates and the use of systematic data collection lead to continual progress and refinement of knowledge.
Explanation:
People should pay attention to scientists when making decisions because scientists use observation and peer review. This process involves careful measurement, experimentation, and scrutiny by other experts in the field. Through this rigorous method, scientific claims become more reliable and can predict real outcomes more accurately than personal opinions or anecdotes. As our understanding builds upon prior knowledge, we can progress further in our comprehension of the world.
Moreover, science is a democratic process. Scientists must be skeptical and discuss their observations and theories openly, subjecting their findings to the critical analysis of their peers. This discourse allows for the best data to emerge and for errors to be exposed and corrected. Additionally, scientific advancements are cumulative. We learn from past discoveries and then develop new understandings based on the foundations laid by those who came before us.
Political scientists, similar to natural scientists, rely on data to make informed predictions. They use systematic data collection and analysis to understand patterns and make forecasts about future events rather than relying solely on technology or random chance.
the displacement of the body in 5 seconds from the beginning of the motion is
Answer:
The displacement of the object is, d = 5V m
Explanation:
Given data,
The time period of displacement, t = 5 s
Let the average velocity of the object be, V = v m/s
If the object has an initial velocity, V and final velocity v, then the average velocity of the object is,
V = (u + v) / 2
The formula for velocity, displacement and time is,
V = d / t
∴ d = V x t
On substitution,
d = V x 5 s
= 5V m
Substituting the value of V gives the value of displacement,
Thus, the displacement of the object is, d = 5V m
5V m is the displacement of the object.
What is Displacement?Displacement is defined as the change in position of an object. It is represented as an arrow that points from the initial position to the final position.
According to the question,
Time period , t = 5 s
Let, average velocity of the object is V = v m/s
Assume the initial velocity, V and final velocity v,
So, the average velocity of the object is,
[tex]V = \frac{(u + v)}{2}[/tex]
The relationship between velocity, displacement and time is,
[tex]V = \frac{d}{t}[/tex]
[tex]d = V * t[/tex]
Put t =5s
[tex]d = V * 5 s[/tex]
[tex]d = 5V m[/tex]
Therefore,
The displacement of the object is, d = 5V m
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A block is at rest on the incline shown in the figure. The coefficients of static and ki- netic friction are μs = 0.62 and μk = 0.53, respectively.
2
29◦
What is the frictional force acting on the 46 kg mass?
The frictional force is 218.6 N
Explanation:
The block in the problem is at rest along the inclined surface: this means that the net force acting along the direction parallel to the incline must be zero.
There are two forces acting along this direction:
- The component of the weight parallel to the incline, downward along the plane, of magnitude
[tex]mg sin \theta[/tex]
where
m = 46 kg is the mass
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
[tex]\theta=29^{\circ}[/tex] is the angle of the incline
- The (static) frictional force, acting upward, of magnitude [tex]F_f[/tex]
Since the block is in equilibrium, we can write
[tex]mg sin \theta - F_f = 0[/tex]
And substituting, we find the force of friction:
[tex]F_f = mg sin \theta = (46)(9.8)(sin 29^{\circ})=218.6 N[/tex]
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i need help with question 8 and 9
8) The height of the shelf is 2.04 m
9) The gravitational potential energy is 100 J
Explanation:
8)
The gravitational potential energy of an object is given by:
[tex]PE=mgh[/tex]
where
m is the mass of the object
g is the acceleration of gravity
h is the heigth of the object, relative to the ground
For the object in this problem, we have
m = 10 kg
[tex]g=9.8 m/s^2[/tex]
And we know that
PE = 200 J
Therefore we can re-arrange the formula to solve for h, the heigth of the object:
[tex]h=\frac{PE}{mg}=\frac{200}{(10)(9.8)}=2.04 m[/tex]
9)
As before, the gravitational potential energy of the object is given by:
[tex]PE=mgh[/tex]
where in this case, we have:
m = 10 kg is the mass of the object
h = 2.04 m is the height of the object from the ground
While in this case, the acceleration of gravity on this planet is
[tex]g=4.9 m/s^2[/tex]
Substituting,
[tex]PE=(10)(4.9)(2.04)=100 J[/tex]
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Objects 1 and 2 attract each other with a gravitational force of 36.0 units. If the mass of Object 2 is tripled, then the new gravitational force will be _____ units.
Answer:
108N
Explanation:
According to law of gravitation which states that "the force
of attraction between two masses in a gravitational field is directly proportional to the product of their masses and inversely proportional to the square of their distance between them.
Mathematically, F = Gm1m2/r²
Where;
m1 and m2 are the masses of the object
G is the gravitational constant
r is the distance between the masses
If Objects 1 and 2 attract each other with a gravitational force of 36.0 units, we will have;
36 = Gm1m2/r²... (1)
If the mass of Object 2 is tripled, the gravitational force becomes
F = Gm1(3m2)/r²
F = 3Gm1m2/r²... (2)
Dividing equation 1 by 2, we will have;
36/F = {Gm1m2/r²}/3Gm1m2/r²
36/F = Gm1m2/r²×r²/3Gm1m2
36/F = 1/3
Cross multiplying we have
F = 36×3
F = 216N
Therefore, the gravitational force when the second object is tripled is 108N
Final answer:
The new gravitational force, when the mass of Object 2 is tripled and the distance between the objects remains the same, would be 108.0 units.
Explanation:
If the mass of Object 2 is tripled, according to the law of universal gravitation, the gravitational force between two objects is directly proportional to the product of their masses. The gravitational force can be described by the formula:
F = G \( \frac{m1 \cdot m2}{d²} \)
Where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the objects, and d is the distance between the centers of the two objects.
In the student's question, if the mass of Object 2 is tripled, and the distance remains unchanged, the new gravitational force would be:
Original force: 36.0 units
New force: 36.0 units \( \times 3\)
New force: 108.0 units
This is because tripling the mass of Object 2 causes the force to triple, as the force is directly proportional to the product of the two masses.
A safe is hurled down from the top of a 1.3 x 102 m
building at a speed of 11.0 m/s. What is its velocity as
it hits the ground?
The final velocity is 49.7 m/s downward
Explanation:
The motion of the object is a free fall motion (affected only by the force of gravity), so the object accelerates downward with a constant acceleration of [tex]g=9.8 m/s^2[/tex] (acceleration of gravity). Therefore, we can use the following suvat equation:
[tex]v^2 -u^2 = 2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
Taking downward as positive direction, we have
u = 11.0 m/s
[tex]a=g=9.8 m/s^2[/tex]
[tex]s=1.3\cdot 10^2 m = 130 m[/tex] (height of the building)
Solving for v, we find the final velocity as the object hits the ground:
[tex]v=\sqrt{u^2+2as}=\sqrt{11.0^2+2(9.8)(120)}=49.7 m/s[/tex]
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A hiker walks 9.4 miles at an angle of 60° south of west. Find the west and south components of the walk. Round your answers to the nearest tenth.
Ax = miles
Answer:
The west axis component of walk is, A = 5 miles
The east axis component of walk is, B = 8 miles
Explanation:
Given data,
The displacement of hiker south of west, R = 9.4 miles
The angle formed south of west, Ф = 60°
The vector components along,
the west axis is
A = R cosФ
A = 9.4 x cos 60
A = 4.7 miles
A = 5 miles
The west axis component of walk is, A = 5 miles
the south axis is
B = R sinФ
B = 9.4 sin 60
B = 8.14 miles
B = 8 miles
The east axis component of walk is, B = 8 miles
Answer:
Ax= -4.7
Ay= -8.1
Explanation:
Which sequence of moon phases is correct? .
new moon, waxing crescent, full moon, waning gibbous
first quarter, new moon, full moon, third quarter
waning crescent, full moon, waxing crescent, new moon
full moon, waxing crescent, waning crescent, new moon
Answer:
d
Explanation:
this is the order of the moons ( you can look it up too)
The correct sequence of moon phases is: new moon, waxing crescent, first quarter, waxing gibbous, full moon, waning gibbous, third quarter, waning crescent. The cycle follows the moon as it appears illuminated from Earth.
Explanation:The correct sequence of the moon phases is: new moon, waxing crescent, first quarter, waxing gibbous, full moon, waning gibbous, third quarter, and waning crescent. The cycle starts with the new moon when the moon is not visible from Earth. The moon then enters the waxing crescent phase when a thin sliver of the moon becomes visible. The first quarter is when half of the moon is illuminated. This is followed by the waxing gibbous phase when more than half but not fully illuminated. The full moon phase is when the entire face of the moon is illuminated. The moon then begins to wane and less of it is illuminated each night. Waning gibbous phase comes first, followed by the third quarter phase when half of the moon is illuminated. The cycle ends with the waning crescent phase when again only a sliver of the moon is visible before transitioning back to a new moon.
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Which of the following is the best thermal insulator?
A.) Air
B.) Water
C.) Metal
D.) Stone
Please help I’m torn between A and B. I’ve asked many and people say A, but I asked my science teacher and she said B. And also I’ve researched and on answers.com also says Water is the better insulator..but idk I’m conflicted! APEX
Answer:
you're right it is b....
Answer:
A.) Air
Explanation:
Ap-ex
What is the quantity of heat energy required to convert 10g cube of ice at -30oC to steam at 120oC. also draw a graph of temperature against energy to show this process.
Answer:
The amount of energy required is 31.1692 kJ .
Explanation:
The transitions of water are as follows,
(243K ice to 273K ice to 273K water to 373k water to 373K steam to 393K steam)
The following required data is,
specific heat capacity of ice= 2.1 kJ/kg
specific heat capacity of water= 4.2 kJ/kg
specific heat capacity of ice= 1.996 kJ/kg
specific latent heat of fusion=334 kJ/kg
specific latent heat of vapourisation = 2260 kJ/kg
FORMULAS:-
temperature change=mc(T2-T1)
phase transistion = mL,
where, m=mass , c=specific heat capacity ,L = latent heat of fusion or vapourisation ,(T2-T1)= temparature change
Thus the total amount of heat is,
=mc(T4-T3) + mL + mc(T3-T2) + mL + mc(T2-T1)
=[tex]10(10^{-3} )(2.1)(30)+10(10^{-3} )(334)+10(10^{-3} )(100)(4.2)+10(10^{-3} )(2260) +10(10^{-3} )(20)(1.996)[/tex]
=(0.3)(2.1) + (3.34) + (4.2) + (22.6) + (0.2)(1.996)
=31.1692 kJ.
Jordan drove from his home to his new college. He drove 150 miles in 2.5 hours. What was his average speed, in miles per hour
Answer:
60 m/h
Explanation:
[tex]v = x \div t[/tex]
so v = 150 / 2.5 = 60 m/h
A lock clicks 88 times in 22 seconds. Calculate the frequency and period of the clock
1) The frequency of the clock is 4 Hz
2) The period of the clock is 0.25 s
Explanation:
1)
In a periodic motion, the frequency of the motion is equal to the number of complete cycles per second.
Mathematically:
[tex]f=\frac{N}{t}[/tex]
f is the frequency
N is the number of cycles completed in a time t
For the clock in this problem, we have
N = 88 (number of cycles)
t = 22 s (time interval)
Substituting,
[tex]f=\frac{88}{22}=4 Hz[/tex]
2)
The period of a periodic motion is the time taken for one complete oscillation to occur.
Mathematically, the period is equivalent to the reciprocal of the frequency:
[tex]T=\frac{1}{f}[/tex]
where
T is the period
f is the frequency
Here we have found
f = 4 Hz
So, the period of the clock is
[tex]T=\frac{1}{4}=0.25 s[/tex]
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The frequency and period of the clock is 4Hz and 0.25s respectively.
Given the data in the question;
Number of cycles; [tex]N = 88[/tex]
Time interval; [tex]t = 22s[/tex]
Frequency; [tex]f = \ ?[/tex]
Period; [tex]T = \ ?[/tex]
Frequency is the number of complete cycles occurring per period of time.
Frequency; [tex]f = \frac{N}{t}[/tex]
We substitute in our given values
[tex]f = \frac{88}{22s} \\\\f = 4s^{-1}\\\\f = 4Hz[/tex]
Therefore, the frequency of the clock is 4Hz
Frequency [tex]f[/tex] is also the reciprocal of the period [tex]T[/tex]:
Hence, [tex]T = \frac{1}{f}[/tex]
We substitute in our values
[tex]T = \frac{1}{4s^{-1}} \\\\T = 0.25s[/tex]
Therefore, the period of the clock is 0.25s
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A group of students were testing different insulators. They used three metal cans, one wrapped with bubble wrap, a second with a paper towel, and third unwrapped. Equal amounts of hot water were poured into each can and the temperature was noted at definite time intervals. The data is shown in the table.
From the data, they concluded that bubble wrap was the best insulating material. What is the weakness in the conclusion?
A) It is the better of two insulators only; it is not the best insulator.
B) The experiment should have been continued till the temperatures of the cans reached 0°C.
C) The experiment must be repeated at least three times before this conclusion can be drawn.
D) The data on the can without insulator is irrelevant and distracts from the main idea of the experiment.
Answer:
A)
Explanation:
The insulator is a material that creates a barrier for the heat transferred, maintaining the temperature of the system almost unaltered. To know what is the best insulator, the experiment needs to be done with an unwrapped can, so that is possible to know how much heat the can be lost, thus letter "d" is incorrect.
The temperature of the water would not achieve 0°C, but the ambient temperature, being in thermal equilibrium, so the letter "b" is also incorrect.
By the data given is already notice the insulator power, because the temperature decreases faster with the paper towel, thus it's not necessary to repeat the experiment only to know which one is better, so the letter "c" is incorrect.
But, it's not possible to affirm that the bubble wrap is the best insulating material, because exists a lot off insulating material that wasn't tested. Besides, the insulation depends on the thickness of the material.
Answer:
A
Explanation:
The term “best” means that there is nothing better. The student cannot conclude that bubble wrap is the best insulator after having tested only two insulating materials. It is the better of two insulators only; it is not the best insulator.
2. A car is proceeding at a speed of 14.0 m/s when it collidds with a stationary car in front of it.
During the collision, the first car moves a distance of 3.000 m as it comes tot a stop. The driver
is wearing her seat belt, so she remains in her seat during the collision. If the driver's mass is
52.0 kg, how much force does the belt exert on her during the collision? Neglect any friction
between the driver and the seat.
The force exerted on her is 1700 N
Explanation:
First of all, we start by calculating the acceleration of the car. Since its motion is a uniformly accelerated motion, we can use the following suvat equation:
[tex]v^2-u^2 = 2as[/tex]
where
v = 0 is the final velocity of the car (which comes to a stop)
u = 14.0 m/s is the initial velocity
a is the acceleration
s = 3.0 m is the distance covered by the car during the collision
Solving for a,
[tex]a=\frac{v^2-u^2}{2s}=\frac{0-14^2}{2(3)}=-32.7 m/s^2[/tex]
And the negative sign means it is a deceleration.
Now we can find the force exerted on the passenger during the collision, using Newton's second law:
[tex]F=ma[/tex]
where
F is the force
m = 52.0 kg is the mass of the passenger
[tex]a=32.7 m/s^2[/tex] is the acceleration (we ignore the sign since we are only interested in the magnitude of the force)
Substituting,
[tex]F=(52.0)(32.7)=1700 N[/tex]
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The diagram shows a student throwing a baseball horizontally at 25 meters per second from a cliff 45 meters above the level ground
Approximately how far from the base of the cliff does the ball hit the ground
The horizontal distance covered by the ball is 75.8 m
Explanation:
The motion of the ball in this problem is a projectile motion, so it follows a parabolic path which consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
First of all, we consider the vertical motion to find the time of flight of the ball. Using the suvat equation:
[tex]s=ut+\frac{1}{2}gt^2[/tex]
where
s = 45 m is the vertical displacement of the ball
t is the time of flight
u = 0 is the initial vertical velocity of the ball
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
Solving for t,
[tex]t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(45)}{9.8}}=3.03 s[/tex]
Now we know that the ball moves horizontally with a constant velocity of
[tex]v_x = 25 m/s[/tex]
So, the horizontal distance covered by the ball during its flight is
[tex]d=v_x t = (25)(3.03)=75.8 m[/tex]
So the ball lands 75.8 m far from the base of the cliff.
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The ball hits the ground approximately 75.30 meters away from the base of the cliff.
Explanation:
Since the baseball is thrown horizontally, the initial vertical velocity will be zero. The time it takes for the ball to fall can be found using the equation h = (gt^2)/2, where h is the vertical displacement and g is the acceleration due to gravity. Plugging in the values, we get t = sqrt(2h/g). The horizontal distance can be found using the equation d = v*t, where d is the distance and v is the horizontal velocity. Plugging in the values, we get d = v*t. Calculating the values, t = sqrt(2*45/9.8) = 3.01 seconds and d = 25 * 3.01 = 75.30 meters.
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FASTTTTTTTTTTTTTTT PLEASEEEEEEEEEEEEE ITS 2O POINTS
The graph below shows a velocity vs. time graph. A graph with horizontal axis time (seconds) and vertical axis velocity (meters per second). A straight line runs from 0 seconds 10 meters per second to 5 seconds 2 meters per second. Which graph would match the same type of movement that the graph shows? A graph with horizontal axis time (seconds) and vertical axis position (meters). A straight line runs from 0 seconds 0 meters upward. A graph with horizontal axis time (seconds) and vertical axis position (meters). A concave line runs from 0 seconds 0 meters upward. A graph with horizontal axis time (seconds) and vertical axis position (meters). A straight line runs from 0 seconds some positive number meters upward downward to some positive number of seconds 0 meters. A graph with horizontal axis time (seconds) and vertical axis position (meters). A convex line runs downward from 0 seconds some positive number of meters to some positive number of seconds 0 meters.
Answer is " A convex line runs downward from 0 seconds some positive number of meters to some positive number of seconds 0 meters. "
Explanation:
The figure shows Velocity vs Time Graph.
At t1=0, u=10m/s
At t2=5, v=2m/s
Let's calculated the acceleration
[tex]a=\frac{v-u}{t2-t1}[/tex]
[tex]a=\frac{2-10}{5-0}[/tex]
[tex]a=\frac{-8}{5}[/tex]
The equation of distance is given by
[tex]d=ut+\frac{a}{2} t^{2}[/tex]
[tex]d=(10)t+\frac{\frac{-8}{5}}{2} t^{2}[/tex]
[tex]d=10t+\frac{-8}{10} t^{2}[/tex]
[tex]d=10t+\frac{-4}{5} t^{2}[/tex]
[tex]5d=50t-4t^{2}[/tex]
From here, You can plot the graph of above equation by taking several points.
When t=0,
[tex]5d=50(0)-4(0)^{2} = 0m[/tex]
When t=5,
[tex]5d=50(5)-4(5)^{2}[/tex]
[tex]5d=250-100[/tex]
[tex]5d=150[/tex]
[tex]d=30m[/tex]
Similarly,
When t= 3s d=22.8m
When t=4s d=27.2m
Figure shown is graph of Distance vs Time.
Thus, answer is " A convex line runs downward from 0 seconds some positive number of meters to some positive number of seconds 0 meters. "
Answer:
Your answer is D) A graph with horizontal axis time (seconds) and vertical axis position (meters). A convex line runs downward from 0 seconds some positive number of meters to some positive number of seconds 0 meters.
Explanation:
A box is pushed 40 m by a mover. The amount of work done was 2,240 j. How much force was exerted on the box
The force exerted on the box is 56 N
Explanation:
The work done by a force on an object is given by
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force
d is the displacement of the object
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
For the box in this problem, we have:
W = 2240 J is the work done
d = 40 m is the displacement of the box
Assuming that the force is parallel to the displacement, [tex]\theta=0[/tex]
Solving the equation for F, we find the force exerted on the box:
[tex]F=\frac{W}{d cos \theta}=\frac{2240}{(40)(cos 0)}=56 N[/tex]
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