Answer:
Complete question: A point charge Q is held at a distance r from the center of a dipole that consists of two charges ±qseparated by a distance s. The dipole is initially oriented so that the charge Q is located in the plane that bisects the dipole. Assume that r≫s. Immediately after the dipole is released,
what is the magnitude of the force on the dipole?
In the space provided, enter the factor that multiplies 1ϵ0 in your answer. Express this factor in terms of q, Q, s, π, and r.
what is the magnitude of the torque on the dipole?
in the space provided, enter the factor that multiplies 1ϵ0 in your answer. Express this factor in terms of q, Q, s, π, and r.
Answer: The magnitude of he electric field of the dipole = E = Kqs/r³
the magnitude of the torque on the dipole is Z = (qs) (KQ/r²) = 1/ϵ₀ (qQs)/4πr³)
Explanation:
From the given question,
We find the magnitude of the force on the dipole.
E= the electric field
ϵ₀= permittivity of free space is
q = magnitude of each charge of the dipole
The dipole movement = p =qs
The electric field of the dipole = E = Kqs/r³
Then
F=QE ⇒ F = Q (Kqs)/r³ ⇒ KqQs/r³
= 1/ϵ
₀ ( qQs)/4πr³)
The electric field due to Q is E = KQ/r²
The next step is to find the magnitude of the torque on the dipole
The torque is denoted by Z =PE sign 90
Z = (qs) (KQ/r²) = 1/ϵ
₀ (qQs)/4πr³)
For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 20 N acts on a certain object, the acceleration of the object is 4 m/s^2 . If the force is changed to 30 N, what will be the acceleration of the object?
Answer:
6 m/s²
Explanation:
We know that the force acting on an object varies directly with the acceleration. The force, F, and acceleration, a, are related by:
F = m * a
Where m is the mass of the object
We then need to find the mass of the object before we can find its acceleration when the force is 30 m/s².
Therefore, when the force is 20 N and the acceleration is 4 m/s²:
20 = m * 4
=> m = 20/4 = 5 kg
The mass of the object is 5 kg. Hence, we can find the acceleration of the object when the force is 30 N
30 = 5 * a
=> a = 30/5 = 6 m/s²
The acceleration of the object is 6 m/s²
Answer:
6m/s²
Explanation:
According to Newton's second law
Force F acting on an object varies directly with the object's acceleration a. Mathematically it is expressed as
F = ma where;
m is the mass of the object
F is the applied force
a is the acceleration
Let m be constant
m = F/a
If a force of 20 N acts on a certain object with an acceleration of 4m/s²
m = 20/4
m = 5kg
If the force is changed to 30 N, its new acceleration can be gotten using the previous formula.
F = ma
a = F/m
a = 30/5 (since mass is kept constant)
a = 6m/s²
A 14kg Box rests on a frictionless surface. It is attached to a 8kg weight by a thin wire that passes over a frictionless pulley. The pulley is a uniform solid disk of mass 3kg and diameter 1m. After the box is released find (a) the tension in the wire on both sides of the pulley, (b) the acceleration of the box, and (c) the horizontal and vertical components of the force on the pulley
Answer:
(a) Tension on both side of wire
[tex]T_1=46.706 N[/tex]
[tex]T_2=51.710 N[/tex]
(b) acceleration of the Box
[tex]a = 3.336 \frac{m}{sec^2}[/tex]
(c) The horizontal and vertical components
Horizontal component [tex]T_1=46.706 N[/tex]
Vertical Component =130.19 N
Explanation:
Refer attached figure for details.
[tex]T_1\ \&\ T_2\ are\ tensions\ in\ the\ string\ and\ a\ is\ the\ acceleration\ of\ the\ masses.[/tex]
Applying Newton's 2 law of motion for 14 kg block in horizontal direction
[tex]T_1 = 14\ a[/tex]-----------(i)
Similarly, applying Newton's 2 law of motion for 8 kg block in vertical direction
[tex]8 g - T_2 =8 a[/tex]-----(ii)
Consider the case of pulley,
[tex]\tau_e_x_t= I\alpha--------(iii)\\\\Where,\\\tau_e_x_t =Torque\ acting\ on\ the\ pulley\\I=moment\ of\ inertia\ of\ pulley\\\alpha= angular\ acceleration[/tex]
where,
[tex]I= \frac{MR^2}{2} (for\ pulley\ disk)[/tex]
[tex]I=\frac{3\cdot0.5^2}{2} =0.375\ kgm^2[/tex] (since mass of the pulley = 3 kg & Radius = 0.5 m)
&[tex]\tau_e_x_t= Net\ force \cdot Distance\ from\ application\ point[/tex]
Hence [tex]\tau_e_x_t = (T_2-T_1) \cdot \frac{1}{2} = 0.375\cdot\alpha[/tex]
[tex]T_2-T_1=0.75\cdot\alpha[/tex]--------(iv)
Relation between linear acceleration (a) and angular acceleration (α) is as follows,
[tex]a = R\alpha=0.5\cdot\alpha \ (R\ is \ radius\ of \ pulley)[/tex]
[tex]\alpha=2a[/tex]--------------------(v)
Putting the value of (v) in to (iv)
[tex]T_2 -T_1= 1.5 a[/tex]---------(vi)
adding equation (i),(ii) & (vi) gives
8g =22 a + 1.5 a
[tex]a = 3.336 \frac{m}{sec^2}[/tex]
now putting the value of a in equation (i) & (ii) we get
[tex]T_1=46.706 N[/tex]
[tex]T_2=46.706 +1.5 \cdot 3.336[/tex] = 51.710 N
(a) Hence Tension on both side of wire
[tex]T_1=46.706 N[/tex]
[tex]T_2=51.710 N[/tex]
(b) acceleration of the Box
[tex]a = 3.336 \frac{m}{sec^2}[/tex]
(c) The horizontal and vertical components
Horizontal component [tex]T_1=46.706 N[/tex]
Vertical Component = [tex]T_2+8\cdot g[/tex] =51.710 + 8 x 9.81 =130.19 N
Answer:
Tension, T1 = 46.2 N and T2 = 52 N, where as acceleration = 3.3 ms^-2.
Forces on the pulley are 46.2 N , 81.4 N horizontal and vertical
respectively.
Explanation:
Given:
Mass of the box on rest,[tex]m_1[/tex] = 14 kg
Mass of the attached box,[tex]m_2[/tex] = 8 kg
Mass of the pulley, [tex]m_3[/tex] = 3 kg
Diameter of the pulley, [tex]d[/tex] = 1 m
Radius of the pulley, [tex]r[/tex] = 0.5 m
Here we will be using the concept of net force ([tex]F_n_e_t[/tex]),net torque ([tex]\tau_n_e_t[/tex]) and acceleration of the pulley .
A FBD is attached with.
Lets find the tension on the wire using Fnet.
⇒ [tex]T_1=m_1(a)[/tex] ...for m1
⇒ [tex]m_2g-T_2=m_2(a)[/tex] can be written as [tex]T_2=m_2g-m_2(a)[/tex] ...for m2
Considering clockwise torque as negative and anticlockwise torque as positive.
Moment of inertia (I) of the disk/pulley = [tex]\frac{m_3r^2}{2}[/tex] and [tex]\alpha=\frac{a}{r}[/tex] .
Now using net torque on the pulley we can say that.
⇒ [tex](T_2-T_1)r=I\alpha[/tex]
⇒ [tex](T_2-T_1)r=\frac{m_3r^2}{2}\times \frac{a}{r}[/tex]
⇒ [tex](T_2-T_1)=\frac{m_3a}{2}[/tex]
⇒ Plugging T1 and T2 .
⇒ [tex]m_2g-m_2a-m_1a=\frac{m_3a}{2}[/tex]
⇒ Isolating a from the rest.
⇒ [tex]m_2g=\frac{m_3a}{2}+m_2a+m_1a[/tex]
⇒ [tex]m_2g=a\ [\frac{m_3}{2}+m_2+m_1][/tex]
⇒ [tex]\frac{m_2g}{\frac{m_3}{2} +m_2+m_1} =a[/tex]
⇒ Plugging the numeric value
⇒ [tex]\frac{(8\times 9.8)}{(\frac{3}{2} +8+14)} =a[/tex]
⇒ [tex]3.3 =a[/tex]
⇒ Acceleration = 3.3 [tex]ms^-^2[/tex]
So,
(a).
Tension in the wire
⇒ [tex]T_1=m_1(a)=14\times 3.3 =46.2\ N[/tex]
⇒ [tex]T_2=m_2g-m_2(a)=8(9.8-3.3)=52\ N[/tex]
(b).
The acceleration of the box is 3.3 ms^-2.
(c).
Forces on the pulley.
Horizontal force, [tex]P_H[/tex] = [tex]T_1[/tex] = [tex]46.2\ N[/tex]
Vertical force,[tex]P_V[/tex] = [tex]T_2+m_3g[/tex] = [tex]52+3(9.8)[/tex] = [tex]81.4\ N[/tex]
The values are as follows:
Tension as T1 = 46.2 N and T2 = 52 N ,where as acceleration =3.3 ms^-2.
Forces on the pulley are 46.2 N , 81.4 N horizontal and vertical
respectively.
What steps are involved in converting potential energy to kinetic energy
Answer:
Decreasing in altitude and increasing in velocity
Explanation:
The formula for potential energy is:
[tex]E_p = mgh[/tex]
where m is mass, g is constant gravitational energy and h is the potential altitude.
The formula for kinetic energy is:
[tex]E_k = mv^2/2[/tex]
where v is the velocity
Since m,g are constant, to convert from potential energy to kinetic energy, h must decreases while v increases. For example dropping an object from a height.
Answer:
Explanation:
Atractive forces tries to stop objects when they try to escape of the influence of these forces. Examples of this situation are the gravitational force and electric force.
When the object loses speed, its speed is decreasing, that is, its kinetic energy is decreasing, because the kinetic energy depends on speed:
[tex]E_k=\frac{1}{2}mv^2[/tex]
this lost of kinetic energy is equilibrated by the increase of the potential energy generated by the atractive force.
Because of this dynamic between the kinetic energy and the potential energy, the total mechanical energy of the object is conserved.
An aircraft as loaded weighs 4,954 pounds at a CG of 30.5 inches. The CG range is 32.0 inches to 42.1 inches. Find the minimum weight of the ballast necessary to bring the CG within the CG range. The ballast arm is 162 inches.
Answer:
57.16
Explanation:
The minimum weight of the ballast required to bring the CG of the aircraft within the given range is approximately 15.2 lbs. This is calculated using the weight of the aircraft, the distances the CG needs to move and the distance from the CG to the location where the ballast is placed.
Explanation:The subject matter of this problem is physics, specifically dealing with the concept of Centres of Gravity (CG). In order to find the minimum weight of the ballast required to bring the CG within the given CG range, we first need to establish how far the current CG is from the lower limit of the range. That is 32.0 - 30.5 = 1.5 inches. We can assume that the weight required to move the CG 1 inch can be found using the formula: (Weight of aircraft X Distance CG needs to move) / Distance from CG to ballast. So, in this case, the minimum ballast weight will be: (4954 lbs * 1.5 inches) / (162 inches - 30.5 inches). Carrying out the calculations, this gives us a ballast weight of approximately 15.2 lbs.
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A student performs a reaction twice. In the second trial, he increases the temperature of the reaction and notes that the reaction happens more quickly. The student concludes that this means the reaction was endothermic. What is wrong with the student's reasoning?
Higher temperature increases reaction rates for both endothermic and exothermic reactions.
An endothermic reaction would not speed up at higher temperatures.
Temperature does not affect the rate of a reaction.
The higher temperature in the second trial actually lowered the activation energy of the reaction.
Answer: higher temperature increases reaction rates for both endothermic and exothermic reactions
Explanation: i took the test
The wrong statement with the student's reasoning is Higher temperature increases reaction rates for both endothermic and exothermic reactions. Hence option A is correct.
What are endothermic and exothermic reactions?
When the reactant absorbs heat energy from the surroundings to form products is called an endothermic reaction. When the heat is absorbed from the surroundings, the system remains cooler and the enthalpy of the system increases.
When the energy is released in the form of heat to form the product is called an exothermic reaction. In this reaction, the temperature of the substance increases due to the release of heat, and the enthalpy of the system decreases.
If the temperature increases the reaction rates increase in the exothermic reaction and it decreases in the endothermic reaction. Hence, increases in temperature increases the reaction rates for both endothermic and exothermic reactions is wrong.
Hence, the ideal solution is A.
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Help ASAP
Answer question 3 please!!!
Answer:
the answer is ture
Explanation:
because the energy substances must absorb in order to change from liquid to gas
If you push down the plunger of a bicycle pump the vhamber's volume is decreased. When that happens pressure in the chamber increases and the air then rushes out the pump and into your flat tire. What gas law does this represent?
Answer:
Boyle's Law
Explanation:
Robert Boyle in his experiment explained the relationship between the volume and the pressure of a gas. In his experiments, he discovered that the volume of a gas is inversely proportional to the pressure at constant temperature. This implies that as the volume of the gas increase, the pressure decreases and as the volume of the gas decrease, the pressure will increase.
Now applying this concenpt to the the plunger of a bicycle pump, you will discover that as the pressure of in the plunger increase, the volume of air inside the chamber is decreasing as it is send out to pump the flat tyre. This clearly indicates inverse proportionality between pressure and volume as explained by Boyle's law.
Therefore, the plunger of a bicycle pump clearly indicates Boyle's law in action.
The operation of a bicycle pump illustrates Boyle's Law. This law states that in a closed system at constant temperature, the volume and pressure of a gas are inversely proportional - as one increases, the other decreases.
Explanation:The situation you described is an application of Boyle's Law, a concept in physics. Boyle's Law states that the pressure and volume of a gas have an inverse relationship when held at a constant temperature. This means that as the volume of gas decreases, like when you push down the plunger of a bicycle pump, the pressure increases.
When the plunger is pushed down, the volume inside the pump decreases, thereby increasing the pressure. This high-pressure air then moves from an area of high pressure (inside the pump) to an area of low pressure (the flat tire), resulting in air being pumped into the tire.
A practical example aiding understanding is a deflated tire. As we start pumping air into it, its volume first increases with not much increase in pressure. However, once the tire is filled to a point where the walls resist further expansion, pressure increases as more air is pumped in. Therefore, Boyle's Law explains the mechanics of a bicycle pump and similar systems pretty well.
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Hurricanes can involve winds in excess of 100 km/h at the outer edge. Make a crude estimate of the energy of such a hurricane, approximating it as a rigidly rotating uniform cylinder of air (density 1.3 kg/m3) of radius 88 km and height 4.4 km .
Answer:
[tex]2.7\cdot 10^{16} J[/tex]
Explanation:
We can approximate the hurricane as a rotating uniform cylinder, so its energy is the rotational kinetic energy, given by:
[tex]E=\frac{1}{2}I\omega^2[/tex] (1)
where
I is the moment of inertia
[tex]\omega[/tex] is the angular velocity
The moment of inertia of a cylinder rotating about its axis is
[tex]I=\frac{1}{2}MR^2[/tex]
where
M is the mass
R is the radius
So formula (1) can be written as
[tex]E=\frac{1}{2}(\frac{1}{2}MR^2)\omega^2=\frac{1}{4}MR^2\omega^2[/tex] (2)
For an object in rotation, the linear speed at the edge is related to the angular velocity by
[tex]v=\omega R[/tex]
So we can rewrite (2) as
[tex]E=\frac{1}{4}Mv^2[/tex]
where we have:
[tex]v=100 km/h = 27.8 m/s[/tex] is the speed at the edge of the hurricane
We have to calculate the mass of the cylinder. We have:
[tex]R=88 km = 88,000 m[/tex] (radius)
[tex]h=4.4 km = 4400 m[/tex] (height)
So the volume is
[tex]V=\pi R^2 h = \pi (88,000)^2 (4400)=1.07\cdot 10^{14} m^3[/tex]
The density is
[tex]\rho = 1.3 kg/m^3[/tex]
So the mass is
[tex]M=\rho V=(1.3)(1.07\cdot 10^{14})=1.39\cdot 10^{14} kg[/tex]
Therefore, the energy is
[tex]E=\frac{1}{4}(1.39\cdot 10^{14})(27.8)^2=2.7\cdot 10^{16} J[/tex]
Question 10 (2 points)
Formula
TK = Tc + 273
Oxygen boils at 90.0 Kelvin. What is the temperature in degrees Celsius?
Units are already included (please just type in the number)
***Round your answer to the nearest whole number ***
**If your answer is negative be sure to include a dash like this -
Blank 1:
Question 11 (2 points)
the answer is -183 degree celcius
Answer:
90= C+273
C=273-90= - 183
Gears can be used to change the direction of a motor output from clock wise to counter clockwise
True or false
Answer:
True
Explanation:
This can be done when the output gear is rotating in a counterclockwise direction. The initial direction of the clockwise gear changes when it comes in contact with the counter clockwise rotating gear. This will thus cause the motor to change its direction due to the counter clockwise rotating gear.
A 2kg book is moved from a shelf that is 2m off the ground to a shelf that is 1.5m off the ground, what is it’s change in gravitational potential energy
The change in gravitational potential energy of the book is 9.81 J.
What is it’s change in gravitational potential energy?The change in gravitational potential energy is calculated as follows:
ΔGPE = m * g * Δh
where:
ΔGPE is the change in gravitational potential energy (in joules)m is the mass of the object (in kilograms)g is the acceleration due to gravity (9.81 m/s²)Δh is the change in height (in meters)In this case, the mass of the book is 2 kg, the acceleration due to gravity is 9.81 m/s², and the change in height is 0.5 m (2 m - 1.5 m).
Therefore, the change in gravitational potential energy is:
ΔGPE = 2 kg * 9.81 m/s² * 0.5 m = 9.81 J
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A trough is filled with a liquid of density 835 kg/m3. The ends of the trough are equilateral triangles with sides 4 m long and vertex at the bottom. Find the hydrostatic force on one end of the trough. (Use 9.8 m/s2 for the acceleration due to gravity.)
The hydrostatic force on one end of the trough can be found using the formula F = pghA, where p is the density of the liquid, g is the acceleration due to gravity, h is the height of the liquid, and A is the area of the end of the trough. In this case, the ends of the trough are equilateral triangles with sides 4m long.
Explanation:To find the hydrostatic force on one end of the trough, we can use the formula F = pghA, where F is the force, p is the density of the liquid, g is the acceleration due to gravity, h is the height of the liquid, and A is the area of the end of the trough. Since the ends of the trough are equilateral triangles, each side has a length of 4m. The area of an equilateral triangle is given by A = sqrt(3)/4 * s^2, where s is the length of the side. In this case, A = sqrt(3)/4 * (4m)^2 = 4sqrt(3)m^2. Plugging in the values, we have F = (835kg/m^3)*(9.8m/s^2)*h*(4sqrt(3)m^2).
The presence of a uniform magnetic field may be detected by using a
Answer:
Magnetic compass
Explanation:
A magnetic field is a field that describes the magnetic effect of electric charges in a relative motion.
Magnetic field allows magnets to interact without contact. The principle involved in the function of the compass is that a magnetic field exerts a force on any moving charge and can be measured and detected by this effect.
Answer:
Magnetic compass
Explanation:
The magnetic compass is the most familiar compass type. It functions as a pointer to "magnetic north", the local magnetic meridian, because the magnetized needle at its heart aligns itself with the horizontal component of the Earth's magnetic field
Compasses are mainly used in navigation to find direction on the earth. This works because the Earth itself has a magnetic field which is similar to that of a bar magnet (see the picture below). The compass needle aligns with the Earth's magnetic field direction and points north-south.
How much energy must be transferred out of the system as heat q to lower its temperature to 0∘c? express your answer numerically in joules?
The energy transferred out of the system as heat is 3950 J, or in scientific notation, [tex]\rm \( 3.95 \times 10^3 \, \text{J} \)[/tex]
The amount of energy q required to change the temperature of a substance can be calculated using the formula:
[tex]\rm \[ q = m \cdot C \cdot \Delta T \][/tex]
Where:
m is the mass of the substance
C is the specific heat capacity of the substance
[tex]\rm\( \Delta T \)[/tex] is the change in temperature
Given that the change in temperature is from the system's current temperature to [tex]\( 0^\circ \text{C} \)[/tex], which is -T in Kelvin, and the specific heat capacity C is typically given in [tex]\rm \( \text{J/g}^\circ \text{C} \)[/tex], we can express the formula as:
[tex]\rm \[ q = m \cdot C \cdot (-T) \][/tex]
Given that the energy is to be expressed in joules, we need to use the SI unit for mass (kilograms) and convert the specific heat capacity to [tex]\rm \( \text{J/kg}^\circ \text{C} \)[/tex]
The conversion factor from [tex]\rm \( \text{J/g}^\circ \text{C} \)[/tex] to [tex]\( \text{J/kg}^\circ \text{C} \)[/tex] is 1000 since [tex]\( 1 \, \text{g} = 0.001 \, \text{kg} \)[/tex]:
[tex]\rm \[ C_{\text{SI}} = C_{\text{g}} \cdot 1000 \][/tex]
Now, we can use the formula to calculate q.
Given:
m (mass of the substance) = [tex]\rm \( 4.70 \, \text{kg} \)[/tex] (assuming mass)
C (specific heat capacity) = [tex]\rm \( 4.18 \, \text{J/kg}^\circ \text{C} \)[/tex]
T (temperature change) = [tex]\rm \( 0^\circ \text{C} - 20^\circ \text{C} = -20^\circ \text{C} \)[/tex]
Substitute the values:
[tex]\rm \[ q = (4.70 \, \text{kg}) \cdot (4.18 \, \text{J/kg}^\circ \text{C}) \cdot (-20^\circ \text{C}) \]\\\\rm q = -3949.6 \, \text{J} \][/tex]
Since the answer is expected in kilojoules (kJ), convert the value from joules to kilojoules:
[tex]\rm \[ q = -3949.6 \, \text{J} \\= -3.9496 \, \text{kJ} \][/tex]
Now, express the result with the correct number of significant figures:
[tex]\rm \[ q = -3.95 \, \text{kJ} \][/tex]
Since the question asks for the energy transferred out of the system as heat, take the absolute value:
[tex]\rm \[ q_{\text{abs}} = 3.95 \, \text{kJ} \\= 3950 \, \text{J} \][/tex]
Therefore, the energy transferred out of the system as heat is 3950 J, or in scientific notation, [tex]\rm \( 3.95 \times 10^3 \, \text{J} \)[/tex]
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To calculate the energy transfer in joules, we need the specific heat capacity of the substance, its mass, and the initial temperature. The formula for this is q = mcΔT. Without these values, we cannot provide a specific numerical answer.
Explanation:To calculate how much energy needs to be transferred out of the system as heat in order to lower its temperature to 0°C, you would need more information. A key factor of this calculation is the specific heat capacity of the substance in the system, as well as its mass. The formula for heat transfer is q = mcΔT, where m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature. Without the values of m and c as well as the initial temperature, it is not possible to provide a numerical answer in joules.
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If 4,000J of energy is transferred and 2,500J is usefully stored, how much energy is wasted
If we do the simple equation of 4,000J subtracted by 2,500J we can easily see that the energy that wasn't useful or wasted is 1,500J
ANSWER = 1,500J
Answer:
4000J transfer and 2500J stored which means you have an energy produce power equals to 6500J. Therefore take 6500J and subtract it with 4000J transfer and there you left with 2500J. so the question is, how much energy is wasted? about 4000 of your energy is been transfer which means it moves out of the original source.
Explanation:
The process of removing heat from a place where it is not wanted and transferring that heat to a place where it makes little or no difference is known as ____.
A. cooling
B. refrigeration
C. defrosting
D. temperature balancing
The process of removing heat from a place where it is not wanted and transferring that heat to a place where it makes little or no difference is known as B) refrigeration.
What is a refrigeration machine accountable for soaking up warmth into the system from something medium is to be cooled?
The evaporator in a refrigeration device must be chillier than the refrigerated space for the purpose to take in heat. The boiling factor of a refrigerant ought to be low sufficient at atmospheric strain to preserve the machine stress above 0 PSIG when working at low temperatures.
The evaporator can be thought of as a “warmness sponge.” Vapor is more dense than liquid and, because the liquid refrigerant boils, it has a tendency to sink. The handiest area wherein the refrigerant vapor is superheated is within the evaporator.
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Use the drop-down menus to complete the sentences
Athin wire has resistance than a thick wire,
A short wire has resistance than a long wire
A warm wire has resistance than a cool wire,
Done
Answer:
A thin wire has a higher resistance than a thick wire
A short wire has a lower resistance than a long wire
A warm wire has a higher resistance than a cool wire
Explanation:
Here we have the formula for resistance by diameter given as follows
[tex]R = \frac{4 \times \rho \times l}{\pi } \times \frac{1}{d^2}[/tex]
Where:
R = Resistance
ρ = Resistivity of the wire
l = Length of the wire
d = Diameter of the wire
a. Therefore, since resistance is inversely proportional to diameter of the wire, a thin wire
A thin wire produces a higher resistance value than a thicker wire with larger diameter, d
b. Also as resistance is directly proportional to the length of the wire, a long wire has a higher resistance value than a short wire
c. The formula for resistance of a wire with temperature is as follows;
[tex]R_T = R_0 \times [1 + \alpha \times (T - T_{20})][/tex]
Where:
R₀ = Copper resistance at 20°
[tex]R_T[/tex] = Copper resistance at temperature T
T = Copper conductor temperature
T₂₀ = 20°
α = Copper coefficient of resistivity
Therefore, as the temperature increase, the resistance increases.
Answer:
thin wire has
✔ more
resistance than a thick wire.
A short wire has
✔ less
resistance than a long wire.
A warm wire has
✔ more
resistance than a cool wire.
Explanation:
Which types of securities has the lowest priority in a bankruptcy proceeding?
Answer:
Common stock
Explanation:
Common stock is also regarded to as shares in which dividends are paid to the holders according to how profitable the organization is.
Common stock is a type of equity security and it is also the least considered in the case of bankruptcy due to its variability and the probability of stockholders not getting anything because of the debtor being insolvent.
The windmill has 7 blades and rotates at an angular speed of 0.5 rad/s. The opening between successive blades is equal to the width of a blade. A golf ball of diameter 9.0 x 10⁻² m is just passing by one of the rotating blades at a minimum speed of 0.1 m/s.
What is the angular acceleration of the windmill?
Answer:
α = - 0.00148 rad/s^2
Explanation:
Given:-
- The number of blades, n = 7
- The angular speed of blades, w = 0.5 rad/s
- The diameter of golf ball, d = 9.0 x 10^-2 m
- The speed of the ball, v = 0.1 m/s
Find:-
What is the angular acceleration of the windmill?
Solution:-
- We first need to visualize the ball "just passing" through between two successive blades. First we will determine the time taken (t) for the golf-ball to just pass the blades i.e it travelled a distance equal to its diameter (d) with given speed (v) to avoid the blades.
d = v*t
t = d / v
t = 0.09 / 0.1
t = 0.9 s
- It takes t = 0.9s for the golf-ball to just pass the windmill. The same amount of time is taken by the windmill blade to cover an arc distance (s) that is equivalent to the diameter of the ball (d) which is also the width of empty space between two successive blades. The angle (θ) between each blade - denoting empty space can be determined by the seeing that all 7 blades are equally spaced in a circle. So:
θ = 2π / 2*n
θ = π / 7
θ = 0.44879 rads
- So the angular speed of the windmill blade (wf) when the ball passes through can be determined by the formula:
wf = θ / t
wf = 0.44879 / 0.9
wf = 0.49866 rad/s
- Now we will use the first rotational kinematics equation of motion with constant angular acceleration ( α ) as follows:
wf = wi + α*t
- Solve for ( α ) :
α = ( wf - wi ) / t
- Plug in the values and evaluate ( α ):
α = ( 0.49866 - 0.5 ) / 0.9
α = - 0.00148 rad/s^2
When light bends or changes direction what is happening
Answer:
When light travels from air into water, it slows down, causing it to change direction slightly. This change of direction is called refraction. When light enters a more dense substance (higher refractive index), it 'bends' more towards the normal line
During a 78-ms interval, a change in the current in a primary coil occurs. This change leads to the appearance of a 4.1-mA current in a nearby secondary coil. The secondary coil is part of a circuit in which the resistance is 12 Ω. The mutual inductance between the two coils is 3.2 mH. What is the change in the primary current?
Answer:
1.2 A
Explanation:
We are given that
Time, dt=78 ms=[tex]78\times 10^{-3}s[/tex]
[tex]1 ms=10^{-3} s[/tex]
[tex]I_s=4.1mA=4.1\times 10^{-3} A[/tex]
[tex]1 mA=10^{-3}A[/tex]
[tex]R=12\Omega[/tex]
[tex]M=3.2mH=3.2\times 10^{-3} H[/tex]
We have to find the change in the primary current.
[tex]V_s=I_sR=4.1\times 10^{-3}\times 12=49.2\times 10^{-3} V[/tex]
[tex]V_s=M\frac{dI}{dt}[/tex]
[tex]dI=\frac{V_sdt}{M}=\frac{49.2\times 10^{-3}\times 78\times 10^{-3}}{3.2\times 10^{-3}}[/tex]
[tex]dI=1.2 A[/tex]
In the summer, why does Alaska have longer days than Florida?
A. Alaska is a little bit closer to the Sun.
B. Alaska experiences much greater precession.
C. Alaska is a much larger area, so it receives more light.
D. Alaska is in the half of Earth that's illuminated longer by sunlight.
Answer:
D. Alaska is in the half of Earth that's illuminated longer by sunlight.
Explanation:
Alaska is closer to the north poll than Florida causing longer day during the summer because Alaska is facing the sun (roughly) 20 hours out of the day.
If the velocity of a pitched ball has a magnitude of 47.0 m/s and the batted ball's velocity is 50.5 m/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.
Answer:
The magnitude of change in momentum of the ball is [tex]97.5 m[/tex] and impulse is also [tex]97.5 m[/tex]
Explanation:
Given:
Velocity of a pitched ball [tex]v _{i} = 47[/tex] [tex]\frac{m}{s}[/tex]
Velocity of ball after impact [tex]v_{f} = -50.5[/tex] [tex]\frac{m}{s}[/tex]
From the formula of change in momentum,
[tex]\Delta P = m (v_{f} -v_{i} )[/tex]
Here mass is not given in question,
Mass of ball is [tex]m[/tex]
Change in momentum is given by,
[tex]\Delta P = m (-50.5 -47)[/tex]
[tex]\Delta P = -97.5 m[/tex]
Magnitude of change in momentum is
[tex]\Delta P = 97.5 m[/tex]
And impulse is given by
[tex]J = \Delta P[/tex]
[tex]J = -97.5 m[/tex]
So impulse and
Therefore, the magnitude of change in momentum of the ball is [tex]97.5 m[/tex] and impulse is also [tex]-97.5 m[/tex]
What is another term for a Lewis structure diagram?
Proton-electron ratio
Valence bond diagram
Bond pair visual
Electron-dot diagram
Final answer:
Another term for a Lewis structure diagram is an 'electron-dot diagram,' which represents the valence electrons of an atom as dots around the element's symbol and is used to visualize the bonding and non-bonding electrons in molecules.
Explanation:
Another term for a Lewis structure diagram is an electron-dot diagram. A Lewis structure diagram is a representation that shows the valence electrons of an atom as dots around the symbol of the element. The dots represent the number of valence electrons present in the atom and are arranged around the chemical symbol in a specific manner with a maximum of two dots on one side. For instance, the Lewis diagram for hydrogen would consist of the symbol 'H' with one dot next to it, representing its single valence electron.
The Lewis diagram is also referred to as a Lewis dot diagram and is used to visualize the bonding between atoms as well as non-bonding valence electrons. When atoms bond, the shared electrons are represented by lines, and lone pairs are depicted by dots surrounding the atoms. These diagrams help in predicting the shape of molecules and the arrangement of atoms.
A 4.00kg counterweight is attached to a light cord, which is would around a spool. The spool is a uniform solid cylinder of radius 8.00cm and mass 2.00kg. (a) What is the net torque on the system about the point O (the origin)? (b) When the counterweight has a speed v, the pulley has an angular speed ω=v/R. Determine the total angular momentum of the system about O. (c) Using the fact that τ=dL/dt and your result from (b), calculate the acceleration of the counterweight. slader
Answer:
Explanation:
Given that,
Mass of counterweight m= 4kg
Radius of spool cylinder
R = 8cm = 0.08m
Mass of spool
M = 2kg
The system about the axle of the pulley is under the torque applied by the cord. At rest, the tension in the cord is balanced by the counterweight T = mg. If we choose the rotation axle towards a certain ~z, we should have:
Then we have,
τ(net) = R~ × T~
τ(net) = R~•i × mg•j
τ(net) = Rmg• k
τ(net) = 0.08 ×4 × 9.81
τ(net) = 3.139 Nm •k
The magnitude of the net torque is 3.139Nm
b. Taking into account rotation of the pulley and translation of the counterweight, the total angular momentum of the system is:
L~ = R~ × m~v + I~ω
L = mRv + MR v
L = (m + M)Rv
L = (4 + 2) × 0.08
L = 0.48 Kg.m
C. τ =dL/dt
mgR = (M + m)R dv/ dt
mgR = (M + m)R • a
a =mg/(m + M)
a =(4 × 9.81)/(4+2)
a = 6.54 m/s
Answer:
a) τnet = 3.1392 N-m
b) L = (0.48 Kg-m)*v
c) a = 6.54 m/s²
Explanation:
Given
m = 4 Kg
R = 8 cm = 0.08 m
M = 2 Kg
a) τnet = ?
b) L = ?
c) a = ?
Solution
a) We use the formula
τnet = R*m*g*Sin 90°
τnet = 0.08 m*4 Kg*9.81 m/s²*(1)
τnet = 3.1392 N-m
b) We apply the equation
L= R*m*v + R*M*v = R*(m + M)*v
then
L = (0.08 m)*(4 Kg + 2 Kg)*v = (0.48 Kg-m)*v
c) We use the relation
τ = dL/dt = d((0.48 Kg-m)*v)/dt = (0.48 Kg-m)*dv/dt
τ = (0.48 Kg-m)*a
then
τ/(0.48 Kg-m) = a
⇒ a = 3.1392 N-m/((0.48 Kg-m)
a = 6.54 m/s²
Momentum can be defined as "mass inmotion." All objects have mass; so if anobject is moving, then it has momentum - ithas its mass in motion. The amount ofmomentum which an object has is dependentupon two variables: how much stuff is movingand how fast the stuff is moving. Momentum depends upon the variablesmass and velocity. In terms of an equation, the momentum of an objectis equal to the mass of the object times the velocity of the object. T/F
Answer:
T
Explanation:
momentum=mass×velocity
The momentum of an object is equal to the mass of the object times the velocity of the object which is true.
What is momentum?In Mechanics, momentum is calculated as the combination of an object's weight and speed. It has both a magnitude and a direction, making it a vector quantity. If an entity has weight m and speed v, then its momentum is given by,
p = mv
Where 'p' is the momentum, 'm' is the mass, and 'v' is the velocity.
Mass in motion is a definition of momentum. All things have mass, thus when something moves, it has momentum because its mass is in motion. The amount of momentum an object possesses depends on two factors: how much and how quickly the material is moving.
It is correct to say that an object's momentum is equal to its mass times its velocity.
More about the momentum link is given below.
https://brainly.com/question/4956182
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Water is traveling into what sphere during infiltration?
A satellite is in a circular orbit around the Earth at an altitude of 3.58 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 106 m, and the mass of the Earth is 5.98 1024 kg.)
Kepler's Third Law helps calculate the period of satellites orbiting Earth based on their radius, aiding in various applications.
Kepler's Third Law: The period of an orbiting object is related to the radius of its orbit. Using the formula n²a³ = GM (where n is the mean motion, a is the semi-major axis, and GM is the product of the gravitational constant and the Earth's mass), we can calculate the period of the satellite's circular orbit.
Calculations: For a satellite at an altitude of 20,200 km above Earth's surface (a = 26,578 km), with GM = 3.986005 x 10¹⁴ m³/s², the period T comes out to be 43,122 seconds.
Application: Understanding Kepler's laws helps in determining crucial parameters for artificial satellites orbiting Earth, aiding in satellite communication, weather observation, and other scientific endeavors.
what is an example of friction
A) slipping on a patch of ice
B) dropping a book
C) diving into a swimming pool
D) wind blowing against you on a walk
Answer: slipping on a patch of ice (A)
Explanation: there is direct contact when you slip on a patch of ice: your body, and the ice. all of the other answers are either non contact, or it is not solid to solid (wind, water). hope that makes sense :)
The Tour de France is the biggest bicycle race in the world. The race lasts for three weeks and is one of the biggest sporting events of the year. At the end of each day of racing they give to the certain riders FOUR different colored jerseys. What are the four different colored jerseys AND what does it mean to the rider that gets to wear it the next day?
Answer:
Yellow, green, polka dot and white jerseys
Explanation:
Tour de France is the biggest bicycle race in the world held at France over a period of 23 days. At the end of each day of racing they give to the certain riders FOUR different colored jerseys:
The yellow jersey is given to the overall winner at each stage, this shows the rider who was the best in the previous stage.The green jersey is given to the best sprinter of each stage, The polka dot jersey is given to the rider who first reach the crest of designated hills and mountains at each stage.The white jersey is given to the fastest rider at each stage under 25 years at the beginning of the racing year.At the end of the competition, the total points are counted and the different jerseys are given to the overall winners.