a race track has a length of 0.750 miles. How many inches is this? One mile equals 5280 feet

The acceleration of the jet is [tex]11.4 m/s^2[/tex]

Explanation:

Since the jet motion is a uniformly accelerated motion (=constant acceleration), we can use the following suvat equation:

[tex]v^2-u^2=2as[/tex]

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the jet in this problem, we have

u = 0 (it starts from rest)

v = 40 m/s (final velocity)

s = 70 m (length of the runway)

Solving for a, we find the acceleration:

[tex]a=\frac{v-u}{t}=\frac{40^2-0}{2(70)}=11.4 m/s^2[/tex]

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The magnitude of the acceleration of the jet is approximately 11.43 m/s².While taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40.

To determine the magnitude of the acceleration of the jet, we can use the following kinematic equation:

v² = u² + 2as

where:

v is the final velocity (40 m/s),

u is the initial velocity (0 m/s, starting from rest),

a is the acceleration

and s is the displacement (70 m).

a = (v² - u²) / (2s)

a = (40² - 0²) / (2 × 70)

a = 1600 / 140

a ≈ 11.43 m/s²

Therefore, the magnitude of the acceleration of the jet is approximately 11.43 m/s².

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Answer:

b

Explanation:

Answer:

1 second

Explanation:

Assuming that the force is in the same direction as speed we can do the graphic.

Answer:

-5.06 m/s

Explanation:

The formula to calculate average speed is

V = x2 - x1 / t2 - t1

The start point of the tumbleweed is 25.6m and the final point is -14.4 m

The start time is 0s and the final time is 7.9s

Replacing the values the result is -5.06m/s.

The result of the speed is negative because the direction of the speed is opposite to the direction of the tumbleweed.

A) The net force on the motorbike is 205.9 N

B) The acceleration of the motorbike is [tex]1.37 m/s^2[/tex]

C) The final speed is 5.2 m/s

D) The elapsed time is 3.80 s

Explanation:

A)

There are two forces acting on the motorbike:

- The applied force, F = 250 N, forward

- The frictional force, [tex]F_f[/tex], backward

The frictional force can be written as

[tex]F_f = \mu mg[/tex]

where

[tex]\mu=0.03[/tex] is the coefficient of kinetic friction

[tex]m=150 kg[/tex] is the mass of the motorbike

[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity

Therefore the net force is given by

[tex]\sum F = F - F_f = F - \mu mg[/tex]

And substituting, we find

[tex]\sum F=250 - (0.03)(150)(9.8)=205.9 N[/tex]

2)

The acceleration of the motorbike can be found by using Newton's second law, which states that the net force is equal to the product between mass and acceleration:

[tex]\sum F = ma[/tex]

where

m is the mass

a is the acceleration

In this problem, we have

[tex]\sum F = 205.9 N[/tex] is the net force

m = 150 kg is the mass

Solving for a, we find the acceleration:

[tex]a=\frac{\sum F}{m}=\frac{205.9}{150}=1.37 m/s^2[/tex]

C)

Since the motion of the motorbike is a uniformly accelerated motion, we can use the following suvat equation:

[tex]v^2-u^2=2as[/tex]

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For this motorbike, we have:

u = 0 (it starts from rest)

[tex]a=1.37 m/s^2[/tex]

s = 350 m

Solving for v,

[tex]v=\sqrt{u^2+2as}=\sqrt{0+2(1.37)(9.8)}=5.2 m/s[/tex]

4)

For this part of the problem, we can use the following suvat equation:

[tex]v=u+at[/tex]

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the elapsed time

Here we have:

v = 5.2 m/s

u = 0

[tex]a=1.37 m/s^2[/tex]

Solving for t, we find

[tex]t=\frac{v-u}{a}=\frac{5.2-0}{1.37}=3.80 s[/tex]

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Answer:

This is a great question

*copy and paste for my physics homework* lol

Answer:

NaCl,AgF

Explanation:

Chemical equations show the reactants and products, as well as other factors such as energy changes, catalysts, and so on. With these equations, an arrow is used to indicate that a chemical reaction has taken place. In general terms, a chemical reaction follows this format:

Reactants→Products

So the reactants of the given reaction are NaCl,AgF

The reactants in the chemical equation NaCl+AgF → NaF+AgCl are sodium chloride (NaCl) and silver fluoride (AgF).

The reactants in the chemical equation NaCl+AgF → NaF+AgCl are sodium chloride (NaCl) and silver fluoride (AgF). In this reaction, a double displacement reaction, also known as a metathesis reaction, occurs where the elements in the reactants switch places, resulting in the formation of new compounds. The sodium ion (Na+) and the fluoride ion (F-) form sodium fluoride (NaF), while the silver ion (Ag+) and the chloride ion (Cl-) form silver chloride (AgCl), which is a precipitate, as illustrated in various silver reaction equations provided.

Answer:

v=3 m/s

Explanation:

the formula for this problem is

V =  v 1  ( m 1 / m 1  + m 2 )

we if we substitute ans solve we get this the answer as 3 m/s

Child and stationary skateboard move with same speed, as child jumps onto skateboard. Approximate speed of child and skateboard is 3 m/s.

Momentum of a object is the force of speed of it in motion. Momentum of a moving body is the product of mass times velocity.

When the two objects collides, then the initial collision of the two body is equal to the final collision of two bodies by the law of conservation of momentum.

Thus by the law of conservation of momentum,

[tex](m_1u_1)+(m_2u_2)=(m_1+m_2)v[/tex]

Here,  [tex]m_1,m_2[/tex] are the masses of two bodies and [tex]u_1,u_2[/tex] are the initial velocities.

Given information-

The mass of the child is 30 kg.

The speed of the child is 10 m/s.

The mass of the skateboard is 10 kg.

Let the speed of the child and skateboard is [tex]v[/tex] m/s.

As the the child and jumps down onto a stationary skateboard then, the speed of child and skateboard should be same.

Thus by the conservation of momentum,

[tex](m_cu_c)+(m_su_s)=(m_c+m_s)v[/tex]

As the initial velocity of the skateboard is 0. Put the values in the above formula as,

[tex](30\times4)+(10\times 0)=(30+10)v\\120+0=40v\\v=3\rm m/s[/tex]

Thus the approximate speed of the child and skateboard is 3 m/s.

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The time taken is [tex]3.75\cdot 10^{-4}s[/tex]

Explanation:

The motion of the bullet is a uniform motion (=constant velocity), therefore we can use the following equation:

[tex]v=\frac{d}{t}[/tex]

where

v is the speed of the bullet

d is the distance covered

t is the time taken

For the bullet in this problem,

d = 0.30 m is the distance travelled

v = 800.0 m/s is the speed

Solving for t, we find the time taken:

[tex]t=\frac{d}{v}=\frac{0.3}{800}=3.75\cdot 10^{-4}s[/tex]

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Answer:

It would eventually crash into the Sun

Explanation:

If the mars is orbiting around the sun, the gravitational force of attraction is between the sun and mars supply the necessary force required for the centripetal motion.

If a planet is in centripetal motion, it is constantly falling towards the sun with the acceleration equal to the gravitational strength at that point.

If the centripetal acceleration of the planet is removed, still the planet would accelerate linearly falling towards the sun.

Hence, if the planets tangential velocity was reduced to zero, It would eventually crash into the Sun

Answer:

[tex]7.3 ms^{-1}[/tex]

Explanation:

Consider the motion of the ball attached to string.

In triangle ABD

[tex]Cos50 = \frac{AB}{AD} \\Cos50 = \frac{AB}{L}\\AB = L Cos50[/tex]

height gained by the ball is given as

[tex]h = BC = AC - AD \\h = L - L Cos50\\h = 1.10 - 1.10 Cos50\\h = 0.393 m[/tex]

[tex]M[/tex]  = mass of the ball attached to string = 110 g

[tex]V[/tex] = speed of the ball attached to string just after collision

Using conservation of energy

Potential energy gained = Kinetic energy lost

[tex]Mgh = (0.5) M V^{2} \\V = sqrt(2gh)\\V = sqrt(2(9.8)(0.393))\\V = 2.8 ms^{-1}[/tex]

Consider the collision between the two balls

[tex]m[/tex]  = mass of the ball fired = 26 g

[tex]v_{o}[/tex] = initial velocity of ball fired before collision = ?

[tex]v_{f}[/tex] = final velocity of ball fired after collision = ?

using conservation of momentum

[tex]m v_{o} = MV + m v_{f}\\26 v_{o} = (110)(2.8) + 26 v_{f}\\v_{f} = v_{o} - 11.85[/tex]

Using conservation of kinetic energy

[tex]m v_{o}^{2} = MV^{2} + m v_{f}^{2} \\26 v_{o}^{2} = 110 (2.8)^{2} + 26 (v_{o} - 11.85)^{2} \\v_{o} = 7.3 ms^{-1}[/tex]

At a maximum angle of 50°, the initial velocity ([tex]V_0[/tex]) of the ball is equal to 7.3 m/s.

Given the following data:

Mass of ball 1 = 26.0 g.

Mass of ball 2 = 110.0 g.

Length = 1.10 m.

Maximum angle = 50°

First of all, we would determine the height of the ball in motion through this derivation:

[tex]h = L-Lcos\theta\\\\h = 1.10-1.10cos50\\\\h = 1.10-0.7071[/tex]

Height, h = 0.3929 meter.

Next, we would determine the velocity of the ball by applying the law of conservation of energy:

[tex]P E=KE\\\\mgh=\frac{1}{2} mv^2\\\\V=\sqrt{2gh} \\\\V=\sqrt{2 \times 9.8 \times 0.3929 }[/tex]

V = 2.7750 m/s.

Also, we would determine the final velocity by applying the law of conservation of momentum:

[tex]m_1v_o=m_1vf+m_2V\\\\26v_0=26v_f+110(2.7750)\\\\26v_f=26v_0-305.25\\\\v_f=(v_0-11.7404)\;m/s[/tex]

Now, we can determine the initial velocity:

[tex]m_1v_o^2=m_1v_f^2+m_2V^2\\\\26v_0^2=26(v_0-11.7404)^2+110(2.7750)^2\\\\26v_0^2=26(v_0-11.7404)^2-847.0688\\\\V_0=7.3\;m/s[/tex]

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Answer:

Option C. The chloroplasts contain chlorophyll pigments requires for photosynthesis.

The cell structure that is considered the site of photosynthesis is known as chloroplasts. Hence, option C is the correct answer.

Photosynthesis is a significant process that takes place in plants. The process in which light energy obtained from the sun is converted into sugar molecules for the utilization by plants cells is known as Photosynthesis.  

Photosynthesis occurs at chloroplasts. Some of the significant features of the chloroplasts are listed as follows:

Thus, we can conclude that the chlorophyll present in chloroplasts is vital for photosynthesis and hence, chloroplasts are the cell structure that acts as the site of photosynthesis. Therefore, option C is the correct answer.

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Answer:

Mg is the symbol for Magnesium. Atomic #- 12

Explanation:

Answer:

The force acting on a body is always equal to the product of the mass of the body and its acceleration.

Explanation:

The force of a body is defined as the product of mass and acceleration of the body.

According to Newton's second law, wherever there is a change in momentum of the body for an interval of time, there is a force acting on it.

                         F = (mv - mu) / t

                             = m (v -u) /t

                              = m a

Where,

                                 (v - u)/t - is the change in velocity of the body in the interval of time. It is equal to the acceleration of the body.

Hence, the equation for the force for any body becomes, F = m x a

Answer:

The gravity pulls the sun and the planets together, while keeping them apart. The inertia provides the tendency to maintain speed and keep moving. The planets want to keep moving in a straight line because of the physics of inertia. However, the gravitational pull wants to change the motion to pull the planets into the core of the sun. Together, this creates a rounded orbit as a form of compromise between the two forces.

Final answer:

Gravity acts as a centripetal force pulling the Moon towards Earth, while inertia gives the Moon its straight-line momentum. Together, they balance each other out, keeping the Moon in a stable elliptical orbit around Earth. The gravity gradient also affects the Moon's rotation and contributes to the equilibrium between Earth and the Moon.

Explanation:

Gravity and Inertia in Maintaining the Moon's Orbit

The Moon remains in orbit around the Earth due to the combined effects of gravity and inertia. Gravity, a fundamental force discovered by Isaac Newton, acts as a centripetal force that pulls the Moon towards the center of the Earth. Without this force, the Moon would move in a straight line into space. On the other hand, inertia is the tendency of an object to maintain its state of motion unless acted upon by an external force. The Moon has a momentum perpendicular to the gravitational pull of the Earth which would allow it to move in a straight line. These two forces together create a delicate balance that results in the Moon's smooth, elliptical orbit around the Earth.

The gravity gradient also plays a role in the Moon's rotation and orbital characteristics. This gradient explains why the Moon is slightly elongated towards the Earth and contributes to maintaining its stable orbit. Furthermore, the Earth and Moon stay in equilibrium since the gravitational force of attraction between them is perfectly balanced by the centrifugal force, stemming from their relative motion.

In summary, gravity acts to pull the Moon towards the Earth, while inertia contributes to the Moon's tendency to move forward. Together, these forces create the conditions for a stable, synchronous orbit, manifesting in phenomena such as synchronous rotation and the consistent face of the Moon that is always directed towards Earth.

The two models used to describe light are the ray model, which is useful in geometric optics for large surfaces, and the wave model, which explains diffraction and color. At the atomic level, the particle model describing light as photons is also used.

The two models used to describe how light behaves are the ray model and the wave model. The ray model of light simplifies its behavior to straight-line paths, which is particularly useful in geometric optics, where light's interaction with large surfaces—such as reflections from mirrors and refractions through lenses—is considered. The wave model, on the other hand, is essential for explaining phenomena like diffraction and the observation of colors, representing light as electromagnetic waves with different frequencies.

Furthermore, at the scale where light interacts on the level of individual atoms, the particle model of light, which describes light as photons, becomes more apparent. This model is crucial for understanding concepts like the photoelectric effect. Therefore, depending on the scale of the interaction and the nature of the observation, either model—or sometimes both—may be more appropriate for describing the behavior of light.

Answer:

the answer is C

Explanation:

Answer:

0.256 m/s

Explanation:

Speed is distance over time.

Find the speed of each trial and then find the average.

Trial 1: v = 0.7 m / 2.5 s = 0.280 m/s

Trial 2: v = 0.7 m / 2.75 s = 0.255 m/s

Trial 3: v = 0.7 m / 2.98 s = 0.235 m/s

v_avg = (0.280 m/s + 0.255 m/s + 0.235 m/s) / 3

v_avg = 0.256 m/s

Round as needed.

Answer:

The efficiency of the ramp is, Eff = 6.63 %

Explanation:

Given,

The work done by the person pushing the furniture up the ramp is, W₁ = 1240 J

The work done by the ramp is, W₀ = 822 J

The efficiency of the ramp is given by the formula,

                                  Eff = ( W₀ / W₁ ) x 100%

                                        = ( 822 / 12400 ) x 100%

                                        = 6.63 %

Hence, the efficiency of the ramp is, Eff = 6.63 %

Answer:

The efficiency of the ramp is, Eff = 6.63 %

Explanation:

Answer:

A. Fewer than four barbarians.

Explanation:

Mechanical advantage = wheel radius / axle radius

If the wheel radius doubles and the axle radius stays the same, then the mechanical advantage doubles.  That means the effort force is half.  So we expect it would take half as many barbarians to turn the wheel.

If the wheel radius were doubled and the axle radius stayed the same, it would take fewer than four barbarians.

Assuming there is no friction in the system, the ratio of the force that performs the useful work to the force applied is the theoretical mechanical advantage of a system.

The extent by which the mechanical advantage really differs from the theoretical value in actuality depends on the amount of friction.

Theoretically, for a  wheel and axle system is:

the mechanical advantage = Radius of wheel/ radius of the axle.

As the  wheel radius were doubled while  the axle radius remains the same; the mechanical advantage of the system will become greater and  fewer than four barbarians were needed now.

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The speed of the bucket is 1.8 m/s

Explanation:

The bucket is in circular motion, therefore the net force acting on it is equal to the centripetal force:

[tex]F=m\frac{v^2}{r}[/tex]

where

m = 2 kg is the mass of the bucket

v is its speed

r = 1.20 m is the radius of the circle

At the lowest point of motion, there are two forces acting on the bucket:

Therefore the equation of motion for the bucket is:

[tex]T-mg=m\frac{v^2}{r}[/tex]

And solving for v, we find the speed of the bucket:

[tex]v=\sqrt{r(\frac{T}{m}-g)}=\sqrt{(1.20)(\frac{25}{2}-9.8)}=1.8 m/s[/tex]

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Answer:

35

Explanation:

Answer:

nice, thats a fast rabbit

Explanation:

Answer:

Angular Velocity at 2 s= 13 rad/s

Explanation:

∅(t)=2[tex]t^{2}[/tex] + 5t + 5

where represents angular displacement at any given time t

Angular Velocity (ω)= [tex]\frac{\textrm{d ∅(t) }}{\textrm{dt}}[/tex]

ω=4t+ 5

Putting in t=2

ω=8+5=13 rad/s

Answer:

Its A.

Explanation:

Answer:

85 ÷ 0.50÷340=z z is the answer

The weight of a wrench on the Moon is 0.624 Newtons.

Weight of the wrench = 5.24 N

The gravitational acceleration on the moon = 1.16 m/s²

Gravitational acceleration on earth = 9.8 m/s².

Weight is calculated by the formula = W = m × g

First, we need to find the mass of the wrench on Earth using Earth's gravity:

m = W ÷ g

m= 5.24 N ÷ 9.8 m/s²

Then we use the mass of the wrench to calculate its weight on the Moon:

Weight on the moon = m × gravity on moon

By substituting the values, we get:

Weight on the moon = m × 1.16 m/s² = (5.24 N / 9.8 m/s²) ×1.16 m/s²

After calculating, the weight of the wrench on the Moon would be:

Weight on the moon = 0.624 N

Answer:

C. Cryosphere

Explanation:

The definition for Cryo is:

Involving extreme Coldness and etc.

There are studies done on Cyro Freezing the body to preserve the body until there is a cure for a deadly disease. They do this as well to try to live in the future. Our technology hasn't been able to get the people alive yet, but when we do.

If you ever need to think of "Cryo" just think of Cryo Freezing.

Answer:

C.

Explanation:

Answer:

0.523598776  seconds

Explanation:

m =2 kg , k =8 N/m

[tex]w = \sqrt {\frac {k}{m}}[/tex]

[tex]w=\sqrt {\frac {8}{2}}= 2 rad/s[/tex]

x = xm cos(wt)

1 =2 cos(2t)

cos 2t=0.5

[tex]2t=cos^{-1} 0.5=1.047197551[/tex]

t=0.523598776  seconds

Final answer:

The time it takes for a 2kg mass attached to a spring with a spring constant of 8N/m to move from x=2 to x=1 is π/4 seconds, which is one-quarter of the period of oscillation in simple harmonic motion.

Explanation:

To calculate the time it takes for a 2kg mass attached to a spring with a spring constant of 8N/m to travel from the point displaced at x=2 to the point x=1, we must understand simple harmonic motion (SHM). In SHM, the angular frequency ω can be determined by the formula ω = √(k/m), where k is the spring constant, and m is the mass of the object attached to the spring. The period of oscillation is given as T = 2π/ω. It's important to note that the time taken to travel from x=2 to x=1 is one-quarter of the period, because the motion from the maximum displacement to the equilibrium position constitutes one-quarter of the cycle of oscillation.

Applying the given values:

Spring constant, k = 8 N/m

Mass, m = 2 kg

We calculate the angular frequency:

ω = √(k/m) = √(8/2) = 2 rad/s

The period of oscillation, T, is:

T = 2π/ω = 2π/2 = π seconds

The time taken to travel from x=2 to x=1 is one-quarter of this period:

Time = T/4 = π/4 seconds.

Final answer:

The specific heat capacity of the metal can be calculated using the equation q = m*c*ΔT. By substituting the given values into the equation and rearranging, we can find that the specific heat capacity of the metal is approximately 0.33 J/g°C.

Explanation:

The specific heat capacity of a substance is the amount of energy required to raise the temperature of 1 gram of the substance by 1°C. In this question, we can use the equation:

q = m*c*ΔT

Where q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

Given that the metal has a mass of 15.3 grams and the temperature rises by 4.3°C, and the water has a mass of 80.2 grams and the temperature rises by 4.3°C, we can substitute these values into the equation to find the specific heat capacity of the metal:

qmetal = mmetal * cmetal * ΔTmetal

qwater = mwater * cwater * ΔTwater

The specific heat capacity, cmetal, can then be calculated by rearranging the equation:

cmetal = (qmetal - mwater * cwater * ΔTwater) / (mmetal * ΔTmetal)

Plugging in the given values, we find that the specific heat capacity of the metal is approximately 0.33 J/g°C.

Answer:

this is a trap ur done