Answer:
The efficiency of the ramp is, Eff = 6.63 %
Explanation:
Given,
The work done by the person pushing the furniture up the ramp is, W₁ = 1240 J
The work done by the ramp is, W₀ = 822 J
The efficiency of the ramp is given by the formula,
Eff = ( W₀ / W₁ ) x 100%
= ( 822 / 12400 ) x 100%
= 6.63 %
Hence, the efficiency of the ramp is, Eff = 6.63 %
Answer:
The efficiency of the ramp is, Eff = 6.63 %
Explanation:
As the skydiver falls to Earth, she experiences positive acceleration due to
A toy car has an initial acceleration of 2 m/s" across a horizontal surface after it is released from rest. After the car travels for a timet
consisting of only the car an open system or a closed system, and why?
Open system because the acceleration of the car is not constant.
Open system, because an external force is applied to the car that causes it to accelerate.
Closed system, because the speed of the car is as expected in the case where an object has uniform acceleration for a timet
Closed system because mechanical energy was not removed from the system as a result of a net force
Rie
B
7:53 PM
12/11/2019
The car is considered as an open system, because an external force is applied to the car that causes constant acceleration of car. Hence, option (B) is correct.
The system isolated from its surrounding is known as closed-system. While, in an open system, the flow of information between the system and surrounding takes place, to cause any change in the system.
As per the concept of open and closed system:
The given problem indicates that car has initial acceleration of [tex]2 \;\rm m/s^{2}[/tex], travels for time t . Which means the car is accelerating constantly.And for a constant acceleration, there must be some external force acting on the car.Hence, the car must be considered an an open system, because the acceleration of car is related with the force, which is being applied from the outside of frame of reference.
Thus, we can conclude that considering only car is an open system because external force is applied to the car that causes it to accelerate. Hence, option (B) is correct.
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What distance will a car traveling 65km/hr travel in 3 hours
Answer:
it will cover 195km in 3 hours
what is the magnitude of an electric field which will balance the weight of an electron on the surface of earth ?
The magnitude of the electric field must be [tex]5.59\cdot 10^{-11} N/C[/tex]
Explanation:
In order for the electron to be in equilibrium, the force of gravity acting on the electron must be equal to the force due to the electric field.
The force of gravity on the electron located on the Earth's surface is:
[tex]F_G = mg[/tex]
where
[tex]m=9.11\cdot 10^{-31} kg[/tex] is the electron mass
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
The force due to the electric field is
[tex]F_E = qE[/tex]
where
[tex]q=1.6\cdot 10^{-16}C[/tex] is the electron charge
E is the magnitude of the electric field
Since the two forces must be balanced,
[tex]F_G = F_E[/tex]
So we find:
[tex]mg=qE\\E=\frac{mg}{q}=\frac{(9.11\cdot 10^{-31})(9.81)}{1.6\cdot 10^{-19}}=5.59\cdot 10^{-11} N/C[/tex]
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If you are rolling a car down a ramp, the speed at the top of the ramp will be (faster/slower) than the speed at the bottom. Is it faster or slower?
Answer:
slower
Explanation:
Due to the fact that it is falling, the object experiences an acceleration due to gravity, so this acceleration will make the car go faster every moment, so the speed at the top will be lower than the speed at the bottom.
The situation can also be thought of as a transaction of potential energy (energy due to the mass of an object and its position on the ground) and kinetic energy (energy due to movement). At the top is the point where the object has the greatest potential energy, and as it moves down this potential energy is exchanged for kinetic energy. The kinetic energy increases while going down the ramp, so it will have greater speed as it falls.
The answer is: the speed at the top of the ramp will be slower than the speed at the bottom.
A 1500kg car, moving at a speed of 20m/s comes to a halt. How much work was done by the brakes?
The work done by the brakes is [tex]-3.0\cdot 10^5 J[/tex]
Explanation:
According to the work-energy theorem, the work done by the brakes on the car is equal to the change in kinetic energy of the car. Therefore:
[tex]W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2[/tex]
where
W is the work done
m is the mass of the car
v is the final speed
u is the initial speed
For the car in this problem, we have:
m = 1500 kg
u = 20 m/s
v = 0 (the car comes to a halt)
Substituting, we find the work done:
[tex]W=0-\frac{1}{2}(1500)(20)^2=-3.0\cdot 10^5 J[/tex]
And the work is negative because the brakes apply a force in the opposite direction to the motion of the car.
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A truck accelerates to a velocity of 38 m/s over 755 m of road
1) The acceleration is [tex]0.96 m/s^2[/tex]
2) The time taken is 39.6 s
Explanation:
1)
Since the motion of the truck is a uniformly accelerated motion (=constant acceleration), we can use the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the truck in this problem,
u = 0 (it starts from rest)
v = 38 m/s
s = 755 m
Solving for a, we find the acceleration:
[tex]a=\frac{v^2-u^2}{2s}=\frac{38^2-0}{2(755)}=0.96 m/s^2[/tex]
2)
For this part we can use the following suvat equation
[tex]v=u+at[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time taken for the velocity to change from u to v
In this problem,
u = 0
v = 38 m/s
[tex]a=0.96 m/s^2[/tex]
Solving for t,
[tex]t=\frac{v-u}{a}=\frac{38-0}{0.96}=39.6 s[/tex]
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The truck's acceleration, starting from rest to a velocity of 38 m/s over 755 m, is approximately 0.956 m/s². It takes about 39.75 seconds to cover this distance.
a. To determine the acceleration of the truck, we can use the kinematic equation:
v^2 = u^2 + 2as
where:
v = final velocity (38 m/s),
u = initial velocity (0 m/s since the truck was initially at rest),
a = acceleration,
s = displacement (755 m).
Rearranging the equation to solve for acceleration (a), we get:
a = (v^2 - u^2) / (2s)
Substitute the given values:
a = (38^2 - 0^2) / (2 * 755)
a = 1444 / 1510
a ≈ 0.956 m/s^2
b. To find the time taken (t), we can use the kinematic equation:
v = u + at
Since the truck started from rest (u = 0), this simplifies to:
t = v / a
Substitute the values:
t = 38 / 0.956
t ≈ 39.75 s
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The question probable may be:
A Truck accelerates to a velocity of 38 m/s over 755 m of road.
a. If the truck was initially at rest, what was its acceleration?
b. How long willthe truck take to travel this distance?
Using the equation for force (due to weight) and your mass , calculate your force
F=m x 9.8m/s2
F=69.3 x 9.8 m/s2 =???
The weight of the object is 679.1 N
Explanation:
The weight of an object is given by:
[tex]W=mg[/tex]
where
W is the weight
m is the mass of the object
g is the acceleration of gravity
For an object near the Earth's surface, the acceleration of gravity is
[tex]g=9.8 m/s^2[/tex]
The mass of the object in this problem is
m = 69.3 kg
Therefore, its weight is
[tex]W=(69.3)(9.8)=679.1 N[/tex]
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If the airman had a mass of 80 kg, find the magnitude of the air drag acting on him when he reached terminal velocity of 54 m/s
The magnitude of the air drag is 784 N
Explanation:
An object falling down reaches the terminal velocity when the magnitude of the air drag acting on it becomes equal to the weight of the object. Mathematically, this condition can be written as:
[tex]F_D = mg[/tex]
where
[tex]F_D[/tex] is the magnitude of the air drag
m is the mass of the object
g is the acceleration of gravity
In this problem, we have
m = 80 kg is the mass of the airman
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
Substituting into the formula, we find:
[tex]F_D = (80)(9.8)=784 N[/tex]
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A force does work on a 50 g particle as the particle moves along the following straight paths in the xy-plane: 25 J from (0 m, 0 m) to (5 m, 0 m); 35 J from (0 m, 0 m) to (0 m, 5 m); -5 J from (5 m, 0 m) to (5 m, 5 m); -15 J from (0 m, 5 m) to (5 m, 5 m); and 20 J from (0 m, 0 m) to (5 m, 5 m).
Is this a conservative force?
If the zero of potential energy is at the origin, what is the potential energy at (5m, 5m)?
1) Yes, it is a conservative force
2) The potential energy at (5m, 5m) is 20 J
Explanation:
1)
A force is defined to be conservative if the work done by the force when moving an object does not depend on the path taken, but only on the initial and final position of the object.
Let's verify if this condition is met for the force in this problem:
- For going from (0 m, 0 m) to (5 m, 5 m), the work done is 20 J (A)
Then we can go from (0 m, 0 m) to (5 m, 5 m) through a different path:
- from (0 m, 0 m) to (5 m, 0 m) (work done: 25 J)
- from (5 m, 0 m) to (5 m, 5 m) (work done: -5 J)
Total work done in the second path: 25 J + (-5 J) = 20 J --> same as (A)
We can also go from (0 m, 0 m) to (5 m, 5 m) through a different path:
- from (0 m, 0 m) to (0 m, 5 m) (work done: 35 J)
- from (0 m, 5 m) to (5 m, 5 m) (work done: -15 J)
Total work done in the third path: 35 J + (-15 J) = 20 J --> same as (A)
So, the force is conservative, since the work done does not depend on the path taken.
2)
For a conservative force, the change in potential energy of the object moved by the force is equal to the work done by the force in moving the object from A to B.
Here have:
Point A: (0m, 0m)
Point B: (5m, 5m)
So, the change in potential energy is equal to the work done from A to B:
[tex]W=\Delta U = U_B-U_A[/tex]
where
[tex]U_B[/tex] is the potential energy in point B
[tex]U_A[/tex] is the potential energy in point A
In this problem, the potential energy at the origin (point A) is zero, so
[tex]U_A = 0[/tex]
Also we know that the work done is
W = 20 J
So, we find
[tex]U_B = W+U_A = 20 + 0 = 20 J[/tex]
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The force exerted is not conservative as different amounts of work are being done to move the particle along different paths between the same points. Potential energy isn't defined in the usual sense because the force isn't conservative, but if taken as the average of the works done, the potential energy at (5,5) could be taken as 20J.
Explanation:A conservative force is defined as one in which the work done on a particle by the force as the particle moves from one point to another is independent of the path taken. Specifically, in the case of a conservative force, the work done is only dependent on the initial and final positions. In the given scenario, different amounts of work are being done to move the particle along different paths between the same points. This indicates that the force is not a conservative one.
The potential energy at a point in a field due to a conservative force is equal to the work done by the force to move the particle from a reference point (in this case, the origin point) to that point. Since the force in this scenario isn't conservative, potential energy isn't defined in the usual sense. Nevertheless, if we insist on measuring it, we could take the average of the works done: for instance, between (0,0) and (5,5) the works done are 35+(-15)=20 and -5+25=20, so we could say the potential energy at (5,5) is 20J considering the origin as the reference point with zero potential energy.
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Andre really likes his new car, and he knows it has a certain amount of mechanical energy. Which types of energy are included in the mechanical
energy of the car? Choose the two that apply.
A. electrical energy from the battery
B. kinetic energy from any movement the car has
C. potential energy based on its position
D. thermal energy from when fuel burns in the engine
Option - B and Option - C are correct.
We have Andre's new car.
We have to determine what types of Energies are included in the Mechanical energies of the car.
What is Mechanical Energy?The energy possessed by an object due to its motion or its position is called Mechanical Energy.
According to the question -
The Mechanical energy of the new car would include the following two types of energy -
Kinetic Energy of Car - The kinetic energy of the car is the energy possessed by the car by virtue of its motion. Mathematically -[tex]$E(K) = \frac{1}{2} mv^{2}[/tex]
Potential Energy of Car - The potential energy of the car is due to its position. Assume that the car of mass 'm' is parked over the mountain at height 'h'. Then its potential energy will be -U(h) = mgh
Hence, Option B and C are correct.
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A Tesla Roadster car accelerates from rest at a rate of 7.1m/s for a time of 3.9s
Calculate the distance it travels in this time.
The distance covered is 54.0 m
Explanation:
Since the motion of the car is a uniformly accelerated motion, we can use the following suvat equation:
[tex]s=ut+\frac{1}{2}at^2[/tex]
where
u is the initial velocity
t is the time
a is the acceleration
s is the distance covered
For the car in this problem, we have
u = 0 (it starts from rest)
[tex]a=7.1 m/s^2[/tex] is the acceleration
t = 3.9 s is the time
Substituting, we find s:
[tex]s=0+\frac{1}{2}(7.1)(3.9)^2=54.0 m[/tex]
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According to Newton's Third Law, If one object exerts a force on a second object, the second object exerts a force on the first object that is:
Question 2 options:
equal in magnitude and opposite in direction
equal in magnitutde and in the same direction
different in magnitude compared to the original force
the same direction as the original force
Answer: equal in magnitude but opposite in direction to the force that it exerts.
Explanation:
Answer:
The second object exert a force that is equal in magnitude and opposite in direction.
Explanation:
Newton's third law of motion states that for every action there is a reaction which is equal in magnitude to the action but acts in opposite directions as the action.
an object weighs 50 N on Jupiter and another object weighs 50 N on the earth. Which has greater mass?
The object on Earth has greater mass
Explanation:
The weight of an object is given by
[tex]W=mg[/tex]
where
W is the weight
m is the mass of the object
g is the strength of the gravitational field at the location of the object
The strength of the gravitational field on Jupiter ([tex]g_J[/tex]) is much larger than that on Earth ([tex]g_E[/tex]), so we can write
[tex]g_J > g_E[/tex]
The weight of the first object on Jupiter is
[tex]W_J = m_1 g_J = 50 N[/tex] (1)
where [tex]m_1[/tex] is the mass of the first object, while the weight of the second object on Earth is
[tex]W_E = m_2 g_E = 50 N[/tex] (1)
while [tex]m_2[/tex] is the mass of the second object.
By dividing eq.(1) by (2), we get
[tex]\frac{m_1 g_J}{m_2 g_E}=1\\\frac{m_1}{m_2}=\frac{g_E}{g_J}[/tex]
And since [tex]g_J > g_E[/tex], this means that [tex]m_2 > m_1[/tex], so the object on Earth has greater mass.
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sound energy cannot travel through
A vacuum,a wooden table,polluted air,pond water
Sound energy cannot travel through a vacuum.
Explanation:
Waves are periodic disturbance of the space, which travel carrying energy but not matter.
There are two types of waves:
Mechanical waves: mechanical waves propagate through the vibrations of the particles in a medium. Examples of mechanical waves are sound waves.Electromagnetic waves: these waves consist of periodic oscillations of electric and magnetic fields, perpendicular to each other. These waves do not need a medium to propagate, so they can also travel in a vacuum.In this problem, we are analyzing sound energy, which is the energy carried by sound waves. Sound waves are mechanical waves, so they need a medium to propagate: therefore, they cannot travel through a vacuum, since there is no medium.
So, sound energy cannot travel through a vacuum.
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A car travels 5 miles north and then 2 miles south in 1/4 hour. What was its average speed?
The average speed of the car is 28 mph
Explanation:
The average speed of an object is equal to the ratio between the total distance covered by the object (regardless of its direction) and the time taken. Therefore:
[tex]speed = \frac{d}{t}[/tex]
where
d is the total distance
t is the time taken
The car in this problem travels 5 miles north and 2 miles south, so the total distance covered is
d = 5 + 2 = 7 miles
While the time taken is
t = 1/4 h = 0.25 h
Therefore, the average speed is
[tex]speed = \frac{7}{0.25}=28 mph[/tex]
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An object can be broken up by a planet's gravity once it passes the _______. The Jovian planets are composed primarily of _______ and helium. Hydrogen and helium don't exist in Earth's _______ because the terrestrial planets of Mercury, Venus, Earth, and Mars couldn't exert a strong gravitational pull on hydrogen and helium gas within the nebula. _______ is the planet closest to the sun, has almost no atmosphere, and what little atmosphere exists is constantly getting blown away by solar wind. The atmosphere of _______ is very hot and dense, comprised of approximately 95 percent carbon dioxide, and the surface is composed of molten bedrock.
Answer:1. Roche limit
2.hydrogen
3.atmosphere
4.mercury
5.venus
6.when an object passes the Roche limit, the strength of gravity on the object increases. If the density of the planet is higher, then the object can break up farther away from the planet. If the density is lower, then the Roche limit is located closer to the planet
7.Farther our in the solar system, beyond the frost line, hydrogen was at a low enough temperature that it could condense. This allowed hydrogen to accumulate under gravity, eventually forming the Jovian planets
Explanation:
An object breaks apart at a planet's Roche limit; Jovian planets mainly consist of hydrogen and helium. Earth's atmosphere lacks these gases due to weaker gravity. Mercury, close to the sun, has little atmosphere, and Venus has a hot, dense atmosphere.
Explanation:An object can be broken up by a planet's gravity once it passes the Roche limit. The Jovian planets are composed primarily of hydrogen and helium. Hydrogen and helium don't exist in Earth's atmosphere because the terrestrial planets of Mercury, Venus, Earth, and Mars couldn't exert a strong gravitational pull on hydrogen and helium gas within the nebula. Mercury is the planet closest to the sun, has almost no atmosphere, and what little atmosphere exists is constantly getting blown away by solar wind. The atmosphere of Venus is very hot and dense, comprised of approximately 95 percent carbon dioxide, and the surface is composed of molten bedrock.
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Need help with 3 and 4
3) The boulder travelled for a distance of 10 m
4) The work done on the car is zero
Explanation:
3)
The work done by a force on an object is given by:
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force
d is the displacement
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
In this problem we have:
F = 24 N
W = 240 J
[tex]\theta=0^{\circ}[/tex], assuming that the force is applied in the same direction as the displacement
Therefore, we can find d, the displacement of the boulder:
[tex]d=\frac{W}{F cos \theta}=\frac{240}{(24)(cos 0)}=10 m[/tex]
4)
As in the previous exercise, the work done is
The work done by a force on an object is given by:
[tex]W=Fd cos \theta[/tex]
In this problem, we have:
F = 9000 N is the force applied
d = 0 is the displacement, since the car has not moved
Therefore, the work done on the car is
[tex]W=(9000)(0)(cos 0)=0[/tex]
So, no work is done on the car.
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Amazon has hired you to help design a new fleet of robots to work in their warehouse. You are trying to decide how powerful the motor that allows the robots to climb vertically up the selves should be. assume that the robot itself will have a mass of 15 kg and needs to be able to carry an object with a mass of 5 kg up to the top of a 20 m shelf in 8 seconds. What minimum wattage should you use?
The minimum power is 490 W
Explanation:
The work that needs to be done by the robot in order to climb the shelves is equal to the gain in gravitational potential energy of the robot + object, therefore:
[tex]W=mg \Delta h[/tex]
where
m = 15 kg + 5 kg = 20 kg is the total mass of the system
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
[tex]\Delta h = 20 m[/tex] is the change in height
Substituting,
[tex]W=(20)(9.8)(20)=3,920 J[/tex]
Now we can calcualte the power (wattage) that the robot must have, using the equation
[tex]P=\frac{W}{t}[/tex]
where
W = 3,920 J is the work done
t = 8 s is the time interval
Substituting,
[tex]P=\frac{3920}{8}=490 W[/tex]
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Which statement about distance and displacement is correct?
Distance does not take direction of motion into account, but displacement does.
Displacement does take direction of motion into account but, but distance does.
Both distance and displacement must take direction of motion into account.
Answer:
The answer i believe is A..
Explanation:
.
Answer:
Distance does not take direction of motion into account, but displacement does.
Explanation:
Distance is said to be how much ground an object covers during motion. Distance is a scalar quantity. Distance has magnitude but no direction. It only concerns how much ground an object covers without considering the start or end points. For example a person covering a distance from point A to B can be computed without considering it starting and ending point. The distance from A to B can be computed as 100 meters.The change in position is not considered, only the distance it covered(100 meters)
While
Displacement is the change in position of an object. Displacement is a vector quantity as it incorporates both direction and magnitude. Displacement considers the starting and ending points of an object in motion. Example a person moving from point A to B, the change in position from point A to B shows their is a displacement.
A 0.0625 tank contains 0.0925kg nitrogen at a gauge pressure of 5.17atm.Find the temperature of the gas in degree Celsius
-271.96 °C
Explanation:We are given;
Volume of the tank as 0.0625 L Mass of nitrogen gas as 0.0925 kg or 92.5 g Pressure of the gas as 5.17 atmwe are required to calculate the temperature of the gas.
Step 1: Calculate the number of moles of nitrogen gasMoles = Mass ÷ Molar mass
Molar mass of nitrogen gas = 28.0 g/mol
Therefore;
Moles of N₂ = 92.5 g ÷ 28.0 g/mol
= 3.304 moles
Step 2: Calculate the temperature of the gas;According to the ideal gas equation;
PV = nRT , where n is the number of moles and R is the ideal gas constant, 0.082057 L.atm/mol.K
Rearranging the formula;
T = PV ÷ nR
= ( 5.17 atm × 0.0625 L) ÷ (3.304 moles × 0.082057)
= 1.19 K
But, °C = K - 273.15
Therefore;
T = 1.19 K - 273.15
= -271.96 °C
Thus, the temperature of the gas will be -271.96 °C
A spy satellite is orbiting earth and experiences a gravitation Force F if a similar satellite with one half the mass is placed in an orbit that is twice as far from the earths center the gravitational force between the earth and the second satellite will be what multiple of F?
The gravitational force on the second satellite is 1/8 of the force exerted on the 1st satellite.
Explanation:
The magnitude of the gravitational force exerted by the Earth on the satellite is given by:
[tex]F=G\frac{Mm}{r^2}[/tex]
where
G is the gravitational constant
M is the Earth's mass
m is the mass of the satellite
r is the radius of the orbit of the satellite
Let's call F the gravitational force on the first satellite, of mass m, with an orbit of radius r.
The second satellite has mass
[tex]m'=\frac{m}{2}[/tex]
and the radius of its orbit is
[tex]r'=2r[/tex]
So, the gravitational force exerted on the second satellite is
[tex]F'=G\frac{M(\frac{m}{2})}{(2r)^2}=\frac{1}{8}(\frac{GMm}{r^2})=\frac{1}{8}F[/tex]
Therefore, the force on the second satellite is 1/8 of the force exerted on the 1st satellite.
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The combination of foods and beverages that constitute an individual’s complete dietary intake over time is known as
Eating Pattern
Mediterranean Diet
Dietary Guidelines
Healthy Intake
Answer:
The combination of foods and beverages that constitute an individual’s complete dietary intake over time is known as Eating pattern.
So, option A is the correct answer.
Explanation:
The Eating pattern is also called Dietary Pattern. Normal eating pattern may be three meals a day, may increased or changed according to the individual, and may refer to overeating.
Dietary guidelines are nutritional guidelines which advice an individual, greater than 2 years, consume a healthy and nutritional diet.
Mediterranean diet is the diet typical to Mediterranean countries, in which there is high consumption of vegetables, fruits, seeds, legumes, nuts and olive. It consists of moderate amounts of carbohydrates and proteins and a moderate to high amount of fats.
A healthy intake is a healthy diet in which the energy from sugars is less than 10% of the total energy intake.
Hence, Option A is the correct answer.
A 1.0-kg block of aluminum is at a temperature of 50 Celsius. How much thermal energy will it lose when it’s temperature is reduced by half?
Answer:
The lose of thermal energy is, Q = 22500 J
Explanation:
Given data,
The mass of aluminium block, m = 1.0 kg
The initial temperature of block, T = 50° C
The final temperature of the block, T' = 25° C
The change in temperature, ΔT = 50° C - 25° C
= 25° C
The specific heat capacity of aluminium, c = 900 J/kg°C
The formula for thermal energy,
Q = mcΔT
= 1.0 x 900 x 25
= 22500 J
Hence, the lose of thermal energy is, Q = 22500 J
The thermal energy loose by the aluminum block will be Q = 22500 J
What will be the amount of energy aluminum block will lose?It is given that Given data,
The mass of the aluminum block, m = 1.0 kg
The initial temperature of the block, T = 50° C
Since the temperature of the block is halved then,
The final temperature of the block, T' = 25° C
The change in temperature, ΔT = 50° C - 25° C = 25° C
The specific heat capacity of aluminum,
c = 900 J/kg°C
The formula to find out the thermal energy will be
[tex]Q=m\times c\times\Delta T[/tex]
[tex]Q=1.0\times 900\times 25[/tex]
[tex]Q= 22500J[/tex]
Thus the thermal energy loose by the aluminum block will be Q = 22500 J
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a jet has a mass of 40000 kilograms the thrush pushing force of each of the four engines is 20000 Newtons what is the Jets acceleration when taking off
Imagine a place in the cosmos..far from all gravitational and frictional influences..Suppose that you visit that place (just suppose)...and throw a rock.
What will the rock do? Why?
After the initial push, the rock will keep moving forever at constant velocity (constant speed in a straight line)
Explanation:
We can answer this question by using Newton's first law of motion:
"An object at rest (or in motion at constant velocity) will stay at rest (or will keep moving at constant velocity) unless acted upon unbalanced forces" (Law of inertia)
In this problem, we have a rock in a place very far from any force that can act on it. This means that there are no unbalanced force acting on it, so the rock will keep its state of motion forever.
In this situation, the rock is initially thrown by the astronaut. After the initial push, which accelerates the rock up to a certain velocity, there will be no more forces acting on the rock. This means that the rock will continue moving at a constant velocity forever, so at a constant speed in a straight line.
Learn more about Newton laws of motion:
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What can electromagnetic radiation, which moves as electromagnetic waves, move through?
A. only space
B. both air and space
C. only air
Answer:
i think its B
Answer:
B. both air and space
Explanation:
Electromagnetic waves propagate through an oscillation of electric and magnetic fields. Therefore, they do not need a material means to propagate, thanks to this we can observe the light emitted by a distant star. In other words, they can travel through vaccum space or a medium like air.
Leah is making a chart to compare and contrast renewable and non-renewable resources. Which of the following would best complete the chart? Renewable Resources Non-renewable Resources __ Used faster than they can be replaced Most sources do not emit greenhouse gases Availability decreases over time Includes solar power, wind power, and geothermal power Includes fossil fuels, natural gas, and coal
Renewable resources can be replaced as quickly as they are used, while non-renewable resources are being used up faster than they can be made by nature.
Explanation:Renewable resources are those that can be replaced by natural processes as quickly as humans use them. Examples include solar power, wind power, and geothermal power. On the other hand, non-renewable resources are consumed or used up faster than they can be made by nature. Examples include fossil fuels such as coal, natural gas, and oil. These resources take millions of years to form and are being used up at a much faster rate than they can be replenished.
A deputy sheriff rides a horse while directing traffic, what energy is being used?
Answer:
Kinetic Energy
Explanation:
In relation to the question, as the sheriff rides a horse, the sheriff is in motion and a body in motion is said top possess kinetic energy.
Kinetic energy is that energy of the body that it gains due to the motion or speed of the body which it gains and maintains.
In other words, we can say that the amount of work needed to accelerate an object from its position of rest and set it into motion at some certain velocity.
A 5.5Kg block is hanging from a rope that is wrapped around the outside of a 13Kg flywheel disk witha radius of 33cm that is hagning form the ceilin. Friction in the flywheel provides a constant torque of 2.5Nm. When the block is released what is the magnitude of its acceleration as it falls
Answer:
[tex]3.9m/s^{2}[/tex]
Explanation:
Using second law of motion
[tex]a =\frac {m1 * g - \frac {T}{r}}{m1 + 0.5 * m2}[/tex] where m1 is mass of block, m2 is mass of flywheel, g is acceleration due to gravity whose value is taken as [tex]9.81 m/s^{2}[/tex], T is torque and r is radius
Substituting 5.5 Kg for m1, 13 Kg for m2, 0.33 m for r, 2.5 Nm for T we obtain
[tex]a = \frac {5.5 \times 9.81 - \frac {2.5}{0.33}}{(5.5 + 0.5 \times13)}=3.9m/s^{2}[/tex]
To find the acceleration of the 5.5 kg block, we consider both gravitational force and frictional torque acting on a 13 kg flywheel. The calculated acceleration of the block is approximately 2.73 m/s².
To determine the magnitude of the acceleration of the 5.5 kg block as it falls, we need to consider several forces and torques involved in the system. These include the gravitational force on the block, the tension in the rope, the rotational inertia of the flywheel, and the frictional torque opposing the motion.
First, let’s identify the key forces:
Gravitational force on the block (Fg): Fg = mblock * g = 5.5 kg * 9.8 m/s² = 53.9 NFrictional torque (τfriction): τfriction = 2.5 NmThe rotational inertia (I) of the flywheel (a disk) is given by:
I = 0.5 * mflywheel * r² = 0.5 * 13 kg * (0.33 m)² = 0.70785 kg·m²
Applying Newton’s second law for rotation, we have:
∑τ = I * α → τtension - τfriction = I * α
Here, τtension is the torque due to the tension in the rope, which is equal to T * r. Hence, we have:
T * r - τfriction = I * α
Also, the linear acceleration (a) of the block is related to the angular acceleration (α) of the flywheel by the equation:
a = α * r
Combining these equations, we get:
T * r - τfriction = I * (a / r)
Solving for T in terms of a:
T = (I * a / r²) + (τfriction / r)
Newton’s second law for the falling block gives us:
mblock * g - T = mblock * a
Substitute T from the earlier equation into this one and solve for a:
mblock * g - [(I * a / r²) + (τfriction / r)] = mblock * a
Rearranging terms to isolate a:
a = [mblock * g - (τfriction / r)] / [mblock + (I / r²)]
Substitute the known values:
mblock = 5.5 kgg = 9.8 m/s²τfriction = 2.5 NmI = 0.70785 kg·m²r = 0.33 ma = [5.5 kg * 9.8 m/s² - (2.5 Nm / 0.33 m)] / [5.5 kg + (0.70785 kg·m² / (0.33 m)²)]
a ≈ 2.73 m/s²
Thus, the magnitude of the acceleration of the block as it falls is approximately 2.73 m/s².