Answer:
n = 1.27
Explanation:
just took test :)
Answer:
N= 1.27
Explanation:
The primary coil of a transformer has N1 = 275 turns, and its secondary coil has N2 = 2,200 turns. If the input voltage across the primary coil is Δv = (160 V)sin ωt, what rms voltage is developed across the secondary coil?
Answer:
Secondary voltage of transformer is 905.23 volt
Explanation:
It is given number of turns in primary of transformer [tex]N_1=275[/tex]
Number of turns in secondary [tex]N_2=2200[/tex]
Input voltage equation of the transformer
[tex]\Delta v=160sin\omega t[/tex]
Here [tex]v_{max}=160volt[/tex]
[tex]v_{rms}=\frac{160}{\sqrt{2}}=113.15volt[/tex]
For transformer we know that
[tex]\frac{V_1}{V_2}=\frac{N_1}{N_2}[/tex]
[tex]\frac{113.15}{V_2}=\frac{275}{2200}[/tex]
[tex]V_2=905.23Volt[/tex]
Therefore secondary voltage of transformer is 905.23 volt