A reciprocating engine of 750mm stroke runs at 240 rpm. If the length of the connecting rod is 1500mm find the piston speed and acceleration when the crank is 45 past the top dead center position.

The answer is c) atomic number

Answer:

the advantages of using multistage compression refrigeration system over a single stage compression system are as follows:

Explanation:

Answer:

The given blanks can be filled as given below

Voltmeter must be connected in parallel

Explanation:

A voltmeter is connected in parallel to measure the voltage drop across a resistor this is because in parallel connection, current is divided in each parallel branch and voltage remains same in parallel connections.

Therefore, in order to measure the same voltage across the voltmeter as that of the voltage drop across resistor, voltmeter must be connected in parallel.

Answer:

a)COP=5.01

b)[tex]W_{in}=2.998[/tex] KW

c)COP=6.01

d)[tex]Q_R=17.99 KW[/tex]

Explanation:

Given

[tex]T_L[/tex]= -12°C,[tex]T_H[/tex]=40°C

For refrigeration

  We know that Carnot cycle is an ideal cycle that have all reversible process.

So COP of refrigeration is given as follows

[tex]COP=\dfrac{T_L}{T_H-T_L}[/tex]  ,T in Kelvin.

[tex] COP=\dfrac{261}{313-261}[/tex]

a)COP=5.01

Given that refrigeration effect= 15 KW

We know that  [tex]COP=\dfrac{RE}{W_{in}}[/tex]

RE is the refrigeration effect

So

5.01=[tex]\dfrac{15}{W_{in}}[/tex]

b)[tex]W_{in}=2.998[/tex] KW

For heat pump

So COP of heat pump is given as follows

[tex]COP=\dfrac{T_h}{T_H-T_L}[/tex]  ,T in Kelvin.

[tex] COP=\dfrac{313}{313-261}[/tex]

c)COP=6.01

In heat pump

Heat rejection at high temperature=heat absorb at  low temperature+work in put

[tex]Q_R=Q_A+W_{in}[/tex]

Given that [tex]Q_A=15[/tex]KW

We know that  [tex]COP=\dfrac{Q_R}{W_{in}}[/tex]

[tex]COP=\dfrac{Q_R}{Q_R-Q_A}[/tex]

[tex]6.01=\dfrac{Q_R}{Q_R-15}[/tex]

d)[tex]Q_R=17.99 KW[/tex]

Answer:

0.25 J/K

Explanation:

Given data in given question

heat (Q) = 100 J

temperature (T) = 400 K

to find out

the change in entropy of the given system

Solution

we use the entropy change equation here i.e  

ΔS = ΔQ / T           ...................a

Now we put the value of heat (Q) and Temperature (T) in equation a

ΔS is the entropy change, Q is heat and T is the temperature,  

so that

ΔS = 100/400 J/K

ΔS = 0.25 J/K

The no-slip condition is the viscosity of a fluid.This is most likely brought on by stress or stressful situations.

Answer/Explanation:

The no-slip condition for viscous fluids assumes that at a solid boundary, the fluid will have zero velocity relative to the boundary. Along with a flow when adhesion is stronger than cohesion. ... Basically the molecules of the fluid crash into the molecules of the wall and get stopped.

Answer:

True

Explanation:

when we write equation of motion we have to assume frame of reference as because frame of reference  is the property that in frame of reference the body is not accelerated and net force acting on the body is zero.

when body is assumed to be any frame of reference we can assume the body is at rest and moving with constant speed.

Answer:

true

Explanation:

hope this helped , God bless

Answer:

Chips are of three types --

1. Continuous chip

2. Discontinuous or segmental chip

3.  Continuous chip with built up edge

Explanation:

Conventional machining process always removes some excess part of the metal in the form of Chips. Every machinist should be well aware of the type of chip formed as it gives the knowledge of the machining process. The chips forms give the knowledge of --

1. Dimension of tool

2. feed rate

3. cutting speed

4. nature of tool

5. Friction between tool and work piece

the different types of chips are :

1. Continuous chips :

  Continuous chips are long ribbon like coil that are bonded together. The continuous chips undergoes plastic deformation continuously. This is the most desirable form of chip produced. When such chips are formed, the  cutting is smooth with good surface finish. Mostly ductile material forms continuous chips.

2. Discontinuous chips :

   Discontinuous chips are formed when metals are machined and the material gets deformed easily. Brittle materials forms discontinuous chips. Discontinuous chips are in the form of loose broken chips that are not continuous. Discontinuous chips are formed when depth of cut and feed is large and cutting sped is low.

3. Continuous chips with built up edge :

   These chips are similar to the continuous chips where surface finish is not smooth. When ductile materials are machined at low cutting speed, a portion of work material tends tends to stick at the rake face of the tool due to the friction between the tools and the chip. This is known as built up edge.

Answer:

Some of the irreversibilities are listed below:

Answer:

(a) 5 m/sec

Explanation:

we have given r=1 meter

angular velocity ω =5 revolution/sec

we have to find the velocity of turbine blade tip

the velocity of turbine blade tip is given by v =rω

where v = velocity of turbine blade tip

           r = radius

          ω = angular velocity

so v =5×1= 5 meter/sec

so the option (a) will be the correct option as in option (a) velocity is given as 5 meter/sec

Answer:

volumetric efficeincy = 0.315%

Explanation:

Given data:

outside diameter = 4.25 inch

inside diameter = 3.25 inch

flow rate V = 1800 rpm

actual flow rate Qa = 29gpm = 6699 inch3/min

volume of pump can be determine by using below formula

[tex]VOLUME = \frac{\pi}{4}*(D_{0}^{2}-D_{1}^{2})L[/tex]

              [tex]=\frac{\pi}{4}*(4.25^{2}-3.25^{2})2[/tex]

[tex]VOLUME = 11.78 inc^{3}[/tex]

theoretical flow rate is given as Qt

[tex]Q_{T} = V.N[/tex]

         = 11.78*1800

         =[tex]21204 inch ^{3}/ min[/tex]

[tex]volumetric efficeincy = \frac{Q_{A}}{Q_{T}}[/tex]

                                   [tex]=\frac{6699}{21204}[/tex]

volumetric efficeincy = 0.315%

Answer:  

  Degree of crystallinity affects polymer properties as increasing in   crystallinity means higher the thermal stability and harder the material. Basically, crystallinity strongly affects polymer properties as it defines the degree of long range order in a material. Crystallinity is also determined by the size as well as molecular chain orientation.

Answer:

True

Explanation:

Shear force diagram is a diagram which is drawn by calculating the shear force either to the right of the section or to the left of the section .

shear force is also be define as the change of moment w.r.t to distance

                              V=[tex]\frac{\mathrm{d}M }{\mathrm{d} x}[/tex]

where V is shear force and M is bending moment.

from the equation we can clearly say that shear force diagram is slope of bending moment diagram.

Explanation:

(a)

The measure of material's ability to conduct thermal energy (heat) is known as thermal conductivity. For examples, metals have high thermal conductivity, it means that they are very efficient at conducting heat. The SI unit of heat capacity is W/m.K.

The expression for thermal conductivity is:

[tex]q=-\kappa \bigtriangledown T[/tex]

Where,

q is the heat flux

[tex]\kappa[/tex] is the thermal conductivity

[tex] \bigtriangledown T[/tex] is the temperature gradient.

(b)

Heat capacity for a substance is defined as the ratio of the amount of energy required to change the temperature of the substance and the magnitude of temperature change. The SI unit of heat capacity is J/K.

The expression for Heat capacity is:

[tex]C=\frac{E}{\Delta T}[/tex]

Where,

C is the Heat capacity

E is the energy absorbed/released

[tex]\Delta T[/tex] is the change in temperature

(c)

Thermal diffusivity is defined as the thermal conductivity divided by specific heat capacity at constant pressure and its density. The Si unit of thermal diffusivity is m²/s.

The expression for thermal diffusivity is:

[tex]\alpha=\frac{\kappa}{C_p \times \rho}[/tex]

Where,

[tex]\alpha[/tex] is thermal diffusivity

[tex]\kappa[/tex] is the thermal conductivity

[tex]C_p[/tex] is specific heat capacity at constant pressure

[tex]\rho[/tex] is density

Answer:

true

Explanation:

Shear strains and direct strains are independent components in a strain tensor at a point. Also the poisson ratio is defined as

μ = - [tex]\frac{lateral strain}{longitudinal strain}[/tex]

Which is independent of shear strains Thus this affect does not apply on shear strains

Answer:2058.992KJ

Explanation:

Given data

Mass of object[tex]\left ( m\right )[/tex]=521kg

initial velocity[tex]\left ( v_0\right )[/tex]=90m/s

Final velocity[tex]\left ( v\right )[/tex]=14m/s

kinetic energy of body is given by=[tex]\frac{1}{2}[/tex][tex]m[/tex][tex]v^{2}[/tex]

change in kinectic energy is given by substracting  final kinetic energy from initial kinetic energy of body.

Change in kinetic energy=[tex]\frac{1}{2}\times m[/tex][tex]\left ( V_0^{2}-V^2\right )[/tex]

Change in kinetic energy=[tex]\frac{1}{2}\times521[/tex][tex]\left ( 90^{2}-14^2\right )[/tex]

Change in kinetic energy=2058.992KJ

STP stands for standard temperature pressure and NTP stands for normal temperature pressure

Answer:

0 K

Explanation:

The thermodynamic absolute temperature is that temperature  at which there is an infinite cooling and so there is no movement of any molecules or particles it is given by kelvin. 0 K is that temperature at which there is no movement of molecule so 0 K or -273°C in degree Celsius is the absolute temperature in thermodynamic temperature scale.  

Answer:

Design of Experiment also known as DoE is a systematic methodology to understand how any process or parameters of any product affects the response variables like physical properties or performance of any product, etc. It serves the purpose of making the job easier.

It is technique to generate valuable information required with minimum experimentation with the use of these:

Process Optimization:

It includes the following:

Answer:

(B) FALSE

Explanation:

view factor [tex]F_{ij}[/tex] depends on the surface emissivity and the surface of geometry  view factor is the term used in radiative heat transfer. View factor is depends upon the radiation which leave the surface and strike the surface.View factor is also called shape factor configuration factor it is denoted by  [tex]F_{ij}[/tex]

Answer:

Explained

Explanation:

Cold working: It is plastic deformation of material at temperature below   recrystallization temperature. whereas hot working is deforming material above the recrystallization temperature.

Given melting point temp of lead is 327° C and lead recrystallizes at about

0.3 to 0.5 times melting temperature which will be higher that 20°C. Hence we can conclude that at 20°C lead will under go cold working only.

Answer:

a) [tex]T_2=569.35 K[/tex]

b)Work done per kg of air=196.84 KJ/Kg

Explanation:

Given: [tex]\gamma =1.4[/tex] for air.

[tex]P_1=90 KPa ,T_=22^\circ C,P_2=900 KPa[/tex]

We know that  

[tex]\dfrac{T_2}{T_1}=\left (\frac{P_2}{P_1}\right )^{\dfrac{{\gamma-1}}{\gamma}}[/tex]

So  [tex]\dfrac{T_2}{295}=\left (\frac{900}{90}\right )^{\dfrac{{1.4-1}}{1.4}}[/tex]

[tex]T_2=569.35 K[/tex]

(a) [tex]T_2=569.35 K[/tex]

(b)Work for adiabatic process

  W=[tex]\frac{P_1V_1-P_2V_2}{\gamma -1}[/tex]

We know that PV=mRT for ideal gas.

 W=[tex]mR\frac{T_1-T_2}{\gamma -1}[/tex]

Now by putting values

work per kg of air=[tex]0.287\times \frac{295-569.35}{1.4 -1}[/tex]

Work w=-196.84 KJ/Kg    (Negative sign indicate work given to input.)

So work done per kg of air=196.84 KJ/Kg

Answer:

Q = 378.247 Bt/hr

Explanation:

given data:

diameter of container = 3 m

so r =  1.5 m

T1 = 50°C

T2 = 100°C

depth y = 3 ft

Heat transfer is given as Q

[tex]Q = SK\Delta T[/tex]

Where

S =  Shape factor for the object

[tex]S = \frac{4\pi r}{1-\frac{r}{2y}}[/tex]

[tex]S = \frac{4\pi *1.5}{1-\frac{1.5}{2*3}}[/tex]

S = 25.132 ft

[tex]Q = SK\Delta T[/tex]

Q = 25.132*0.301 *(100-50)

Q = 378.247 Bt/hr

Answer:

The surface temperature is 921.95°C .

Explanation:

Given:

   a=25 cm ,P=350 hp⇒P=260750 W

Power transmitted [tex]0.95\times 260750[/tex]W and remaining will lost in the form of heat.This heat transmitted to air by the convection.

 h=230[tex]\frac{W}{m^2-K},\eta =0.95[/tex]

Actually heat will be transmit by the convection.

In convection Q=hA[tex]\Delta T[/tex]

So [tex]P=\Delta T\times Q[/tex]

[tex]0.05\times 260750=230\times0.25^2\(T-15)[/tex]

T=921.95°C

So the surface temperature is 921.95°C .

Answer:

Absolute Pressure=315.06256 kPa

Explanation:

Gauge pressure= 31 psi

Atmospheric Pressure at Sea level= 1 atm=101.325 kPa

[tex]1\ psi=6.89476\ kPa\\\Rightarrow 31\ psi=31\times 6.89476\\\Rightarrow 31\ psi=213.73756\ kPa=Gauge\ Pressure\\Absolute\ Pressure=Gauge\ Pressure+Atmospheric\ Pressure\\\Rightarrow Absolute\ Pressure=213.73756+101.325\\\therefore Absolute\ Pressure=315.06256\ kPa[/tex]

Answer:

a) [tex]h_L=1.17m[/tex]

b)[tex]h_L=1.52m[/tex]

c)[tex]P_1=1.721 kN[/tex]

  [tex]P_2=2.236 kN[/tex]

Explanation:

velocities of the pipe;

velocity of small dia pipe

[tex]v_{small}=\frac{Q}{A_{small}} =\frac{0.15}{\frac{\pi}{4}\times d^2 }= \frac{0.15}{\frac{\pi}{4}\times 0.15^2 }=8.52m/s[/tex]

velocity of larger dia pipe

[tex]v_{large}=\frac{Q}{A_{large}} =\frac{0.15}{\frac{\pi}{4}\times d^2 }= \frac{0.15}{\frac{\pi}{4}\times 0.25^2 }=3.05m/s[/tex]

a) pressure head loss when water is flowing from large to smaller pipe

  [tex]h_L=(\frac{1}{C_c} -1)^2 \times \frac{v^2}{2g}[/tex]

[tex]h_L=(\frac{1}{0.64} -1)^2 \times \frac{8.52^2}{2\times 9.81} = 1.17m[/tex]

b) pressure head loss when water flow from small pipe to large pipe

[tex]h_L= \frac{v^2}{2g}(1-\frac{A_{small}}{A_{large}} )^2[/tex]

[tex]h_L=\frac{8.52^2}{2\times9.81}(1-\frac{\frac{\pi}{4}\times 0.15^2}{\frac{\pi}{4}\times 0.25^2}} )^2= 1.52 m[/tex]

c) power loss in both cases are

[tex]P_1= \rho g Q h_{L1}= 1000 \times 9.81\times 0.15\times 1.17= 1.721 kN[/tex]

[tex]P_2= \rho g Q h_{L2}= 1000 \times 9.81\times 0.15\times 1.52= 2.236 kN[/tex]

Answer:

output=[tex]\frac{2}{(s+3)(s+4)}[/tex]

Explanation:

output =transfer function ×input

here transfer function G=[tex]\frac{2}{(S+3)(S+4)} {}[/tex]

input = unit impulse

in S domain unit impulse =1

so output =[tex]\frac{2}{(S+3)(S+4)} {}[/tex]

=[tex]\frac{2}{(s+3)(s+4)}[/tex]

Answer:44.61 KJ

Explanation:

Let h_1,V_1,Z_1 be the initial specific enthalpy,velocity&elevation of the system

and h_2,V_2,Z_2 be the Final specific enthalpy,velocity&elevation of the system

mass(m)=7kg

Applying Steady Flow Energy Equation

[tex]m\left [ h_1+\frac{v_1^2}{2g}+gZ_1\right ][/tex]+Q=[tex]\left [ h_2+\frac{v_2^2}{2g}+gZ_2\right ][/tex]+W

[tex]h_1-h_2=4 KJ/kg[/tex]

[tex]V_1=13m/s[/tex]

[tex]V_2=23m/s[/tex]

[tex]Z_1-Z_2=40m[/tex]

substituting values

[tex]7\left [ h_1+\frac{13^{2}}{2g}+gZ_1\right ]+7\times2[/tex] = [tex]\left [ h_2+\frac{23^2}{2g}+gZ_2\right ][/tex]+W

W=[tex]7\left [h_1-h_2+\frac{V_1^2-V_2^2}{2000g}+g\frac{\left (Z_1-Z_2 \right )}{1000}\right ][/tex]+Q

W=[tex]7\left [4+\frac{13^2-23^2}{2000g}+g\frac{\left (40 \right )}{1000}[\right ][/tex]+[tex]2\times 7[/tex]

W=44.61KJ

Answer:

Explanation:

we have given E(t)=120 sin(12t)

R=5 ohm

L=0.2 H

ω=12 ( from expression of E)

[tex]X_L=0.2\times 12=2.4[/tex] ohm

[tex]X_C=\frac{1}{\omega \times C}=\frac{1}{12\times 0.043}=1.9379\ ohm[/tex]

[tex]Z=\sqrt{R^2+\left ( \omega L-\frac{1}{\omega C} \right )^2}[/tex]

[tex]Z=\sqrt{5^2+\left ( \2.4-1.9379 )^2}[/tex]

=5.021 ohm

so amplitude of current =  [tex]\frac{v}{z}=\frac{120}{5.021}=23.89[/tex]

Answer:

Fabrication method of composite materials varies for one product of material to other product. It is basically developed to meet the product requirement.

The fabrication of composite parts are depends upon different factors that are:

Types of fabrication methodologies are :