A rectangle is enlarged by a factor of 6 that originally has the area of 20in squared. What is the area of the enlarged rectangle?


A: 120in squared


B: 720in squared


C: 2,400in squared


D: 14,400in squared

Answer:

if you mean volume its 840

Step-by-step explanation:

i just multiplied the 3 numbers

This question is based on the slide reflection. Therefore, the correct option is (2), that is, translate 5 units down, and then reflect over the y-axis.

Given:

Reflect the triangle across the y-axis, and then translate the image 5 units down.

We have to choose the correct option as per given question.

According to the question,

It is a slide reflection.  

In this case, the order of sliding and reflection is not necessary, if the gliding is parallel to the line of reflection.

Hence, the equivalent to translate five units down, and then reflect over the y-axis.

In general,  that rotations will not be equivalent to an odd number of reflections.

Therefore, the correct option is (2), that is, translate 5 units down, and then reflect over the y-axis.

For more details, please refer this link:

https://brainly.com/question/8668014

Your answer is a right triangle, reason is because they usually use it for right triangles, not obtuse nor acute. Tangent ratio is used to find the length for the right triangle sides and it also gives the degree for each right triangle angle (right triangle has three angles, where there are 2 angles and 1 right angle.)

Hope this helped!

Nate

Answer:

The tangent ratio is used for right  triangles.

Step-by-step explanation:

We have been given an incomplete statement. We are supposed to fill in the given blank for statement using correct option.

Statement:

The tangent ratio is used for _  triangles.

We know that tangent is a trigonometric ratio, which represent relation between opposite side of right triangle to its adjacent side.

Therefore, the correct term for our given statement is 'right' and option C is the correct choice.

Shown below

No graph has been plotted, but the question is answerable either way and I'll be happy to help you. In this problem, we have the following inequality:

[tex]x-y-2\geq 0[/tex]

Before we focus on getting the shaded region, let's graph the equation of the line:

[tex]x-y-2=0[/tex]

So let's write this equation in slope intercept form [tex]y=mx+6[/tex]:

STEP 1: Write the original equation.

[tex]x-y-2=0[/tex]

STEP 2: Subtract -x from both sides.

[tex]x-y-2-x=0-x \\ \\ \\ Group \ like \ terms \ on \ the \ left \ side: \\ \\ (x-x) - y-2=-x \\ \\ The \ x's \ cancel \ out \ on \ the \ left: \\ \\ -y-2=-x[/tex]

STEP 3: Add 2 to both sides.

[tex]-y-2+2=-x+2 \\ \\ -y=-x+2[/tex]

STEP 4: Multiply both sides by -1.

[tex](-1)(-y)=(-1)(-x+2) \\ \\ y=x-2[/tex]

So, [tex]m=1[/tex] and [tex]b=-2[/tex]. The graph of this line passes through these points:

[tex]If \ x=0 \ then: \\ \\ y=x-2 \therefore y=(0)-2 \therefore y=-2 \\ \\ Passes \ through \ (0,-2) \\ \\ \\ If \ y=0 \ then: \\ \\ y=x-2 \therefore 0=x-2 \therefore x=2 \\ \\ Passes \ through \ (2,0)[/tex]

By plotting this line, we get the line shown in the first figure below. To know whether the shaded region is either above or below the graph, let's take point (0,0) to test this, so from the inequality:

[tex]x-y-2\geq 0 \\ \\ Let \ x=y=0 \\ \\ 0-0-2\geq 0 \\ \\ -2\geq 0 \ False![/tex]

Since this statement is false, then the conclusion is that the region doesn't include the origin, so the shaded region is below the graph as indicated in the second figure below. The inequality includes the symbol ≥ so this means points on the line are included in the region and the line is continuous.

Answer:

[tex]\large\boxed{y=-\dfrac{31}{5}x-8}[/tex]

Step-by-step explanation:

The slope-intercept form of an equation of a line:

[tex]y=mx+b[/tex]

m - slope

b - y-intercept - (0, b)

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

====================================

We have the points (0, -8) → b = -8, and (-5, 23).

Substitute:

[tex]m=\dfrac{23-(-8)}{-5-0}=\dfrac{31}{-5}=-\dfrac{31}{5}[/tex]

Put the value of the slope and of the y-intercept to the equation of a line:

[tex]y=-\dfrac{31}{5}x-8[/tex]

[tex]((5 \times 1) - (4 \times - 1) = \\ 5 - ( - 4) = \\ 5 + 4 = \\ 9[/tex]

Answer:

m=4

Step-by-step explanation:

11m - 15 -5m= 9

Combine like terms

6m -15 =9

Add 15 to each side

6m - 15+15 = 9+15

6m = 24

Divide each side by 6

6m/6 =24/6

m = 4

Answer:

D

Step-by-step explanation:

This is exponential growth, and to my understanding, the format goes:

initial amount (percent growth/ decay)^time

percent growth = (decimal percent + 1)

percent decay = (1 - decimal percent)

Your equation:

1500(1.02)^t

Using the above format, 1500 appears to be the initial amount, which increases by 2% per annum.

i think

Answer:

The correct option is A

Step-by-step explanation:

The given expression is:

√10/4√8

We have to eliminate the √ from the denominator

4√8 = (2^3)^1/4

Multiply the whole expression by (2)^1/4

=(2)^1/4 * √10/ 2^(1/4)*(2^3)^(1/4)

= 2^(1/4) · 10^(2/4)  / 2^1/4+3/4

=2^(1/4) · 10^(2/4) / 2^1+3/4

=2^(1/4) · 10^(2/4) / 2^4/4

=2^(1/4) · 10^(2/4) /2

=2^(1/4) · 100^(1/4) /2

=200^1/4 /2

= 4√200 /2

Thus the correct option is A....

Answer:

correct answer is a

Step-by-step explanation:

Answer with explanation:

Both the normal distribution curves have sample mean equal to 16.

Normal distribution curve 1 is more wider than Curve 2, resulting in greater standard deviation.

So, Curve 1 has the  greatest standard deviation.

The first normal distribution curve has the greatest standard deviation.

Standard deviation describes how far from the mean the given data set spread out.

Thus, we can conclude that the first normal distribution curve has the greatest standard deviation.

Learn more about normal distribution curve here: https://brainly.com/question/14644201

Answer:

75 cubic centimeters

Step-by-step explanation:

Volume of a cone is the area of the base times a third of the height.

The base is a circle.

The formula for the area of a circle is [tex]\pi \cdot r^2[/tex].

We are given that we want to use [tex]3.14[/tex] for [tex]\pi[/tex] and

r=(diameter)/2=6/2=3 cm.

So the area of the base is [tex]3.14 \cdot 3^2=28.26[/tex].

Now the height of the cone is 8 cm.

A third of the height is 8/3 cm.

So we want to compute area of base times a third of the height.

Let's do that:

[tex]\frac{8}{3} \cdot 28.26[/tex]

75.36 cubic centimeters

To the nearest cubic centimeters this is 75

To calculate the volume of a cone, we use the formula for the volume of a cone, which is:
\[ V = \frac{1}{3} \pi r^2 h \]
Where:
- \( V \) is the volume of the cone
- \( \pi \) is the constant Pi (approximated as 3.14)
- \( r \) is the radius of the cone's base
- \( h \) is the height of the cone
Given that the diameter of the cone is 6 cm, we find the radius by dividing the diameter by 2:
\[ r = \frac{diameter}{2} = \frac{6 cm}{2} = 3 cm \]
Now we have the radius and the height (which is given as 8 cm), we can substitute these values into the formula:
\[ V = \frac{1}{3} \pi r^2 h = \frac{1}{3} \times 3.14 \times (3 cm)^2 \times 8 cm \]
First, square the radius:
\[ (3 cm)^2 = 9 cm^2 \]
Now, perform the multiplication:
\[ V = \frac{1}{3} \times 3.14 \times 9 cm^2 \times 8 cm \]
\[ V = 3.14 \times 3 cm^2 \times 8 cm \]
\[ V = 9.42 cm^2 \times 8 cm \]
\[ V = 75.36 cm^3 \]
Finally, you want to round the volume to the nearest cubic centimeter. Since \( 75.36 \) is already a decimal to the nearest hundredth and has no fractional part in cubic centimeters, we simply round it to the nearest whole number:
\[ V \approx 75 \]
So, the volume of the cone is approximately \( 75 \) cubic centimeters.

Answerits not

Step-by-step explanation:

Answer:

Step 1: 5

Step 2: -1/5

Step 3: 2/3

Step 4: 2/3

Only one pair of opposite sides is parallel

Step-by-step explanation:

Answer:

4x - 3y = 5

Step-by-step explanation:

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

First obtain the equation in point- slope form

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 1, - 3) and (x₂, y₂ ) = (2, 1)

m = [tex]\frac{1+3}{2+1}[/tex] = [tex]\frac{4}{3}[/tex]

Using (a, b) = (2, 1), then

y - 1 = [tex]\frac{4}{3}[/tex] (x - 2) ← in point- slope form

Multiply both sides by 3

3y - 3 = 4(x - 2) ← distribute and rearrange

3y - 3 = 4x - 8 ( add 8 to both sides )

3y + 5 = 4x ( subtract 3y from both sides )

5 = 4x - 3y, so

4x - 3y = 5 ← in standard form

Sure, let's find the equation of the line that passes through the points (-1, -3) and (2, 1) step-by-step.
1. First, calculate the slope (m) of the line using the formula:
  \[
  m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - (-3)}{2 - (-1)}
  \]
  \[
  m = \frac{1 + 3}{2 + 1} = \frac{4}{3}
  \]
2. The slope-intercept form of a line equation is \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
  We already found the slope \( m = \frac{4}{3} \), so we just need to find \( b \).
  Using the first point (-1, -3), plug the values into the slope-intercept form:
  \[
  -3 = \frac{4}{3}(-1) + b
  \]
  Calculate \( b \):
  \[
  -3 = -\frac{4}{3} + b
  \]
  Add \( \frac{4}{3} \) to both sides:
  \[
  b = -3 + \frac{4}{3}
  \]
  \[
  b = -\frac{9}{3} + \frac{4}{3}
  \]
  \[
  b = -\frac{5}{3}
  \]
3. Now we have \( y = \frac{4}{3}x - \frac{5}{3} \) in slope-intercept form.
4. Next, we will convert this to standard form, which is \( Ax + By = C \), where \( A \), \( B \), and \( C \) are integers, and \( A \) is positive.
  Multiply both sides of the slope-intercept equation by 3, the common denominator, to eliminate fractions:
  \[
  3y = 4x - 5
  \]
5. Rewriting in standard form, we move the \( x \)-term to the left side:
  \[
  -4x + 3y = -5
  \]
6. In standard form, \( A \) should be positive. If we multiply the entire equation by -1, we will make \( A \) positive:
  \[
  4x - 3y = 5
  \]
7. This is already simplified since the greatest common divisor (GCD) of 4, -3, and 5 is 1. Thus, the coefficients are already in their simplest integer values.
The final equation for the line in standard form is:
\[ 4x - 3y = 5 \]

Answer:

a. 8g 1dg 3cg 3mg

b. 11dag 8g

c. 24kg 9hg

d. 7kg 1hg

Step-by-step explanation:

Answer:

a. 8g 1dg 3cg 3mg  

b. 11dag 8g  

c. 24kg 9hg  

d. 7kg 1hg

Step-by-step explanation:

got it from the other person

Answer:

domain of (f O g)(x) is {x|x≠0}

Step-by-step explanation:

Given:

f(x) = x + 7

g(x) = 1/x -13

Putting g(x) in f(x) i.e f(g(x))

(fog)(x)= 1/x -13 +7

          = 1/x-6

Domain of 1/x-6 is {x|x≠0} !

For this case we have the following functions:

[tex]f (x) = x + 7\\g (x) = \frac {1} {x} -13[/tex]

We must find [tex](f_ {0} g) (x).[/tex] By definition we have to:

[tex](f_ {0} g) (x) = f (g (x))[/tex]

So:

[tex](f_ {0} g) (x) = \frac {1} {x} -13 + 7 = \frac {1} {x} -6[/tex]

By definition, the domain of a function is given by all the values for which the function is defined.

The function [tex](f_ {0} g) (x) = \frac {1} {x} -6[/tex] is no longer defined when x = 0.

Thus, the domain is given by all real numbers except zero.

Answer:

x nonzero

Answer:

[tex]\large\boxed{\sqrt{-36}+\sqrt{-100}+7=7+16i}[/tex]

Step-by-step explanation:

[tex]\sqrt{-1}=i\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\=====================\\\\\sqrt{-36}=\sqrt{(36)(-1)}=\sqrt{36}\cdot\sqrT{-1}=6i\\\sqrt{-100}=\sqrt{(100)(-1)}=\sqrt{100}\cdot\sqrt{-1}=10i\\\\\sqrt{-36}+\sqrt{-100}+7=6i+10i+7=7+16i[/tex]

Answer:

The answer is [tex]16i+7[/tex]

Step-by-step explanation:

In order to determine the answer, we have to know about imaginary numbers.

The imaginary numbers are different to real numbers because they use a new unit called "imaginary unit":

[tex]i=\sqrt{-1}[/tex]

i: imaginary unit

This new unit is applied like a factor when we have even roots with negative numbers inside.

In this case:

[tex]\sqrt{-36}=\sqrt{-1}*\sqrt{36}=6i\\\sqrt{-100}=\sqrt{-1}*\sqrt{100}=10i\\   \\\sqrt{-36}+\sqrt{-100}+7\\ 6i+10i+7\\16i+7[/tex]

Finally, the answer is [tex]16i+7[/tex]

Answer:

1 and 4

5 and 8  are alternate exterior angles

2 and 3

6 and 7 are alternate interior angles

Step-by-step explanation:

The alternate exterior angles are the angles on the outside that are opposite each other

1 and 4 are alternate exterior angles

5 and 8 are alternate exterior angles

The alternate interior angles are the angles on the inside that are opposite each other

2 and 3 are alternate interior angles

6 and 7 are alternate interior angles

Answer:

1 and 4 , 5 and 8

Step-by-step explanation:

Answer:

[tex]\frac{1}{2}[/tex] x²

Step-by-step explanation:

let the length of the side be l

Then using Pythagoras' identity on the right triangle formed by the diagonal ( hypotenuse ) and the 2 sides

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

l² + l² = x²

2l² = x² ( divide both sides by 2 )

l² = [tex]\frac{1}{2}[/tex] x² ( since A of square = l² )

Answer:

C

Step-by-step explanation:

your answer will be option number

(3) {(1,1),(2,9),(4,8)}

I hopes its help's u

please follow me..!!

@Abhi.❤❤

Answer:

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

To calculate m use the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

3

Using (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (- 3, 6)

m = [tex]\frac{6-0}{-3-0}[/tex] = [tex]\frac{6}{-3}[/tex] = - 2

Since the line passes through the origin (0, 0) then y- intercept is 0

y = - 2x ← equation of line

4

let (x₁, y₁ ) = (6, 0) and (x₂, y₂ ) = (0, 3)

m = [tex]\frac{3-0}{0-6}[/tex] = [tex]\frac{3}{-6}[/tex] = - [tex]\frac{1}{2}[/tex]

note the line crosses the y- axis at (0, 3) ⇒ c = 3

y = - [tex]\frac{1}{2}[/tex] x + 3 ← equation of line

5

let (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (-2, - 3)

m = [tex]\frac{-3-3}{-2-0}[/tex] = [tex]\frac{-6}{-2}[/tex] = 3

note the line crosses the y- axis at (0, 3) ⇒ c = 3

y = 3x + 3 ← equation of line

Answer:

ASA postulate

Step-by-step explanation:

The sum of the measures of interior angles of triangle is always 180°, so

∠LRT=180°-∠RTL-∠RLT=180°-∠2-∠4;

∠KST=180°-∠STK-∠SKT=180°-∠1-∠3.

Since

∠1≅∠2 and ∠3≅∠4, we have that ∠LRT ≅ ∠KST.

The ASA (Angle-Side-Angle) postulate states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent. (The included side is the side between the vertices of the two angles.)

In your case:

Triangles TKS and TLR are congruent by ASA postulate.

Answer:

Residual in this case is -4.215

Step-by-step explanation:

A residual can be defined by

Residual = Actual value - Predicted value

We are given:

Predicted value of y = 34.215

Actual value of y = 30

Putting values in the formula:

Residual = Actual value - Predicted value

Residual = 30 - 34.215

Residual = -4.215

So, residual in this case is -4.215

Answer:

27+4x+8y

or

4x+8y+27 ( I can reorder this a few different ways. I don't know what your choices are)

Step-by-step explanation:

11+4(x+2y+4)

We can apply distributive property to the 4(x+2y+4), this will give us 4x+8y+16.

Bring down the 11+ and we have 11+4x+8y+16.

The only like terms we have is 11 and 16.  So reorder using commutative property and get 11+16+4x+8y.

I'm going to simplify the 11+16 part which gives us 27.

In the end we have 27+4x+8y.

Let me line up so it is all nice and neat:

11+4(x+2y+4)

11+4x+8y+16

11+16+4x+8y

27+4x+8y

Answer:

We have the following equation: y = 36 - x. And we need to find which of the following points belong to the graph:

If any of the points belong to the equation, then the equality will be met.

Then:

7 = 36 - (-13)

7 = 36 + 13

7 = 49 ❌

1 = 36 - (-35)

1 = 71❌

5 = 36 - 11

5 = 25 ❌

3 = 36 - 27

3 = 9 ❌

None of the points belong to the graph. Therefore, all points are NOT on the grah of p(x) = 36 - x.

Answer:

ANSWER IS (-35,1)

Step-by-step explanation:

I got it because I am looking at the answer right now

Answer:

Option B - [tex]20\leq x\leq 24.60[/tex]  

Step-by-step explanation:

Given : Tyrese works each day and earns more money per hour the longer he works. Write a function to represent a starting pay of $20 with an increase each hour by 3%.

To find : Determine the range of the amount Tyrese makes each hour if he can only work a total of 8 hours.

Solution :

A starting pay is $20.

let x be the number of hours.

There is pay of $20 with an increase each hour by 3%.

i.e. Increment is [tex]\frac{3}{100}\times 20\times x=\frac{3}{5}x[/tex]

Total earnings a function can represent is

[tex]y=20+\frac{3}{5}x[/tex]

We have given, he can only work a total of 8 hours.

So, The maximum amount she make in 8 hours is

[tex]y=20+\frac{3}{5}\times 8=20+4.8[/tex]

[tex]y=24.8[/tex]

Initial amount is $20.

Therefore, The range of the amount Tyrese makes each hour if he can only work a total of 8 hours is [tex]20\leq x\leq 24.80[/tex]

So, Approximately the required result is option B.

Answer: Second Option

[tex]f (x)=\frac{2}{x}[/tex] and [tex]g(x)=\frac{2}{x}[/tex]

Step-by-step explanation:

If we have a function f(x) and its inverse function [tex]f ^ {- 1} (x) = g (x)[/tex]

Then by definition:

[tex](fog) (x) = (gof) (x) = x[/tex]

Notice that the inverse of the function [tex]f (x)=\frac{2}{x}[/tex] is [tex]f ^ {- 1}(x)=\frac{2}{x}[/tex]

then:

If [tex]f (x)=\frac{2}{x}[/tex] and [tex]g(x)=\frac{2}{x}[/tex]

Then:

[tex](fog) (x) =\frac{2}{\frac{2}{x}}[/tex]

[tex](fog) (x) =\frac{2x}{2}[/tex]

[tex](fog) (x) =x[/tex]

The answer is the second option

Answer:

Step-by-step explanation:

The slope-intercept form of an equation of a line:

[tex]y=mx+b[/tex]

m - slope

b - y-intercept

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

================================================

We have the points (-6, 4) and (2, 0).

Substitute:

[tex]m=\dfrac{0-4}{2-(-6)}=\dfrac{-4}{8}=-\dfrac{1}{2}[/tex]

Put the value of the slope and coordinates of the point (2, 0) to the equation of a line:

[tex]0=-\dfrac{1}{2}(2)+b[/tex]

[tex]0=-1+b[/tex]          add 1 to both sides

[tex]1=b\to b=1[/tex]

The equation of a line in the slope-intercept form:

[tex]y=-\dfrac{1}{2}x+1[/tex]

Convert to the standard form [tex]Ax+By=C[/tex]

[tex]y=-\dfrac{1}{2}x+1[/tex]           multiply both sides by 2

[tex]2y=-x+2[/tex]             add x to both sides

[tex]x+2y=2[/tex]

Answer:

Option 1.

Step-by-step explanation:

It is given that the line passes through the points (-6,4) and (2,0).

If a line passes through two points, then the equation of line is

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

Using the above formula the equation of line is

[tex]y-(4)=\dfrac{0-4}{2-(-6)}(x-(-6))[/tex]

[tex]y-4=\dfrac{-4}{8}(x+6)[/tex]

[tex]y-4=\dfrac{-1}{2}(x+6)[/tex]

Muliply both sides by 2.

[tex]2y-8=-x-6[/tex]

[tex]x+2y=-6+8[/tex]

[tex]x+2y=2[/tex]

Therefore, the correct option is 1.

Answer:

-1680

Step-by-step explanation:

Above would be positive.

Below would be negative.

You have 1680 below, so the answer as a signed number for the elevation would be -1680.

The signed number - 1680 feet addresses the excavator's exhuming point 1680 feet underneath ocean level (negative worth demonstrates beneath ocean level).

The signed number addressing the height of the point 1680 feet beneath ocean level is - 1680 feet. The negative sign demonstrates that the worth is beneath the reference point, which for this situation is ocean level.

With regard to heights, we utilize positive numbers to address positions over the reference point (ocean level) and negative numbers to address positions beneath it.

The miner dug downward in this scenario, lowering the elevation above sea level. Since it is below the reference point, the elevation is negative.

The greatness of - 1680 feet shows the separation from ocean level to the place of removal, and the negative sign demonstrates the bearing beneath ocean level.

Learn more about elevation here:

https://brainly.com/question/88158

#SPJ2

Answer:

x = -6 or x = 2

Step-by-step explanation:

The given equation is:

[tex]x^{2}+4x-4=8\\\\ x^2+4x-4-8=0\\\\ x^2+4x-12=0\\\\[/tex]

This is quadratic equation, so we can use the quadratic formula to find the roots of the equation i.e. the value of x that satisfy the given equation.

According to the quadratic formula, the two roots will be:

[tex]x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}[/tex]

Here,

a = coefficient of x² = 1

b = coefficient of x = 4

c = constant term = -12

Using these values, we get:

[tex]x=\frac{-4 \pm \sqrt{(4)^2-4(1)(-12)}}{2(1)}\\\\ x=\frac{-4 \pm \sqrt{64}}{2}\\\\ x=\frac{-4 \pm 8}{2}\\\\ x = \frac{-4-8}{2} , x = \frac{-4+8}{2}\\\\ x=-6, x = 2[/tex]

Thus, the two values of x that satisfy the given equation are: -6 and 2. So 1st option gives the correct answer.

Answers:

22

9

20

17

20

35

26

32

23

9