A roadway for stunt drivers is designed for racecars moving at a speed of 97 m/s. A curved section of the roadway is a circular arc of 420 m radius. The roadway is banked so that a vehicle can go around the curve with the friction force from the road equal to zero. At what angle is the roadway banked?

Answer:

The answer is GFCI

(ground fault circuit interrupter)

Explanation:

A ground fault circuit interrupter (GFCI) can help prevent electrocution.

If a person's body starts to receive a shock, the GFCI senses this and cuts off the power before he/she can get injured. GFCIs are generally installed where electrical circuits may accidentally come into contact with water.

What is a circuit breaker?

It is an automatically operated electrical switch designed to protect an electrical circuit from damage caused by excess current from an overload or short circuit. Its basic function is to interrupt current flow after a fault is detected.

Given Information:  

Elapsed time = t = 6 seconds

Required Information:

Distance = d = ?

Answer:

Distance = d = 2.058 km

Explanation:

We know that the speed of sound in the air is given by

v = 343 m/s

The relation between distance, speed and time is given by

distance = speed*time

substituting the given values yields,

distance = 343*6

distance = 2058 m

There are 1000 meters in 1 km so

d = 2058/1000

d = 2.058 km

Therefore, the storm is about 2.058 km away when elapse time between the lightning and the thunderclap is 6 seconds.

Answer:

4.7 N

Explanation:

130 g = 0.13 kg

The momentum of the snowball when it's thrown at the wall is

[tex]p = mv = 0.13*6.5 = 0.845 kgm/s[/tex]

Which is also the impulse. From here we can calculate the magnitude of the average force F knowing the duration of the collision is 0.18 s

[tex]p = F\Delta t[/tex]

[tex]F*0.18 = 0.845[/tex]

[tex]F = 0.845 / 0.18 = 4.7 N[/tex]

The term phenotype in a more specific context to describe the collective expression of the genotype in conjunction with the environment on a plant's observable characteristics.

Explanation:

Some of the phenotypic traits includes Height, color, shape.

Phenotype is a physical properties or expression of a gene in an individual.

Phenotype are features that is observable or can be seen. This could include the physical appearance where we have height, color, shape.

Phenotypic traits are the observable features such as plant height and eye color, hair color.

Therefore, some of the phenotypic traits that scientist can investigate are height, shape and color.

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Answer:

I disagree.

Explanation:

Yes, traits may be similar, but it all depends on the dominant and recessive alleles that are passed on.  No one person can look alike.  Even with twins, a widow's peak or close lobes can be different.

I hope this was the brainliest answer! Thank you for letting me help you.

The acceleration of the raindrop is equal to the acceleration due to gravity. The distance the raindrop has fallen in 3.00 seconds is 44.1 meters. The mass of the raindrop at 3.00 seconds is 88.2 grams.

To find the acceleration, we can use the given proposed solution for velocity, v = at. Taking the derivative of this equation with respect to time gives us dv/dt = a. Substituting this into the differential equation, we have xg = x(a) + v^2. Since the initial velocity is zero, v = 0 and the equation simplifies to xg = xa. Dividing by x, we get g = a. Therefore, the acceleration is equal to the acceleration due to gravity, g.

To find the distance the raindrop has fallen in t = 3.00 s, we can use the equation x = (1/2)at^2. Since we know the acceleration is g, we plug in the values into the equation: x = (1/2)(g)(3.00 s)^2 = (1/2)(9.8 m/s^2)(9.00 s^2) = 44.1 meters.

To find the mass of the raindrop at t = 3.00 s, we can use the given equation m = kx. Plugging in the values, m = (2.00 g/m)(44.1 m) = 88.2 grams.

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Answer:

a) time t1 = 2.14s

b) initial angular speed w1 = 6 rad/s

Explanation:

Given that;

Initial Angular velocity = w1

Angular distance = s = 65 rad

time = t = 5 s

Angular acceleration a = 2.80 rad/s^2

Using the equation of motion;

s = w1t + (at^2)/2

w1 = (s-0.5(at^2))/t

Substituting the values;

w1 = (65 - (0.5×2.8×5^2))/5

w1 = 6rad/s

Time to reach w1 from rest;

w1 = at1

t1 = w1/a = 6/2.8 = 2.14s

a) time t1 = 2.14s

b) initial angular speed w1 = 6 rad/s

Answer:

a. The wheel was turning 2.14 s before the start of the 5.00 s interval.

b. The angular velocity of the wheel at the start of the 5.00 s interval was 6.00 rad/s.

Explanation:

At the start of the 5.00s interval, the wheel might have an initial angular velocity [tex]\omega_0[/tex]. We can obtain it from the kinematic equation:

[tex]\theta=\omega_0t+\frac{1}{2}\alpha t^{2}\\\\\implies \omega_0=\frac{\theta}{t}-\frac{1}{2}\alpha t[/tex]

Plugging in the known values for the time interval, the angular displacement and the angular acceleration, we get:

[tex]\omega_0=\frac{65.0rad}{5.00s}-\frac{1}{2}(2.80rad/s^{2})(5.00s)\\\\\omega_0=6.00rad/s[/tex]

It means that the angular velocity of the wheel at the start of the 5.00 s interval was 6.00 rad/s (b).

The time it took for the wheel to reach that angular velocity can be obtained from another kinematic equation:

[tex]\omega = \omega_0+\alpha t\\\\\implies t=\frac{\omega-\omega_0}{\alpha}[/tex]

It is important to take in account that in this case, the initial angular velocity is zero as the wheel started from rest, and the final angular velocity is the one we got in the previous question:

[tex]t=\frac{6.00rad/s-0}{2.80rad/s^{2}}\\\\t=2.14s[/tex]

Finally, the wheel was turning 2.14 s before the start of the 5.00 s interval (a).

Answer:

Explanation:

The magnetic field due to a straight wire carrying current is given by

B = μo• I / 2πr

Where,

μo = permeability of free space

μo = 4π×10^-7 Tm/A

I is the current in wire

I = 5A

r Is the distance of point from the wire.

The distance between the parallel conductors and the point is r/2

R = 0.283/2 = 0.1415m

Check attachment on how I used Pythagoras theorem to find the diagonal of the square..

Hence, the magnetic field at point P is

B = μo•I / 2πR

B = 4π × 10^-7 × 5 / 2π × 0.1415

B = 7.07 × 10^-6 T.

Answer:

19/49

Explanation:

Using v = u + at  where v = velocity of ball after 5 s on planet X = 31 m/s, u = initial velocity of ball on planet X = 50 m/s , a = acceleration due to gravity on planet X and t = 5 s

So, 31 = 50 - a × 5 = 50 - 5a

31 - 50 = 5a

-19 = 5a

a = -19/5 = -3.8 m/s²

So, the magnitude of a = 3.8 m/s²

So a/g = 3.8/9.8 = 19/49

The fraction of the magnitude of the gravitational field near the surface of Planet X to the gravitational field near the surface of the Earth is 0.39.

Given the following data:

We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex]

To determine what fraction is the magnitude of the gravitational field near the surface of Planet X to the gravitational field near the surface of the Earth:

First of all, we would calculate the acceleration due to gravity (g) on Planet X by using first equation of motion:

Mathematically, the first equation of motion is calculated by using the formula;

[tex]V = U-at[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]31=50-a(5)\\\\5a =50-31\\\\5a=19\\\\a=\frac{19}{5}[/tex]

Acceleration, a = 3.8 [tex]m/s^2[/tex]

For the ratio:

[tex]Fraction = \frac{a}{g} \\\\Fraction = \frac{3.8}{9.8}[/tex]

Fraction = 0.39

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Answer:

The magnitude of the net force F₁₂₀ on the lid when the air inside the cooker has been heated to 120 °C is [tex]\frac{135.9}{A}N[/tex]

Explanation:

Here we have

Initial temperature of air T₁ = 20 °C = ‪293.15 K

Final temperature of air T₁ = 120 °C = 393.15 K

Initial pressure P₁ = 1 atm = ‪101325 Pa

Final pressure P₂ = Required

Area = A

Therefore we have for the pressure cooker, the volume is constant that is does not change

By Chales law

P₁/T₁ = P₂/T₂

P₂ = T₂×P₁/T₁ = 393.15 K× (‪101325 Pa/‪293.15 K) = ‭135,889.22 Pa

∴ P₂ = 135.88922 KPa = 135.9 kPa

Where Force = [tex]\frac{Pressure}{Area}[/tex] we have

Force = [tex]F_{120}=\frac{135.9}{A}N[/tex].

Answer:

v2 = 1.67m/s

she will travel at 1.67m/s afterwards

Explanation:

Given;

Mass of grandma m1 = 50kg

Mass of sack m2 = 10kg

Initial speed of grandma v1 = 2m/s

Final velocity of both = v2

The momentum equation of the initial and final momentum can be written as;

m1v1 = m1v2 + m2v2 = (m1+m2)v2

(Since the collision is inelastic they both move at the same velocity v2 after the collision)

making v2 the subject of formula;

v2 = (m1v1)/(m1+m2)

Substituting the values;

v2 = (50×2)/(50+10)

v2 = 1.67m/s

she will travel at 1.67m/s afterwards

Answer:

r = 6.5*10^-3 m

Explanation:

I'm assuming you meant to ask the diameters of the disk, if so, here's it

Given

Quantity of charge on electron, Q = 1.4*10^9

Electric field strength, e = 1.9*10^5

q = Q * 1.6*10^-19

q = 2.24*10^-10

E = q/ε(0)A, making A the subject of formula, we have

A = q / [E * ε(0)], where

ε(0) = 8.85*10^-12

A = 2.24*10^-10 / (1.9*10^5 * 8.85*10^-12)

A = 2.24*10^-10 / 1.6815*10^-6

A = 1.33*10^-4 m²

Remember A = πr²

1.33*10^-4 = 3.142 * r²

r² = 1.33*10^-4 / 3.142

r² = 4.23*10^-5

r = 6.5*10^-3 m

Answer:

0.552 m/s

Explanation:

Given,

Mass of the block = 2.05 Kg

initial compression, x₁ = 0.03690 m

Spring constant, k = 830 N/m

coefficient of friction of the block, μ = 0.380

distance moved by the block,x₂ = 0.20 m

Speed, v  = ?

Using conservation of energy

Initial spring energy + Work done by friction = Final spring energy + kinetic energy

[tex]\dfrac{1}{2}kx_1^2 - \mu mg x_2 = \dfrac{1}{2}kx_2^2 + \dfrac{1}{2}mv^2[/tex]

[tex]\dfrac{1}{2}\times 830\times 0.039^2 - 0.38\times 2.05\times 9.81\times 0.02 = \dfrac{1}{2}\times 830 \times 0.02^2 + \dfrac{1}{2}\times 2.05\times v^2[/tex]

v² = 0.3047

v = 0.552 m/s

Hence, the speed of the block is equal to 0.552 m/s

Answer:

a) 1.26e^-10F

b) 1.47e^-10F

c) 2.39e^-8C   2.89e^-8C

d) E=4500.94N/C

e) E'=5254.23N/C

f) 100.68V

g) 1.65e^-10J

Explanation:

To compute the capacitance we can use the formula:

[tex]C=\frac{k\epsilon_o A}{d}[/tex]

where k is the dielectric constant of the material between the plates. d is the distance between plates and A is the area.

(a) Before the material with dielectric constant is inserted we have that k(air)=1. Hence, we have:

[tex]k=1\\A=0.30m^2\\d=0.021m\\e_o=8.85*10^{-12}C^2/(Nm^2)\\\\C=\frac{(1)(8.85*10^{-12}C^2/(Nm^2))(0.30m^2)}{0.021m}=1.26*10^{-10}F[/tex]

(b) With the slab we have that k=4.8 and the thickness is 4mm=4*10^{-3}m. In this case due to the thickness of the slab is not the same as d, we have to consider the equivalent capacitance of the series of capacitances:

[tex]C=(\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_1})\\\\\\C_1=\frac{(1)(8.85*10^{-12}C^2/(Nm^2))(0.30m^2)}{8.5*10^{-3}m}=3.1*10^{-10}F\\\\C_2=\frac{(4.8)(8.85*10^{-12}C^2/(Nm^2))(0.30m^2)}{4*10^{-3}m}=3.186*10^{-9}F\\\\C=1.47*10^{-10}F[/tex]

(c)

The charge between the plates for both cases, with the slab is given by:

Q : without the slab

Q': with the slab

[tex]Q=CV=(1.26*10^{-10}F)(190V)=2.39*10^{-8}C\\\\Q'=C'V=(1.47*10^{-10F})(190V)=2.79*10^{-8}C\\[/tex]

(d) The electric field between the plate is given by:

[tex]E=\frac{Q}{2\epsilon_o A}[/tex]

E: without the slab

E': with the slab

[tex]E=\frac{2.39*10^{-8}C}{2(8.85*10^{-12}C^2/Nm^2)(0.30m^2)}=4500.94N/C\\\\E'=\frac{2.79*10^{-8}C}{2(8.85*10^{-12}C^2/Nm^2)(0.30m^2)}=5254.23N/C\\[/tex]

(f) We can assume the system as composed by V=V1+V'+V1 as in (c). By using the equation V=Ed we obtain:

[tex]V=2(4500.94)(8.85*10^{-3}m)+(5254.23)(4*10^{-3}m)=100.68V[/tex]

(g) External work is the difference between the energies of the capacitor before and after the slab is placed between the parallels:

[tex]\Delta E=\frac{1}{2}[(1.26*10^{-10}F)(120V)-(1.47*10^{-10})(100.6V)]=1.65*10^{-10}J[/tex]

Answer:

Density = 1464.8kg/m3

the density of the metal is 1464.8kg/m^3

Explanation:

Given;

Mass m = 450g

Density = Mass/Volume = m/V

Volume V = change in height × base area = ∆h × A

∆h = 4.8cm

A = 8×8 = 64cm^2

V = 4.8×64 = 307.2cm^3

Density = 450g/307.2cm^3

Density = 1.4648g/cm^3

Density = 1.4648 × 1000kg/m^3

Density = 1464.8kg/m3

the density of the metal is 1464.8kg/m^3

Answer:

1464.84 kg/m³

Explanation:

Density = mass/volume.

D = m/v................. Equation 1

But from Archimedes principle,

every object immersed in water will displaced an amount of water equal to its own volume

Therefore,

v = v'................... Equation 2

Where v = volume of the irregular object, v' = volume of water displaced.

Since the base of the container is a square,

Then,

v' = L²(d)...................... Equation 3

Where L = length of the square base of the container, d = rise in water level.

Substitute equation 3 into equation 1

D = m/L²d......................... Equation 4

Given: m = 450 g = 0.45 kg, L = 8 cm = 0.08 m, d = 4.8 cm = 0.048 m

Substitute into equation 4

D = 0.45/(0.08²×0.048)

D = 0.45/0.0003072

D = 1464.84 kg/m³

Answer:

Explanation:

Without seeing the options i can tell you this:

A balanced force is equal on both sides

The friction would equal the force

The amount on the left (friction side) would equal the amount on right (force side)

Or the net force would equal zero

You should post the answer options for more help

Answer: A book falls to the floor.

A car skids to a stop.

A foam ball launches

Explanation:

Answer:

As the electrons (tiny particles inside atoms) in the electric current wiggle back and forth along the antenna, they create invisibleelectromagnetic radiation in the form ofradio waves. ... 1) Electricity flowing into the transmitter antenna makes electrons vibrate up and down it, producing radio waves.

Answer:

As the electrons (tiny particles inside atoms) in the electric current wiggle back and forth along the antenna, they create invisible electromagnetic radiation in the form of radio waves.

Explanation:

Answer:

length of fin = 34.417

effectiveness = 33.77

Explanation:

the pictures attached below shows the whole explanation

Answer:

Oumuamua is outside the solar system which is in cigar shaped.

Hope it will help you :))

Every star, except the Sun, is outside the solar system.

Answer:

4.29×10⁵ C

Explanation:

From the question,

The energy stored in the battery = Kinetic energy of the car+ Energy needed to make the car climbed the hill+Energy required to exert a force.

E = 1/2mv²+mgh+Fd.................... Equation 1

Where E = Energy stored in the battery, m = mass of the car, v = velocity of the car, h = height of the hill, F = force exerted on the car, d = distance traveled by the car.

But,

d = vt.................... Equation 2

Where v = velocity, t = time.

Substitute equation 2 into equation 1

E = 1/2mv²+mgh+F(vt)................... Equation 3

Given: m = 770 kg, v = 26 m/s, h = 2.15×10² m = 215 m, F = 5.3×10² N = 530 N, t = 1 hour = 3600 s, g = 9.8 m/s²

Substitute into equation 1

E = 1/2(770)(26²)+(770)(9.8)(215)+(530)(26)(3600)

E = 260260+1622390+49608000

E = 51490650 J

Using,

E = qV................. Equation 4

Where q = charge of the battery, V = Voltage.

make q the subject of the equation

q = E/V............... Equation 5

Given: E = 51490650 J, V = 120 V

Substitute into equation 5

q = 51490650/120

q = 429088.75 C

q = 4.29×10⁵ C

Answer:

When a system is at equilibrium in terms of concentration what happens is that the rate of change of the concentration of the product and the reactants does not vary or change with time.

Explanation:

What is equilibrium?

A chemical reaction is in equilibrium when the concentrations of reactants and products are constant - their ratio does not vary.

Equilibrium does not necessarily mean that reactants and products are present in equal amounts. It means that the reaction has reached a point where the concentrations of the reactant and product are unchanging with time, because the forward and backward reactions have the same rate.

Final answer:

A chemical system at equilibrium reflects no net change in reactant and product concentrations. Upon a concentration change, Le Chatelier's principle dictates that the system will adjust to partially counteract the change and set up a new equilibrium.

Explanation:

When a system is at equilibrium, it means no net change in the concentrations of reactants and products takes place. This is because the rate of the forward reaction, in which reactants are converted into products, is equal to the rate of the reverse reaction, in which products transform back into reactants. However, when there is a change in concentration of either reactants or products during equilibrium, the system responds according to Le Chatelier's principle. This principle states that the system will adjust to partially counteract the change and reestablish a new equilibrium state.

For example, if you were to increase the concentration of a reactant, the system tends to counter this by producing more product, essentially shifting the equilibrium to the right. Conversely, if you decrease the concentration of a product, the system will proceed to produce more of that product from the reactants, again shifting the reaction to the right, until a new equilibrium is established.

Answer:

New moon

Explanation:

A solar eclipse can only take place at the phase of new moon, when the moon passes directly between the sun and Earth and its shadows fall upon Earth's surface.

A solar eclipse happens when the moon is perfectly aligned between the Earth and the Sun, thus obscuring it.

If the moon is between the Earth and the Sun, the far side of the moon is lighted, and thus you have a new moon.

Answer:

c.20

Explanation:

Answer:

In high jump as well as long jump, instateneous velocity is more important than average velocity.

In relay races and 400m races, average is more important than instateneous velocity.

Explanation:

Instantaneous velocity is the velocity of anything in motion at a specific point in time. This is determined quite similarly to average velocity, however, we look at the period of time so that it approaches zero. If there is a standard velocity over a period of time, its average and instantaneous velocities may be the same. Instantaneous velocity is calculated as the limit as t approaches zero of the change in d over the change in t.

The range or length of long jump depends on the instantenous velocity of the jump and the height of high jump depends on the instantenous velocity of the height.

A person with greater average velocity wins a race. The average velocity of anything or object is referred to as its total displacement divided by the total time taken. That is to say, it is the rate at which an object changes its position from one place to another. Average velocity is also a Vector quantity. Meters per second is the SI unit. Although, any distance unit per any time unit can be used when necessary, such as miles per hour (mph) or kilometer per hour (kmph)

Instantaneous velocity is more important in specific instances like a tennis stroke or a football collision, while average velocity is more important for calculating average rates of change in situations like road trips or rehab.

Instantaneous velocity is more important than average velocity in situations where we need to know the velocity at a specific instant in time. Examples of this include a tennis player's stroke in which they aim to hit the ball on the sweet spot of the racket for maximum velocity and minimal vibration, and in a collision in football where a player with the same velocity but greater mass has a greater impact due to their greater momentum.

On the other hand, average velocity is more important in situations where we need to calculate the average rate of change of position over a given time interval. Examples include calculating the average velocity of a car during a road trip to determine the time taken to reach a destination, and in rehab where the average velocity of a patient's movement is measured to track progress over time.

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Answer:

[tex]\frac{d\Phi_B}{dt}=\frac{d(\pi r_1^2B)}{dt}=\pi r_1^2\frac{dB}{dt}[/tex]

Explanation:

To calculate the rate of change of the flux we have to take into account that the magnetic flux is given by

[tex]\Phi_B=\vec{B}\cdot \vec{A}[/tex]

in this case the direction of B is perpendicular to the direction of A. Hence

[tex]\Phi_B=BA[/tex]

and A is the area of a circle:

[tex]A=\pi r^2[/tex]

in this case we are interested in the flux of a area of a lower radius r1. Hence

[tex]A=\pi r_1^2[/tex]

Finally, the change in the magnetic flux will be

[tex]\frac{d\Phi_B}{dt}=\frac{d(\pi r_1^2B)}{dt}=\pi r_1^2\frac{dB}{dt}[/tex]

hope this helps!!

Explanation:

Let us assume that the mass of a pitched ball is 0.145 kg.

Initial velocity of the pitched ball, u = 47.5 m/s

Final speed of the ball, v = -51.5 m/s (in opposite direction)

We need to find the magnitude of the change in momentum of the ball and the impulse applied to it by the bat. The change in momentum of the ball is given by :

[tex]\Delta p=m(v-u)\\\\\Delta p=0.145\times ((-51.5)-47.5)\\\\\Delta p=-14.355\ kg-m/s[/tex]

So, the magnitude of the change in momentum of the ball is 14.355 kg-m/s.

Let the the ball remains in contact with the bat for 2.00 ms. The impulse is given by :

[tex]J=\dfrac{\Delta p}{t}\\\\J=\dfrac{14.355}{2\times 10^{-3}}\\\\J=7177.5\ kg-m/s[/tex]

Hence, this is the required solution.

The magnitude of the change in momentum of the ball is 99 m/s. The magnitude of the impulse applied to the ball by the bat is also 99 m/s.

To find the magnitude of the change in momentum of the ball, we can use the equation:

Magnitude of change in momentum = magnitude of final momentum - magnitude of initial momentum

Given that the initial velocity of the ball is 47.5 m/s and the final velocity of the batted ball is 51.5 m/s in the opposite direction, the magnitude of the change in momentum is:

Magnitude of change in momentum = 51.5 m/s - (-47.5 m/s) = 99 m/s

The magnitude of the impulse applied to the ball by the bat is equal to the magnitude of the change in momentum. Therefore, the magnitude of the impulse applied to the ball is 99 m/s.

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Answer:

B) exposure to red light

Explanation:

Plants use a phytochrome system to sense the level, intensity, duration, and color of environmental light do as to adjust their physiology.

The phytochromes are a family of chromoproteins with a linear tetrapyrrole chromophore, similar to the chlorophyll. Phytochromes have two photo-interconvertible forms: Pr and Pfr. Pr absorbs red light (~667 nm) and is immediately converted to Pfr. Pfr absorbs far-red light (~730 nm) and is quickly converted back to Pr. Absorption of red or far-red light causes a massive change to the shape of the chromophore, altering the conformation and activity of the phytochrome protein to which it is bound. Together, the two forms represent the phytochrome system.

Answer:

The idea that little children are continually coming up with ideas and testing them is called the general theory.