Answer:
Molar mass of the gas is 64.3 g/mol
Explanation:
Given:
Temperature of gas, T = 301 K
Pressure of gas, P = 1.5 atm
Density of gas, D = 3.90 g/L
To determine:
The molar mass, M of the gas
Explanation
Based on the ideal gas equation
[tex]PV = nRT[/tex]
where P = pressure, V = volume ; R = gas constant, T = temperature
n = moles of the gas
[tex]n = \frac{mass(m)}{molar\ mass(M)}[/tex]
substituting for n in the ideal gas equation:
[tex]PV = \frac{m}{M} *RT\\\\M = (\frac{m}{V})*\frac{RT}{P} \\\\density , d = \frac{mass(m)}{Volume(V)} \\\\Therefore:\\\\M = d*\frac{RT}{P} = 3.90 g/L *\frac{.0821Latm/mol-K*301K}{1.5atm} =64.3 g/mol[/tex]
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