Answer:
B. The test contains 10 three-point questions and 14 five-point questions.
Step-by-step explanation:
Let us first find the solution to the system of equations.
x+y= 24
3x+5y= 100
We use substitution method.
x=24-y
Replacing the value of x in the second equation.
3(24-y)+5y=100
Then solve for y.
72-3y+5y=100
2y=100-72
2y=28
y=14
To find x let us replace the value of y in x=24-y
x=24-14
x=10
This means that the test has 14 five-point questions and 10 three point questions.
What is the solution to the system?
X+y+z=2
2x+y-z=-1
X=5-2z
Answer:
x = 1, y = -1, z = 2 → (1, -1, 2)Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}x+y+z=2&(1)\\2x+y-z=-1&(2)\\x=5-2z&(3)\end{array}\right\\\\\text{Substitute (3) to (1) and (2):}\\\\\left\{\begin{array}{ccc}(5-2z)+y+z=2\\2(5-2z)+y-z=-1&\text{use the distributive property}\end{array}\right\\\left\{\begin{array}{ccc}5-2z+y+z=2\\10-4z+y-z=-1\end{array}\right\qquad\text{combine like terms}\\\left\{\begin{array}{ccc}5+y-z=2&\text{subtract 5 from both sides}\\10+y-5z=-1&\text{subtract 10 from both sides}\end{array}\right[/tex]
[tex]\left\{\begin{array}{ccc}y-z=-3\\y-5z=-11&\text{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}y-z=-3\\-y+5z=11\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad4z=8\qquad\text{divide both sides by 4}\\.\qquad\qquad \boxed{z=2}\\\\\text{Put it to the first equation:}\\\\y-2=-3\qquad\text{add 2 to both sides}\\\boxed{y=-1}\\\\\text{Put the values of}\ z\\text{to (3):}\\\\x=5-2(2)\\x=5-4\\\boxed{x=1}[/tex]
What is the coefficient of xy^4 in the expansion of (2x+y)^5
Answer:
The coefficient of xy^4 is 10
Step-by-step explanation:
to solve the questions we proceed as follows:
(2x+y)^5
=(2x+y)²(2x+y)²(2x+y)
We will solve the brackets by whole square formula:
=(4x²+4xy+y²)(4x²+4xy+y²)(2x+y)
By multiplying the brackets we get:
=32x^5+32x^4y+8x³y²+32x^4y+32x³y²+8x²y³+8x³y²+4x²y³+2xy^4+16x^4y+
16x³y²+4x²y³+16x³y²+16x²y³+4xy^4+4x²y³+4xy^4+y^5
=32x^5+80x^4y+80x³y²+40x²y³+10xy^4+y^5
Therefore the coefficient of xy^4 is 10
The answer is 10....
Answer: 10
Step-by-step explanation: a p e x
Jamin wants to paint a wall in his bedroom. Not only does he need to buy paint, but he also needs to buy tape to tape off all sides of the wall and the window. How many feet of painter's tape will Jamin need to buy (assume no overlap)? [Note: The wall and window are both rectangular.]
17.5 ft
35 ft
28 ft
21 ft
The perimeter of the walls is 6 + 6 + 8 + 8 = 28 feet.
The perimeter of the window is 2 + 2 + 1.5 + 1.5 = 7 feet.
Total = 28 + 7 = 35 feet of tape.
I would say B.35 is the answer.
A light bulb company produces a constant number of new light bulbs in their factory each week, and stores them in a warehouse where old light bulbs from the previous year are also stored. After 3 weeks, they have 15,000 bulbs in the warehouse. After 7 weeks, they have 65,000 bulbs.
What is the equation in point-slope formula?
Answer:
y - 15000 = 12500(x-3)
You have $60. The jacket you want costs $25.50 and 7% tax. what is the top tag price (excludes sales tax) left to also buy a pair of shorts?
the assumption being, that there's a 7% sales tax on any item in the store.
so if you buy the jacket, you pay 25.5 plust 7% of 25.5.
and if you buy the shoes for price say "s", then you pay "s" plus 7% of "s".
whatever those two amounts are, they must be $60, because that's all you have in your pocket anyway.
[tex]\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{7\% of 25.5}}{\left( \cfrac{7}{100} \right)25.5}\implies 0.07(25.5)~\hfill \stackrel{\textit{7\% of "s"}}{\left( \cfrac{7}{100} \right)s}\implies 0.07s \\\\[-0.35em] ~\dotfill[/tex]
[tex]\bf \stackrel{\textit{jacket}}{25.5}+\stackrel{\textit{jacket's tax}}{0.07(25.5)}+\stackrel{\textit{shoes}}{s}+\stackrel{\textit{shoe's tax}}{0.07s}~~=~~\stackrel{\textit{in your pocket}}{60} \\\\\\ 25.5+1.785+s+0.07s=60\implies 27.285+1.07s=60 \\\\\\ 1.07s=60-27.285\implies 1.07s=32.715\implies s=\cfrac{32.715}{1.07}\implies s\approx 30.57[/tex]
Given the triangle below, what is m
Answer:
82.8 degrees
Step-by-step explanation:
The information given here SSS. That means side-side-side.
So we get to use law of cosines.
[tex](\text{ the side opposite the angle you want to find })^2=a^2+b^2-2ab \cos(\text{ the angle you want to find})[/tex]
Let's enter are values in.
[tex]12^2=10^2+8^2-2(10)(8) \cos(B)[/tex]
I'm going to a little simplification like multiplication and exponents.
[tex]144=100+64-160 \cos(B)[/tex]
I'm going to some more simplification like addition.
[tex]144=164-160\cos(B)[/tex]
Now time for the solving part.
I'm going to subtract 164 on both sides:
[tex]-20=-160\cos(B)[/tex]
I'm going to divide both sides by -160:
[tex]\frac{-20}{-160}=\cos(B)[/tex]
Simplifying left hand side fraction a little:
[tex]\frac{1}{8}=\cos(B)[/tex]
Now to find B since it is inside the cosine, we just have to do the inverse of cosine.
That looks like one of these:
[tex]\cos^{-1}( )[/tex] or [tex]\arccos( )[/tex]
Pick your favorite notation there. They are the same.
[tex]\cos^{-1}(\frac{1}{8})=B[/tex]
To the calculator now:
[tex]82.81924422=B[/tex]
Round answer to nearest tenths:
[tex]82.8[/tex]
the terminal side of an angle in standard position passes through P(-3,-4). what’s the value of tan(Theta)
Answer:
4/3
Step-by-step explanation:
I drew a picture in the attachment to show what we are looking at.
I found the point (-3,-4). I drew my angle my triangle from the x-axis and the origin to the point.
The angle that is theta is the one formed by the x-axis and the hypotenuse of the triangle where this hypotenuse was formed from the line segment from the origin to the given point.
[tex]\tan(\theta)=\frac{\text{opposite to }\theta}{\text{adjacent to }\theta}=\frac{-4}{-3}=\frac{4}{3}[/tex]
So we could have said [tex]\tan(\theta)=\frac{y}{x}[/tex].
celest
Guided Practice
4. Find the next three terms in the sequence.
etric Sequences
-3, 6, -12, 24, ...
A - 48,96, -1923
hential Growth and
B 48, -96, 192
stest
C -36, 72, -144
mials
mials and Factoring
nic Equations and
Answer:
A - 48,96, -192
Step-by-step explanation:
Given:
geometric sequence:
-3, 6, -12, 24,
geometric sequence has a constant ratio r and is given by
an=a1(r)^(n-1)
where
an=nth term
r=common ratio
n=number of term
a1=first term
In given series:
a1=-3
r= a(n+1)/an
r=6/-3
r=-2
Now computing next term a5
a5=a1(r)^(n-1)
= -3(-2)^(4)
= -48
a6=a1(r)^(n-1)
= -3(-2)^(5)
= 96
a7=a1(r)^(n-1)
= -3(-2)^(9)
= -192
So the sequence now is -3, 6, -12, 24,-48,96,-192
correct option is A!
I want to start a lemonade stand and determine how much lemonade I need to sell to break even each day.
If I know I spend $5 on supplies and sell lemonade at $0.50 per glass determine the number of glasses I must sell to break even. After you find the number of glasses tell me what the x-intercept, y-intercept and slope. Represent in the function you determined
Answer:
Total cost spent on supplies = 5 dollars
Lemonade will be sold at 0.5 dollars.
Let the total glasses of lemonade sold be x
So, revenue generated will be = 0.5x
To get the break even we will equal both.
[tex]0.5x=5[/tex]
[tex]x=5/0.5[/tex]
x = 10
Hence, number of glasses to be sold are 10.
The profit or y can be found as;
[tex]y=0.5x-5[/tex]
So, putting x = 11
[tex]y=0.5(11)-5[/tex]
y = 0.5
Putting x = 12
[tex]y=0.5(12)-5[/tex]
y = 1
Putting x = 13
[tex]y=0.5(13)-5[/tex]
y = 1.5
The slope is 0.5.
The y-intercept is -5. This means if 0 glasses of lemonade are sold then there is a loss of $5.
The y intercept is obtained when x=0.
[tex]y=0.5(0)-5[/tex]
y = -5
The x-intercept is 10 or the number of glasses I must sell to break even.
what is the approximate area of the circle shown below? 16 cm
Answer:
201.143 (approx.) cm²
area of circle = (pi)x(radius)^2
= 22/7 x (8)^2
=22/7 x 64
= 1408/7
= 201.142857143
= 201.143 cm^2 (approx.)
Answer:
the approximate area of circle is 201 cm²
D is the correct option.
Step-by-step explanation:
From, the given figure, the diameter of the circle is 16 cm.
The radius is half of the diameter.
Hence, the radius of circle is 16/2 = 8 cm
The area of a circle is given by
[tex]A=\pi r^2[/tex]
Substituting the value of r and π
[tex]A=3.14(8)^2\\\\A=200.96\\\\A\approx201[/tex]
Therefore, the approximate area of circle is 201 cm²
D is the correct option.
- The whole batch cost $28,000 and contained 140 items. Write the two rates (ratios) implied
by this statement. What would be the price for 200 items?
Please show work
Answer:
The answer would be 14
Step-by-step explanation:
you just divide 28,00 by 200 and that gives you 14
Using the given points and line, determine the slope of the line.
(1, 2) and (2, 1)
Answer:
-1
Step-by-step explanation:
To find the slope of a line given two points, you can use [tex]\frac{y_2-y_1}{x_2-x_1}[/tex] where [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are points on the line.
Or you could just line up the points vertically and subtract them vertically, then put 2nd difference over first.
Like so:
( 2 , 1 )
-( 1 , 2 )
--------------------
1 -1
So the slope is -1/1 or just -1.
what is the domain of this function?
Answer:
x ≥ 0
Step-by-step explanation:
The domain of the function is the inputs, or in this case, the x values.
The inputs are x greater than or equal to zero all the way to infinity.
Answer:
Step-by-step explanation:
The domain includes 0 and all real numbers greater than 0: x ≥ 0
Suppose BC is congruent to CA. Can you use the SSS Postulate or the SAS Postulate to prove ABD is congruent to DCA
Answer:
probably sas
Step-by-step explanation:
sas because the 2 sides are congruent, but i don't have enough information to know for sure
For the function y=x^5+1x^3-30x, find all real zeros.
Answer:
The real zeroes are -√5 , 0 , √5
Step-by-step explanation:
* Lets explain how to solve the problem
- The function is y = x^5 + x³ - 30x
- Zeros of any equation is the values of x when y = 0
- To find the zeroes of the function equate y by zero
∴ x^5 + x³ - 30x = 0
- To solve this equation factorize it
∵ x^5 + x³ - 30x = 0
- There is a common factor x in all the terms of the equation
- Take x as a common factor from each term and divide the terms by x
∴ x(x^5/x + x³/x - 30x/x) = 0
∴ x(x^4 + x² - 30) = 0
- Equate x by 0 and (x^4 + x² - 30) by 0
∴ x = 0
∴ (x^4 + x² - 30) = 0
* Now lets factorize (x^4 + x² - 30)
- Let x² = h and x^4 = h² and replace x by h in the equation
∴ (x^4 + x² - 30) = (h² + h - 30)
∵ (x^4 + x² - 30) = 0
∴ (h² + h - 30) = 0
- Factorize the trinomial into two brackets
- In trinomial h² + h - 30, the last term is negative then the brackets
have different signs ( + )( - )
∵ h² = h × h ⇒ the 1st terms in the two brackets
∵ 30 = 5 × 6 ⇒ the second terms of the brackets
∵ h × 6 = 6h
∵ h × 5 = 5h
∵ 6h - 5h = h ⇒ the middle term in the trinomial, then 6 will be with
(+ ve) and 5 will be with (- ve)
∴ h² + h - 30 = (h + 6)(h - 5)
- Lets find the values of h
∵ h² + h - 30 = 0
∴ (h + 6)(h - 5) = 0
∵ h + 6 = 0 ⇒ subtract 6 from both sides
∴ h = -6
∵ h - 5 = 0 ⇒ add 5 to both sides
∴ h = 5
* Lets replace h by x
∵ h = x²
∴ x² = -6 and x² = 5
∵ x² = -6 has no value (no square root for negative values)
∵ x² = 5 ⇒ take √ for both sides
∴ x = ± √5
- There are three values of x ⇒ x = 0 , x = √5 , x = -√5
∴ The real zeroes are -√5 , 0 , √5
Use row reduction to solve the system of equations. x-2y+z=4, 3x-5y-17z=3, 2x-6y+43z=-5
Answer:
x = -1223, y = -629, and z = -31.
Step-by-step explanation:
This question can be solved using multiple ways. I will use the Gauss Jordan Method.
Step 1: Convert the system into the augmented matrix form:
• 1 -2 1 | 4
• 3 -5 -17 | 3
• 2 -6 43 | -5
Step 2: Multiply row 1 with -3 and add it in row 2:
• 1 -2 1 | 4
• 0 1 -20 | -9
• 2 -6 43 | -5
Step 3: Multiply row 1 with -2 and add it in row 3:
• 1 -2 1 | 4
• 0 1 -20 | -9
• 0 -2 41 | -13
Step 4: Multiply row 2 with 2 and add it in row 3:
0 2 -40 -18
• 1 -2 1 | 4
• 0 1 -20 | -9
• 0 0 1 | -31
Step 5: It can be seen that when this updated augmented matrix is converted into a system, it comes out to be:
• x - 2y + z = 4
• y - 20z = -9
• z = -31
Step 6: Since we have calculated z = -31, put this value in equation 2:
• y - 20(-31) = -9
• y = -9 - 620
• y = -629.
Step 8: Put z = -31 and y = -629 in equation 1:
• x - 2(-629) - 31 = 4
• x + 1258 - 31 = 4
• x = 35 - 1258.
• x = -1223
So final answer is x = -1223, y = -629, and z = -31!!!
Joseph claims that a scatterplot in which the y-values increase as the x-values increase must have a linear association. Amy claims that the scatterplot could have a nonlinear association. Which statement about their claims is true?
Joseph is correct because only a line will increase along the whole data set. The scatterplot will have a positive, linear association.
Joseph is correct because only a line will decrease along the whole data set. The scatterplot will have a negative, linear association.
Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.
Amy is correct because only a nonlinear association could increase along the whole data set. A line has the same slope at any point, but a curve can get steeper at different points.
Answer:
The answer is C
Step-by-step explanation:
Answer:
Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.
Step-by-step explanation:
Both linear and nonlinear associations could increase along the whole data set. That's why Joseph and the fourth option are incorrect.
A triangular field has sides of 120.32 m and 204.61 m, and the angle between them measures 60.881°. Find the area of the field
Answer:
A=10753.5715 m^2.
Step-by-step explanation:
The area of a triangle with the information SAS given is:
A=1/2 * (side) * (other side) * sin(angle between)
A=1/2 * (204.61)*(120.32) * sin(60.881)
A=10753.5715 m^2.
SAS means two sides with angle between.
Answer: [tex]10,753.57\ m^2[/tex]
Step-by-step explanation:
You need to use the SAS area formula. This is:
[tex]A=\frac{a*b*sin(\alpha)}{2}[/tex]
You know that the triangular field has sides of 120.32 meters and 204.61 meters and the angle between them measures 60.881°. Then:
[tex]a=120.32\ m\\b=204.61\ m\\\alpha =60.881\°[/tex]
Substituting these values into the formula, you get that the area of this triangle is:
[tex]A=\frac{(120.32\ m)(204.61\ m)*sin(60.881\°)}{2}\\\\A=10,753.57\ m^2[/tex]
Which equation is used to help form the combined gas law?
Need help ASAP !
If pressure is constant
then PV= nRT
is equivalent to V= ( nR/P) T
V= kT ( where k is constant nR/P)
As V is directly proportional to T
So V1/T1 = V2/T2
Answer:
The correct answer
Step-by-step explanation:
Jeri is 3 years younger than Laura, whose age is x. How old is Jeri? x - 3 yrs old x + 3 yrs old 3x yrs old
Answer:
3x yrs old
Step-by-step explanation:
True or false? An angle whose vertex is at the center of the circle is a central angle of that circle.
This statement would be true: if the vertex of an angle is at the center of the circle, then it would be the central angle.
The length of a new rectangular playing field is 5 yards longer than triple the width. If the perimeter of the rectangular playing field is 346 yards, what are itsdimensions?
The length and width of the rectangular field are determined using algebra by setting up and solving two equations which represent the relationships between the length, width, and perimeter of the field. The dimensions are found to be 46 yards for the width and 137 yards for the length.
Explanation:The dimensions of the rectangular playing field can be found using algebra, specifically the formulas for the dimensions and perimeter of a rectangle. The problem can be translated into two equations reflecting the relationships of the field's width and length to the perimeter.
The first equation is: L = 3W + 5, which represents the relationship that the length is 5 yards longer than triple the width.
The second equation is derived from the formula for the perimeter of a rectangle (P = 2L + 2W), which given the problem's perimeter of 346 yards gets us: 2L + 2W = 346.
Substitute the first equation into the second to solve for the width, then use that result to find the length. The solution indicates that the width of the rectangular playing field is 46 yards, and the length is 137 yards.
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Find the length of RJ
Answer:
Option C 89
Step-by-step explanation:
In this problem we know that
KJ=KR+RJ
we have
KJ=95 units
KR=6 units
substitute and solve for RJ
95=6+RJ
subtract 6 both sides
RJ=95-6=89 units
Answer:
The correct option is C.
Step-by-step explanation:
We need to find the length of line segment RJ.
From the given figure it is clear that line segment KJ is the sum of line segments KR and RJ.
[tex]KJ=KR+RJ[/tex]
The length of line segment KJ is 95 units and the length of KR is 6 units.
Substitute KJ=95 and KR=6 in the above equation.
[tex]95=6+RJ[/tex]
Subtract 6 from both the sides.
[tex]95-6=6+RJ-6[/tex]
[tex]89=RJ[/tex]
The length of segment RJ is 89 units. Therefore the correct option is C.
What is the volume of the regular pyramid bellow?
Answer:
128 units^3
Step-by-step explanation:
[tex]v = \frac{b \times b \times h}{3} = \\ = \frac{8 \times 8 \times 6}{3} = \\ = 128 \: {units}^{3} [/tex]
Step-by-step explanation:
base areas x height / 3
a^2 . h / 3
8^2 . 6 / 3
= 128 units^3
iyi ödevler
have a good lesson
Polygon ABCD is translated to create polygon A’B’C’D’. Point A is located at (1,5), and point A’ is located at (-2,3). Which expression defines the transformation of any point (x,y) to (x’,y’) on the polygons?
Answer:
The expression is (x,y) -----> (x-3,y-2)
Step-by-step explanation:
we have that
A(1,5) ----> A'(-2,3)
so
The rule of the translation is equal to
(x,y) -----> (x',y')
(x,y) -----> (x-3,y-2)
That means-----> the translation is 3 units at left and 2 units down
janis jogs around a rectangular park that is 3/4 mi long and 1/4 mi wide. how far is it around the park?
Answer:
[tex]2\ miles[/tex]
Step-by-step explanation:
we know that
The distance around the park is equal to the perimeter of the rectangular park
The perimeter is equal to
[tex]P=2(L+W)[/tex]
we have
[tex]L=\frac{3}{4}\ mi[/tex]
[tex]W=\frac{1}{4}\ mi[/tex]
substitute the values
[tex]P=2(\frac{3}{4}+\frac{1}{4})[/tex]
[tex]P=2(\frac{4}{4})[/tex]
[tex]P=2\ mi[/tex]
Answer:
3 219⁄1000 km. [2 mi.]
Step-by-step explanation:
P = 2l + 2w
P = 2[¾] + 2[¼]
P = 1½ + ½
P = 2
I am joyous to assist you anytime.
If f(x) = -x + 8 and g(x) = x^4, what is (gºf)(2)?
Answer:
[tex]\large\boxed{(g\circ f)(2)=1296}[/tex]
Step-by-step explanation:
[tex](g\circ f)(x)=g\bigg(f(x)\bigg)\\\\f(x)=-x+8,\ g(x)=x^4\\\\(g\circ f)(x)=\g\bigg(f(x)\bigg)=(-x+8)^4\\\\(g\circ f)(2)\to\text{put x = 2 to the equation}\ (g\circ f)(x):\\\\(g\circ f)(2)=(-2+8)^4=(6)^4=1296[/tex]
[tex]\bf \begin{cases} f(x)=&-x+8\\ g(x)=&x^4\\ (g\circ f)(x) =& g(~~f(x)~~) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(2)=-(2)+8\implies f(2)=\boxed{6} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{(g\circ f)(2)}{g(~~f(2)~~)}\implies g\left( \boxed{6} \right) = (6)^4\implies \stackrel{(g\circ f)(2)}{g(6)} = 1296[/tex]
Which of the following is an integer?
0
4
© -12.5
0 0.454545...
Answer: 4
Step-by-step explanation: 4 is the answer because an integer is any whole number, but not 0.
Why is the x intercept wrong?
PLEASE HELP ASAP
Of the three functions in the tables, which represent linear relationships?
A. f and h
B. all three functions
c. f and g
D. g and h
Answer:
A. f and h
Step-by-step explanation:
For a linear function the First Differences of the y-values must be a constant. i.e. if we take the difference between any two consecutive y values or values of f(x) it should be the constant. For this rule to work, x values must change by the same number every time, which is true for all three given functions.
For function f:
The values of f(x) are: 5,8,11,14
We can see the difference in consecutive two values is a constant i.e. 3, so the First Difference is the same. Hence, function f is a linear function.
For function g:
The values of g(x) are: 8,4,16,32
We can see the difference among two consecutive values is not a constant. Since the first differences are not the same, this function is not a linear.
For function h:
The values of h(x) are: 28, 64, 100, 136
We can see the difference among two consecutive values is a constant i.e. 36. Therefore, function h is a linear function.
To identify the linear relationships in the tables, we need to look for constant rates of change. Functions f and g have this property, while h does not.
Explanation:In order to identify which functions represent linear relationships, we need to look for patterns in the tables. A linear relationship is characterized by a constant rate of change.
Looking at the tables, we can see that functions f and g have a constant difference between the values in the input column (x) and the output column (y). However, function h does not have a constant rate of change, so it does not represent a linear relationship.
Therefore, the correct answer is A. f and h, as these two functions represent linear relationships.
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