A simple pendulum is used to determine the acceleration due to gravity at the surface of a planet. The pendulum has a length of 2 m and its period is measured to be 2 s. The value of g obtained in this investigation is most nearly __________.A. 1 m/s²B. 2 m/s²C. 5 m/s²D. 10 m/s²E. 20 m/s²

Answer:

The height will be 917431.2 m.

Explanation:

Power of bulb = 75 W

Time kept on 1 hr = 60 x 60 = 3600 sec

Energy of bulb = power x time

E = 75 x 3600 = 270000 J

From conservation of energy, kinetic energy of the bulb is equal to the potential energy of the bulb due to its height of fall.

Potential energy = m x g x h

Where g = acceleration due to gravity 9.81 m/s2

m = mass = 30 g = 0.03 kg

PE = 0.03 x 9.81 x h = 0.2943h

Equating withe the energy of bulb (still obeying energy conservation)

270000 = 0.2943h

h = 270000/0.2943 = 917431.2 m

The incandescent bulb would have to be dropped from a height of approximately 918,367.35 meters to have its kinetic energy equal to the energy consumed in one hour of use.

To determine from what height you should drop a 75-watt incandescent bulb so that upon reaching the floor, its kinetic energy will equal the energy used to power it for 1.0 hour, we use the formula for gravitational potential energy (PE) and kinetic energy (KE), where PE = mgh and KE = ½ mv². The power consumption of the bulb indicates how much energy it uses per second, so we first calculate the energy consumed in one hour (E = power × time). Since the bulb is 75 watts, and there are 3600 seconds in an hour, it uses 75 W × 3600 s = 270,000 joules in one hour. This is the energy we want the bulb to have as kinetic energy when it hits the ground. To find the height, we set this equal to the potential energy at the start (mgh) and solve for h:

E = mgh

270000 J = (0.03 kg)(9.8 m/s²)(h)

h = 270000 J / (0.03 kg × 9.8 m/s²)

h = 918367.35 m

Thus, the bulb would have to be dropped from a height of approximately 918367.35 meters to have the same energy when it impacts the ground as it uses in one hour of being lit.

Answer:

Explanation:

Given that,

Mass of cannon

M1= 500kg and initially at rest

U1 = 0m/s

Mass of clown

M2 = 100kg

so it was initial at rest before this time, therefore, U2 = 0

Recoils speed of cannon V1 =5m/s, the recoils speed is after the cannon has left the barrel.

Using construction of linear momentum

Momentum before collision is equal to momentum after collision

The initial momentum is zero since the two bodies are until at rest

And the final momentum is

M1•V1 + M2•V2

Then,

P(initial) = P(final)

0 = M1•V1 + M2•V2

0 = 500 × 5 + 100 × V2

0 = 2500 +100•V2

100•V2 = -2500

V2 = -2500/100

V2 = —25m/s

So, the final velocity of the clown is -25m/s, opposite direction of the cannon

Answer:

hall mobility = 139.8 x 10 ∧3

carrier density = 83.1 x 10 ∧14

Explanation:

The pictures attached below shows the full explanation

Answer:

Solid

Explanation:

The plasma is the liquid part of blood, it is 90% and accounts for 55% of blood volume. It is what red blood cells, white blood cells, and platelets move around in. These cells remain solid within the plasma. I hoped this helped!

Although blood cells are contained within a special liquid called plasma, the cells themselves are suspended in plasma.

Blood is a fluid tissue that is made up of plasma, red blood cells, white blood cells, and platelets. Plasma is the liquid part of blood that makes up about 55% of blood volume.

Red blood cells make up about 45% of blood volume and are responsible for carrying oxygen to the tissues. White blood cells make up about 1% of blood volume and are responsible for fighting infection. Platelets are responsible for clotting blood.

The cells are suspended in the plasma because they are too small to sink to the bottom of the blood. The plasma also helps to transport the cells throughout the body.

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Answer:

A pi bond

Explanation:

A pi bond is a type of covalent bond that results from the formation of a molecular orbital by the side-to-side overlap of atomic orbitals along a plane perpendicular to a line connecting the nuclei of the atoms.

Answer:

We conclude that ball 2 has a larger mass.

Explanation:

This is because the internal forces at collision are an action reaction pair. The force on ball 1 due to ball 2 equals the force on ball 2 due to ball 1. Since these forces are equal in magnitude, let's denote it by F. So

For each ball, F = ma and a = F/m. Since F is the same for both balls, if follows that the acceleration of each ball is inversely proportional to its mass. That is, a ∝ 1/m.

Since ball 1 has a higher acceleration, it has a lower mass. Also ball 2 has a small acceleration, so it has a higher mass.

Answer:

See explanation

Explanation:

Solution:-

- Denote the following:

  mass of ball 1 = m1

  initial velocity of ball 1 = vi,1

  Final velocity of ball 1 = vf,1

  mass of ball 2 = m2

  initial velocity of ball 2 = vi,2

  Final velocity of ball 2 = vf,2

- Since there are no external forces acting on the system containing the two balls then we can say that the linear momentum of the system is conserved.

- The conservation of linear momentum says that the momentum before or after the collision remains conserved:

                                    Pi = Pf

Where,                        p = m*v

- The conservation of momentum for the given system:

                    m1*vi,1 + m2*vi,2 = m1*vi,1 + m2*vi,2  

- Since no information is given about the initial conditions. We will consider the internal force (F) that acts when two balls come in contact. Then apply Newton's second law of motion on both balls individually:

                                F = m*a

Where,             m: Mass of object

                        a: Acceleration of the object

- For ball 1:

                               F1 = m1*a1

- For ball 2:

                              F2 = m2*a2

Given that a1 > a2, and the the internal force that acts on both balls during collision obeys Newton's 3rd Law i.e for every action there is an equal but opposite reaction: So , F1 = F2

                             F = m1*a1

                             F = m2*a2

                             m1*a1 = m2*a2

- Since, a1 > a2 for above equation to hold true then m1 < m2. That is the mass of ball 1 is quite less compared to ball 2.

Answer:

Note: Check the attached image for a clearer question

From the attached image, the answers are 2,3,6,7

Explanation:

Maximum power occurs at resonance, i.e. [tex]X_{L} = X_{C}[/tex], not when impedance is greater than resistance

Resonance occurs when the Inductive reactance equals the capacitive reactance, i.e. [tex]X_{L} = X_{C}[/tex], not [tex]R^{2} = (X_{L} - X_{C} ) ^{2}[/tex]

and when, [tex]w = \frac{1}{\sqrt{LC} }[/tex]

Therefore, option B is correct

Since the formula for impedance is [tex]Z = \sqrt{R^{2} + (X_{L}-X_{C}) ^{2} }[/tex], at resonance, Z = R i.e. the impedance is minimum

At resonance, there is maximum power and minimum impedance

Thew Quality Factor, [tex]Q = \frac{w_{0}L }{R} = \frac{1}{R} \sqrt{\frac{L}{C} }[/tex]

The impedance Z is always larger than the resistance R, note that it is not stated that this condition is at Resonance, that makes it correct.

[tex]Z = \sqrt{R^{2} + X^{2} }[/tex]

Explanation:

Given that,

Initial speed of the billiard ball 1, u = 30i cm/s

Initial speed of another billiard ball 2, u' = 40j cm/s

After the collision,

Final speed of first ball, v = 50 cm/s

Final speed of second ball, v' = 0 (as it stops)

Let us consider that both balls have same mass i.e. m

Initial kinetic energy of the system is :

[tex]K_i=\dfrac{1}{2}mu^2+\dfrac{1}{2}mu'^2\\\\K_i=\dfrac{1}{2}m(u^2+u'^2)\\\\K_i=\dfrac{1}{2}m((30)^2+(40)^2)\\\\K_i=1250m\ J[/tex]

Final kinetic energy of the system is :

[tex]K_f=\dfrac{1}{2}mv^2+\dfrac{1}{2}mv'^2\\\\K_f=\dfrac{1}{2}m(v^2+v'^2)\\\\K_f=\dfrac{1}{2}m((50)^2+(0)^2)\\\\K_f=1250m\ J[/tex]

The change in kinetic energy of the system is equal to the difference of final and initial kinetic energy as :

[tex]\Delta K=K_f-K_i\\\\\Delta K=1250m-1250m\\\\\Delta K=0[/tex]

So, the change in kinetic energy of the system as a result of the collision is equal to 0.    

Answer:

Explained.

Explanation:

Let me explain the two cases in by one.

(1) When Person wearing a jacket, heat from his or her body is going to get trapped inside his or her jacket to keep this person warm when a thermometer is placed inside, it would indicate a higher temperature on the scale.

(2) When Jacket is Hanging in a closet, its temperature would be roughly close to room temperature and when we would place a thermometer it would not indicate any change on its scale.

Answer:

Voltage can be calculated in various ways but I am a easier solution to it:

Explanation:

V=I×R instead of this formula I use:

P=I×V

600=400×V

600=400V

Divide both sides by 400

V=3÷2

V=1.5 J/C

1volt=1coulomb or joule

Answer:1.5V

Explanation: power =IV

Where I= current

V= voltage

Therefore Voltage=power/current

V= 600/400= 1.5

Answer:

0.01 rad

Explanation:

For a double-slit experiment, we have that dsinθ = nλ. The separation between the central maximum and an adjacent maximum is when n = 1

dsinθ = λ

The angular separation θ = sin⁻¹(λ/d)

now d = 100λ

θ = sin⁻¹(λ/100λ) = sin⁻¹(0.01) = 0.573°

θ = 0.573° × π/180 = 0.01 rad

Answer:

1.349 × 10¹² electrons

Explanation:

At equilibrium, the tension T in the string is resolved into horizontal and vertical components. Tcos17 being the vertical component and Tsin17 the horizontal component. The electrostatic force of repulsion at equilibrium, F = kq²/r² where q = excess charge on sphere and r = distance apart at equilibrium,F acts horizontally to the left and its weight, mg acts vertically downwards.

For equilibrium, sum of horizontal components = 0 and  sum of horizontal components = 0. So, Tsin17 - F = 0

Tsin17 = F ⇒ Tsin17 = kq²/r² (1)

Also Tcos17 - mg = 0  ⇒ Tcos17 = mg (2)

Dividing (1) by (2), we have

Tsin17/Tcos17 = kq²/r² ÷ mg

tan17 = kq²/mgr²

q = r√(mgtan17/k)

We find r using cosine rule r = √(500² + 500² -2 × 500²cos 2 × 17) since the string and the masses form an isosceles triangle at equilibrium.

r = √(2 × 500² -2 × 500²cos34) = 500√2(1 - cos 34) = 500√2 × 0.1710 =120.89 mm = 0.1209 m

substituting m = 9.60 g = 9.6 × 10⁻³ g, k = 9 × 10⁹ Nm²/C² and r into q, we have,

q = r√(mgtan17/k)

  = 0.1209 m√(9.6 × 10⁻³ g × 9.8 m/s² × tan17/9 × 10⁹ Nm²/C²)

  = 0.1209 m√(28.76 × 10⁻³ N/9 × 10⁹ Nm²/C²)

  =  0.1209 m√(3.195 × 10⁻¹² C²/m²)

  =  0.1209 m × 1.7877 × 10⁻⁶ C/m

  = 0.2161 × 10⁻⁶ C

  = 2.161 × 10⁻⁷ C

To find the number of surplus electrons, n on each sphere, we divide q by e the electron charge.

So, n = q/e = 2.161 × 10⁻⁷ C ÷ 1.602 × 10⁻¹⁹ C = 0.6825 × 10¹² = 1.349 × 10¹² electrons

The number of surplus electrons on each sphere : 3.27 * 10¹²

Given data :

Mass of metal spheres = 9.60 g

length of string = 500 mm

Angle made by each string with the vertical ( ∅ )  = 17°

we will apply the formula below

number of surplus electrons ( n  ) = [tex]\frac{q}{e}[/tex]  ----- ( 1 )

whereby :

Considering The forces acting on the metal spheres

Tan ∅ = [tex]\frac{q^{2} }{4\pi e_{o}mgr^{2} }[/tex]   ----- ( 2 )

First step : Determine the distance between the spheres

r = 2l * sin∅

 = 2 * 0.500 * sin17°

 = 0.2924 m

Next step : Determine the charge on each sphere

Back to equation ( 2 )

Tan 17° = [tex]\frac{(8.99*10^{9}) * q^{2} }{(9.60 * 10^{-3})*(9.81)*(0.2924 )^{2} }[/tex]

q² = [ ( 0.3057 ) * ( 9.60 * 10⁻³ ) * ( 9.81 ) * ( 0.2924 )² ] / ( 8.99 * 10⁹ )

    = 0.00246 / 8.99 * 10⁹

    = 2.7364 * 10⁻¹³

Charge on each sphere ( q ) = √ (  2.7364 * 10⁻¹³ ) = 5.23 * 10⁻⁷ C

Final step : The number of surplus electrons on each sphere

Back to equation ( 1 )

n = q / e

  = ( 5.23 * 10^-7 ) / ( 1.6 * 10^-19 )

  = 3.27 * 10¹²

Hence we can conclude that the number of surplus electrons on each sphere : 3.27 * 10¹².

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Answer:

The speed at the top of the hill is 4.38 m/s

Explanation:

Here we have total Kinetic = KE (translational) +KE (rotational)

=0.5 m v² + 0.5m·r²v²/r² = m·v²

Therefore at height 0.6 m we have

0.6 mg = mv²

When v = 5.01 m/s maximum height is

m·g·h=m·5.01²

or h = 2.56 m

Therefore at 0.6 m we have 2.56 - 0.6 more height energy to climb

which gives

1.96·m·g = m v₂²

or v₂² = 19.22

v₂ = 4.38 m/s.

Sound waves spread out and bend around corners, while light waves behave like rays and do not bend around corners.

The difference between sound waves and light waves when passing through an opening is that light waves behave like rays and do not bend around corners, while sound waves spread out and bend around corners due to their longer wavelengths.

Light waves have very short wavelengths, which allows them to act like rays and create sharp shadows when passing through openings. On the other hand, sound waves have longer wavelengths, on the order of the size of the opening, and can bend around corners.

For example, when light shines through an open door into a dark room, we expect to see a sharp shadow of the doorway on the floor and no light bending around corners. However, when sound passes through a door, we expect to hear it everywhere in the room, indicating that sound waves spread out and bend around corners.

The following sentences are completed and explained below

Explanation:

A is a seasonal wind known as monsoon wind that blows in the opposite direction of normal winds.

Prevailing winds are the wind that blows mainly from a single general direction.

Seasonal winds that blow in the opposite direction of normal winds often cause drought in the winter.

The monsoon winds are seasonal winds that refers to wind systems that have a pronounced seasonal reversal of direction.

The winds that blow from single direction over a specific area of the earth is known as prevailing winds.

1. Monsoon wind: a seasonal wind that blows in the opposite direction of normal winds.

2. Prevailing wind: it is a wind that blows mainly from a single (one) general direction.

3. Seasonal winds that blow in the opposite direction of normal winds often cause drought in the winter.

A wind can be defined as the natural movement of air and its constituent gases blowing in a particular with respect to a planet's surface.

Based on the location of occurrence and periodicity, winds are classified into three (3) main categories and these are:

1. Local winds: these include bora, foehn, loo, mistral, etc.

2. Secondary winds: these include mountain and valley breeze, monsoon wind, etc.

3. Primary winds: polar easterlies, trade winds, westerlies, etc.

In this exercise, you're required to complete the given sentences as follows:

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Final answer:

Technician A is correct, as there is slippage between input and output speeds in fluid couplings without a mechanical lock-up. Technician B is incorrect, as the impeller and turbine rpms do not match in a torque converter coupling.

Explanation:

Technician A is correct. In any type of fluid coupling without a mechanical lock-up, there is always some slippage between the input and output speeds. This means that the output speed will be less than the input speed, resulting in a difference between them.

Technician B is incorrect. In a torque converter coupling, the impeller and turbine do not have matching rpm (revolutions per minute). The impeller rpm is higher than the turbine rpm, which allows the torque converter to efficiently transfer power from the engine to the transmission.

Answer:

D. Could be as small as 4 m, and as large as 12 m.

Explanation:

Since the magnitudes are vectors instead of scalars, their sum is not just the sum of their magnitudes; their directions must be taken in account. The maximum possible magnitude of the resultant occurs when both vectors have the same direction; in that case the resultant magnitude is the sum of the individual magnitudes (in this case, 12 meters). In the other hand, the minimum possible magnitude is when the vectors have opposite directions; in that case the magnitude of the resultant is the substraction of one magnitude to another (in this case, 4 meters). Finally, the right answer is D, because the possible values range from 4m to 12m.

Final answer:

The magnitude of the resultant vector when adding two displacement vectors of 4 m and 8 m can be as small as 4 m if they are in opposite directions or as large as 12 m if they are collinear and in the same direction.(Option D)

Explanation:

The question asks about the magnitude of the resultant vector when two displacement vectors are added. A displacement vector has both magnitude and direction, and when two vectors are combined, their resultant depends on both their magnitudes as well as the angle between them. When two vectors are added, the magnitude of the resulting vector can vary depending on this angle. If the vectors are collinear and in the same direction, the magnitude of the resultant will be the sum of the magnitudes of the individual vectors, which is the maximum possible magnitude.

However, vectors can also be in opposite directions, in which case the resultant magnitude will be the difference between the two, representing the minimum magnitude. Therefore, given two displacement vectors with magnitudes of 4 m and 8 m, the magnitude of the resultant vector upon addition can range from 4 m to 12 m. This occurs because if the vectors are in the same direction, their magnitudes add up (to 12 m); if they are opposite, the resultant is the difference (to 4 m). In any other scenario of different angles between the vectors, the resultant will fall somewhere between 4 m and 12 m.

Answer:

-(0.330m/s² ) kˆ

Explanation:

given data:

Mass of particle 'm'= 1.81 x [tex]10^{-3}[/tex] kg

Velocity 'v'= (3.00 x[tex]10^{4}[/tex] m/s)j

Charge of particle 'q'= 1.22 x [tex]10^{-8}[/tex] C

Uniform magnetic field 'B' = (1.63iˆ + 0.980jˆ )T

In order to calculate particle's acceleration, we'll use Newton's second law of motion i.e F=ma

Also,the force a magnetic field exerts on a charge q moving with velocity v is called the magnetic Lorentz force. It is given by:

F = qv × B

F= ma = qV x B

a= [tex]\frac{q(v*B)}{m}[/tex] --->eq(1)

Lets determine the value of (v x B) first

v x B= (3.00 x[tex]10^{4}[/tex] m/s)j x (1.63iˆ + 0.980jˆ )

v x B= 4.89 x [tex]10^{4}[/tex]

Plugging all the required values in eq(1)

a= [1.22 x [tex]10^{-8}[/tex] x (4.89 x [tex]10^{4}[/tex]kˆ)] / 1.81 x [tex]10^{-3}[/tex]

a=  -(0.330m/s² ) kˆ

-ve sign is representing the opposite direction

Answer:

All of the above!

Explanation:

All of the answers are true! I hope I helped!

Answer:

Drinking 20oz of sports drinks decrease the urine volume compared to 20oz of water

Explanation:

Sport drinks typically used by athletes contain water,carbs and electrolytes which helps to replenish the lost minerals from the body during exercises.

Electrolytes an important ingredients of sports drinks is typically sodium and potassium they help the body to retain water,hence less volume of urine is released from the body.

Correct question:

A child bounces a 57 g superball on the sidewalk. The velocity change of the superball is from 24 m/s downward to 11 m/s upward. If the contact time with the sidewalk is 1/800 s, what is the magnitude of the average force exerted on the superball by the sidewalk? Answer in units of N.

Answer:

The magnitude of the average force exerted on the superball by the sidewalk is 592.8 N

Explanation:

Given;

mass of the superball, m = 57 g = 0.057 kg

initial velocity of the superball, u = 24 m/s

final velocity of the superball, v = 11  m/s

contact time with the sidewalk, t =  1 / 800 s

To determine the magnitude of the average force exerted on the superball by the sidewalk, we apply Newton's second law of motion;

F = ma

[tex]But, a = \frac{v-u}{t} \\\\Thus, F = m(\frac{v-u}{t} )\\\\F = 0.057(\frac{11-24}{1/800} )\\\\F = 0.057(\frac{-13}{1/800})\\\\F = -0.057(\frac{800*13}{1})\\\\ F = -592.8 \ N\\\\Magnitude \ of \ the \ force \ is \ 592.8 \ N[/tex]

Therefore, the magnitude of the average force exerted on the superball by the sidewalk is 592.8 N

Explanation:

THERE FORE THE REACTION IS FRICTION FORCE.

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It should be pushing because when you swim you are pushing yourself

Answer:

d. will increase

Explanation:

The process is spinning is known as stellar rotation, it is the rotation of a star about it axis in an angular direction. Now, A single star in the process of forming starts by spinning slowly which is as a result of its size but as  the star collapses under the pull of its own gravity, the radius of the size shrinks and reduces, then the  spinning rate escalate and increases.

Answer:

6.45 x 10-7 meters

Explanation:

Taking speed of light as 300000000 m/s

We know that speed of light is product of wavelength and frequency and expressed as

s=fw

Where s represent speed, f is frequency and w is wavelength

Substituting 4.65*10^14 Hz for frequency then the wavelngth will be given by

300000000=4.65*10^14 *w

w=300000000÷4.65*10^14

w=6.451612903225*10^-7 m

Rounded off, the wavelength is 6.45 x 10-7 meters

Answer:

60V

Explanation:

240V/12 loops = 20 volts per loop.

20 * 3 = 60 volts  

Answer:

60V

Explanation:

Answer:

See explanation

Explanation:

Depth: Earthquakes can happen anywhere from at the surface to 700 kilometers below. In general, deeper earthquakes are less damaging because their energy dissipates before it reaches the surface. So it is highly likely that the earthquake 1 was shallower than earthquake 2.

Distance from the epicenter: The epicenter is the point at the surface right above where the earthquake originates and is usually the place where the earthquake's intensity is the greatest. Plausible that earthquake 1 might have been closer to its epicenter as compared to earthquake 2.

Local geologic conditions: The nature of the ground at the surface of an earthquake can have a profound influence on the level of damage. Loose, sandy, soggy soil, like in Mexico City, can liquefy if the shaking is strong and long enough, for example. That doesn't bode well for any structures on the surface. Plausible that the area around the earthquake 1 might have poorer geologic conditions as compared to area of earthquake 2.

Answer:

Chemical

Explanation:

Jordana pulled a muscle while running at a track meet. Her coach gave her a self-heating pack to treat the injury. The instructions on the box said to twist the pack until the liquids mix. Chemical energy contained in the pack is responsible for producing the heat.

Chemical energy is the energy that is released when chemical substances engage in a chemical reaction and change into other substances. Batteries, food, and gas are a few examples of chemical energy storage mediums.

Chemical energy is the energy held in atom and molecule bonding. Chemical energy can be found in things like batteries, biomass, oil, natural gas, and coal. When humans burn fuel in a car's engine or wood in a fireplace, chemical energy is transformed into thermal energy.

Around the world, we generate heat and power using chemical energy. Methane, natural gas, oil, and petroleum are examples of fossil fuels that we burn to create steam that turns turbines to generate power.

Thus, Chemical energy contained in the pack is responsible for producing the heat.

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Answer:

5.67 m/s ( towards left)

Explanation:

We are given that

[tex]m_1=6 kg[/tex]

[tex]m_2=10 kg[/tex]

Speed of mass 10 kg=3.4 m/s

We have to find the velocity of other mass.

When there is no external force applied the the linear momentum will be conserved

[tex]-m_2v_2=m_1v_2[/tex]

Substitute the values

[tex]10\times 3.4=6v_1[/tex]

[tex]v_1=-\frac{10\times 3.4}{6}[/tex]

[tex]v_1=-5.67 m/s[/tex]

The mass 6 kg moves to the left with speed 5.67 m/s.