The grams of fat present is 12 grams.
Based on the given information,
• A slice of pizza contains 13 grams of protein, 29 grams of carbs.
• The total calories present in the pizza is 280 kcal.
Now there is a need to find the grams of fat present in the pizza,
Total calories = 280 kcal
Total calories of carbohydrates = 29 × 4 kcal (1 g of carb contain 4kcal of energy) = 116 kcal.
Total calories of protein = 13 × 4 kcal (1 g of protein contains 4kcal of energy) = 52 kcal.
Calories due to fat = (280 kcal) - (116 kcal + 52 kcal)
= 112 kcal
1 gram of fat contains 9kcal of energy. The amount of fat can be determined as,
Amount of fat = (112/9) g = 12.44 grams or 12 grams of fat.
Thus, the grams of fat present is 12 grams.
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Determine the number of particles in each of the following. Show the unit conversion method. A. 0.250 mol silver B. 8.56 x 10-3 mol NaCl C. 35.4 mol CO2 D. 0.425 mol N2
The number of particles in A is 1.506 x 10²³, in B is 5.156 x 10²⁰, in C is 2.131 x 10²⁵, and in D is 2.559 x 10²³.
What is the number of particles in the given elements or compounds?To determine the number of particles in each of the following substances, it is required to use Avogadro's number, which is 6.022 x 10²³ particles per mole. We can use dimensional analysis, also known as the unit conversion method, to convert from moles to particles.
A. 0.250 mol silver
Number of particles = 0.250 mol x 6.022 x 10²³ particles/mol
Number of particles = 1.506 x 10²³ particles
B. 8.56 x 10⁻³ mol NaCl
Number of particles = 8.56 x 10⁻³ mol x 6.022 x 10²³ particles/mol
Number of particles = 5.156 x 10²⁰ particles
C. 35.4 mol CO₂
Number of particles = 35.4 mol x 6.022 x 10²³ particles/mol
Number of particles = 2.131 x 10²⁵ particles
D. 0.425 mol N₂
Number of particles = 0.425 mol x 6.022 x 10²³ particles/mol
Number of particles = 2.559 x 10²³ particles
Therefore, there are approximately 1.506 x 10²³ particles in 0.250 mol of silver, 5.156 x 10²⁰ particles in 8.56 x 10⁻³ mol of NaCl, 2.131 x 10²⁵ particles in 35.4 mol of CO₂, and 2.559 x 10²³ particles in 0.425 mol of N₂.
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Based on the entries in the following table, which element is most commonly bonded to the acidic hydrogen? table some weak acids in water at 25 ∘c
Final answer:
Hydrogen bonding in acids, solvation energy terms, and the impact of strong acids on conjugate bases are crucial concepts in understanding acid dissociation and acid-base behavior in solution.
Explanation:
Hydrogen bonding occurs when a hydrogen atom, part of a polar covalent bond, is bonded to a more electronegative atom. In the case of acids, hydrogen bonds form between the hydrogen atom of the acid (H-A) and water molecules. This results in the acid dissociation process, where the acid molecule becomes an anion.
Solvation energy terms play a crucial role in driving hydrogen ion transfer in solution. Despite thermodynamic considerations indicating that most strong Brønsted acids should not act as acids towards water, solvation energy terms, aided by entropic effects, drive hydrogen ion transfer in solution.
In general, strong acids form very weak conjugate bases, while weak acids form stronger conjugate bases. Water has a leveling effect on dissolved acids, generating hydronium and hydroxide ions, the strongest acid and base in water.
If 5.400 g of c6h6 is burned and the heat produced from the burning is added to 5691 g of water at 21 °c, what is the final temperature of the water?
The final temperature of the water : 30.506 °C
Further explanationThe law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released
Qin = Qout
Heat can be calculated using the formula:
Q = mc∆T
m = mass, g
∆T = temperature difference, °C / K
From reaction:
2C₆H₆ (l) + 15O₂ (g) ⟶12CO₂ (g) + 6H₂O (l) +6542 kJ, heat released by +6542 kJ to burn 2 moles of C₆H₆
If there are 5.400 g of C₆H₆ then the number of moles:
mol = mass: molar mass C₆H₆
mol = 5.4 : 78
mol C₆H₆ = 0.0692
so the heat released in combustion 0.0692 mol C₆H₆:
[tex]\rm Q=heat=\dfrac{0.0692}{2}\times 6542\:kJ\\\\Q=226.353\:kJ[/tex]
the heat produced from the burning is added to 5691 g of water at 21 C
So :
Q = m . c . ∆T (specific heat of water = 4,186 joules / gram ° C)
226353 = 5691 . 4.186.∆T
[tex]\rm \Delta T=\dfrac{226353}{5691\times 4.186}\\\\\Delta T=9.506\\\\\Delta T=T(final)-Ti(initial)\\\\9.506=T_f-21\\\\T_f=30.506\:C[/tex]
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which of the following is an inorganic compound?
h2o water molecule
ch3(ch2)3ch3 pentane
c4h10 butane
c6h12o6 glucose,
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PLESE HELP
According to Ampere, which of the following sets of current-carrying wires would repel each other? The arrow point indicates the direction of the current in each wire.
Answer: Option (c) is the correct answer.
Explanation:
When current passes through a wire then a magnetic field is formed. Therefore, when two wires carry current in the same direction then both the wires with have respective magnetic fields in the same direction and their total magnetic field will be large.
But when current between two wires flow in opposite direction then the magnetic field produced will also be in opposite direction. Therefore, both the magnetic fields cancel each other out. Thus, total magnetic field will be small.
As a result, wires which carry current in the opposite direction repel each other.
Can someone help me please?
If 75.0 g of silderite ore (FeCO3) is heated with an excess of oxygen, 45.0 g of ferric oxide (Fe2O3) is produced.
4feCO3(s) + O2(g) -> 2fe2O3(s) + 4CO2(g)
what is the percent of yield of this reaction?,
The mass of an object is found by _____.
comparison with standard mass units
weighing the object
displacing water
measuring the object
that's the answer comparison with standard mass units
Hello!
comparison with standard mass units
is your answer
A balloon contains 0.158 mol of gas and has a volume of 2.46 l. if an additional 0.113 mol of gas is added to the balloon (at the same temperature and pressure), what is its final volume?
Answer is: final volume is 4.21 liters.
Use Avogadro's Law (the Volume Amount Law): If the amount of gas in a container is increased, the volume increases.
The volume-amount fraction will always be the same value if the pressure and temperature remain constant.
V₁ / n₁ = V₂ / n₂.
2.46 l / 0.158 mol = V₂ / 0.271 mol.
V₂ = 4.21 l.
To find the final volume of the balloon, we can use the combined gas law equation. The initial pressure is calculated using the number of moles and volume. This pressure, along with the final number of moles, initial volume, and constant temperature, can be used to find the final volume.
Explanation:To solve this problem, we can use the combined gas law equation (P1V1/T1 = P2V2/T2) which relates the pressure, volume, and temperature of a gas. Since the temperature and pressure remain constant, we can use the equation to find the final volume. First, calculate the initial pressure by dividing the number of moles by the volume. Then substitute the initial pressure, final number of moles, and initial volume into the equation, and solve for the final volume.
Given:
N1 = 0.158 mol
N2 = 0.113 mol
V1 = 2.46 L
V2 = ?
P1 = N1/V1
Substituting the values:
P1 = 0.158 mol / 2.46 L = 0.0642 atm
Now, substitute the values into the combined gas law equation:
P1V1/T1 = P2V2/T2
Solving for V2:
V2 = (P1V1T2) / (P2T1)
Since the temperature and pressure remain constant, we can write the equation as:
V2 = (P1V1) / P2
Substituting the values:
V2 = (0.0642 atm * 2.46 L) / (0.113 mol) = 1.396 L
The final volume of the balloon is 1.396 L.
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0 ml of a 1.20 m solution is diluted to a total volume of 228 ml. a 114-ml portion of that solution is diluted by adding 111 ml of water. what is the final concentration? assume the volumes are additive.
The final concentration of the solution after the described dilution process is approximately 0.00855 M.
Let's first ascertain the original dilution's concentration. Using the dilution equation:
[tex]C_1V_1 = C_2V_2[/tex]Where:
C₁ = 1.20 M (initial concentration)V₁ = 0 mlV₂ = 228 mlC₂ = final concentration after the first dilutionSince 0 ml is a typo, let us assume the starting volume V₁ is enough such as 1 mL. Plugging in the values:
(1.20 M)(1 ml) = (C₂)(228 ml)C₂ = 1.20 / 228Now, calculate the concentration after the second dilution:
V₁ = 114 mlV₂ = 114 ml + 111 ml = 225 mlUsing the intermediate solution:
[tex]C_1V_1 = C_2V_2[/tex]
The final concentration after the second dilution is about 0.00855 M.
Among teenagers, what is the most commonly used substance?
For which of the following reactions is ΔH∘rxn equal to ΔH∘f of the product(s)?
You do not need to look up any values to answer this question.
Check all that apply.
Check all that apply.
C(s,graphite)+O2(g)→CO2(g)
Li(s)+12F2(l)→LiF(s)
CO(g)+12O2(g)→CO2(g)
BaCO3(s)→BaO(s)+CO2(g)
2Li(s)+F2(g)→2LiF(s)
Li(s)+12F2(g)→LiF(s)
inal answer:
The reaction C(s, graphite) + O2(g) → CO2(g) is the one where ΔH°rxn equals the ΔH°f of the product, CO2(g), because it forms carbon dioxide from its constituent elements in their standard states. Option A
Explanation:
For an element or compound, the enthalpy change (ΔH) of a reaction that forms it from its elements in their standard states is called the standard enthalpy of formation (ΔH°f).
Therefore, ΔH°rxn is equal to ΔH°f for a reaction that produces a compound directly from its constituent elements in their most stable forms at 1 atm pressure and 25°C (298 K). Examining the provided reactions, the one that fits this description is:
C(s, graphite) + O2(g) → CO2(g)
This reaction forms carbon dioxide (CO2) directly from its elements, carbon in the form of graphite (the most stable form of carbon at standard conditions) and oxygen gas, both of which are in their standard states. Thus, ΔH°rxn for this reaction is equivalent to the ΔH°f of carbon dioxide.
Other reactions listed may be formation reactions, but they introduce compounds like fluorine in liquid form (F2(l)), which is not the standard state of fluorine at 25°C; hence, they do not meet the criteria. Option A
An atom of potassium loses one electron. what does it become a negative potassium, positive potassium
Which compound will form an acidic solution when dissolved in water? which compound will form an acidic solution when dissolved in water? nano2 khso4 kbr ba(no3)2?
Among the compounds NaNO2, KHSO4, KBr, and Ba(NO3)2, KHSO4 forms an acidic solution when dissolved in water. It can donate a proton, subsequently increasing the concentration of hydronium ions. The other compounds do not result in an increased concentration of hydronium ions and thus, do not form acidic solutions.
Explanation:When you're determining which of these compounds--NaNO2, KHSO4, KBr, Ba(NO3)2--forms an acidic solution when dissolved in water, it's important to understand how compounds behave in water. Most notably, you should know that an acidic solution contains a greater concentration of hydronium ions (H3O+) than hydroxide ions (OH-).
Sulfuric acid is a diprotic acid, which means it can donate two protons. It forms both sulfates and hydrogen sulfates in solution, and most of these compounds moderate the pH when dissolved in water. Consequently, KHSO4 is the compound that will result in an acidic solution, since upon dissolution, it can donate a proton and thereby increase the concentration of H3O+ ions.
As a note, the other compounds listed (NaNO2, KBr, Ba(NO3)2) do not increase the concentration of H3O+ ions; thus, they won't form acidic solutions. For instance, Ba(NO3)2 in a neutralization reaction with water will form a neutral salt and water.
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Consider the following reaction. 2Fe2O3 --> 4Fe + 3O2 deltaH = +824.2KJ The formation of 42.0 g of O2 results in? 1) the absorption of 361 kJ of heat. 2) the absorption of 11500 kJ of heat. 3) the absorption of 1080 kJ of heat.
The formation of oxygen in the reaction, the absorption of 361 kJ of heat takes place.
The heat of formation of oxygen will be
[tex]\rm \Delta H[/tex] is +824.2 kJ.
The positive sign of H denotes that the reaction accepts energy from the surroundings. It is an endothermic reaction.
In the reaction the % formation of Oxygen is :
Total product formed = 7 moles
Oxygen formed = 3 moles
% Oxygen formed = [tex]\rm \frac{3}{7}\;\times\;100[/tex]
% oxygen formed = 42.85 %
The total enthalpy for the formation of product is +824.2 kJ.
The enthalpy for the formation of 42.85 % Oxygen = +824.2 [tex]\times[/tex] 42.85 / 100 kJ.
The enthalpy of the formation of oxygen in the reaction will be 353.22 kJ.
The closest is 361 kJ.
So, for the formation of oxygen in the reaction, the absorption of 361 kJ of heat takes place.
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Which equation expresses Newtons second law of motion
When writing 6,020,000 in scientific notation, it is correctly written as: 6.02 x 106 6.02 x 10-6 602. x 106 0.602 x 10-8
6.02 x 10^6 is correct it's not negative because youre moving in the positive direction in terms of sci not.
When copper (ii) carbonate is heated if forms copper (ii) oxide and carbon dioxide?
Dissolving 25.00 g cucl2 in enough water to make 250 ml of solution gives a solution concentration equal to
The concentration of the solution made by dissolving 25.00 g of CuCl2 in enough water to make 250 mL of solution is 0.74 M.
Explanation:In this question, we are dealing with molarity calculation. The molarity of a solution is determined by the formula: Molarity (M) = moles of solute/volume of solution in liters. But first, we need to convert the mass of CuCl2 into moles. CuCl2 has a molar mass of about 134.45 g/mol. So, we divide 25.00 g CuCl2 by 134.45 g/mol which equals 0.185 moles. The volume of the solution is 250 mL, which we convert to liters to match the units in the molarity formula. This gives us 0.250 L. We now substitute these values into the molarity formula - M = 0.185 moles/0.250 L = 0.74 M. Therefore, the concentration of the solution is 0.74 M.
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Many manufacturing processes involve chemical reactions that reach equilibrium. Why would chemists adjust conditions to favor the forward reaction in a process
Who wants a metal?
Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?
Both have the same molar mass.
Both have the same number of ions.
Both are made up of 6.02 x 10^23 molecules.
Both are made up of 6.02 x 10^23 formula units.,
Which best compares 1 mol of sodium chloride to 1 mol of aluminum chloride?
A. Both have the same molar mass.
B. Both have the same number of ions.
C. Both are made up of 6.02 mc014-1 1023 molecules.
D. Both are made up of 6.02 mc014-2 1023 formula units.
The correct answer on E.D.G is ---Both are made up of 6.02 mc014-2 1023 formula units. D
Answer: Option (d) is the correct answer.
Explanation:
A formula unit is basically empirical formula of a compound which tells us how many atoms of one element are combining with how many atoms of another element.
For example, empirical formula of sodium chloride is NaCl. So, basically it shows that one atom of sodium is reacting with one atom of chlorine.
Also according to Avogadro, there are [tex]6.022 \times 10^{23}[/tex] atoms present in 1 mole of each substance.
Thus, we can conclude that both are made up of [tex]6.022 \times 10^{23}[/tex] formula units best compares 1 mol of sodium chloride to 1 mol of aluminum chloride.
Calculate the mass of water produced when 6.97 g of butane reacts with excess oxygen
SHOW WORK!!!!!!!
a) how many meters are there in 5 kilometers.
b) Find the number of milligrams in 0.5 kilograms.
c) Convert 5 meters to kilometers.
d) Find the number of millimeters in 6.98 centimeters.
e) how many meters are equal to 2700. millimeters.
What equals the molar mass of a element
The molar mass of an element is equal to the element's atomic weight mentioned in the periodic table.
What is molar mass?
Molar mass of a compound or a molecule is defined as the mass of the elements which are present in it.The molar mass is considered to be a bulk quantity not a molecular quantity. It is often an average of the of the masses at many instances.
The molecular mass and formula mass are used as synonym for the molar mass.It does not depend on the amount of substance which is present in the sample.It has units of gram/mole.
Molar masses of an element are given as relative atomic masses while that of compounds is the sum of relative atomic masses which are present in the compound.The element's molar mass is mentioned in the box of the element's symbol in the periodic table.
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If 3.0 moles of x and 4.0 moles of y react according to the hypothetical reaction below, how many moles of the excess reactant will be left over at the end of the reaction? x + 2 y yields xy2
Which is an advantage of using chemical indicators?
A. They are inexpensive to use.
B. They have very limited use.
C. They require the use of electricity.
D. They change color at specific temperatures.,
Answer: The answer is A....... they are inexpensive to use
Explanation: got it right on Edge
How are the electron structures of boron (B) and aluminum (Al) similar?
Answer:
- Both of their valence electrons are at p subshell.
- They have the first subshell full of electrons.
- Both of them have just 1 electron at the last p subshell.
Explanation:
Hello,
In this case, we could understand their electron structures by identifying their electron configurations as shown below:
[tex]B^5\rightarrow 1s^2,2s^2,2p^1\\Al^{13}\rightarrow 1s^2,2s^2,2p^6,3s^2,3p^1[/tex]
In such a way, we could notice the following similarities:
- Both of their valence electrons are at p subshell.
- They have the first subshell full of electrons.
- Both of them have just 1 electron at the last p subshell.
Best regards.
If a solid line represents a covalent bond and a dotted line represents intermolecular attraction, which of these choices shows a hydrogen bond?
-O...H-C-
-N...H-O-
-C...H-F-
H-H
The correct option that shows a hydrogen bond is -N...H-O-, as it fits the criterion of hydrogen being covalently bonded to a highly electronegative atom (N) and attracted to a lone pair on another electronegative atom (O) in a neighboring molecule.
Explanation:If a solid line represents a covalent bond and a dotted line represents intermolecular attraction, the choice that shows a hydrogen bond is -N...H-O-. This is because hydrogen bonds are a type of dipole-dipole interaction that occurs when a hydrogen atom is covalently bonded to a highly electronegative atom, such as nitrogen (N), oxygen (O), or fluorine (F), and is attracted to a lone pair of electrons on an atom in a neighboring molecule.
Hydrogen bonds are particularly strong among dipole-dipole interactions, although they are much weaker compared to a covalent bond. Therefore, the correct answer is the one where hydrogen is bonded to nitrogen (which is highly electronegative) and is attracted to oxygen from another molecule, hence forming a hydrogen bond.
A chemical reaction takes place in which energy is absorbed arrange the characteristics of the reaction in order from start to finish
What is the estimated effective nuclear charge, Z eff, experienced by an electron in a 3p orbital of a chlorine atom?
a. -1
b. 5
c. 7
d. 17,
The estimated effective nuclear charge (Zeff) experienced by an electron in the 3p orbital of a chlorine atom is approximately 7, as inner electrons shield the nucleus' full charge of 17. This is derived from considering the electron configuration of chlorine and the shielding effects provided by inner electrons.
Explanation:The question is asking about the effective nuclear charge (Zeff) experienced by an electron in the 3p orbital of a chlorine atom. The effective nuclear charge is the net positive charge an electron feels after accounting for the shielding effect of the other electrons. A neutral chlorine atom has an atomic number of 17, which means there are 17 protons in the nucleus. However, the effective nuclear charge felt by an electron in the 3p orbital is not the full charge of 17 due to the shielding of the electrons in closer orbitals.
The electron configuration of a neutral chlorine atom is 1s22s22p63s23p5. The 10 electrons in the 1s, 2s, and 2p orbitals shield the 3p electrons from the full nuclear charge. Using Slater's rules, one can estimate the effective nuclear charge felt by a 3p electron. The value of Zeff is typically between 1 and the actual nuclear charge (Z), which is 17 for chlorine. The exact Zeff would require taking into account the actual amount of shielding provided by the inner electrons, which tends to be a complex calculation considering electron-electron interactions and the distribution of electron density.
However, based on Slater's rules and shielding effects, a rough estimate for the Zeff would be closer to the chlorine's atomic number (17) than to 1, making options a (-1) and b (5) incorrect. Since the 10 inner electrons shield the nuclear charge, a reasonable estimate for Zeff for a 3p electron in chlorine might be around 7 (17 nuclear charge - 10 shielding electrons), but advanced calculations are required for a precise value. Therefore, answer choice c (7) seems to be the most appropriate estimate based on basic principles.
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Diffusion of nonpolar molecules would not be affected by
Diffusion of nonpolar molecules is does not affected by charge. Because they have no partial charges. Hence option d is correct.
What is diffusion?Diffusion of substance is the spreading or transfer of compounds based on concentration gradient or pressure gradient. Molecules diffuses from higher concentration region to lower concentration region.
Non-polar molecules are those which have no permanent dipole moment. They have no partial charges formed during chemical bonding. Whereas, polar compounds are those having permanent dipole moment and are having partial charges.
All other factors, such as temperature, pressure, concentration and molecular size will affect the rate of diffusion. Thus for non-polar compounds charge is affecting the diffusion.
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Your question is incomplete but your complete question probably was:
Diffusion of nonpolar molecules would not be affected by
a.molecule size.
b.steepness of the concentration gradient.
c.temperature.
d.charge.
e.steepness of the pressure gradient