A small increase in aperture will result in

a.small increase in brightness large increase in brightness small decrease in size large decrease in sizea. small increase in brightness

A. Igneous

Extrusive igneous rocks cool and solidify quicker than intrusive igneous rocks. They are formed by the cooling of molten magma on the earth's surface.

Sedimentary (sed-uh-MEN-tuh-ree) rocks, unlike the other two kinds of rocks, are formed on or near Earth's surface. They form from sediments eroded from other rocks. The sediments may come from igneous, metamorphic, or other sedimentary rocks.

The answer is C.  

An object on the moon is six times lighter than on Earth.

The statement accurately describes the weight of an object on the moon is  An object on the moon is 1/6 times lighter than on Earth.

The weight is the product of mass of the object and acceleration due to gravity on the specific planet.

When the acceleration due to gravity is less, the weight measured will be less. The acceleration due to gravity on the moon is 1.6 m/s2, about a sixth that of Earth’s.

Thus, an object on the moon is 1/6 times lighter than on Earth.

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Igneous Rocks are rocks that are made from magma (molten lava). The correct order of the Igneous Rock formation is ACBD.

These are the rocks made from magma (molten lava). The magma form in the upper mantle and lower crust because of very high temperature.

These rocks form,

Therefore, the correct order of the Igneous Rock formation is ACBD.

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A 500 kg cannon exerts 600 N force on 10 kg cannon ball

Now here we can say that as per Newton's III law every action has equal and opposite reaction force

So here when cannon exert a force of 600 N on the ball then equal and opposite magnitude force will act on cannon itself

Part a)

Okay now we will find the acceleration of cannon using the same force

so as per Newton's formula

[tex]F = ma[/tex]

[tex]600 = 500 * a[/tex]

[tex]a = 1.2 m/s^2[/tex]

Part b)

Okay now we will find the acceleration of cannon ball using the given force

so as per Newton's formula

[tex]F = ma[/tex]

[tex]600 = 10 * a[/tex]

[tex]a = 60 m/s^2[/tex]

I have attached the solution as image.

Final Answer:

The two possible solutions of [tex]5x^{2} - 5 = 0[/tex] are [tex]\( x = \pm \sqrt{3} \)[/tex].

Explanation:

To find the solutions to the quadratic equation [tex]\(5x^2 - 15 = 0\)[/tex], we first add 15 to both sides to isolate the term involving [tex]\(x^2\)[/tex], yielding [tex]\(5x^2 = 15\)[/tex]. Then, we divide both sides by 5 to solve for [tex]\(x^2\)[/tex], giving us [tex]\(x^2 = 3\)[/tex]. Taking the square root of both sides, we obtain [tex]\(x = \pm \sqrt{3}\)[/tex]. Therefore, the two possible solutions are [tex]\(x = \sqrt{3}\)[/tex] and [tex]\(x = -\sqrt{3}\)[/tex]. These solutions represent the values of x for which the equation is true.

 In summary, vectors are quantities with both magnitude and direction, and their addition and multiplication by scalars follow specific rules. Scalars are quantities with only magnitude and are added by simple arithmetic. The correct option for any statement about vectors and scalars would be the one that accurately reflects these properties

To provide a solution to the question, we need to understand the key differences between vectors and scalars as described by the students in the chart. Here are the typical characteristics that distinguish vectors from scalars:

1. Magnitude and Direction: Vectors have both magnitude and direction, whereas scalars have only magnitude. This is the fundamental difference between the two. For example, velocity is a vector quantity because it describes both the speed (magnitude) and the direction of motion, while speed alone is a scalar quantity.

 2. Representation: Vectors are often represented by arrows, where the length of the arrow corresponds to the magnitude and the arrowhead indicates the direction. Scalars are typically represented by a number with units, if applicable.

 3. Addition: When adding vectors, both their magnitudes and directions must be considered, which often involves geometric construction or trigonometric calculations. In contrast, scalar addition is straightforward and involves simply adding the numerical values.

 4. Multiplication by a Scalar: Multiplying a vector by a scalar changes the magnitude of the vector but not its direction. The result is a vector that is parallel to the original vector.

 5. Dimensionality: Vectors can be one-dimensional (straight line), two-dimensional (plane), or three-dimensional (space). Scalars are zero-dimensional, as they are just single values without direction.

6. Physical Quantities: Examples of vector quantities include displacement, velocity, acceleration, and force. Examples of scalar quantities include mass, temperature, energy, and time.

 Based on these characteristics, the students' statements can be analyzed to determine if they are correct or incorrect. For instance, if a student says that a vector has only magnitude, this statement is incorrect because vectors must have both magnitude and direction.

To solve the question accurately, we would need to see the specific statements made by each student in the chart. However, without the actual statements, we can only provide a general explanation of the differences between vectors and scalars.

 In summary, vectors are quantities with both magnitude and direction, and their addition and multiplication by scalars follow specific rules. Scalars are quantities with only magnitude and are added by simple arithmetic. The correct option for any statement about vectors and scalars would be the one that accurately reflects these properties."

Amplitude and distance.

The prefix "giga..." means 1 billion. We talk about that flash drive as if its capacity is exactly 1 billion bytes.

But with digital things, a "giga..." Is actually 2^30 = 1,073,741,824 .

Solid sphere is the correct answer.

Answer:

D) A Solid Sphere

Explanation:

As per Dalton's atomic description he said that atom is not divisible and that is the smallest part of atom.

It has no net charge and it can not be divided further. So till Dalton's theory of atom electron and nucleons were not discovered.

So we can consider atom as a model of Solid sphere  because similar to a solid sphere the atom is considered to be unique and not destructible.

So here correct answer will be

D) A Solid Sphere

Answer: 1500 m/sec. ( b )

Solution:

V= f (λ)

Speed = frequency. Wavelength  

And frequency = 1/time period

First we will find the frequency :

Frequency = 1/time period

1/0.006 = 166.67 Hz

Using this in the equation:

Speed = frequency. Wavelength  

V= f (λ)

9 × 166.67  

= 1500.03 ≈ 1500

V (Speed) = 1500 m/s.

Note: Do not forget to mention the units or otherwise they may cost you marks!

Answer:

B

Explanation:

Density: g/mL, kg/cubic meter  

Volume: L, teaspoon  

Mass: g, MeV/sq. C

The common units for length, weight, and time in the American system are foot, pound, and second, respectively. In the metric system, the common units for length, weight, and time are meter, kilogram, and second, respectively.

In the American system of measurement, the common units for length, weight, and time are foot, pound, and second, respectively. For example, the ton (2240 lb) is a larger unit of weight, the yard (3 ft) is a smaller unit of length, and the minute (60 s) is a smaller unit of time.

In the metric system, the common units for length, weight, and time are meter, kilogram, and second, respectively. For example, the kilometer (1000 m) is a larger unit of length, the gram (0.001 kg) is a smaller unit of weight, and the millisecond (0.001 s) is a smaller unit of time.

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That's true, and there are also other mechanisms that can also create floods.

The circuit component the symbol represents is: C) Battery

Explanation :

An electric circuit is a closed network consisting of an electrical component. It consists of a resistor, a battery, an ammeter, a voltmeter etc.

A symbol is given to every component.

The given symbol shows a battery. It consists of more than one cell and used as a power source in a circuit. It has two terminals i.e a positive terminal and a negative terminal.          

The positive terminal of a battery is a cathode and a negative terminal is an anode.    

Hence, the correct option is (C) " battery ".

Answer:

True

Explanation:

Color is the splitting of light into different spectra. Light, by nature, is monochromatic. This means that it has one wave length. The prism experiment has proved that light has many colors. About 7 colors have been discovered.

The colors simply denote the different wavelengths of the "monochromatic" light. The colors are the different wavelengths of light when it is split.

The eye, sees color as a reflection. In the electron sense, color is as a result o electrons being "excited" or promoted from a lower orbital to a higher energy orbital.

Answer:

a)  Acceleration = [tex]8.75m/s^2[/tex]

b) Slow down acceleration = 0.625[tex]m/s^2[/tex]

c) Car travels 9.8 m

Explanation:

  Acceleration = Change in velocity/Time

a) Change in velocity = 3.5-0 = 3.5 m/s

   Time = 0.4 seconds

    Acceleration = [tex]3.5/0.4=8.75m/s^2[/tex]

b) Change in velocity = 0 - 3.5 = -3.5 m/s

   Time = 5.6 seconds

   Acceleration = [tex]-3.5/5.6=-0.625m/s^2[/tex]

   Slow down acceleration = 0.625[tex]m/s^2[/tex]

c) We have equation of motion, [tex]v^2=u^2+2as[/tex], where u is the initial velocity, u is the final velocity, s is the displacement and a is the acceleration.

 Here v = 0 m/s, u = 3.5 m/s, a = -0.625[tex]m/s^2[/tex]

 Substituting

    [tex]0^2=3.5^2-2*0.625*s\\ \\ s=9.8m[/tex]

  So, car travels 9.8 m

Answer:

    Magnitude of the force exerted by the heart muscle  = 0.03 N

Explanation:

  We have force = mass * acceleration

   Acceleration = Rate of change of velocity = Change in velocity/time = (0.32-0.20)/0.08

                          = 0.12/0.08 = 12/8 = 1.5 [tex]m/s^2[/tex]

   Mass of blood = 20 g = 20/1000 kg = 0.02 kg

   Magnitude of the force exerted by heart muscle = 0.02*1.5 = 0.03 N

The magnitude of the force exerted by the heart muscle is 0.03 N.

From Newton's second law, we know that F = ma

Where;

F = force

m = mass of the body

a = acceleration

Now we must find the acceleration from:

a = v - u/t

a = acceleration

v = final velocity

u = initial veocity

t = time taken

Substituting values;

a = 0.32 m/s -  0.20 m/s/ 0.08 s

a = 1.5 m/s^2

Since F = ma

But m was given in grams and we must convert to kilograms so m = 0.002 Kg

Therefore;

F = 0.002 Kg × 1.5 m/s^2

F = 0.03 N

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Answer:

Number of carbon, hydrogen, and oxygen atoms in sugar:

Explanation:

1) Given balanced chemical equation:

2) Mass conservation law: in a chemical reaction, the atoms are not created nor destroyed; they recombine to form new substances, so the number of atoms of each kind in the reactants is equal to the number of atoms of the same kind in the products.

3) Balance.

-----------------------------------------------------------------------------------------------------

Atom          Products                    =            Reactants

-----------------------------------------------------------------------------------------------------

C                12CO₂ ⇒ 12               =             12 in sugar

-----------------------------------------------------------------------------------------------------

H               11H₂O ⇒ 11 × 2 = 22   =             22 in sugar

-----------------------------------------------------------------------------------------------------

O               12CO₂ ⇒ 12 × 2 = 24                12 × 2 = 24 in O₂ + x in sugar

                  11H₂O ⇒ 11

                 -----------------------------       --------------------------------------------------

                  24 + 11 = 35                =         24 + x

----------------------------------------------------------------------------------------------------

Solve for x: 35 = 24 + x ⇒  x = 35 - 24 = 11 ∴ 11 O atoms in sugar

Conclusion:

Number of carbon, hydrogen, and oxygen atoms in sugar:

To create a pathway for the liquid to flow easily is a correct reason to physically connect objects with a bond wire when transferring flammable liquids. Physically connect the two conductive objects together with a bond wire to eliminate a difference in static charge potential among them. The bond wire is attached between the containers in the process of flammable filling liquid actions except for a metallic path is found.

Answer

Correct Option is A

Explanation:

Correct Option is A that is to create a pathway for the liquid to flow easily

Option B

This option is not correct because objects are not conductive.  

Option C

This option is also not correct because better options are there to lessen the spill

Hope this answer will help you

an acoustic wave carries energy

A mechanical wave----

In the A case, v0=0, in the B case v0 >0, so v is greater in the B case. In other words, v is related to the kinetic energy, since the rock B has a larger kinetic energy in the beginning, it also has a larger kinetic energy (larger velocity) in the end.

The correct answer is that rock a has a greater velocity when each rock reaches the ground at the bottom of the cliff.

To understand why rock a has a greater velocity upon impact with the ground, let's consider the physics of free-falling objects under the influence of gravity. Both rocks are subject to the acceleration due to gravity, which is approximately[tex]\(9.81 \, \text{m/s}^2\)[/tex] downward.

For rock a, which is simply dropped from rest, its initial velocity is zero. The only force acting on it is gravity, pulling it downward. Its velocity at any time \(t\) before it hits the ground can be calculated using the equation for uniformly accelerated motion:

[tex]\[ v_{a} = u_{a} + gt \][/tex]

where[tex]\(v_{a}\)[/tex] is the final velocity, [tex]\(u_{a}\)[/tex] is the initial velocity (which is zero for rock a), [tex]\(g\)[/tex] is the acceleration due to gravity, and [tex]\(t\)[/tex] is the time of fall. Since [tex]\(u_{a} = 0\)[/tex], the equation simplifies to:

[tex]\[ v_{a} = gt \][/tex]

For rock b, which is thrown upward, its initial velocity[tex]\(u_{b}\)[/tex] is upward and has some positive value. As it rises, it slows down due to the acceleration due to gravity acting in the opposite direction of its motion. At its highest point, its velocity will be zero, and then it will start to fall back down, accelerating due to gravity until it hits the ground. The velocity of rock b just before impact can be calculated using the same equation for uniformly accelerated motion, but taking into account that it starts with an initial upward velocity and then reverses direction:

[tex]\[ v_{b} = u_{b} - gt_{up} + gt_{down} \][/tex]

where [tex]\(t_{up}\)[/tex]is the time it takes for rock b to reach its highest point and \[tex](t_{down}\)[/tex]is the time it takes to fall back to the ground. Since the acceleration due to gravity is the same for both rocks, and assuming that air resistance is negligible, the time of ascent [tex]\(t_{up}\)[/tex] for rock b is equal to the time of descent [tex]\(t_{down}\), so \(t_{up} = t_{down} = t/2\).[/tex] The equation for rock b's velocity upon impact becomes:

[tex]\[ v_{b} = u_{b} - g(t/2) + g(t/2) \] \[ v_{b} = u_{b} \][/tex]

Since rock a was dropped from rest, its velocity upon impact is due solely to the acceleration due to gravity over the entire time \(t\) of its fall, while rock b's velocity upon impact is its initial launch velocity minus the effect of gravity over half the time (as it rises) and plus the effect of gravity over the other half of the time (as it falls).

Because rock a starts from rest and only accelerates downward, it will have a greater velocity upon impact than rock b, which has its initial upward velocity reduced by the same gravitational acceleration over the time of its ascent and then increased by the same gravitational acceleration over the time of its descent. Thus, rock a's velocity at the moment of impact will be greater than rock b's velocity at the moment of impact, assuming they both hit the ground at the same time and air resistance is negligible.

we know that

the speed is equal to

[tex]speed=\frac{distance}{time}[/tex]

The slope of the line on the graph is equal to the speed of the car

so

during the segment B the slope of the line is equal to zero

that means

the speed of the car is zero

therefore

the answer is the option B

The car has come to a stop and has zero velocity

Option (B) is correct .i.e. the car has come to a stop and has zero velocity.

Further Explanation:

According to the theory of graphs, ‘the straight line parallel to x axis’ means the quantity given on y axis is not changing or is constant with respect to the change in the quantity on x axis. This is why because the slope of that particular straight line is zero.

Concept:

Mathematically, the slope is defined as the tangent (trigonometry) of the angle made by the segment with the x axis or it is also defined as the ratio of change in the quantity on y-axis to change in the quantity on x-axis.

[tex]\boxed{\text{slope}=\tan(\theta)}[/tex]

Here, [tex]\theta[/tex] is the angle made by the segment of graph with x-axis

The slope can also be expressed as:

[tex]\boxed{\text{slope}=\dfrac{\text{change in quantity given on y-axis}}{\text{change in quantity given on x-axis}}}[/tex]

Here, the quantity given on y axis is car’s position and that given on x axis is time taken by the car to travel.

The slope of position-time graph gives velocity.  So, by the definition of slope, we have  

[tex]{\text{velocity}=\dfrac{\text{change in position}}{{\text{change in time}}}[/tex]

Here, as shown in the graph, the two ends of the segment B have same values of position on y axis. So, change in position will be zero.

Substitute [tex]0[/tex] for [tex]\text{change in position}[/tex] in above expression.

[tex]\text{Velocity}=0\text{ m/s}[/tex]

This shows that the speed of the car in the segment B of the graph will be zero as there is no change in the position of the car with respect to time.

Thus, option (B) is correct .i.e. the car has come to a stop and has zero velocity.

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Answer Details:

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords:

Position, car, relation to time, segment B, 80 sec, zero velocity, travelling, faster, graph, position vs time, constant velocity, slope, change in position, change in time.

a falling rain drop may be an example.

Answer:

When a ball is dropped from some height from rest then while its motion under gravity its initial gravitational potential energy converts into kinetic energy

Explanation:

When ball is placed at some height "h" above the floor at rest then initial gravitational potential energy is given as

[tex]U = mgh[/tex]

here we know

m = mass of the ball

g = acceleration due to gravity

h = height of the ball

now when ball is dropped from this height then its initial potential energy will convert into kinetic energy.

so speed of ball at some instant of time is given as

[tex]\frac{1}{2} mv^2 = mgh[/tex]

[tex]v = \sqrt{2gh}[/tex]

so here in this case gravitational potential energy will convert into kinetic energy of ball

From that particular list:

Mica (A), Quartz (B), and Copper (D) are minerals.

Steam (C) isn't.

Answer:

C. 1.00 m/s^2

Explanation:

We can solve the problem by using Newton's second law:

[tex]F=ma[/tex]

where

F is the net force acting on an object

m is the mass of the object

a is its acceleration

In this case, the net force applied by Amber is F=35 N, while the total mass of the brother+the wagon is

[tex]m=32 kg+3 kg=35 kg[/tex]

Therefore, we can re-arrange the previous equation to find the acceleration:

[tex]a=\frac{F}{m}=\frac{35 N}{35 kg}=1.00 m/s^2[/tex]

Answer:

trade winds

Explanation:

In tropics regions on the lower portion of earth's atmosphere the surface winds are observed in prevailing pattern. In northern hemisphere the trade wind predominantly blows from north east. In southern hemisphere it flows from south east. Subtropical high and the equator is in between these areas.

Thus, trade wind blow between the subtropical high and the equator.

Answer:

trade winds

Explanation:

The average velocity for the entire curve on a position-time graph can be found by calculating the slope between the initial and final points. In this case, the average velocity is -4 m/s.

The correct answer would be Option A: -4 m/s.

To find the average velocity for the entire curve on a position-time graph, you can calculate the slope of the line connecting the initial and final points on the graph.

In this case, it looks like the curve has a downward slope, so the average velocity would be negative. Based on the given answer options, the correct answer would be Option A: -4 m/s.

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In the experiment of free fall bob released a bag of mass 1 lb

so here we can say that initial speed of the bag is Zero

time taken by the bag to free fall is given as

t = 1.5 s

also the acceleration of free fall is given as

a = 9.8 m/s^2

now we will use kinematics equation here for finding the distance of free fall

[tex]d = v_i * t + \frac{1}{2} at^2[/tex]

[tex]d = 0 + \frac{1}{2}*9.8* 1.5^2[/tex]

[tex]d = 4.9 * 2.25[/tex]

[tex]d = 11.025 m[/tex]

so the bag will fall down by total distance of 11.025 m from its initial released position.

The 1.0 lb bag of feathers has traveled approximately 11.025 meters after falling for 1.5 seconds, assuming it is in free fall and subject to Earth's gravitational acceleration of 9.8 m/s².

To determine the distance the 1.0 lb bag of feathers has traveled after falling for 1.5 seconds, assuming it has reached free fall and is only affected by gravitational acceleration, we can use the formula for the distance covered by an object in free fall:

d = ½ * g * t²,

where g is the acceleration due to gravity (9.8 m/s²) and t is the time in seconds.

Plugging in the values:

d = ½ * 9.8 m/s² * (1.5 s)²

d = ½ * 9.8 * 2.25

d = ½ * 22.05

d = 11.025 meters

Therefore, the bag of feathers has traveled approximately 11.025 meters after falling for 1.5 seconds.

Answer:

a)  Initial speed of the ball = 14.45 m/s

b) At height 6 m speed of ball = 9.55 m/s

c) Maximum height reached = 10.65 m

Explanation:

a)  We have equation of motion [tex]s=ut+\frac{1}{2} at^2[/tex], where s is the displacement, u is the initial velocity, t is the time taken and a is the acceleration.

s = 6 m, t = 0.5 seconds, a = acceleration due to gravity value = -9.8[tex]m/s^2[/tex]

 Substituting

    [tex]6=u*0.5-\frac{1}{2} *9.8*0.5^2\\ \\ u=14.45m/s[/tex]

 Initial speed of the ball = 14.45 m/s

 b) We have equation of motion [tex]v^2=u^2+2as[/tex], where v is the final velocity

   s = 6 m, u = 14.45 m/s, a = -9.8[tex]m/s^2[/tex]

    Substituting

        [tex]v^2=14.45^2-2*9.8*6\\ \\ v=9.55m/s[/tex]

  So at height 6 m speed of ball = 9.55 m/s

c) We have equation of motion [tex]v^2=u^2+2as[/tex], where v is the final velocity

   u = 14.45 m/s, v =0 , a = -9.8[tex]m/s^2[/tex]

   Substituting

     [tex]0^2=14.45^2-2*9.8*s\\ \\ s=10.65 m[/tex]

  Maximum height reached = 10.65 m