Answer:
Copy MATLAB code to plot the magnitude of magnetic field strength with respect to z on the axis of solenoid:
z=-20:0.01:20;
H=120.*(((20-(2.*z))./sqrt((20-(2.*z)).^2+100))+((20+(2.*z))./sqrt((20+(2.*z)).^2+100)));
plot(z,H)
title('plot of |H| vs z along the axis of solenoid')
ylabel('Magnitude of magnetic field 'H")
xlabel('position on axis of solenoid 'z")
Explanation:
full explanation is attached as picture and the resultant plot also.
Go online and search for information about companies that have been harmed or bankrupted by a disaster. Choose one such company and create a brief case study about it. Successful narratives will focus on the manner in which the organization was impacted, including financial losses, losses of sales, or the need for layoffs.
Answer:
See explaination
Explanation:
In recent times and in the past, so many companies have been dealt with or bankrupted by disaster.
This disasters are in the form of floods, earthquake and tsunami. This has led to many companies across world to have faced problem. As Japan is particularly vulnerable to natural disaster because of its climate and topography let me take example of japan .The tsunami that struck Japan in March this year which has lead to a debt of worth nearly $8 billion due to failed businesses. A total of 341 firms in japan with a combined 6,376 employees has got affected by this disaster.
One of company that hit hard by these disaster is Toyota. Toyota is a Japanese multinational automotive manufacturer headquartered in Toyota, Aichi, Japan. Actually due to flood in thailand toyota has faced a big loss. As flood hit thailand the parts of vehicle which is produced in thailand has stopped . It leads to interruption in the supply chain of some Thailand made components.
This lead to suspension of production as thai made component was unavailable.It has been reported until the situation of thailand will be good toyota plants in Indiana, Kentucky and Ontario, Canada, will be shut down . And production rate at plant in North America will get slow down .This flood leads to a loss of 37500 vehicles .Due to this reason toyota was forced to open its plants in Southeast asian country just to enhance the production rate.Sales of vehicle has also got reduced in thailand . Hence toyota faced a total loss of 1.6 billion dollar.
In Nigeria, due to the insurgency of the Boko Haram, many companies have entirely stopped operations in some regions, this harsh realities leads to massive loss of revenue for such companies.
A two-dimensional reducing bend has a linear velocity profile at section (1) . The flow is uniform at sections (2) and (3). The fluid is incompressible and the flow is steady. Find the maximum velocity, V1,max, at section (1).
To find the maximum velocity at section (1) in a two-dimensional reducing bend with a linear velocity profile, apply the principle of conservation of mass and the equation Q = Av. The maximum velocity, V1,max, occurs at section (1) where the cross-sectional area is the smallest.
Explanation:To find the maximum velocity, V1,max, at section (1) in a two-dimensional reducing bend with a linear velocity profile at section (1), we can apply the principle of conservation of mass. As the cross-sectional area decreases, the velocity increases to maintain constant flow rate. At section (1), the velocity is maximum due to the smallest area.
Using the equation Q = Av, where Q is the flow rate, A is the cross-sectional area, and v is the velocity, we can determine the maximum velocity at section (1). The maximum velocity, V1,max, occurs at section (1) where the cross-sectional area is the smallest, resulting in the highest velocity to maintain flow rate continuity.
The size of an engine is called the engine
A. bore.
B. stroke.
C. displacement.
D. mass.
A and B connect the gear box to the wheel assemblies of a tractor, and shaft C connects it to the engine. Shafts A and Blie in the vertical yz plane, while shaft C is directed along the x axis. Replace the couples applied to the shafts with a single equivalent couple, specifying its magnitude and the direction of its axis.
The couplings are not all on the same axis or plane, but if the A and B connector were to be described, it would travel with a magnitude of roughly 15 by the yz axis diagonal to the x axis. The axis would be oriented so that it was pointing upward into the second quadrant.
What is magnitude?In terms of physics, magnitude is just "distance or quantity." It displays an object's size, direction, or motion in absolute or relative terms. It is employed to indicate the size or scope of something.
In physics, the term "magnitude" often refers to a size or amount. Magnitude is defined as "how much of a quantity." The magnitude can be used, for instance, to compare the speeds of a car and a bicycle.
It can also be used to indicate how far something has come or how much something weighs relative to its size.
Thus, The couplings are not all on the same axis or plane.
For more details about magnitude, click here:
https://brainly.com/question/14452091
#SPJ2
A certain well-graded sand deposit has an in-situ relative density of about 50%. A laboratory strength test on a sample of this soil produced an effective friction angle of 31. Does this test result seem reasonable? Explain the basis for your response.
Answer:
The result seem reasonable.
Explanation:
Relative density shows us how heavy a substance is in comparison to water.It aids us in determine the density of an unknown substance by knowing the density of a known substance. Relative density is defined as the ratio of the density (mass of a unit volume) of a substance to the density of a given reference material. It is very important in the accurate determination of density.
Relative density= emax - e/emax - emin× 100
Relative density ranges between 35 and 65 because the soil is in medium state.
For well graveled sand, maximum friction angle is uo^r
and for minimum friction angle, minimum friction angle is 33°.
Therefore, for given friction angle of 31° (shear strength criteria). This result seem reasonable.
Therefore, it is worthy to note that if friction angle is more, the shear strength is more which implies that it is a densified soil, that is to say, void ratio decreases.
A three-phase source delivers 4.8 kVA to a wye-connected load with a phase voltage of 214 V and a power factor of 0.9 lagging. Calculate the source line current and the source line voltage.
Answer:
a) 7.5A
b) 370V
Explanation:
Note that the Line current is the current through any one line between a three-phase source and load.
From the given question, The source line current =7.5A(approximately)
While the Source line voltage = 370V.
Kindly go through the attached file for a step by step detail of how I arrived at these answers.
The source line current in the three-phase system is 2.08 A and the source line voltage is approximately 371 V.
Explanation:To calculate the source line current and the source line voltage in a three-phase system, we can use the formula:
I = P / (sqrt(3) * V * PF)
Where I is the source line current, P is the power delivered to the load, V is the phase voltage, and PF is the power factor.
Given that the power delivered is 4.8 kVA, the phase voltage is 214 V, and the power factor is 0.9 lagging, we can substitute these values into the formula and calculate:
I = 4.8 kVA / (sqrt(3) * 214 V * 0.9)
Calculating this gives us a source line current of 2.08 A.
To find the source line voltage, we can use the formula:
Vline = sqrt(3) * Vphase
Substituting the phase voltage of 214 V into the formula gives us a source line voltage of approximately 371 V.
Consider incompressible flow in a circular channel. Derive general expressions for Reynolds number in terms of (a) volume flow rate Q and tube diameter D and (b) mass flow rate mp and tube diameter. The Reynolds number is 1800 in a section where the tube diameter is 6 mm. (c) Find the Reynolds number for the same flow rate in a section where the tube diameter is 6 mm.
Answer:
a) [tex]Re = \frac{4\cdot \rho \cdot Q}{\pi\cdot \mu\cdot D}[/tex], b) [tex]Re = \frac{4\cdot \dot m}{\pi\cdot \mu\cdot D}[/tex], c) 1600
Explanation:
a) The Reynolds Number is modelled after the following formula:
[tex]Re = \frac{\rho \cdot v \cdot D}{\mu}[/tex]
Where:
[tex]\rho[/tex] - Fluid density.
[tex]\mu[/tex] - Dynamics viscosity.
[tex]D[/tex] - Diameter of the tube.
[tex]v[/tex] - Fluid speed.
The formula can be expanded as follows:
[tex]Re = \frac{\rho \cdot \frac{4Q}{\pi\cdot D^{2}}\cdot D }{\mu}[/tex]
[tex]Re = \frac{4\cdot \rho \cdot Q}{\pi\cdot \mu\cdot D}[/tex]
b) The Reynolds Number has this alternative form:
[tex]Re = \frac{4\cdot \dot m}{\pi\cdot \mu\cdot D}[/tex]
c) Since the diameter is the same than original tube, the Reynolds number is 1600.
An average person produce 0.25 kg of moisture while taking a shower and 0.05 kg while bathing in a tub. Consider a family of four who each shower once a day in a bathroom that is not ventilated. Taking the heat of vaporization of water to be 2450 kJ/kg, determine the contribution of showers to the latent heat load of the air conditioner per day in summer?
Answer:
Q = 2450 KJ/day
Explanation:
We are given;
The amount of moisture produced by a person while taking shower; m = 0.25 kg/person
Total number of persons in the family; N = 4
Latent heat of vaporization of water:
h_fg = 2450 KJ/kg
Since amount of moisture per person is 0.25kg per day,thus for 4 people, total mass; m_total = 4 x 0.25 = 1 kg per day
The formula for the amount of latent heat added to the space due to shower per day, is given as;
Q = m_total x h_fg
Plugging in the relevant values;
Q = 1 x 2450 = 2450 KJ/day
Water is flowing in a pipe. Which is the correct statement about the effect of an increase in the Reynolds number of the flow:
a.if the flow is laminar it cannot become turbulent if the wall is smooth.
b.if the flow is turbulent it could become laminar.
c.if the flow is laminar it could become turbulent.
d.if the flow is laminar it cannot become turbulent unless the wall is rough.
Answer:
c.if the flow is laminar it could become turbulent.
Explanation:
The Reynolds number (Re) is a dimensionless quantity used to help predict flow patterns in different fluid flow situations. At low Reynolds numbers of below 2300 flows tend to be dominated by laminar, while at high Reynolds numbers above 4000, turbulence results from differences in the fluid's speed and direction. In between these values is the transition region of flow.
In practice, fluid flow is generally chaotic, and very small changes to shape and surface roughness of bounding surfaces can result in very different flows.
Traditional password entry schemes are susceptible to "shoulder surfing" in which an attacker watches an unsuspecting user enter their password or PIN number and uses it later to gain access to the account. One way to combat this problem is with a randomized challenge-response system. In these systems, the user enters different information every time based on a secret in response to a randomly generated challenge. Consider the fol- lowing scheme in which the password consists of a five-digit PIN number (00000 to 99999). Each digit is assigned a random number that is 1, 2, or 3. The user enters the random numbers that correspond to their PIN instead of their actual PIN numbers.For example, consider an actual PIN number of 12345. To authenticate the user would be presented with a screen such as:PIN: 0 1 2 3 4 5 6 7 8 9 NUM: 3 2 3 1 1 3 2 2 1 3The user would enter 23113 instead of 12345. This doesn’t divulge the password even if an attacker intercepts the entry because 23113 could correspond to other PIN numbers, such as 69440 or 70439. The next time the user logs in, a different sequence of random numbers would be generated, such as: PIN: 0 1 2 3 4 5 6 7 8 9 NUM: 1 1 2 3 1 2 2 3 3 3Your program should simulate the authentication process. Store an actual PIN number in your program. The program should use an array to assign random numbers to the digits from 0 to 9. Output the random digits to the screen, input the response from the user, and output whether or not the user’s response correctly matches the PIN number.I have this code so far, but would like to input cstrings and vectors to fulfill the requirements, I need help with that. This is for c++ for beginners#include #include #include #include using namespace std;void generateRandomNumbers(int *random){ // Use current time as seed for random generatorsrand(time(0));for(int i=0;i<10;i++){random[i] = 1 + rand() % 3;}}bool isMatch(string pin,string randomPin,int *random){int index;for(int i=0;i<(int)pin.length();i++){ //converting pin number to int so that we can check the random number at that indexindex = pin[i]-'0';if((randomPin[i]-'0') != random[index-1])return false;}return true;}int main(){string pin = "12345";string randomPin;int random[10];generateRandomNumbers(random);cout << "Randomly Generated numbers " << endl;for(int i=0;i<10;i++){cout << random[i] << " ";}cout << endl;cout << "Now Enter your pin interms of random numbers: ";cin >> randomPin;if(isMatch(pin,randomPin,random)){cout << "Both matches" << endl;}else{cout << "Sorry you entered wrong pin.." << endl;}}
The following code or the program will be used:
Explanation:
import java.util.Scanner;
public class Authenticate
{
public static void main(String[] args)
{
// Actual password is 99508
int[] actual_password = {9, 9, 5, 0, 8};
// Array to hold randomly generated digits
int[] random_nums = new int[10];
// Array to hold the digits entered by the user to authenticate
int[] entered_digits = new int[actual_password.length];
// Randomly generate numbers from 1-3 for
// for each digit
for (int i=0; i < 10; i++)
{
random_nums[i] = (int) (Math.random() * 3) + 1;
}
// Output the challenge
System.out.println("Welcome! To log in, enter the random digits from 1-3 that");
System.out.println("correspond to your PIN number.");
System.out.println();
System.out.println("PIN digit: 0 1 2 3 4 5 6 7 8 9");
System.out.print("Random #: ");
for (int i=0; i<10; i++)
{
System.out.print(random_nums[i] + " ");
}
System.out.println();
System.out.println();
// Input the user's entry
Scanner keyboard = new Scanner(System.in);
System.out.println("Enter code.");
String s = keyboard.next();
String s = keyboard.next();
// Extract the digits from the code and store in the entered_digits array
for (int i=0; i<s.length(); i++)
{
entered_digits[i] = s.charAt(i) - '0'; // Convert char to corresponding digit
}
// At this point, if the user typed 12443 then
// entered_digits[0] = 1, entered_digits[1] = 2, entered_digits[2] = 4,
// entered_digits[3] = 4, and entered_digits[4] = 3
/****
TO DO: fill in the parenthesis for the if statement
so the isValid method is invoked, sending in the arrays
actual_password, entered_digits, and random_nums as
parameters
***/
if (isValid (actual_password, entered_digits, random_nums)) // FILL IN HERE
{
System.out.println("Correct! You may now proceed.");
}
else
{
System.out.println("Error, invalid password entered.");
}
/***
TO DO: Fill in the body of this method so it returns true
if a valid password response is entered, and false otherwise.
For example, if:
actual = {9,9,5,0,8}
randnums = {1,2,3,1,2,3,1,2,3,1}
then this should return true if:
entered[0] == 1 (actual[0] = 9 -> randnums[9] -> 1)
entered[1] == 1 (actual[1] = 9 -> randnums[9] -> 1)
entered[2] == 3 (actual[2] = 5 -> randnums[5] -> 3)
entered[3] == 1 (actual[3] = 0 -> randnums[0] -> 1)
entered[4] == 3 (actual[4] = 8 -> randnums[8] -> 3)
or in other words, the method should return false if any of
the above are not equal.
****/
public static boolean isValid(int[] actual, int[] entered, int[] randnums)
{
int Index = 0;
boolean Valid = true;
while (Valid && (Index < actual.length))
{
int Code = actual[Index];
if (entered [Index] != randnums [Code])
{
Valid = false;
}
Index++;
}
return Valid;
}
The power P generated by a certain windmill design depends upon its diameter D, the air density ????, the air viscosity µ, the wind velocity V, the rotation rate Ωand the number of blades n. (a) Write this relationship in dimensionless form. A model windmill, of diameter 50 cm, develops 3.8 kW at sea level when V 40 m/s and when rotating at 4200 rpm. (b) What power will be developed by a geometrically and dynamically similar prototype, of diameter 15 m, in winds of 35 m/s at 500 m standard altitude from sea level? (c) What is the appropriate rotation rate
Answer:
a) check the attached files below
b) What power will be developed by a geometrically and dynamically similar prototype, of diameter 15 m, in winds of 35 m/s at 500 m standard altitude from sea level = 2184.56KW
c) What is the appropriate rotation rate = 122.5 rpm
Explanation:
please kindly check the attachment below.
For a steel alloy it has been determined that a carburizing heat treatment of 7 hour duration will raise the carbon concentration to 0.38 wt% at a point 3.8 mm from the surface. Estimate the time (in hours) necessary to achieve the same concentration at a 6.2 mm position for an identical steel and at the same carburizing temperature.
Answer:
18.6h
Explanation:
To solve this Duck's second law in form of Diffusion will be used.
Also note that since the temperature is constant D (change) will also be constant.
Please go through the attached files for further explanation and how the answer Is gotten.
1. The following is a lumped model for an antenna. The input is vin and we are interested in the current through the inductor, iout. 0.5 F 0.5 H 0.5 Ω + − vin iout (a) Find the transfer function G(s) = Iout(s) Vin(s) (b) Use the linear approximation rules to sketch the Bode Plot for G(s). (c) According to your sketch, what is the steady state output if the input is vin(t) = cos(10t)?
Answer:
(a) [tex]G(s) = \frac{i_{out(s)}}{v_{in}(s)} = \frac{2S}{S^2+4S+4}[/tex]
(b) see plot in the attached explanation.
(c) [tex]i_{out}(t) = 0.2 Cos(10t-63)[/tex]
Explanation:
See attached solution a to c
Change the open-loop transfer function into G(s) = 1 s(s+2) , Design a lag compensation so that the dominant poles of the closed-loop system are located at s = –1 ± j and the steady-state error to a unit-ramp input is less than 0.2. Verify your design by providing the compensated closed-loop system root locus and calculating the steady-state error to a unit-ramp input.
Answer:
[tex]D_c(s) = 1.8(\frac{s+1.11}{s+0.2})[/tex]
Explanation:
Code attached with picture.
1. A four-lane freeway (two lanes in each direction) is located on rolling terrain and has 12-ft lanes, no lateral obstructions within 6 ft of the pavement edges, and there are two ramps within three miles upstream of the segment midpoint and three ramps within three miles downstream of the segment midpoint. A weekday directional peak-hour volume of 1800 vehicles (familiar users) is observed, with 700 arriving in the most congested 15-min period. If a LOS no worse than C is desired, determine the maximum number of heavy vehicles that can be present in the peak-hour traffic stream.
Answer:
Maximum number of vehicle = 308
Explanation:
See the attached file for the calculation.
a hollow shaft is required to transmit 600kw at 110 rpm, the maximum torque being 20% greater than the mean. the shear stress is not to exceed 63 mpa and twist in a length of 3 meters not t exeed 1.4 degrees Calculate the minimum external diameter satisfying these conditions.
Answer:
175.5 mm
Explanation:
a hollow shaft of diameter ratio 3/8 is required to transmit 600kw at 110 rpm, the maximum torque being 20% greater than the mean. the shear stress is not to exceed 63 mpa and twist in a length of 3 meters not t exeed 1.4 degrees Calculate the minimum external diameter satisfying these conditions. G = 80 GPa
Let
D = external diameter of shaft
Given that:
d = internal diameter of the shaft = 3/8 × D = 0.375D,
Power (P) = 600 Kw, Speed (N) = 110 rpm, Shear stress (τ) = 63 MPa = 63 × 10⁶ Pa, Angle of twist (θ) = 1.4⁰, length (l) = 3 m, G = 80 GPa = 80 × 10⁹ Pa
The torque (T) is given by the equation:
[tex]T=\frac{60 *P}{2\pi N}\\ Substituting:\\T=\frac{60*600*10^3}{2\pi*110} =52087Nm[/tex]
The maximum torque ([tex]T_{max[/tex]) = 1.2T = 1.2 × 52087 =62504 Nm
Using Torsion equation:
[tex]\frac{T}{J} =\frac{\tau}{R}\\ J=\frac{T.R}{\tau} \\\frac{\pi}{32}[D^4-(0.375D)^4]=\frac{62504*D}{2(63*10^6)} \\D^3(0.9473)=0.00505\\D=0.1727m=172.7mm[/tex]
[tex]\theta=1.4^0=\frac{1.4*\pi}{180}rad[/tex]
From the torsion equation:
[tex]\frac{T}{J} =\frac{G\theta }{l}\\ J=\frac{T.l}{G\theta} \\\frac{\pi}{32}[D^4-(0.375D)^4]=\frac{62504*3}{84*10^9*\frac{1.4*\pi}{180} } \\D=0.1755m=175.5mm[/tex]
The conditions would be satisfied if the external diameter is 175.5 mm
A circular specimen of MgO is loaded in three-point bending. Calculate the minimum possible radius of the specimen without fracture, given that: the applied load is 5560 N the flexural strength is 105 MPa the separation between the supports is 45 mm Input your answer as X.XX mm, but without the unit of mm.
Answer:
radius = 9.1 × [tex]10^{-3}[/tex] m
Explanation:
given data
applied load = 5560 N
flexural strength = 105 MPa
separation between the support = 45 mm
solution
we apply here minimum radius formula that is
radius = [tex]\sqrt[3]{\frac{FL}{\sigma \pi}}[/tex] .................1
here F is applied load and is length
put here value and we get
radius = [tex]\sqrt[3]{\frac{5560\times 45\times 10^{-3}}{105 \times 10^6 \pi}}[/tex]
solve it we get
radius = 9.1 × [tex]10^{-3}[/tex] m
a steam coil is immersed in a stirred heating tank. Saturated steam at 7.50 bar condenses within the coil , and the condensate emerges at at its saturation temperature. A solvent with a heat capacity of 2.30 kJ is fed to the tank at a steady rate of 12.0 kg/min and a temperature of 25°C, and the heated solvent is discharged at the same flow rate. The tank is initially filled with 760 kg of solvent at 25°C, at which point the flows of both steam and solvent are commenced. The rate at which heat is transferred from the steam coil to the solvent is given by the expression where UA (the product of a heat transfer coefficient and the area through which the heat is transferred) equals 11.5 kJ/min·°C. The tank is well stirred, so that the temperature of the contents is spatially uniform and equals the outlet temperature.
Write a differential energy balance on the tank contents.
Answer:
d/dt[mCp(Ts-Ti)] = FCp(Ts-Ti) - FoCp(Ts-Ti) + uA(Ts-Ti)
Explanation:
Differential balance equation on the tank is given as;
Accumulation = energy of inlet steam - energy of outlet steam+ heat transfer from the steamwhere;Accumulation = d/dt[mcp(Ts-Ti)]
Energy of inlet steam = FCp(Ts-Ti)
Energy of outlet steam = FoCp(Ts-Ti)
Heat transfer from the steam = uA(Ts-Ti)
Substituting into the formula, we have;
Accumulation = energy of inlet steam - energy of outlet steam+ heat transfer from the steamd/dt[mCp(Ts-Ti)] = FCp(Ts-Ti) - FoCp(Ts-Ti) + uA(Ts-Ti)The differential energy balance is [tex]\(\frac{dT}{dt} = \frac{11.5 T_s + 690 - 39.1 T}{1748}\).[/tex]
To write a differential energy balance on the tank contents, we need to consider the energy entering and leaving the system. The system in question is the well-stirred heating tank. Here are the steps to formulate the energy balance:
1. Define the system and parameters:
- The solvent enters the tank at a flow rate of 12.0 kg/min and at a temperature of 25°C.
- The solvent has a heat capacity [tex]\( C_p = 2.30 \text{ kJ/kg°C} \).[/tex]
- The tank is initially filled with 760 kg of solvent at 25°C.
- Heat transfer rate from the steam coil to the solvent is given by
[tex]\( UA(T_s - T) \)[/tex] where [tex]\( UA = 11.5 \text{ kJ/min·°C} \), \( T_s \)[/tex] is the steam temperature, and ( T ) is the solvent temperature.
- The tank is well-stirred, ensuring uniform temperature throughout, and the outlet temperature equals the tank temperature.
2. Energy balance:
The energy balance for a well-stirred tank in differential form is given by:
[tex]\[ \frac{d(U)}{dt} = \dot{Q}_{\text{in}} + \dot{m} C_p T_{\text{in}} - \dot{m} C_p T_{\text{out}} \][/tex]
Where:
- ( U ) is the internal energy of the tank contents.
[tex]- \( \dot{Q}_{\text{in}} \)[/tex] is the heat transfer rate from the steam coil.
[tex]- \( \dot{m} \)[/tex] is the mass flow rate of the solvent.
[tex]- \( T_{\text{in}} \)[/tex] is the inlet temperature of the solvent.
[tex]- \( T_{\text{out}} \)[/tex] of the solvent (equal to tank temperature ( T ).
Since [tex]\( \dot{m}_{\text{in}} = \dot{m}_{\text{out}} = \dot{m} \) and \( T_{\text{out}} = T \):[/tex]
[tex]\[ \frac{d(U)}{dt} = UA(T_s - T) + \dot{m} C_p (T_{\text{in}} - T) \][/tex]
3. Internal energy change:
The internal energy change of the tank contents can be expressed as:
[tex]\[ \frac{d(U)}{dt} = m C_p \frac{dT}{dt} \][/tex]
Where ( m ) is the mass of the solvent in the tank (760 kg) and ( T ) is the solvent temperature in the tank.
4. Combine the equations:
Substituting [tex]\( \frac{d(U)}{dt} = m C_p \frac{dT}{dt} \)[/tex] into the energy balance:
[tex]\[ m C_p \frac{dT}{dt} = UA(T_s - T) + \dot{m} C_p (T_{\text{in}} - T) \][/tex]
5. Simplify the equation:
Substitute the given values:
[tex]- \( m = 760 \text{ kg} \)\\ - \( C_p = 2.30 \text{ kJ/kg°C} \)\\ - \( \dot{m} = 12.0 \text{ kg/min} \) - \( UA = 11.5 \text{ kJ/min·°C} \)\\ - \( T_{\text{in}} = 25 \text{ °C} \)[/tex]
[tex]\[ 760 \cdot 2.30 \frac{dT}{dt} = 11.5 (T_s - T) + 12.0 \cdot 2.30 (25 - T) \][/tex]
Simplify to:
[tex]\frac{dT}{dt} = 11.5 (T_s - T) + 27.6 (25 - T) \]\[ 1748[/tex]
Further simplify:
[tex]\[ 1748 \frac{dT}{dt} = 11.5 T_s - 11.5 T + 690 - 27.6 T \][/tex]
Combine like terms:
[tex]\[ 1748 \frac{dT}{dt} = 11.5 T_s + 690 - 39.1 T \][/tex]
Finally:
[tex]\[ \frac{dT}{dt} = \frac{11.5 T_s + 690 - 39.1 T}{1748} \][/tex]
This is the differential energy balance equation for the tank contents.
Lorraine Jean Hopping's viewpoint in "Bone Detective" is that Diane France's work has helped many people. Hopping's purpose in writing this text is to
Answer:
inform the readers about Diane and her unusual job.
Explanation:
The purpose of Lorraine Jean Hopping's viewpoint in "Bone Detective" is just to inform the readers about Diane as a person and how what she does has really helped people even though her job was really unusual. It was mainly for the purpose of passing information across to the readers and nothing else.
Answer:
Explanation:she is trying to inform you hope it helps
A silicon pn junction diode at t has a cross sectional area of cm the length of the p region is and the length of the n region is the doping concentrations are determine approximately the series resistance of the diode and the current through the diode that will produce a drop across this series resistance.
Answer:
Explanation:
r=72.3 is my thought
I hope it is helpful
Write a program to accept a one-line string (maximum of 100 characters) from the keyboard. Edit the string entered in Part 1a (with code that you write) to remove all the white space,digits, punctuation, and other special characters, leaving only the letters. Print out the resulting compressed string to the screen.
Answer:
// This program is written in C++ programming language
// Comments are used for explanatory purpose
/* The aim of this program is to to remove all the white space,digits, punctuation, and other special characters, leaving only the letters. */
// Program starts here
#include <stdio.h>
#include<iostream>
using namespace std;
int main()
{
// Declare Variable of 100 characters
char word[100];
// Prompt user for input
cout<<"Your input goes here (max, 100 characters)";
cin>>word;
// Iterate through string to check for non alphabetic characters
for (int i = 0; word[i] != '\0'; ++i) {
// Check for uppercase and lowercase letters
while (!((word[i] >= 'a' && word[i] <= 'z') || (word[i] >= 'A' && word[i] <= 'Z') || word[i] == '\0')) {
for (int j = i; word[j] != '\0'; ++j) {
word[j] = word[j + 1];
}
word[j] = '\0';
}
}
cout<<"The resulting compressed string: "<<word;
return 0;
}
Answer:
w = str(input("input your values: "))
values = ' '.join(filter(str.isalpha, w))
while len(w) < 100:
print(values)
break
Explanation:
The code is written in python
w = str(input("input your values: "))
This code ask the user to input any string values with characters, numbers, line spaces , letters etc.
values = ' '.join(filter(str.isalpha, w))
This code filters the inputted value to bring only letters. All the letter are then joined together
while len(w) < 100:
The code check if the inputted value is less than 100 characters. While it is less than 100 characters. If it is less than 100 character the next code will function.
print(values)
This code prints the joined letters after checking with a while loop to confirm the length of character is less than 100
break
The break function breaks the code whether it print the values or not.
Generally, the letters will only be printed if the character inputted is less than 100 and later break the while loop or will not print any letter if the character is greater than 100 and later break.
Air at T1 = 32°C, p1 = 1 bar, 50% relative humidity enters an insulated chamber operating at steady state with a mass flow rate of 3 kg/min and mixes with a saturated moist air stream entering at T2 = 7°C, p2 = 1 bar. A single mixed stream exits at T3 = 17°C, p3 = 1 bar. Neglect kinetic and potential energy effects
Determine
(a) the relative humidity and temperature, in °C, of the exiting stream.
To determine the relative humidity of the mixed air stream based on the information provided, one would typically use a psychrometric chart or other moist air property calculations. Without access to the required psychrometric data or tables to reference, an accurate calculation cannot be provided here, but principles of moist air mixing and conservation of mass for the water vapor can guide the process.
Explanation:To determine the relative humidity and temperature of the exiting stream in the mixing chamber problem, we need to use the principles of thermodynamics specifically relating to moist air properties. This requires using a psychrometric chart or similar calculation methods to find the properties of the mixed air stream. The information provided in the initial question about the temperatures, pressures, and humidities of the incoming air streams is used along with conservation of mass and energy principles.
However, as a tutor on Brainly, I do not have access to the necessary tables or psychrometric data through this platform, which are required to calculate the final relative humidity of the exiting stream. Such data typically includes saturation pressure, saturation temperature, and specific enthalpy of the air-water mixture at various conditions.
To solve the problem accurately, you would need to reference the appropriate psychrometric chart or software at the specific temperatures given in the question. Assuming the total pressure remains constant and using the principle of the conservation of mass for the water vapor, the mixing ratio of the incoming streams can be used to determine the mixing ratio of the outgoing stream. Then, with the final temperature known, you could identify the corresponding saturation mixing ratio and use it to calculate the relative humidity.
If we assume that the mass flow rates of both streams are equal, we can consider that the exiting air stream will be a mixture of the two streams. Given the final exit temperature of 17°C, we could interpolate between the saturation mixing ratios at the temperatures given for the two streams to estimate the relative humidity, but a more precise result would come from detailed calculations or a psychrometric chart.
Construction of a reservoir behind a dam Group of answer choices
a. stabilizes the sides of reservoir walls; the water buoys them up.
b. destabilizes the slopes because of the weight of the dam.
c. can destablize the slopes by increasing pore fluid pressure.
d. has no effect on slope stability.
Answer:
c. can destablize the slopes by increasing pore fluid pressure.
Explanation: A reservoir is a term used in Agriculture or geography to describe a location where water is either collected artificially or naturally for later use in farming or to act as dam for the supply of water in large communities. Most countries of the world make use of reservoirs to store water for future use.
For each of the three products that are observed in the NMR spectrum, there is a diagnostic proton that can be used to accurately calculate the product ratios. Calculate the percentage of the mixture that is o-bromoaniline. To answer this question correctly, you will need to use the BEST diagnostic signals for each isomer.
1. Proton assignments for each isomer: p-bromoaniline: Hd signal around 7.5 ppm (doublet, 2H), Hb signal around 6.7 ppm (doublet, 2H) o-bromoaniline: Ha and Hc signals overlapping around 7.6-7.65 ppm (multiplets, 4H total) o,p-dibromoaniline: Hb signal around 6.6 ppm (doublet, 2H), Hd signal around 7.55 ppm (doublet, 1H) o,o,p-tribromoaniline: No clear signals observed, likely not formed.
2. The isomer not observed to be formed is o,o,p-tribromoaniline. A plausible experimental explanation is that the highly brominated product is less favored due to steric hindrance and deactivation of the ring towards further electrophilic substitution.
3. Diagnostic protons for product ratio calculations: p-bromoaniline: Hb around 6.7 ppm o-bromoaniline: Ha/Hc around 7.6-7.65 ppm o,p-dibromoaniline: Hd around 7.55 ppm o,o,p-tribromoaniline: N/A (not formed)
4. Calculating product ratios using diagnostic proton integrations: p-bromoaniline: Integration of Hb signal ≈ 2.0, relative ratio = 2.0/2.0 = 100% o-bromoaniline: Integration of Ha/Hc signals ≈ 2.8, relative ratio = 2.8/4.8 ≈ 58% o,p-dibromoaniline: Integration of Hd signal ≈ 1.0, relative ratio = 1.0/3.0 ≈ 33% o,o,p-tribromoaniline: 0% (not formed)
5. Theoretical reasons for relative product abundance: i. p-bromoaniline: Dominant product due to the directing effect of the amino group favoring para substitution. ii. o-bromoaniline: Formed in moderate amounts due to some ortho substitution, but less favored than para. iii. o,p-dibromoaniline: Formed in smaller amounts due to the decreased reactivity of the ring after the first substitution. iv. o,o,p-tribromoaniline: Not formed, likely due to high steric hindrance and deactivation of the ring towards further substitution
The complete question:
The chemist’s crude product mixture was submitted for NMR analysis to give Spectrum C. Using the expected splitting patterns and chemical shift changes you predicted in part a, assign each proton for each of the isomers above (see structures on Spectrum C) by labeling each signal on the spectrum with the appropriate letter. Keep the integration ratios in mind when assigning each proton.
2. One of the four potential products above was NOT observed to be formed. Which one? Propose a very brief experimental explanation for the absence of this product.
3. For each of the three products that are observed in Spectrum C, there is a diagnostic proton that can be used to accurately calculate the product ratios. (Remember that a good diagnostic proton has a “clean” signal that has minimal overlap with other signals- see the “Using Integrations to Calculate Compound Ratios” page in the Assignment Information folder on Top Hat.) What diagnostic proton can be used to calculate product ratios for each isomer? If the isomer was not formed, write “N/A.”
4. Using the diagnostic protons you listed in part c, calculate the percent of each isomer. Show calculations for each isomer. If an isomer was not formed, write “0%.”
5. Provide a theoretical reason for the relative abundance of the following products
i. p-bromoaniline
ii. o-bromoaniline
iii. o,p-dibromoaniline
iv. o,o,p-tribromoaniline
Spectrum C bromination of aniline, crude solvent: CDCl Notes 1. Spectrum C is the zoomed-in aromatic region (6.3-7.9 ppm); amine protons are not shown 2. There are 2 overlapping signals from relevant protons at 6.60-6.65 ppm. You should assign both NH2 NH2 NH2 NH2 Br Br Chloroform H Sovent Но Hb He Br Hd ignore (possible oxidation product) 7.8 7.7 7.6 7.5 7.4 7.3 7.2 7.1 7.0 6.9 6.8 6.7 6.6 6.5 6.4 ppm p-bromoaniline o-bromoaniline o,p- dibromoaniline o,o,p- tribromoaniline %p-bromoaniline %o-bromoaniline % o,p- dibromoaniline % o,o,p- tribromoaniline. show all working. solve in hum, and form
Refrigerant 134a is the working fluid in a vaporcompression heat pump that provides 35 kW to heat a dwelling on a day when the outside temperature is below freezing. Saturated vapor enters the compressor at 1.6 bar, and saturated liquid exits the condenser, which operates at 8 bar. Determine for isentropic compression a. the refrigerant mass flow rate, in kg/s. b. the compressor power, in kW. c. the coefficient of performance. Recalculate the quantities in parts (b) and (c) for an isentropic compressor efficiency of 75%.
Thermodynamic calculations for mass flow rate, compressor power, and coefficient of performance of a heat pump require refrigerant property data, which is not provided in the question. An energy balance and compressor efficiency adjustment are also essential for accurate calculations.
Explanation:To calculate the properties of the heat pump using refrigerant 134a and determine the refrigerant mass flow rate, compressor power, and coefficient of performance, we need to make use of thermodynamic equations and refrigerant property data under the given conditions (such as pressures and phase states).Normally, these calculations would involve using a thermodynamic properties table or software to find enthalpies for the refrigerant at the specified conditions. An energy balance would be applied around the compressor and condenser. The work done by the compressor can be calculated using the enthalpy values before and after the compressor and assuming an isentropic process initially, and then adjusting for the non-ideal compressor efficiency of 75% in the revised calculation.For the coefficient of performance (COP) of the heat pump, it is calculated as the ratio of heat output to work input for the heating mode. The provided heat output is given here as 35 kW. For ideal conditions, the COP can be calculated without the compressor efficiency factor; for the revised COP with a 75% efficient compressor, this factor is taken into account.Unfortunately, without the enthalpy values or additional data, it is not possible to provide the numerical answers to the student's question.
Water in a household plumbing system originates at the neighborhood water main where the pressure is 480 kPa, the velocity is 5 m/s, and the elevation is 2.44 m. A 19-mm (3/4-in) copper service line supplies water to a two-story residence where the faucet in the master bedroom is 40 m (of pipe) away from the main and at an elevation of 7.62 m. If the sum of the minor-loss coefficients is 3.5, estimate the maximum (open faucet) flow. How would this flow be affected by the operation of other faucets in the house?
Answer:
1. Maximum flow = 0.7768 L/s
2. The flow would reduced if other faucets were open. This is due to increase pipe flow and frictional resistance between the water main and the faucets.
Explanation:
See the attached file for the calculation.
simply supported beam is subjected to a linearly varying distributed load ( ) 0 q x x L 5 q with maximum intensity 0 q at B. The beam has a length L 5 4 m and rectangular cross section with a width of 200 mm and height of 300 mm. Determine the maximum permissible value for the maximum inten- sity, 0 q , if the allowable normal stresses in tension and compression are 120 MPa.
Answer:
q₀ = 350,740.2885 N/m
Explanation:
Given
[tex]q(x)=\frac{x}{L} q_{0}[/tex]
σ = 120 MPa = 120*10⁶ Pa
[tex]L=4 m\\w=200 mm=0.2m\\h=300 mm=0.3m\\q_{0}=? \\[/tex]
We can see the pic shown in order to understand the question.
We apply
∑MB = 0 (Counterclockwise is the positive rotation direction)
⇒ - Av*L + (q₀*L/2)*(L/3) = 0
⇒ Av = q₀*L/6 (↑)
Then, we apply
[tex]v(x)=\int\limits^L_0 {q(x)} \, dx\\v(x)=-\frac{q_{0}}{2L} x^{2}+\frac{q_{0} L}{6} \\M(x)=\int\limits^L_0 {v(x)} \, dx=-\frac{q_{0}}{6L} x^{3}+\frac{q_{0} L}{6}x[/tex]
Then, we can get the maximum bending moment as follows
[tex]M'(x)=0\\ (-\frac{q_{0}}{6L} x^{3}+\frac{q_{0} L}{6}x)'=0\\ -\frac{q_{0}}{2L} x^{2}+\frac{q_{0} L}{6}=0\\x^{2} =\frac{L^{2}}{3}\\ x=\sqrt{\frac{L^{2}}{3}} =\frac{L}{\sqrt{3} }=\frac{4}{\sqrt{3} }m[/tex]
then we get
[tex]M(\frac{4}{\sqrt{3} })=-\frac{q_{0}}{6*4} (\frac{4}{\sqrt{3} })^{3}+\frac{q_{0} *4}{6}(\frac{4}{\sqrt{3} })\\ M(\frac{4}{\sqrt{3} })=-\frac{8}{9\sqrt{3} } q_{0} +\frac{8}{3\sqrt{3} } q_{0}=\frac{16}{9\sqrt{3} } q_{0}m^{2}[/tex]
We get the inertia as follows
[tex]I=\frac{w*h^{3} }{12} \\ I=\frac{0.2m*(0.3m)^{3} }{12}=4.5*10^{-4}m^{4}[/tex]
We use the formula
σ = M*y/I
⇒ M = σ*I/y
where
[tex]y=\frac{h}{2} =\frac{0.3m}{2}=0.15m[/tex]
If M = Mmax, we have
[tex](\frac{16}{9\sqrt{3} }m^{2} ) q_{0}\leq \frac{120*10^{6}Pa*4.5*10^{-4}m^{4} }{0.15m}\\ q_{0}\leq 350,740.2885\frac{N}{m}[/tex]
consider a household that uses 23.8 kw-hour of electricity per day on average. (kw-hours is a measure of energy that will be discussed in detail in a later chapter. at this point we want to establish estimations.) most of that electricity is supplied by fossil fuels. to reduce their carbon footprint, the household wants to install solar panels, which receive on average 336 w/m2 from the sun each day. if the solar panels are 19.0% efficient (fraction of solar energy converted into useable electrical energy), what area of solar panels is needed to power the household
Answer:
15.53 m2
Explanation:
Energy needed = 23.8 kW-hr
Solar intensity of required panel = 336 W/m2
Efficiency of panels = 19%
Power needed = 23.8kW-hr = 23800 W-h,
In one day there are 24 hr, therefore power required = 23800/24 = 991.67 W
991.67 = 19% of incident power
991.67 = 0.19x
x = incident power = 991.67/0.19 = 5219.32 W
Surface area required = 5219.32/336
= 15.53 m2
Question 1: Consider a vapour compression refrigeration cycle that uses R-134a as refrigerant. The R-134a enters the compressor as a saturated vapour at 200 kPa, and exits the condenser as a saturated liquid at 900 kPa. The rate of refrigeration of the cycle is to be 6.0 tons of refrigeration (1 ton of refrigeration = 3.517 kW). The compressor isentropic efficiency is 80%. Determine: a) The temperature of evaporation and condensation of the refrigerant; b) Mass flow of the refrigerant R-134a, in kg/min; c) Coefficient of Performance (COP) of the refrigeration cycle. Typical vapour compression refrigeration systems use a throttling valve (or an orifice tube, or a capillary tube) to reduce the liquid refrigerant’s pressure. This is a highly irreversible process. If the cycle efficiency is to be improved by replacing the throttle with a rotary expander with 70% isentropic efficiency, d) What is the new COP? The expander delivers its work developed to the compressor.
Answer:
a) The temperature of evaporation is -10.09°C
The temperature of condensation is 35.53°C
b) The mass flow of the refrigerant is 0.149 kg/s
c) The COP is 3.65
d) The new COP is 4.05
Explanation:
please look at the solution in the attached Word file
Compute the acceleration of gravity for a given distance from the earth's center, distCenter, assigning the result to accelGravity. The expression for the acceleration of gravity is: (G * M) / (d2), where G is the gravitational constant 6.673 x 10-11, M is the mass of the earth 5.98 x 1024 (in kg) and d is the distance in meters from the earth's center (stored in variable distCenter).Sample program:#include int main(void) { const double G = 6.673e-11; const double M = 5.98e24; double accelGravity = 0.0; double distCenter = 0.0; distCenter = 6.38e6; printf("accelGravity: %lf\n", accelGravity); return 0;
Answer:
See Explaination
Explanation:
#include <stdio.h>
int main(void)
{
const double G = 6.673e-11;
const double M = 5.98e24;
double accelGravity = 0.0;
double distCenter = 0.0;
distCenter = 6.38e6;
//<StudentCode>
accelGravity = (G * M) / (distCenter * distCenter);
printf("accelGravity: %lf\n", accelGravity);
return 0;
}