A solution has [oh−] = 2.3×10−2 m . use the ion product constant of water kw=[h3o+][oh−] to find the [h3o+] of the solution.

Answers

Answer 1

Answer:

The concentration of hydronium ions in the solution is [tex]4.35\times 10^{-13} M[/tex].

Explanation:

Concentration of hydroxide ions = [tex][OH^-]=2.3\times 10^{-2}[/tex]

Concentration of hydroxide ions = [tex][H_3O^+]=?[/tex]

[tex]H_2O+H_2O\rightleftharpoons H_3O^++OH^-[/tex]

The ionic product of water is given as:

[tex]K_w=[H_3O^+][OH^-][/tex]

The value of ionic product of water, [tex]K_w=1\times 10^{-14}[/tex]

[tex]K_w=1\times 10^{-14}=[H_3O^+][OH^-][/tex]

[tex]1\times 10^{-14}=[H_3O^+]\times 2.3\times 10^{-2}M[/tex]

[tex][H_3O^+]=\frac{1\times 10^{-14}}{2.3\times 10^{-2}}=4.35\times 10^{-13} M[/tex]

The concentration of hydronium ions in the solution is [tex]4.35\times 10^{-13} M[/tex].

Answer 2

The concentration of hydronium, ion [H₃O⁺] in the solution containing 2.3×10⁻² M concentration of hydroxide ion, [OH⁻] is 4.35×10⁻¹³ M

How to determine the concentration of hydronium, ion [H₃O⁺]?

The following data were obtained from the question given above:

Concentration of hydroxide ion, [OH⁻] = 2.3×10⁻² MConcentration of hydronium, ion [H₃O⁺] = ?

[H₃O⁺] × [OH⁻] = 10¯¹⁴

[H₃O⁺] × 2.3×10⁻² = 10¯¹⁴

Divide both side by 2.3×10⁻²

[H₃O⁺] = 10¯¹⁴ / 2.3×10⁻²

= 4.35×10⁻¹³ M

Thus, we can conclude that the concentration of hydronium ion, [H₃O⁺] in the solution is 4.35×10⁻¹³ M

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Related Questions

Anthracene is a yellow, crystalline solid found in coal tar. complete this structure for anthracene, c14h10, by adding bonds and hydrogen atoms as necessary.what type of hybrid orbitals are utilized by carbon in anthracene?how many σ bonds and π bonds are there in an anthracene molecule? how many valence electrons occupy σ-bond orbitals and how many occupy π -bond orbitals?

Answers

Anthracene is a polycyclic aromatic hydrocarbon with chemical formula C₁₄H₁₀. The number of fused rings in Anthracene are three in number. This compound is colorful and is used in the formation of different dyes due to its property of deloclization of pi electrons. All the carbon atoms in Anthracene are sp² hybridized with a trigonal planar structure hence, the Anthracene is planar in nature.

Number of Sigma Bonds:

                                         There are 26 sigma bonds (colored in Blue) in Anthracene among which 10 sigma bonds are between carbon and hydrogen atoms while the remaining are between the carbon atoms.

Number of Pi-Bonds:

                                  There are 7 pi bonds in Anthracene (colored in red). All pi bonds are present between carbon and carbon atoms.

Number of Electrons in Sigma Bonds:

                                                             As one sigma bond is formed by 2 electrons hence, 26 sigma bonds will be formed by 52 electrons.

Number of Electrons in Pi Bonds:

                                                       As one pi bond is formed by the side wise overlap of two p orbitals hence one pi bond is formed by two electrons so, 7 pi bonds will be formed by 14 electrons.

The hybrid orbital that is utilized by the carbon in anthracene is [tex]\boxed{{\text{s}}{{\text{p}}^2}}[/tex] .

The anthracene molecule contains [tex]\boxed{{\mathbf{26}}{\text{ }}{\mathbf{sigma}}}[/tex] bonds and [tex]\boxed{{\mathbf{7}}{\text{ }}{\mathbf{\pi }}}[/tex]  bonds.

The number of valence electrons in sigma orbital is [tex]\boxed{{\mathbf{52}}}[/tex]  and pi-orbitals is [tex]\boxed{{\mathbf{14}}}[/tex] .

Further explanation:

The anthracene is a crystalline compound and it is yellow in color. It contains three fused rings of benzene thus it is a polyaromatic compound.it has a molecular formula [tex]{{\text{C}}_{{\text{14}}}}{{\text{H}}_{{\text{10}}}}[/tex].

Prediction of hybridization:

The hybridization can be determined by calculating the number of hybrid orbitals (X) which is to be formed by the atom. The formula to calculate the number of hybrid orbitals (X) as follows:

[tex]\boxed{{\text{X}}={\text{Number of bond pair}}+{\text{Number of lone pair}}}[/tex]

Here X is a steric number.

When X is 2 then hybridization is sp.

When X is 3 then hybridization is [tex]{\text{s}}{{\text{p}}^2}[/tex].

When X is 4 then hybridization is [tex]{\text{s}}{{\text{p}}^3}[/tex] .

The structure of anthracene is attached in the image.

Since all carbon atom in anthracene contains three bond pairs and no lone pair thus, the hybridization can be calculated as follows:

[tex]\begin{aligned}{\text{X}}&={\text{Number of bond pair}}+{\text{Number of lone pair}}\\&=3+0\\&=3\\\end{aligned}[/tex]

The value of X is 3, therefore, the hybridization of each carbon in anthracene is [tex]{\text{s}}{{\text{p}}^2}[/tex]  

The structure of anthracene contains 26 sigma bond and 7 pi bonds. (refer to the image attached).

The number of valance electron in sigma orbital is twice of the number of sigma bond present in the molecule because every sigma bond contains 2 electrons.

[tex]{\text{Valence electron in sigma orbital}} = 2\left({{\text{sigma bond}}}\right)[/tex]

In anthracene, number of sigma bond is 26, therefore,

[tex]\begin{aligned}{\text{Valence electron in sigma orbital}}&=2\left({{\text{sigma bond}}}\right)\\&=2\left({{\text{26}}}\right)\\&=52\\\end{aligned}[/tex]

The number of valance electron present in pi-orbital is twice of the number of pi bond present in the molecule because every pi-bond contains 2 electrons.

[tex]\begin{aligned}\text{Valence electron in }\pi\text{-orbital}&=2(\pi\text{-bond})\end{aligned}[/tex]

In anthracene, number of pi bond is 7, therefore,

[tex]\begin{aligned}\text{Valence electron in }\pi\text{-orbital}&=2(\pi\text{-bond})\\&=2(7)\\&=14\end{aligned}[/tex]

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Answer details:

Grade: Senior school

Subject: Chemistry

Chapter: Covalent bonding

Keywords: Anthracene, yellow crystalline, coal tar, structure of anthracene, C14H10, hybrid orbitals.

In which set are the substances arranged in order of decreasing solubility in water? (a) (c) al(oh)3 > mg(oh)2 > naoh cac03 > nahc03 > na2c03 (b) (d) bas04 > cas04 > mgs04 agcl > agbr > agl?

Answers

(A) Al(OH)₃ > Mg(OH)₂ > NaOH
polarity is increasing as the metallic character is increasing . So this order is not correct. NaOH as we all know is completely soluble in water.

(B) BaSO₄> CaSO₄ > MgSO₄
This one is also not correct because here also polarity is increasing so solubility should increase.

(C) CaCO₃> NaHCO₃ > Na₂CO₃
this is als not correct .Na₂CO₃ is more polar is completely soluble in water whereas CaCO₃ is insoluble.

(D) AgCl > AgBr > AgI
In D as we go from AgCl to AgI polarity is decreasing so solubility is decreasing .

What is the change in atomic mass when an atom emits an alpha particle? A. decreases by 2 B. decreases by 1 C. decreases by 4 D. remains the same

Answers

Answer is "C"

alpha decay is an emission of ₂⁴He nucleus. If an element undergoes an alpha decay, the mass of the daughter nucleus formed is reduced by 4 compared to mass of parent atom and atomic number is reduced by 2 compared to atomic number of parent atom.

a section of the periodic table is shown below which of the following statements is true?

Answers

Oxygen is more reactive than fluorine because oxygen needs only one electron to fill its outermost shell.
Neon is inert because its outermost shell is complete. Neon is already in noble gas configuration and it will be very difficult to change this, essentially making it inert.

Nitrogen is inert because its outermost shell has eight electrons. Nitrogen's outermost shell only has 3 electrons so it is generally unstable and wants to gain 3 more to be in noble gas configuration.

Oxygen is more reactive than fluorine because oxygen needs only one electron to fill its outermost shell. This is just completely false, Fluorine is the most reaction element there is.

Fluorine is more reactive than neon because fluorine has to lose only one electron to fill its outermost shell. Although fluorine is more reactive, this is because it only needs to GAIN one more electron, not lose one more.

Identify the three ingredients used in a blast furnace to make pig iron.

Answers

Final answer:

The three ingredients used in a blast furnace to make pig iron are roasted ore, coke, and limestone.

Explanation:

In a blast furnace, the three ingredients used to make pig iron are:

Roasted Ore: The iron ore is heated in air to remove water and convert sulfides into oxides.Coke: This is a fuel made by heating coal in the absence of air. It provides the high temperature required for the reduction reactions.Limestone: Impure calcium carbonate (CaCO3) is added to remove impurities and form s_lag.

The combination of these three ingredients undergoes various reactions in different temperature zones of the blast furnace, resulting in the production of molten iron and s_lag.

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You adjust the temperature so that a sound wave travels more quickly through the air. You increase the temperature from 30°C to 36°C. What's the velocity of the sound wave at this new temperature? A. 335.6 m/s B. 352.6 m/s C. 344.0 m/s D. 350.0 m/s

Answers

The equation relating the velocity of sound in air to the air temperature is: v = 331 + 0.6T, where T is the temperature in degrees Celsius. For this case, when T = 36 C:
v = 331 + 0.6(36) = 331 + 21.6 = 352.6 m/s, which is choice B

Twice bill's number added to 17 is 7. What is his number

Answers

-5.

-5 * 2 = -10
-10 + 17 = 7
Let b=bills number
2b+17=7
Subtract 17 from both sides
2b=-10
Divide both sides by 2
b=-5
Bill’s number is -5

I hope this helps )

Does the structure below exhibit geometric isomerism? ch3 tally1 ch3― c ―ch═ch―ch3 tally1 ch3

Answers

Answer:
            YES! The given compound exhibit Geometrical Isomerism.

Explanation:
                   In Geometrical Isomerism or Cis-Trans Isomerism, isomers possess same molecular formula, same structural formula with a double bond and with a only difference in the arrangement of atoms or group of atoms about the double bond in three dimensional space.
                   4,4-dimethylpent-2-ene (given problem) has two groups about the double bond i.e. Methyl (CH₃-) and tertiary Butyl [(CH₃)₃-C-]. In cis configuration both groups are at same side of the double bond, while in trans configuration both groups are located opposite to each other as shown below,

It is found that doubling the concentration of a quadruples the reaction rate and tripling the concentration of b triples the reaction rate. what is the overall order of the reaction?

Answers

Reactant A must be second order and reactant B first order. Overall = add them so 3rd order.

The reaction is second order with respect to reactant A and first order with respect to reactant B, giving an overall reaction order of 3.

To determine the overall order of a reaction, we need to find the individual orders with respect to each reactant.

1. Doubling the concentration of reactant A increases the reaction rate by a factor of four. This indicates that the reaction is second order with respect to A, because 2² = 4.

2. Tripling the concentration of reactant B increases the reaction rate by a factor of three. This means the reaction is first order with respect to B, because 3¹ = 3.

Therefore, the overall order of the reaction is the sum of the orders with respect to each reactant:

Order with respect to A: 2Order with respect to B: 1

The overall order = 2 + 1 = 3.

The ______________of matter depends upon how close the individual particles are together. A) identity B) mass C) state D) temperature

Answers

Actually it’s c because if the particles are extremely loose they’re most likely a gas if they lose but close they’re a liquid and if they’re organized.

Answer:

State

Explanation:

The state of matter depends on the closeness of the particles. Gases have particles that are very far apart and solids are close together. This is determined by the strength of attraction of these particles to one another.

Which equilibrium reaction will experience a shift towards the products in equilibrium position when the concentration of ni2+ is increased? view available hint(s) which equilibrium reaction will experience a shift towards the products in equilibrium position when the concentration of is increased? ni2+(aq)+6nh3(aq)⇌[ni(nh3)6]2+ [ni(h2o)6]2+(aq)+3en(aq)⇌[ni(en)3]2+(aq)+6nh3(aq) ni(oh)2(s)⇌ni2+(aq)+2oh−(aq) nis(s)⇌ni2+(aq)+s2−(aq)?

Answers

Answer is 
      Ni²(aq) + 6NH(aq) [Ni(NH)

When the concentration of Ni²⁺(aq) increases, according to the Le Chatelier’s principle system tries to become equilibrium by reducing the increased factor. To do that, the concentration of Ni²⁺(aq) should be reduced. Hence, the forward reacted should be promoted to reduce the Ni²⁺(aq) concentration.

The molecular mass of methyl ethanoate is 75.1 amu . calculate the molecular mass of propanoic acid, an isomer of methyl ethanoate. express your answer with the appropriate units.

Answers

Final answer:

The molecular mass of propanoic acid, an isomer of methyl ethanoate, is 74.09 amu, calculated by the sum of atomic masses of carbon, hydrogen, and oxygen in its molecular formula, C3H6O2.

Explanation:

To calculate the molecular mass of propanoic acid, an isomer of methyl ethanoate, we need to first understand that isomers are compounds with the same molecular formula but different structures, and hence, the same molecular mass. Propanoic acid's molecular formula is C3H6O2. Using the atomic masses of carbon (12.01 amu), hydrogen (1.01 amu), and oxygen (16.00 amu), we calculate the molecular mass as follows:

(3 × 12.01 amu) + (6 × 1.01 amu) + (2 × 16.00 amu) = 36.03 amu + 6.06 amu + 32.00 amu = 74.09 amu

Therefore, the molecular mass of propanoic acid is 74.09 amu.

A 5.018 gram sample of a certain hydrate of magnesium sulfate, mgso4•xh2o, is heated until all the water is driven off. the resulting anhydrous compound weighs 2.449 grams. what is the formula of the hydrate?

Answers

Hydrate of magnesium sulphate undergoes dehydration upon action of heat. This process can be chemically represent as follows:

MgSO4.XH2O  → MgSO4 + XH20
       (5.018 g)      (2.449 g)     (2.569 g)

Number of moles of H2O evolved = [tex] \frac{2.569}{Molecular.weight} [/tex]
                                                      = [tex] \frac{2.569}{18} [/tex]
                                                      = 0.1427
Number of moles of MgSO4 generated after decomposition,
= [tex] \frac{2.449}{Molecular.weight} [/tex]
=[tex] \frac{2.449}{120.37} [/tex]
=0.0203

Now dividing  both these numbers by the smallest one to get the mole ratio that exists between MgSO4 and H20

For H2O, [tex] \frac{0.1427}{0.0203} [/tex] = 7.02 ~7

Thus, formula of hydrate is MgSO4.7H2O

What is the consequence of deforestation?

Answers

loss of biodiversity

Answer:

The consequence of deforestation is discussed below.

Explanation:

One of the outcomes of deforestation is a waste of biodiversity. Deforestation also improves greenhouse gas discharges, disturbs the water series, improves soil erosion and reduces the physical attraction of a region.deforestation causes the Decline of nutrients in the clay that are obtained from the categorization of tree petals.

At 350°c, keq = 1.67 × 10-2 for the reversible reaction 2hi (g) ⇌ h2 (g) + i2 (g). what is the concentration of hi at equilibrium if [ h2 ] is 2.44 × 10-3 m and [ i2 ] is 7.18 × 10-5 m?

Answers

according to the reversible reaction equation:

2Hi(g) ↔ H2(g) + i2(g)

and when Keq is the concentration of the products / the concentration of the reactants.

Keq = [H2][i2]/[Hi]^2

when we have Keq = 1.67 x 10^-2

[H2] = 2.44 x 10^-3

[i2] = 7.18 x 10^-5

so, by substitution:

1.67 x 10^-2 = (2.44 x 10^-3)*(7.18x10^-5)/[Hi]^2

∴[Hi] = 0.0033 M

The equilibrium constant expression for the reaction 2HI (g) ⇌ H₂ (g) + I₂ (g) and given concentrations of H₂ and I₂ , we calculated the concentration of HI at equilibrium to be approximately 3.24 × 10⁻³ M. We used the equilibrium constant Keq = 1.67 × 10⁻² to solve for [HI].

To find the concentration of HI at equilibrium for the reaction 2HI (g) ⇌ H₂. (g) + I₂ (g) given Keq, [H₂] and [I₂], we can use the equilibrium constant expression:

Keq = [H2][I₂] / [HI]₂

Given data:

Keq = 1.67 × 10⁻²[H₂] = 2.44 × 10⁻³M[I₂] = 7.18 × 10⁻⁵ M

Plug these values into the equilibrium expression and solve for [HI]:

Keq = [H₂][I₂] / [HI]₂1.67 × 10⁻² = (2.44 × 10⁻³)(7.18 × 10⁻⁵) / [HI]₂

First, calculate the numerator:

(2.44 × 10⁻³)(7.18 × 10⁻⁵) = 1.75192 × 10⁻⁷

Now plug this back into the equation:

1.67 × 10⁻² = 1.75192 × 10⁻⁷ / [HI]₂

Solving for [HI]₂ :

[HI]₂ = 1.75192 × 10⁻⁷ / 1.67 × 10⁻² ≈ 1.0496 × 10⁻⁵

Taking the square root to find [HI]:

[HI] = √(1.0496 × 10⁻⁵) ≈ 3.24 × 10⁻³ M


Correct question is: At 350°C , keq = 1.67 × 10⁻² for the reversible reaction 2HI (g) ⇌ H₂ (g) + I₂ (g). what is the concentration of hi at equilibrium if [ H₂ ] is 2.44 × 10⁻³ m and [ I₂ ] is 7.18 × 10⁻⁵ m?

The half life of carbon is 5700 years. if you started with 100g of carbon 14 how much would remain after 4 half lives

Answers

When dealing with a half life question, you should use the half life formula which is: y = a(b)^t/h

QUICK TIMES RUNNING OUT!


What method could you use to seperate oil from water? Remember that the both must still remain, they just have to be seperated.

Answers

1. You could drain off the oil as a supernatant, since oil is less dense than water.
2. You could attempt to evaporate the water since they have different boiling points (212 vs 572 F), and then condense it in a separate container using a distillation unit.

In a future hydrogen-fuel economy, the cheapest source of h2 will certainly be water. it takes 467 kj to produce 1 mol of h atoms from water. what is the frequency, wavelength, and minimum energy of a photon that can free an h atom from water? enter your answers in scientific notation.

Answers

1 mol ≡ 6.023 x 10^23 molecules  are produced using 467000 j of energy,
then production of 1 molecule will required energy = [tex] \frac{467000}{6.023X10^2^3} [/tex] = 7.7536 x 10^(-19) j

Thus, mininum energy of a photon that can free a H-atom from water is 7.7536 x 10^(-19) j.

Now, we know that E = hv
where, h = planck's constant = 6.63  10^(34) J.s
v = frequency of photon 
∴ v = [tex] \frac{E}{h} [/tex] = [tex] \frac{7.7536 X 10^(^-^1^9^)}{6.63X10^(^-^3^4^)} [/tex] = 1.1702 X 10^(15) Hz

We also know that, wavelength (∧) = [tex] \frac{c}{v} [/tex]
                                                        = [tex] \frac{3X10^8}{1.1702X10^(^1^5^)} [/tex]
                                                        = 2.56 X 10^(-7) m

The minimum energy of a photon that can produce one hydrogen atom from water is [tex]\boxed{7.755 \times {{10}^{ - 19}}{\text{ J}}}[/tex]

The frequency of the photon is [tex]\boxed{1.17 \times {{10}^{15}}{\text{ }}{{\text{s}}^{ - 1}}}[/tex].

The wavelength of the photon is [tex]\boxed{2.563 \times {{10}^{ - 7}}{\text{ m}}}[/tex].

Further Explanation:

Frequency[tex]\left( \nu  \right)[/tex] is defined as number of times n event occurs in unit time. It is generally applied to waves including light, sound, and radio waves. It is denoted by [tex]{\nu }}[/tex] and its SI unit is Hertz (Hz).

Wavelength is the characteristic property of a wave. It is defined as the distance between two successive crests or troughs. A crest is that point where there is maximum displacement of the medium whereas trough is a point that has minimum displacement of the medium. It is represented by [tex]\lambda[/tex] and its SI unit is meter (m).

First, the energy required to produce one hydrogen atom in joule can be calculated as follows:

[tex]E\left({\text{J}}\right)=\frac{{E\left( {{\text{kJ}}}\right)\times\left({\frac{{{{10}^3}{\text{ J}}}}{{{\text{kJ}}}}}\right)}}{{{{\text{N}}_{\text{A}}}}}[/tex]           …… (1)

Here, [tex]{{\text{N}}_{\text{A}}}[/tex] is an Avogadro's number and has a value [tex]6.022 \times {10^{23}}{\text{ mo}}{{\text{l}}^{ - 1}}[/tex].

Substitute [tex]467{\text{ kJ/mol}}[/tex] for [tex]E\left( {{\text{kJ}}} \right)[/tex] and [tex]6.022 \times {10^{23}}{\text{ mo}}{{\text{l}}^{ - 1}}[/tex] for [tex]{{\text{N}}_{\text{A}}}[/tex] in equation (1).

[tex]\begin{aligned}E\left( {\text{J}} \right)&=\frac{{\left({467{\text{ kJ/mol}}} \right) \times \left( {\frac{{{{10}^3}{\text{ J}}}}{{{\text{kJ}}}}}\right)}}{{6.022\times {{10}^{23}}{\text{ mo}}{{\text{l}}^{-1}}}}\\&=7.755\times{10^{-19}}{\text{ J}}\\\end{aligned}[/tex]

Thus the energy of a photon that can free one atom of hydrogen is [tex]7.755 \times {10^{ - 19}}{\text{ J}}[/tex].

The expression of frequency and energy is as follows:

[tex]E=hv[/tex]              …… (2)

Here, [tex]v[/tex] is a frequency of photon and h is a Plank’s constant and has a value [tex]\left({6.626\times{{10}^{-34}}{\text{ Js}}}\right)[/tex].

Rearrange equation (2) to calculate the frequency of the photon as follows:

[tex]v=\frac{E}{h}[/tex]               …… (3)

Substitute [tex]6.626\times{10^{-34}}{\text{ J}}\cdot{\text{s}}[/tex] for h and [tex]7.755 \times {10^{-19}}{\text{ J}}[/tex] for E in equation (3).

[tex]\begin{aligned}v&=\frac{{7.755\times{{10}^{-19}}{\text{ J}}}}{{6.626\times{{10}^{-34}}{\text{ Js}}}}\\&=1.17\times{10^{15}}{\text{}}{{\text{s}}^{-1}}\\\end{aligned}[/tex]

Thus the frequency of photon is [tex]1.17\times{10^{15}}{\text{}}{{\text{s}}^{-1}}[/tex].

The expression to calculate the wavelength from energy of the photon is as follows:

[tex]E = \frac{{h{\text{c}}}}{{\lambda }}}[/tex]                  …… (4)

Here [tex]{\lambda }}[/tex] is a wavelength of a photon and c is a speed of light.

Rearrange equation (4) to calculate wavelength of the photon as follows:

[tex]{\lambda }}=\frac{{h{\text{c}}}}{E}[/tex]                                 …… (5)

Substitute [tex]6.626 \times {10^{ - 34}}{\text{ J}} \cdot {\text{s}}[/tex] for h, [tex]3.0 \times {10^8}{\text{ m/s}}[/tex] for c and [tex]7.755 \times {10^{ - 19}}{\text{ J}}[/tex] for E in equation (5).

[tex]\begin{aligned}{\lambda}}=\frac{{\left({6.626\times {{10}^{-34}}{\text{ J}}\cdot {\text{s}}} \right)\left( {3.0 \times {{10}^8}{\text{ m/s}}}\right)}}{{\left({7.755\times {{10}^{ - 19}}{\text{ J}}} \right)}}\\=2.563\times {10^{-7}}{\text{m}}\\\end{aligned}[/tex]

Hence wavelength of the photon is equal to [tex]2.563 \times {10^{ - 7}}{\text{ m}}[/tex].

Learn more:

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Structure of atom

Keywords: Hydrogen atom, cheapest source of h2, 467 kj, 1 mol of h atom, frequency wavelength.

) what is the mass percent of a solution prepared by dissolving 18.9 grams of an unknown solid into 39.5 grams of water?

Answers

The  mass %  of  a solution  prepared  by   dissolving 18.9  grams  of  an unknown  solid into  39.5 grams of water is  calculated as  below


%(M/M) =  mass of the solute(unknown  salt)/ mass of the solvent(water)  x 100

 = 18.9 g/ 39.5 g x100  =47.85% (M/M)

Answer:

32.4%

Explanation:

Step 1: Given data

Mass of the solute = 18.9 g

Mass of the solvent = 39.5 g

Mass of the solution = Mass of the solute + Mass of the solvent = 58.4 g

Step 2: Calculate the mass percent of the solute in the solution

We use the following expression.

[tex]\% m/m =\frac{mass\ of\ the\ solute}{mass\ of\ the\ solution} \times 100\%=\frac{18.9g}{58.4g} \times 100\% =32.4\%[/tex]

The equilibrium concentrations were found to be [br2] = 2.2 × 10−3 m, [cl2] = 3.0 × 10−2 m, and [brcl] = 1.5 × 10−2 m. write the equilibrium expression, and calculate the equilibrium constant for this reaction at this temperature.

Answers

[tex]Br_{2} + Cl_{2}---\ \textgreater \ 2BrCl K_{eq} = \frac{[BrCl]^{2}}{[Br_{2}][Cl_{2}]]} = \frac{[1.5*10^{-2}]^{2}}{[2.2*10^{-3}][3.0*10^{-2}]} =0.34*10=3.4 K_{eq}=3.4[/tex]

Which state of matter is most likely represented in the diagram shown below?

A square is shown with the title State of Matter. An array of circles arranged neatly in rows and columns is shown. Tiny single arcs are shown near some circles near the outer edge of the array

Gas
Solid
Liquid
Plasma

Answers

I am actually taking this test right now and I think it is Solid please let me know if I am correct

its defiantly a solid, because the particles are packed in close together and it has a definite shape and volume. water is lose and not packed in like this. and with gas, the particles would juts fly everywhere and plasma is electricity and a wild card. so its definitely a solid, trust me

HELPPPP PLEASE ASAP!!!

Answers

Answer:

230
     Th
  90

Explanation:

The left side shows the element uranium with mass number 234 (superscript to the left of ths symbol) and atomic mass 92 (subscript to the left of the symbol).

So,  you have to find the mass number and atomic numbers missing on the right side which added to those shown for the helium atom reach 234 and 92.

This the the mathematics:

1) Mass number of U - mass number of He = 234 - 4 = 230 ⇒ the mass number of the missing element is 230.

2) atomic number of U - atomic number of He = 92 - 2 = 90 ⇒ the atomic number of the missing element is 90.

Now, you use the atomic mass to identify the element. You do it by simply searching in a periodic table. There you find that the atomic number 90 corresponds to thorium, whose symbol is Th.

Now you have that the product that completes the right side of the decay equation is:

230
     Th
  90


For a solution with an [oh−] of 10−8 m, what would be the value of [h+] , ph and poh, respectively? 1. 106 m, 6, 8 2. 10−6 m, 6, 8 3. 10−6 m, 8, 6 4. 10−14 m, 6, 8 5. 10−6 m, 6, 14 6. 10−14 m, 8, 6

Answers

Q1)pOH
the hydroxide ion concentration can be used to calculate the pOH of the solution 
pOH can be calculated using the following equation 
pOH = -log[OH⁻]
pOH = -log (10⁻⁸ M)
pOH = 8
therefore pOH of solution is 8

Q2) pH 
by knowing the pOH value we can calculate the pH value
since
pH + pOH = 14
and pOH = 8
therefore pH = 14 - 8
pH = 6

Q3)
pH scale is used to determine how acidic or basic a solution is
knowing the pH value we can calculate hydrogen ion concentration 
pH = -log[H⁺]
[H⁺] = antilog(-pH)
[H⁺] = antilog(-6)
[H⁺] = 10⁻⁶ M

answer is 2. 10⁻⁶ M, 6, 8

Our good friend and pseudo scientist, homer simpson, attempts to analyze 300 mg of an unknown compound containing only c and h by burning it in excess oxygen. 540 mg of h2o is produced. you may assume that all the hydrogen in the compound ended up as water.

Answers

[tex] C_{x}H_{y} + O_{2} --\ \textgreater \ x CO_{2} + \frac{y}{2} H{2}O 540mg H_{2}O* \frac{1 mmol H_{2}O}{18 mg H_{2}O} =30 mmol H_{2}O \\ \\30 mmolH_{2}O -have - 60 mmol H \\ \\ 60 mmol H* \frac{1mg H}{1 mmol H} =60 mg H \\ \\300mg C_{x}H_{y} - 60 mg H= 240 mg C \\ \\ 240 mgC* \frac{1mmol}{12mg} =20 mmol C 20 mmol C: 60 mmol H=1 mol C : 3 mol H [/tex]

Some chemical reactions can proceed in just one direction . True or False ?

Answers

the answer is False. i think
it is true because Chemical reactions release the same amount of engery whether an enzyme is involved or not. 

Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 7.80 moles of magnesium perchlorate, Mg(ClO4)2.

Answers

 The number of moles of moles of  Magnesium,chlorine and oxygen atoms in 7.80 moles of Mg(ClO4)2 is calculated as below

find the total number of each atom in Mg(ClO4)2

that is mg = 1 atom
        Cl =  1x2 = 2 atoms
        O  = 4  x2 = 8 atoms

then multiply 7.80 moles with total number of each atom , to get the number moles of each atom
that is

Mg = 7.80 x1= 7.80  moles
cl =   7.80  x2=15.6  moles
O =  7.80 x8= 62.4 moles

In 7.80 moles of magnesium perchlorate (Mg(ClO4)2), there are approximately 7.80 moles of magnesium atoms, 15.60 moles of chlorine atoms, and 31.20 moles of oxygen atoms.

Magnesium perchlorate (Mg(ClO4)2) consists of one magnesium (Mg) atom, two chlorine (Cl) atoms, and eight oxygen (O) atoms per formula unit. To calculate the number of moles of each element in 7.80 moles of magnesium perchlorate, you can use the mole ratios from the chemical formula.

First, you have 7.80 moles of the entire compound. Since there is one magnesium atom in each formula unit, there are also 7.80 moles of magnesium atoms. Similarly, as there are two chlorine atoms in each formula unit, you have 2 * 7.80 = 15.60 moles of chlorine atoms. Lastly, since there are eight oxygen atoms in each formula unit, there are 8 * 7.80 = 62.40 moles of oxygen atoms. So, in 7.80 moles of magnesium perchlorate, you have approximately 7.80 moles of magnesium atoms, 15.60 moles of chlorine atoms, and 31.20 moles of oxygen atoms.

Learn more about atoms here: https://brainly.com/question/19030729

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The process by which complex compounds are decomposed by living systems is called
fermentation
distillation
oxidation
reduction

Answers

A. Fermentation

Hope this helps!
the answer is fermentation

What is the noble gas configuration for silicon? [Ne] 3s2 3p1 [Ar] 4s1 [Kr] 5s1 [Ne] 3s2 3p2

Answers

Answer: The noble gas notation for silicon atom is [tex][Ne]3s^23p^2[/tex]

Explanation:

Noble gas notation is defined as the notation in which the configuration of an atom is written in terms of previous noble gas.

Silicon is the 14th element of the periodic table having 14 electrons.

The nearest noble gas to this element is neon.

So, the noble gas notation for silicon atom = [tex][Ne]3s^23p^2[/tex]

Write a balanced equation to show the reaction of gaseous ethane,c2h6 with gaseous oxygen to form carbon monoxide gas,co, and water vapor

Answers

2C2H6 + 5O2 = 4co + 6h2o

Answer: The balanced chemical equation is written below.

Explanation:

Combustion reaction is defined as the chemical reaction in which a hydrocarbon reacts with oxygen gas to produce carbon dioxide gas and water molecule.

If supply of oxygen gas is limited, it is known as incomplete combustion and carbon monoxide gas is also produced as a product.

The chemical equation for this reaction of ethene and oxygen gas follows:

[tex]2C_2H_6+5O_2\rightarrow 4CO+6H_2O[/tex]

By Stoichiometry of the reaction:

2 moles of ethene gas reacts with 5 moles of oxygen gas to produce 4 moles of carbon monoxide gas and 6 moles of water vapor.

Hence, the balanced chemical equation is written above.

The simplest substances on Earth are called ________.

A. compounds
B. elements
C. solutions
D. molecules

Answers

the answer is element because there is no two subsances that can make up an element
The answer would be elements
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