Answer:
22.7%
Explanation:
We must first put down the equation of reaction to guide our work while solving the problem.
KCN(aq) + HCl (aq)--> KCl(aq) + HCN(aq)
The questions specifically state that HCl is in excess so KCN is the limiting reactant.
Number of moles of KCN reacted= mass of KCN reacted / molar mass of KCN
Mass of KCN reacted= 3.2 g
Molar mass of KCN= 65.12 g/mol
Number of moles of KCN= 3.2/65.12 g/mol= 0.049 moles
Theoretical yield of HCN is obtained thus;
From the reaction equation;
1 mol of KCN produced 1 mole of HCN thus 0.049 moles of KCN will produce 0.049 moles of HCN.
Mass of HCN = number of moles ×molar mass
Molar mass of HCN= 27.0253 g/mol
Hence mass of HCN produced= 0.049mol × 27.0253 g/mol= 1.32g of HCN
Actual yield of HCN= 0.30g
% yield= actual yield/ theoretical yield ×100
% yield= 0.30/1.32 ×100
%yield= 22.7%
Answer:
The theoretical yield HCN is 1.33 grams
The percent yield HCN is 22.56 %
Explanation:
Step 1: Data given
Mass of KCN = 3.2 grams
Molar mass KCN = 65.12 g/mol
Mass of HCN produced = 0.30 grams
Step 2: The balanced equation
KCN + HCl --> KCl + HCN
Step 3: Calculate moles KCN
Moles KCN = mass KCN / moalr mass KCN
Moles KCN = 3.2 grams / 65.12 g/mol
Moles KCN = 0.0491 moles
Step 4: Calculate moles HCN
For 1 mol KCN we need 1 mol HCl to produce 1 mol KCl and 1 mol HCN
For 0.0491 moles HCN we'll have 0.0491 moles HCN
Step 5: Calculate mass HCN
Mass HCN = moles HCN * molar mass HCN
Mass HCN = 0.0491 moles * 27.03 g/mol
Mass HCN = 1.33 grams = the theoretical yield
Step 6: Calculate the percent yield HCN
Percent yield = (actual yiel / theoretical yield) * 100 %
Percent yield = (0.30 grams / 1.33 grams)
Percent yield = 22.56 %
A neutral solution has a pH =
When a solution is basic, the pH is always greater than
When a solution is basic, the pOH is always less than
Answer:
7.
Explanation:
A neutral solution has a pH=7.
A basic solution has a pH>7.
An acidic solution has a pH<7.
Answer:
7,7,7
Explanation:
Which word equation shows lithium oxide being formed from the reaction between oxygen and lithium? oxygen + lithium oxide Right arrow. Lithium lithium + oxygen Right arrow. Lithium oxide oxygen + lithium Right arrow. Lithium + oxide lithium oxide Right arrow. Lithium + oxygen
Answer: lithium + oxygen Right arrow. lithium oxide
lithium + oxygen proper arrow. lithium oxide This equation indicates lithium oxide is formed from the reaction between oxygen and lithium.
what is lithium oxide used for?
Lithium oxide is used as a flux in ceramic glazes and creates blues with copper and pinks with cobalt. Lithium oxide reacts with water and steam, forming lithium hydroxide, and needs to be isolated from them.
wherein is Lithium Oxide found?Lithium Oxide is an extraordinarily insoluble thermally stable Lithium source suitable for glass, optic, and ceramic programs. Lithium oxide is a white stable also referred to as lithia, it is produced whilst lithium metallic burns inside the presence of oxygen.
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The diagram shows a pump. Which labels can replace
X and the Y in the diagram?
X: potassium, Y: sodium
X: sodium, Y potassium
X: sodium, Y: calcium
X: calcium, Y: potassium
Answer: The Answer is B. X: Sodium, Y: Potassium
Explanation: No Explanation I just Guessed. Hope This Help's Someone
Answer:
The answer is
X:Sodium Y:Potassium
Explanation:
I took the course and got it right
Consider the equation ; N₂ + 3 H₂ → 2 NH₃ What is the mole ratio of hydrogen to ammonia (NH₃)?
1. 1:1
2. 1:2
3. 3:2
4 5:4
Answer:
3. 3:2
Explanation:
in the reactants, 3 is the coefficient for the hydrogen atoms.
In the products, 2 is the coefficient for the ammonia atoms.
how is temperature related to the physical change of a substance ?
Answer: Temperature is a measure of the kinetic energy of particles in a substance. As temperature increases, the atoms or molecules in a substance gain energy. As temperature decreases, the particles lose energy. A change in the energy of particles causes a change in their arrangement. A change in the arrangement of particles can lead to a physical change.
Explanation:
Chemistry: Gas Laws Problems!
Answer : The final volume at STP is, 1000 L
Explanation :
According to the Boyle's, law, the pressure of the gas is inversely proportional to the volume of gas at constant temperature and moles of gas.
[tex]P\propto \frac{1}{V}[/tex]
or,
[tex]P_1V_1=P_2V_2[/tex]
where,
[tex]P_1[/tex] = initial pressure = 1520 mmHg = 2 atm (1 atm = 760 mmHg)
[tex]P_2[/tex] = final pressure at STP = 1 atm
[tex]V_1[/tex] = initial volume = 500.0 L
[tex]V_2[/tex] = final volume at STP = ?
Now put all the given values in the above formula, we get:
[tex]2atm\times 500.0L=1atm\times V_2[/tex]
[tex]V_2=1000L[/tex]
Therefore, the final volume at STP is, 1000 L
The volume of the gas at STP is [tex]\(1000.0 \, \text{L}\)[/tex].
1. Convert initial pressure to atm:
[tex]\[ P_1 = \frac{1520 \, \text{mm Hg}}{760 \, \text{mm Hg/atm}} = 2 \, \text{atm} \][/tex]
2. Apply the Combined Gas Law:
[tex]\[ \frac{P_1 \cdot V_1}{T_1} = \frac{P_2 \cdot V_2}{T_2} \][/tex]
Given:
[tex]\[ V_1 = 500.0 \, \text{L} \][/tex]
[tex]\[ P_1 = 2 \, \text{atm} \][/tex]
[tex]\[ P_2 = 1 \, \text{atm} \][/tex]
[tex]\[ T_1 = T_2 \][/tex] (temperature does not change)
Substituting the values, we get:
[tex]\[ \frac{(2 \, \text{atm} \cdot 500.0 \, \text{L})}{T} = \frac{(1 \, \text{atm} \cdot V_2)}{T} \][/tex]
3. Solve for [tex]\(V_2\)[/tex]:
Cross-multiply and solve for [tex]\(V_2\)[/tex]:
[tex]\[ 2 \cdot 500.0 = 1 \cdot V_2 \][/tex]
[tex]\[ V_2 = \frac{2 \cdot 500.0}{1} \][/tex]
[tex]\[ V_2 = 1000.0 \, \text{L} \][/tex]
At room temperature, which answer is the most compressible?
one liter of water, a liquid
one liter of oxygen, a gas
one liter of iron, a solid
one liter of mercury, a liquid
Answer:
i think its 1 liter of oxygen , a gas
Final answer:
One liter of oxygen gas is the most compressible among the options given, due to the significant spaces between gas molecules allowing for easier compression.
Explanation:
When considering the compressibility of various substances at room temperature, gases such as oxygen are the most compressible due to the large spaces between their molecules. In comparison, liquids like water and mercury are less compressible because their molecules are closer together, but they still offer some degree of compressibility. Solids like iron, however, are much less compressible because their atoms are tightly packed in a lattice structure. Of the options provided, one liter of oxygen gas would be the most compressible, as the spacing between gas molecules allows them to be pushed closer together far more easily than molecules in a liquid or atoms in a solid.
Ag2O(s) → 2Ag(s) + ½ O2(g) ΔH° = 31.05 kJ Which statements concerning the reaction above are true? (1) heat is released (2) heat is absorbed (3) reaction is exothermic (4) reaction is endothermic (5) products have higher enthalpy content than reactants (6) reactants have higher enthalpy content than products A) 1, 3, and 5 B) 1, 3, and 6 C) 2, 4, and 6 D) 2, 4, and 5
Answer:
D) 2, 4, and 5
Explanation:
In order to fully comprehend the answer choices we must take a close look at the value of ΔH° = 31.05. The enthalpy change of the reaction is positive. A positive value of enthalpy of reaction implies that heat was absorbed in the course of the reaction.
If heat is absorbed in a reaction, that reaction is endothermic.
Since ∆Hreaction= ∆H products -∆H reactants, a positive value of ∆Hreaction implies that ∆Hproducts >∆Hreactants, hence the answer choice above.
Answer:
D
Explanation:
HgO + Cl2 → HgCl + O2
A. Double Replacement
B. Single Replacement
C. Combustion
D. Decomposition
E. Synthesis
Answer:
B. Single Replacement
Explanation:
Single replacement:
It is the reaction in which one elements replace the other element in compound.
AB + C → AC + B
Chemical equation:
2HgO + Cl₂ → HgCl + O₂
This is the single replacement reaction. In this reaction chlorine replace the oxygen from mercury oxide and form mercury chloride.
Other options are incorrect because,
Decomposition reaction:
It is the reaction in which one reactant is break down into two or more product.
AB → A + B
Synthesis reaction:
It is the reaction in which two or more simple substance react to give one or more complex product.
A + B → AB
Double replacement:
It is the reaction in which two compound exchange their ions and form new compounds.
AB + CD → AC +BD
How many dots should be shown in the Lewis dot diagram of carbon?
1
2
3
4
Answer:
Im 90% sure its 3.
Explanation:
Answer:
4
Explanation:
Heat transfer focuses on transfers between the system and _____
A. accessories
B. universe
C. phases
D. surroundings
If 0.545J of heat leads to a 0.892 degree C change, what mass of water is present?
Answer:
I got .146 g of water
Explanation:
Refer to this equation:
Q= mcΔt
Q= .545 J
c= 4.186 J/g
Δt= .892
plug in values:
.545 J = m(4.186 J/g)(.892°C)
simplify:
.545 J = m(3.734 J/g°C)
.146 g
For a reaction system at equilibrium, LeChatelier's principle can be used to predict the A) activation energy for the system B) type of bonds in the reactants C) effect of a stress on the system D) polarity of the product molecules
For a reaction system at equilibrium, LeChatelier's principle can be used to predict the "effect of a stress on the system".
Option: C
Explanation:
Le Chatelier's theory can be implemented to forecast a system's behavior due to variations in pressure, temperature, or concentration that will lead in predictable and contested variations in the system adjustments to establish a new state of equilibrium. This means that adding heat to a process would favor the endothermic path of a reaction, because this decreases the amount of heat generated in the system.
Here shift in equilibrium take place when volume increase, the total pressure decreases, which have potential to reverse the reaction, while on increasing pressure of system, the total volume decreases of the gaseous system, which can shift an equilibrium in the direction of the fewer molecules.
For a reaction system at equilibrium, the Le principle can be used to predict the effect of a stress on the system.
The Le principle is an observation about chemical equilibria of reactions. Le principle can be used to predict the effect of a stress like changing concentration of a substance has on a reaction system at equilibrium.
If the concentration of a reaction species is increased at constant Temperature and Volume, the equilibrium system will shift in the direction that reduces the concentration of that substance so we can conclude that the Le principle can be used to predict the effect of a stress on the system.
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which solution contains phenolphthalein pink?
The decomposition of sulfonyl chloride, SOCl2 is a first order reaction with a half life of 8.75 hours. Calculate the concentration of SOCl2 after 17.0 hours have passed in an experiment where the initial concentration of sulfonyl chloride was .0837M.
Answer:
[tex][SOCl_2]=0.0218M[/tex]
Explanation:
The equations for a first order reaction are:
[tex]\dfrac{d[A]}{dt}=-k[A][/tex]
[tex][A]=[A_0]e^{-kt}[/tex]
[tex]t\frac{1}{2}=\dfrac{\ln 2}{k}[/tex]
1. Calculate the constant of reaction, k:
Use the equation
[tex]t\frac{1}{2}=\dfrac{\ln 2}{k}[/tex]
[tex]8.75h=\dfrac{\ln 2}{k}[/tex]
[tex]k=\dfrac{\ln 2}{8.75h}[/tex]
[tex]k\approx 0.0792168h^{-1}[/tex]
2. Calculate the concentration after 17.0 hours
Use the equation
[tex][A]=[A_0]e^{-kt}[/tex]
[tex][SOCl_2]=0.0837M\cdot e^{-0.0792168h^{-1}\times 17.0h}[/tex]
[tex][SOCl_2]=0.0218M[/tex]
Which process is used to determine the concentration of an acid?
Answer:
testing
Explanation:
some scientist somewhere made acid and probably forgot the recipe/ingredients so they kept making it and used plastic to see if it would melt it
How many moles are there in 24.00 g of NaCl
Answer:
The answer to your question is 0.41 moles
Explanation:
Data
moles of NaCl = ?
mass of NaCl = 24 g
Process
To solve this problem just calculate the molar mass of NaCl, and remember that the molar mass of any substance equals to 1 mol.
1.- Calculate the molar mass
NaCl = 23 + 35.5 = 58.5 g
2.- Use proportions and cross multiplication
58.5 g of NaCl ------------------- 1 mol
24.0 g ------------------- x
x = (24 x 1) / 58.5
x = 0.41 moles
Which element will have the following property in the periodic table 1)Largest atomic size 2) Highest electron affinity 3) lowest ionisation enthalpy in group II 4) gaseous form at room temperature
In the periodic table, Francium has the largest atomic size, Chlorine has the highest electron affinity, Barium has the lowest ionization enthalpy in Group II, and gaseous elements at room temperature include noble gases and some non-metals like Fluorine and Oxygen.
The periodic table organizes elements in such a way that we can predict their properties based on their position. These properties, including atomic size, electron affinity, and ionization enthalpy, show clear patterns or trends within the table. As a tutor from the Brainly platform, let's address the specific properties asked in the question.
The element with the largest atomic size is typically found at the bottom left of the periodic table. Francium (Fr) is generally considered to have the largest atomic radius because it belongs to Group 1 and is the heaviest alkali metal. The atomic size increases down a group and decreases across a period from left to right.Highest electron affinity is generally observed in halogens. Chlorine (Cl), being very eager to gain an electron to achieve a noble gas electron configuration, has one of the highest electron affinities.The element with the lowest ionization enthalpy in Group II is expected to be at the bottom of the group. Barium (Ba), being at the lower part of Group II, has lower ionization energy compared to its counterparts up the group.Gases at room temperature from Group II are notable as they are non-existent; however, elements that are in gaseous form at room temperature from the periodic table include the noble gases such as Radon (Rn), Xenon (Xe), Krypton (Kr), Argon (Ar), Neon (Ne), Helium (He), and some non-metals like Fluorine (F), Chlorine (Cl), Oxygen (O), Nitrogen (N), and Hydrogen (H).The reduction potential (E0′) of a substance reflects its tendency to donate or accept electrons. The larger the difference (ΔE0′) between the reduction potentials of the electron donor and the electron acceptor, __________.A) the greater the change in free energy (ΔG0′), and the less energy is releasedB) the closer the substances are on the electron towerC) the more enzymes will be required to catalyze the reaction(s)D) the greater the change in free energy (ΔG0′), and the greater the energy released
Answer:
The greater the change in free energy (ΔG0′), and the greater the energy released
Explanation:
Recall that the change in free energy is given by:
∆G°'= nFE°'
But E° is given by E°acceptor - E°donor
Hence the greater the difference between E°acceptor and E°donor, the greater the value of E° and consequently the greater the value of ∆G° and the energy released.
Note: E°acceptor and E°donor refer to reduction potentials of donor and acceptor
If 35 mL of 0.10 Macid solution is neutralized by 21.8 mL of a basic solution, what is the molarity
of the base? MaVa = MbVb
The specific heat capacity of an unknown metal is 0.343 J/(g•°C). Calculate the energy required to raise the temperature of 224 g of this metal by 71°C.
Answer:
Preceding accumulative aggregate of energy indispensable is disseminated as 5455 J.
Explanation:
Allotted the contiguous information:
Q: Not identified.
M: 224 g
S: 0.343 J/g°C
Final thermodynamics: 71°C
Initial thermodynamics: 0°C
ΔT = 71°C
We can equate as imminent:
Q = 224 g · 0.343 J/g°C · 71°C
Q ⇒ 5455 J
Hence, the pertaining preeminent albeit paramount indispensable consignment or quantity of energy obligated, concerning an augmentation in thermodynamics subject to the undisclosed metal by 71°C is 5,455 J.
The energy required to raise the temperature of the metal is 5365.256 J.
Explanation:To calculate the energy required to raise the temperature of a substance, we use the formula:
q = m * c * ΔT
The energy required to raise the temperature of a substance can be calculated using the formula: q = mcΔT where q is the energy in joules, m is the mass in grams, c is specific heat capacity in J/(g•°C), and ΔT is the change in temperature in °C.
Given that the mass (m) of the metal is 224 g, the specific heat capacity (c) is 0.343 J/(g•°C), and the temperature change (ΔT) is 71°C, you can substitute these values into the formula:
Plugging in the values given:
q = (224 g) * (0.343 J/(g•°C)) * (71°C)
Simplifying the equation gives:
q = 5365.256 J
Therefore, the energy required to raise the temperature of 224 g of this metal by 71°C is 5365.256 J.
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2. If 6.0g of carbon is heated in air, the mass of the product obtained could be either 22.0g or 14.0g depending on the amount of air present. Show that this verifies the law of multiple proportions.
3. Alaxin, (C5H8)nO5, is a new malaria drug. Determine the molecular formula of alaxin if its relative molecular mass is 284.
(H = 1, C = 12, O = 16)
i dont seem to remeber
2 . The ratio of 1:2 in the mass of second element, oxygen in CO and CO2 verifies the law of proportion.
3. [tex]C_{15}[/tex][tex]H_{24}[/tex][tex]O_{5}[/tex] is the molecular formula of the new malaria drug given.
Explanation:
Balanced chemical reaction:
C + O ⇒ C0
C + O2 ⇒ CO2
law of multiple formulation states that when two elements combine to form a compound the ratio of the mass of elements is a whole number.
Carbon reacts with oxygen to produce:
Mass of carbon mass of oxygen ratio of O in CO2 to O in CO
CO = 12 16 3:4
CO2 = 12 32 3:8
CO 6 gm 8 3:4
CO2 6 16 3:8
The ratio of the mass of the second element i.e oxygen is CO:CO2 is 1:2, hence it shows law of multiple proportions.
3. given,
(C5H8)nO5 = emperical formula
relative molecular mass = 284
molecular formula= ?
The value of n will be calculated as:
(12x5)+ (1x8)n + (16x5) = 284
(60 +8)n + 80 = 284
68n + 80 = 284
68n = 284 - 80
68n = 204
n = 3
Multiplying the emperical formula by n
(C5H8)3O5
[tex]C_{15}[/tex][tex]H_{24}[/tex][tex]O_{5}[/tex] is the molecular formula of the drug.
The formation of different carbon oxide compounds with differing masses of oxygen that combine with a fixed mass of carbon demonstrates the law of multiple proportions with a small whole number ratio. To find the molecular formula of Alaxin, the relative molecular mass is divided by the mass of its empirical formula, yielding a molecular formula of C10H16O10.
Explanation:The law of multiple proportions states that when two elements combine to form more than one compound, the masses of one element that combine with a fixed mass of the other are in the ratio of small whole numbers. To verify this with carbon and oxygen, we consider the two cases: carbon dioxide (CO2) and carbon monoxide (CO).
When 6.0g of carbon reacts with oxygen, we can get either 22.0g of carbon dioxide or 14.0g of carbon monoxide. The mass of oxygen that combines with the 6.0g of carbon can be calculated for each compound:
For carbon dioxide: Mass of oxygen = 22.0g (total mass) - 6.0g (carbon) = 16.0gFor carbon monoxide: Mass of oxygen = 14.0g (total mass) - 6.0g (carbon) = 8.0gThe ratio of the mass of oxygen in carbon dioxide to the mass of oxygen in carbon monoxide is 16.0g : 8.0g = 2:1, which is a small whole number ratio, thus verifying the law of multiple proportions.
To determine the molecular formula of Alaxin, given its relative molecular mass is 284:
Calculate the relative molecular mass of the empirical formula (C5H8O5): (12*5) + (1*8) + (16*5) = 60 + 8 + 80 = 148 g/mol.Divide the relative molecular mass of Alaxin by the empirical formula mass to find n: 284 / 148 = 1.92, approximately 2.The molecular formula is (C5H8O5)2, or C10H16O10.
How many grams of sodium bromide must be dissolved in 400.0 g of water to produce a 0.500 molal solution?
Answer:
The answer is 20.6 grams.
Explanation:
Molality describes the concentration of a solution. It can be defined as the number of moles of a solute dissolved in 1 kilogram of solvent. Then it is equal to the moles of solute (the substance that dissolves) divided by the kilograms of solvent (the substance used to dissolve):
[tex]Molality=\frac{number of moles of solute}{kilogram of solvent}[/tex]
The molality is expressed in units ([tex]\frac{moles}{kg}[/tex]).
So, you can apply the following rule of three with the solution being 0.5 molal: if in 1 kg of solution there are 0.5 moles of solute, in 0.4 kg (400 g, being 1kg = 1000g) how many moles of solute are there?
[tex]moles=\frac{0.4 kg*0.5 moles}{1 kg}[/tex]
moles=0.2 moles
Now, you know:
Na: 23 g/moleBr: 80 g/moleThen, The molar mass of sodium bromide NaBr is
NaBr= 23 g/mole + 80 g/mole= 103 g/mole
Now a new rule of three applies, if in 1 mole of sodium bromide there are 103 grams, in 0.2 mole how much mass is there?
[tex]mass=\frac{0.2 moles*103 grams}{1 mole}[/tex]
mass= 20.6 grams
The answer is 20.6 grams.
NEED HELP WITH CHEM :)
What volume of a 3.70 M NaCl solution is needed for a reaction that requires 118 g of NaCl?
Answer:
volume of solution L =0.54 L
Explanation:
Given data:
Molarity of NaCl solution = 3.70 M
Mass of NaCl = 118 g
Solution:
First of all we will calculate the number of moles.
Number of moles = mass/ molar mass
Number of moles = 118 g/ 58.5 g
Number of moles = 2 mol
Now we will calculate the volume from molarity formula:
Molarity = number of moles / volume of solution L
3.70 M = 2 mol / volume of solution L
volume of solution L = 2 mol / 3.70 M
volume of solution L =0.54 L
The heat of combustion of propane, C3H8, is 2220 kJ/mol. The specific heat of copper is 0.385 J/g°C. How many grams of propane must be burned to raise the temperature of a 10.0 kg block of copper from 25.0°C to 65.0°C, assuming none of the heat is lost to the surroundings?
Answer:
Explanation:
q = (mass) (temp change) (specific heat)
q = (10000 g) (40 °C) (0.385 J/g⋅°C) = 154000 J = 154 kJ
154 kJ / 2220 kJ/mol = 0.069369369 mol
0.069369369 mol times 44.0962 g/mol = 3.06 g (to three sig figs)
answer choice 4
The heat of combustion ([tex]\Delta[/tex]Hc0) is the amount of energy released as heat when a compound completely burns with oxygen under standard conditions.
3.05988g. grams of propane must be burned to raise the temperature of a 10.0 kg block of copper from 25.0°C to 65.0°C.
What is meant by heat of combustion?The heat of combustion ([tex]\Delta[/tex]Hc0) is the amount of energy released as heat when a compound completely burns with oxygen under standard conditions. In most cases, a hydrocarbon reacts with oxygen to produce carbon dioxide, water, and heat.The heat of combustion of a substance is the amount of energy released when a specific amount (e.g., 1 mol, 1g, 1 L) of the substance completely burns in oxygen. The heat of combustion is typically measured at 298K (25 C) and 101.3kPa.The energy released when a substance X completely burns with an excess of oxygen under standard conditions (25°C and 1 bar). It is the inverse of the enthalpy change for the combustion reaction in thermodynamic terms.q=m*c*(change of T)
q=10000g(0.385J/g*c)*(65.0C-25.0C)or (338.2 K-298.2K)
q=154000J
154000J*(1 mol/2220 KJ)=69.36936 x [tex]10 ^-3[/tex] mol
here's where I'm stuck
0.069369 mol
and i know that for every 1 mol there is 44.11g of C3H8.
0.069369 mol* (44.11g C3H8)/1mol = 3.05988g.
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What volume of water should be used to dissolve 19.6 g of LiF to create a 0.320 M solution?
Answer:
2.4 L
Explanation:
Given data:
Mass of LiF = 19.6 g
Molarity of solution = 0.320 M
Volume of water used = ?
Solution:
Number of moles = mass/molar mass
Number of moles = 19.6 g/ 26 g/mol
Number of moles = 0.75 mol
Volume required:
Molarity = number of moles/ volume in L
0.320 M = 0.75 mol / volume in L
Volume in L = 0.75 mol /0.320 M
M = mol/L
Volume in L = 2.4 L
How many miles of C5H12 are there in 362.8 grams of the compound?
Answer:
5.03 moles
Explanation:
Find the molar mass of C5H12 and you will get 72.17 g/mol
Next to find the number of moles, you divide 362.8 by the molar mass and you get
(362.8 g)/(72.17 g/mol)= 5.03 moles
Liquid A has a vapor pressure of 7.37 kPa at 40C. Liquid B has a vapor pressure of 18.04kPa at 40C. Which liquid would evaporate faster at 40C? Explain your answer.
Answer:
Liquid B because of its higher vapor pressure due to the fact that evaporation rate is directly proportional to vapor pressure
Explanation:
The vapor pressure of liquid at equilibrium is a function to the liquid's rate of evaporation. The evaporation rate and hence the vapor pressure is a measure of the propensity of the particles of the liquid to leave the surface of the liquid and exist as vapor directly above the liquid. As high evaporation rate leads to high vapor pressure, a liquid with a higher vapor pressure will evaporate faster than one with a lower vapor pressure at the same temperature and pressure.
Therefore, liquid B with a vapor pressure of 18.04 kPa at 40° C will evaporate faster than liquid A with a lower vapor pressure of 7.37 kPa at the same 40°C.
Liquid B with a higher vapor pressure of 18.04 kPa at 40°C would evaporate faster than liquid A with 7.37 kPa, as higher vapor pressure indicates that the liquid is more volatile and its molecules can more easily escape into the gas phase.
Explanation:At 40°C, between liquid A with a vapor pressure of 7.37 kPa and liquid B with a vapor pressure of 18.04 kPa, liquid B would evaporate faster. This is because vapor pressure is a measure of the tendency of molecules to escape from a liquid and enter the gas phase. A higher vapor pressure indicates that molecules can break away from the surface of the liquid more easily, which is indicative of a more volatile liquid. Therefore, liquid B, with its higher vapor pressure at the same temperature, is the more volatile and will evaporate more rapidly than liquid A.
Vapor pressure of a liquid is directly related to its intermolecular forces; liquids with weaker intermolecular forces have higher vapor pressures, and hence they evaporate faster. Conversely, greater intermolecular forces result in a lower vapor pressure and slower evaporation rate. For volatile liquids in a mixture, adding their partial pressures yields the total vapor pressure of the mixture
You purchase several rolls of fiberglass insulation and pay extra for installation. Have you purchased a product or a service?
You purchase several rolls of fiberglass insulation and pay extra for installation. This is a service.
What is fiberglass insulation?The majority of homes include fibreglass, an insulation substance made of incredibly thin glass fibres. It is frequently used in two forms of insulation: loose-fill and batts and rolls. Additionally, rigid boards or duct insulation are both options.
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Ozone reacts completely with NO, producing NO2 and O2. A 13.0 L vessel is filled with 1.30 mol of NO and 1.30 mol of O3 at 401.0 K. Find the partial pressure of each product and the total pressure in the flask at the end of the reaction.
Answer:
6.58 atm total
3.29 atm NO2
3.29 atm O2
Explanation:
Balanced equation:
O3 + NO → NO2 + O2
There are equal numbers of moles of both reactants, so neither is in excess and either could be considered the limiting reactant.
( 1.30 mol NO) x (1 mol NO2 / 1 mol NO) = 1.30 mol NO2
( 1.30 mol NO) x (1 mol O2 / 1 mol NO) = 1.30 mol O2
Total pressure by using the formula;
P = nRT / V
= ( 1.30 mol + 1.30 mol) x (0.08205746 L atm/K mol) x (401.0 K) / (13.0 L)
= 6.58 atm
Partial pressure for NO2;
(6.58 atm) x (1.30 mol NO2) / (1.30 mol + 1.30 mol)
= 3.29 atm NO2
Partial pressure for O2
6.58 atm total - 3.29 atm NO2
= 3.29 atm O2
1. The partial pressure of nitrogen dioxide ([tex]NO_2[/tex]) is equal to 3.29 atm.
2. The partial pressure of oxygen gas ([tex]O_2[/tex]) is equal to 3.29 atm.
3. The total pressure in the flask at the end of the chemical reaction is 6.58 atm.
Given the following data:
Volume of flask = 13.0 LitersNumber of moles of NO = 1.30 moles.Number of moles of [tex]O_3[/tex] = 1.30 moles.Temperature = 401.0 K.Scientific data:
Ideal gas constant, R = 0.0821L⋅atm/mol⋅KTo determine the partial pressure of each product and the total pressure in the flask at the end of the chemical reaction:
First of all, we would write a balanced chemical equation for the chemical reaction as follows:
[tex]O_3 + NO \rightarrow NO_2+O_2[/tex]
Since the numbers of moles of reactants are equal, the total number of moles of products is:
[tex]n=1.3+1.3[/tex]
n = 2.6 moles
Now, we can find the total pressure in the flask at the end of the chemical reaction by using the ideal gas law equation;
[tex]PV=n RT[/tex]
Where;
P is the pressure.V is the volume.n is the numbers of moles of gas.R is the ideal gas constant.T is the temperature.Making P the subject of formula, we have;
[tex]P=\frac{nRT}{V}[/tex]
Substituting the parameters into the formula, we have;
[tex]P=\frac{2.6 \times 0.0821 \times 401}{13}\\\\P=\frac{85.597}{13}[/tex]
Total pressure, P = 6.58 atm.
Next, we would determine the partial pressure of each product:
[tex]Molefraction \;of \;a \;substance =\frac{No.\; of \; moles \;of \;substance}{Total \;no. \;of \; moles \;of \;substances}[/tex]
[tex]Molefraction \;of \;a \;substance =\frac{1.3}{2.6} \\\\Molefraction \;of \;a \;substance =0.5[/tex]
For [tex]NO_2[/tex]:
[tex]Partial \;pressure = Molefraction \times Total\;pressure\\\\Partial \;pressure = 0.5 \times 6.58[/tex]
Partial pressure of [tex]NO_2[/tex] = 3.29 atm.
For [tex]O_2[/tex]:
[tex]Partial \;pressure = Molefraction \times Total\;pressure\\\\Partial \;pressure = 0.5 \times 6.58[/tex]
Partial pressure of [tex]O_2[/tex] = 3.29 atm.
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