A space-walking astronaut has become detached from her spaceship. she's floating in space while holding nothing nothing but a wrench. She is thinking how to get back to the spaceship which she can see 50 meters from her current location. what can she do to get back to the spaceship? Use language from Newton's laws of motion in your answer

Answers

Answer 1

she could throw her tool belt in the opposite direction, sending her floating towards her ship. That would apply to Newton's Law ofwhat is in motion stays in motion unless interrupted. Therefore if you threw it one way you would keep going the other way because there are no molecules to interrupt your path.


Answer 2
Final answer:

To return to her spaceship, the astronaut should apply Newton's third law of motion by throwing the wrench away from the ship, which will propel her towards it via an equal and opposite reaction.

Explanation:

The astronaut floating in space can return to her spaceship by utilizing Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. By throwing the wrench away from the spaceship, there will be a reactive force that pushes the astronaut towards the spaceship. The mass of the wrench and the force with which the astronaut throws it will determine the velocity at which she moves towards the spaceship, according to the conservation of momentum. Newton's laws of motion and the conservation of momentum are key principles that will help her navigate back to safety.


Related Questions

Which is an example of the conversion of gravitational potential energy into kinetic energy?

Answers

a falling rain drop may be an example.

Answer:

When a ball is dropped from some height from rest then while its motion under gravity its initial gravitational potential energy converts into kinetic energy

Explanation:

When ball is placed at some height "h" above the floor at rest then initial gravitational potential energy is given as

[tex]U = mgh[/tex]

here we know

m = mass of the ball

g = acceleration due to gravity

h = height of the ball

now when ball is dropped from this height then its initial potential energy will convert into kinetic energy.

so speed of ball at some instant of time is given as

[tex]\frac{1}{2} mv^2 = mgh[/tex]

[tex]v = \sqrt{2gh}[/tex]

so here in this case gravitational potential energy will convert into kinetic energy of ball

Which of these are minerals? Select all that apply

A) mica

B) quartz

C) steam

D) copper

Answers

From that particular list:

Mica (A), Quartz (B), and Copper (D) are minerals.

Steam (C) isn't.

While Bob is demonstrating the gravitational force on falling objects to his class, he drops an 1.0 lb bag of feathers from the top of the science building. Determine the distance the bag has traveled after falling for 1.5 seconds assuming it has reach free fall and given the gravitational acceleration of 9.8 m/sec2.

Answers

In the experiment of free fall bob released a bag of mass 1 lb

so here we can say that initial speed of the bag is Zero

time taken by the bag to free fall is given as

t = 1.5 s

also the acceleration of free fall is given as

a = 9.8 m/s^2

now we will use kinematics equation here for finding the distance of free fall

[tex]d = v_i * t + \frac{1}{2} at^2[/tex]

[tex]d = 0 + \frac{1}{2}*9.8* 1.5^2[/tex]

[tex]d = 4.9 * 2.25[/tex]

[tex]d = 11.025 m[/tex]

so the bag will fall down by total distance of 11.025 m from its initial released position.


Final answer:

The 1.0 lb bag of feathers has traveled approximately 11.025 meters after falling for 1.5 seconds, assuming it is in free fall and subject to Earth's gravitational acceleration of 9.8 m/s².

Explanation:

To determine the distance the 1.0 lb bag of feathers has traveled after falling for 1.5 seconds, assuming it has reached free fall and is only affected by gravitational acceleration, we can use the formula for the distance covered by an object in free fall:

d = ½ * g * t²,

where g is the acceleration due to gravity (9.8 m/s²) and t is the time in seconds.

Plugging in the values:

d = ½ * 9.8 m/s² * (1.5 s)²

d = ½ * 9.8 * 2.25

d = ½ * 22.05

d = 11.025 meters

Therefore, the bag of feathers has traveled approximately 11.025 meters after falling for 1.5 seconds.

a toy friction car is propelled forward from rest by a girl's hand which causes it to reach a forward velocity of 3.5m/s in 0.4 seconds. it is then rreleased and later stops in 5.6 seconds.

a) what is the acceleration with which the car speeded up?

b)what is the acceleration with which the car slowed down?

c) how far did the toy car travel?

Answers

Answer:

a)  Acceleration = [tex]8.75m/s^2[/tex]

b) Slow down acceleration = 0.625[tex]m/s^2[/tex]

c) Car travels 9.8 m

Explanation:

  Acceleration = Change in velocity/Time

a) Change in velocity = 3.5-0 = 3.5 m/s

   Time = 0.4 seconds

    Acceleration = [tex]3.5/0.4=8.75m/s^2[/tex]

b) Change in velocity = 0 - 3.5 = -3.5 m/s

   Time = 5.6 seconds

   Acceleration = [tex]-3.5/5.6=-0.625m/s^2[/tex]

   Slow down acceleration = 0.625[tex]m/s^2[/tex]

c) We have equation of motion, [tex]v^2=u^2+2as[/tex], where u is the initial velocity, u is the final velocity, s is the displacement and a is the acceleration.

 Here v = 0 m/s, u = 3.5 m/s, a = -0.625[tex]m/s^2[/tex]

 Substituting

    [tex]0^2=3.5^2-2*0.625*s\\ \\ s=9.8m[/tex]

  So, car travels 9.8 m

Four students are comparing vectors and scalars. The chart contains each students statements about vectors and scalars

Answers

Vectors have a magnitude and direction whereas scalars only have a magnitude. The dot product of two vectors is a scalar.

 In summary, vectors are quantities with both magnitude and direction, and their addition and multiplication by scalars follow specific rules. Scalars are quantities with only magnitude and are added by simple arithmetic. The correct option for any statement about vectors and scalars would be the one that accurately reflects these properties

To provide a solution to the question, we need to understand the key differences between vectors and scalars as described by the students in the chart. Here are the typical characteristics that distinguish vectors from scalars:

1. Magnitude and Direction: Vectors have both magnitude and direction, whereas scalars have only magnitude. This is the fundamental difference between the two. For example, velocity is a vector quantity because it describes both the speed (magnitude) and the direction of motion, while speed alone is a scalar quantity.

 2. Representation: Vectors are often represented by arrows, where the length of the arrow corresponds to the magnitude and the arrowhead indicates the direction. Scalars are typically represented by a number with units, if applicable.

 3. Addition: When adding vectors, both their magnitudes and directions must be considered, which often involves geometric construction or trigonometric calculations. In contrast, scalar addition is straightforward and involves simply adding the numerical values.

 4. Multiplication by a Scalar: Multiplying a vector by a scalar changes the magnitude of the vector but not its direction. The result is a vector that is parallel to the original vector.

 5. Dimensionality: Vectors can be one-dimensional (straight line), two-dimensional (plane), or three-dimensional (space). Scalars are zero-dimensional, as they are just single values without direction.

6. Physical Quantities: Examples of vector quantities include displacement, velocity, acceleration, and force. Examples of scalar quantities include mass, temperature, energy, and time.

 Based on these characteristics, the students' statements can be analyzed to determine if they are correct or incorrect. For instance, if a student says that a vector has only magnitude, this statement is incorrect because vectors must have both magnitude and direction.

To solve the question accurately, we would need to see the specific statements made by each student in the chart. However, without the actual statements, we can only provide a general explanation of the differences between vectors and scalars.

 In summary, vectors are quantities with both magnitude and direction, and their addition and multiplication by scalars follow specific rules. Scalars are quantities with only magnitude and are added by simple arithmetic. The correct option for any statement about vectors and scalars would be the one that accurately reflects these properties."

For this position-time graph, what is the average velocity for the entire curve?

A. -4 m/s
B. -10 m/s
C. +10 m/s
D. +4 m/s

Answers

A. Without doing much math, it can be seen from the graph that the altitude is decreasing. The slope of the position time graph determines velocity, so by comparing the start to the end of the graph, it can be seen that -100m was the change in altitude and 25 seconds was the change in time. Divide -100 by 25 to get -4m/s.
Final answer:

The average velocity for the entire curve on a position-time graph can be found by calculating the slope between the initial and final points. In this case, the average velocity is -4 m/s.

The correct answer would be Option A: -4 m/s.

Explanation:

To find the average velocity for the entire curve on a position-time graph, you can calculate the slope of the line connecting the initial and final points on the graph.

Identify the initial position and time on the graph.Identify the final position and time on the graph.Calculate the change in position by subtracting the initial position from the final position.Calculate the change in time by subtracting the initial time from the final time.Divide the change in position by the change in time to calculate the average velocity.

In this case, it looks like the curve has a downward slope, so the average velocity would be negative. Based on the given answer options, the correct answer would be Option A: -4 m/s.

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A car's position in relation to time is plotted on the graph. What can be said about the car during segment B?

A) The car travels for 80 seconds during segment B.
B) The car has come to a stop and has zero velocity.
C) The car is traveling faster during segment B than in segment C.
D) The car is traveling with a constant velocity due to the flat line of the graph.

Answers

we know that

the speed is equal to

[tex]speed=\frac{distance}{time}[/tex]

The slope of the line on the graph is equal to the speed of the car

so

during the segment B the slope of the line is equal to zero

that means

the speed of the car is zero

therefore

the answer is the option B

The car has come to a stop and has zero velocity

Option (B) is correct .i.e. the car has come to a stop and has zero velocity.

Further Explanation:

According to the theory of graphs, ‘the straight line parallel to x axis’ means the quantity given on y axis is not changing or is constant with respect to the change in the quantity on x axis. This is why because the slope of that particular straight line is zero.

Concept:

Mathematically, the slope is defined as the tangent (trigonometry) of the angle made by the segment with the x axis or it is also defined as the ratio of change in the quantity on y-axis to change in the quantity on x-axis.

[tex]\boxed{\text{slope}=\tan(\theta)}[/tex]

Here, [tex]\theta[/tex] is the angle made by the segment of graph with x-axis

The slope can also be expressed as:

[tex]\boxed{\text{slope}=\dfrac{\text{change in quantity given on y-axis}}{\text{change in quantity given on x-axis}}}[/tex]

 

Here, the quantity given on y axis is car’s position and that given on x axis is time taken by the car to travel.

The slope of position-time graph gives velocity.  So, by the definition of slope, we have  

[tex]{\text{velocity}=\dfrac{\text{change in position}}{{\text{change in time}}}[/tex]

Here, as shown in the graph, the two ends of the segment B have same values of position on y axis. So, change in position will be zero.

Substitute [tex]0[/tex] for [tex]\text{change in position}[/tex] in above expression.

[tex]\text{Velocity}=0\text{ m/s}[/tex]

This shows that the speed of the car in the segment B of the graph will be zero as there is no change in the position of the car with respect to time.

Thus, option (B) is correct .i.e. the car has come to a stop and has zero velocity.

Learn More:

1. A highway patrolman traveling at the speed limit is passed by a car https://brainly.com/question/2456051

2. Head-on collision of the two bodies https://brainly.com/question/2097915

Answer Details:

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords:

Position, car, relation to time, segment B, 80 sec, zero velocity, travelling, faster, graph, position vs time, constant velocity, slope, change in position, change in time.

The acceleration due to gravity on the moon is 1.6 m/s2, about a sixth that of Earth’s. Which accurately describes the weight of an object on the moon? An object on the moon is 1/6 times lighter than on Earth. An object on the moon is 1/6 times heavier than on Earth. An object on the moon is six times lighter than on Earth. An object on the moon is six times heavier than on Earth.

Answers

The answer is C.  

An object on the moon is six times lighter than on Earth.


The statement accurately describes the weight of an object on the moon is  An object on the moon is 1/6 times lighter than on Earth.

What is weight?

The weight is the product of mass of the object and acceleration due to gravity on the specific planet.

When the acceleration due to gravity is less, the weight measured will be less. The acceleration due to gravity on the moon is 1.6 m/s2, about a sixth that of Earth’s.

Thus, an object on the moon is 1/6 times lighter than on Earth.

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What Device can be used to increase voltage from a source of direct-current?

Answers

multi meter reading instruments Device can be used to increase voltage know direct-current

A 500 kg cannon exerts a force of 600 N on a 10 kg cannon ball. Find (a) the acceleration of the cannon and (b) the acceleration of the cannon ball.

Answers

A 500 kg cannon exerts 600 N force on 10 kg cannon ball

Now here we can say that as per Newton's III law every action has equal and opposite reaction force

So here when cannon exert a force of 600 N on the ball then equal and opposite magnitude force will act on cannon itself

Part a)

Okay now we will find the acceleration of cannon using the same force

so as per Newton's formula

[tex]F = ma[/tex]

[tex]600 = 500 * a[/tex]

[tex]a = 1.2 m/s^2[/tex]

Part b)

Okay now we will find the acceleration of cannon ball using the given force

so as per Newton's formula

[tex]F = ma[/tex]

[tex]600 = 10 * a[/tex]

[tex]a = 60 m/s^2[/tex]

Are external computer flash drive can hold 1 gigabyte of data. How many bytes is this?

Answers

The prefix "giga..." means 1 billion. We talk about that flash drive as if its capacity is exactly 1 billion bytes.

But with digital things, a "giga..." Is actually 2^30 = 1,073,741,824 .

Rock a is dropped from a cliff and rock b is thrown upward from the same position on the cliff.
a. when each rock reaches the ground at the bottom of the cliff, which rock has a greater velocity?

Answers

In the A case, v0=0, in the B case v0 >0, so v is greater in the B case. In other words, v is related to the kinetic energy, since the rock B has a larger kinetic energy in the beginning, it also has a larger kinetic energy (larger velocity) in the end.

The correct answer is that rock a has a greater velocity when each rock reaches the ground at the bottom of the cliff.

To understand why rock a has a greater velocity upon impact with the ground, let's consider the physics of free-falling objects under the influence of gravity. Both rocks are subject to the acceleration due to gravity, which is approximately[tex]\(9.81 \, \text{m/s}^2\)[/tex] downward.

For rock a, which is simply dropped from rest, its initial velocity is zero. The only force acting on it is gravity, pulling it downward. Its velocity at any time \(t\) before it hits the ground can be calculated using the equation for uniformly accelerated motion:

[tex]\[ v_{a} = u_{a} + gt \][/tex]

where[tex]\(v_{a}\)[/tex] is the final velocity, [tex]\(u_{a}\)[/tex] is the initial velocity (which is zero for rock a), [tex]\(g\)[/tex] is the acceleration due to gravity, and [tex]\(t\)[/tex] is the time of fall. Since [tex]\(u_{a} = 0\)[/tex], the equation simplifies to:

[tex]\[ v_{a} = gt \][/tex]

For rock b, which is thrown upward, its initial velocity[tex]\(u_{b}\)[/tex] is upward and has some positive value. As it rises, it slows down due to the acceleration due to gravity acting in the opposite direction of its motion. At its highest point, its velocity will be zero, and then it will start to fall back down, accelerating due to gravity until it hits the ground. The velocity of rock b just before impact can be calculated using the same equation for uniformly accelerated motion, but taking into account that it starts with an initial upward velocity and then reverses direction:

[tex]\[ v_{b} = u_{b} - gt_{up} + gt_{down} \][/tex]

where [tex]\(t_{up}\)[/tex]is the time it takes for rock b to reach its highest point and \[tex](t_{down}\)[/tex]is the time it takes to fall back to the ground. Since the acceleration due to gravity is the same for both rocks, and assuming that air resistance is negligible, the time of ascent [tex]\(t_{up}\)[/tex] for rock b is equal to the time of descent [tex]\(t_{down}\), so \(t_{up} = t_{down} = t/2\).[/tex] The equation for rock b's velocity upon impact becomes:

[tex]\[ v_{b} = u_{b} - g(t/2) + g(t/2) \] \[ v_{b} = u_{b} \][/tex]

Since rock a was dropped from rest, its velocity upon impact is due solely to the acceleration due to gravity over the entire time \(t\) of its fall, while rock b's velocity upon impact is its initial launch velocity minus the effect of gravity over half the time (as it rises) and plus the effect of gravity over the other half of the time (as it falls).

Because rock a starts from rest and only accelerates downward, it will have a greater velocity upon impact than rock b, which has its initial upward velocity reduced by the same gravitational acceleration over the time of its ascent and then increased by the same gravitational acceleration over the time of its descent. Thus, rock a's velocity at the moment of impact will be greater than rock b's velocity at the moment of impact, assuming they both hit the ground at the same time and air resistance is negligible.

a ball is thrown upwards at an unknown speed. in a time of
.5 second the ball has a height of 6 meters.

what is the initial speed of the ball?

what is the balls speed at a height of 6 meters?

what would be the balls maximum height? (hint: you dont know the time to reach maximum height)

Answers

Answer:

a)  Initial speed of the ball = 14.45 m/s

b) At height 6 m speed of ball = 9.55 m/s

c) Maximum height reached = 10.65 m

Explanation:

a)  We have equation of motion [tex]s=ut+\frac{1}{2} at^2[/tex], where s is the displacement, u is the initial velocity, t is the time taken and a is the acceleration.

s = 6 m, t = 0.5 seconds, a = acceleration due to gravity value = -9.8[tex]m/s^2[/tex]

 Substituting

    [tex]6=u*0.5-\frac{1}{2} *9.8*0.5^2\\ \\ u=14.45m/s[/tex]

 Initial speed of the ball = 14.45 m/s

 b) We have equation of motion [tex]v^2=u^2+2as[/tex], where v is the final velocity

   s = 6 m, u = 14.45 m/s, a = -9.8[tex]m/s^2[/tex]

    Substituting

        [tex]v^2=14.45^2-2*9.8*6\\ \\ v=9.55m/s[/tex]

  So at height 6 m speed of ball = 9.55 m/s

c) We have equation of motion [tex]v^2=u^2+2as[/tex], where v is the final velocity

   u = 14.45 m/s, v =0 , a = -9.8[tex]m/s^2[/tex]

   Substituting

     [tex]0^2=14.45^2-2*9.8*s\\ \\ s=10.65 m[/tex]

  Maximum height reached = 10.65 m

f a wave has a wavelength of 9 meters and a period of 0.006, what is the velocity of the wave? A. 1,200 m/s B. 1,500 m/s C. 1,800 m/s D. 1,285 m/s

Answers

Answer: 1500 m/sec. ( b )

Solution:

V= f (λ)

Speed = frequency. Wavelength  

And frequency = 1/time period

First we will find the frequency :

Frequency = 1/time period

1/0.006 = 166.67 Hz

Using this in the equation:

Speed = frequency. Wavelength  

V= f (λ)

9 × 166.67  

= 1500.03 ≈ 1500

V (Speed) = 1500 m/s.

Note: Do not forget to mention the units or otherwise they may cost you marks!


Answer:

B

Explanation:

Dalton's model of an atom is best described as _____. A. A solar system B. A cloud C. A scoop of chocolate chip ice cream D. A solid sphere

Answers

Solid sphere is the correct answer.

Answer:

D) A Solid Sphere

Explanation:

As per Dalton's atomic description he said that atom is not divisible and that is the smallest part of atom.

It has no net charge and it can not be divided further. So till Dalton's theory of atom electron and nucleons were not discovered.

So we can consider atom as a model of Solid sphere  because similar to a solid sphere the atom is considered to be unique and not destructible.

So here correct answer will be

D) A Solid Sphere

The color of a substance is a physical property. Please select the best answer from the choices provided T F

Answers

True. Bc a physical property is the appearance. A chemical property is like flammability. Hope this helps!

Answer:

True

Explanation:

Color is the splitting of light into different spectra. Light, by nature, is monochromatic. This means that it has one wave length. The prism experiment has proved that light has many colors. About 7 colors have been discovered.

The colors simply denote the different wavelengths of the "monochromatic" light. The colors are the different wavelengths of light when it is split.

The eye, sees color as a reflection. In the electron sense, color is as a result o electrons being "excited" or promoted from a lower orbital to a higher energy orbital.

whats the standard unit for measuring mass

Answers

Kilograms


The kilogram is the SI base unit of mass and is equal to the mass of the international prototype of the kilogram, a platinum-iridium standard that is kept at the International Bureau of Weights and Measures (BIPM)

Hope this helps!
The standard unit for measuring mass is kilograms.

Kat is creating a model to show how plate movements are linked to the formation of new rocks, and she is trying to place the steps in the correct order. Which step comes first?


The tectonic plates move apart from one another

Lava flows onto Earth's surface


magma forms beneath the plates and rises up through the cracks


Lava cools and hardens to form igneous rock

Answers

1. Tectonic plates move
2. Magma forms and rises through the cracks
3. Lava flows onto the Earth’s surface
4. Lava cools and hardens to form igneous rock

Igneous Rocks are rocks that are made from magma (molten lava). The correct order of the Igneous Rock formation is ACBD.

Igneous Rock:

These are the rocks made from magma (molten lava). The magma form in the upper mantle and lower crust because of very high temperature.

These rocks form,

Movement of a tectonic plate.The magma inside the crust rises from the cracks.Lava flows on the surface of the earth.When lava cools and crystallizes, it forms igneous rocks.

Therefore, the correct order of the Igneous Rock formation is ACBD.

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Which of these types of rock form near earths surface? Select all that apply.

A. Igneous

B. Sedimentary

C. Metamorphic

Answers

A. Igneous

Extrusive igneous rocks cool and solidify quicker than intrusive igneous rocks. They are formed by the cooling of molten magma on the earth's surface.

Sedimentary (sed-uh-MEN-tuh-ree) rocks, unlike the other two kinds of rocks, are formed on or near Earth's surface. They form from sediments eroded from other rocks. The sediments may come from igneous, metamorphic, or other sedimentary rocks.



Jonas sees this symbol in a circuit diagram.


Which circuit component does the symbol represent?

A) resistor
B) bulb
C) battery
D) voltmeter

Answers

The circuit component the symbol represents is: C) Battery

Explanation :

An electric circuit is a closed network consisting of an electrical component. It consists of a resistor, a battery, an ammeter, a voltmeter etc.

A symbol is given to every component.

The given symbol shows a battery. It consists of more than one cell and used as a power source in a circuit. It has two terminals i.e a positive terminal and a negative terminal.          

The positive terminal of a battery is a cathode and a negative terminal is an anode.    

Hence, the correct option is (C) " battery ".

What are two examples of common units for each of the above measurements

Answers

Density: g/mL, kg/cubic meter  

Volume: L, teaspoon  

Mass: g, MeV/sq. C

Final answer:

The common units for length, weight, and time in the American system are foot, pound, and second, respectively. In the metric system, the common units for length, weight, and time are meter, kilogram, and second, respectively.

Explanation:

In the American system of measurement, the common units for length, weight, and time are foot, pound, and second, respectively. For example, the ton (2240 lb) is a larger unit of weight, the yard (3 ft) is a smaller unit of length, and the minute (60 s) is a smaller unit of time.

In the metric system, the common units for length, weight, and time are meter, kilogram, and second, respectively. For example, the kilometer (1000 m) is a larger unit of length, the gram (0.001 kg) is a smaller unit of weight, and the millisecond (0.001 s) is a smaller unit of time.

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When the amount of water in a river increases so much that the river overflows its channel, a flood occurs.True or false

Answers

That's true, and there are also other mechanisms that can also create floods.

When sugar is burned, water vapor and carbon dioxide are produced. A sugar molecule has a specific number of carbon, hydrogen, and oxygen atoms. Use the balanced chemical equation to identify the number of carbon, hydrogen, and oxygen atoms in sugar. Sugar + 12O2 ? 11H2O + 12CO2

Answers

Answer:

Number of carbon, hydrogen, and oxygen atoms in sugar:

C: 12H: 22O: 11

Explanation:

1) Given balanced chemical equation:

Sugar(s) + 12O₂(g) →  11H₂O(g) + 12CO₂(g)

2) Mass conservation law: in a chemical reaction, the atoms are not created nor destroyed; they recombine to form new substances, so the number of atoms of each kind in the reactants is equal to the number of atoms of the same kind in the products.


3) Balance.

-----------------------------------------------------------------------------------------------------

Atom          Products                    =            Reactants

-----------------------------------------------------------------------------------------------------

C                12CO₂ ⇒ 12               =             12 in sugar

-----------------------------------------------------------------------------------------------------

H               11H₂O ⇒ 11 × 2 = 22   =             22 in sugar

-----------------------------------------------------------------------------------------------------

O               12CO₂ ⇒ 12 × 2 = 24                12 × 2 = 24 in O₂ + x in sugar

                  11H₂O ⇒ 11

                 -----------------------------       --------------------------------------------------

                  24 + 11 = 35                =         24 + x

----------------------------------------------------------------------------------------------------

         

Solve for x: 35 = 24 + x ⇒  x = 35 - 24 = 11 ∴ 11 O atoms in sugar


Conclusion:

Number of carbon, hydrogen, and oxygen atoms in sugar:

C: 12H: 22O: 11

amber applies a net force of 35 N to pull her younger brother (32 kg) in a wagon (3 kg). at what rate does the wagon accerlerate

A. 1.09 m/s2
B. 0.91 m/s2
C. 1.00 m/s2
D. It doesn’t accelerate because force and mass are equal

Answers

Answer:

C. 1.00 m/s^2

Explanation:

We can solve the problem by using Newton's second law:

[tex]F=ma[/tex]

where

F is the net force acting on an object

m is the mass of the object

a is its acceleration

In this case, the net force applied by Amber is F=35 N, while the total mass of the brother+the wagon is

[tex]m=32 kg+3 kg=35 kg[/tex]

Therefore, we can re-arrange the previous equation to find the acceleration:

[tex]a=\frac{F}{m}=\frac{35 N}{35 kg}=1.00 m/s^2[/tex]

According to a simplified model of a mammalian heart, at each pulse approximately 20 g of blood is accelerated from 0.20 m/s to 0.32 m/s during a period of 0.08 s . What is the magnitude of the force exerted by the heart muscle?

Answers

Answer:

    Magnitude of the force exerted by the heart muscle  = 0.03 N

Explanation:

  We have force = mass * acceleration

   Acceleration = Rate of change of velocity = Change in velocity/time = (0.32-0.20)/0.08

                          = 0.12/0.08 = 12/8 = 1.5 [tex]m/s^2[/tex]

   Mass of blood = 20 g = 20/1000 kg = 0.02 kg

   Magnitude of the force exerted by heart muscle = 0.02*1.5 = 0.03 N

The magnitude of the force exerted by the heart muscle is 0.03 N.

From Newton's second law, we know that F = ma

Where;

F = force

m = mass of the body

a = acceleration

Now we must find the acceleration from:

a = v - u/t

a = acceleration

v = final velocity

u = initial veocity

t = time taken

Substituting values;

a = 0.32 m/s -  0.20 m/s/ 0.08 s

a = 1.5 m/s^2

Since F = ma

But m was given in grams and we must convert to kilograms so m = 0.002 Kg

Therefore;

F = 0.002 Kg × 1.5 m/s^2

F = 0.03 N

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Which is a correct reason to physically connect objects with a bond wire when transferring flammable liquids? A. To create a pathway for the liquid to flow easily B. To eliminate a difference in the static charge potential C. To lessen the likelihood of a spill

Answers

When Transferring Flammable Liquids - Option A

To create a pathway for the liquid to flow easily is a correct reason to physically connect objects with a bond wire when transferring flammable liquids. Physically connect the two conductive objects together with a bond wire to eliminate a difference in static charge potential among them. The bond wire is attached between the containers in the process of flammable filling liquid actions except for a metallic path is found.


Answer

Correct Option is A

Explanation:

Correct Option is A that is to create a pathway for the liquid to flow easily

Option B

This option is not correct because objects are not conductive.  

Option C

This option is also not correct because better options are there to lessen the spill

Hope this answer will help you


Identify two factors that determine the intensity of sound

Answers

Amplitude and distance.

What are the two possible solutions to 5x^2−15=0?

Answers

I have attached the solution as image.

Final Answer:

The two possible solutions of [tex]5x^{2} - 5 = 0[/tex] are [tex]\( x = \pm \sqrt{3} \)[/tex].

Explanation:

To find the solutions to the quadratic equation [tex]\(5x^2 - 15 = 0\)[/tex], we first add 15 to both sides to isolate the term involving [tex]\(x^2\)[/tex], yielding [tex]\(5x^2 = 15\)[/tex]. Then, we divide both sides by 5 to solve for [tex]\(x^2\)[/tex], giving us [tex]\(x^2 = 3\)[/tex]. Taking the square root of both sides, we obtain [tex]\(x = \pm \sqrt{3}\)[/tex]. Therefore, the two possible solutions are [tex]\(x = \sqrt{3}\)[/tex] and [tex]\(x = -\sqrt{3}\)[/tex]. These solutions represent the values of x for which the equation is true.

Which is defined as a disturbance in matter that carries energy from one place to another?

Answers

an acoustic wave carries energy

A mechanical wave----

which surface winds blow between the subtropical high and the equator

A) trade winds

B) polar easterlies

C) sea breezes

D) westerlies

Answers

Answer:

trade winds

Explanation:

In tropics regions on the lower portion of earth's atmosphere the surface winds are observed in prevailing pattern. In northern hemisphere the trade wind predominantly blows from north east. In southern hemisphere it flows from south east. Subtropical high and the equator is in between these areas.

Thus, trade wind blow between the subtropical high and the equator.


Answer:

trade winds

Explanation:

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