A species of catfish, can generate up to 350 voltsWrite an inequality to represent the amount of electricity generated by the catfish

Answers

Answer 1
catfish≤350 because the catfish cannot generate more than 350 volts.
Answer 2

The inequality to represent the amount of electricity generated by the catfish, which can generate up to 350 volts, is:  [tex]\[ 0 \leq E \leq 350 \][/tex] where [tex]\( E[/tex]  represents the amount of electricity in volts.

This inequality indicates that the electricity generated by the catfish is at least 0 volts and at most 350 volts. The lower bound of 0 volts is included because the catfish cannot generate negative voltage, and the upper bound of 350 volts is the maximum it can generate.


Related Questions

How was his payment

Answers

Subtract off the down payment: 880 - 250 = 630

So he'll pay 630 over 8 equal payments
Divide: 630/8 = 78.75

His monthly payment is $78.75

The length of a rectangle is stored in a double variable named length, the width in one named width. write an expression whose value is the length of the diagonal of the rectangle. submit

Answers

sqrt(pow(length, 2) + pow(width, 2))

Three times the number of blue marbles exceeds twice the number of red marbles by 18 also five times the number blue marbles is two less than six times number of red marbles how many of each are there

Answers

Let
x----------> number of blue marbles
y----------> number of red marbles
we know that
3x=2y+18----------> y=(3x-18)/2------> equation 1
and
5x=6y-2-----------> y=(5x+2)/6----------> equation 2
(1)=(2)
(3x-18)/2=(5x+2)/6----> 3*(3x-18)=5x+2
9x-54=5x+2
9x-5x=2+54-------> 4x=56---------> x=14
y=(3x-18)/2-------> y=(3*14-18)/2=24/2-------> y=12

the answer is
14 blue marbles
12 red marbles

The average monthly amount Isabella has spent on gasoline since 1990 is shown in the table. Use the data in the table to complete the statements. Let x be the number of years since 1990. The year 2005 corresponds to an x-value of . The function that best models the data, with numerical values rounded to the nearest hundredth, is f(x) = x + 22.08. Models have their limitations. For which year would this model not make sense to use?

Answers

Answer 1: 15
Answer 2: 11.55
Answer 3: 1985

A company's advertising budget is split between newspaper ads, magazine ads, television ads, and Internet ads. The company spends the same amount of money on newspaper and magazine ads. It spends 4 times the amount of money on television ads as it does on newspaper ads. It spends 2 times the amount of money on Internet ads as newspaper ads. If the budget is $22,000, how much money is spent on magazine ads?

Answers

The spent 2,750 on the magazine adds.

2,750+2750=(2750x4)+(2750x2)=22,000

Answer:

2,750+2750=

2750 x 4+2750 x 2=

22,000

Step-by-step explanation:

Look at the picture below // 99 points // PLEASEE HELPP

Answers

Your answer is D.
The polygon won't change shape or size, just its position.
D is the answer, because it will only move to the right and down but not change its shape at all.

Please mark Brainliest!

-Belle

describe the transformation of the following function y=tan(2x-pi)

Answers

[tex]\bf ~~~~~~~~~~~~\textit{function transformations} \\\\\\ f(x)=Asin(Bx+C)+D \\\\ f(x)=Acos(Bx+C)+D\\\\ f(x)=Atan(Bx+C)+D \\\\ -------------------\\\\ \bullet \textit{ stretches or shrinks}\\ ~~~~~~\textit{horizontally by amplitude } |A|\cdot B\\\\ \bullet \textit{ flips it upside-down if }A\textit{ is negative}\\ ~~~~~~\textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }B\textit{ is negative}\\ ~~~~~~\textit{reflection over the y-axis}[/tex]

[tex]\bf \bullet \textit{ horizontal shift by }\frac{C}{B}\\ ~~~~~~if\ \frac{C}{B}\textit{ is negative, to the right}\\\\ ~~~~~~if\ \frac{C}{B}\textit{ is positive, to the left}\\\\ \bullet \textit{vertical shift by }D\\ ~~~~~~if\ D\textit{ is negative, downwards}\\\\ ~~~~~~if\ D\textit{ is positive, upwards}\\\\ \bullet \textit{function period or frequency}\\ ~~~~~~\frac{2\pi }{B}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\ ~~~~~~\frac{\pi }{B}\ for\ tan(\theta),\ cot(\theta)[/tex]

with that template in mind, let's check this one,

[tex]\bf y=tan(\stackrel{B}{2}x\stackrel{C}{-\pi })\\\\ -------------------------------\\\\ \textit{horizontal shift of }\cfrac{C}{B}\implies \cfrac{-\pi }{2},\textit{ so of }\frac{\pi }{2}\textit{ to the right} \\\\\\ \textit{horizontal shrinkage of }B\implies 2, \textit{so by }\frac{1}{2}[/tex]

the solutions to the inequality y>-3x+2 are shaded on the grap.which point is a solution?

Answers

You are lacking the choices, but any point that you plot that falls in that shaded region would work just fine. 

Solve and show steps. will award brainliest.

Answers

For the first question please find the attached diagram.

As per the diagram, P is the upstream point and Q is the downstream point. The distance between P and Q is 22.5 miles.

Let the speed of the boat in the still waters of the lake be represented by S.

Then, when the boat travels upstream, the net speed of the boat will be (S-6) miles per hour because the river flows downstream and thus the speed of the boat will have to be subtracted from the speed of the river.

Now, we know that the relationship between the net speed, distance and time of travel is give as:

Distance = Net Speed x Time of travel

For the upstream ride of the board we know that Distance is 22.5 miles and Net Speed is (S-6). Therefore, the above equation will become:

[tex] 22.5=(S-6)\times T_{1} [/tex] where [tex] T_{1} [/tex] represents the time taken to travel upstream.

We can rearrange the above equation to be:

[tex] T_{1}=\frac{22.5 }{S-6} [/tex]......................(Equation 1)

By similar arguments we know that the downstream speed of the boat is S+6 and the distance travelled is the same and so the time taken to travel downstream (represented by [tex] T_{2} [/tex]) will be:

[tex] T_{2}=\frac{22.5}{S+6} [/tex]................(Equation 2)

Now, we know that the total time of travel should be 9 hours.

This means that: [tex] T_{1}+T_{2}=9 [/tex]............(Equation 3)

Plugging in the values of [tex] T_{1} [/tex] and [tex] T_{2} [/tex] from (Equation 1) and (Equation 2) into (Equation 3), we get:

[tex] \frac{22.5 }{S-6} +\frac{22.5 }{S+6}=9 [/tex]

Simplifying the above we will get a quadratic equation:

[tex] 9S^2-45S-54=0 [/tex]

The roots of this quadratic equation are:

[tex] S=-1 [/tex] and [tex] S=6 [/tex]

Since, speed cannot be negative, [tex] S=-1 [/tex] is out of consideration.

The speed of the boat in the lake is thus [tex] S=6 [/tex] miles per hour.

But we have a problem with S=6 too. The problem is that if S=6, then the boat will not be able to move upstream.

Let us solve problem 2

We are given that: [tex] \frac{x-2}{x+3}+\frac{10x}{x^2-9} [/tex]

We can rewrite it as:

[tex] \frac{x-2}{x+3}+\frac{10x}{(x-3)(x+3)} [/tex]

[tex] \frac{(x-3)(x-2)+10x}{(x-3)(x+3)} =\frac{x^2-5x+6+10x}{(x-3)(x+3)} [/tex]

Now, the numerator can be simplified as:

[tex] \frac{x^2+10x+6}{(x-3)(x+3)} =\frac{(x+3)(x+2)}{(x-3)(x+3)} =\frac{x+2}{x-3} [/tex]

Thus, our final simplified answer is:

[tex] \frac{x+2}{x-3} [/tex]

The restriction on the variable x is that it cannot be equal to either +3 or -3 as that would make the denominator of the original question equal to zero.

Thus, the restriction is [tex] x\neq \pm 3 [/tex]

A land mass is roughly in the shape of a rectangle whose perimeter is 1180 miles. the width is 110 miles less than the length. find the length and the width?

Answers

Answer: length = 350 miles, widht = 240 miles

Explanation:

1) Shape: rectangle

2) dimensions:

length = l
width = w

3) Formula of the perimeter of a rectangle, p = 2 * l + 2 * w

4) Data:

p = 1180 miles

length = x

width = x - 110 miles

5) Equation: p = 2x + 2(x - 110)

2x + 2(x - 110) = 1180

2x + 2x - 220 = 1180

4x = 1180 + 220

4x = 1400

x = 1400 / 4

x = 350

=> length = 350

and width = 350 - 110 = 240

6) Verification:

p = 2*length + 2 * width

1180 = 2 * 350 + 2*240

1180 = 700 + 480

1180 = 1180 => check.

Answer: length = 350 miles, widht = 240 miles

The dimensions of a triangle are shown below. If the height of the triangle is increased by a factor of 4, which statement will be true about the area of the triangle?

Answers

The area of the triangle will increase by 4^2 . That is by a factor of 16.

Answer:

The area will increase by a factor of 4

Step-by-step explanation:

4 * 4 = 16

IT'S UP THERE STEVE (Like on family feud)

PLEASE HELP
Use the domain {½ , 1, 2, 4, 8} to plot the points on the graph for the given equation.
[tex]y=log_{2}x[/tex]

WILL MARK AS BRAINLIEST

Answers

Since the domain are the x-values of the function, we need to find the y-values using those x-values.
- for x=[tex] \frac{1}{2} [/tex], [tex]log x_{2} ( \frac{1}{2} )=-1[/tex]. Now we have our first ordered pair: [tex]( \frac{1}{2} ,-1)[/tex]
- for [tex]x=1[/tex], [tex]log_{2} (1)=0[/tex] which gives us our next ordered pair: [tex](1,0)[/tex]
- for x=2, [tex]log_{2} (2)=1[/tex], so (2,1)
- for x=4, [tex]log_{2} (4)=2[/tex], so (4,2)
- for x=8, [tex]log_{2} (8)=3[/tex], so our last order pair is (8,3)

Finally we can plug the points and joint them to create our graph:

Answer:

Warning the guy above is correct just make sure you count each line as 1,2,4,8. On the graph if you count the bold big lines for the domain you will run out of room for the last domain for 8. Like the person above did.

Step-by-step explanation:

Dylan works 30 hours a week. His hours are decreased by 20%. How many hours does he now work each week?

Answers

20% of 30 is 6. 30-6 is 24. He now works for 24 hours! Please mark brainliest!!!

Answer:

He now work 24 hours each week

Step-by-step explanation:

Dylan works 30 hours a week. His hours are decreased by 20%.

The number of work hours 30 is decreased by 20%

we need to find 20% of 30

[tex]30 \cdot \frac{20}{100} =6[/tex]

So number of hours should be decreased by 6

[tex]30-6= 24[/tex]

he now work 24 hours each week

The graph of the function g(x) is shown on the coordinate plane below. For what value of x does g(x)=0

Answers

where is the graph
:)
:)

Answer:

the answer is 6 on algebra nation

Step-by-step explanation:

if a and b are independent events then it must be true that P(A|B)=P(A) TRUE OR FALE

Answers

True.  
Because two events A and B are called independent if P(A|B)= P(A), i.e., if conditioning on one does not effect the probability of the other.

(20 points) Find AC, BC, m
Pleasee

Answers

Givens
====
DF = 8
FE = 2
======
Find BF 
By similar triangles 
FC/FE = DF/FC
FC^2 = 8*2
FC = sqrt(16)
FC = 4
Find AC

what is the sum of (5xy + x - 8) and (13x + 2)

Answers

5xy+x-8+13x+2=
Combine like terms
5xy+14x-6

if a sample of 21 runners were taken from a population of 580 runners, μ could refer to the mean of how many runners times?

Answers

21 because that's the only people that you have information on.

Answer:

the answers is 580

Adrien has 4 liters of milk. He drinks y liters each day. If Adrien has x liters of milk left after one week, express d in terms of y.

Answers

the correct question is
Adrien has 4 liters of milk. He drinks y liters each day. If Adrien has x liters of milk left after one week, express x in terms of y

we know that
y------------> liters of milk that Adrien drinks each day
x-----------> liters of milk left after one week
in one week
Adrien drinks 7y
and
x=4-7y

 the answer is 
x=4-7y

Ann buys a dress in a sale. The normal price of the dress is reduced by 20%. The normal price is £36.80. Work out the sale price!


Also explain how you calculated it ...

Answers

Hello!

Let's do this step by step!

#1

"Reducing" means to make something smaller, like a discount. So we are reducing the price of the dress by 20%. This means we must first find what 20% of the dress's price is and then subtract that from the price.

#2

36.80 * 20% = 7.36

So, 20% of 36.80 is 7.36. Subtract that: 

#3

36.80 - 7.36 = 29.44

Answer: 

The sale price of the dress is $29.44. 

Good day!

help:


quadrilateral ABCD is located at A(-2,2) B(-2,4) G(2,4) D(2,2). the quadrilateral is then transformed using the rule (x+2,y-3) to form the image A'B'C'D'. what are the new coordinates of of A'B'C'D'? describe what characteristics you would find if the corresponding vertices were connected with line segments.

Answers

The given rule is a translation to the right (2 steps) and down (3 steps).
In order to find the new coordinates, you need to take the given x and add 2 and the given y and subtract 3.
Therefore:
A' (-2+2 , 2-3) --> (0,-1)
B' (-2+2 , 4-3) --> (0,1)
C' (2+2 , 4-3) --> (4,1)
D' (2+2, 2-3) --> (4,-1)

Since the quadrilaterals ABCD and A'B'C'D' are rectangles, connecting the corresponding vertices would give you a parallelepiped, which means that AA', BB', CC', DD' are parallel and congruent segments. 

Which equation is y = –6x2 + 3x + 2 rewritten in vertex form?

Answers

y = -6x^2 + 3x + 2
y = -6(x^2 - 0.5x) + 2
y = -6[ (x - 0.25)^2 - 0.0625] + 2
y =  -6(x - 0.25)^2 + 2.375  Answer

Answer:

c

Step-by-step explanation:

Please guys help me with this question!

Answers

i belive that it is b. 32%

Write the polynomial −11x^3 − 2 − 9x^5 − 4x^2 − 6x^4 − 14x in standard form. Then give the leading coefficient. HELP ASAP! 

Answers

to write it in standard form, you line up the terms from the highest degree (exponent) to the lowerest
− 9x^5− 6x^4 −11x^3− 4x^2− 14x − 2
the leading coefficient refers to the coefficient of the highest degree, which is -9 in this case. 
Lets get started :)

Writing a polynomial is standard form means arranging them accordingly, in descending power form:

-11x³ - 2 - 9x⁵ - 4x² - 6x⁴ - 14x

The highest power is 5, now we should arrange in decreasing manner
-9x⁵ - 6x⁴ - 11x³ - 4x² - 14x - 2

The leading coefficient is -9

Using the fafsa, you can apply for

Answers

Not a math question but,

FAFSA stands for Free Application for Federal Student Aid. it is used to apply for student loans, grants, and scholarships sometimes.

 if xy=c^2, prove that x^2 dx/dy+c^2=0

Answers

Hello,

xy=c²==>y=c²/x
==>y'=dy/dx=-c²/x²==>x² dy/dx+c²=0 (there is a mistake)

find the circumferences

Answers

check the picture below.

so... notice, the larger green circle, has a radius of 22.

now, the blue smaller circle, is taking up half of the diameter of the green one, so, the diameter for the small one is 22, and its radius is half that, or 11.

[tex]\bf \textit{circumference of a circle}\\\\ C=2\pi r\\\\ -------------------------------\\\\ \stackrel{\textit{large green circle}}{C=2\cdot \pi \cdot 22}\implies C=44\pi \qquad\qquad \qquad \stackrel{\textit{small blue circle}}{C=2\cdot \pi \cdot 11}\implies C=22\pi [/tex]

helppppppppppppppppppppppppp

Answers

the allknowing wanser is c

We evaluate the function at a known point.
 We have that for x = 0
 y = sin (x + 90)
 y = sin (0 + 90)
 y = sen (90)
 y = 1
 Then, the function sought will be:
 y = sin (x + 90)
 Answer:
 y = sin (x + 90)
 option A

I will go to the mall if and only if I get paid today.

Determine the conditions that will make the biconditional true.

A. It is true if I go to the mall and I get paid. It is true if I go to the mall and I don’t get paid.
B. It is true if I go to the mall and I get paid. It is true if I don’t go to the mall and I don’t get paid.
C. It is true if I go to the mall and I don’t get paid. It is true if I don’t go to the mall and I don’t get paid.
D. It is true if I go to the mall and I get paid. It is true if I don’t go to the mall and I get paid.

Answers

I would say it would be  B.

Final answer:

The correct answer is Option B, covering both true-true and false-false scenarios.

Explanation:

To determine the conditions that make the biconditional statement true, let's analyze it step by step. The statement in question is: "I will go to the mall if and only if I get paid today." A biconditional statement is true in two scenarios: both parts are true or both parts are false.

Looking at the options provided:

Option A is incorrect because if the statement is true, I cannot go to the mall without getting paid.Option B is correct because it encompasses both scenarios where the biconditional statement holds true: If I go to the mall, then I must have gotten paid, and if I don’t go to the mall, then I must not have gotten paid.Option C is incorrect because according to the biconditional, I cannot go to the mall unless I have been paid.Option D is incorrect because if I don’t go to the mall, it must mean that I didn't get paid, which is not covered in this option.

Therefore, the correct answer is Option B: It is true if I go to the mall and I get paid today. It is also true if I don't go to the mall and I don't get paid today. This matches the requirements of a biconditional statement where either both conditions are true or both are false.

30 POINTS + BRAINLIEST.. PLEASE CHECK MY ANSWER

Answers

You are correct.
Good job!

Answer:

you are correct good job

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