Binary ionic compounds are: Check all that apply.
A.Compounds with very different electronegativities
B.Made from two metals
C.Compounds that share electrons
D.Metals and nonmetal ions
Compounds with very different electronegativities AND metals and non metals.
Assume the second cart moves in the negative direction. two carts with masses of 4.6 kg and 3.3 kg move toward each other on a frictionless track with speeds of 5.1 m/s and 4.9 m/s, respectively. the carts stick together after colliding head-on. find their final speed. answer in units of m/s.
A weightlifter raises a 200-kg barbell through a height of 2 m in 2.2 s. the average power he develops during the lift is
Answer:
Power, P = 1781.81 watts
Explanation:
It is given that,
Mass of the barbell, m = 200 kg
It is lifted to a height of, h = 2 m
Time taken, t = 2.2 s
We need to find the develops during the lift. We know that the pwer developed by an object is equal to the rate of doing work. Mathematically, it is given by :
[tex]P=\dfrac{W}{t}[/tex]
[tex]P=\dfrac{mgh}{t}[/tex]
[tex]P=\dfrac{200\times 9.8\times 2}{2.2}[/tex]
P = 1781.81 watts
So, the average power developed during the lift is 1781.81 watts. Hence, this is the required solution.
How far away from the sun would a planet mercury's size have to be before it would have an atmosphere?
A transverse wave on a rope is given by y(x,t)= (0.750cm)cos(π[(0.400cm−1)x+(250s−1)t]). part a part complete find the amplitude.
The amplitude of the given transverse wave in the rope is [tex]\boxed{0.750\,{\text{cm}}}[/tex].
Further Explanation:
The given expression of the wave developed in the rope is.
[tex]y\left( {x,t} \right) = \left( {0.750\,{\text{cm}}} \right)\cos \left( {\pi \left[ {\left( {0.400\,{\text{cm}} - {\text{1}}} \right)x + \left( {250\,{\text{s}} - 1} \right)t} \right]} \right)[/tex]
The standard equation of the wave produced in a rope is given as.
[tex]\boxed{y\left( {x,t} \right) = A\cos \left( {kx + \omega t} \right)}[/tex]
Here, [tex]y[/tex] is the position of the wave, [tex]A[/tex] is the amplitude of the wave, [tex]k[/tex] is the wave number and [tex]\omega[/tex] is the angular frequency of the wave.
On comparing the above equation of the wave with the standard equation of the wave produced in a rope, the amplitude of the wave can be obtained as follows.
[tex]A = 0.750\,{\text{cm}}[/tex]
Thus, the amplitude of the given transverse wave in the rope is [tex]\boxed{0.750\,{\text{cm}}}[/tex].
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Answer Details:
Grade: High School
Chapter: Waves
Subject: Physics
Keywords: Transverse, wave, amplitude, angular frequency, stationary wave, rope, velocity, position, wave number.
A bullet is fired at a speed of 2434 ft/s. what is this speed expressed in millimeters per minute?
HELP!! Physical or chemical property? For the questions..
______________ is a measure of the force of gravity pulling on an object of a given mass.
As a moon follows its orbit around a planet, the maximum grav- itational force exerted on the moon by the planet exceeds the minimum gravitational force by 11%. find the ratio rmax/rmin, where rmax is the moon's maximum distance from the center of the planet and rmin is the minimum distance.
Which arrow best represents the path of an object with projectile motion?
Answer:
C
Explanation:
Projectiles follow a parabolic path and I got it right on the quiz
Answer:
C
Explanation:
What is the average speed of a human that runs a distance of 5 miles in 1 hour?
Which of the following would most likely happen if water did not form hydrogen bonds? (2 points)
Answer:
Water would not expand when it freezes
Explanation:
At the end of a factory production line, boxes start from rest and slide down a 30 ∘ ramp 5.8 m long. part a if the slide is to take no more than 3.9 s , what's the maximum allowed frictional coefficient
Calculate the kinetic energy of an 86-kg scooter moving at 16 m/s
The kinetic energy of an 86 - kilogram scooter moving at 16 m / s would be 11008 Joules.
What is mechanical energy?Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.
As given in the problem, we have to calculate the kinetic energy of an 86 - kilogram scooter moving at 16 m / s ,
The mass of the scooter = 86 kilogram
The velocity fo the scooter = 16 meters per second
The kinetic energy of the scooter = 0.5 × m × v²
= 0.5 × 86 × 16²
= 11008 Joules
Thus , the kinetic energy of an 86 - kilogram scooter moving at 16 m / s would be 11008 Joules .
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The kinetic energy of an 86-kg scooter moving at 16 m/s is calculated using the formula KE = ½ mv², resulting in 10,976 Joules or 10.976 kJ of kinetic energy.
To calculate the kinetic energy of an 86-kg scooter moving at 16 m/s, you can use the kinetic energy formula KE = ½ mv², where m is mass and v is velocity. Substituting the given values, we get KE = ½ (86 kg) (16 m/s)². After performing the calculation, the kinetic energy of the scooter is found to be 10,976 Joules or 10.976 kJ.
Animals, including humans, need shelter, food, water, air, and space in order to survive. How do animals satisfy their basic needs?
if you come from study island then its all of them
Food, shelter and clothes are basic need of the humans. Animals like tiger hunt the animals in the jungle, some animals leaves on green grass which are abundantly present in the jungle. for shelter they live in the group at suitable place.
What is Animal ?Animals belong to the biological kingdom Animalia and are multicellular, eukaryotic creatures. Animals generally ingest organic matter, breathe oxygen, can reproduce sexually, and form from a hollow ball of cells called a blastula during early development. There are an estimated 7.77 million animal species in existence as of 2022, but only 2.16 million of them have been described, including 1.05 million insects, over 36,000 fish, over 11,700 reptiles, over 11,100 birds, and 6,596 mammals. Animals can be as little as 8.5 micrometres (0.00033 in) or as large as 33.6 metres (110 ft). They construct extensive food webs through their complex interactions with one another and their surroundings. Zoology is the study of animals from a scientific perspective.
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every 24 hours, about how many hours are spent socializing and watching tv?
Answer:
16+ hours
Explanation:
because they have a job and jobs are long so they would take as much time as they can get
Describe the image of an object that is 38 cm from a concave mirror that has a focal length of 10 cm.
A concave mirror with a focal length of 10 cm will form a virtual, upright image that is 11.43 cm away from the mirror. The magnification of the image will be -0.301.
Explanation:A concave mirror with a focal length of 10 cm will form an image of an object that is 38 cm away. To determine the characteristics of the image, we can use the mirror equation: 1/f = 1/di + 1/do, where f is the focal length, di is the image distance, and do is the object distance. Rearranging the equation, we get di = 1 / (1/f - 1/do). Plugging in the given values, di = 1 / (1/10 - 1/38) = 11.43 cm.
The negative sign indicates that the image is virtual and upright. Furthermore, to determine the magnification of the image, we can use the formula: magnification = -di / do. Plugging in the values, magnification = -11.43 / 38 = -0.301.
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A 92-kg astronaut and a 2000-kg satellite are at rest relative to a space station. the astronaut pushes on the satellite, giving it a speed of 0.14 m/s directly away from the station. seven and a half seconds later the astronaut comes into contact with the station. part a what was the initial distance from the station to the astronaut?
Answer:
22.8 s
Explanation:
First we calculate the change in momentum of the satellite.
ΔP = 2000 kg (0.14 m/s 0 m/s) = 280 kg·m/s
The change in momentum of the satellite is equal to the change in momentum of the astronaut as a result of Newton's Third law. Therefore:
280 kg·m/s = 92kg * v
v = 3.04 m/s
d = speed * time = 3.04 m/s * 7.5 s = 22.8 m
ball A has a mass of 5.0 kg. ball B has twice the mass of ball A. The Two balls collide and stick together in a perfectly inelastic collision. after the collision the combined balls are at rest. if the velocity of ball A before the collision was 13 m/s, what was the velocity of ball B before the collision?
A. 6.5
B. -6.5 m/s
C. 26 m/s
D. -13 m/s
E. 0.0 m/s
Using the conservation of momentum principle, the initial velocity of ball B before the collision is calculated to be -6.5 m/s given that the collision is perfectly inelastic and both balls come to rest after they stick together.
The problem describes a perfectly inelastic collision situation where ball A, with a mass of 5.0 kg and an initial velocity of 13 m/s, collides with ball B, which has twice the mass of ball A, and they stick together and come to rest. To find the initial velocity of ball B before the collision, we can use the conservation of momentum principle. The total momentum before the collision must equal the total momentum after the collision.
Let's denote the mass of ball A as mA and the mass of ball B as mB. The initial velocity of ball A is vA1 = 13 m/s, and let's denote the initial velocity of ball B as vB1. The mass of ball B is twice that of ball A, so mB = 2mA. Since the balls are at rest after the collision, their combined momentum is zero.
The momentum conservation equation can be written as:
mAvA1 + mBvB1 = 0
Substituting the given values and solving for vB1 we get:
(5.0 kg)(13 m/s) + (2 × 5.0 kg)vB1 = 0
65 kg×m/s + 10.0 kgvB1 = 0
vB1 = -(65 kg×m/s) / (10.0 kg)
vB1 = -6.5 m/s
Therefore, the initial velocity of ball B before the collision was -6.5 m/s, which corresponds to option B.
Sam boards a ski lift, and rides up the mountain at 6 miles per hour. once at the top, sam immediately begins skiing down the mountain, averaging 54 miles per hour, and does not stop until reaching the entrance to the lift. the whole trip, up and down, takes 40 minutes. assuming the trips up and down cover the same distance, how many miles long is the trip down the
A body 'A' of mass 1.5kg travelling along the positive X-axis with speed of 4.5m/s collides with another body 'B' of mass 3.2kg, which initially is at rest as a result of the collision, 'A' is deflected and moves in a speed of 2.1m/s in a direction which is at an angle of 30 degree below the X-axis. 'B' is set in motion at an angle Φ above the X-axis. calculate the velocity of 'B' after the collision.
Which ions are most abundant in an acid?
The hydrogen ion is the most abundant in an acid for it is a bare proton that associates with any water in the molecule, solution or reaction so the H+ ions produced by an acid exist as H3O+ ions.
Moreover, in the Arrhenius theory, an acid is a substance that dissociates to produce H+ ions in solution and a base as a substance that dissociates to produce OH- ions in solution. Meanwhile, in the Bronsted-Lowery theory, an acid is considered as a proton donor.
A uniform bridge 20.0m long and weighing 4.00 x 10^5 N is supported by two pillars located 3.00m from each end. If a 1.96 x 10 ^4N car is parked 8.00m from one end of the bridge. How much force does each pillar exert?
The left support exerts a force of 2.0392 x 10⁵ N and the right support exerts a force of 2.1568 x 10⁵ N on the bridge. This is calculated by considering the total weight supported by the bridge and the location of the car.
Explanation:The problem you are asking about relates to static equilibrium, a concept in Physics. To find the force exerted by each pillar, we must first find the total weight supported by the bridge. The total weight is the sum of the weight of the bridge itself (4.00 x 10⁵ N) and the weight of the car (1.96 x 10^4 N), which gives us a total of 4.196 x 10⁵ N.
The location of the car changes the balance of these forces. The first pillar is 8m from the car and the second pillar is 12m from the car. To find the force on each pillar, we apply the principle that the sum of the moments about any point in a system in equilibrium is zero. Using the left pillar as the point, the moments of the bridge's weight and the car's weight are counterbalanced by the force of the right pillar:
Force_right_pillar = (Bridge_weight * Bridge_mid_point + Car_weight * Distance_from_left_pillar) / Total_bridge_length = ((4.00 x 10⁵ N * 10m) + (1.96 x 10⁴ N * 8m)) / 20m = 2.1568 x 10⁵ N.
The force exerted by the left pillar is then the total weight minus the force on the right pillar: Force_left_pillar = Total_weight - Force_right_pillar = 4.196 x 10⁵ N - 2.1568 x 10⁵ N = 2.0392 x 10⁵ N. So, the left support exerts a force of 2.0392 x 10⁵ N, and the right one exerts a force of 2.1568 x 10⁵ N.
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The forces exerted by the pillars supporting a 20.0m long and [tex]4.00 * 10^5 N[/tex] bridge with a [tex]1.96 * 10^4 N[/tex] car parked 8.00m from one end are approximately [tex]2.13 * 10^5 N[/tex] and [tex]2.07 * 10^5 N[/tex].
To find the forces exerted by each pillar on the uniform bridge, we need to consider the torque (moment of force) and the equilibrium conditions of the bridge.
Here is the step-by-step solution:
Given Data:
Length of the bridge (L) = 20.0 mWeight of the bridge [tex](W_{bridge}) = 4.00 * 10^5 N[/tex]Weight of the car [tex](W_{car}) = 1.96 * 10^4 N[/tex]Distance of each pillar from the end = 3.00 mPosition of the car from one end = 8.00 mThe two pillars provide upward forces labeled as [tex]F_L[/tex] and [tex]F_R[/tex].
1. Identify the distances to center of mass:
Center of mass of bridge from left end = 10.0 mPosition of car from left end = 8.0 m2. Set up equilibrium equations:
Since the bridge is in static equilibrium, the sum of the forces and the sum of the torques must be zero.
Sum of Vertical Forces:
[tex]F_L + F_R - W_{bridge} - W_{car} = 0\\F_L + F_R = 4.00 * 10^5 N + 1.96 * 10^4 N\\F_L + F_R = 4.196 * 10^5 N[/tex]
Sum of Torques about the left pillar (taking counterclockwise as positive):
[tex]-(W_{bridge} * 7.0 m) - (W_{car} * 5.0 m) + (F_R * 14.0 m) = 0\\-(4.00 * 10^5 N * 7.0 m) - (1.96 * 10^4 N * 5.0 m) + (F_R * 14.0 m) = 0\\-2.8 * 10^6 Nm - 9.8 * 10^4 Nm + 14 F_Rm = 0\\14 F_R = 2.898 **10^6 Nm\\F_R = 2.898 * 10^6 Nm / 14 m\\F_R = 2.07 * 10^5 N\\[/tex]
Substitute F_R back into the sum of the forces equation:
[tex]F_L + 2.07 * 10^5 N = 4.196 * 10^5 N\\F_L = 4.196 * 10^5 N - 2.07 * 10^5 N\\F_L = 2.126 * 10^5 N\\[/tex]
Result:
The forces exerted by the pillars are approximately:
[tex]F_L = 2.13 * 10^5 N\\F_R = 2.07 * 10^5 N[/tex]
You are given two carts, a and
b. they look identical and you are told that they are made of the same material. you place a at rest on an air track and give b a constant velocity directed to the right so that it collides elastically with
a. after the collision, both carts move to the right, the velocity of b being smaller than what it was before the collision. what do you conclude?
In the described collision, the momentum of cart B is partially transferred to cart A due to the conservation of momentum principle. Hence, cart A starts moving and cart B slows down but continues to move to the right.
Explanation:The scenario you described relates to the physics principle of conservation of momentum. In the collision of the carts, the total momentum before the collision equals the total momentum after the collision. This is because in an elastic collision, both kinetic energy and momentum are conserved. Initially, only cart B had momentum (since it was moving), and cart A was at rest. After the collision, both carts moved to the right, indicating that some of cart B's momentum was transferred to cart A. The fact that cart B moved slower after the collision indicates that it transferred some of its initial momentum to cart A. Hence, we can conclude that cart A gained momentum while cart B lost some but kept enough to continue moving to the right.
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A long, straight, vertical wire carries a current upward. due east of this wire, in what direction does the magnetic field point? a long, straight, vertical wire carries a current upward. due east of this wire, in what direction does the magnetic field point? upward west north south downward east
The magnetic field is due east of a long, straight, vertical wire carrying a current upward points downward.
Explanation:The magnetic field created by a long, straight, vertical wire carrying a current upward can be determined using the right-hand rule. According to the right-hand rule, if you point your right thumb in the direction of the current in the wire, your fingers will curl in the direction of the magnetic field.
Since the wire is carrying current upward, the magnetic field will point in the clockwise direction when viewed from above. Therefore, the magnetic field due east of the wire will point downward.
The 2779-m Brooklyn-Battery Tunnel, connecting Brooklyn and Manhattan, is one of the world's longest underwater vehicular tunnels. (a) Determine its fundamental frequency of vibration. (b) What harmonic must be excited so that it resonates in the audio region at 20 Hz or greater?
Because there is very little friction, the lever is an extremely efficient simple machine. using a 90.0% efficient lever, what input work is required to lift a(n) 19.0 kg mass through a distance of 45 cm? 3232 incorrect: your answer is incorrect. seenkey 93.2 j
Answer:
Input work: 93.2 J
Explanation:
The work efficiency formula is:
efficiency = output work/ input work
Solving for input work:
input work = output work/efficiency
The work required to lift an object is computed as follows:
Output work = mass * gravity * height
Using mass in kg, gravity in m/(s^2) and height in m; then work is expressed in Joules. Combining the equations and replacing with data, we get (units are omitted):
input work = 19*9.81*0.45/0.9 = 93.2 J
Note that 45 cm is equivalent to 0.45 m
Select the correct answer. What is tan for the given triangle? 0.60 1.67 1.33 5.00 0.20
Please help!! will mark brainiest and 60 pnts!!!
1) An items real value is
A) Equal to its price
B) Always greater than its perceived value
C) Equal to the cost of its production
D) An average of the price of competitor items
2) Bartering is an example of the exchange process at work.
A) True
B) False
3) The core of marketing is
A) Real value
B) Perceived value
C) Utility
D) Social media
4) Colligate football merchandise associated with colleges in the SEC (South Eastern Conference) are more popular in Alabama than in Oregon because of their
A) Time utility
B) Place utility
C) Form utility
D) Image utility
5) A consumer who is willing to pay more for a pre-assembled piece of furniture as opposed to a cheaper piece of furniture that has to be put together after purchase recognizes the item’s
A) Real value
B) Perceived value
C) Form utility
D) Possession utility
6) By marketing an item, sellers attempt to increase the real value of an item.
A) True
B) False
7) In modern-day society, the exchange process is primarily based on which of the following?
A) The bartering system
B) The honor system
C) The monetary system
D) The gold standard
8) All companies with a website use this online venue to directly sell their products to consumers.
A) True
B) False
9) In today’s society, some services and commodities can be successfully promoted via Internet marketing alone.
A) True
B) False
10) In marketing, an item’s utility refers to only how that product is used by the consumer.
A) True
B) False
1) C 2) A 3) C 4) B 5) C 6) A 7) C 8) A 9) A 10) B Is the answer
Which Of The Following Are Part Of The Ten Essentials List?
A. Extra Clothes And Rain Gear
B. Umbrella
C. Sunscreen And Hat
D. First Aid Kit
E. Water Purifier
F. Sleeping Pad
the are A,C,D that is answer the don't forget to see more answer