A stock solution of naoh is 0.800 m. what volume of this solution (in ml) is needed to prepare 2.00 l of 0.342 m naoh?

Answers

Answer 1
The  volume  of  the solution(in Ml)  needed  to  prepare 2.00 L  of 0.342 M  NaOH    is calculated using the below  formula

M1V1 =M2V2
M1=0.800 M
V1=?
M2=0.342  m
V2=  2.00  L

by  making  V1   the  subject  of the  formula = M2V2/M1

= 2.00 L x 0.342/ 0.800 =0.855  L  stock  solution  is neede



Related Questions

The concentration of the solid phase _____ the quantity present.

depends on
changes with the amount of
is equal to
always remains the same regardless of

Answers

The concentration of the solid phase always remains the same regardless of the quantity present. Most of the chemical reactions and separation systems involve the transport of more or one components in solid phase.
For example, in the process of solid catalyzed reactions, the result of solid phase transport might be negligible though it is hard to identify it in the rate of data in the analysis.

Answer: Option (b) is the correct answer.

Explanation:

A solution that contains more number of solute particles than the solvent particles is known as a concentrated solution.

For example, concentrated solution of sulfuric acid.

On the other hand, a solution that contains less number of solute particles than the solvent particles is known as a dilute solution.

For example, a dilute solution of HCl.

Hence, we can conclude that concentration of a substance changes with change in the amount of solute.

Therefore, the concentration of the solid phase changes with the amount of the quantity present.

A gas originally at 27 °c and 1.00 atm pressure in a 2.6 l flask is cooled at constant pressure until the temperature is 11 °c. the new volume of the gas is

Answers

Final answer:

According to Charles's law, the final volume of a gas that is cooled from 27 °c to 11 °c at constant pressure, and initially in a 2.6 L flask, is 2.46 L.

Explanation:

This question pertains to Charles's law, which states that the volume of a gas is directly proportional to its temperature if kept at a constant pressure. In this case, the initial temperature T₁ is 27°C (which converts to 300 K) and the final temperature T₂ is 11°C (or 284 K). The initial volume V₁ is 2.6 L. Remembering to convert degrees Celsius to Kelvin (by adding 273), we can solve for V₂, the unknown final volume, by setting up the equation V₁/T₁ = V₂/T₂.

Solving for V₂ yields V₂ = V₁ × (T₂/T₁) = 2.6 L × (284K/300K) = 2.46 L. So, if a gas originally at 27 °c and 1.00 atm pressure in a 2.6 L flask is cooled at constant pressure until the temperature is 11 °c, the new volume of the gas is 2.46 L.

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Mercury is a pollutant classified as

Answers

Mercury is classified as an heavy metal
Mercury is a pollutant classified as heavy metal.

Mercury is a planet it closest to the sun and the eighth largest.

Hope it helped you.

-Charlie

Which term best describes an electrical circuit?
Select one:
a. steady flow
b. quick burst
c. short-lived phenomenom
d. dangerous explosion

Answers

Out of all of these, the only one that will ever make sense is A: Steady Flow.
Final answer:

An electrical circuit is best described as a 'steady flow.' Electricity in a circuit flows continuously from the power source, through the device being powered, and back to the source.

Explanation:

The term that best describes an electrical circuit is steady flow. In a basic electrical circuit, electricity moves from a power source like a battery through conductive materials such as wires to the device that it's powering (like a light bulb), and then it returns to the source. This movement is a continuous or steady flow of electric charge, and it usually happens until the power source is depleted or the circuit is otherwise disrupted.

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For ethanol, propanol, and n-butanol the boiling points, surface tensions, and viscosities all increase. what is the reason for this increase?

Answers

Moving from Ethanol through Propanol to Butanol the physical properties like boiling points, surface tension and viscosity increases because of the increases in intermolecular interactions between the molecules of given compounds.

Explanation:
                   Ethanol, propanol and butanol all have hydroxyl groups in common, means all have hydrogen bond intractions between their molecules. So, taking the hydrogen bonding interaction constant we are left with only the difference in the number of carbon atoms.
                    Butanol has the greatest physical properties than other two because it has four carbon atom chain. So, as we know the London Dispersion forces or Van der Waal forces increases with increase in molecular size and chain length of hydrocarbon.
                    Therefore, the strength of London forces is greater in butanol than other two while ethanol has the smallest chain comparatively hence, lowest physical properties.  
Final answer:

The increase in boiling points, surface tensions, and viscosities for ethanol, propanol, and n-butanol is due to stronger hydrogen bonding and van der Waals dispersion forces as these molecules get larger and contain more electrons.

Explanation:

The boiling points, surface tensions, and viscosities of ethanol, propanol, and n-butanol increase due to the presence of hydrogen bonding and van der Waals dispersion forces. As the molecules get larger and have more electrons, the van der Waals forces increase. This causes the boiling points to rise because more energy is needed to overcome these intermolecular forces. The surface tension and viscosity also increase as the molecular size and intermolecular forces increase.

Moreover, the boiling point of an alcohol is significantly higher compared to the analogous alkane due to the presence of hydrogen bonding in addition to van der Waals forces and dipole-dipole interactions. Alcohols also exhibit a pattern where the boiling points increase with the number of carbon atoms, reflecting the increase in intermolecular attractions as the molecule size increases.

Boric acid frequently is used as an eyewash to treat eye infections. the ph of a 0.050m solution of borin acid is 5.28. what is the value of the boric acid ionization constant, ka

Answers

Based on  Henderson - Hasselbach equation, we have
pH = pka + log [tex] \frac{[Acid]}{\text{[conjugate base]}} [/tex]
Given: pH = 5.28 and [Acid] = 0.05 m,
∴ pKa = 5.28 - log (0.05) = 6.58
∴ Ka = 2.624 X [tex] 10^{-7} [/tex]

Thus, ionization constant of boric acid is 2.624 X [tex] 10^{-7} [/tex]

To find the ionization constant ([tex]K_a[/tex]) of boric acid from its pH of 5.28, calculate the hydrogen ion concentration [tex][H^+][/tex] using the pH, then apply the acid dissociation formula. The [tex]K_a[/tex] of boric acid is found to be 1.74 x [tex]10^{-9[/tex].

The pH of a 0.050 M solution of boric acid is 5.28, and the student is asked to calculate the ionization constant ([tex]K_a[/tex]) of boric acid.

To find [tex]K_a[/tex], we first need to calculate the concentration of hydrogen ions [tex][H^+][/tex] in the solution, which can be derived from the pH value:

pH = -log[tex][H^+][/tex]

5.28 = -log[tex][H^+][/tex]

[tex][H^+][/tex] = 10-5.28

Next, we use the acid dissociation formula for a weak acid like boric acid ([tex]H_3BO_3[/tex]):

[tex]H_3BO_3[/tex](aq) ⇌ [tex]H^+[/tex](aq) + [tex]B(OH)_4^-[/tex](aq)

Assuming the degree of ionization is small and equating the concentration of [tex]H^+[/tex] with that of [tex]B(OH)_4^-[/tex], we get:

[tex][H^+][/tex] = [tex][B(OH)_4^-][/tex]

Therefore:

Ka = [tex][H^+][/tex][tex][B(OH)_4^-][/tex] / [tex][H_3BO_3][/tex]

Ka = (10-5.28)2/0.050 M

Ka = 10-10.56/0.050

Ka = 1.74 x [tex]10^{-9[/tex]

So the Ka of boric acid is 1.74 x [tex]10^{-9[/tex].

Write a balanced equation for the double-replacement precipitation reaction described, using the smallest possible integer coefficients. a precipitate forms when aqueous solutions of chromium(iii) iodide and potassium hydroxide are combined.

Answers

[tex]CrI_{3}_{(aq)} + 3KOH_{(aq)} --\ \textgreater \ Cr(OH)_{3} _{(s)} +3KI_{(aq)}[/tex]

A chemistry student mixes 5 grams of sodium chloride (NaCl) in 100 ml of water and stirs until all of the salt is dissolved. Once dissolved, the student measures the electrical conductivity of the solution. An additional 5 grams of NaCl is then dissolved in the solution. Which statement MOST accurately describes how the additional five grams of salt will affect the electrical conductivity of the solution?

Answers

I think the best choice is
A) The conductivity of the solution will increase because more ions are being added to the solution. 
Because number ions will be increased, but big amount of NaCl can be still dissolved.

When additional 5 grams of NaCl are dissolved in solution the conductivity of solution increases as more ions are available for conduction.

What are ions?

An ion is defined as an atom or a molecule which has a net electrical charge. There are 2 types of ions :1) cation 2) anion . The cation is the positively charged ion and anion is the negatively charged ion . As they are oppositely charged they attract each resulting in the formation of ionic bond.

Ions consisting of single atom are mono-atomic ions while which consists of two or more ions are called as poly-atomic ions . They are created by chemical interactions . They are very reactive in their gaseous state and rapidly react with  the oppositely charged ions resulting in neutral molecules.

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The increase in the population of people living in urban areas will cause a decrease in urban sprawl.


Please select the best answer from the choices provided

T
F

Answers

This is false/ i know because i live in an urban area and it increases by human construction.

Answer: The given statement is false.

Explanation:

When there occurs unrestricted growth and development in number of urban areas for housing, commercial development, roads etc then it is known as urban sprawl.

Hence, when there will be more population in an urban area then there will be more urban sprawl because then there will be more demand for facilities.

Thus, we can conclude that the statement increase in the population of people living in urban areas will cause a decrease in urban sprawl, is false.

The solubility product constant of pbcl2 is 1.7 × 10−5 . what is the maximum concentration of pb2+ that can be in ocean water that contains 0.0500 m nacl?

Answers

Answer is: the maximum concentration of Pb²⁺ is 6.8·10⁻³ M.
Chemical reaction 1: PbCl₂(s) → Pb²⁺(aq) + 2Cl⁻(aq).
Chemical reaction 2: NaCl(aq) → Na⁺(aq) + Cl⁻(aq).
Ksp(PbCl₂) = 1.7·10⁻⁵.
c(NaCl) = c(Cl⁻) = 0.0500 M.
Ksp(PbCl₂) = c(Pb²⁺) · c(Cl⁻)².
c(Pb²⁺) = Ksp(PbCl₂) ÷ c(Cl⁻)².
c(Pb²⁺) = 1.7·10⁻⁵ M³ ÷ (0.0500 M)².
c(Pb²⁺) = 0.000017 M³ ÷ 0.0025 M².
c(Pb²⁺) = 0.0068 M = 6.8·10⁻³ M.

The human eye contains a certain protein called rhodopsin that changes shape when it is exposed to light. When rhodopsin absorbs light, part of it undergoes a chemical change. This is how eyes sense the presence of light.

Answers

the other person is also correct

Final answer:

Rhodopsin, found in the retina's rod cells, is essential for vision by changing shape when exposed to light, initiating signal transduction to the brain. Rods are crucial for dim light vision, while cones handle color vision. The absorption of light by rhodopsin ultimately allows humans to see.

Explanation:

The human eye detects light through a sophisticated process involving rhodopsin, a special photopigment found in the retina. This pigment is a combination of a protein called opsin and the molecule 11-cis-retinal. When light reaches the photoreceptors, rods and cones, within the retina, it causes a conformational change in rhodopsin. Specifically, when light hits the rods, it causes the 11-cis retinal to change to all-trans retinal, splitting rhodopsin into opsin and all-trans retinal. This change sends a signal to the brain, allowing us to perceive the presence of light and, ultimately, see.

Rod cells are more sensitive and are crucial for vision in dim light, while cone cells provide detailed color vision under brighter light conditions. Rods contain rhodopsin with a maximum absorption around 500 nm, mainly in the blue-green region of the visible spectrum. Cones contain three types of photopigments, called opsins, each sensitive to different wavelengths of light corresponding to the primary colors red, green, and blue. The process of light absorption by rhodopsin and signal transduction to the brain is fundamental for human vision.

Given the starting solution had a concentration of 1.25 m, how many moles of co[h2o]6cl2 were available in the amount of starting solution you used

Answers

Final answer:

To calculate the number of moles of co[h2o]6cl2 in the starting solution, we can use the molarity (concentration) of the solution and the volume of the solution used. If 1L of the solution is used, the number of moles would be equal to the molarity of the solution.

Explanation:

The question is about finding out the number of moles of co[h2o]6cl2 present in a starting solution with a given molarity (concentration). Molarity, in a nutshell, is defined as the number of moles of solute per liter of solution. Given that the molarity of the solution is 1.25M, we can directly relate this to the number of moles using the definition of molarity. For example, if we used 1L of the solution, the number of moles would be 1.25moles. If less or more than 1L of solution was used, the number of moles would be less or more, respectively, which is directly proportional to the volume of the solution used.

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Which reaction below represents the first ionization of sb?which reaction below represents the first ionization of ?sb2−(g) → sb3−(g) + e−sb+(g) + e− → sb2+(g)sb(g) + e− → sb−(g)sb−(g) + e− → sb2−(g)sb(g) → sb+(g) + e−?

Answers

Answer is: Sb(g) → Sb⁺(g) + e⁻.
Neutral atom in gas state lose one valence electron and become cation with postive charge.
The first ionisation energy is the energy required to remove one mole of the valence electrons from one mole of gaseous atoms to produce one mole of gaseous ions each with a charge of 1+.
Most metals have strong metallic bond, because strong electrostatic attractive force between valence electrons (metals usually have low ionization energy and lose electrons easy) and positively charged metal ions.

Answer: The reaction for the first ionization of Sb is [tex]Sb(g)\rightarrow Sb^+(g)+e^-[/tex]

Explanation: Ionization of an atom is defined as the reaction when an electron is released from an isolated gaseous atom in their gaseous state.

General equation for the first ionization reaction is:

[tex]X(g)\rightarrow X^+(g)+e^-[/tex]

So, from the given choices in the question, only one option represents the first ionization of Antimony atom (Sb-atom), which is [tex]Sb(g)\rightarrow Sb^+(g)+e^-[/tex]


Which pure substance will have the intermolecular force oh hydrogen bonding with itself

Answers

Molecules are characterized by inter and intra molecular forces of interaction. intramolecular forces are those forces that are present within the molecular framework. Ionic and covalent are typical examples of intra-molecular forces of interaction which held atoms together and assist in formation of molecules. On other hand, intermolecular forces of interaction, occurs between two different molecules. They are further sub-categories as dipole-dipole, dipole-induced dipole, van der Waal's, hydrogen bonding etc.

In current context, hydrogen bonding exist if hydrogen atom in a molecule is attached to electronegative elements like O, F or N. Classic example of the system exhibiting hydrogen bonding is pure water. In pure water, water molecules are held together by hydrogen bonding.

Draw the lewis structure for the molecule ch2chch3. how many sigma and pi bonds does it 30) contain

Answers

Answer:
            1-Propene has eight sigma bonds and one pi bond.

Explanation:
                   The lewis structure of 1-Propene is shown below. All sigma bonds are highlighted by blue color and the pi bond is highlighted by red color.
                   Carbon having four unpaired electrons in its excited state can form four covalent (sigma bonds) bonds. In given structure the orbitals containing unpaired electron in sp³ hybridized C undergo head to head overlap with three hydrogen atoms having single unpaired electron and orbital of other sp² hybridized carbon in same fashion. So, four sigma bonds are formed by sp³ hybridized carbon atom.
                    The doubly bonded carbon atoms also form sigma bond but two unpaired electrons of these two carbons undergo the formation of pi bond. This pi bond forms when the orbitals overlap along the plane perpendicular to the existing sigma bond resulting in the formation of single pi bond.

Lewis structure are the diagrams, which represent the bonding between atoms of a molecule. It also shows the number of lone pairs present in the atom. The propene Lewis structure shows that it has 8 sigma and 1 pi bonds.

Propene or CH[tex]_2[/tex]CHCH[tex]_3[/tex], is an organic compound that is released by the burning of forest fires, motor vehicles, and aircraft exhaust. The Lewis structure of propene shows that it has 8 sigma bonds and one pi bond.

Sigma bonds are represented as single bond. Pi bonds are represented as double or triple bond.

The given image below is the Lewis structure of propene.

Carbon is a tetravalent atom, and in its its excited stated can form 4 covalent bonds. In the diagram, it is seen that carbon is [tex]\text{sp}^2[/tex] hybridized. Carbon forms head to head overlapping with the three hydrogen atoms, forming three sigma bonds.

Since, the carbon is a tetravalent atom, it will form one sigma and one pi bond. The pi bonds are formed when orbitals overlap perpendicularly along the plane of sigma bond.  

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What is the geometry around the bottom carbon atom in acetonitrile? what is the geometry around the bottom carbon atom in acetonitrile? tetrahedral trigonal planar linear?

Answers

The left carbon has no double or triple bond so the type of hybridization is sp³ and the shape is tetrahedral

The right carbon has triple bond so the type of hybridization is sp and the shape is Linear 

Check the attached pictures to understand and choose the one you want 

Final answer:

The bottom carbon atom in acetonitrile has a linear geometry due to the sp hybridization created by two regions of electron density, corresponding to a triple bond with nitrogen and a single bond with another carbon.

Explanation:

The geometry around the bottom carbon atom in acetonitrile is linear. Acetonitrile, which has the formula CH3CN, features a triple bond between the bottom carbon (the carbon atom bonded to the nitrogen) and the nitrogen atom. This carbon is attached to two groups: a nitrogen atom and another carbon (part of the methyl group). The triple bond counts as a single region of electron density due to the presence of multiple bonds to the same atom. Therefore, it only has two regions of electron density, leading to sp hybridization and a linear molecular geometry with the C-C-C and C-C-N bond angles both being approximately 180°.

A gas occupies 4.23 l at 2.25 atm. what is the volume at 3.46 atm?

Answers

Boyle's law gives the relationship between pressure and volume of gas.
It states that at constant temperature pressure in inversely proportional to volume. 
PV = k
where P - pressure V - volume and k - constant 
P1V1 = P2V2
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation 
substituting the values in the equation 
2.25 atm x 4.23 L = 3.46 atm x V 
V = 2.75 L
new volume is 2.75 L

What is the value of q when the solution contains 2.50×10−3 m mg2+ and 2.00×10−3m co32−? express your answer numerically?

Answers

when q is the concentration of the products / the concentration of the reactants

when the balanced equation of the reaction is:

MgCO3(s) → Mg^2+   +  CO3^2-

so, Q = [Mg^2+][CO3^2-]

and we neglect the concentration of MgCO3(s) as it is in the solid phase.

when [Mg^2+] = 2.5 x 10^-3 m

[CO3^2-] = 2 x 10^-3 m

so by substitution:

Q = 2.5 x 10^-3 * 2 x 10^-3

    = 0.000005 M


The value of [tex]\( Q \)[/tex] for the given solution is [tex]\( 5.00 \times 10^{-6} \).[/tex]

To determine the reaction quotient [tex]\( Q \)[/tex] for the dissolution reaction of magnesium carbonate, [tex]\( \text{MgCO}_3 \)[/tex], we need to understand the solubility product constant ([tex]\( K_{\text{sp}} \)[/tex]) and the concentrations of the ions involved.

Given:

Concentration of [tex]\( \text{Mg}^{2+} \)[/tex]: [tex]\( 2.50 \times 10^{-3} \) M[/tex]

Concentration of [tex]\( \text{CO}_3^{2-} \)[/tex]: [tex]\( 2.00 \times 10^{-3} \) M[/tex]

Reaction:

For the dissolution of [tex]\( \text{MgCO}_3 \)[/tex]:

[tex]\[ \text{MgCO}_3(s) \leftrightarrow \text{Mg}^{2+}(aq) + \text{CO}_3^{2-}(aq) \][/tex]

Expression for the Reaction Quotient ([tex]\( Q \)[/tex]):

[tex]\[ Q = [\text{Mg}^{2+}][\text{CO}_3^{2-}] \][/tex]

Substitute the given concentrations into the expression:

[tex]\[ Q = (2.50 \times 10^{-3} \, \text{M})(2.00 \times 10^{-3} \, \text{M}) \][/tex]

Calculation:

[tex]\[ Q = (2.50 \times 10^{-3}) \times (2.00 \times 10^{-3}) \][/tex]

[tex]\[ Q = 5.00 \times 10^{-6} \][/tex]

The ionization constant for water (kw) is 9.614*10-14 at 60°c. calculate [h3o+], [oh−], ph, and poh for pure water at 60°c.

Answers

The Kw (the ionic product for water) at 60°C is 9.614·10⁻¹⁴ mol²/dm⁶.
Kw = [H₃O⁺] · [OH⁻].
[H₃O⁺] = [OH⁻] = √9.614·10⁻¹⁴ mol²/dm⁶.
[H⁺] = [OH⁻] = 3.1·10⁻⁷ mol/L.
pH = -log[H₃O⁺].
pH = -log(3.1·10⁻⁷ mol/L).
pH = 6.5; potential of hydrogen of neutral solution at 60°C.
pOH = -log[OH⁻].
pOH = 6.5.

Find the age t of a sample, if the total mass of carbon in the sample is mc, the activity of the sample is a, the current ratio of the mass of 14 6c to the total mass of carbon in the atmosphere is r, and the decay constant of 14 6c is λ. assume that, at any time, 14 6c is a negligible fraction of the total mass of carbon and that the measured activity of the sample is purely due to 14 6c. also assume that the ratio of mass of 14 6c to total carbon mass in the atmosphere (the source of the carbon in the sample) is the same at present and on the day when the number of 14 6c atoms in the sample was set. express your answer in terms of the mass ma of a 14 6c atom, mc, a, r, and λ.

Answers

the age of the sample (t) can be expressed as:** t = (1 / λ) * ln(a / r)

**1. Relate Activity and Initial Abundance:**

The activity (a) of the sample is proportional to the current number of ¹⁴⁶C atoms in the sample (N) relative to the initial number of ¹⁴⁶C atoms (N₀) at the time the sample was isolated from the atmosphere:

a ∝ N / N₀

**2. Relate Number of Atoms to Mass:**

The number of ¹⁴⁶C atoms (N) is related to the total mass of carbon (mc) and the mass of a single ¹⁴⁶C atom (ma) through Avogadro's constant (Na):

N = (mc / ma) * Na

**3. Consider Decay and Substitute:**

Over time, ¹⁴⁶C atoms decay with a decay constant (λ). We can express the change in the number of ¹⁴⁶C atoms using the radioactive decay equation:

dN/dt = -λN

Since we're looking for the age (t), we can integrate this equation to find the relationship between N and t:

N(t) = N₀ * e^(-λt)  // (Equation 1)

Substitute N₀ with the initial number of ¹⁴⁶C atoms proportional to the initial ¹⁴⁶C/¹²C ratio in the atmosphere (r * mc / ma * Na):

N(t) = (r * mc / ma * Na) * e^(-λt) // (Equation 2)

**4. Relate Activity and Current ¹⁴⁶C/¹²C Ratio:**

The current activity (a) is also proportional to the current ¹⁴⁶C/¹²C ratio in the sample:

a ∝ (mc / ma * Na) * [N(t) / mc]

Substitute N(t) from Equation 2:

a ∝ (mc / ma * Na) * [ (r * mc / ma * Na) * e^(-λt) ] / mc

**5. Solve for Age (t):**

Cancel common factors and simplify:

a ∝ r * e^(-λt)

Taking the natural logarithm of both sides:

ln(a/r) = -λt

The final expression for the age of the sample [tex]t[/tex] in terms of the given variables is [tex]t = -\frac{1}{\lambda} \ln \left( \frac{a}{\lambda \cdot \frac{m_c \cdot r}{m_a}} \right)[/tex]

Step 1: Understanding Activity

The activity [tex]A[/tex] of a radioactive sample is related to the number of radioactive nuclei present [tex]N[/tex] by the equation:
[tex]A = \lambda N[/tex]
Here, [tex]\lambda[/tex] is the decay constant and represents the probability of decay per unit time.

Step 2: Relating Activity to Carbon-14

Given that the measured activity [tex]a[/tex] of the sample is purely due to [tex]^{14}C[/tex] and can be expressed as:
[tex]a = \lambda N_t[/tex]
Where [tex]N_t[/tex] is the current number of [tex]^{14}C[/tex] atoms in the sample.

Step 3: Finding Original Amount of Carbon-14

If we denote the original number of [tex]^{14}C[/tex] atoms in the sample as [tex]N_0[/tex], this can be related to the total mass of carbon in the sample and the ratio [tex]r[/tex] as follows:
[tex]N_0 = \frac{m_c \cdot r}{m_a}[/tex]
Where [tex]m_a[/tex] is the mass of a single [tex]^{14}C[/tex] atom.

Step 4: Calculating Age

The relationship between current [tex]N_t[/tex], original [tex]N_0[/tex], and time [tex]t[/tex] can be expressed using the formula for exponential decay:
[tex]N_t = N_0 e^{-\lambda t}[/tex]
Thus, rearranging this expression, we find:
[tex]t = -\frac{1}{\lambda} \ln \left( \frac{N_t}{N_0} \right)[/tex]

Step 5: Substituting Values

Substituting in our earlier expressions:
[tex]t = -\frac{1}{\lambda} \ln \left( \frac{N_t}{\frac{m_c \cdot r}{m_a}} \right)[/tex]
This simplifies further to:
[tex]t = -\frac{1}{\lambda} \left( \ln(N_t) - \ln\left(\frac{m_c \cdot r}{m_a}\right) \right)[/tex]
Thus, we can express [tex]t[/tex] as:
[tex]t = -\frac{1}{\lambda} \ln(N_t) + \frac{1}{\lambda} \ln\left(\frac{m_c \cdot r}{m_a}\right)[/tex]
[tex]t = -\frac{1}{\lambda} \ln \left( \frac{a}{\lambda \cdot \frac{m_c \cdot r}{m_a}} \right)[/tex]

A reaction vessel contains nh3, n2, and h2 at equilibrium at a certain temperature. the equilibrium concentrations are [n2] = 0.31 m, [h2] = 1.51 m, and [nh3] = 0.75 m. calculate the equilibrium constant, kc, if the reaction is represented as

Answers

The balanced equation for the reaction is,
          N₂(g) + 3H₂(g) ⇄ 2NH₃(g)

Since the given concentrations are taken at the equilibrium state, we can use those directly for the calculation.

Kc = [NH₃(g)]² / ([N₂(g)] x [H₂(g)]³)
Kc = (0.75 M)² / ((0.31 M) x (1.51 M)³)
Kc = 0.527 M⁻²
Final answer:

To calculate the equilibrium constant (Kc), we use the law of mass action. The equation for the reaction is N2 + 3H2 ⇌ 2NH3. By plugging in the given equilibrium concentrations into the equation and solving, we find that Kc is approximately 0.05927.

Explanation:

To calculate the equilibrium constant, Kc, we need to use the law of mass action. The equation for the reaction is:

N2 + 3H2 ⇌ 2NH3

Kc is calculated by taking the concentrations of the products (NH3) raised to their stoichiometric coefficients and dividing by the concentrations of the reactants (N2 and H2) raised to their stoichiometric coefficients.

Kc = ([NH3]²) / ([N2][H2]³)

Plugging in the given equilibrium concentrations ([NH3] = 0.75 M, [N2] = 0.31 M, [H2] = 1.51 M) into the equation, we get:

Kc = (0.75²) / (0.31 × 1.51³)

Kc = 1.125 / (0.468 × 3.448)³

Kc = 1.125 / (0.468 × 40.7855)

Kc = 1.125 / 18.986

Kc ≈ 0.05927

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What is the molarity of 555 l of a ba(oh)2 solution if the ph is 10.20? 1. 2.26 × 10−5 m 2. 6.31 × 10−11 m 3. 5.15 × 10−7 m 4. 3.15 × 10−11 m 5. 3.14 × 10−4 m 6. 1.58 × 10−4 m 7. 7.92 × 10−5 m 8. 4.40 × 10−2 m?

Answers

First, you need to get POH from the value of PH:

when POH = 14 - PH 

                   = 14 - 10.2

                    = 3.8
then we are going to get the value of [OH] from the POH value:

POH = -㏒[OH-]

3.8  = - ㏒ [OH-]

∴[OH-] = 1.58 x 10^-4

then, we will get the moles of ba(OH)2 = (1.58 x 10^-4) / 2 

                                                                  = 0.0000792 moles 

∴ the molarity of Ba(OH)2 = 7.92 x 10^-5

Answer:

7. 7.92 × 10−5

Explanation:

Hello,

In this case, with the given pH, one could find the pOH:

[tex]pOH=14-pH=14-10.20=3.8[/tex]

Thus, since barium hydroxide is completely dissolved in water based on:

[tex]Ba(OH)_2\rightarrow Ba^{+2}+2OH^-[/tex]

The concentration of hydroxyl ions is twice to that of the hydroxide (2:1 mole relationship). Therefore, by considering the relationship between the pOH and the concentration of hydroxyl we have:

[tex]pOH=-log([OH]^-)\\[/tex]

[tex][OH]^-=10^{-3.8}=1.58x10^{-4}M[/tex]

Finally, given the 1:2 mole ratio of barium hydroxide to hydroxyl ions, the concentration of barium hydroxide results:

[tex][Ba(OH)_2]=2*[OH^-]=\frac{1}{2} *1.58x10^{-4}M[/tex]

[tex][Ba(OH)_2]=7.92x10^{-5}M[/tex]

Thus, the answer is 7. 7.92 × 10−5.

Regards.

What is measured by the reaction rate?

the speed at which products form

the time required for a reaction to go to completion

the probability that a reaction will occur

Answers

The reaction rate is the speed at which products form, based on the rate of the slowest step in the mechanism.

Answer: Option (a) is the correct answer.

Explanation:

Rate of reaction is defined as the rate at which a chemical reaction occurs. That is, it tells how rapidly or slowly the products are formed.

Mathematically,         Rate = [tex]\frac{-\Delta [reactants]}{\Delta t}[/tex]

It also tells the number of successful collisions taking place.

Thus, we can conclude that the speed at which products form is measured by the reaction rate.

The reaction of cr2+(aq) with cr2o2−7(aq) in acid solution to form cr3+(aq). calculate δg∘rxn.

Answers

The reaction is:
6 Cr²⁺ + Cr₂O₇²⁻ + 14 H⁺ → 8 Cr³⁺ + 7 H₂O

E₀ = 1.33 - (-0.5) = 1.83 V

ΔG = - n f E₀
      = - 6 * 96485  * 1.83
      = - 1059405.3 J / mol
      = - 1059.4 kJ / mol

Answer:

The correct answer is -1059.45 kJ.

Explanation:

The balanced equation is:

6Cr₂⁺ + Cr₂O₇²⁻ + 14H⁺ ⇒ 8Cr₃⁺ + 7H₂O

In the mentioned reaction 6 electrons are transferred

By calculating Ecell with the use of reduction potential of each cell:

Ecell = Eox + Ered

Ered = 0.50V

Eox = -Ered = -(-0.50V) = 0.50V

Ered = 1.33V

Ecell = 0.50V + 1.33V

Ecell = 1.83V

Now in order to calculate ΔG

n = 6, Faraday constant (f) = 9.68470 × 10⁴ = 96847 C mol⁻¹

ΔG = -nFE

ΔG = -6 × 96487 C mol-1 × 1.83V

ΔG = -1059.42 KJ

The relation between ΔG and ΔG°rxn

ΔG = ΔG° + RTlnQ

Under the standard condition Q = 1 and ΔG = ΔG°

Thus,

ΔG°rxn = ΔG = -1059.42 KJ

: hydrochloric acid reacts with the mineral calcite to produce carbon dioxide gas, water, and calcium chloride. based on what you have learned in activity a and activity b, what are three things you could do to make the reaction occur more quickly?

Answers

Following three things when applied could make the reaction to occur more quickly;

1) Increasing Temperature:
                                          Increase in temperature increases the Kinetic energy of molecules. This results in increase in the velocity and rate of collisions between reactants. Hence, greater the number of collisions between reactants per time greater will be the probability of formation of product per unit time.

2) Grinding Calcite:
                              Grinding of Calcium carbonate results in the increase of surface area of calcite. So greater the surface area greater is the exposure of Calcium carbonate to HCl molecules, hence the rate of formation of product increases.

3) Using Catalyst:
                            Very important. Catalyst when used decreases the activation energy and increase the rate of reaction by following methods.

                       a) Providing new pathway

                       b) weakening the bonds

                       c) providing surface area

                       d) holding up the reactant close to each other.

The things that can be done to make the reaction occur quickly include increasing the temperature, grinding calcite, and using catalyst.

It should be noted that a catalyst is used to speed up the rate of a chemical reaction. Also, increasing the temperature is important in increasing the kinetic energy of the molecules.

Furthermore, it should be noted that grinding calcite results in the rise in the surface area of the calcite. Therefore, the formation of product will rise.

In conclusion, these are important in making hydrochloric acid react with the mineral calcite quickly.

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Determine if the bond between each pairs of atoms would be pure covalent, polar covalent, or ionic. n and se

Answers

Types of Bonds can be predicted by calculating the difference in electronegativity.

If, Electronegativity difference is,

 

                Less than 0.4 then it is Non Polar Covalent Bond

                

                Between 0.4 and 1.7 then it is Polar Covalent Bond

            

                Greater than 1.7 then it is Ionic

 

For N and Se,

                    E.N of Nitrogen         =   3.04

                    E.N of Selenium        =   2.55

                                                   ________

                    E.N Difference             0.49          (Weakly Polar Covalent)


As you have not provided remaining pairs, so if you have any of them, follow the method as mentioned above.

Pure covalent bond is formed between Br and Br. Polar covalent bonds are formed by O and F, N and Cl, and others. A connection between Sr and O is ionic.

We can take into account the difference in electronegativity between the elements involved to determine the sort of bond—pure covalent, polar covalent, or ionic—between each pair of atoms:

The terms "Br and Br" (bromine and bromine)

Since both atoms are composed of the same element, their electronegativity is the same.

The difference in electronegativity is 0.

Because the identical atoms share the electrons evenly, a pure covalent link is produced.

Oxygen and fluorine, or O and F:

The electronegativity of oxygen (O) is roughly 3.44.

With a value of roughly 3.98, fluorine (F) has a higher electronegativity.

O and F have different electronegativities by 0.54.

This slight difference in electronegativity points to a polar covalent connection, where the electrons are distributed unevenly, leaving the less electronegative atom (O) with a partial positive charge and the more electronegative atom (F) with a partial negative charge.

Nitrogen and chlorine, or N and Cl

The electronegativity of nitrogen (N) is around 3.04.

The electronegativity of chlorine (Cl) is roughly 3.16.

N and Cl have different electronegativities of 0.12 each.

This slight variation in electronegativity suggests a polar covalent connection, similar to that between O and F.

Oxygen and strontium are two elements.

About 0.95 is the electronegativity of strontium (Sr).

With a value of about 3.44, oxygen (O) has a much higher electronegativity.

Between Sr and O, there is a significant difference in electronegativity (3.44 - 0.95 = 2.49).

The creation of Sr²⁺ ions and O₂ ions, which are bound together by electrostatic forces, results from the electrons being transferred from Sr to O in an ionic bond, as indicated by the high electronegativity difference.

To sum up:

Pure covalent bond is formed between Br and Br.

Polar covalent bonds are formed by O and F, N and Cl, and others.

A connection between Sr and O is ionic.

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In a laboratory experiment, John uses a mesh to separate soil particles from water. Which technique of separation is he using? chromatography distillation filtration fragmentation condensation

Answers

filtration, he used a mesh to filter out the stuff

Answer: Option (c) is the correct answer.

Explanation:

A mesh is a kind of net like structure generally used for the purpose of filtration.

Distillation is defined as the method used to separate two liquids with a difference of less than or around [tex]25^{o}C[/tex] in their boiling point.  

So, a liquid with low boiling point will evaporate and its vapors can be collected in a separate container.

Chromatography is defined as a method for separating a mixture by passing it in a solution with the help of a medium where the components of the mixture travel at different rates.

And, filtration is a method used to separate a solid from a liquid by passing through a porous barrier. The solid remain stick to the barrier and liquid passes through the barrier.

A method in which a solid substance is broken down into different parts or fragments is known as fragmentation.

Condensation is a process is in which vapor phase of a substance changes into liquid phase.

Thus, we can conclude that in the given situation John is using the technique of filtration.

The bond energy for the van der waals bond between two helium atoms is 7.9×10−4ev. assuming that the average kinetic energy of a helium atom is (3/2)kbt, at what temperature is the average kinetic energy equal to the bond energy between two helium atoms? use kb=8.62×10−5ev/k.

Answers

Given: van der Waal's bond energy of He = 7.9×10−4ev;
and kb=8.62×10−5ev/k

Now, according to Kinetic theory of gases we know that, 
K.E = 3/2 (kb) T
where T = temperature

∴ T = (2 K.E)/(3 x kb)
Now for K.E = 7.9×10−4ev
T = (2  X 7.9×10−4)/ (3 X 8.62×10−5) = 6.1 K

Thus, at temperature of 6.1 K, average kinetic energy equal to the bond energy between two helium atoms

Which choice best describes the polarity of bri5? view available hint(s) which choice best describes the polarity of ? the molecule is polar and has polar bonds. the molecule is nonpolar and has polar bonds. the molecule is polar and has nonpolar bonds. the molecule is nonpolar and has nonpolar bonds?

Answers

Final answer:

While BrI5 is not a common molecule and potentially not real, based on similar molecular structures, it would most likely be a polar molecule with polar bonds due to its presumed asymmetry and the difference in electronegativity between bromine and iodine.

Explanation:

The molecule in question, BrI5 (bromine pentaiodide), does not appear to exist or is not common in chemical literature. However, assuming it follows similar principles of molecular polarity, we can deduce its polarity based on the provided information. A molecule is polar if it has polar bonds and is not symmetric, meaning that the polarities do not cancel out. Conversely, a molecule is nonpolar if it has polar bonds but is symmetric, such that the polarization cancels out, or if there are no polar bonds present.

Since BrI5 is hypothetically a molecule consisting of a central atom of bromine with five iodine atoms surrounding it, its structure would likely be asymmetric due to the odd number of atoms, leading to an uneven distribution of charge. Thus, if BrI5 did exist, it would most likely have polar bonds (as bromine and iodine have different electronegativities) and would not be symmetric; hence, it would be a polar molecule with polar bonds.

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In the book, Rumble Fish by S.E. Hinton, where dies it take place

Answers

Rumble Fish takes place in a southwestern town. It is not clear in the book, but the author has said that it is her hometown of Tulsa, Oklahoma.

Final answer:

The book Rumble Fish by S.E. Hinton takes place in Tulsa, Oklahoma.

Explanation:

In the book Rumble Fish by S.E. Hinton, the story takes place in a fictional city called Tulsa, Oklahoma. The setting is important because it represents the harsh realities of urban life and the struggles faced by the characters in the book.

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