A stone is thrown from a cliff and lands in the sea. Air resistance is negligible. Which statement is correct whilst the stone is in motion?

vertical component of stone's displacement is constant
horiz. comp. of stone's displacement is constant
vertical component of stone's velocity is constant
horiz. comp. of stone's veolcity is constant

When object falls freely we can say

its initial speed will be ZERO

and its acceleration due to gravity must be

[tex]a = g = 9.8 m/s^2[/tex]

Now we need to find the distance of free fall in 3 s of time

So here we will use kinematics

[tex]y = v* t + \frac{1}{2} at^2[/tex]

now we will plug in all values in it

[tex]y = 0 + \frac{1}{2}* 9.8 * 3^2[/tex]

[tex]y = 44.1 m[/tex]

So it will fall by total distance of 44.1 m

Answer:

The brick will cover a distance of [tex]44.1\;\rm{m[/tex].

Explanation:

Given: A brick starting from rest fall freely in 3 seconds.

As mentioned in question,

When an object falls freely then its initial speed will be [tex](u)=0\; \rm{m/s[/tex].

Acceleration due to gravity is [tex]a=g=9.8\;\rm{m/s^{-2[/tex].

Time [tex](t)=3\; \rm{seconds[/tex]

Using the laws of motion: [tex]s=ut+\frac{1}{2}at^2[/tex]

Substiuting all the values we get:

[tex]s=0\times3+\frac{1}{2}\times9.8\times3^2\\s=0.5\times9.8\times 9\\s=44.1\;\rm{m[/tex]

Therefore, the brick will cover a distance of [tex]44.1\;\rm{m[/tex].

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Final answer:

To calculate instantaneous velocity using the slope of a graph, Larry and Balky should use a graph with velocity on the y-axis and time on the x-axis.

Explanation:

Larry and Balky want to calculate instantaneous velocity using slope in their experiment with a marble rolling down an incline. To accomplish this, they should plot velocity on the y-axis and time on the x-axis. The reason for this is because time is generally considered the independent variable, and velocity, which depends on the time passed, is the dependent variable. In a graph formatted this way, the slope at any given point will represent the instantaneous velocity of the marble at that point in time. As velocity (v) is equal to the displacement (d) divided by time (t), a straight graph of velocity versus time would show velocity as the slope of that line, thus proving option A to be the correct choice for their graph format.

Velocity = 1.32

Direction = South

Answer:

Velocity = 0.55 m/s

Direction  = South

Explanation:

Given

let us take the south as positive direction

Velocity of the balloon [tex]v_{b}[/tex] = + 0.87 m/s

Velocity of wind [tex]v_{w}[/tex] = - 0.32 m/s

Solution

Resultant velocity

[tex]v = v_{b} + v_{w} \\\\v = 0.87+(-0.32)\\\\v = 0.55 m/s[/tex]

since the resultant velocity is positive, balloon is directed southward

The charge will most likely leave the electric field near C) Y

Answer:

Option (C)

Explanation:

The direction of electric field is upwards

The charge is negative is nature, so the force on the charge particle is in the opposite direction of electric field that means the force on the charged particle is downward. The relation between the force and the electric field is given by

F =  -q x E

So, the charged particle experience a force in the downward direction and then leaves the electric filed near point Y.

Explanation:

The data given is as follows.

     mass = 2.0 kg

     time = 3 seconds

 gravitational acceleration = [tex]9.8 m/s^{2}[/tex]

Calculate the distance traveled by the rock when it falls is as follows.

          [tex]Distance = \frac{1}{2} \times acceleration \times time^{2}[/tex]

                                 = [tex]\frac{1}{2} \times 9.8 m/s^{2} \times (3 second)^{2}[/tex]

                                 = [tex]\frac{1}{2} \times 9.8 m/s^{2} \times 9 second^{2}[/tex]

                                 = 44.1 m

Therefore, the distance traveled by rock is 44.1 meter.

Remark

It's not the number that's the problem. It's the minus sign.

Just use F = m*a to get the numerical answer. F = 51 * 11  = 561 N

Now we come to the hard part. If you learn nothing else in physics, you learn that minus signs are either your best buddy or your worst enemy -- one that you pay a mafia hit man a lot of money to get rid of.

In this case, you better start looking for a guy wearing a white tie.

What you are finding is a force that is acting against the starting block. In order to move forward, you have to push against something to accomplish going forward.  That's  why the block is there: it absorbs the push and you pop forward. You should draw a diagram of the block so you see how many forces act on it.

Answer: - 561

Ball leaves the table of height 0.60 m

Initial speed of the ball is in horizontal direction which is 2.4 m/s

Now here we can say that time taken by the ball to hit the ground will be given by kinematics equation in vertical direction

[tex]\Delta y = v_y*t + \frac{1}{2}at^2[/tex]

here in y direction we can say

[tex]\Delta y  = 0.60 m[/tex]

[tex]v_y = 0[/tex]

[tex]a = 9.8 m/s^2[/tex] due to gravity

now from above equation we have

[tex]0.60 = 0 + \frac{1}{2}*9.8*t^2[/tex]

[tex]t = 0.35 s[/tex]

Now in the same time the distance that ball move in horizontal direction is given as

[tex]d = v_x* t[/tex]

given that

[tex]v_x = 2.4 m/s[/tex]

[tex]d = 2.4 * 0.35[/tex]

[tex]d = 0.84 m[/tex]

So it will move a total distance of 0.84 m where it will land

The time required for the pool ball to hit the ground is approximately 0.35 seconds and it would cover a horizontal distance of about 0.84 meters from the edge of the table to the landing location.

Your question involves the physics concept of projectile motion. Here, we can use the concepts of horizontal velocity and vertical displacement to calculate the time it would take the pool ball to hit the ground and the horizontal distance it would cover.

Firstly, solving for the fall time, we use the equation of motion: h = 0.5gt², where h is the height, g is the gravity constant (9.8 m/s²), and t is the time. Given the height h = 0.60m, we find t≈0.35s.

Secondly, to find the horizontal distance (the distance between the table's edge and the ball's landing location), we use the formula d = vt, where d is distance, v is horizontal velocity, and t is time. So, d ≈ 2.4m/s * 0.35s = 0.84m.

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Answer: C)Acceleration due to gravity affects all bodies the same since it depends primarily on the gravity of the planet, not on the object being dropped.

Explanation:

Using equation of motion,

[tex]v^{2}=u^{2}+2gh[/tex]

where v= final velocity , u= initial velocity , h= height from where object is dropped ,acceleration due to gravity , [tex]g=\frac{GM}{R^{2}}[/tex]

G= universal gravitational constant, M=mass of planet , R= radius of planet

Therefore g depends on mass and radius of planet .

=>If all objects are dropped from same height with zero initial speed the final speed depends only on acceleration due to gravity which is a property of planet taken into consideration and does not depend on the object.

For example if a piece of paper and a heavy stone are dropped from the same height with zero initial speed then both objects will have same final speed .

Acceleration due to gravity affects all bodies the same since it depends primarily on the gravity of the planet, not on the object being dropped.

The correct answer is C) Acceleration due to gravity affects all bodies the same since it depends primarily on the gravity of the planet, not on the object being dropped.

Acceleration due to gravity is constant for all objects near the surface of the Earth, regardless of their mass. This means that when objects are dropped from the same height, they will all experience the same acceleration. As a result, they will all hit the ground with the same velocity, disregarding air resistance.

For example, if you drop a feather and a rock from the same height, both will fall at the same rate due to gravity. However, the feather will experience more air resistance and take longer to reach the ground.

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A timeline is necessary a. For every goal.

Here are a few reasons why it is so:

The conversions are as follows

60.°C = 333 Kelvin

212 F = 373 K

200 C = 273 K

27 C = 300 K

This question involves matching temperatures in differing scales: degrees Celsius, Kelvin, and Fahrenheit. However, only the first match (60°C to 333K) can be made with the given options. The remaining options don't correspond correctly.

The question involves converting and matching different temperature scales, namely degrees Celsius (°C), Kelvin (K), and degrees Fahrenheit (°F). Here are the matched equivalent temperatures:

The question involves converting and matching different temperature scales, namely degrees Celsius (°C), Kelvin (K), and degrees Fahrenheit (°F). Here are the matched equivalent temperatures:

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Given

initial position = Xi= 19.9m

Final position Xf = 5.4m

Average velocity= Va = -0.418m/s

it shows displacement is reverse.

To find  t=?

As   Va = (Xf- Xi) / t

t = (Xf-Xi) / ( Va)

t = ( 5.4-19.9) / (-0.418)

t = (-14.5 ) / (-0.418)   (-ve sign cancel out at numerator and denominator)

t =34.69 s

For free fall motion the displacement can be found by graphically as well as by kinematics equation

Here acceleration of object is constant as it fall due to gravity so we can use

[tex]d = v_i * t + \frac{1}{2}at^2[/tex]

here if body starts with zero initial speed then we can say

[tex]d = 0 + \frac{1}{2}*9.8*t^2[/tex]

here we need to find the displacement from t = 0 to t = 6s

so we can say

[tex]d = \frac{1}{2}*9.8*6^2[/tex]

[tex]d = 176.4 m[/tex]

so the displacement will be 176.4 m

in order to find the displacement from the graph of velocity and time we need to find the area under the graph for given time interval that will also give us same displacement for given period of time.

Answer:

+360m

Explanation:

You are missing some parts of the question but I have found them else where. The graph will be shown below.

The formula for this is [ d = vt ] where v = velocity and t = time.

On the graph, we can see that the acceleration is constant. The line goes to a maximum velocity of 60m/s and a maximum time of 6 seconds.

Find the displacement with what we are given.

d = 60 * 6

d = 360m

Since we are going forward, we are going to add a "+" sign in front.

Best of Luck!

Answer A

Cars A, B, C, D, and E are moving on tracks from left to right. The lengths of the tracks are the same. Assuming each car started at the beginning of its track, which cars are moving at a constant velocity?

A) A and C  

B) B and D  

C) C and E  

D) D and A

The cars A and C are moving with a constant velocity. The correct option is A.

The diagram attached, is a motion diagram, which marks the positions of an object measured at equal time intervals by means of dots.

If the dots are evenly spaced, it shows that the object is making equal displacements in equal intervals of time, which means that the object has a constant velocity.

In the attached diagram, it can be seen that the dots for the cars A and C are equally spaced, showing that these cars are moving with a constant velocity.

The cars B and D are accelerating, since the space between the dots appears to increase.

The car E is decelerating, as the distance between the dots progressively decreases.

Hence only the cars A and C are moving with constant velocities, with A having a greater velocity than C.

c is the correct answer

it would be 4 kilomotors

As it is given here that two blocks are pulled towards right side with constant horizontal velocity.

Both blocks are given that moving with speed 2 m/s

Now we can say that by Newton's II law

F = ma

i.e. Net force on a system is product of its mass and acceleration

but as we can see that here two blocks are moving with  constant speed so here as per definition of acceleration we will say

[tex]a = \frac{dv}{dt}[/tex]

As we know that v = constant

[tex]a = 0[/tex]

so here from 2nd law

[tex]F = 0[/tex]

so net force must be zero  block A

So correct FBD must be "option A"

we should not represent any force on it

The correct answer is water vapor.

Answer: Water Vapor

Explanation:

Kinetic energy is the energy possessed by an object by virtue of its motion.

Solid state : In this state, the molecules are arranged in regular and repeating pattern. The molecules are closely packed that means they are fixed and have low kinetic energy.

For example : Ice

Liquid state : In this state, the molecules are present in random and irregular pattern. The molecules are closely packed but they can move from one place to another and hence have low kinetic energy.

For example : water

Gaseous state : In this state, the molecules are present in irregular pattern. The molecules are not closely packed and they can move freely from one place to another and spread out and thus have high kinetic energy.

For example : water vapor

Answer:

Nervous and endocrine

Explanation:

she could throw her tool belt in the opposite direction, sending her floating towards her ship. That would apply to Newton's Law ofwhat is in motion stays in motion unless interrupted. Therefore if you threw it one way you would keep going the other way because there are no molecules to interrupt your path.

To return to her spaceship, the astronaut should apply Newton's third law of motion by throwing the wrench away from the ship, which will propel her towards it via an equal and opposite reaction.

The astronaut floating in space can return to her spaceship by utilizing Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. By throwing the wrench away from the spaceship, there will be a reactive force that pushes the astronaut towards the spaceship. The mass of the wrench and the force with which the astronaut throws it will determine the velocity at which she moves towards the spaceship, according to the conservation of momentum. Newton's laws of motion and the conservation of momentum are key principles that will help her navigate back to safety.

The problem corresponds to the motion of a projectile (the salmon), with initial speed [tex]v_0[/tex], initial direction [tex]\theta=37.6^{\circ}[/tex] and vertical acceleration [tex]g=9.81 m/s^2[/tex] downward. The two equations which gives the horizontal and vertical position of the salmon at time t are

[tex]S_x (t) = v_0 cos \theta t[/tex] (1)

[tex]S_y (t) = v_0 sin \theta t - \frac{1}{2}gt^2[/tex] (2)

We can solve the problem by requiring Sx=3.16 m and Sy=0.379 m, the data of the problem.

Solving eq.(1) for t:

[tex]t=\frac{S_x}{v_0 cos \theta}[/tex]

And substituting this expression of t into eq.(2), we get the following expression for [tex]v_0[/tex]:

[tex]v_0 =\sqrt{\frac{g S_x^2}{2(tan \theta S_x -S_y)cos^2 \alpha}}[/tex]

And substituting the numbers into the equation, we find

[tex]v_0 = 6.16 m/s[/tex]

The minimum speed Salmon must jump is [tex]\boxed{6.16{\text{ }}{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {\text{s}}}} \right. \kern-\nulldelimiterspace} {\text{s}}}}[/tex].

Further explain:

Here, the given problem is on the basis of the projectile motion.

Given:

Initial direction [tex]\left( \theta\right)[/tex] with horizontal is [tex]37.6^\circ[/tex].  

The distance travel by Salmon in x-direction at time [tex]t[/tex] is [tex]3.16{\text{ m}}[/tex].

The distance travel by Salmon in y-direction at time [tex]t[/tex] is [tex]0.379{\text{ m}}[/tex].  

Acceleration due to gravity is [tex]9.8{{\text{m}} \mathord{\left/ {\vphantom {{\text{m}} {{{\text{s}}^2}}}} \right. \kern-\nulldelimiterspace} {{{\text{s}}^2}}}[/tex].  

Formula and concept used:

The velocity component in x-direction [tex]\left( {{v_x}} \right)[/tex] is[tex]v\cos \theta[/tex].  

Distance travel by Salmon in x-direction at time [tex]t[/tex] is,

[tex]\begin{gathered}{s_x} = {v_x}t \hfill \\{s_x} = v\cos \theta\cdot t \hfill \\ \end{gathered}[/tex]

Simplify above equation,

[tex]\boxed{t=\dfrac{{{s_x}}}{{v\cos \theta }}}[/tex]                           …… (1)

The velocity component in y-direction[tex]\left( {{v_y}} \right)[/tex] is [tex]v\sin \theta[/tex].  

Distance travel by Salmon in y-direction at time [tex]t[/tex] is,

[tex]{s_y} = {v_y}t - \frac{1}{2}g{t^2}[/tex]

Substitute the value of [tex]{v_y}[/tex] in above equation,

[tex]\boxed{{s_y} = v\sin \theta\cdot t - \frac{1}{2}g{t^2}}[/tex]                       …… (2)

Substitute the value of [tex]t[/tex] from equation (1) in to the equation (2).

[tex]\begin{aligned}{s_y}&=v\sin \theta\cdot \left( {\frac{{{s_x}}}{{v\cos \theta }}} \right) - \frac{1}{2}g{\left( {\frac{{{s_x}}}{{v\cos \theta }}} \right)^2} \hfill \\&={s_x}\tan\theta- \frac{{g{{\left( {{s_x}} \right)}^2}}}{{2{v^2}{{\cos }^2}\theta}}\hfill\\\end{aligned}[/tex]

Simplify the above equation to obtain the value of [tex]v[/tex] ,

[tex]\dfrac{{g{{\left( {{s_x}} \right)}^2}}}{{2{v^2}{{\cos }^2}\theta }}={s_x}\tan \theta-{s_y}[/tex]

Rearrange the above expression.

[tex]\dfrac{1}{{{v^2}}}=\dfrac{{2{{\cos }^2}\theta\cdot \left( {{s_x}\tan\theta- {s_y}} \right)}}{{g{{\left( {{s_x}} \right)}^2}}}[/tex]

Simplify the above equation,

[tex]{v^2} = \dfrac{{g{{\left( {{s_x}} \right)}^2}}}{{2{{\cos }^2}\theta\cdot \left( {{s_x}\tan \theta- {s_y}} \right)}}[/tex]

Taking the square root both the sides in above equation,

[tex]\boxed{v=\sqrt {\frac{{g{{\left( {{s_x}} \right)}^2}}}{{2{{\cos }^2}\theta\cdot \left( {{s_x}\tan \theta- {s_y}} \right)}}} }[/tex]                                                   …… (3)

Calculation:

Substitute the value of [tex]{s_x}[/tex] as [tex]3.16{\text{ m}}[/tex] , the value of [tex]{s_y}[/tex] as [tex]0.379{\text{ m}}[/tex] , the value of [tex]\theta[/tex]  as [tex]37.6^\circ[/tex]  in equation (3).

[tex]\begin{aligned}v&=\sqrt {\frac{{9.8{{\left( {3.16} \right)}^2}}}{{2{{\cos }^2}37.6^\circ\cdot\left( {3.16\tan 37.6^\circ- 0.379} \right)}}}\\&=\sqrt {\frac{{97.86}}{{2.579}}}\\&=\sqrt {37.945}\\&=6.16{\text{ }}{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern-\nulldelimiterspace}{\text{s}}}\\\end{aligned}[/tex]  

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Answer detail:

Grade: Senior School

Subject: Physics

Chapter: Projectile motion

Keywords:

Salmon, jump, waterfall, angle of inclination, continue upstream, projectile, acceleration, velocity, acceleration due to gravity, Newton’s laws, equation of motion, velocity, component of acceleration.

Answer:

A) 33-newton force pointing upward

Explanation:

Hope this help!

Answer: (B) There is complete destructive interference between the incoming and reflected waves

Explanation:

For example, if you pluck a guitar the waves will travel back and forth. They consist of nodes and anti-nodes. It is created, when the wave traveling to one side and bounces of the other end and comes back. As it travels to the other side, it is reflected thus, comes back. So standing waves occurs when there is interference.

When the wave is produced, the points where the string is not moving are called nodes and where they are moving are called anti-nodes. The positions where nodes are produced, destructive interference occurs and where anti-nodes are produced, constructive interference occurs

Answer:

There is complete destructive interference between the incoming and reflected waves

Explanation:

I did gradpoint

Answer: Virtual image

Explanation:

- The light rays never converges, because the light rays crosses the point where all the rays accumulate, taking it away from the lens

- The virtual image that is produced, is positioned in front of the lens

- Light when passes through a concave lens, it is refracted away from the focal point making an image look smaller  

- When light passes through a convex lens, it is refracted towards the focal point making the image look bigger

Answer:

Virtual image

Explanation:

a p e x verified

id have to say its thunder

The circulatory system sends nutrients to the body's cells.

Answer: Circulatory system

Explanation:

The circulatory system moves nutrients from the source to various parts of the body.

The nutrients is supplied to each and every cell of the body because each cell of the body needs energy to work efficiently.

The nutrients and the waste materials are also carried from the various cells to the kidney and liver for filtration.

Hence, the circulatory system is responsible for the transport of nutrients from the source to various parts of the body.

heat and pressure would be your answer hope it helps

Answer:

heat and pressure

Explanation:

Answer:

Driverless cars will transport people to and from the train station.

Explanation:

the person above is correct

The United Kingdom planning to use driverless cars beginning in 2015 in a way such that Driverless cars will transport people to and from the train station, therefore the correct answer is option C.

An EV stands for an electric vehicle. Electric vehicles (EVs) are autos that are powered totally or partially by electricity.

According to a lot of experts, self-driving cars can be programmed to be safer than human drivers.

These automobiles are able to perceive their surroundings and predict what lies ahead, something that humans are not capable of doing thanks to the sensors and cameras that are directing and monitoring them.

The right response is option C since the United Kingdom plans to employ autonomous automobiles starting in 2015 in a mode that will allow them to carry people to and from the railway station.

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Answer: Option A: The number of trees sampled.

The accuracy can be understood as how close is the measured value to the true value.   The aim is to monitor the population size of the insect pest in a 50 square kilometer. Random trees are selected, and number of eggs and larvae are counted. So, the measured value would be closer to actual value when the number of trees sampled are increased. More the number of trees sampled, less would be the chances of error and the accuracy of the estimate would increase.

Answer:

a.) the number of tress sampled

work done is defined as product of force and displacement in the direction of force.

So we can say formula of work done is

[tex]W = F.d[/tex]

so here it is given that

F = 350 N

d = 3.85 m

from above equation we have

[tex]W = 350 * 3.85[/tex]

[tex]W = 1347.5 J[/tex]

So net work done is 1347.5 J

Here this is net work done which includes Work done by applied force and also the work done by gravitational force of earth

1) 3.7 km/hr  N19°W

2) she must aim at N20°E

work sheet  #6

relative velocity